Search Results

Search found 3240 results on 130 pages for 'groupwise maximum'.

Page 35/130 | < Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >

  • Duplicate monitor on highest resolution in Windows 7

    - by AlexanderMP
    I have a monitor with a native resolution of 2560x1440, connected through display port. I also have an AV Receiver connected to the video card via HDMI, to have surround sound in games. All using Radeon HD 5670 (will upgrade soon to HD 7850). The problem is that my computer detects the receiver as a separate monitor, with the highest available resolution of 1920x1080. I have 3 options: Disconnect the second display. But then the sound (digital audio output through video card) also disappears. Duplicate displays. But then my primary monitor resolution is reduced to a maximum of just 1920x1080, that being the maximum of the second monitor. Extend desktop. This is the solution I picked so far, it being the least evil. The problems I face in this situations are 2: I have a blank part of the desktop where I sometimes lose my mouse pointer, so I made the extension small, 640x480, and placed it in a corner; when I turn off the main display, all windows resize to 640x480. In Kubuntu I had the option to duplicate the displays, while keeping the higher resolution. Which was great. I tried overriding using the Win7 netbook hack, but it's not available on non-netbooks. Is there a similar solution for this problem in Windows 7?

    Read the article

  • Spotlight on RIVA: CRM integration for Oracle CRM on Demand and Microsoft Exchange

    - by Richard Lefebvre
    Introducing Riva from Omni - an Oracle ISV partner specializing in Enterprise Management and Integration Solutions Riva delivers advanced, server-side integration for Oracle CRM On Demand and Microsoft Exchange or even Novell GroupWise. Riva allows Oracle customers to go beyond the standard Outlook plug-in to deliver additional value for the end user as they interact between Outlook and CRM On Demand. Riva syncs CRM On Demand to ALL Exchange mail apps, not just Windows Outlook.  So, whether customers are using Outlook 2010, Outlook Web Access (web client), Outlook 2011 for Mac, Apple Mail, Outlook on Citrix  or a mobile device, Riva's got them covered. There are no plug-ins to be installed, configured, managed and maintained on users' desktops, laptops as Riva delivers Server-side synchronisation for CRMOD and Exchange. The automation of CRM and Outlook integration will remove the reliance upon users to synchronise between the two with Riva handling this process. Riva allows administrators to define sync policies and apply them to individuals or groups of users depending on their sync requirements. Administrators will be able to determine and manage the exposure of the most pertinent detail to be synchronised between Outlook and CRM On Demand. Custom and organic contact filtering for large deployments i.e. Based on ownership, groupings and contact frequency, filters can be applied on what contact records are shared with the users. Riva provides the capability to synchronise CRM and Outlook beyond Contacts, Calendar entries and Email. The synchronisation can be extended to cater for  opportunities, quotes and custom objects for example within the Outlook interface. Riva SmartConvert Folders can automate the creation of opportunities and associated contacts for example if they don't already exist. This can facilitate a reduction in manual detail entry through quick association whilst also benefiting user adoption. From a mobile perspective, Riva allows users to view and manage their CRM On Demand contacts, calendar, tasks, opportunities and cases from iPad, iPhone, Android and BlackBerry devices.  Again, there are no mobile apps or additional plugins to install, configure or manage. We sync CRM On Demand to Exchange.  Because the mobile device is connected to an Exchange mailbox, the information automatically syncs down to the native address book, calendar and mail apps on the smartphone or tablet. Riva Datasheet for CRM On Demand Riva Brochure – Oracle CRM On Demand  Technical Knowledgebase & Riva Trial  http://kb.omni-ts.com/47/ Comparison to Outlook Plug-ins Riva Diagram – Riva Comparison with Outlook Plug-ins Contact: Wolfgang Berger - [email protected]

