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  • What Can You Do When You Need More Than Just CRM?

    - by charles.knapp
    Sometimes a company needs more than just CRM to grow profitably. What if you also need ERP for streamlining the rest of your operations? Unlike CRM-only companies, Oracle can help you - today. For example, Myriad Genetics was an early pioneer and is currently a global life sciences leader in the exciting field of molecular diagnostic products. To keep pace with company growth, Myriad needed to integrate disparate systems and automate paper-based processes. Furthermore, Myriad needed to increase sales pipeline visibility to maximize customer service. Myriad selected Oracle CRM On Demand and E-Business Suite ERP applications. As a result, Myriad standardized sales processes, ensured greater visibility into the pipeline, and improved customer service. Read more here about Myriad and their business results.

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  • Requirements Gathering Form?

    - by Daveo
    Do you use a standard form to gather requirements from a customer prior to making a website? If so what are the questions you ask? For example Purpose of Website: (sell products, reduce number of enquires, reduce work load, etc) Do you have you’re an existing logo? (can you send it via email) Do you have a preferred font for the website text? Do you have a colour theme for your logo, business cards, shop you would like to keep on the website Do you have photos you can provide of your Products? etc Ofcause it would need to be tweaked slightly for each customer but I was looking for a generic document as a baseline.

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  • Have you Been Missing the 'About This Record' Functionality on the Customer Form...?

    - by MargaretW
    Do you have fond memories of the 'Help -> About This Record'  functionality that used to be available in the old Customer form - when it was a form, and not a java html screen?  Back in Release 11i, we had the ability to identify when the customer record had last been updated and by whom.  When some forms were replaced by Java HTML screens, you could identify some of this information via the 'About this Page' hyperlink at the bottom left hand corner of the HTML page.  You could enable this by enabling the FND: Diagnostics profile option, but many customers found this had an adverse effect on performance and additionally was not user-friendly.   Our customers tell us that this feature was widely used to identify owner/update information in many business processes, including auditing, customer entry/update, research and testing.  There have been various efforts to revert this feature by customising java pages, but this was not fully successful in some cases.  Oracle Support is happy to announce that this functionality has now been included in the Customer screens in Release 12.2 onwards.   You will be able to query the record history at customer level, at site level, at site address levels and for all tabs relating to the customer. Simply click on the 'Record History' icon, available in the Record History column on a summary screen, or via the same icon on the individual detail screen to display the following information: Last Updated Date: Last Updated By Creation Date Created By Last Update Login

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  • Save or update for FK relationship Sqlalchemy

    - by Alex
    I've googled, but haven't been able to find the answer to this seemingly simple question. I have two relations, a customer and an order. Each order is associated to a single cusomter, and therefore has a FK relationship to the customer table. The customer relation only stores customer names, and I have set a unique constraint on the customer table barring duplicate names. Let's say I create a new order instance and set a customer for the order. Something like: order_instance.customer = Customer("customer name") When I save the order instance, SqlAlchemy will complain if a customer with this name already exists in the customer table. How do I specify to SqlAlchemy to insert into the customer table if a customer with this name doesn't already exist, or just ignore (or even update) to the customer relation? I don't really want to have to check each time if a customer with some name already exists...

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  • Customer Attribute, not sorting select options

