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• PHP Code Problem...

  - by aamir Fayyaz

  function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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• PHP/MySQL Interview - How would you have answered?

  - by martincarlin87

  I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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• Add multiple IF tags in php

  - by Andy

  Hi , I would like to add this condition : {if $profile.sex == 1 || $profile.sex == 4} {/if} To this code : case 'friendlist': if ( app_Features::isAvailable( 14 ) ) { $_output = '<div class="memhome_link">'; $_output.= '<a href="'.SK_Navigation::href( 'profile_friend_list' ).'" '.$class.'>'.$lang_section->text( 'href_my_friendlist').'</a>'; $_output.= ' ('.app_FriendNetwork::countFriends( SK_HttpUser::profile_id() ).')'; $_output.= '</div>'; } break; Can anybody give me any help , please ? Thanks for all the help .

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• PHP IF statement not taking variable into account!

  - by Jess

  I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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• My MYSQL & PHP while code is out of memory, when there is only one row

  - by Sam

  Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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• Simple PHP query question: LIKE

  - by pg

  When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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• How to write ½ in php

  - by skarama

  Hi everyone, Quick question, how can I make this valid : if($this->datos->bathrooms == "1½"){$select1 = JText::_( 'selected="selected"' );} The ½ doesn't seem to be recognized. I tried to write it as &#189; but then it looks for &#189; literally, and not the ½ sign. Any ideas?

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• Auto form posting in php without curl.

  - by Deepali

  I want a code for auto post a form with filled data .But I dont want to use curl. Any help. Thanks in adv.

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• Update a Google Doc (or file stored with Docs) with PHP

  - by tb

  It seems Zend Gdata doesn't provide a way to interface with the PUT API for Google Docs. I'd like to clear a document with a known id and update its contents. Should I authenticate with Zend's Gdata and use an HTTP PUT request? How?

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• Make HTTP/1.1 request with PHP

  - by ejunker

  My code is using file_get_contents() to make GET requests to an API endpoint. It looks like it is using HTTP/1.0 and my sysadmin says I need to use HTTP/1.1. How can I make an HTTP/1.1 request? Do I need to use curl or is there a better/easier way?

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• PHP radio button check if null

  - by Dallox

  So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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• How to match Regex right to left in php

  - by monkey_boys

  This my simple data : <table></table><table></table><table>aaa</table> how to match <table></table><table></table>***<table>aaa</table>*** it should be return <table></table><table></table>

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• Merge array in a different way in PHP

  - by user2984974

  I have these two arrays: $array1 = array( '0' => 'apple', '1' => '' , '2' => 'cucumber' ); $array2 = array( '0' => '', '1' => 'bmw', '2' => 'chrysler' ); if I do this to merge these arrays: $result_arr = array_merge($array1, $array2); print_r( count ( array_filter($result_arr) ) ); the output would be 4. However, I need to get the number 3. So, when there are two things on the same position (same key) count it only once. Is it possible to merge/count elements in arrays like that?

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• Mail php function does'nt send the email

  - by Mamadou

  Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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• php: parsing and converting array structure

  - by mwb

  I need to convert one array structure into another array structure. I hope someone will find it worthy their time to show how this could be done in a simple manner. It's a little above my array manipulation skills. The structure we start out with looks like this: $cssoptions = array( array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'width' , 'value' => '200px' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '#content' , 'rule' => 'margin-right' , 'value' => '20px' ) // end data set , array( 'group' => 'Colors' , 'selector' => '#content' , 'rule' => 'color' , 'value' => '#444' ) // end data set , array( 'group' => 'Measurements' , 'selector' => '.sidebar' , 'rule' => 'margin-top' , 'value' => '10px' ) // end data set ); // END $cssoptions It's a collection of discreet datasets, each consisting of an array that holds two key = value pairs describing a 'css-rule' and a 'css-rule-value'. Further, each dataset holds a key = value pair describing the 'css-selector-group' that the 'css-rule' should blong to, and a key = value pair describing a 'rule-group' that should be used for structuring the rendering of the final css into a neat css code block arranged by the kind of properties they describe (colors, measurement, typography etc..) Now, I need to parse that, and turn it into a new structure, where the: 'rule' => 'rule-name' , 'value' => 'value-string' for each dataset is converted into: 'rule-name' => 'value-string' ..and then placed into a new array structure where all 'rule-name' = 'value-string' pairs should be aggregated under the respective 'selector-values' Like this: '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block ..and finally all those blocks should be grouped under their respective 'style-groups', creating a final resulting array structure like this: $css => array( 'Measurements' => array( '#content' => array( 'width' => '200px' , 'margin-right' => '20px' ) // end selecor block , '.sidebar' => array( 'margin-top' => '10px' ) // end selector block ) // end rule group , 'Colors' => array( '#content' => array( 'color' => '#444' ) // end selector block ) // end rule group ); // end css

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• Using PHP to Seperate Results of a txt file

  - by outbreak

  I am trying to display the last 10 lines of a File and from there take those results and break them down to 10 individual lines.. Currently the code I have found from examples is: $filearray = file("test.txt"); $lastfifteenlines = array_slice($filearray,-10); echo implode($lastfifteenlines, "\n") It display's the 10 items I need however it does not break them down onto individual lines the current results are: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 I need that to instead display as: 1.0.0.11 1.0.0.12 1.0.0.13 1.0.0.14 1.0.0.15 Thanks in Advance for the Asistance!