    Read the article

  • Using R to Analyze G1GC Log Files

    - by user12620111
    Using R to Analyze G1GC Log Files body, td { font-family: sans-serif; background-color: white; font-size: 12px; margin: 8px; } tt, code, pre { font-family: 'DejaVu Sans Mono', 'Droid Sans Mono', 'Lucida Console', Consolas, Monaco, monospace; } h1 { font-size:2.2em; } h2 { font-size:1.8em; } h3 { font-size:1.4em; } h4 { font-size:1.0em; } h5 { font-size:0.9em; } h6 { font-size:0.8em; } a:visited { color: rgb(50%, 0%, 50%); } pre { margin-top: 0; max-width: 95%; border: 1px solid #ccc; white-space: pre-wrap; } pre code { display: block; padding: 0.5em; } code.r, code.cpp { background-color: #F8F8F8; } table, td, th { border: none; } blockquote { color:#666666; margin:0; padding-left: 1em; border-left: 0.5em #EEE solid; } hr { height: 0px; border-bottom: none; border-top-width: thin; border-top-style: dotted; border-top-color: #999999; } @media print { * { background: transparent !important; color: black !important; filter:none !important; -ms-filter: none !important; } body { font-size:12pt; max-width:100%; } a, a:visited { text-decoration: underline; } hr { visibility: hidden; page-break-before: always; } pre, blockquote { padding-right: 1em; page-break-inside: avoid; } tr, img { page-break-inside: avoid; } img { max-width: 100% !important; } @page :left { margin: 15mm 20mm 15mm 10mm; } @page :right { margin: 15mm 10mm 15mm 20mm; } p, h2, h3 { orphans: 3; widows: 3; } h2, h3 { page-break-after: avoid; } } pre .operator, pre .paren { color: rgb(104, 118, 135) } pre .literal { color: rgb(88, 72, 246) } pre .number { color: rgb(0, 0, 205); } pre .comment { color: rgb(76, 136, 107); } pre .keyword { color: rgb(0, 0, 255); } pre .identifier { color: rgb(0, 0, 0); } pre .string { color: rgb(3, 106, 7); } var hljs=new function(){function m(p){return p.replace(/&/gm,"&").replace(/"}while(y.length||w.length){var v=u().splice(0,1)[0];z+=m(x.substr(q,v.offset-q));q=v.offset;if(v.event=="start"){z+=t(v.node);s.push(v.node)}else{if(v.event=="stop"){var p,r=s.length;do{r--;p=s[r];z+=("")}while(p!=v.node);s.splice(r,1);while(r'+M[0]+""}else{r+=M[0]}O=P.lR.lastIndex;M=P.lR.exec(L)}return r+L.substr(O,L.length-O)}function J(L,M){if(M.sL&&e[M.sL]){var r=d(M.sL,L);x+=r.keyword_count;return r.value}else{return F(L,M)}}function I(M,r){var L=M.cN?'':"";if(M.rB){y+=L;M.buffer=""}else{if(M.eB){y+=m(r)+L;M.buffer=""}else{y+=L;M.buffer=r}}D.push(M);A+=M.r}function G(N,M,Q){var R=D[D.length-1];if(Q){y+=J(R.buffer+N,R);return false}var P=q(M,R);if(P){y+=J(R.buffer+N,R);I(P,M);return P.rB}var L=v(D.length-1,M);if(L){var O=R.cN?"":"";if(R.rE){y+=J(R.buffer+N,R)+O}else{if(R.eE){y+=J(R.buffer+N,R)+O+m(M)}else{y+=J(R.buffer+N+M,R)+O}}while(L1){O=D[D.length-2].cN?"":"";y+=O;L--;D.length--}var r=D[D.length-1];D.length--;D[D.length-1].buffer="";if(r.starts){I(r.starts,"")}return R.rE}if(w(M,R)){throw"Illegal"}}var E=e[B];var D=[E.dM];var A=0;var x=0;var y="";try{var s,u=0;E.dM.buffer="";do{s=p(C,u);var t=G(s[0],s[1],s[2]);u+=s[0].length;if(!t){u+=s[1].length}}while(!s[2]);if(D.length1){throw"Illegal"}return{r:A,keyword_count:x,value:y}}catch(H){if(H=="Illegal"){return{r:0,keyword_count:0,value:m(C)}}else{throw H}}}function g(t){var p={keyword_count:0,r:0,value:m(t)};var r=p;for(var q in e){if(!e.hasOwnProperty(q)){continue}var s=d(q,t);s.language=q;if(s.keyword_count+s.rr.keyword_count+r.r){r=s}if(s.keyword_count+s.rp.keyword_count+p.r){r=p;p=s}}if(r.language){p.second_best=r}return p}function i(r,q,p){if(q){r=r.replace(/^((]+|\t)+)/gm,function(t,w,v,u){return w.replace(/\t/g,q)})}if(p){r=r.replace(/\n/g,"")}return r}function n(t,w,r){var x=h(t,r);var v=a(t);var y,s;if(v){y=d(v,x)}else{return}var q=c(t);if(q.length){s=document.createElement("pre");s.innerHTML=y.value;y.value=k(q,c(s),x)}y.value=i(y.value,w,r);var u=t.className;if(!u.match("(\\s|^)(language-)?"+v+"(\\s|$)")){u=u?(u+" "+v):v}if(/MSIE [678]/.test(navigator.userAgent)&&t.tagName=="CODE"&&t.parentNode.tagName=="PRE"){s=t.parentNode;var p=document.createElement("div");p.innerHTML=""+y.value+"";t=p.firstChild.firstChild;p.firstChild.cN=s.cN;s.parentNode.replaceChild(p.firstChild,s)}else{t.innerHTML=y.value}t.className=u;t.result={language:v,kw:y.keyword_count,re:y.r};if(y.second_best){t.second_best={language:y.second_best.language,kw:y.second_best.keyword_count,re:y.second_best.r}}}function o(){if(o.called){return}o.called=true;var r=document.getElementsByTagName("pre");for(var p=0;p|=||=||=|\\?|\\[|\\{|\\(|\\^|\\^=|\\||\\|=|\\|\\||~";this.ER="(?![\\s\\S])";this.BE={b:"\\\\.",r:0};this.ASM={cN:"string",b:"'",e:"'",i:"\\n",c:[this.BE],r:0};this.QSM={cN:"string",b:'"',e:'"',i:"\\n",c:[this.BE],r:0};this.CLCM={cN:"comment",b:"//",e:"$"};this.CBLCLM={cN:"comment",b:"/\\*",e:"\\*/"};this.HCM={cN:"comment",b:"#",e:"$"};this.NM={cN:"number",b:this.NR,r:0};this.CNM={cN:"number",b:this.CNR,r:0};this.BNM={cN:"number",b:this.BNR,r:0};this.inherit=function(r,s){var p={};for(var q in r){p[q]=r[q]}if(s){for(var q in s){p[q]=s[q]}}return p}}();hljs.LANGUAGES.cpp=function(){var a={keyword:{"false":1,"int":1,"float":1,"while":1,"private":1,"char":1,"catch":1,"export":1,virtual:1,operator:2,sizeof:2,dynamic_cast:2,typedef:2,const_cast:2,"const":1,struct:1,"for":1,static_cast:2,union:1,namespace:1,unsigned:1,"long":1,"throw":1,"volatile":2,"static":1,"protected":1,bool:1,template:1,mutable:1,"if":1,"public":1,friend:2,"do":1,"return":1,"goto":1,auto:1,"void":2,"enum":1,"else":1,"break":1,"new":1,extern:1,using:1,"true":1,"class":1,asm:1,"case":1,typeid:1,"short":1,reinterpret_cast:2,"default":1,"double":1,register:1,explicit:1,signed:1,typename:1,"try":1,"this":1,"switch":1,"continue":1,wchar_t:1,inline:1,"delete":1,alignof:1,char16_t:1,char32_t:1,constexpr:1,decltype:1,noexcept:1,nullptr:1,static_assert:1,thread_local:1,restrict:1,_Bool:1,complex:1},built_in:{std:1,string:1,cin:1,cout:1,cerr:1,clog:1,stringstream:1,istringstream:1,ostringstream:1,auto_ptr:1,deque:1,list:1,queue:1,stack:1,vector:1,map:1,set:1,bitset:1,multiset:1,multimap:1,unordered_set:1,unordered_map:1,unordered_multiset:1,unordered_multimap:1,array:1,shared_ptr:1}};return{dM:{k:a,i:"",k:a,r:10,c:["self"]}]}}}();hljs.LANGUAGES.r={dM:{c:[hljs.HCM,{cN:"number",b:"\\b0[xX][0-9a-fA-F]+[Li]?\\b",e:hljs.IMMEDIATE_RE,r:0},{cN:"number",b:"\\b\\d+(?:[eE][+\\-]?\\d*)?L\\b",e:hljs.IMMEDIATE_RE,r:0},{cN:"number",b:"\\b\\d+\\.(?!\\d)(?:i\\b)?",e:hljs.IMMEDIATE_RE,r:1},{cN:"number",b:"\\b\\d+(?:\\.\\d*)?(?:[eE][+\\-]?\\d*)?i?\\b",e:hljs.IMMEDIATE_RE,r:0},{cN:"number",b:"\\.\\d+(?:[eE][+\\-]?\\d*)?i?\\b",e:hljs.IMMEDIATE_RE,r:1},{cN:"keyword",b:"(?:tryCatch|library|setGeneric|setGroupGeneric)\\b",e:hljs.IMMEDIATE_RE,r:10},{cN:"keyword",b:"\\.\\.\\.",e:hljs.IMMEDIATE_RE,r:10},{cN:"keyword",b:"\\.\\.\\d+(?![\\w.])",e:hljs.IMMEDIATE_RE,r:10},{cN:"keyword",b:"\\b(?:function)",e:hljs.IMMEDIATE_RE,r:2},{cN:"keyword",b:"(?:if|in|break|next|repeat|else|for|return|switch|while|try|stop|warning|require|attach|detach|source|setMethod|setClass)\\b",e:hljs.IMMEDIATE_RE,r:1},{cN:"literal",b:"(?:NA|NA_integer_|NA_real_|NA_character_|NA_complex_)\\b",e:hljs.IMMEDIATE_RE,r:10},{cN:"literal",b:"(?:NULL|TRUE|FALSE|T|F|Inf|NaN)\\b",e:hljs.IMMEDIATE_RE,r:1},{cN:"identifier",b:"[a-zA-Z.][a-zA-Z0-9._]*\\b",e:hljs.IMMEDIATE_RE,r:0},{cN:"operator",b:"|=||   Using R to Analyze G1GC Log Files   Using R to Analyze G1GC Log Files Introduction Working in Oracle Platform Integration gives an engineer opportunities to work on a wide array of technologies. My team’s goal is to make Oracle applications run best on the Solaris/SPARC platform. When looking for bottlenecks in a modern applications, one needs to be aware of not only how the CPUs and operating system are executing, but also network, storage, and in some cases, the Java Virtual Machine. I was recently presented with about 1.5 GB of Java Garbage First Garbage Collector log file data. If you’re not familiar with the subject, you might want to review Garbage First Garbage Collector Tuning by Monica Beckwith. The customer had been running Java HotSpot 1.6.0_31 to host a web application server. I was told that the Solaris/SPARC server was running a Java process launched using a commmand line that included the following flags: -d64 -Xms9g -Xmx9g -XX:+UseG1GC -XX:MaxGCPauseMillis=200 -XX:InitiatingHeapOccupancyPercent=80 -XX:PermSize=256m -XX:MaxPermSize=256m -XX:+PrintGC -XX:+PrintGCTimeStamps -XX:+PrintHeapAtGC -XX:+PrintGCDateStamps -XX:+PrintFlagsFinal -XX:+DisableExplicitGC -XX:+UnlockExperimentalVMOptions -XX:ParallelGCThreads=8 Several sources on the internet indicate that if I were to print out the 1.5 GB of log files, it would require enough paper to fill the bed of a pick up truck. Of course, it would be fruitless to try to scan the log files by hand. Tools will be required to summarize the contents of the log files. Others have encountered large Java garbage collection log files. There are existing tools to analyze the log files: IBM’s GC toolkit The chewiebug GCViewer gchisto HPjmeter Instead of using one of the other tools listed, I decide to parse the log files with standard Unix tools, and analyze the data with R. Data Cleansing The log files arrived in two different formats. I guess that the difference is that one set of log files was generated using a more verbose option, maybe -XX:+PrintHeapAtGC, and the other set of log files was generated without that option. Format 1 In some of the log files, the log files with the less verbose format, a single trace, i.e. the report of a singe garbage collection event, looks like this: {Heap before GC invocations=12280 (full 61): garbage-first heap total 9437184K, used 7499918K [0xfffffffd00000000, 0xffffffff40000000, 0xffffffff40000000) region size 4096K, 1 young (4096K), 0 survivors (0K) compacting perm gen total 262144K, used 144077K [0xffffffff40000000, 0xffffffff50000000, 0xffffffff50000000) the space 262144K, 54% used [0xffffffff40000000, 0xffffffff48cb3758, 0xffffffff48cb3800, 0xffffffff50000000) No shared spaces configured. 2014-05-14T07:24:00.988-0700: 60586.353: [GC pause (young) 7324M->7320M(9216M), 0.1567265 secs] Heap after GC invocations=12281 (full 61): garbage-first heap total 9437184K, used 7496533K [0xfffffffd00000000, 0xffffffff40000000, 0xffffffff40000000) region size 4096K, 0 young (0K), 0 survivors (0K) compacting perm gen total 262144K, used 144077K [0xffffffff40000000, 0xffffffff50000000, 0xffffffff50000000) the space 262144K, 54% used [0xffffffff40000000, 0xffffffff48cb3758, 0xffffffff48cb3800, 0xffffffff50000000) No shared spaces configured. } A simple grep can be used to extract a summary: $ grep "\[ GC pause (young" g1gc.log 2014-05-13T13:24:35.091-0700: 3.109: [GC pause (young) 20M->5029K(9216M), 0.0146328 secs] 2014-05-13T13:24:35.440-0700: 3.459: [GC pause (young) 9125K->6077K(9216M), 0.0086723 secs] 2014-05-13T13:24:37.581-0700: 5.599: [GC pause (young) 25M->8470K(9216M), 0.0203820 secs] 2014-05-13T13:24:42.686-0700: 10.704: [GC pause (young) 44M->15M(9216M), 0.0288848 secs] 2014-05-13T13:24:48.941-0700: 16.958: [GC pause (young) 51M->20M(9216M), 0.0491244 secs] 2014-05-13T13:24:56.049-0700: 24.066: [GC pause (young) 92M->26M(9216M), 0.0525368 secs] 2014-05-13T13:25:34.368-0700: 62.383: [GC pause (young) 602M->68M(9216M), 0.1721173 secs] But that format wasn't easily read into R, so I needed to be a bit more tricky. I used the following Unix command to create a summary file that was easy for R to read. $ echo "SecondsSinceLaunch BeforeSize AfterSize TotalSize RealTime" $ grep "\[GC pause (young" g1gc.log | grep -v mark | sed -e 's/[A-SU-z\(\),]/ /g' -e 's/->/ /' -e 's/: / /g' | more SecondsSinceLaunch BeforeSize AfterSize TotalSize RealTime 2014-05-13T13:24:35.091-0700 3.109 20 5029 9216 0.0146328 2014-05-13T13:24:35.440-0700 3.459 9125 6077 9216 0.0086723 2014-05-13T13:24:37.581-0700 5.599 25 8470 9216 0.0203820 2014-05-13T13:24:42.686-0700 10.704 44 15 9216 0.0288848 2014-05-13T13:24:48.941-0700 16.958 51 20 9216 0.0491244 2014-05-13T13:24:56.049-0700 24.066 92 26 9216 0.0525368 2014-05-13T13:25:34.368-0700 62.383 602 68 9216 0.1721173 Format 2 In some of the log files, the log files with the more verbose format, a single trace, i.e. the report of a singe garbage collection event, was more complicated than Format 1. Here is a text file with an example of a single G1GC trace in the second format. As you can see, it is quite complicated. It is nice that there is so much information available, but the level of detail can be overwhelming. I wrote this awk script (download) to summarize each trace on a single line. #!/usr/bin/env awk -f BEGIN { printf("SecondsSinceLaunch IncrementalCount FullCount UserTime SysTime RealTime BeforeSize AfterSize TotalSize\n") } ###################### # Save count data from lines that are at the start of each G1GC trace. # Each trace starts out like this: # {Heap before GC invocations=14 (full 0): # garbage-first heap total 9437184K, used 325496K [0xfffffffd00000000, 0xffffffff40000000, 0xffffffff40000000) ###################### /{Heap.*full/{ gsub ( "\\)" , "" ); nf=split($0,a,"="); split(a[2],b," "); getline; if ( match($0, "first") ) { G1GC=1; IncrementalCount=b[1]; FullCount=substr( b[3], 1, length(b[3])-1 ); } else { G1GC=0; } } ###################### # Pull out time stamps that are in lines with this format: # 2014-05-12T14:02:06.025-0700: 94.312: [GC pause (young), 0.08870154 secs] ###################### /GC pause/ { DateTime=$1; SecondsSinceLaunch=substr($2, 1, length($2)-1); } ###################### # Heap sizes are in lines that look like this: # [ 4842M->4838M(9216M)] ###################### /\[ .*]$/ { gsub ( "\\[" , "" ); gsub ( "\ \]" , "" ); gsub ( "->" , " " ); gsub ( "\\( " , " " ); gsub ( "\ \)" , " " ); split($0,a," "); if ( split(a[1],b,"M") > 1 ) {BeforeSize=b[1]*1024;} if ( split(a[1],b,"K") > 1 ) {BeforeSize=b[1];} if ( split(a[2],b,"M") > 1 ) {AfterSize=b[1]*1024;} if ( split(a[2],b,"K") > 1 ) {AfterSize=b[1];} if ( split(a[3],b,"M") > 1 ) {TotalSize=b[1]*1024;} if ( split(a[3],b,"K") > 1 ) {TotalSize=b[1];} } ###################### # Emit an output line when you find input that looks like this: # [Times: user=1.41 sys=0.08, real=0.24 secs] ###################### /\[Times/ { if (G1GC==1) { gsub ( "," , "" ); split($2,a,"="); UserTime=a[2]; split($3,a,"="); SysTime=a[2]; split($4,a,"="); RealTime=a[2]; print DateTime,SecondsSinceLaunch,IncrementalCount,FullCount,UserTime,SysTime,RealTime,BeforeSize,AfterSize,TotalSize; G1GC=0; } } The resulting summary is about 25X smaller that the original file, but still difficult for a human to digest. SecondsSinceLaunch IncrementalCount FullCount UserTime SysTime RealTime BeforeSize AfterSize TotalSize ... 