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  • Unable to parse variable length string separated by delimiter

    - by Technext
    Hi, I have a problem with parsing a string, which consists only of directory path. For ex. My input string is Abc\Program Files\sample\ My output should be Abc//Program Files//sample The script should work for input path of any length i.e., it can contain any no. of subdirectories. (For ex., abc\temp\sample\folder\joe) I have looked for help in many links but to no avail. Looks like FOR command extracts only one whole line or a string (when we use ‘token’ keyword in FOR syntax) but my problem is that I am not aware of the input path length and hence, the no. of tokens. My idea was to use \ as a delimiter and then extract each word before and after it (), and put the words to an output file along with // till we reach the end of the string. I tried implementing the following but it did not work: @echo off FOR /F "delims=\" %%x in (orig.txt) do ( IF NOT %%x == "" echo.%%x//output.txt ) The file orig.txt contains only one line i.e, Abc\Program Files\sample\ The output that I get contains only: Abc// The above output contains blank spaces as well after ‘Abc//’ My desired output should be: Abc//program Files//sample// Can anyone please help me with this? Regards, Technext

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  • how to pass value to controller??

    - by rajesh
    When I try to pass url value to controller action, action is not getting the required value. I'm sending the value like this: function value(url,id) { alert(url); document.getElementById('rating').innerHTML=id; var params = 'artist='+id; alert(params); // var newurl='http://localhost/songs_full/public/eslresult/ratesong/userid/1/id/27'; var myAjax = new Ajax.Request(newurl,{method: 'post',parameters:params,onComplete: loadResponse}); //var myAjax = new Ajax.Request(url,{method:'POST',parameters:params,onComplete: load}); //alert(myAjax); } function load(http) { alert('success'); } and in the controller I have: public function ratesongAction() { $user=$_POST['rating']; echo $user; $post= $this->getRequest()->getPost(); //echo $post; $ratesongid= $this->_getParam('id'); } But still not getting the result. I am using zend framework.

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  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

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  • Reference problem when returning an object from array in PHP

    - by avastreg
    I've a reference problem; the example should be more descriptive than me :P I have a class that has an array of objects and retrieve them through a key (string), like an associative array: class Collection { public $elements; function __construct() { $this->elements = array(); } public function get_element($key) { foreach($this->elements as $element) { if ($element->key == $key) { return $element; break; } } return null; } public function add_element ($element) { $this->elements[] = $element; } } Then i have an object (generic), with a key and some variables: class Element { public $key; public $another_var; public function __construct($key) { $this->key = $key; $this->another_var = "default"; } } Now, i create my collection: $collection = new Collection(); $collection->add_element(new Element("test1")); $collection->add_element(new Element("test2")); And then i try to change variable of an element contained in my "array": $element = $collection->get_element("test1"); $element->another_var = "random_string"; echo $collection->get_element("test1")->another_var; Ok, the output is random_string so i know that my object is passed to $element in reference mode. But if i do, instead: $element = $collection-get_element("test1"); $element = null; //or $element = new GenericObject(); $element-another_var = "bla"; echo $collection-get_element("test1")-another_var; the output is default like if it lost the reference. So, what's wrong? I have got the references to the variables of the element and not to the element itself? Any ideas?

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  • Appending a TR to Table Not Formatting Correctly

    - by TimNguyenBSM
    My PHP script is sending back an array: $currentStatus = ( isset( $status ) ) ? "1" : "0"; $html = "<tr><td>" . $email . "</td><td>" . ( ( $status->type == 0 ) ? "View Only" : ( ( $status->type == 1 ) ? "View & Mark" : "View, Mark & Edit" ) ) . "</td><td>Invited</td></tr>"; echo json_encode( array( $html, $currentStatus ) ); Then my jquery is appending this to the table: ... success: function( result ) { var resultArray = eval( result ); $( "#myTable tr:last").append( resultArray[0] ); ... } Problem is, when it prints, it prints the following extra marks: [email protected]<\/td> View Only<\/td> Invited<\/td><\/tr>","1"] If I only echo the HTML it appends to table just fine, but I cant do that because I need the $currentStatus back too to do something with it. Thanks!

