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Error or not and insert to database mysql

- by Azzyh

Why wont this work? <?php include "top.php"; include "connect.php"; if(isset($_POST["submit"])) { $error = ""; if(empty($_POST["name"])) { $error .= "Du glömde märket!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att bedömma märket!<br>"; if(empty($_POST["worth"])){ $error .= "Du glömde att välja vilken klass den hör till!<br>"; if(empty($_POST["username"])){ $error .= "Du glömde att skriva ditt namn!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att skriva någonting?!!<br>"; }}}}} if(!empty($error)){ echo $error; }else{ $name = $_POST["name"]; $rating = $_POST["rating"]; $worth = $_POST["worth"]; $favorite = $_POST["favorite"]; $username = $_POST["username"]; $description = $_POST["description"]; mysql_query("INSERT INTO brands (name, rating, worth, favorite, username, description) VALUES ('$name', '$rating', '$worth', '$favorite', '$username', '$description')"); echo "<span style='color: green'>Yir yir, <a href='brand.php'>klicka här för att gå till Märken.</a></span>"; } } It doesnt come with errors it just say the succeed message like it has inserted to database

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php while loop throwing a error over a $var < 10 statement

- by William

Okay, so for some reason this is giving me a error as seen here: http://prime.programming-designs.com/test_forum/viewboard.php?board=0 However if I take away the '&& $cur_row < 10' it works fine. Why is the '&& $cur_row < 10' causing me a problem? $sql_result = mysql_query("SELECT post, name, trip, Thread FROM (SELECT MIN(ID) AS min_id, MAX(ID) AS max_id, MAX(Date) AS max_date FROM test_posts GROUP BY Thread ) t_min_max INNER JOIN test_posts ON test_posts.ID = t_min_max.min_id WHERE Board=".$board." ORDER BY max_date DESC", $db); $num_rows = mysql_num_rows($sql_result); $cur_row = 0; while($row = mysql_fetch_row($sql_result) && $cur_row < 10) { $sql_max_post_query = mysql_query("SELECT ID FROM test_posts WHERE Thread=".$row[3].""); $post_num = mysql_num_rows($sql_max_post_query); $post_num--; $cur_row++; echo''.$cur_row.'<br/>'; echo'<div class="postbox"><h4>'.$row[1].'['.$row[2].']</h4><hr />' .$row[0]. '<br /><hr />[<a href="http://prime.programming-designs.com/test_forum/viewthread.php?thread='.$row[3].'">Reply</a>] '.$post_num.' posts omitted.</div>'; }

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Facebook fbAsyncInit firing twice

- by JoelD

I'm using Facebook's Javascript SDK to allow login/logout, and my problem is that when I use their window.fbAsyncInit call to initiate the FB session, it always fires twice. I've included a simplified code sample. I'd appreciate any help! <html><head> <script type="text/javascript"> ...some of my own functions, not related to Facebook... </script> </head> <body> <div id="fb-root"></div> <script> window.fbAsyncInit = function() { FB.init({ appId : '<?php echo FACEBOOK_APPID; ?>', session : <?php echo json_encode($session); ?>, status:false, cookie:true, xfbml: true }); alert("1"); FB.getLoginStatus(function(response) { if(response.session) { ...do stuff... } else { ...do other stuff...} }); }; alert("2"); </script> ...page contents... </body></html> The "2" alert fires a single time, and then the "1" alert fires twice.

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Is there a way to access Joomla 1.5 user variables (like user id) from a Flex 4 application using a PHP Data Service?

- by Zachary G. Schroeder

I have written a script (in two files) that correctly displays a Joomla user id, like this: //this is testy.php define( '_JEXEC', 1 ); define('JPATH_BASE', dirname(FILE)); define( 'DS', DIRECTORY_SEPARATOR ); require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' ); require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' ); $mainframe =& JFactory::getApplication('site'); $id = JFactory::getUser()-id; The above file is located in the Joomla root folder. The other file is in a different directory and is as follows: //this is testid.php include '../../joomla/testy.php'; echo $id; However, and here is the rub, when I change the "echo" to a "return" and put the second code snippet inside my Flex 4 Data Service script file, like this... function getUserId() { include '../../joomla/testy.php'; return $id; } ...I get a Flex error that says this: Fatal error: Class 'JRequest' not found in /var/www/html/joomla/libraries/joomla/import.php on line 33 I am extremely confused by this error and would appreciate any suggestions that the stackoverflow community may have. Thanks so much! Zach

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PHP Dom problem, how to insert html code in a particular div