2014-05-12T18:36:34.669-0700: 3985.744 561 0 0.57 0.06 0.16 1724416 1720320 9437184 2014-05-12T18:36:34.839-0700: 3985.914 562 0 0.51 0.06 0.19 1724416 1720320 9437184 2014-05-12T18:36:35.069-0700: 3986.144 563 0 0.60 0.04 0.27 1724416 1721344 9437184 2014-05-12T18:36:35.354-0700: 3986.429 564 0 0.33 0.04 0.09 1725440 1722368 9437184 2014-05-12T18:36:35.545-0700: 3986.620 565 0 0.58 0.04 0.17 1726464 1722368 9437184 2014-05-12T18:36:35.726-0700: 3986.801 566 0 0.43 0.05 0.12 1726464 1722368 9437184 2014-05-12T18:36:35.856-0700: 3986.930 567 0 0.30 0.04 0.07 1726464 1723392 9437184 2014-05-12T18:36:35.947-0700: 3987.023 568 0 0.61 0.04 0.26 1727488 1723392 9437184 2014-05-12T18:36:36.228-0700: 3987.302 569 0 0.46 0.04 0.16 1731584 1724416 9437184 Reading the Data into R Once the GC log data had been cleansed, either by processing the first format with the shell script, or by processing the second format with the awk script, it was easy to read the data into R. g1gc.df = read.csv("summary.txt", row.names = NULL, stringsAsFactors=FALSE,sep="") str(g1gc.df) ## 'data.frame': 8307 obs. of 10 variables: ## $ row.names : chr "2014-05-12T14:00:32.868-0700:" "2014-05-12T14:00:33.179-0700:" "2014-05-12T14:00:33.677-0700:" "2014-05-12T14:00:35.538-0700:" ... ## $ SecondsSinceLaunch: num 1.16 1.47 1.97 3.83 6.1 ... ## $ IncrementalCount : int 0 1 2 3 4 5 6 7 8 9 ... ## $ FullCount : int 0 0 0 0 0 0 0 0 0 0 ... ## $ UserTime : num 0.11 0.05 0.04 0.21 0.08 0.26 0.31 0.33 0.34 0.56 ... ## $ SysTime : num 0.04 0.01 0.01 0.05 0.01 0.06 0.07 0.06 0.07 0.09 ... ## $ RealTime : num 0.02 0.02 0.01 0.04 0.02 0.04 0.05 0.04 0.04 0.06 ... ## $ BeforeSize : int 8192 5496 5768 22528 24576 43008 34816 53248 55296 93184 ... ## $ AfterSize : int 1400 1672 2557 4907 7072 14336 16384 18432 19456 21504 ... ## $ TotalSize : int 9437184 9437184 9437184 9437184 9437184 9437184 9437184 9437184 9437184 9437184 ... head(g1gc.df) ## row.names SecondsSinceLaunch IncrementalCount ## 1 2014-05-12T14:00:32.868-0700: 1.161 0 ## 2 2014-05-12T14:00:33.179-0700: 1.472 1 ## 3 2014-05-12T14:00:33.677-0700: 1.969 2 ## 4 2014-05-12T14:00:35.538-0700: 3.830 3 ## 5 2014-05-12T14:00:37.811-0700: 6.103 4 ## 6 2014-05-12T14:00:41.428-0700: 9.720 5 ## FullCount UserTime SysTime RealTime BeforeSize AfterSize TotalSize ## 1 0 0.11 0.04 0.02 8192 1400 9437184 ## 2 0 0.05 0.01 0.02 5496 1672 9437184 ## 3 0 0.04 0.01 0.01 5768 2557 9437184 ## 4 0 0.21 0.05 0.04 22528 4907 9437184 ## 5 0 0.08 0.01 0.02 24576 7072 9437184 ## 6 0 0.26 0.06 0.04 43008 14336 9437184 Basic Statistics Once the data has been read into R, simple statistics are very easy to generate. All of the numbers from high school statistics are available via simple commands. For example, generate a summary of every column: summary(g1gc.df) ## row.names SecondsSinceLaunch IncrementalCount FullCount ## Length:8307 Min. : 1 Min. : 0 Min. : 0.0 ## Class :character 1st Qu.: 9977 1st Qu.:2048 1st Qu.: 0.0 ## Mode :character Median :12855 Median :4136 Median : 12.0 ## Mean :12527 Mean :4156 Mean : 31.6 ## 3rd Qu.:15758 3rd Qu.:6262 3rd Qu.: 61.0 ## Max. :55484 Max. :8391 Max. :113.0 ## UserTime SysTime RealTime BeforeSize ## Min. :0.040 Min. :0.0000 Min. : 0.0 Min. : 5476 ## 1st Qu.:0.470 1st Qu.:0.0300 1st Qu.: 0.1 1st Qu.:5137920 ## Median :0.620 Median :0.0300 Median : 0.1 Median :6574080 ## Mean :0.751 Mean :0.0355 Mean : 0.3 Mean :5841855 ## 3rd Qu.:0.920 3rd Qu.:0.0400 3rd Qu.: 0.2 3rd Qu.:7084032 ## Max. :3.370 Max. :1.5600 Max. :488.1 Max. :8696832 ## AfterSize TotalSize ## Min. : 1380 Min. :9437184 ## 1st Qu.:5002752 1st Qu.:9437184 ## Median :6559744 Median :9437184 ## Mean :5785454 Mean :9437184 ## 3rd Qu.:7054336 3rd Qu.:9437184 ## Max. :8482816 Max. :9437184 Q: What is the total amount of User CPU time spent in garbage collection? sum(g1gc.df$UserTime) ## [1] 6236 As you can see, less than two hours of CPU time was spent in garbage collection. Is that too much? To find the percentage of time spent in garbage collection, divide the number above by total_elapsed_time*CPU_count. In this case, there are a lot of CPU’s and it turns out the the overall amount of CPU time spent in garbage collection isn’t a problem when viewed in isolation. When calculating rates, i.e. events per unit time, you need to ask yourself if the rate is homogenous across the time period in the log file. Does the log file include spikes of high activity that should be separately analyzed? Averaging in data from nights and weekends with data from business hours may alias problems. If you have a reason to suspect that the garbage collection rates include peaks and valleys that need independent analysis, see the “Time Series” section, below. Q: How much garbage is collected on each pass? The amount of heap space that is recovered per GC pass is surprisingly low: At least one collection didn’t recover any data. (“Min.=0”) 25% of the passes recovered 3MB or less. (“1st Qu.=3072”) Half of the GC passes recovered 4MB or less. (“Median=4096”) The average amount recovered was 56MB. (“Mean=56390”) 75% of the passes recovered 36MB or less. (“3rd Qu.=36860”) At least one pass recovered 2GB. (“Max.=2121000”) g1gc.df$Delta = g1gc.df$BeforeSize - g1gc.df$AfterSize summary(g1gc.df$Delta) ## Min. 1st Qu. Median Mean 3rd Qu. Max. ## 0 3070 4100 56400 36900 2120000 Q: What is the maximum User CPU time for a single collection? The worst garbage collection (“Max.”) is many standard deviations away from the mean. The data appears to be right skewed. summary(g1gc.df$UserTime) ## Min. 1st Qu. Median Mean 3rd Qu. Max. ## 0.040 0.470 0.620 0.751 0.920 3.370 sd(g1gc.df$UserTime) ## [1] 0.3966 Basic Graphics Once the data is in R, it is trivial to plot the data with formats including dot plots, line charts, bar charts (simple, stacked, grouped), pie charts, boxplots, scatter plots histograms, and kernel density plots. Histogram of User CPU Time per Collection I don't think that this graph requires any explanation. hist(g1gc.df$UserTime, main="User CPU Time per Collection", xlab="Seconds", ylab="Frequency") Box plot to identify outliers When the initial data is viewed with a box plot, you can see the one crazy outlier in the real time per GC. Save this data point for future analysis and drop the outlier so that it’s not throwing off our statistics. Now the box plot shows many outliers, which will be examined later, using times series analysis. Notice that the scale of the x-axis changes drastically once the crazy outlier is removed. par(mfrow=c(2,1)) boxplot(g1gc.df$UserTime,g1gc.df$SysTime,g1gc.df$RealTime, main="Box Plot of Time per GC\n(dominated by a crazy outlier)", names=c("usr","sys","elapsed"), xlab="Seconds per GC", ylab="Time (Seconds)", horizontal = TRUE, outcol="red") crazy.outlier.df=g1gc.df[g1gc.df$RealTime > 400,] g1gc.df=g1gc.df[g1gc.df$RealTime < 400,] boxplot(g1gc.df$UserTime,g1gc.df$SysTime,g1gc.df$RealTime, main="Box Plot of Time per GC\n(crazy outlier excluded)", names=c("usr","sys","elapsed"), xlab="Seconds per GC", ylab="Time (Seconds)", horizontal = TRUE, outcol="red") box(which = "outer", lty = "solid") Here is the crazy outlier for future analysis: crazy.outlier.df ## row.names SecondsSinceLaunch IncrementalCount ## 8233 2014-05-12T23:15:43.903-0700: 20741 8316 ## FullCount UserTime SysTime RealTime BeforeSize AfterSize TotalSize ## 8233 112 0.55 0.42 488.1 8381440 8235008 9437184 ## Delta ## 8233 146432 R Time Series Data To analyze the garbage collection as a time series, I’ll use Z’s Ordered Observations (zoo). “zoo is the creator for an S3 class of indexed totally ordered observations which includes irregular time series.” require(zoo) ## Loading required package: zoo ## ## Attaching package: 'zoo' ## ## The following objects are masked from 'package:base': ## ## as.Date, as.Date.numeric head(g1gc.df[,1]) ## [1] "2014-05-12T14:00:32.868-0700:" "2014-05-12T14:00:33.179-0700:" ## [3] "2014-05-12T14:00:33.677-0700:" "2014-05-12T14:00:35.538-0700:" ## [5] "2014-05-12T14:00:37.811-0700:" "2014-05-12T14:00:41.428-0700:" options("digits.secs"=3) times=as.POSIXct( g1gc.df[,1], format="%Y-%m-%dT%H:%M:%OS%z:") g1gc.z = zoo(g1gc.df[,-c(1)], order.by=times) head(g1gc.z) ## SecondsSinceLaunch IncrementalCount FullCount ## 2014-05-12 17:00:32.868 1.161 0 0 ## 2014-05-12 17:00:33.178 1.472 1 0 ## 2014-05-12 17:00:33.677 1.969 2 0 ## 2014-05-12 17:00:35.538 3.830 3 0 ## 2014-05-12 17:00:37.811 6.103 4 0 ## 2014-05-12 17:00:41.427 9.720 5 0 ## UserTime SysTime RealTime BeforeSize AfterSize ## 2014-05-12 17:00:32.868 0.11 0.04 0.02 8192 1400 ## 2014-05-12 17:00:33.178 0.05 0.01 0.02 5496 1672 ## 2014-05-12 17:00:33.677 0.04 0.01 0.01 5768 2557 ## 2014-05-12 17:00:35.538 0.21 0.05 0.04 22528 4907 ## 2014-05-12 17:00:37.811 0.08 0.01 0.02 24576 7072 ## 2014-05-12 17:00:41.427 0.26 0.06 0.04 43008 14336 ## TotalSize Delta ## 2014-05-12 17:00:32.868 9437184 6792 ## 2014-05-12 17:00:33.178 9437184 3824 ## 2014-05-12 17:00:33.677 9437184 3211 ## 2014-05-12 17:00:35.538 9437184 17621 ## 2014-05-12 17:00:37.811 9437184 17504 ## 2014-05-12 17:00:41.427 9437184 28672 Example of Two Benchmark Runs in One Log File The data in the following graph is from a different log file, not the one of primary interest to this article. I’m including this image because it is an example of idle periods followed by busy periods. It would be uninteresting to average the rate of garbage collection over the entire log file period. More interesting would be the rate of garbage collect in the two busy periods. Are they the same or different? Your production data may be similar, for example, bursts when employees return from lunch and idle times on weekend evenings, etc. Once the data is in an R Time Series, you can analyze isolated time windows. Clipping the Time Series data Flashing back to our test case… Viewing the data as a time series is interesting. You can see that the work intensive time period is between 9:00 PM and 3:00 AM. Lets clip the data to the interesting period:     par(mfrow=c(2,1)) plot(g1gc.z$UserTime, type="h", main="User Time per GC\nTime: Complete Log File", xlab="Time of Day", ylab="CPU Seconds per GC", col="#1b9e77") clipped.g1gc.z=window(g1gc.z, start=as.POSIXct("2014-05-12 21:00:00"), end=as.POSIXct("2014-05-13 03:00:00")) plot(clipped.g1gc.z$UserTime, type="h", main="User Time per GC\nTime: Limited to Benchmark Execution", xlab="Time of Day", ylab="CPU Seconds per GC", col="#1b9e77") box(which = "outer", lty = "solid") Cumulative Incremental and Full GC count Here is the cumulative incremental and full GC count. When the line is very steep, it indicates that the GCs are repeating very quickly. Notice that the scale on the Y axis is different for full vs. incremental. plot(clipped.g1gc.z[,c(2:3)], main="Cumulative Incremental and Full GC count", xlab="Time of Day", col="#1b9e77") GC Analysis of Benchmark Execution using Time Series data In the following series of 3 graphs: The “After Size” show the amount of heap space in use after each garbage collection. Many Java objects are still referenced, i.e. alive, during each garbage collection. This may indicate that the application has a memory leak, or may indicate that the application has a very large memory footprint. Typically, an application's memory footprint plateau's in the early stage of execution. One would expect this graph to have a flat top. The steep decline in the heap space may indicate that the application crashed after 2:00. The second graph shows that the outliers in real execution time, discussed above, occur near 2:00. when the Java heap seems to be quite full. The third graph shows that Full GCs are infrequent during the first few hours of execution. The rate of Full GC's, (the slope of the cummulative Full GC line), changes near midnight.   plot(clipped.g1gc.z[,c("AfterSize","RealTime","FullCount")], xlab="Time of Day", col=c("#1b9e77","red","#1b9e77")) GC Analysis of heap recovered Each GC trace includes the amount of heap space in use before and after the individual GC event. During garbage coolection, unreferenced objects are identified, the space holding the unreferenced objects is freed, and thus, the difference in before and after usage indicates how much space has been freed. The following box plot and bar chart both demonstrate the same point - the amount of heap space freed per garbage colloection is surprisingly low. par(mfrow=c(2,1)) boxplot(as.vector(clipped.g1gc.z$Delta), main="Amount of Heap Recovered per GC Pass", xlab="Size in KB", horizontal = TRUE, col="red") hist(as.vector(clipped.g1gc.z$Delta), main="Amount of Heap Recovered per GC Pass", xlab="Size in KB", breaks=100, col="red") box(which = "outer", lty = "solid") This graph is the most interesting. The dark blue area shows how much heap is occupied by referenced Java objects. This represents memory that holds live data. The red fringe at the top shows how much data was recovered after each garbage collection. barplot(clipped.g1gc.z[,c("AfterSize","Delta")], col=c("#7570b3","#e7298a"), xlab="Time of Day", border=NA) legend("topleft", c("Live Objects","Heap Recovered on GC"), fill=c("#7570b3","#e7298a")) box(which = "outer", lty = "solid") When I discuss the data in the log files with the customer, I will ask for an explaination for the large amount of referenced data resident in the Java heap. There are two are posibilities: There is a memory leak and the amount of space required to hold referenced objects will continue to grow, limited only by the maximum heap size. After the maximum heap size is reached, the JVM will throw an “Out of Memory” exception every time that the application tries to allocate a new object. If this is the case, the aplication needs to be debugged to identify why old objects are referenced when they are no longer needed. The application has a legitimate requirement to keep a large amount of data in memory. The customer may want to further increase the maximum heap size. Another possible solution would be to partition the application across multiple cluster nodes, where each node has responsibility for managing a unique subset of the data. Conclusion In conclusion, R is a very powerful tool for the analysis of Java garbage collection log files. The primary difficulty is data cleansing so that information can be read into an R data frame. Once the data has been read into R, a rich set of tools may be used for thorough evaluation.

