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  • how to make Regular expression into non-greedy ?

    - by Rueta
    Hi everyone! I have made a Work with JQ. My Work is a string width a special character block begin and end of string. I want take the text in that special characters, i used regular expression for find in string, but how to make JQ find multi result when have two special character or more. My html here; <div id="container"> <div id="textcontainer"> Cu?c chi?n pháp lý gi?a [|co th?|nghi?m|] th? tru?ng [|test2|dây là test l?n 2|] ch?ng khoán [|M?|day la nuoc my|] và ngân hàng d?u tu quy?n l?c nh?t Ph? Wall m?i ch? b?t d?u. </div> </div> and my JQ $(document).ready(function() { var takedata = $("#textcontainer").text(); var test = 'abcd adddb'; var filterdata = takedata.match(/(\[.+\])/); alert(filterdata); //end write js }); my result is: [|co th?|nghi?m|] th? tru?ng [|test2|dây là test l?n 2|] ch?ng khoán [|M?|day la nuoc my|] . but this is'nt the result i want :(. How to get [text] for times 1 and [demo] for times 2 ?. pls help me !. thankyou :)

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  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • Regular expression for dividing country calling codes

    - by RickiG
    Hi I have a list of calling codes for all countries(the phone number prefixes), I would like to split them up in the country name and the actual code so I can put then into an xml. I have tried back and forth but can not get a regexp going that takes all cases into account. I think it is fairly simple for someone with a bit of experience. The codes have these formats: Afghanistan 93 Anguilla 1 264 Antarctica 6721 Antigua and Barbuda 1 268 Bosnia and Herzegovina 387 Canada 1 Congo, Republic of the 242 Cote d'Ivoire 225 Ireland (Eire) 353 United States of America 1 There are around 235 of them in total, but these are the regulars and the exceptions. ^[a-zA-Z]\s,'()] for between 1 and X words and then it is [0-9\s]{1,5}$ for the numbers: X XX XXX XXXX X XXX So if I should express it as a sentence it would be: "from beginning of a line, take all characters (1) including space,'() until you encounter digits, then take all of these including space(2) until you encounter a line break." I am using TextMate, and the docs says: TextMate uses the Oniguruma regular expression library by K. Kosako. I would appreciate any help given:) Thank you.

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  • Regular Expression to replace a pattern at runtime(C#3.0)

    - by deepak.kumar.goyal
    I have a requirement. I have some files in a folder among which some file names looks like say **EUDataFiles20100503.txt, MigrateFiles20101006.txt.** Basically these are the files that I need to work upon. Now I have a config file where it is mentioned as the file pattern type as EUDataFilesYYYYMMDD, MigrateFilesYYYYMMDD. Basically the idea is that, the user can configure the file pattern and based on the pattern mentioned, I need to search for those files that are present in the folder. i.e. at runtime the YYYYMMDD will get replaced by the Year Month and Date Values. It does not matter what dates will be there(but not with time stamp ; only dates)). And the EUDataFiles or MigrateFiles names will be there.(they are fixed) i.e. If the folder has a file name as EUDataFile20100504.txt(i.e. Year 2010, Month 05, Day 04) , I should ignore this file as it is not EUDataFiles20100504.txt (kindly note that the name is plural - File(s) and not file for which the system will ignore the file). Similarly, if the Pattern given as EUDataFilesYYYYMMDD and if the file present is of type EUDataFilesYYYYDDMM then also the system should ignore. How can I solve this problem? Is it doable using regular expression(Replacing the pattern at runtime)? If so can anyone be good enough in helping me out? I am using C#3.0 and dotnet framework 3.5. Thanks

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  • How to use PHP preg_replace regular expression to find and replace text

    - by Roger
    I wrote this PHP code to make some substitutions: function cambio($txt){ $from=array( '/\+\>([^\+\>]+)\<\+/', //finds +>text<+ '/\%([^\%]+)\%/', //finds %text% ); $to=array( '<span class="P">\1</span>', '<span>\1</span>', ); return preg_replace($from,$to,$txt); } echo cambio('The fruit I most like is: +> %apple% %banna% %orange% <+.'); Resulting into this: The fruit I most like is: <span class="P"> <span>apple</span> <span>banna</span> <span>orange</span> </span>. however I needed to identify the fruit's span tags, like this: The fruit I most like is: <span class="P"> <span class="a">apple</span> <span class="b">banna</span> <span class="c">coco</span> </span>. I'd buy a fruit to whom discover a regular expression to accomplish this :-)