- by sala_7

I am trying to replace the html code inside the div 'resultsContainer' with the html of $response. The result of my unsuccessful code is that the contents of 'resultsContainer' remain and the html of $response shows up on screen as text rather than being parsed as html. Finally, I would like to inject the content of $response inside 'resultContainer' without having to create any new div, I need this: <div id='resultsContainer'>Html inside $response here...</div> and NOT THIS: <div id='resultsContainer'><div>Html inside $response here...</div></div> // Set Config libxml_use_internal_errors(true); $doc = new DomDocument(); $doc->strictErrorChecking = false; $doc->validateOnParse = true; // load the html page $app = file_get_contents('index.php'); $doc->loadHTML($app); // get the dynamic content $response = file_get_contents('search.php'.$query); $response = utf8_decode($response); // add dynamic content to corresponding div $node = $doc->createElement('div', $response); $doc->getElementById('resultsContainer')->appendChild($node); // echo html snapshot echo $doc->saveHTML();

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JSON Returning Null in PHP

- by kira423

Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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PHP If/Else for Wordpress Custom Fields

- by HollerTrain

I have a site that is using custom fields, and I want to either show the content for the field if the field is being used, and if the field is not being used per a Post then of course don't show the contents of the fields. Seems my code below is not correct, as it is showing the content in the else block when the Post is not using any of the custom fields. Any help would be greatly appreciated! Here is the Post in question: http://beta.ohsinsider.com/insider-top-stories/workers%E2%80%99-compensation-may-not-shield-you-from-lawsuits-by-injured-workers Here is the Post Edit showing that the field I am calling in my code are not being used (http://screencast.com/t/aBjt1drIw). I have confirmed that when I do input the value for the custom field is it being outputted in the Post. Here is the code I am using: <?php $pdfurl = get_post_meta($post->ID, 'pdf', true); $wordurl = get_post_meta($post->ID, 'word', true); if( !empty($pdf) || !empty($word) ){ ?> <?php /* show nothing then */ } else { ?> <div id="post_downloads_box"> <h3 class="single_related_footer">Dfownload Now</h3> <div id="post_downloads_box_left"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'pdf', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_pdf_icon.jpg" /></a> </div> <div id="post_downloads_box_right"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'word', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_word_icon.jpg" /></a> </div> </div> <?php } ?>

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Require reasonably random results from an SQL SELECT query within a Joomla article (Cache enabled)

- by Shrinivas

Setup: Joomla website on LAMP stack I have a MySQL table containing some records, these are queried by a simple SELECT on the Joomla article, as pasted below. This specific Joomla website has Caching turned on in Joomla's Global Configuration. I need to randomize the order in which I display the resultset, each time the page is loaded. Regular php/mysql would offer me two approaches for this: 1. use 'order by RAND()' or any of a number of methods to allow a SELECT query to return reasonably random results. 2. once php gets the result from the SELECT into an array, shuffle the array to get a reasonably random order of array items. However, as this Joomla instance has Caching turned ON in its Global Configuration, either of the above approaches fails. The first time I load the page the order is randomized, however any further reloads do not cause the order to change, as the page is delivered from cache. The instant the Cache is disabled, both approaches (shuffle/order by rand) work perfectly. What am I missing? How do I override the Global Cache for this specific article? A very simple requirement, that is met by both php and mysql reasonably well, is blocked by the Joomla Cache that I cannot turn off. The php that returns results from the database. <pre> $db = JFactory::getDBO(); $select = "SELECT id FROM jos_mytable;"; //order by RAND() $db->setQuery($select); echo $db->getQuery(); //Show me the Query! $rows = $db->loadObjectList(); //shuffle($rows); foreach($rows as $row) { echo "$row->id"; }

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php code works with mamp but not on ubuntu server

- by user355510

Hello, I have start looking at a twitter php library http://github.com/abraham/twitteroauth, but i can't get it to work on my ubuntu server, but on my mac, with mamp it works without any problems. This is the code that don't won't to work on my server, but in mamp. Yes i have edit config file <?php /* Start session and load library. */ session_start(); require_once('twitteroauth/twitteroauth.php'); require_once('config.php'); /* Build TwitterOAuth object with client credentials. */ $connection = new TwitterOAuth(CONSUMER_KEY, CONSUMER_SECRET); /* Get temporary credentials. */ $request_token = $connection->getRequestToken(OAUTH_CALLBACK); /* Save temporary credentials to session. */ $_SESSION['oauth_token'] = $token = $request_token['oauth_token']; $_SESSION['oauth_token_secret'] = $request_token['oauth_token_secret']; /* If last connection failed don't display authorization link. */ switch ($connection->http_code) { case 200: /* Build authorize URL and redirect user to Twitter. */ $url = $connection->getAuthorizeURL($token); header('Location: ' . $url); break; default: /* Show notification if something went wrong. */ echo 'Could not connect to Twitter. Refresh the page or try again later.'; } I have enable php session on my ubuntu server, because this code works <?php session_start(); $_SESSION["secretword"] = "hello there"; $secretword = $_SESSION["secretword"] ; ?> <html> <head> <title>A PHP Session Example</title> </head> <body> <?php echo $secretword; ?> </body> </html>