    - by Bosworth99
    Made a module that creates some customer EAV attributes. One of these attributes is a Select, and I'm dropping a bunch of options into their respective tables. Everything lines up and is accessible on both the front end and the back. Last thing before calling this part of things finished is the sort order of the options. They come out all scrambled, instead of the obvious default or alphabetical (seemingly at random... very wierd). I'm on Mage v1.11 (Pro/Enterprise). config.xml <config> <modules> <WACI_CustomerAttr> <version>0.1.0</version> </WACI_CustomerAttr> </modules> <global> <resources> <customerattr_setup> <setup> <module>WACI_CustomerAttr</module> <class>Mage_Customer_Model_Entity_Setup</class> </setup> <connection> <use>core_setup</use> </connection> </customerattr_setup> </resources> <models> <WACI_CustomerAttr> <class>WACI_CustomerAttr_Model</class> </WACI_CustomerAttr> </models> <fieldsets> <customer_account> <agency><create>1</create><update>1</update></agency> <title><create>1</create><update>1</update></title> <phone><create>1</create><update>1</update></phone> <mailing_address><create>1</create><update>1</update></mailing_address> <city><create>1</create><update>1</update></city> <state><create>1</create><update>1</update></state> <zip><create>1</create><update>1</update></zip> <fed_id><create>1</create><update>1</update></fed_id> <ubi><create>1</create><update>1</update></ubi> </customer_account> </fieldsets> </global> </config> mysql4-install-0.1.0.php <?php Mage::log('Installing WACI_CustomerAttr'); echo 'Running Upgrade: '.get_class($this)."\n <br /> \n"; //die ( 'its running' ); $installer = $this; /* @var $installer Mage_Customer_Model_Entity_Setup */ $installer->startSetup(); // bunch of attributes // State $installer->addAttribute('customer','state', array( 'type' => 'varchar', 'group' => 'Default', 'label' => 'State', 'input' => 'select', 'default' => 'Washington', 'source' => 'WACI_CustomerAttr/customer_attribute_data_select', 'global' => Mage_Catalog_Model_Resource_Eav_Attribute::SCOPE_STORE, 'required' => true, 'visible' => true, 'user_defined' => 1, 'position' => 67 ) ); $attrS = Mage::getSingleton('eav/config')->getAttribute('customer', 'state'); $attrS->addData(array('sort_order'=>67)); $attrS->setData('used_in_forms', array('adminhtml_customer','customer_account_edit','customer_account_create'))->save(); $state_list = array('Alabama','Alaska','Arizona','Arkansas','California','Colorado','Connecticut','Delaware','Florida','Georgia', 'Hawaii','Idaho','Illinois','Indiana','Iowa','Kansas','Kentucky','Louisiana','Maine','Maryland','Massachusetts','Michigan', 'Minnesota','Mississippi','Missouri','Montana','Nebraska','Nevada','New Hampshire','New Jersey','New Mexico','New York', 'North Carolina','North Dakota','Ohio','Oklahoma','Oregon','Pennsylvania','Rhode Island','South Carolina','South Dakota', 'Tennessee','Texas','Utah','Vermont','Virginia','Washington','West Virginia','Wisconsin','Wyoming'); $aOption = array(); $aOption['attribute_id'] = $installer->getAttributeId('customer', 'state'); for($iCount=0;$iCount<sizeof($state_list);$iCount++){ $aOption['value']['option'.$iCount][0] = $state_list[$iCount]; } $installer->addAttributeOption($aOption); // a few more $installer->endSetup(); app/code/local/WACI/CustomerAttr/Model/Customer/Attribute/Data/Select.php <?php class WACI_CustomerAttr_Model_Customer_Attribute_Data_Select extends Mage_Eav_Model_Entity_Attribute_Source_Abstract{ function getAllOptions(){ if (is_null($this->_options)) { $this->_options = Mage::getResourceModel('eav/entity_attribute_option_collection') ->setAttributeFilter($this->getAttribute()->getId()) ->setStoreFilter($this->getAttribute()->getStoreId()) ->setPositionOrder('asc') ->load() ->toOptionArray(); } $options = $this->_options; return $options; } } theme/variation/template/persistent/customer/form/register.phtml <li> <?php $attribute = Mage::getModel('eav/config')->getAttribute('customer','state'); ?> <label for="state" class="<?php if($attribute->getIsRequired() == true){?>required<?php } ?>"><?php if($attribute->getIsRequired() == true){?><em>*</em><?php } ?><?php echo $this->__('State') ?></label> <div class="input-box"> <select name="state" id="state" class="<?php if($attribute->getIsRequired() == true){?>required-entry<?php } ?>"> <?php $options = $attribute->getSource()->getAllOptions(); foreach($options as $option){ ?> <option value='<?php echo $option['value']?>' <?php if($this->getFormData()->getState() == $option['value']){ echo 'selected="selected"';}?>><?php echo $this->__($option['label'])?></option> <?php } ?> </select> </div> </li> All options are getting loaded into table eav_attribute_option just fine (albeit without a sort_order defined), as well as table eav_attribute_option_value. In the adminhtml / customer-manage customers-account information this select is showing up fine (but its delivered automatically by the system). Seems I should be able to set the sort-order on creation of the attributeOptions, or, certainly, define the sort order in the data/select class. But nothing I've tried works. I'd rather not do a front-end hack either... Oh, and how do I set the default value of this select? (Different question, I know, but related). Setting the attributes 'default' = 'washington' seems to do nothing. There seem to be a lot of ways to set up attribute select options like this. Is there a better way that the one I've outlined here? Perhaps I'm messing something up. Cheers

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  • Using Lite Version of Entity in nHibernate Relations?

