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  • Zend Framework :: Is this code good for user login (Its begining- because that I want to know if its

    - by Yosef
    Hi, I new in Zend. Main Question: Is this code good for user login (Its beginning- because that I want to know if its can be improve)? Code understanding question: Is every time that in action call to his view- code execution in action not going to next row until view request? (I asking about IndexAction that I write down) Thanks view index.phtml <? echo $this->form controller IndexAction.php public function indexAction() { $form=new Application_Form_Login(); $this->view->form = $form; if ($this->getRequest()->isPost()) { $formData = $this->getRequest()->getPost(); if ($form->isValid($formData)) { echo " test value username: ".$form->getValue('username'); } } } form Login.php public function init() { $this->setMethod('post'); $this->setName('user login'); $username = new Zend_Form_Element_Text('username'); $username->setLabel("username") ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $password = new Zend_Form_Element_Password('password'); $password->setLabel('password') ->setRequired(true) ->addFilter('StripTags') ->addFilter('StringTrim') ->addValidator('NotEmpty'); $submit = new Zend_Form_Element_Submit('submit'); $this->addElements(array($username, $password, $submit)); }

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  • Who to select value from DropDown list in PHP???Problem

    - by sandy
    Hello .. I want to know the error in this code The following code retrieves the names of the members of the database query in the dropdownlist But how do I know who you selected.... I want to send messages only to the members that selected form dropdown list <?php include ("connect.php"); $name = $_POST['sector_list']; echo $name ; ?> <form method="POST" action="" > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('select * from members ') or die (mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option size ="40" value=" '. $row['MemberID'] . '" name="' . $row['MemberName']. '">' . $row['MemberName']. '</option>'; } ?> </select> </form> I hope somebody can help me

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  • Basic PHP OOPS Query

    - by appu
    Ok. I am starting out OOPS in PHP. Created a couple of classes: customer(parent) and sales(child) class that inherits from parent class. Created another testcustomer.php in which a new sales object is created however the salesprint() function defined in the sales class does not echo out customer's name though it is set to be "Jane" in the class.customer.php(parent). My thinking is that when sales class extends customer class PHP automatically includes all the code from class.customer.php to sales.customer.php and therefore the constructor in parent class set $name to "Jane". Here is the code: class.customer.php <?php class customer{ private $name; private $cust_no; public function __construct($customerid) { $this->name = 'Jane'; $this->cust_no = $customerid; } } ?> class.sales.php <?php require_once('class.customer.php'); class sales extends customer{ public function salesprint($customerid) { echo "Hello $this->name this is a print of your purchased products"; } } ?> testcustomer.php require_once('class.sales.php'); $objsales = new sales(17); $objsales->salesprint(17); ?> The Output I get Hello this is a print of your purchased products. What am i doing wrong ? thanks romesh

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  • $_POST in php 5.3.5 does not work

    - by naji
    dear all iam working in php 5.3.5 this is the html file <html> <body> <form action="welcome.php" method="post"> Name: <input type="text" name="fname" /> Age: <input type="text" name="age" /> <input type="submit" /> </form> </body> </html> and this is the php file <html> <body> Welcome <?php echo $_POST["fname"]; ?>!<br /> You are <?php echo $_POST["age"]; ?> years old. </body> </html> the problem the values are not passed and the output like Welcome ! You are years old. But it has to be like this Welcome John! You are 28 years old. can any one help me please?? naji

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  • INSERT INTO table doesn't work???

