Can a conforming C# compiler optimize away a local (but unused) variable if it is the only strong re
- by stakx
The title says it all, but let me explain:
void Case_1()
{
var weakRef = new WeakReference(new object());
GC.Collect(); // <-- doesn't have to be an explicit call; just assume that
// garbage collection would occur at this point.
if (weakRef.IsAlive) ...
}
In this code example, I obviously have to plan for the possibility that the new'ed object is reclaimed by the garbage collector; therefore the if statement.
(Note that I'm using weakRef for the sole purpose of checking if the new'ed object is still around.)
void Case_2()
{
var unusedLocalVar = new object();
var weakRef = new WeakReference(unusedLocalVar);
GC.Collect(); // <-- doesn't have to be an explicit call; just assume that
// garbage collection would occur at this point.
Debug.Assert(weakReferenceToUseless.IsAlive);
}
The main change in this code example from the previous one is that the new'ed object is strongly referenced by a local variable (unusedLocalVar). However, this variable is never used again after the weak reference (weakRef) has been created.
Question: Is a conforming C# compiler allowed to optimize the first two lines of Case_2 into those of Case_1 if it sees that unusedLocalVar is only used in one place, namely as an argument to the WeakReference constructor? i.e. is there any possibility that the assertion in Case_2 could ever fail?