    - by Amitabh
    Is it a good idea to create a lighter version of an Entity in some cases just for performance reason pointing to same table but with fewer columns mapped. E.g If I have a Contact Table which has 50 Columns and in few of the related entities I might be interested in FirstName and LastName property is it a good idea to create a lightweight version of Contact table. E.g. public class ContactLite { public int Id {get; set;} public string FirstName {get; set;} public string LastName {get; set;} } Also is it possible to map multiple classes to same table?

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  • Report Model; problem regarding many-to-many relations

    - by Koen
    I'm having trouble setting up a report model to create reports with report builder. I guess I'm doing something wrong when configuring the report model, but it might also due to change of primary entity in report builder. I have 3 tables: Client, Address and Product. The Client has PK ClientNumber. The Address and Product both have a FK relation on ClientNumber. The relation between Client and Address is 1-to-many and also between Client and Product: Product-(many:1)-Client-(1:many)-Address. I've created a report model (mostly auto generate) with these 3 tables, for each table I've made an Entity. Now on the Client Entity , I've got 2 roles, Address and Product. They both have a cardinality of 'OptionalMany', because Client can have multiple Addresses or Products. On both Address and Product I have a Client Role with cardinality 'One', because for each Address or Product, there has to be a Client (tried OptionalOne as well...). Now I'm trying to create a report in Report Builder (2.0) where I select fields from these three entities. I'd like an overview of Clients with their main address and their products, but I don't seem to be able to create a report with fields from both Address and Products in it. I start by selecting attributes from Client, and as soon as I add Product for example the Primary entity changes as if I'm selecting Products (instead of Clients). This is a basic example of a problem I'm facing in a much more complex model. I've tried lots of different things for 2 days, but I can't get it to work. Does anyone have an idea how to cope with this? (Using SSRS 2008)

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  • Linq to Entities and POCO foreign key relations mapping (1 to 0..1) problem

    - by brainnovative
    For my ASP.NET MVC 2 application I use Entity Framework 1.0 as my data access layer (repository). But I decided I want to return POCO. For the first time I have encountered a problem when I wanted to get a list of Brands with their optional logos. Here's what I did: public IQueryable<Model.Products.Brand> GetAll() { IQueryable<Model.Products.Brand> brands = from b in EntitiesCtx.Brands.Include("Logo") select new Model.Products.Brand() { BrandId = b.BrandId, Name = b.Name, Description = b.Description, IsActive = b.IsActive, Logo = /*b.Logo != null ? */new Model.Cms.Image() { ImageId = b.Logo.ImageId, Alt = b.Logo.Alt, Url = b.Logo.Url }/* : null*/ }; return brands; } You can see in the comments what I would like to achieve. It worked fine whenever a Brand had a Logo otherwise it through an exception that you can assign null to the non-nullable type int (for Id). My workaround was to use nullable in the POCO class but that's not natural - then I have to check not only if Logo is null in my Service layer or Controllers and Views but mostly for Logo.ImageId.HasValue. It's not justified to have a non null Logo property if the id is null. Can anyone think of a better solution?

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  • Linq to Entities and LEFT OUTER JOIN issue with MANY:1 relations

    - by Robert Koritnik
    Can somebody tell me, why does Linq to Entities translate many to 1 relationships to left outer join instead of inner join? Because there's referential constraint on DB itself that ensures there's a record in the right table, so inner join should be used instead (and it would work much faster) If relation was many to 0..1 left outer join would be correct. Question Is it possible to write LINQ in a way so it will translate to inner join rather than left outer join. It would speed query execution a lot... I haven't used eSQL before, but would it be wise to use it in instead of LINQ? Edit I updated my tags to include technology I'm using in the background: Entity Framework V1 Devart dotConnect for Mysql MySql database If someone could test if the same is true on Microsoft SQL server it would also give me some insight if this is Devart's issue or it's a general L2EF functionality... But I suspect EF is the culprit here.