    - by Joann
    I found a tutorial from nettuts and it has a source code in it so tried implementing it in my site.. It is working now. However, it doesn't have a Registration system so I am making one. The thing is, as I have expected, my code is not working... It doesn't seem to know how to INSERT into the database. Here's the function that inserts data into the db. function register_User($un, $email, $pwd) { $query = "INSERT INTO users( username, password, email ) VALUES(:uname, :pwd, :email) LIMIT 1"; if($stmt = $this->conn->prepare($query)) { $stmt->bind_param(':uname', $un); $stmt->bind_param(':pwd', $pwd); $stmt->bind_param(':email', $email); $stmt->execute(); if($stmt->fetch()) { $stmt->close(); return true; } else return "The username or email you entered is already in use..."; } } I have debugged the connection to the database from within the class, it says it's connected. I tried using this method instead: function register($un, $email, $pwd) { $registerquery = $this->conn->query( "INSERT INTO users(uername, password, email) VALUES('".$un."', '".$pwd."', '".$email."')"); if($registerquery) { echo "<h4>Success</h4>"; } else { echo "<h4>Error</h4>"; } } And it echos "Error"... Can you please help me pen point the error in this??? :(

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  • Need help with PHP URL encoding/decoding

    - by Kenan
    On one page I'm "masking"/encoding URL which is passed to another page, there I decode URL and start file delivering to user. I found some function for encoding/decoding URL's, but sometime encoded URL contains "+" or "/" and decoded link is broken. I must use "folder structure" for link, can not use QueryString! Here is encoding function: $urll = 'SomeUrl.zip'; $key = '123'; $result = ''; for($i=0; $i<strlen($urll); $i++) { $char = substr($urll, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)+ord($keychar)); $result.=$char; } $result = urlencode(base64_encode($result)); echo '<a href="/user/download/'.$result.'/">PC</a>'; Here is decoding: $urll = 'segment_3'; //Don't worry for this one its CMS retrieving 3rd "folder" $key = '123'; $resultt = ''; $string = ''; $string = base64_decode(urldecode($urll)); for($i=0; $i<strlen($string); $i++) { $char = substr($string, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)-ord($keychar)); $resultt.=$char; } echo '<br />DEC: '. $resultt; So how to encode and decode url. Thanks

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  • PHP classes totally forgotten something today - sorry

    - by russp
    Hi guys, really sorry about being "totally thick today" but I have forgotten how to do something simple - too much time not in php recently. Want to use the OS phpapi How do I print out the individual rows - see told you I was being thick today // The fields we will be fetching. if (isset($_GET['test']) && $_GET['test'] == 'plaxo') { // plaxo is a PortableContacts end-point so doesn't know about the OpenSocial specific fields $profile_fields = array(); } else { $profile_fields = array( 'aboutMe', 'displayName', 'bodyType', 'currentLocation', 'drinker', 'happiestWhen', 'lookingFor' ); } // The number of friends to fetch. $friend_count = 2; $batch = $osapi->newBatch(); // Fetch the current user. $self_request_params = array( 'userId' => $userId, // Person we are fetching. 'groupId' => '@self', // @self for one person. 'fields' => $profile_fields // Which profile fields to request. ); $batch->add($osapi->people->get($self_request_params), 'self'); // Fetch the friends of the user $friends_request_params = array( 'userId' => $userId, // Person whose friends we are fetching. 'groupId' => '@friends', // @friends for the Friends group. 'fields' => $profile_fields, // Which profile fields to request. 'count' => $friend_count // Max friends to fetch. ); $batch->add($osapi->people->get($friends_request_params), 'friends'); // Get supportedFields Request $batch->add($osapi->people->getSupportedFields(), 'supportedFields'); // Send the batch request. $result = $batch->execute(); Say I wanted to print out "aboutMe", whats the echo? cos echo $result['aboutMe'] doesn't work.

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  • PHP - print content from file after manipulation

    - by ludicco
    Hello there, I'm struggling trying to read a php file inside a php and do some manipulation..after that have the content as a string, but when I try to output that with echo or print all the php tags are literally included on the file. so here is my code: function compilePage($page,$path){ $contents = array(); $menu = getMenuFor($page); $file = file_get_contents($path); array_push($contents,$menu); array_push($contents,$file); return implode("\n",$contents); } and this will return a string like <div id="content> <h2>Here is my title</h2> <p><? echo "my body text"; ?></p> </div> but this will print exactly the content above not compiling the php on it. So, how can I render this "compilePage" making sure it returns a compiled php result and not just a plain text? Thanks in advance

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • SQL wont work? It doesn't come up with errors either

