Make object by it's name
- by Ockonal
Hello, is it possible to return exemplar of object using passed type name (string) in c++?
I have some base abstract class Base and a few derivates. Example code:
class Base
{
/* ... */
};
class Der1 : public Base
{
/* ... */
};
class Der2 : public Base
{
/* ... */
};
And I need function like:
Base *objectByType(const std::string &name);
Number of derivates classes are changeable and I don't want to make something like switching of name and returning by hands new object type. Is it possible in c++ to do that automatically anyway?
p.s. usage should looks like:
dynamic_cast<Der1>(objectByType("Der1"));
I need pure c++ code (crossplatform). Using boost is permissible.