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  • Regular expression, excluding .. in suffix of email addy

    - by user1754700
    This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

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  • Invalid quantifer error using Regular Expression (UK Telephone numbers)

    - by Matt
    HI all, as per the title I am getting the error "Invalid Quantifier" Trying to match this reg ex:- ^(((+44\s?\d{4}|(?0\d{4})?)\s?\d{3}\s?\d{3})|((+44\s?\d{3}|(?0\d{3})?)\s?\d{3}\s?\d{4})|((+44\s?\d{2}|(?0\d{2})?)\s?\d{4}\s?\d{4}))(\s?#(\d{4}|\d{3}))?$ Infact ive tried a few UK telephone number regex's from the regex librairy but im getting the same error all the time. If anyone can help id be much appreciative! Just for info, im using the jQuery form validation librairy, and here is my code: - $(document).ready(function(){ //Set Fields to be validated $("#EventForm").validate(); $( "#StartDate" ).datepicker(); $( "#EndDate" ).datepicker(); //Add Postcode Regex Method to Validator Function $.validator.addMethod( "postcode", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid postcode." ); //Add UK Telephone number Regex Method to Validator Function $.validator.addMethod( "telephone", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid UK telephone number in the format - 01856 666666." ); //Add Postcode Regular Expression Rule to Postcode Field $("#EventPostcode").rules("add", { postcode: "^([a-zA-Z]){1}([0-9][0-9]|[0-9]|[a-zA-Z][0-9][a-zA-Z]|[a-zA-Z][0-9][0-9]|[a-zA-Z][0-9]){1}([ ])([0-9][a-zA-z][a-zA-z]){1}$"}); $("#EventTelephoneNo").rules("add", { telephone: "^(((\+44\s?\d{4}|\(?0\d{4}\)?)\s?\d{3}\s?\d{3})|((\+44\s?\d{3}|\(?0\d{3}\)?)\s?\d{3}\s?\d{4})|((\+44\s?\d{2}|\(?0\d{2}\)?)\s?\d{4}\s?\d{4}))(\s?\#(\d{4}|\d{3}))?$"}); }); Many thanks

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  • Regular Expression with Names and Emails

    - by Nina
    I am having a problem with regular expressions at the moment. What I'm trying to do is that for each line through the iteration, it checks for this type of pattern: Lastname, Firstname If it finds the name, then it will take the first letter of the first name, and the first six letters of the lastname and form it as an email. I have the following: $checklast = "[A-z],"; $checkfirst = "[A-z]"; if (ereg($checklast, $parts[1])||ereg($checkfirst, $parts[2])){ $first = preg_replace($checkfirst, $checkfirst{1,1}, $parts[2]); print "<a href='mailto:[email protected];'> $parts[$i] </a>"; } This one obviously broke the code. But I was initially attempting to find only the first letter of the firstname and then after that the first six letters of the lastname followed by the @email.com This didn't work out too well. I'm not sure what to do at this point. Any help is much appreciated.

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  • AWK: compare apache dates without using regular expression

    - by smallmeans
    I'm writing a loganalysis application and wanted to grab apache log records between two certain dates. Assume that a date is formated as such: 22/Dec/2009:00:19 (day/month/year:hour:minute) Currently, I'm using a regular expression to replace the month name with its numeric value, remove the separators, so the above date is converted to: 221220090019 making a date comparison trivial.. but.. Running a regex on each record for large files, say, one containing a quarter million records, is extremely costly.. is there any other method not involving regex substitution? Thanks in advance Edit: here's the function doing the convertion/comparison function dateInRange(t, from, to) { sub(/[[]/, "", t); split(t, a, "[/:]"); match("JanFebMarAprMayJunJulAugSepOctNovDec", a[2]); a[2] = sprintf("%02d", (RSTART + 2) / 3); s = a[3] a[2] a[1] a[4] a[5]; return s >= from && s <= to; } "from" and "to" are the intervals in the aforementioned format, and "t" is the raw apache log date/time field (e.g [22/Dec/2009:00:19:36)

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

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  • Javascipt Regular Expression