    - by Stefan
    Hey there, I have php function which checks to see if variables are set and then adds them onto my sql query. However I am don't seem to be getting any results back!? $where_array = array(); if (array_key_exists("location", $_GET)) { $location = addslashes($_GET['location']); $where_array[] = "`mainID` = '".$location."'"; } if (array_key_exists("gender", $_GET)) { $gender = addslashes($_GET["gender"]); $where_array[] = "`gender` = '".$gender."'"; } if (array_key_exists("hair", $_GET)) { $hair = addslashes($_GET["hair"]); $where_array[] = "`hair` = '".$hair."'"; } if (array_key_exists("area", $_GET)) { $area = addslashes($_GET["area"]); $where_array[] = "`locationID` = '".$area."'"; } $where_expr = ''; if ($where_array) { $where_expr = "WHERE " . implode(" AND ", $where_array); } $sql = "SELECT `postID` FROM `posts` ". $where_expr; $dbi = new db(); $result = $dbi->query($sql); $r = mysql_fetch_row($result); I'm trying to call the data after in a list like so: $dbi = new db(); $offset = ($currentpage - 1) * $rowsperpage; // get the info from the db $sql .= " ORDER BY `time` DESC LIMIT $offset, $rowsperpage"; $result = $dbi->query($sql); // while there are rows to be fetched... while ($row = mysql_fetch_object($result)){ // echo data echo $row['text']; } // end while Anyone got any ideas why I am not retrieving any data? -Stefan

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  • jquery draggable/droppable issue

    - by Scarface
    Hey guys I have a drag and drop function that does not fully work. What I want to do is be able to drag and drop a picture into a div and have that picture pop up in the div. I have a list of 2 pictures right now, so I have the following function echoed for each picture. Both pictures are draggable and droppable, but the first one is the only one that appears in the div, regardless of which picture gets dragged in. I am not sure what is wrong because the jquery function seems to be unique to each picture. If any one has any suggestions I would appreciate it greatly. while ($row = mysql_fetch_assoc($query)) { $image=htmlentities($row['image']); //image name $uniqid=uniqid(); //unique id for jquery functions $dirname = "usercontent/$user/images/$image"; echo "<img id=\"$uniqid\" src=\"$dirname\" width=\"75\" height=\"75\"/>"; echo "<script> $(function() { $(\"#$uniqid\").draggable({ scroll: true, scrollSensitivity: 10, scrollSpeed: 10, revert: true, helper: 'clone', cursorAt: { cursor: 'move', top: 27, left: 27 } }); $(\"#droppable2, #droppable-background , #droppable2-innerer\").droppable({ greedy: true, activeClass: 'ui-state-hover', hoverClass: 'ui-state-active', drop: function(event, ui) { $(this).addClass('ui-state-highlight').find('> p').html('Dropped!'); $('#droppable-background').css(\"background-image\",\"url($dirname)\"); } }); }); </script>"; }

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  • How to change the attribute value of svg file

    - by rafiq7s
    Hello, In samplexml.svg there is a node <image width="744" height="1052" xlink:href="image1.png"/> I need to replace "image1.png" with another value like "image2.png". Please guide me with sample code how to to that. I could get the attribute value "image1.png". Here is the code: > <?php $xdoc = new DomDocument; > $xdoc->Load('samplexml.svg'); $tagName > = $xdoc->getElementsByTagName('image')->item(0); > $attribNode = > $tagName->getAttributeNode('xlink:href'); > > echo "Attribute Name : > ".$attribNode->name; echo "<br > />Attribute Value : > ".$attribNode->value; ?> Here is samplexml.svg: > <svg> <g> <title>Test title</title> > <image x="0" y="0" width="744" > height="1052" > xlink:href="image1.png"/> </g> </svg> Please help me, how to change this attribute value. Regards, rafiq7s

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  • Passing jquery JSON from Codeigniter controller to view