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  • Heroku Push Problem part 2 - Postgresql - PGError Relations does not exist - Ruby on Rails

    - by bgadoci
    Ok so got through my last problem with the difference between Postgresql and SQLite and seems like Heroku is telling me I have another one. I am new to ruby and rails so a lot of this stuff I can't decipher at first. Looking for a little direction here. The error message and PostsController Index are below. I checked my routes.rb file and all seems well there but I could be missing something. I will post if you need. Processing PostsController#index (for 99.7.50.140 at 2010-04-23 15:19:22) [GET] ActiveRecord::StatementInvalid (PGError: ERROR: relation "tags" does not exist : SELECT a.attname, format_type(a.atttypid, a.atttypmod), d.adsrc, a.attnotnull FROM pg_attribute a LEFT JOIN pg_attrdef d ON a.attrelid = d.adrelid AND a.attnum = d.adnum WHERE a.attrelid = '"tags"'::regclass AND a.attnum > 0 AND NOT a.attisdropped ORDER BY a.attnum ): PostsController#index def index @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @ugtag_counts = Ugtag.count(:group => :ugctag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @vote_counts = Vote.count(:group => :post_title, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = [:tags, :votes] end @posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id, posts.id ", :order => "created_at DESC", :page => params[:page], :per_page => 5) @popular_posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id, posts.id", :order => "vote_total DESC", :page => params[:page], :per_page => 3) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end

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  • Stock management of assemblies and its sub parts (relations)

    - by The Disintegrator
    I have to track the stock of individual parts and kits (assemblies) and can't find a satisfactory way of doing this. Sample bogus and hyper simplified database: Table prod: prodID 1 prodName Flux capacitor prodCost 900 prodPrice 1350 (900*1.5) prodStock 3 - prodID 2 prodName Mr Fusion prodCost 300 prodPrice 600 (300*2) prodStock 2 - prodID 3 prodName Time travel kit prodCost 1650 (1350+300) prodPrice 2145 (1650*1.3) prodStock 2 Table rels relID 1 relSrc 1 (Flux capacitor) relType 4 (is a subpart of) relDst 3 (Time travel kit) - relID 2 relSrc 2 (Mr Fusion) relType 4 (is a subpart of) relDst 3 (Time travel kit) prodPrice: it's calculated based on the cost but not in a linear way. In this example for costs of 500 or less, the markup is a 200%. For costs of 500-1000 the markup is 150%. For costs of 1000+ the markup is 130% That's why the time travel kit is much cheaper than the individual parts prodStock: here is my problem. I can sell kits or the individual parts, So the stock of the kits is virtual. The problem when I buy: Some providers sell me the Time Travel kit as a whole (with one barcode) and some sells me the individual parts (with a different barcode) So when I load the stock I don't know how to impute it. The problem when I sell: If I only sell kits, calculate the stock would be easy: "I have 3 Flux capacitors and 2 Mr Fusions, so I have 2 Time travel kits and a Flux Capacitor" But I can sell Kits or individual parts. So, I have to track the stock of the individual parts and the possible kits at the same time (and I have to compensate for the sell price) Probably this is really simple, but I can't see a simple solution. Resuming: I have to find a way of tracking the stock and the database/program is the one who has to do it (I cant ask the clerk to correct the stock) I'm using php+MySql. But this is more a logical problem than a programing one

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  • get_or_create generic relations in Django & python debugging in general

    - by rabidpebble
    I ran the code to create the generically related objects from this demo: http://www.djangoproject.com/documentation/models/generic_relations/ Everything is good intially: >>> bacon.tags.create(tag="fatty") <TaggedItem: fatty> >>> tag, newtag = bacon.tags.get_or_create(tag="fatty") >>> tag <TaggedItem: fatty> >>> newtag False But then the use case that I'm interested in for my app: >>> tag, newtag = bacon.tags.get_or_create(tag="wholesome") Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/manager.py", line 123, in get_or_create return self.get_query_set().get_or_create(**kwargs) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 343, in get_or_create raise e IntegrityError: app_taggeditem.content_type_id may not be NULL I tried a bunch of random things after looking at other code: >>> tag, newtag = bacon.tags.get_or_create(tag="wholesome", content_type=TaggedItem) ValueError: Cannot assign "<class 'generics.app.models.TaggedItem'>": "TaggedItem.content_type" must be a "ContentType" instance. or: >>> tag, newtag = bacon.tags.get_or_create(tag="wholesome", content_type=TaggedItem.content_type) InterfaceError: Error binding parameter 3 - probably unsupported type. etc. I'm sure somebody can give me the correct syntax, but the real problem here is that I have no idea what is going on. I have developed in strongly typed languages for over ten years (x86 assembly, C++ and C#) but am new to Python. I find it really difficult to follow what is going on in Python when things like this break. In the languages I mentioned previously it's fairly straightforward to figure things like this out -- check the method signature and check your parameters. Looking at the Django documentation for half an hour left me just as lost. Looking at the source for get_or_create(self, **kwargs) didn't help either since there is no method signature and the code appears very generic. A next step would be to debug the method and try to figure out what is happening, but this seems a bit extreme... I seem to be missing some fundamental operating principle here... what is it? How do I resolve issues like this on my own in the future?