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  • PHP: parse $_FILES[] data in multidimesional array

    - by superUntitled
    Example form here: http://jsfiddle.net/superuntitled/uaTtx/1/ I have a form that allows for dynamic duplication of the form fields. The form allows for file uploads and text input, so the data is sent in both $_POST and $_FILES arrays. The the initial set of inputs look like this: <input type="text" name="question[1][text]" /> <input type="file" name="question[1][file]" /> <input type="text" class="a" name="answer[1][text][]" /> <input type="file" name="answer[1][file][]" /> When duplicated the fields are incremented, they look like this: <input type="text" name="question[2][text]" /> <input type="file" name="question[2][file]" /> <input type="text" class="a" name="answer[2][text][]" /> <input type="file" name="answer[2][file][]" /> To complicate matters, the "answer" form fields can also be duplicated (thus the [] at the end of the 'answer' name array. How can I parse the posted $_FILES array? I have tried something like this: foreach ($_FILES['question'] as $p_num) { echo $p_num['file']['name']; foreach ($_FILES['answer'] as $a_num) { echo $a_num['file']['name']; } } but I get an "Undefined index: file... " error. How can I parse out the posted values.

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  • Recaptcha with Ajax error

    - by Brandon
    I'm having trouble validating a recaptcha input. Heres my code: // Validate Recaptcha Input var challenge = $("#recaptcha_challenge_field").val(); var response = $("#recaptcha_response_field").val(); var dataString = 'recaptcha_challenge_field=' + challenge + '&recaptcha_response_field=' + response; var html = $.ajax({ type: "POST", url: "PHP/recaptchaverify.php", data: dataString, async: true }).responseText; console.log(html); if(html == 'accept') { alert("CORRECT"); } else { alert("The reCAPTCHA wasn't entered correctly. Go back and try it again."); $("#recaptcha_response_field").focus(); Recaptcha.reload(); return false; } Now I passed my variables to recpatchaverify.php require_once('../scripts/recaptcha-php/recaptchalib.php'); $privatekey = "MYKEY"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { // What happens when the CAPTCHA was entered incorrectly echo "error"; } else { // Your code here to handle a successful verification echo "accept"; } Now my problem is the html variable is displaying "accept" whenever I enter the Recaptcha correctly, but it won't work in the IF statement?

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  • PHP/Javascript: Restart Form Button Isn't Working, Code Insde

    - by Josh K
    Basically I want a confirmation box to pop up when they click the button asking if they sure they want to restart, if yes, then it destroys session and takes them to the first page. Heres what i got... echo "<form id=\"form\" name=\"form\" method=\"post\" action=\"nextpage.php\">\n"; echo " <input type=\"button\" name='restart' value='Restart' id='restart' onclick='restartForm()' />"; and for the script... <script type=\"text/javascript\"> <!-- function restartForm() { var answer = confirm('Are you sure you want to start over?'); if (answer) { form.action=\"firstpage.php\"; session_destroy(); form.submit(); } else alert ('Restart Cancelled'); } // -- </script>"; EDIT: Note that pressing the button brings up the confirm box, but if you click okay nothing happens sometimes. Sometimes if u click cancel it still submits the form (To the original action)

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  • Fatal error: Call to a member function escape() on a non-object in .....on line 10

    - by danyo
    i am making a simple javascript login form for wordpress. i have the form submitting to the following bit of php to handle the login: <?php get_header(); global $user_ID; if (!$user_ID) { if($_POST){ //We shall SQL escape all inputs $username = $wpdb->escape($_REQUEST['username']); $password = $wpdb->escape($_REQUEST['password']); $remember = $wpdb->escape($_REQUEST['rememberme']); if($remember) $remember = "true"; else $remember = "false"; $login_data = array(); $login_data['user_login'] = $username; $login_data['user_password'] = $password; $login_data['remember'] = $remember; $user_verify = wp_signon( $login_data, false ); //wp_signon is a wordpress function which authenticates a user. It accepts user info parameters as an array. if ( is_wp_error($user_verify) ) { echo "<span class='error'>Invalid username or password. Please try again!</span>"; exit(); } else { echo "<script type='text/javascript'>window.location='". get_bloginfo('url') ."'</script>"; exit(); } } else { //get_header(); ?> any ideas on why i am getting the error? Cheers, Dan

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  • Problem with RSA-encrypting a string in PHP and passing it to .NET service

    - by jonasaxelsson
    I need to call a web service that requires a login url containing an RSA encrypted, base_64 encoded and url-encoded login data. I don't have a formal php training, but even for me it seems like an easy task, however when calling the service I get an 'Invalid Format' response. What am I doing wrong and is there another way to come up with the encrypted string? Code example below. Thank you for your help! http://www.edsko.net/misc/ for encryption. $message = '?id=112233&param1=hello&[email protected]&name=Name'; $keyLength = '2048'; $exponent = '65537'; $modulus = '837366556729991345239927764652........'; $encryptedData = rsa_encrypt($message, $exponent, $modulus, $keyLength); $data = urlencode(base64_encode($encryptedData)); $loginurl = 'http://www.somedomain.com/LoginWB.aspx?Id=9876&Data='.$data; echo '<iframe src="'.$loginurl.'" width="570px" height="800px">'; echo '</iframe>'; ?