    - by dede
    I've been struggling to make it work, but cannot pass the inserted data from the controler to the view in CI using JSON. The input value from the form is successfully inserted into the database, but cannot make it appear in the view. This is my view file ajax_view.php: <script type="text/javascript" src="<?php echo base_url(); ?>js/jquery-1.4.2.min.js"></script> $(document).ready(function(){ $("#submit").click(function(){ var inp = $('#inp').val(); $.post("ajax/ajax_input", { 'send' : inp }, function(data){ alert(data.input_text); }, "json"); }); }); </script> </head> <body> <form id="form1" method="post" action=""> <label for="inp">Text</label> <input type="text" name="inp" id="inp" /> <label for="submit"></label> <input type="submit" name="submit" id="submit" value="Submit" /> And this is the ajax_input method of the ajax.php controller: <?php // Initializing controller ..... // ............................. //ajax method function ajax_input(){ $var_1 = trim($this->input->post('send')); $array = array('input_text' => $var_1); echo json_encode($array); $this->db->insert('ajax',$array); } Trying to debug it with Firebug, it gives me that data.input_text is empty. What am I doing wrong? EDIT: I'm using XAMPP on Win, so is it posible that json configuration is the problem?

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  • Run a command as cron would but from the command line.

    - by BCS
    I have a script that I'm trying to run from cron. When I run it from bash, it work just fine. However when I let cron do it's thing, I get a: myscript.sh: line 122: syntax error: unexpected end of file What I want is a way to run a command as if it was a cron job, but do it in my shell. As a side note: does anyone know what would be differnt under cron? (the script already has a #!/bin/sh line) To answer my own question: I added this to my crontab: * * * * * bcs for ((i=1; i <= 55; i++)) ; do find ~/.crontemp/ -name '*.run' -exec "{}" ";" ; sleep 1; done` and created this script: #!/bin/sh tmp=$(mktemp ~/.crontemp/cron.XXXXX) mknod $tmp.pipe p mv $tmp $tmp.pre echo $* '>' $tmp.pipe '1>&2' >> $tmp.pre echo rm $tmp.run >> $tmp.pre chmod 700 $tmp.pre mv $tmp.pre $tmp.run cat $tmp.pipe rm $tmp.pipe With that, I can run an arbitrary command with a delay of not more than one second. (And yes, I know there are all kinds of security issue involved in that)

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  • How to send a future email using AT command.

    - by BHare
    I just need to send one email into the future, so I figured i'd be best at using at rather than using cron. This is what I have so far, its messy and ugly and not that great at escaping: <pre> <?php $out = array(); // Where is the email going? $email = "[email protected]"; // What is the body of the email (make sure to escape any double-quotes) $body = "This is what is actually emailed to me"; $body = escapeshellcmd($body); $body = str_replace('!', '\!', $body); // What is the subject of the email (make sure to escape any double-quotes) $subject = "It's alive!"; $subject = escapeshellcmd($subject); $subject = str_replace('!', '\!', $subject); // How long from now should this email be sent? IE: 1 minute, 32 days, 1 month 2 days. $when = "1 minute"; $command= <<<END echo " echo \"$body\" > /tmp/email; mail -s \"$subject\" $email < /tmp/email; rm /tmp/email; " | at now + $when; END; $ret = exec($command, $out); print_r($out); ?> </pre> The output should be something like warning: commands will be executed using /bin/sh job 60 at Thu Dec 30 19:39:00 2010 However I am doing something wrong with exec and not getting the result? The main thing is this seem very messy. Is there any alternative better methods for doing this? PS: I had to add apache's user (www-data for me) to /etc/at.allow ...Which I don't like, but I can live with it.