    Read the article

  • Nginx + Haproxy + Thin + Rails - 503 Service Unavailable -

    - by Luca G. Soave
    I don't know how troubleshoot this. I get "503 Service Unavailable" http error for all "nginx upstreams" proxy passing calls to haproxy fast_thin and slow_thin ( server 127.0.0.1:3100 and server 127.0.0.1:3200 ), which loadbalance on 6 Thin servers ( 127.0.0.1:3000 .. 3005 ). Static files like /blog are currently fine. The falldown is: nginx on port 80 - haproxy on 3100 and 3200 - thin on 3000 .. 3005 and then Rails. Here it is /etc/nginx/nginx.conf : user nginx; worker_processes 2; pid /var/run/nginx.pid; events { worker_connections 1024; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; sendfile on; tcp_nopush on; keepalive_timeout 65; tcp_nodelay on; include /etc/nginx/conf.d/*.conf; } then /etc/nginx/conf.d/default.conf upstream fast_thin { server 127.0.0.1:3100; } upstream slow_thin { server 127.0.0.1:3200; } server { listen 80; server_name www.gitwatcher.com; rewrite ^/(.*) http://gitwatcher.com/$1 permanent; } server { listen 80; server_name gitwatcher.com; access_log /var/www/gitwatcher/log/access.log; error_log /var/www/gitwatcher/log/error.log; root /var/www/gitwatcher/public; # index index.html; location /about { proxy_pass http://fast_thin; break; } location /trends { proxy_pass http://slow_thin; break; } location /categories { proxy_pass http://slow_thin; break; } location /signout { proxy_pass http://slow_thin; break; } location /auth/github { proxy_pass http://slow_thin; break; } location / { proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_redirect off; if (-f $request_filename/index.html) { rewrite (.*) $1/index.html break; } if (-f $request_filename.html) { rewrite (.*) $1.html break; } if (!-f $request_filename) { proxy_pass http://slow_thin; break; } } } then haproxy config file /etc/haproxy/haproxy.cfg : global log 127.0.0.1 local0 log 127.0.0.1 local1 notice #log loghost local0 info maxconn 4096 #chroot /usr/share/haproxy user haproxy group haproxy daemon #debug #quiet nbproc 1 # number of processing cores defaults log global retries 3 maxconn 2000 contimeout 5000 mode http clitimeout 60000 # maximum inactivity time on the client side srvtimeout 30000 # maximum inactivity time on the server side timeout connect 4000 # maximum time to wait for a connection attempt to a server to succeed option httplog option dontlognull option redispatch option httpclose # disable keepalive (HAProxy does not yet support the HTTP keep-alive mode) option abortonclose # enable early dropping of aborted requests from pending queue option httpchk # enable HTTP protocol to check on servers health option forwardfor # enable insert of X-Forwarded-For headers balance roundrobin # each server is used in turns, according to assigned weight stats enable # enable web-stats at /haproxy?stats stats auth haproxy:pr0xystats # force HTTP Auth to view stats stats refresh 5s # refresh rate of stats page listen rails_proxy 127.0.0.1:3100 # - equal weights on all servers # - maxconn will queue requests at HAProxy if limit is reached # - minconn dynamically scales the connection concurrency (bound my maxconn) depending on size of HAProxy queue # - check health every 20000 microseconds server web1 127.0.0.1:3000 weight 1 minconn 3 maxconn 6 check inter 20000 server web1 127.0.0.1:3001 weight 1 minconn 3 maxconn 6 check inter 20000 server web1 127.0.0.1:3002 weight 1 minconn 3 maxconn 6 check inter 20000 listen slow_proxy 127.0.0.1:3200 # cluster for slow requests, lower the queues, check less frequently server slow1 127.0.0.1:3003 weight 1 minconn 1 maxconn 3 check inter 40000 server slow2 127.0.0.1:3004 weight 1 minconn 1 maxconn 3 check inter 40000 server slow3 127.0.0.1:3005 weight 1 minconn 1 maxconn 3 check inter 40000 and the Thin config file /etc/thin/gitwatcher.yml : --- chdir: /var/www/gitwatcher environment: production address: 0.0.0.0 port: 3000 timeout: 30 log: log/thin.log pid: tmp/pids/thin.pid max_conns: 1024 max_persistent_conns: 100 require: [] wait: 30 servers: 6 daemonize: true if I look into open listen ports, I got the following : root@fullness:/var/www/gitwatcher# lsof | grep TCP | egrep "nginx|haproxy|thin" nginx 834 root 8u IPv4 921 0t0 TCP *:http (LISTEN) nginx 835 nginx 8u IPv4 921 0t0 TCP *:http (LISTEN) nginx 837 nginx 8u IPv4 921 0t0 TCP *:http (LISTEN) haproxy 1908 haproxy 4u IPv4 11699 0t0 TCP localhost:3100 (LISTEN) haproxy 1908 haproxy 6u IPv4 11701 0t0 TCP localhost:3200 (LISTEN) root@fullness:/var/www/gitwatcher# iptables -L get me the following : Chain INPUT (policy DROP) target prot opt source destination ACCEPT all -- anywhere anywhere state RELATED,ESTABLISHED ACCEPT all -- anywhere anywhere state RELATED,ESTABLISHED ACCEPT tcp -- anywhere anywhere tcp dpt:22222 ACCEPT tcp -- anywhere anywhere tcp dpt:http ACCEPT tcp -- anywhere anywhere tcp dpt:https ACCEPT all -- anywhere anywhere DROP all -- anywhere anywhere Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination ACCEPT all -- anywhere anywhere Any help ?

    Read the article

  • Ubuntu 12.04 does not see windows already install on my computer (dual installation)

    - by jacinta
    I was trying to install the ubuntu 12.4 along side windows 7 on my new HP Pavilion 64k desktop with windows 7 computer but Ubuntu said that ( This computer has no detected operating system) and some one said (I suggest you chkdsk your Windows partition. I also suggest you resize the NTFS in WIndows then install Ubuntu to the free space.) Therefore I did (To shrink a simple or spanned volume using the Windows interface In Disk Management, right-click the simple or spanned volume you want to shrink. Click Shrink Volume…. Follow the instructions on your screen.) Then When I try to install ubuntu 12.4 after doing this, I received the same error. I was going to undo what I did but I see that I lose 1g when I do that so now what do I do? it says I can do a new simple volume and maybe then the space will no longer be unallocated. Please help me. I think I have a bad cd (ubuntu 12.4) cause from my research I see that I am not suppose to get a screen saying that (The computer has no detected operating system) I think this is a bad cd and I hope I did not mess up my computer. Please help. .................................................................................... O k I think I am following what you said about how to edit my question irrational john. I did chkdsk as you and actionparsnip (andrew-woodhead666) told me to AND ALSO did a lot of other things before I found out how to chkdsk. No problems. Thank you. Then I put back the space (extended) I took from system. I still was only able to put back 15 and not 16 so it is up to 99mb not back to 100mb. Then I shrank HP (C) as you told me, to 10 13,240 mb which is (12.93gb Unallocated). I did not change it into NTSF by doing the (New Simple Volume Action) I just left it. Then I tried to install UBUNTU 12.04 live CD amd64 and it gave me the results it was sometimes giving me before which is result (THAT Ubuntu) does not tell me weather I have or have not an already installed windows7. It just goes to a window that would have showed me information on what I have and on the bottom (DEVICE FOR BOOT LOADER INSTALLATION /dev/sda ) and the option to go BACK, QUIT, or INSTALL. (I think it is the INSTALLATION TYPE window). Therefore I do what I have been doing and I QUIT. What do I do now? Sorry that it seems like I cannot do anything on my own. On the Youtube video how to install ubuntu dual-boot alongside windows UBUNTU is installed so easy. The installation option page gives 3 options including dual instillation and the disk even lets you use a slider to slide to the size of the partition size you want. Yet my UBUNTU live cd is a mess and I checked it as one of you guys told me and got back information that it is good. Oh well this guy says you should press a control key to tell which device you are using to install ubuntu before the screen comes up. I guess cause it is old. This page also shows you easy stuff that do not show up on my cd. how to dual-boot UBUNTU and windows 7 P.S.. I saw this on the windows 7 website windows.microsoft.com/en-US/windows7/Formatting-disks-and-drives-frequently-asked-questions CREATE A BOOT PARTITION I HAD TO LEAVE OUT THE HTTP STUFF CAUSE I AM ONLY ALLOWED 2 ON A PAGE IT SAID To create a boot partition Warning Warning If you are installing different versions of Windows, you must install the earliest version first. If you don't do this, your computer may become inoperable. Open Computer Management by clicking the Start button Picture of the Start button, clicking Control Panel, clicking System and Security, clicking Administrative Tools, and then double-clicking Computer Management.? Administrator permission required If you're prompted for an administrator password or confirmation, type the password or provide confirmation. In the left pane, under Storage, click Disk Management. Right-click an unallocated region on your hard disk, and then click New Simple Volume. In the New Simple Volume Wizard, click Next. Type the size of the volume you want to create in megabytes (MB) or accept the maximum default size, and then click Next. Accept the default drive letter or choose a different drive letter to identify the volume, and then click Next. In the Format Partition dialog box, do one of the following: If you don't want to format the volume right now, click Do not format this volume, and then click Next. To format the volume with the default settings, click Next. For more information about formatting, see Formatting disks and drives: frequently asked questions. Review your choices, and then click Finish. AND THIS ON ANOTHER PAGE. Formatting disks and drives: frequently asked questions Hard disks, the primary storage devices on your computer, need to be formatted before you can use them. When you format a disk, you configure it with a file system so that Windows can store information on the disk. Hard disks in new computers running Windows are already formatted. If you buy an additional hard disk to expand the storage of your computer, you might need to format it. Storage devices such as USB flash drives and flash memory cards usually come preformatted by the manufacturer, so you probably won't need to format them. CDs and DVDs, on the other hand, use different formats from hard disks and removable storage devices. For information about formatting CDs and DVDs, see Which CD or DVD format should I use? Warning Warning Formatting erases any existing files on a hard disk. If you format a hard disk that has files on it, the files will be deleted. WHAT I DID WAS I GOT TO COMPUTER MANAGEMENT SECTION THEN I CLICKED ON DRIVE HP(C) (it put stripes on to show it is selected) Then I click on ACTION selected ALL TASKS AND THEN selected SHRINK VOLUME and then chose how much space from what it was giving me that I wanted. (12.93gb) AND THAT WAS ALL I DID. THEN I TRIED TO INSTALL UBUNTU i NEVER GOT THE 3RD SCREEN THAT IS IN THE VIDEO I INCLUDED (THE YOUTUBE WITH THE ENGLISH GUY) INSTALLATION TYPE I ALSO DID NOT GET THE 4TH SCREEN THAT ALLOWS YOU TO SELECT PARTITION SIZE what i got next was the 2nd INSTILLATION TYPE window shown on the (LINUX BS DOS.COM) PAGE THAT I INCLUDED and it showed no information about any drives (no drives /partition or stuff was shown) only the Boot Loader statement and the dev/sda bar and that's why i did not press install but chose to QUIT. SORRY I JUST NOW SAW YOUR ANSWER IRRATIONAL JOHN. I SHRANK HP(C) BY 12.93GB MY UNALLOCATED SPACE IS NOW 12.93GB HP(C) = 907.17gb NTSF...YOU ARE CORRECT WITH EVERYTHING YOU SAID This is what i read on (http://)windows.microsoft.com/en-US/windows7/Create-a-boot-partition I am only allowed 2 links Create a boot partition You must be logged on as an administrator to perform these steps. A boot partition is a partition that contains the files for the Windows operating system. If you want to install a second operating system on your computer (called a dual-boot or multiboot configuration), you need to create another partition on the hard disk, and then install the additional operating system on the new partition. Your hard disk would then have one system partition and two boot partitions. (A system partition is the partition that contains the hardware-related files. These tell the computer where to look to start Windows.) To create a partition on a basic disk, there must be unallocated disk space on your hard disk. With Disk Management, you can create a maximum of three primary partitions on a hard disk. You can create extended partitions, which include logical drives within them, if you need more partitions on the disk. Picture of disk space in Computer ManagementUnallocated disk space If there is no unallocated space, you will either need to create space by shrinking or deleting an existing partition or by using a third-party partitioning tool to repartition your hard disk. For more information, see Can I repartition my hard disk? To create a boot partition Warning Warning If you are installing different versions of Windows, you must install the earliest version first. If you don't do this, your computer may become inoperable. Open Computer Management by clicking the Start button Picture of the Start button, clicking Control Panel, clicking System and Security, clicking Administrative Tools, and then double-clicking Computer Management.? Administrator permission required If you're prompted for an administrator password or confirmation, type the password or provide confirmation. In the left pane, under Storage, click Disk Management. Right-click an unallocated region on your hard disk, and then click New Simple Volume. In the New Simple Volume Wizard, click Next. Type the size of the volume you want to create in megabytes (MB) or accept the maximum default size, and then click Next. Accept the default drive letter or choose a different drive letter to identify the volume, and then click Next. In the Format Partition dialog box, do one of the following: If you don't want to format the volume right now, click Do not format this volume, and then click Next. To format the volume with the default settings, click Next. For more information about formatting, see Formatting disks and drives: frequently asked questions. Review your choices, and then click Finish. I did what you told me @irrational john and this is the screen shot. I ENTERED ubuntu@ubuntu:~$ sudo os-prober computer did not respond so I entered ubuntu@ubuntu:~$ sudo apt-get -y remove dmraid computer responded with Reading package lists... Done Building dependency tree Reading state information... Done The following packages will be REMOVED: dmraid 0 upgraded, 0 newly installed, 1 to remove and 0 not upgraded. After this operation, 141 kB disk space will be freed. (Reading database ... 147515 files and directories currently installed.) Removing dmraid ... update-initramfs is disabled since running on read-only media Processing triggers for man-db ... I entered ubuntu@ubuntu:~$ sudo os-prober Computer Responded with /dev/sda1:Windows 7 (loader):Windows:chain /dev/sda3:Windows Recovery Environment (loader):Windows1:chain ubuntu@ubuntu:~$ ............... @obsessiveFOSS I don't know what is a Grub menu and I do not know what is the Ubuntu boot option The answer you gave to me was correct. This one {This apparently removes the dmraid metadata. After doing that, you can use the desktop icon Install Ubuntu 12.04 LTS to start the Ubuntu installer. This time the Installation Type window should contain the option to Install Ubuntu alongside Windows 7.} This is what I decided to do. I did not see the rest of your help 'till now. Never the less. I think the best thing for me to do now is to get a cheap used laptop and either do a dual installation or just install Ubuntu on to it. This way if I have any issues that I cannot solve like the one I had here, at least I will still have a usable computer to work on and to use to get answers with because I am not an expert like the people on this forum. Thanks a lot I will try to keep learning and do research enough to some day help someone else.