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  • change php variable on click event

    - by Claudiu
    I want to change php variable ($start and $end called by var b1 and var b2) if the user clicks on button. Now I know that php is server side, but how can I do it? I read something about using $get but I don't know how to implement it: <?php if ( is_user_logged_in() ) { ?> <input type="submit" value="Start Chat" id="start_chat" style="position: absolute; top: 30px; left: 10px;" /> <?php } ?> <script> jQuery('#start_chat').click(function(){ $(this).data('clicked', true); }); var b1 = '<?php echo $start; ?>'; var b2 = '<?php echo $end; ?>'; if(jQuery('#start_chat').data('clicked')) { // change var b1 and b2 } else { // do not change anything } </script> <div id="eu_la"> <?php $start = strtotime('9:30'); $end = strtotime('12:30'); $timenow = date('U'); if((date('w') == 4) && ($timenow >= $start && $timenow <= $end)) { // day 2 = Tuesday include('facut_mine.php'); } else { do_shortcode('[upzslider usingphp=true]'); } ?>

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • remove row on click on specific td of that row by jquery

    - by I Like PHP
    i have an table <table class="oldService"> <thead> <th>name</th> <th>age</th> <th>action</th> </thead> <tbody> <?php foreach($array as $k=>$v){ ?> <tr> <td><?php echo $k[name] ?></td> <td><?php echo $k[age]?></td> <td id="<?php $k[id]" class="delme">X</td> </tr> <?php } ?> </tbody> <table> now i want to delete any row by clicking on X of each row except first and last row, and also need to confirm before deletion. i used below jquery <script type="text/javascript"> jQuery(document).ready(function(){ jQuery('table.oldService>tbody tr').not(':first').not(':last').click(function(){ if(confirm('want to delete!')){ jQuery(jQuery(this).addClass('del').fadeTo(400, 0, function() { jQuery(this).remove()})); jQuery.get('deleteService.php', {id:jQuery(this).attr('id')}); } else return false;}); }); </script> this is working perfect,but it execute by click on that row( means any td), i want that this event only occour when user click on X(third td) . please suggest me how to modify this jquery so that the event occur on click of X.

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  • Redirect in codeigniter after login

    - by edelweiss
    Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

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  • Variable won't store in session

    - by Mittens
    So I'm trying to store the "rank" of a user when they log in to a control panel which displays different options depending on the given rank. I used the same method as I did for storing and displaying the username, which is displayed on the top of each page and works just fine. I can't for the life of me figure out why it won't work for the rank value, but I do know that it is not saving it in the session. Here is the bit that's not working; $username = ($_POST['username']); $password = hash('sha512', $_POST['password']); $dbhost = 'mysql:host=¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦;dbname=¦¦¦¦¦¦¦¦¦¦¦'; $dbuser = '¦¦¦¦¦¦¦¦¦¦¦'; $dbpassword = '¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦'; try { $db = new PDO($dbhost, $dbuser, $dbpassword); $statement = $db->prepare("select password from users where email = :name"); $statement->execute(array(':name' => $username)); $result = $statement->fetch(); $pass = $result[password]; $rank = $result[rank];} catch(PDOException $e) {echo $e->getMessage();} if ($password == $pass) { session_start(); $_SESSION['username'] = $username; $_SESSION['rank'] = $rank; header('Location: http://¦¦¦¦¦¦¦¦¦.ca/manage.php'); } else{ include'../../includes/head.inc'; echo '<h1>Incorrect username or password.</h1>'; include'../../includes/footer.inc'; } I'm also new to the whole PDO thing, hence why my method of authenticating the password is pretty sketchy.

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  • How to evaluate json member using variable ?