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• PHP string parsing

  - by tmatthews

  I am trying to parse a list of operating system instances with their unique identifiers. I am looking for a solution to parse a text string, and pass the values into two variables. The string to be parsed is as followed: "Ubuntu 9.10" {40f2324d-a6b2-44e4-90c3-0c5fa82c987d}

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• What are the PHP "encryption" functions?

  - by Rob

  Looking for built in encryption functions, not to hide the string from the clever programmer, but instead just to obfuscate it a bit. Looking for functions such as str_rot13 and base64_encode, but I can't seem to locate any. Surely there are more?

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• php / phpDoc - @return instance of $this class ?

  - by searbe

  How do I mark a method as "returns an instance of the current class" in my phpDoc? In the following example my IDE (Netbeans) will see that setSomething always returns a foo object. But that's not true if I extent the object - it'll return $this, which in the second example is a bar object not a foo object. class foo { protected $_value = null; /** * Set something * * @param string $value the value * @return foo */ public function setSomething($value) { $this->_value = $value; return $this; } } $foo = new foo(); $out = $foo->setSomething(); So fine - setSomething returns a foo - but in the following example, it returns a bar..: class bar extends foo { public function someOtherMethod(){} } $bar = new bar(); $out = $bar->setSomething(); $out->someOtherMethod(); // <-- Here, Netbeans will think $out // is a foo, so doesn't see this other // method in $out's code-completion ... it'd be great to solve this as for me, code completion is a massive speed-boost. Anyone got a clever trick, or even better, a proper way to document this with phpDoc?

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• login/logout problem in PHP

  - by user356170

  i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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• PHP: Auto Updating subscriptions?

  - by Duncan Palmer

  Hey guys I am currently making a website and I am hopefully going to start a premium service for it. What I am currently looking into right now is how to make an "auto updating" shop which removes 1 day from how many days left the user has left on their premium status. so for example if the users purchases 30 days of premium, each day that 30 with negate 1 so.. 30, 29, 28, 27.. etc and then if the days gets to 0 in will remove premium status. The only way I can think of keeping track of this right now is by manually monitoring each persons premium status but that wouldnt be very practical. What would the best way for me to do this? (hopefully "automatically") Thanks.

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• PHP strtotime() setting date to default

  - by Paddyd

  I have a script which is reading values from an excel sheet and inserting them into an sql table. My problem is when the script reads in some of the date fields it is setting them to a default value : 1970-01-01 01:00:00 I have noticed that this is happening when it comes across a date where the 'day' is greater than 12 : 13/05/2012 18:52:33 (dd-mm-yyyy hh-mm-ss) I thought this may be due to the script thinking that this is the month field (i.e american format) and it sees it as an invalid value, so I set the default timezone to my own hoping it may resolve the problem but it made no difference. date_default_timezone_set('Europe/Dublin'); Here is an example of what my code is doing: Excel field value : 01/05/2012 18:32:45 Script: $start_time = $data->val($x,5); echo $start_time = date("Y-m-d H:i:s", strtotime($start_time)); Output: 2012-01-05 18:32:45 This is the exact format I am looking for (except for the fact that the day and month fields are switched around i.e american date format) but it doesnt work for the type of dates I mentioned above.

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• PHP: constant as variable in function

  - by m4recek

  I'm trying to use constant as a function paramter, is it possible to check type of this constant. Example of what I want: class ApiError { const INVALID_REQUEST = 200; } class Response { public function status(ApiError $status) { //function code here } } USE: $response = new Response(); $response->status(ApiError::INVALID_REQUEST); This shoud check that given $status is constant of class ApiError. Is something like this possible?

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• Testing if string is sha1 in PHP

  - by SGWebsNow

  I'm planning on storing the passwords as a sha1, so I need a way to validate that it is a sha1 at another point in my website. I was planning on using preg_match, but I do not know how to make regex patterns. Could someone help me out with one? Thanks

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• Rotating images with PHP reduces quality especially over about 10-20 actions

  - by Dylan Cross

  I am using this code below to rotate my jpeg images, the problem is that after around 10-20 times of rotating the image the image is dramatically lower quality, especially blue skies and such, my question is how can I keep these images the same high quality image? There must be a way. I mean, i keep the original image on the server for each image uploaded, and I don't do anything to that, so if need be it, I guess I could always come up with some way of using that over whenever possible.. But would rather not have to. $source = imagecreatefromjpeg($filename); $rotate = imagerotate($source, 90, 0); imagejpeg($rotate, $filename ,100);

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