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Create new table with Wordpress API

- by Fire G

I'm trying to create a new plugin to track popular posts based on views and I have everything done and ready to go, but I can't seem to create a new table using the Wordpress API (I can do it with standard PHP or with phpMyAdmin, but I want this plugin to be self-sufficient). I've tried several ways ($wpdb-query, $wpdb-get_results, dbDelta) but none of them will create the new table. function create_table(){ global $wpdb; $tablename = $wpdb->prefix.'popular_by_views'; $ppbv_table = $wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N); if(is_null($ppbv_table)){ $create_table_sql = "CREATE TABLE '".$tablename."' ( 'id' BIGINT(50) NOT NULL AUTO_INCREMENT, 'url' VARCHAR(255) NOT NULL, 'views' BIGINT(50) NOT NULL, PRIMARY KEY ('id'), UNIQUE ('id') );"; $wpdb->show_errors(); $wpdb->flush(); if(is_null($wpdb->get_results("SHOW TABLES LIKE '".$tablename."'" , ARRAY_N))) echo 'crap, the SQL failed.'; } else echo 'table already exists, nothing left to do.';}

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Uploading File Problem in PHP on Drupal

- by Nitz

I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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$_FILES is null, $_POST is not null

- by Cory Dee

When I am going to upload a file, my $_POST variable knows the file name, but the $_FILES variable is null. I've used this code before, so I'm really stumped. Here's what I'm using for input: <label for="importFile">Attach Resume:</label> <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input type="file" name="importFile" id="importFile" class="validate['required']"> And for processing: $uploaddir = "E:/Sites/OPL/2008/assets/apps/newjobs/resumes/"; $uploadfile = $uploaddir . time() . '-' . urlencode(basename($_FILES['importFile']['name'])); if (!move_uploaded_file($_FILES['importFile']['tmp_name'], $uploadfile)) { echo 'Error uploading file. Error number: ' . $_FILES['importFile']['error']; var_dump($_FILES['importFile']); echo $_POST['importFile']; die(); } Which is giving me this result: Error uploading file. Error number: NULL Maintaining The OPL Website.doc Any help would be greatly appreciated.

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Why doesn't this short php script send email?

- by RoryG

I can't seem to get my php script to send email. <?php echo "Does this page work?"; mail('my email address', 'test subject', 'test message'); ?> First, I have set the mail function settings in the php.ini file as follows: I checked my email account settings on outlook. It does not require authentication, its port is 25, and its type of encrypted connection is 'Auto'. Given this I configured my php.ini file accordingly: SMTP = ssl://smtp1.iis.com smtp_port = 25 Then I set: sendmail_from: my email address The echo statement prints out in the browser, so I know the php file is recognized and processed. But the browser also shows the following error: Warning: mail() [function.mail]: "sendmail_from" not set in php.ini or custom "From:" header missing in C:\xampp\htdocs\mailtest.php on line 3 I have clearly set the sendmail_from so I don't know what else to do. I have also tried removing the 'ssl://' part from the SMTP setting in the php.ini file, and configuring the php5.ini file. Which of these .ini files should I be configuring anyways?

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formatting mysql data for ouptut into a table

- by bsandrabr

Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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How to do this in a smart way

- by Azzyh

Hello SO. My websystem im coding with now is integrated from the originally phpBB system. With this i mean when you log on my websystem, you have actually logged into the forum from the login page. Now i came to the "log out" part, and i want to make it smart. Right now its a simply link with logout: <a href="<?php echo BASEDIR; ?>../../ucp.php?mode=logout&sid=<? echo $user->data['session_id']; ?>" style="margin-left: 14px; font-size: 10px;">- Log Out</a> As you see in the link it refers to the forum´s ucp.php?mode=logout, and you need to have the SID variable in it in order to log out right.. anyway.. I want to do this log out part in a smart way, i mean, not so you land on the forum´s "you have now been logged out", i want something maybe like run this page in background when you click, and then it refreshes the current page your on. Or should it be smarter just try to modify the phpbb file ucp.php? I think its hard coded, and not the way I am coding, so thats why i find it abit tricky. Thank you for your answers and examples on how this could be done, in a smart way..

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Why my autocomplete doesn't whant to be multiple ???