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  • Problem with Xpath PHP

    - by user294597
    Im tring to access some links through Google using xpath. The below does works fine and all the links are shown. $query = $xpath->evaluate("/html/body//a"); for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('href'); echo $url."<br>"; } But when i try the below xpath nothing is shown..Im sure that the xpath is correct coz its evaluated and the result is shown in xpather.. /html/body[@id='gsr']/div[@id='cnt']/div[@id='res']/div[1]/ol/li/div//cite for ($x=0 ; $x < $query -> length; $x++) { $href=$query->item($x); $url=$href->getAttribute('cite'); echo $url."<br>"; } can some one please tell me what i am doin wrong? any help will be much appreciated

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  • How do you slow down the output from a DOS command

    - by JW
    I have lots of experience of writing php scripts that are run in the context of a webserver and almost no epxerience of writing php scripts for CLI or GUI output. I have used the command line for linux but do not have much expereince with DOS. Lets say I have php script that is: <?php echo('Hello world'); for ($idx = 0 ; $idx < 100 ; $idx++ ) { echo 'I am line '. $idx . PHP_EOL; } Then, I run it in my DOS Command prompt: # php helloworld.php Now this will spurt out the output quckly and i have to scroll the DOS command window up to see the output. I want to see the output one 'screen full' at a time. How do you do that from the perspective of a DOS user? Furthermore, although this is not my main main question, I would be also interested in knowing how to make the php script 'wait for input' from the command prompt.

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  • Problem when use compiled .A with simulator mode

    - by Paska
    Hi all, i have a lib .a that run only in device mode. My sdk vers is 4.2 with xcode 3.2.x. In simulator, compile correctle with no warning and no errors, but in run mode (simulator) it crash with this error: Detected an attempt to call a symbol in system libraries that is not present on the iPhone: strtod$UNIX2003 called from function pj_init in image MyAPP. If you are encountering this problem running a simulator binary within gdb, make sure you 'set start-with-shell off' first Program received signal: “SIGABRT”. I try to clean, rebuild and set "set start-with-shell off" from terminal in this way: cd ~ echo '' >> .gdbinit echo 'set start-with-shell 0' >> .gdbinit Restarted all, but nothing. The problem don't wont to resolve! Is there any tag or property that i forgotted to set in the options? In other linker flag is there only "-ObjC". It's very important to solve this issue... any idea please? thanks, A EDIT: It's my lib, compiled in simulator mode! EDIT: It run only with Simulator 4.1. Don't work with iphone 4.0, 4.2 and ipad 3.2 (all simulator).

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  • How to populate html combo box with mysql data

    - by user225269
    Please help, I'm having trouble loading mysql data on the combo box. The data that I'm loading is 1 column from a table. Here is my current code, and it crashed firefox for some reason: <td colspan=”2?>Religion</TD> <td> <select name="REL" onClick="submitCboSemester();"> <?php $query_disp="SELECT * FROM Religion ORDER BY RID"; $result_disp = mysql_query($query_disp, $conn); while($query_data = mysql_fetch_array($result_disp)) { ?> <option value="<? echo $query_data["RID"]; ?>"<?php if ($query_data["RID"]==$_POST['REL']) {?>selected<? } ?>><? echo $query_data["RELIGION"]; ?></option> <? } ?> </select> </td> The column is RELIGION and it ID is RID How do I populate the combo box with all the data in the column RELIGION

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  • How to control table width in code ignator?

    - by riad
    Dear Exparts, In codeIgnator frame work the below is my code working properly.But i cannot control the table width. So,when a long value come into the table then table going to extra large width.But i need to wrap the outcomes data.So,How i can fixed the table width? Pls see my code below.. ///controller code/// $config['base_url'] = base_url().'Search_Controller/songSearchPage/'; $config['total_rows'] = $this->db->count_all('tbl_rbt'); $config['per_page'] = '5'; $config['full_tag_open'] = '<p>'; $config['full_tag_close'] = '</p>'; $this->pagination->initialize($config); //load the model and get results $data[]=array(); $data['extraHeadContent'] = '<script type="text/javascript" src="' . base_url() . 'js/song_search.js"></script>'; $data['results'] = $this->search_model->getSongResult($config['per_page'],$this->uri->segment(3)); // load the HTML Table Class $this->table->set_heading('Song Name','Album Name','Artist Name'); // load the view $this->load->view('song_search_page',$data); /////view code///// <div class="song_element_output"> <?php echo $this->table->generate($results); ?> <?php echo $this->pagination->create_links(); ?> </div> Could anybody can help me to control the table??? Thanks Riad

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  • execute a string of PHP code on the command line