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  • Modelling class relations

    - by phenevo
    Hi, I have a few classes: Article ------- Content ID Magazine -------- Name Code And 3 tables in database: Articles Magazines ArticlesInMagazines (two fields: IDArticle and CodeMagazine) In my app, I've got a module to manage Articles, and a datagridview to relate their associated magazines DataGridView has twofields: MagazineCode IsPublished (indicates articles which have been published in this magazine). The same article can be in many magazines (1:n) How would you implement on model ? Article have to has a field : List ?? I am concerned because Magazine associates Articles

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  • Hibernate and parent/child relations

    - by Marco
    Hi to all, I'm using Hibernate in a Java application, and i feel that something could be done better for the management of parent/child relationships. I've a complex set of entities, that have some kind of relationships between them (one-to-many, many-to-many, one-to-one, both unidirectional and bidirectional). Every time an entity is saved and it has a parent, to estabilish the relationship the parent has to add the child to its collection (considering a one-to-may relationship). For example: Parent p = (Parent) session.load(Parent.class, pid); Child c = new Child(); c.setParent(p); p.getChildren().add(c); session.save(c); session.flush(); In the same way, if i remove a child then i have to explicitly remove it from the parent collection too. Child c = (Child) session.load(Child.class, cid); session.delete(c); Parent p = (Parent) session.load(Parent.class, pid); p.getChildren().remove(c); session.flush(); I was wondering if there are some best practices out there to do this jobs in a different way: when i save a child entity, automatically add it to the parent collection. If i remove a child, automatically update the parent collection by removing the child, etc. For example, Child c = new Child(); c.setParent(p); session.save(c); // Automatically update the parent collection session.flush(); or Child c = (Child) session.load(Child.class, cid); session.delete(c); // Automatically updates its parents (could be more than one) session.flush(); Anyway, it would not be difficult to implement this behaviour, but i was wondering if exist some standard tools or well known libraries that deals with this issue. And, if not, what are the reasons? Thanks

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  • Tables as relations in ER diagrams

    - by Richard Mar.
    Assume I have the following tables (**bold** - primary key, *italics* - foreign key): patient(**patient_id**, name) disease(**disease_id**, name) patient_disease(**p_d_id**, *patient_id*, *disease,_id* ) I want to draw the ER diagram for this. My idea is to make two entities, one for patient and one for disease, then make a n-to-n relation between them, with p_d_id as its attribute. Is that how it's supposed to be?

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  • Formtastic with Mongoid embedded_in relations

    - by miah
    Is there any quick way to make a form for embeds_many-embedded_in relation? I have the following: class Team include Mongoid::Document field :name, :type => String embeds_many :players end class Player include Mongoid::Document embedded_in :team, :inverse_of => :players field :name, :type => String end I want to create a form for team with embedded editing for players. Seen https://github.com/bowsersenior/formtastic_with_mongoid_tutorial but "TODO" there.

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  • how to query with child relations to same table and order this correctly

    - by robertpnl
    Hi, Take this table: id name sub_id --------------------------- 1 A (null) 2 B (null) 3 A2 1 4 A3 1 The sub_id column is a relation to his owm table, to column ID. subid --- 0:1 --- id Now I have the problem to make a correctly SELECT query to show that the child rows (which sub_id is not null) directly selected under his parent row. So this must be a correctly order: 1 A (null) 3 A2 1 4 A3 1 2 B (null) A normal SELECT order the id. But how or which keyword help me to order this correctly? JOIN isn't possible I think because I want to get all the rows seperated. Because the rows will be displayed on a Gridview (ASP.Net) with EntityDataSource but the child rows must be displayed directly under his parent. Thank you.

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  • MATLAB: Automatic detection of relations between workspace variables through functions

    - by Peterstone
    Hi all, I´m trying to write a function what detect this relation between the variables I have got in the workspace: v1 - fft(v2) = 0 Where v1, v2 are variables of my workspace. Sometimes I need to know which variables have a certain numerical relation. If I have thirty, I don´t want to be looking for this relation in "manual way", just itroducing a sentence for each pair of different variables. I would like a function in which I introuce (or I modify this function every time I need it) the sentence (for instance what I wrote before) and the function show me the pair of variables a I am looking for. Does anyone know how to do it? Thank you so much!