- by Toni Michel Caubet

please, give me a hand on this one; i'm trying to use autocomplete so user can enter tags by comma separated, example: 'autocomplete, jquery , next , last' ok, i had the autocomplete working by sending him an $array with all the tags of my website with the previous format aswell, this is my code: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); mostrar_notificacion('autocomplete_etiquetas_cargado?'); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> All i want it's user to select a tag, apply the ', ' and the autocomplete to be ready for next tag i'm trying with (i know they are diff id's, also diff inputs): <? $b = new ingrediente(0, ''); $c = $b->autocomplete_ingredientes(); ?> <script type="text/javascript"> function cargar_autocomplete_ingredientes(){ $("#ingredientes").autocomplete({ source: [<? echo $c; ?>], multiple: true, multipleSeparator: ", " }); } </script> But with out success.... 10€ via paypal if answered before 23h (its 21:50 now), it's not much, it's an incentive :P

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how to read uploaded files from xampp

- by user225269

I have this code for uploading files on the server: <tr> <td> <form enctype="multipart/form-data" action="uploadaction.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="100000" /> </td> </tr> <tr> <td> Select the image: <input name="uploadedfile" type="file" /> </td> <tr> <td> <input type="submit" value="Upload File" /> </form> </td> </tr> And here's the action form: <?php $target_path = "uploads/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> What php function will I use? Can you give me an example on how to read the file back and display it in the browser? Please help, thanks.

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Error after redirection using CakePHP

- by Praveen kalal

I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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how close a connection from server side that created by ajax from client side

- by saeid

I have this sample php code: <?php function response($a) { @ob_end_clean(); header("Connection: close"); ob_start(); echo $a; $length = ob_get_length(); header("Content-Length: $length"); ob_end_flush(); flush(); } response("test1"); sleep(5); echo "test2"; ?> now I make a connection to server from client by ajax. now I want to server only send "test1" to me and then close the connection. but connection not closed and wait 5 seconds and send me "test1 test2" !! this is response headers from server to me : X-Powered-By: PHP/5.3.27 Connection: close Vary: Accept-Encoding,User-Agent Content-Encoding: gzip Cache-Control: private, no-cache, no-store, ------revalidate, no-transform Transfer-Encoding: chunked Content-Type: text/html in response headers I do not see Content-Length header. is problem for this ?? or if not what I must do now for solving problem ??

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Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

- by ggfan

In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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php search database for row

- by Brenden Morley

Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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How to load data on option box in php

- by user225269

I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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twitter streaming api instead of search api

- by user1711576

I am using twitters search API to view all the tweets that use a particular hashtag I want to view. However, I want to use the stream function, so, I only get recent ones, and so, I can then store them. <?php global $total, $hashtag; $hashtag = $_POST['hash']; $total = 0; function getTweets($hash_tag, $page) { global $total, $hashtag; $url = 'http://search.twitter.com/search.json?q='.urlencode($hash_tag).'&'; $url .= 'page='.$page; $ch = curl_init($url); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $json = curl_exec ($ch); curl_close ($ch); echo "<pre>"; $json_decode = json_decode($json); print_r($json_decode->results); $json_decode = json_decode($json); $total += count($json_decode->results); if($json_decode->next_page){ $temp = explode("&",$json_decode->next_page); $p = explode("=",$temp[0]); getTweets($hashtag,$p[1]); } } getTweets($hashtag,1); echo $total; ?> The above code is what I have been using to search for the tweets I want. What do I need to do to change it so I can stream the tweets instead? I know I would have to use the stream url https://api.twitter.com/1.1/search/tweets.json , but what do I need to change after that is where I don't know what to do. Obviously, I know I'll need to write the database sql but I want to just capture the stream first and view it. How would I do this? Is the code I have been using not any good for just capturing the stream?

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PHP Foreach statement issue. Multiple rows are returned

- by Daniel Patilea

I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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Wordpress Admin Panel Code Input

- by Wes

I've got a wordpress admin panel for one of my themes and one of the boxes has an input for some code to drive google adsense. when I put the code into the box and call it with my php tags the code comes out like this: <script type="\"text/javascript\""> </script> <script type="\"text/javascript\"" src="%5C%22http://pagead2.googlesyndication.com/pagead/show_ads.js%5C%22"> </script> Which I assume is a feature to stop SQL injections. How can I call pure code form a box? This is how I currently have that textbox setup. array( "name" => "Code for Top ad", "desc" => "Enter the HTML that will drive the banner ad for the page header", "id" => $shortname."_headerAd", "type" => "textarea"), and then echo it out with this: <?php echo get_option('lifestyle_headerAd'); ?>

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