    - by Ghoul Fool
    Having problems with regular expressions in JavaScript. I've got a number of strings that need delimiting by commas. Unfortunately the sub strings don't have quotes around them which would make life easier. var str1 = "Three Blind Mice 13 Agents of Cheese Super 18" var str2 = "An Old Woman Who Lived in a Shoe 7 Pixies None 12" var str3 = "The Cow Jumped Over The Moon 21 Crazy Cow Tales Wonderful 9" They are in the form of PHRASE1 (Mixed type with spaces") INTEGER1 (1 or two digit) PHRASE2 (Mixed type with spaces") WORD1 (single word mixed type, no spaces) INTEGER2 (1 or two digit) so I should get: result1 = "Three Blind Mice, 13, Agents of Cheese, Super, 18" result2 = "An Old Woman Who Lived in a Shoe, 7, Pixies, None, 12" result3 = "A Cow Jumped Over The Moon, 21, Crazy Cow Tales, Wonderful, 9" I've looked at txt2re.com, but can't quite get what I need and ended up delimiting by hand. But I'm sure it can be done, albeit someone with a bigger brain. There are lots of examples of regEx but I couldn't find any to deal with phrases; so I was wondering if anyone could help me out. Thank you.

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  • Regular Expressions .NET

    - by Fosa
    I need a regular expression for some arguments that must match on a string. here it is... The string exists out of minimum 8 en maximum 20 characters. These characters of this string may be characters of the alfabet or special chars --With other words..all charachters except from the whitespaces In the complete string there must be atleast 1 number. The string cannot start with a number or an underscore The last 2 characters of the string must be identical, But it doenst matter if those last --identical characters are capital or non-capital (case insensitive) Must match all : +234567899 a_1de*Gg xy1Me*__ !41deF_hij2lMnopq3ss C234567890123$^67800 *5555555 sDF564zer"" !!!!!!!!!4!!!!!!!!!! abcdefghijklmnopq9ss May not match : Cannot be less then 8 or more then 20 chars: a_1+Eff B41def_hIJ2lmnopq3stt Cannot contain a whitespace: A_4 e*gg b41def_Hij2l nopq3ss Cannot start with a number or an underscore: __1+Eff 841DEf_hij2lmnopq3stt cannot end on 2 diffrent characters: a_1+eFg b41DEf_hij2lmnopq3st Cannot be without a number in the string: abCDefghijklmnopqrss abcdef+++dF !!!!!!!!!!!!!!!!!!!! ------------------------------------------------------ This is what I have so far...But I'm really breaking my head on this... If you Don't know the answer completely it's not a problem... I just want to get in the right direction ([^0-9_])(?=.*\d)(\S{8,20})(?i:[\S])\1

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  • complex regular expression task

    - by Don Don
    Hi, What regular expressions do I need to extract section title(s) in a text file? So, in the following sample text, I'd like to extract "Communication and Leadership" "1.Self-Knowledge" "2. Humility" "(3) Clear Thinking". Many thanks. Communication and Leadership True leaders understand that, rather than forcing their followers into a preconceived mold, their job is to motivate and organize followers to collectively accomplish goals that are in everyone's interests. The ability to communicate this to co-workers and followers is critical to the effectiveness of leadership. 1.Self-Knowledge Superior leaders are able to devote their skills and energies to leadership of a group because they have worked through personal issues to the point where they know themselves thoroughly. A high level of self-knowledge is a prerequisite to effective communication skills, because the things that you communicate as a leader are coming from within. 2. Humility This subversion of personal preference requires a certain level of humility. Although popular definitions of leaders do not always see them as humble, the most effective leaders actually are. This humility may not be expressed in self-effacement, but in a total commitment to the goals of the organization. Humility requires an understanding of one's own relative unimportance in comparison to larger systems. (3) Clear Thinking Clarity of thinking translates into clarity of communication. A leader whose goals or personal analysis is muddled will tend to deliver unclear or ambiguous directions to followers, leading to confusion and dissatisfaction. A leader with a clear mind who is not ambivalent about her purposes will communicate what needs to be done in a s traightforward and unmistakable manner.