    - by Miftah
    Hi i've got a problem evaluating json. My goal is to insert json member value to a function variable, take a look at this function func_load_session(svar){ var id = ''; $.getJSON('data/session.php?load='+svar, function(json){ eval('id = json.'+svar); }); return id; } this code i load session from php file that i've store beforehand. i store that session variable using dynamic var. <?php /* * format ?var=[nama_var]&val=[nilai_nama_var] */ $var = $_GET['var']; $val = $_GET['val']; $load = $_GET['load']; session_start(); if($var){ $_SESSION["$var"] = $val; echo "Store SESSION[\"$var\"] = '".$_SESSION["$var"]."'"; }else if($load){ echo $_SESSION["$load"]; } ?> using firebug, i get expected response but i also received error uncaught exception: Syntax error, unrecognized expression: ) pointing at this eval('id = json.'+svar); i wonder how to solve this

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  • Why won't the following PDO transaction won't work in PHP?

    - by jfizz
    I am using PHP version 5.4.4, and a MySQL database using InnoDB. I had been using PDO for awhile without utilizing transactions, and everything was working flawlessly. Then, I decided to try to implement transactions, and I keep getting Internal Server Error 500. The following code worked for me (doesn't contain transactions). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } Then I attempted to utilize transactions with the following code (which doesn't work). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->beginTransaction(); $dbh->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); $dbh->commit(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } When I run the previous code, I get an Internal Server Error 500. Any help would be greatly appreciated! Thanks!

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  • Bash script not working on a new dedicated server

    - by Scott
    Recently I have migrated to the new dedicated server which is running on the same operating system - FreeBSD 8.2. I got a root account access and all permissions have been set properly. My problem is that, the bash script I was running on the old server doesn't works on the new machine, the only error appearing while running the script is: # sh script.sh script.sh: 3: Syntax error: word unexpected (expecting ")") Here is the code itself: #!/usr/local/bin/bash PORTS=(7777:GAME 11000:AUTH 12000:DB) MESSG="" for i in ${PORTS[@]} ; do PORT=${i%%:*} DESC=${i##*:} CHECK=`sockstat -4 -l | grep :$PORT | awk '{print $3}' | head -1` if [ "$CHECK" -gt 1 ]; then echo $DESC[$PORT] "is up ..." $CHECK else MESSG=$MESSG"$DESC[$PORT] wylaczony...\n" if [ "$DESC" == "AUTH" ]; then MESSG=$MESSG"AUTH is down...\n" fi if [ "$DESC" == "GAME" ]; then MESSG=$MESSG"GAME is down...\n" fi if [ "$DESC" == "DB" ]; then MESSG=$MESSG"DB is down...\n" fi fi done if [ -n "$MESSG" ]; then echo -e "Some problems ocurred:\n\n"$MESSG | mail -s "Problems" [email protected] fi I don't really code in bash, so I don't know why this happend...

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  • removing a case clause: bash expansion in sed regexp: X='a\.b' ; Y=';;' sed -n '/${X}/,/${Y}/d'

    - by ChrisSM
    I'm trying to remove a case clause from a bash script. The clause will vary, but will always have backslashes as part of the case-match string. I was trying sed but could use awk or a perl one-liner within the bash script. The target of the edit is straightforward, resembles: $cat t.sh case N in a\.b); #[..etc., varies] ;; esac I am running afoul of the variable expansion escaping backslashes, semicolons or both. If I 'eval' I strip my backslash escapes. If I don't, the semi-colons catch me up. So I tried subshell expansion within the sed. This fouls the interpreter as I've written it. More escaping the semi-colons doesn't seem to help. X='a\.b' ; Y=';;' sed -i '/$(echo ${X} | sed -n 's/\\/\\\\/g')/,/$(echo ${Y} | sed -n s/\;/\\;/g')/d t.sh And this: perl -i.bak -ne 'print unless /${X}/ .. /{$Y}/' t.sh # which empties t.sh and eval perl -i.bak -ne \'print unless /${X}/ .. /{$Y}/' t.sh # which does nothing

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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • jquery - DOM traversal question