    Read the article

  • Salesforce/PHP - Bulk Outbound message (SOAP), Time out issue - See update #2

    - by Phill Pafford
    Salesforce can send up to 100 requests inside 1 SOAP message. While sending this type of Bulk Ooutbound message request my PHP script finishes executing but SF fails to accept the ACK used to clear the message queue on the Salesforce side of things. Looking at the Outbound message log (monitoring) I see all the messages in a pending state with the Delivery Failure Reason "java.net.SocketTimeoutException: Read timed out". If my script has finished execution, why do I get this error? I have tried these methods to increase the execution time on my server as I have no access on the Salesforce side: set_time_limit(0); // in the script max_execution_time = 360 ; Maximum execution time of each script, in seconds max_input_time = 360 ; Maximum amount of time each script may spend parsing request data memory_limit = 32M ; Maximum amount of memory a script may consume I used the high settings just for testing. Any thoughts as to why this is failing the ACK delivery back to Salesforce? Here is some of the code: This is how I accept and send the ACK file for the imcoming SOAP request $data = 'php://input'; $content = file_get_contents($data); if($content) { respond('true'); } else { respond('false'); } The respond function function respond($tf) { $ACK = <<<ACK <?xml version = "1.0" encoding = "utf-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <soapenv:Body> <notifications xmlns="http://soap.sforce.com/2005/09/outbound"> <Ack>$tf</Ack> </notifications> </soapenv:Body> </soapenv:Envelope> ACK; print trim($ACK); } These are in a generic script that I include into the script that uses the data for a specific workflow. I can process about 25 requests (That are in 1 SOAP response) but once I go over that I get the timeout error in the Salesforce queue. for 50 requests is usually takes my PHP script 86.77 seconds. Could it be Apache? PHP? I have also tested just accepting the 100 request SOAP response and just accepting and sending the ACK the queue clears out, so I know it's on my side of things. I show no errors in the apache log, the script runs fine. I did find some info on the Salesforce site but still no luck. Here is the link. Also I'm using the PHP Toolkit 11 (From Salesforce). Other forum with good SF help Thanks for any insight into this, --Phill UPDATE: If I receive the incoming message and print the response, should this happen first regardless if I do anything else after? Or does it wait for my process to finish and then print the response? UPDATE #2: okay I think I have the problem: PHP uses the single thread processing approach and will not send back the ACK file until the thread has completed it's processing. Is there a way to make this a mutli thread process? Thread #1 - accept the incoming SOAP request and send back the ACK Thread #2 - Process the SOAP request I know I could break it up into like a DB table or flat file, but is there a way to accomplish this without doing that? I'm going to try to close the socket after the ACK submission and continue the processing, cross my fingers it will work.

    Read the article

  • Getting java.lang.ClassNotFoundException: com.mysql.jdbc.Driver Exception

    - by Yashwant Chavan
    Hi , I am getting Following Exception while configuring the Connection Pool in Tomcat This is Context.xml <Context path="/DBTest" docBase="DBTest" debug="5" reloadable="true" crossContext="true"> <!-- maxActive: Maximum number of dB connections in pool. Make sure you configure your mysqld max_connections large enough to handle all of your db connections. Set to -1 for no limit. --> <!-- maxIdle: Maximum number of idle dB connections to retain in pool. Set to -1 for no limit. See also the DBCP documentation on this and the minEvictableIdleTimeMillis configuration parameter. --> <!-- maxWait: Maximum time to wait for a dB connection to become available in ms, in this example 10 seconds. An Exception is thrown if this timeout is exceeded. Set to -1 to wait indefinitely. --> <!-- username and password: MySQL dB username and password for dB connections --> <!-- driverClassName: Class name for the old mm.mysql JDBC driver is org.gjt.mm.mysql.Driver - we recommend using Connector/J though. Class name for the official MySQL Connector/J driver is com.mysql.jdbc.Driver. --> <!-- url: The JDBC connection url for connecting to your MySQL dB. --> <Resource name="jdbc/TestDB" auth="Container" type="javax.sql.DataSource" maxActive="100" maxIdle="30" maxWait="10000" username="root" password="password" driverClassName="com.mysql.jdbc.Driver" url="jdbc:mysql:///BUSINESS"/> </Context> This is Bean Entry <bean id="dataSource" class="org.springframework.jndi.JndiObjectFactoryBean"> <property name="jndiName" value="jdbc/TestDB"></property> <property name="resourceRef" value="true"></property> </bean> org.springframework.jdbc.CannotGetJdbcConnectionException: Could not get JDBC Co nnection; nested exception is org.apache.tomcat.dbcp.dbcp.SQLNestedException: Ca nnot load JDBC driver class 'com.mysql.jdbc.Driver' at org.springframework.jdbc.datasource.DataSourceUtils.getConnection(Dat aSourceUtils.java:82) at org.springframework.jdbc.core.JdbcTemplate.execute(JdbcTemplate.java: 382) at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:45 8) at org.springframework.jdbc.core.JdbcTemplate.query(JdbcTemplate.java:46 6) at com.businesscaliber.dao.Dao.getQueryForListMap(Dao.java:66) at com.businesscaliber.dao.MiscellaneousDao.getDefaultSucessStory(Miscel laneousDao.java:109) at com.businesscaliber.listeners.BusinessContextLoader.contextInitialize d(BusinessContextLoader.java:40) at org.apache.catalina.core.StandardContext.listenerStart(StandardContex t.java:3795) at org.apache.catalina.core.StandardContext.start(StandardContext.java:4 252) at org.apache.catalina.core.ContainerBase.addChildInternal(ContainerBase .java:760) at org.apache.catalina.core.ContainerBase.addChild(ContainerBase.java:74 0) at org.apache.catalina.core.StandardHost.addChild(StandardHost.java:544) at org.apache.catalina.startup.HostConfig.deployWAR(HostConfig.java:831) at org.apache.catalina.startup.HostConfig.deployWARs(HostConfig.java:720 ) at org.apache.catalina.startup.HostConfig.deployApps(HostConfig.java:490 ) at org.apache.catalina.startup.HostConfig.start(HostConfig.java:1150) at org.apache.catalina.startup.HostConfig.lifecycleEvent(HostConfig.java :311) at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(Lifecycl eSupport.java:120) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1022) at org.apache.catalina.core.StandardHost.start(StandardHost.java:736) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1014) at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443 ) at org.apache.catalina.core.StandardService.start(StandardService.java:4 48) at org.apache.catalina.core.StandardServer.start(StandardServer.java:700 ) at org.apache.catalina.startup.Catalina.start(Catalina.java:552) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl. java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAcces sorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:585) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:295) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:433) Caused by: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot load JDBC driv er class 'com.mysql.jdbc.Driver' at org.apache.tomcat.dbcp.dbcp.BasicDataSource.createDataSource(BasicDat aSource.java:1136) at org.apache.tomcat.dbcp.dbcp.BasicDataSource.getConnection(BasicDataSo urce.java:880) at org.springframework.jdbc.datasource.DataSourceUtils.doGetConnection(D ataSourceUtils.java:113) at org.springframework.jdbc.datasource.DataSourceUtils.getConnection(Dat aSourceUtils.java:79) ... 30 more Caused by: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:306) at java.lang.ClassLoader.loadClass(ClassLoader.java:251) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:319) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:164) at org.apache.tomcat.dbcp.dbcp.BasicDataSource.createDataSource(BasicDat aSource.java:1130)

    Read the article

  • Explain the Peak and Flag Algorithm

    - by Isaac Levin
    EDIT Just was pointed that the requirements state peaks cannot be ends of Arrays. So I ran across this site http://codility.com/ Which gives you programming problems and gives you certificates if you can solve them in 2 hours. The very first question is one I have seen before, typically called the Peaks and Flags question. If you are not familiar A non-empty zero-indexed array A consisting of N integers is given. A peak is an array element which is larger than its neighbours. More precisely, it is an index P such that 0 < P < N - 1 and A[P - 1] < A[P] A[P + 1] . For example, the following array A: A[0] = 1 A[1] = 5 A[2] = 3 A[3] = 4 A[4] = 3 A[5] = 4 A[6] = 1 A[7] = 2 A[8] = 3 A[9] = 4 A[10] = 6 A[11] = 2 has exactly four peaks: elements 1, 3, 5 and 10. You are going on a trip to a range of mountains whose relative heights are represented by array A. You have to choose how many flags you should take with you. The goal is to set the maximum number of flags on the peaks, according to certain rules. Flags can only be set on peaks. What's more, if you take K flags, then the distance between any two flags should be greater than or equal to K. The distance between indices P and Q is the absolute value |P - Q|. For example, given the mountain range represented by array A, above, with N = 12, if you take: two flags, you can set them on peaks 1 and 5; three flags, you can set them on peaks 1, 5 and 10; four flags, you can set only three flags, on peaks 1, 5 and 10. You can therefore set a maximum of three flags in this case. Write a function that, given a non-empty zero-indexed array A of N integers, returns the maximum number of flags that can be set on the peaks of the array. For example, given the array above the function should return 3, as explained above. Assume that: N is an integer within the range [1..100,000]; each element of array A is an integer within the range [0..1,000,000,000]. Complexity: expected worst-case time complexity is O(N); expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments). Elements of input arrays can be modified. So this makes sense, but I failed it using this code public int GetFlags(int[] A) { List<int> peakList = new List<int>(); for (int i = 0; i <= A.Length - 1; i++) { if ((A[i] > A[i + 1] && A[i] > A[i - 1])) { peakList.Add(i); } } List<int> flagList = new List<int>(); int distance = peakList.Count; flagList.Add(peakList[0]); for (int i = 1, j = 0, max = peakList.Count; i < max; i++) { if (Math.Abs(Convert.ToDecimal(peakList[j]) - Convert.ToDecimal(peakList[i])) >= distance) { flagList.Add(peakList[i]); j = i; } } return flagList.Count; } EDIT int[] A = new int[] { 7, 10, 4, 5, 7, 4, 6, 1, 4, 3, 3, 7 }; The correct answer is 3, but my application says 2 This I do not get, since there are 4 peaks (indices 1,4,6,8) and from that, you should be able to place a flag at 2 of the peaks (1 and 6) Am I missing something here? Obviously my assumption is that the beginning or end of an Array can be a peak, is this not the case? If this needs to go in Stack Exchange Programmers, I will move it, but thought dialog here would be helpful. EDIT