    - by Matthew J Morrison
    I'd like to be able to run a line of PHP code on the command line similar to how the following options work: :~> perl -e "print 'hi';" :~> python -c "print 'hi'" :~> ruby -e "puts 'hi'" I'd like to be able to do: :~> php "echo 'hi';" I've read that there is a -r option that can do what I need for php, however it doesn't appear to be available when I try to use it. I've tried using PHP 5.2.13 and PHP 4.4.9 and neither have an -r option available. I wrote this script (that I called run_php.php) - which works, but I'm not a huge fan of it just because I feel like there should be a more "correct" way to do it. #!/usr/bin/php5 -q <?php echo eval($argv[1]); ?> My question is: is there a -r option? If so, why is it not available when I run --help? If there is no -r option, what is the best way to do this (without writing an intermediary script if possible)? Thanks!

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  • Weird problem with PHP mail() under Linux.

    - by Vilx-
    This is the case when it "works on my machine". Except that my machine is Windows, and the target is some sort of Linux. The idea is that the mail() function puts a newline between the MIME-Version and Content-Type headers, thus breaking the whole thing. Here's the code, simpliefied as much as possible: <?php $HTMLPart = chunk_split(base64_encode('<html><body style="color: red">Test.</body></html>')); $PlaintextPart = chunk_split(base64_encode('>>> TEST <<<')); $Headers =<<<AKAM From: "My Test" <[email protected]> Reply-To: [email protected] MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="9-1410065408-1410065408=:27514" AKAM; $Body =<<<AKAM This is a multi-part message in MIME format. --9-1410065408-1410065408=:27514 Content-Type: text/plain; charset="windows-1252" Content-Transfer-Encoding: base64 $PlaintextPart --9-1410065408-1410065408=:27514 Content-Type: text/html; charset="windows-1252" Content-Transfer-Encoding: base64 $HTMLPart --9-1410065408-1410065408=:27514-- AKAM; echo 'Try 3: '; echo mail('[email protected]', 'Testmail', $Body, $Headers) ? 'WIN' : 'FAIL'; ?>

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  • jquery autocomplete: works for first value, how to enable it for next?

    - by Toni Michel Caubet
    hello there! I'm using autocomplete so user can easly enter data on inputs, like this: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> $a = $b its an array with a result like: 'help','please',i','need','to,'be able to', 'select next item',' with autocomplete'; and i checked the ui documentation, but it doesn't fith with my source method.. any idea? I'm trying like this (edited with Bugai13 aportation): <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>], multiple: true, multipleSeparator: ", ", matchContains: true }); } </script> but i don't know how to do it.. any idea? are .push and .pop functions from the autocomplete? or shall i define, them? thanks again! PS: i'm getting adicted to this site! PS: come on dudes, i think the answer will be very usefull for many people PS: is it allowed to offer paypal reward?

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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  • How could I cache images that I'm pulling from a magento database through ajax?

    - by wes
    Here's script being called through ajax: <?php require_once '../app/Mage.php'; umask(0); /* not Mage::run(); */ Mage::app('default'); $cat_id = ($_POST['cat_id']) ? $_POST['cat_id'] : NULL; try { $category = new Mage_Catalog_Model_Category(); $category->load($cat_id); $collection = $category->getProductCollection(); $output = '<ul>'; foreach ($collection as $product) { $cProduct = Mage::getModel('catalog/product'); $cProduct->load($product->getId()); $output .= '<li><img id="'.$product->getId().'" src="' . (string)Mage::helper('catalog/image')->init($cProduct, 'small_image')->resize(75) . '" class="thumb" /></li>'; } $output .= '</ul>'; echo $output; } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } I'm just passing in the Category ID, which I've tacked onto the navigation links, then doing some work to eventually just pass back all product images in that category. I'm using this on a drag and drop build-a-bracelet type of application, and the amount of images returned is sometimes in the 500s. So it get's pretty held up during transmission, sometimes 10 seconds or so. I know I'd do good by caching them some way, just not sure how to go about it. Any help is much appreciated. Thanks. -Wes

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