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  • Getting dialogue snippets from text using regular expressions

    - by sheldon
    I'm trying to extract snippets of dialogue from a book text. For example, if I have the string "What's the matter with the flag?" inquired Captain MacWhirr. "Seems all right to me." Then I want to extract "What's the matter with the flag?" and "Seem's all right to me.". I found a regular expression to use here, which is "[^"\\]*(\\.[^"\\]*)*". This works great in Eclipse when I'm doing a Ctrl+F find regex on my book .txt file, but when I run the following code: String regex = "\"[^\"\\\\]*(\\\\.[^\"\\\\]*)*\""; String bookText = "\"What's the matter with the flag?\" inquired Captain MacWhirr. \"Seems all right to me.\""; Pattern p = Pattern.compile(regex); Matcher m = p.matcher(bookText); if(m.find()) System.out.println(m.group(1)); The only thing that prints is null. So am I not converting the regex into a Java string properly? Do I need to take into account the fact that Java Strings have a \" for the double quotes?

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  • JavaScript (jQuery) Regular Expression for searching through an array

    - by CoryDorning
    First and foremost, I do not know RegEx but am trying to piece something together to make this work. Just wanted you to be forewarned. ;) Anyways, I'm trying to create a regular expression to take a word from an array and see if it matches a word in another array. I only want the search to return true if the keyword array string contains the searchTerm word. (i.e. oneone would be false, so would ones). Any help is GREATLY appreciated. var searchTerm = ['one','two','three']; var keywords = ['String which contains one', 'This string is 2', 'Three is here']; var keywordIndex; // loop through each keyword array $.each(keywords, function(i) { $.each(searchTerm, function(j) { var rSearchTerm = new RegExp('\b' + searchTerm[j] + '\b',i); // if search term is found, swap accordion div content if (keywords[i].search(rSearchTerm) > -1) { keywordIndex = i; // grouping keyword is in } }); // end searchTerm loop }); // end keyword loop

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  • need to clean malformed tags using regular expression

    - by Brian
    Looking to find the appropriate regular expression for the following conditions: I need to clean certain tags within free flowing text. For example, within the text I have two important tags: <2004:04:12 and . Unfortunately some of tags have missing "<" or "" delimiter. For example, some are as follows: 1) <2004:04:12 , I need this to be <2004:04:12> 2) 2004:04:12>, I need this to be <2004:04:12> 3) <John Doe , I need this to be <John Doe> I attempted to use the following for situation 1: String regex = "<\\d{4}-\\d{2}-\\d{2}\\w*{2}[^>]"; String output = content.replaceAll(regex,"$0>"); This did find all instances of "<2004:04:12" and the result was "<2004:04:12 ". However, I need to eliminate the space prior to the ending tag. Not sure this is the best way. Any suggestions. Thanks

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  • regular expression repeating subexpression

    - by Michael Z
    I have the following text <pattern name="pattern1"/> <success>success case 1</success> <failed> failure 1</failed> <failed> failure 2</failed> <unknown> unknown </unknown> <pattern name="pattern2"/> <success>success case 2</success> <otherTag>There are many other tags.</otherTag> <failed> failure 3</failed> And the regular expression <failed>[\w|\W]*?</failed> matches all the lines contains failed tag. What do I need to to if I want to include the lines contains pattern tag as well? Basically, I want the following output: <pattern name="pattern1"/> <failed> failure 1</failed> <failed> failure 2</failed> <pattern name="pattern2"/> <failed> failure 3</failed> I am doing this in javascript, I do not mind of doing some intermediate steps.

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • Regular expression to convert ul to textindent and back, with a different attribute value for first

    - by chapmanio
    Hi, This is a related to a previous question I have asked here, see the link below for a brief description as to why I am trying to do this. Regular expression from font to span (size and colour) and back (VB.NET) Basically I need a regex replace function (or if this can be done in pure VB then that's fine) to convert all ul tags in a string to textindent tags, with a different attribute value for the first textindent tag. For example: <ul> <li>This is some text</li> <li>This is some more text</li> <li> <ul> <li>This is some indented text</li> <li>This is some more text</li> </ul> </li> <li>More text!</li> <li> <ul> <li>This is some indented text</li> <li>This is some more text</li> </ul> </li> <li>More text!</li> </ul> Will become: <textformat indent="0"> <li>This is some text</li> <li>This is some more text</li> <li> <textformat indent="20"> <li>This is some indented text</li> <li>This is some more text</li> </textformat> </li> <li>More text!</li> <li> <textformat indent="20"> <li>This is some indented text</li> <li>This is some more text</li> </textformat> </li> <li>More text!</li> </textformat> Basically I want the first ul tag to have no indenting, but all nested ul tags to have an indent of 20. I appreciate this is a strange request but hopefully that makes sense, please let me know if you have any questions. Thanks in advance.