    Read the article

  • Steganography Experiment - Trouble hiding message bits in DCT coefficients

    - by JohnHankinson
    I have an application requiring me to be able to embed loss-less data into an image. As such I've been experimenting with steganography, specifically via modification of DCT coefficients as the method I select, apart from being loss-less must also be relatively resilient against format conversion, scaling/DSP etc. From the research I've done thus far this method seems to be the best candidate. I've seen a number of papers on the subject which all seem to neglect specific details (some neglect to mention modification of 0 coefficients, or modification of AC coefficient etc). After combining the findings and making a few modifications of my own which include: 1) Using a more quantized version of the DCT matrix to ensure we only modify coefficients that would still be present should the image be JPEG'ed further or processed (I'm using this in place of simply following a zig-zag pattern). 2) I'm modifying bit 4 instead of the LSB and then based on what the original bit value was adjusting the lower bits to minimize the difference. 3) I'm only modifying the blue channel as it should be the least visible. This process must modify the actual image and not the DCT values stored in file (like jsteg) as there is no guarantee the file will be a JPEG, it may also be opened and re-saved at a later stage in a different format. For added robustness I've included the message multiple times and use the bits that occur most often, I had considered using a QR code as the message data or simply applying the reed-solomon error correction, but for this simple application and given that the "message" in question is usually going to be between 10-32 bytes I have plenty of room to repeat it which should provide sufficient redundancy to recover the true bits. No matter what I do I don't seem to be able to recover the bits at the decode stage. I've tried including / excluding various checks (even if it degrades image quality for the time being). I've tried using fixed point vs. double arithmetic, moving the bit to encode, I suspect that the message bits are being lost during the IDCT back to image. Any thoughts or suggestions on how to get this working would be hugely appreciated. (PS I am aware that the actual DCT/IDCT could be optimized from it's naive On4 operation using row column algorithm, or an FDCT like AAN, but for now it just needs to work :) ) Reference Papers: http://www.lokminglui.com/dct.pdf http://arxiv.org/ftp/arxiv/papers/1006/1006.1186.pdf Code for the Encode/Decode process in C# below: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Drawing.Imaging; using System.Drawing; namespace ImageKey { public class Encoder { public const int HIDE_BIT_POS = 3; // use bit position 4 (1 << 3). public const int HIDE_COUNT = 16; // Number of times to repeat the message to avoid error. // JPEG Standard Quantization Matrix. // (to get higher quality multiply by (100-quality)/50 .. // for lower than 50 multiply by 50/quality. Then round to integers and clip to ensure only positive integers. public static double[] Q = {16,11,10,16,24,40,51,61, 12,12,14,19,26,58,60,55, 14,13,16,24,40,57,69,56, 14,17,22,29,51,87,80,62, 18,22,37,56,68,109,103,77, 24,35,55,64,81,104,113,92, 49,64,78,87,103,121,120,101, 72,92,95,98,112,100,103,99}; // Maximum qauality quantization matrix (if all 1's doesn't modify coefficients at all). public static double[] Q2 = {1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1, 1,1,1,1,1,1,1,1}; public static Bitmap Encode(Bitmap b, string key) { Bitmap response = new Bitmap(b.Width, b.Height, PixelFormat.Format32bppArgb); uint imgWidth = ((uint)b.Width) & ~((uint)7); // Maximum usable X resolution (divisible by 8). uint imgHeight = ((uint)b.Height) & ~((uint)7); // Maximum usable Y resolution (divisible by 8). // Start be transferring the unmodified image portions. // As we'll be using slightly less width/height for the encoding process we'll need the edges to be populated. for (int y = 0; y < b.Height; y++) for (int x = 0; x < b.Width; x++) { if( (x >= imgWidth && x < b.Width) || (y>=imgHeight && y < b.Height)) response.SetPixel(x, y, b.GetPixel(x, y)); } // Setup the counters and byte data for the message to encode. StringBuilder sb = new StringBuilder(); for(int i=0;i<HIDE_COUNT;i++) sb.Append(key); byte[] codeBytes = System.Text.Encoding.ASCII.GetBytes(sb.ToString()); int bitofs = 0; // Current bit position we've encoded too. int totalBits = (codeBytes.Length * 8); // Total number of bits to encode. for (int y = 0; y < imgHeight; y += 8) { for (int x = 0; x < imgWidth; x += 8) { int[] redData = GetRedChannelData(b, x, y); int[] greenData = GetGreenChannelData(b, x, y); int[] blueData = GetBlueChannelData(b, x, y); int[] newRedData; int[] newGreenData; int[] newBlueData; if (bitofs < totalBits) { double[] redDCT = DCT(ref redData); double[] greenDCT = DCT(ref greenData); double[] blueDCT = DCT(ref blueData); int[] redDCTI = Quantize(ref redDCT, ref Q2); int[] greenDCTI = Quantize(ref greenDCT, ref Q2); int[] blueDCTI = Quantize(ref blueDCT, ref Q2); int[] blueDCTC = Quantize(ref blueDCT, ref Q); HideBits(ref blueDCTI, ref blueDCTC, ref bitofs, ref totalBits, ref codeBytes); double[] redDCT2 = DeQuantize(ref redDCTI, ref Q2); double[] greenDCT2 = DeQuantize(ref greenDCTI, ref Q2); double[] blueDCT2 = DeQuantize(ref blueDCTI, ref Q2); newRedData = IDCT(ref redDCT2); newGreenData = IDCT(ref greenDCT2); newBlueData = IDCT(ref blueDCT2); } else { newRedData = redData; newGreenData = greenData; newBlueData = blueData; } MapToRGBRange(ref newRedData); MapToRGBRange(ref newGreenData); MapToRGBRange(ref newBlueData); for(int dy=0;dy<8;dy++) { for(int dx=0;dx<8;dx++) { int col = (0xff<<24) + (newRedData[dx+(dy*8)]<<16) + (newGreenData[dx+(dy*8)]<<8) + (newBlueData[dx+(dy*8)]); response.SetPixel(x+dx,y+dy,Color.FromArgb(col)); } } } } if (bitofs < totalBits) throw new Exception("Failed to encode data - insufficient cover image coefficients"); return (response); } public static void HideBits(ref int[] DCTMatrix, ref int[] CMatrix, ref int bitofs, ref int totalBits, ref byte[] codeBytes) { int tempValue = 0; for (int u = 0; u < 8; u++) { for (int v = 0; v < 8; v++) { if ( (u != 0 || v != 0) && CMatrix[v+(u*8)] != 0 && DCTMatrix[v+(u*8)] != 0) { if (bitofs < totalBits) { tempValue = DCTMatrix[v + (u * 8)]; int bytePos = (bitofs) >> 3; int bitPos = (bitofs) % 8; byte mask = (byte)(1 << bitPos); byte value = (byte)((codeBytes[bytePos] & mask) >> bitPos); // 0 or 1. if (value == 0) { int a = DCTMatrix[v + (u * 8)] & (1 << HIDE_BIT_POS); if (a != 0) DCTMatrix[v + (u * 8)] |= (1 << HIDE_BIT_POS) - 1; DCTMatrix[v + (u * 8)] &= ~(1 << HIDE_BIT_POS); } else if (value == 1) { int a = DCTMatrix[v + (u * 8)] & (1 << HIDE_BIT_POS); if (a == 0) DCTMatrix[v + (u * 8)] &= ~((1 << HIDE_BIT_POS) - 1); DCTMatrix[v + (u * 8)] |= (1 << HIDE_BIT_POS); } if (DCTMatrix[v + (u * 8)] != 0) bitofs++; else DCTMatrix[v + (u * 8)] = tempValue; } } } } } public static void MapToRGBRange(ref int[] data) { for(int i=0;i<data.Length;i++) { data[i] += 128; if(data[i] < 0) data[i] = 0; else if(data[i] > 255) data[i] = 255; } } public static int[] GetRedChannelData(Bitmap b, int sx, int sy) { int[] data = new int[8 * 8]; for (int y = sy; y < (sy + 8); y++) { for (int x = sx; x < (sx + 8); x++) { uint col = (uint)b.GetPixel(x,y).ToArgb(); data[(x - sx) + ((y - sy) * 8)] = (int)((col >> 16) & 0xff) - 128; } } return (data); } public static int[] GetGreenChannelData(Bitmap b, int sx, int sy) { int[] data = new int[8 * 8]; for (int y = sy; y < (sy + 8); y++) { for (int x = sx; x < (sx + 8); x++) { uint col = (uint)b.GetPixel(x, y).ToArgb(); data[(x - sx) + ((y - sy) * 8)] = (int)((col >> 8) & 0xff) - 128; } } return (data); } public static int[] GetBlueChannelData(Bitmap b, int sx, int sy) { int[] data = new int[8 * 8]; for (int y = sy; y < (sy + 8); y++) { for (int x = sx; x < (sx + 8); x++) { uint col = (uint)b.GetPixel(x, y).ToArgb(); data[(x - sx) + ((y - sy) * 8)] = (int)((col >> 0) & 0xff) - 128; } } return (data); } public static int[] Quantize(ref double[] DCTMatrix, ref double[] Q) { int[] DCTMatrixOut = new int[8*8]; for (int u = 0; u < 8; u++) { for (int v = 0; v < 8; v++) { DCTMatrixOut[v + (u * 8)] = (int)Math.Round(DCTMatrix[v + (u * 8)] / Q[v + (u * 8)]); } } return(DCTMatrixOut); } public static double[] DeQuantize(ref int[] DCTMatrix, ref double[] Q) { double[] DCTMatrixOut = new double[8*8]; for (int u = 0; u < 8; u++) { for (int v = 0; v < 8; v++) { DCTMatrixOut[v + (u * 8)] = (double)DCTMatrix[v + (u * 8)] * Q[v + (u * 8)]; } } return(DCTMatrixOut); } public static double[] DCT(ref int[] data) { double[] DCTMatrix = new double[8 * 8]; for (int v = 0; v < 8; v++) { for (int u = 0; u < 8; u++) { double cu = 1; if (u == 0) cu = (1.0 / Math.Sqrt(2.0)); double cv = 1; if (v == 0) cv = (1.0 / Math.Sqrt(2.0)); double sum = 0.0; for (int y = 0; y < 8; y++) { for (int x = 0; x < 8; x++) { double s = data[x + (y * 8)]; double dctVal = Math.Cos((2 * y + 1) * v * Math.PI / 16) * Math.Cos((2 * x + 1) * u * Math.PI / 16); sum += s * dctVal; } } DCTMatrix[u + (v * 8)] = (0.25 * cu * cv * sum); } } return (DCTMatrix); } public static int[] IDCT(ref double[] DCTMatrix) { int[] Matrix = new int[8 * 8]; for (int y = 0; y < 8; y++) { for (int x = 0; x < 8; x++) { double sum = 0; for (int v = 0; v < 8; v++) { for (int u = 0; u < 8; u++) { double cu = 1; if (u == 0) cu = (1.0 / Math.Sqrt(2.0)); double cv = 1; if (v == 0) cv = (1.0 / Math.Sqrt(2.0)); double idctVal = (cu * cv) / 4.0 * Math.Cos((2 * y + 1) * v * Math.PI / 16) * Math.Cos((2 * x + 1) * u * Math.PI / 16); sum += (DCTMatrix[u + (v * 8)] * idctVal); } } Matrix[x + (y * 8)] = (int)Math.Round(sum); } } return (Matrix); } } public class Decoder { public static string Decode(Bitmap b, int expectedLength) { expectedLength *= Encoder.HIDE_COUNT; uint imgWidth = ((uint)b.Width) & ~((uint)7); // Maximum usable X resolution (divisible by 8). uint imgHeight = ((uint)b.Height) & ~((uint)7); // Maximum usable Y resolution (divisible by 8). // Setup the counters and byte data for the message to decode. byte[] codeBytes = new byte[expectedLength]; byte[] outBytes = new byte[expectedLength / Encoder.HIDE_COUNT]; int bitofs = 0; // Current bit position we've decoded too. int totalBits = (codeBytes.Length * 8); // Total number of bits to decode. for (int y = 0; y < imgHeight; y += 8) { for (int x = 0; x < imgWidth; x += 8) { int[] blueData = ImageKey.Encoder.GetBlueChannelData(b, x, y); double[] blueDCT = ImageKey.Encoder.DCT(ref blueData); int[] blueDCTI = ImageKey.Encoder.Quantize(ref blueDCT, ref Encoder.Q2); int[] blueDCTC = ImageKey.Encoder.Quantize(ref blueDCT, ref Encoder.Q); if (bitofs < totalBits) GetBits(ref blueDCTI, ref blueDCTC, ref bitofs, ref totalBits, ref codeBytes); } } bitofs = 0; for (int i = 0; i < (expectedLength / Encoder.HIDE_COUNT) * 8; i++) { int bytePos = (bitofs) >> 3; int bitPos = (bitofs) % 8; byte mask = (byte)(1 << bitPos); List<int> values = new List<int>(); int zeroCount = 0; int oneCount = 0; for (int j = 0; j < Encoder.HIDE_COUNT; j++) { int val = (codeBytes[bytePos + ((expectedLength / Encoder.HIDE_COUNT) * j)] & mask) >> bitPos; values.Add(val); if (val == 0) zeroCount++; else oneCount++; } if (oneCount >= zeroCount) outBytes[bytePos] |= mask; bitofs++; values.Clear(); } return (System.Text.Encoding.ASCII.GetString(outBytes)); } public static void GetBits(ref int[] DCTMatrix, ref int[] CMatrix, ref int bitofs, ref int totalBits, ref byte[] codeBytes) { for (int u = 0; u < 8; u++) { for (int v = 0; v < 8; v++) { if ((u != 0 || v != 0) && CMatrix[v + (u * 8)] != 0 && DCTMatrix[v + (u * 8)] != 0) { if (bitofs < totalBits) { int bytePos = (bitofs) >> 3; int bitPos = (bitofs) % 8; byte mask = (byte)(1 << bitPos); int value = DCTMatrix[v + (u * 8)] & (1 << Encoder.HIDE_BIT_POS); if (value != 0) codeBytes[bytePos] |= mask; bitofs++; } } } } } } } UPDATE: By switching to using a QR Code as the source message and swapping a pair of coefficients in each block instead of bit manipulation I've been able to get the message to survive the transform. However to get the message to come through without corruption I have to adjust both coefficients as well as swap them. For example swapping (3,4) and (4,3) in the DCT matrix and then respectively adding 8 and subtracting 8 as an arbitrary constant seems to work. This survives a re-JPEG'ing of 96 but any form of scaling/cropping destroys the message again. I was hoping that by operating on mid to low frequency values that the message would be preserved even under some light image manipulation.