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  • Help with active record relations

    - by Christian Fazzini
    class CreateActivities < ActiveRecord::Migration def self.up create_table :activities do |t| t.references :user t.references :media t.integer :artist_id t.string :type t.timestamps end end def self.down drop_table :activities end end class Fan < Activity belongs_to :user, :counter_cache => true end class Activity < ActiveRecord::Base belongs_to :user belongs_to :media belongs_to :artist, :class_name => 'User', :foreign_key => 'artist_id' end class User < ActiveRecord::Base has_many :activities has_many :fans end I tried changing my activity model too, without any success: class Activity < ActiveRecord::Base has_many :activities, :class_name => 'User', :foreign_key => 'user_id' has_many :activities, :class_name => 'User', :foreign_key => 'artist_id' end One thing to note. Activity is an STI. Fan inherits from Activity. In console, I do: # Create a fan object. User is a fan of himself fan = Fan.new => #<Fan id: nil, user_id: nil, media_id: nil, artist_id: nil, type: "Fan", comment: nil, created_at: nil, updated_at: nil> # Assign a user object fan.user = User.first => #<User id: 1, genre_id: 1, country_id: 1, .... # Assign an artist object fan.artist_id = User.first.id => 1 # Save the fan object fan.save! => true Activity.last => #<Fan id: 13, user_id: 1, media_id: nil, artist_id: 1, type: "Fan", comment: nil, created_at: "2010-12-30 08:41:25", updated_at: "2010-12-30 08:41:25"> Activity.last.user => #<User id: 1, genre_id: 1, country_id: 1, ..... But... Activity.last.artist => nil Why is Activity.last.artist returning nil?

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  • Confusions with CSS and JavaScript relations ?

    - by Anil Namde
    I have table cell which has class "cellActive". Which has following defination .cellActive{background:"#DDDDDD"} Now i am trying to read the background color property for the cell and it comes null/"". var bgColor = cell.style.backgroundColor; // returning "" Is that something mistake on my part of its by behavior. If CSS class is assigning CSS to element can't we read its value in JS ? Does this mean that if we are not assigning property directly to the element we cant get it if in case its inheriting it ?

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  • CSS and JavaScript relations ?

    - by Anil Namde
    I have table cell which has class "cellActive". Which has following defination .cellActive{background:"#DDDDDD"} Now i am trying to read the background color property for the cell and it comes null/"". var bgColor = cell.style.backgroundColor; // returning "" Is that something mistake on my part of its by behavior. If CSS class is assigning CSS to element can't we read its value in JS ? Does this mean that if we are not assigning property directly to the element we cant get it if in case its inheriting it ?

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  • Enable export to XML via HTTP on a large number of models with child relations

    - by Vasil
    I've a large number of models (120+) and I would like to let users of my application export all of the data from them in XML format. I looked at django-piston, but I would like to do this with minimum code. Basically I'd like to have something like this: GET /export/applabel/ModelName/ Would stream all instances of ModelName in applabel together with it's tree of related objects . I'd like to do this without writing code for each model. What would be the best way to do this?

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  • Django: remove all m2m relations

    - by pistacchio
    Hi, if I have two simple models: class Tag(models.Model): name = models.CharField(max_length=100) class Post(models.Model): title = models.CharField(max_length=100) tags = models.ManyToManyField(Tag, blank=True) given a Post object with a number of Tags added to it, I know hot to remove any of them, but how to do a mass remove (remove all)? Thanks

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  • How to solve recursion relations in mathematica efficiently?

    - by Qiang Li
    I have a recursion to solve for. f(m,n)=Sum[f[m - 1, n - 1 - i] + f[m - 3, n - 5 - i], {i, 2, n - 2*m + 2}] + f[m - 1, n - 3] + f[m - 3, n - 7] f(0,n)=1, f(1,n)=n However, the following mma code is very inefficient f[m_, n_] := Module[{}, If[m < 0, Return[0];]; If[m == 0, Return[1];]; If[m == 1, Return[n];]; Return[Sum[f[m - 1, n - 1 - i] + f[m - 3, n - 5 - i], {i, 2, n - 2*m + 2}] + f[m - 1, n - 3] + f[m - 3, n - 7]];] It takes unbearably long to compute f[40,20]. Could anyone please suggest an efficient way of doing this? Many thanks!

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