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  • Match over multiple lines perl regular expression

    - by John
    Hi, I have a file like this: 01 00 01 14 c0 00 01 10 01 00 00 16 00 00 00 64 00 00 00 65 00 00 01 07 40 00 00 22 68 61 6c 2e 6f 70 65 6e 65 74 2e 63 6f 6d 3b 30 30 30 30 30 30 30 30 32 3b 30 00 00 00 00 01 08 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 28 40 00 00 21 72 65 61 6c 6d 31 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 00 01 25 40 00 00 1e 68 61 6c 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 00 00 01 1b 40 00 00 20 72 65 61 6c 6d 2e 6f 70 65 6e 65 74 2d 74 65 6c 65 63 6f 6d 2e 6c 61 6e 00 00 01 02 40 00 00 0c 01 00 00 16 00 00 01 a0 40 00 00 0c 00 00 00 01 00 00 01 9f 40 00 00 0c 00 00 00 00 00 00 01 16 40 00 00 0c 00 00 00 00 00 00 01 bb 40 00 00 28 00 00 01 c2 40 00 00 0c 00 00 00 00 00 00 01 bc 40 00 00 13 31 39 37 37 31 31 31 32 32 33 31 00 I am reading the file and then finding certain octets and replacing them with tags: while(<FH>){ $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; # } So for example, 00 00 00 64 would be replaced by the tag. This was working fine, but it doesn't seem to able to match over multiple lines any more. For example the pattern 31 31 32 32 33 31 runs over multiple lines, and the regular expression doesn't seem to catch it. I tried using /m /s pattern modifiers to ignore new lines but they didn't match it either. The only way around it I can come up with, is to read the whole file into a string using: undef $/; my $whole_file = <FH>; my $line = $whole_file; $line =~ s/(00 00 00 64)/<incr4> /g; $line =~ s/(00 00 00 65)/<incr4> /g; $line =~ s/(30 30 30 30 30 32)/<incr6ascii:999999:0>/g; $line =~ s/(31 31 32 32 33 31)/<incr6ascii:999999:0>/g; print OUTPUT $line; This works, the tags get inserted correctly, but the structure of the file is radically altered. It is all dumped out on a single line. I would like to retain the structure of the file as it appears here. Any ideas as to how I might do this? /john

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  • Google Rolls Out Secured Search. It’s Slightly Different From Regular Search

    - by Gopinath
    Google rolled out secured version of it’s search engine at https://google.com (did you notice https instead of http?). This search engine lets everyone to use Google search in a secured way. How is it secured? When you use https://google.com, the data exchanged between your browser and Google servers is encrypted to make sure that no one can sniff it. Is my search history secured from Google? No. The search queries you submit to Google are stored in Google servers. There is no change Google’s search history recording. Any differences between Regular Search and Secured Search Results? Yes. Secured search is slightly different from regular search. When you are accessing Google Secured Search Image search options will not be available on the left side bar. Site may respond slow compared to regular search site as there is a overhead to establish between your browser and the server. Join us on Facebook to read all our stories right inside your Facebook news feed.

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  • From escaped html -> to regular html? - Python

    - by RadiantHex
    Hi folks, I used BeautifulSoup to handle XML files that I have collected through a REST API. The responses contain HTML code, but BeautifulSoup escapes all the HTML tags so it can be displayed nicely. Unfortunately I need the HTML code. How would I go on about transforming the escaped HTML into proper markup? Help would be very much appreciated!

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  • Limit user input to allowable comma delimited words with regular expression using javascript

    - by Marc
    I want to force the user to enter any combination of the following words. the words need to be comma delimited and no comma at the beginning or end of the string the user should only be able to enter one of each word. Examples admin basic,ectech admin,ectech,advanced basic,advanced,admin,ectech my attempt ^((basic|advanced)|admin|ectech)((,basic|,advanced)|,admin|,ectech){0,2}$ Thanks Marc

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