    Read the article

  • SQL SERVER – Reducing CXPACKET Wait Stats for High Transactional Database

    - by pinaldave
    While engaging in a performance tuning consultation for a client, a situation occurred where they were facing a lot of CXPACKET Waits Stats. The client asked me if I could help them reduce this huge number of wait stats. I usually receive this kind of request from other client as well, but the important thing to understand is whether this question has any merits or benefits, or not. Before we continue the resolution, let us understand what CXPACKET Wait Stats are. The official definition suggests that CXPACKET Wait Stats occurs when trying to synchronize the query processor exchange iterator. You may consider lowering the degree of parallelism if a conflict concerning this wait type develops into a problem. (from BOL) In simpler words, when a parallel operation is created for SQL Query, there are multiple threads for a single query. Each query deals with a different set of the data (or rows). Due to some reasons, one or more of the threads lag behind, creating the CXPACKET Wait Stat. Threads which came first have to wait for the slower thread to finish. The Wait by a specific completed thread is called CXPACKET Wait Stat. Note that CXPACKET Wait is done by completed thread and not the one which are unfinished. “Note that not all the CXPACKET wait types are bad. You might experience a case when it totally makes sense. There might also be cases when this is also unavoidable. If you remove this particular wait type for any query, then that query may run slower because the parallel operations are disabled for the query.” Now let us see what the best practices to reduce the CXPACKET Wait Stats are. The suggestions, with which you will find that if you search online through the browser, would play a major role as and might be asked about their jobs In addition, might tell you that you should set ‘maximum degree of parallelism’ to 1. I do agree with these suggestions, too; however, I think this is not the final resolutions. As soon as you set your entire query to run on single CPU, you will get a very bad performance from the queries which are actually performing okay when using parallelism. The best suggestion to this is that you set ‘the maximum degree of parallelism’ to a lower number or 1 (be very careful with this – it can create more problems) but tune the queries which can be benefited from multiple CPU’s. You can use query hint OPTION (MAXDOP 0) to run the server to use parallelism. Here is the two-quick script which helps to resolve these issues: Change MAXDOP at Server Level EXEC sys.sp_configure N'max degree of parallelism', N'1' GO RECONFIGURE WITH OVERRIDE GO Run Query with all the CPU (using parallelism) USE AdventureWorks GO SELECT * FROM Sales.SalesOrderDetail ORDER BY ProductID OPTION (MAXDOP 0) GO Below is the blog post which will help you to find all the parallel query in your server. SQL SERVER – Find Queries using Parallelism from Cached Plan Please note running Queries in single CPU may worsen your performance and it is not recommended at all. Infect this can be very bad advise. I strongly suggest that you identify the queries which are offending and tune them instead of following any other suggestions. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, SQL White Papers, SQLAuthority News, T SQL, Technology

    Read the article

  • Sun Fire X4800 M2 Posts World Record x86 SPECjEnterprise2010 Result

    - by Brian
    Oracle's Sun Fire X4800 M2 using the Intel Xeon E7-8870 processor and Sun Fire X4470 M2 using the Intel Xeon E7-4870 processor, produced a world record single application server SPECjEnterprise2010 benchmark result of 27,150.05 SPECjEnterprise2010 EjOPS. The Sun Fire X4800 M2 server ran the application tier and the Sun Fire X4470 M2 server was used for the database tier. The Sun Fire X4800 M2 server demonstrated 63% better performance compared to IBM P780 server result of 16,646.34 SPECjEnterprise2010 EjOPS. The Sun Fire X4800 M2 server demonstrated 4% better performance than the Cisco UCS B440 M2 result, both results used the same number of processors. This result used Oracle WebLogic Server 12c, Java HotSpot(TM) 64-Bit Server 1.7.0_02, and Oracle Database 11g. This result was produced using Oracle Linux. Performance Landscape Complete benchmark results are at the SPEC website, SPECjEnterprise2010 Results. The table below compares against the best results from IBM and Cisco. SPECjEnterprise2010 Performance Chart as of 3/12/2012 Submitter EjOPS* Application Server Database Server Oracle 27,150.05 1x Sun Fire X4800 M2 8x 2.4 GHz Intel Xeon E7-8870 Oracle WebLogic 12c 1x Sun Fire X4470 M2 4x 2.4 GHz Intel Xeon E7-4870 Oracle Database 11g (11.2.0.2) Cisco 26,118.67 2x UCS B440 M2 Blade Server 4x 2.4 GHz Intel Xeon E7-4870 Oracle WebLogic 11g (10.3.5) 1x UCS C460 M2 Blade Server 4x 2.4 GHz Intel Xeon E7-4870 Oracle Database 11g (11.2.0.2) IBM 16,646.34 1x IBM Power 780 8x 3.86 GHz POWER 7 WebSphere Application Server V7 1x IBM Power 750 Express 4x 3.55 GHz POWER 7 IBM DB2 9.7 Workgroup Server Edition FP3a * SPECjEnterprise2010 EjOPS, bigger is better. Configuration Summary Application Server: 1 x Sun Fire X4800 M2 8 x 2.4 GHz Intel Xeon processor E7-8870 256 GB memory 4 x 10 GbE NIC 2 x FC HBA Oracle Linux 5 Update 6 Oracle WebLogic Server 11g Release 1 (10.3.5) Java HotSpot(TM) 64-Bit Server VM on Linux, version 1.7.0_02 (Java SE 7 Update 2) Database Server: 1 x Sun Fire X4470 M2 4 x 2.4 GHz Intel Xeon E7-4870 512 GB memory 4 x 10 GbE NIC 2 x FC HBA 2 x Sun StorageTek 2540 M2 4 x Sun Fire X4270 M2 4 x Sun Storage F5100 Flash Array Oracle Linux 5 Update 6 Oracle Database 11g Enterprise Edition Release 11.2.0.2 Benchmark Description SPECjEnterprise2010 is the third generation of the SPEC organization's J2EE end-to-end industry standard benchmark application. The SPECjEnterprise2010 benchmark has been designed and developed to cover the Java EE 5 specification's significantly expanded and simplified programming model, highlighting the major features used by developers in the industry today. This provides a real world workload driving the Application Server's implementation of the Java EE specification to its maximum potential and allowing maximum stressing of the underlying hardware and software systems. The workload consists of an end to end web based order processing domain, an RMI and Web Services driven manufacturing domain and a supply chain model utilizing document based Web Services. The application is a collection of Java classes, Java Servlets, Java Server Pages, Enterprise Java Beans, Java Persistence Entities (pojo's) and Message Driven Beans. The SPECjEnterprise2010 benchmark heavily exercises all parts of the underlying infrastructure that make up the application environment, including hardware, JVM software, database software, JDBC drivers, and the system network. The primary metric of the SPECjEnterprise2010 benchmark is jEnterprise Operations Per Second ("SPECjEnterprise2010 EjOPS"). This metric is calculated by adding the metrics of the Dealership Management Application in the Dealer Domain and the Manufacturing Application in the Manufacturing Domain. There is no price/performance metric in this benchmark. Key Points and Best Practices Sixteen Oracle WebLogic server instances were started using numactl, binding 2 instances per chip. Eight Oracle database listener processes were started, binding 2 instances per chip using taskset. Additional tuning information is in the report at http://spec.org. See Also Oracle Press Release -- SPECjEnterprise2010 Results Page Sun Fire X4800 M2 Server oracle.com OTN Sun Fire X4270 M2 Server oracle.com OTN Sun Storage 2540-M2 Array oracle.com OTN Oracle Linux oracle.com OTN Oracle Database 11g Release 2 Enterprise Edition oracle.com OTN WebLogic Suite oracle.com OTN Disclosure Statement SPEC and the benchmark name SPECjEnterprise are registered trademarks of the Standard Performance Evaluation Corporation. Sun Fire X4800 M2, 27,150.05 SPECjEnterprise2010 EjOPS; IBM Power 780, 16,646.34 SPECjEnterprise2010 EjOPS; Cisco UCS B440 M2, 26,118.67 SPECjEnterprise2010 EjOPS. Results from www.spec.org as of 3/27/2012.