    - by David
    Hi, Basically what I have here is a button that adds a new list item to an unordered list. Within this list item is a dropdown box (.formSelector) that when changed triggers an ajax call to get the values for another dropdown box (.fieldSelector) in the same list item. The problem is on this line: $(this).closest(".fieldSelector").append( If I change it to $(".fieldSelector").append( the second box updates correctly. The problem with this is that when I have multiple list items it updates every dropdown box on the page with the class fieldSelector, which is undesirable. How can I traverse the DOM to just pick the fieldSelector in the current list item? Any help is greatly appreciated. Complete code: $("button", "#newReportElement").click(function() { $("#reportElements").append("<li class=\"ui-state-default\"> <span class=\"test ui-icon ui-icon-arrowthick-2-n-s \"></span><span class=\"ui-icon ui-icon-trash deleteRange \"></span> <select name=\"form[]\" class=\"formSelector\"><? foreach ($forms->result() as $row) { echo "<option value='$row->formId'>$row->name</option>"; }?></select><select class=\"fieldSelector\" name=\"field[]\"></select></li>"); $(".deleteRange").button(); $('.formSelector').change(function() { var id = $(this).val(); var url = "<? echo site_url("report/formfields");?>" + "/" + id; var atext = "ids:"; $.getJSON(url, function(data){ $.each(data.items, function(i,item){ $(this).closest(".fieldSelector").append( $('<option></option>').val(item.formId).html(item.formLabel) ); }); }); }); return false; });

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  • retrieve only sub-pages (wordpress)

    - by Radek
    I want to list all sub-pages only one level though of one particular page. I was reading Function Reference/get pages and thought that $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; will do the trick but it is not working. It lists all pages on the same level like the page I call that code from. If I omit parent option I will get all pages even with sub-pages that I want. But I want only sub-pages. The whole function is like function about_menu(){ if (is_page('about')){ $pages = get_pages( array( 'child_of' => $post->ID, 'parent' => $post->ID)) ; foreach($pages as $page) { ?> <h2><a href="<?php echo get_page_link($page->ID) ?>"><?php echo $page->post_title ?></a></h2> <?php } } } and mine is second one

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  • A stupid question about wordpress and php

    - by bubdada
    It may seem stupid question, but i've a serious problem... if you could check out orcik.net the thumbnail images does not appear. I figured out the reason but I don't know how to solve.. http://orcik.net/projects/thumb/orcikthumb.php?src=http://orcik.net/wp-content/uploads/2010/05/mac-safari-search-cache.png If you go to the above link you will get page not found error. However, if you go to the link below you'll get the thumbnail version of the image... http://orcik.net/projects/thumb/orcikthumb.php?src=/wp-content/uploads/2010/05/mac-safari-search-cache.png I'm using this piece of code on wordpress and the line appears like <a href="<?php the_permalink() ?>" rel="bookmark"> <img src="<?php bloginfo('template_directory'); ?>/includes/orcikthumb.php?src=<?php get_thumbnail($post->ID, 'full'); ?>&amp;h=<?php echo get_theme_mod($height); ?>&amp;w=<?php echo get_theme_mod($width); ?>&amp;zc=1" alt="<?php the_title(); ?>" /> </a> Thus, I believe I can't change the directory of image. But I could not figure out why I am getting page not found error. Is that might be CHMOD'es??? or something else?? Thanks

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  • post values to external page explicitly PHP

    - by JPro
    Hi, I want to post values to a page through a hyperlink in another page. Is it possible to do that? Let's say I have a page results.php which has the starting line, <?php if(isset($_POST['posted_value'])) { echo "expected value"; // do something with the data } else { echo "no the value expected"; } If from another page say link.php I place a hyperlink like this: <a href="results.php?posted_value=1"> , will this be accepetd by the results page? If instead if I replace the above starting line with if(isset($_REQUEST['posted_value'])), will this work? I believe the above hyperlink evaluates to GET, but since the only visibility difference between GET and POST that is you can see parameters in the address bar with GET But, is there any other way to place a hyperlink which can post values to a page? or can we use jquery in the place of hyperlink to POST the values? Can anyone please suggest me something on this please? Thanks.

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  • What is wrong with this php loop?

    - by Mark R
    I made a loop but it doesn't work. here's what I did: <?php if(is_tree('4')) { ?> <?php $show_after_p = 2; $content = apply_filters('the_content', $post->post_content); if(substr_count($content, '<p>') > $show_after_p) { $contents = explode("</p>", $content); $p_count = 1; foreach($contents as $content) { echo $content; if($p_count == $show_after_p) { ?> YOUR AD CODE GOES HERE < ? } echo "</p>"; $p_count++; } } ?> <?php else : ?> <?php the_content('<p class="serif">Read the rest of this page &raquo;</p>'); ?> <?php endif; } ?> I need to make it work but don't know how. I'm guessing it's a simple syntax error I'm not seeing?

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