    Read the article

  • Big Data – Beginning Big Data – Day 1 of 21

    - by Pinal Dave
    What is Big Data? I want to learn Big Data. I have no clue where and how to start learning about it. Does Big Data really means data is big? What are the tools and software I need to know to learn Big Data? I often receive questions which I mentioned above. They are good questions and honestly when we search online, it is hard to find authoritative and authentic answers. I have been working with Big Data and NoSQL for a while and I have decided that I will attempt to discuss this subject over here in the blog. In the next 21 days we will understand what is so big about Big Data. Big Data – Big Thing! Big Data is becoming one of the most talked about technology trends nowadays. The real challenge with the big organization is to get maximum out of the data already available and predict what kind of data to collect in the future. How to take the existing data and make it meaningful that it provides us accurate insight in the past data is one of the key discussion points in many of the executive meetings in organizations. With the explosion of the data the challenge has gone to the next level and now a Big Data is becoming the reality in many organizations. Big Data – A Rubik’s Cube I like to compare big data with the Rubik’s cube. I believe they have many similarities. Just like a Rubik’s cube it has many different solutions. Let us visualize a Rubik’s cube solving challenge where there are many experts participating. If you take five Rubik’s cube and mix up the same way and give it to five different expert to solve it. It is quite possible that all the five people will solve the Rubik’s cube in fractions of the seconds but if you pay attention to the same closely, you will notice that even though the final outcome is the same, the route taken to solve the Rubik’s cube is not the same. Every expert will start at a different place and will try to resolve it with different methods. Some will solve one color first and others will solve another color first. Even though they follow the same kind of algorithm to solve the puzzle they will start and end at a different place and their moves will be different at many occasions. It is  nearly impossible to have a exact same route taken by two experts. Big Market and Multiple Solutions Big Data is exactly like a Rubik’s cube – even though the goal of every organization and expert is same to get maximum out of the data, the route and the starting point are different for each organization and expert. As organizations are evaluating and architecting big data solutions they are also learning the ways and opportunities which are related to Big Data. There is not a single solution to big data as well there is not a single vendor which can claim to know all about Big Data. Honestly, Big Data is too big a concept and there are many players – different architectures, different vendors and different technology. What is Next? In this 31 days series we will be exploring many essential topics related to big data. I do not claim that you will be master of the subject after 31 days but I claim that I will be covering following topics in easy to understand language. Architecture of Big Data Big Data a Management and Implementation Different Technologies – Hadoop, Mapreduce Real World Conversations Best Practices Tomorrow In tomorrow’s blog post we will try to answer one of the very essential questions – What is Big Data? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Big Data, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

    Read the article

  • Dual Screen will only mirror after 12.04 upgrade

    - by Ne0
    I have been using Ubuntu with a dual screen for years now, after upgrading to 12.04 LTS i cannot get my dual screen working properly Graphics: 01:00.0 VGA compatible controller: Advanced Micro Devices [AMD] nee ATI RV350 AR [Radeon 9600] 01:00.1 Display controller: Advanced Micro Devices [AMD] nee ATI RV350 AR [Radeon 9600] (Secondary) I noticed i was using open source drivers and attempted to install official binaries using the methods in this thread. Output: liam@liam-desktop:~$ sudo apt-get install fglrx fglrx-amdcccle Reading package lists... Done Building dependency tree Reading state information... Done The following packages will be upgraded: fglrx fglrx-amdcccle 2 upgraded, 0 newly installed, 0 to remove and 12 not upgraded. Need to get 45.1 MB of archives. After this operation, 739 kB of additional disk space will be used. Get:1 http://gb.archive.ubuntu.com/ubuntu/ precise/restricted fglrx i386 2:8.960-0ubuntu1 [39.2 MB] Get:2 http://gb.archive.ubuntu.com/ubuntu/ precise/restricted fglrx-amdcccle i386 2:8.960-0ubuntu1 [5,883 kB] Fetched 45.1 MB in 1min 33s (484 kB/s) (Reading database ... 328081 files and directories currently installed.) Preparing to replace fglrx 2:8.951-0ubuntu1 (using .../fglrx_2%3a8.960-0ubuntu1_i386.deb) ... Removing all DKMS Modules Error! There are no instances of module: fglrx 8.951 located in the DKMS tree. Done. Unpacking replacement fglrx ... Preparing to replace fglrx-amdcccle 2:8.951-0ubuntu1 (using .../fglrx-amdcccle_2%3a8.960-0ubuntu1_i386.deb) ... Unpacking replacement fglrx-amdcccle ... Processing triggers for ureadahead ... ureadahead will be reprofiled on next reboot Setting up fglrx (2:8.960-0ubuntu1) ... update-alternatives: warning: forcing reinstallation of alternative /usr/lib/fglrx/ld.so.conf because link group i386-linux-gnu_gl_conf is broken. update-alternatives: warning: skip creation of /etc/OpenCL/vendors/amdocl64.icd because associated file /usr/lib/fglrx/etc/OpenCL/vendors/amdocl64.icd (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalcl.so because associated file /usr/lib32/fglrx/libaticalcl.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalrt.so because associated file /usr/lib32/fglrx/libaticalrt.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: forcing reinstallation of alternative /usr/lib/fglrx/ld.so.conf because link group i386-linux-gnu_gl_conf is broken. update-alternatives: warning: skip creation of /etc/OpenCL/vendors/amdocl64.icd because associated file /usr/lib/fglrx/etc/OpenCL/vendors/amdocl64.icd (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalcl.so because associated file /usr/lib32/fglrx/libaticalcl.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-alternatives: warning: skip creation of /usr/lib32/libaticalrt.so because associated file /usr/lib32/fglrx/libaticalrt.so (of link group i386-linux-gnu_gl_conf) doesn't exist. update-initramfs: deferring update (trigger activated) update-initramfs: Generating /boot/initrd.img-3.2.0-25-generic-pae Loading new fglrx-8.960 DKMS files... Building only for 3.2.0-25-generic-pae Building for architecture i686 Building initial module for 3.2.0-25-generic-pae Done. fglrx: Running module version sanity check. - Original module - No original module exists within this kernel - Installation - Installing to /lib/modules/3.2.0-25-generic-pae/updates/dkms/ depmod....... DKMS: install completed. update-initramfs: deferring update (trigger activated) Processing triggers for bamfdaemon ... Rebuilding /usr/share/applications/bamf.index... Setting up fglrx-amdcccle (2:8.960-0ubuntu1) ... Processing triggers for initramfs-tools ... update-initramfs: Generating /boot/initrd.img-3.2.0-25-generic-pae Processing triggers for libc-bin ... ldconfig deferred processing now taking place liam@liam-desktop:~$ sudo aticonfig --initial -f aticonfig: No supported adapters detected When i attempt to get my settings back to what they were before upgrading i get this message requested position/size for CRTC 81 is outside the allowed limit: position=(1440, 0), size=(1440, 900), maximum=(1680, 1680) and GDBus.Error:org.gtk.GDBus.UnmappedGError.Quark._gnome_2drr_2derror_2dquark.Code3: requested position/size for CRTC 81 is outside the allowed limit: position=(1440, 0), size=(1440, 900), maximum=(1680, 1680) Any idea's on what i need to do to fix this issue?

    Read the article

  • Partner Webcast: Innovation in Products - October 1st, 2012 at 04:00 PM CET (03:00 PM GMT) Program

    - by Richard Lefebvre
    I am pleased to invite you to join the Innovations in Products – webcast. Innovations in Products will present Oracle Product's new functions and features including sales positioning. The key objectives of these webcasts are to inspire System Integrator's implementation personnel to conduct successful after sales in their Customer projects. Innovations in Products will be presented on the 1st Monday of each quarter after the billable day (4:00 to 5:00 PM CET). The webcast is intended for System Integrator's Implementation Certified Specialists but Innovations in Products is open for other system Integrator's personnel as well. At first, two Oracle representatives will discuss Oracle's contribution to partners. Then you will see product breakout session followed by Q&A with Oracle Experts. Each session will last for maximum 1 hour. A Q&A document covering all questions and answers will be made available after the webcast. What are the Benefits for partners? Find out how Innovations in Products helps you to improve your after sales Discover new functions and features so you can enrich your Customers's solution Learn more about Oracle products, especially sales positioning Hear crucial questions raised by colleague alike, learn from their interest Engage and present your questions to subject experts Be inspired of the richness of Oracle's product portfolio – for your and your customer's benefit. Note: Should you already be familiar with a specific Product, then choose another one. Doing so you would expand your knowledge of the overall product portfolio. Some presentations contain product demonstration, although these presentations are not intended to be extremely detailed technical presentations. Product breakout sessions available on October 1st:   Topics Speaker To Register Fusion HCM Social Capabilities, Enterprise social capabilities embedded in how you run your business Anca Dumitru, HCM Presales Consultant, EMEA Presales Center CLICK HERE Oracle Fusion Applications Security Concepts, Overview Alexandra Dan, Applications Technology Presales Consultant, EMEA Presales Centre CLICK HERE Fusion Financials Overview - Focus on Fusion Payables, Meeting the Payables' Challenges Elena Nita, Senior ERP Sales Consultant, EMEA Presales Center CLICK HERE Introduction to Oracle RightNow CX, Empowering companies to engage directly with their customers through great Social, Web, Chat and Contact Center experiences. Cais Champsi, Presales Consultant, EMEA Presales Centre CLICK HERE Oracle Endeca Information Discovery, Product Overview Emma Palii, BI Sales Consultant, EMEA Presales Center CLICK HERE To access previously presented 23 Applications Products presentations and 6 Public Sector Value Proposition presentations, please click here. You might want to bookmark the overall registration page Innovations in Products October 1st and the global event calendar page events.oracle.com. Delivery Format Innovations in Products – program is a series of FREE prerecorded Oracle product presentations followed by Q&A. It will be delivered over the Web. Participants have the opportunity to submit questions during the web cast via chat and subject matter experts will provide verbal answers live. Innovations in Products consists of several parallel prerecorded product breakout sessions, each lasting for max. 1 hour. At first, two Oracle representatives will discuss Oracle's contribution to Partners. Then you'll see the product breakout sessions followed by Q&A with Oracle Experts. A Q&A document covering all questions and answers will be made available after the webcast. You can also see Innovations in Products afterwards as its content will be available online for the next 6-12 months. The next Innovations in Products web casts will be presented as follows: October 1st 2012 January 14th 2013 April 8th 2013. Note: Depending on local network bandwidth please allow some seconds time the presentations to download. You might want to refresh your screen by pressing F5. Duration: Maximum 1 hour For further information please contact me Markku Rouhiainen. Best regards Markku Rouhiainen Director, Applications Partner Enablement EMEA

    Read the article

  • Where is the value of OEA

    - by [email protected]
    In a room full of architects, if you were to ask for the definition of enterprise architecture, or the importance thereof,  you are likely to get a number of varying view points ranging from,  a complete analysis of the digital assets of an organization,  to, a strategic alignment of business goals/objectives to IT initiatives.  Similiarily in a room full of senior business executives,  if you asked them how they see their IT groups and their effectiveness to align to business strategy,  you would get a myriad of responses,  ranging from, “a huge drain on our bottom line”, “always more expensive than budgeted”, “lack of agility,  by the time IT is ready,  my business strategy has changed”, and on the rare occurrence, “ a leader of innovation,  that is lock step with my business strategy”. However does this necessarily demonstrate the overall value of enterprise architecture.  Having a framework, and process is of critical importance to help produce a number of the artefacts that ultimately align technology goals and initiatives to business strategy,  however,  is that really where the value is?  I believe that first we need to understand the concept of value.  Value typically is a measure of sorts,  when we purchase a product it’s value is equivalent to the maximum amount that someone is willing to pay for the product,  however,  is the same equation valid in terms of the business value of enterprise architecture? Is the library of artefacts generated through a process/framework, inclusive of a strategic roadmap to realize the enterprise architecture where the value is? If we agree that enterprise architecture is the alignment of IT and IT assets to support business strategy, and by achieving our business strategy, we have we have increased the business value of the enterprise then;  it seems that, in order to really identify the true value of an enterprise architecture,  we need to understand how we measure business value .  A number of formal measurement methodologies exist for this purpose, business models, balanced scorecards, etc   After we have an understanding on how to measure the business value of each of the organizational units within an enterprise, then we understand how the enterprise architecture contributes to the success of business strategy,  and EXECUTE on the roadmap to implement, and deliver the IT initiatives that provide MEASUREABLE returns, As we analyse the value chain of each of the individual organizational units within the enterprise we may identify how that unit has performed by quantitatively measuring it proximity to achieving the goals defined by the business for each unit. However, It would appear that true business value (the aggregate of all of the business units in the value chain), is to some degree subjectively measured  as for public companies this lies in shareholder value,  as the true value, or be it, the maximum amount that someone would pay for shares of an organization.

    Read the article

  • Is this simple XOR encrypted communication absolutely secure?

    - by user3123061
    Say Alice have 4GB USB flash memory and Peter also have 4GB USB flash memory. They once meet and save on both of memories two files named alice_to_peter.key (2GB) and peter_to_alice.key (2GB) which is randomly generated bits. Then they never meet again and communicate electronicaly. Alice also maintains variable called alice_pointer and Peter maintains variable called peter_pointer which is both initially set to zero. Then when Alice needs to send message to Peter they do: encrypted_message_to_peter[n] = message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] Where n i n-th byte of message. Then alice_pointer is attached at begining of the encrypted message and (alice_pointer + encrypted message) is sent to Peter and then alice_pointer is incremented by length of message (and for maximum security can be used part of key erased) Peter receives encrypted_message, reads alice_pointer stored at beginning of message and do this: message_to_peter[n] = encrypted_message_to_peter[n] XOR alice_to_peter.key[alice_pointer + n] And for maximum security after reading of message also erases used part of key. - EDIT: In fact this step with this simple algorithm (without integrity check and authentication) decreases security, see Paulo Ebermann post below. When Peter needs to send message to Alice they do analogical steps with peter_to_alice.key and with peter_pointer. With this trivial schema they can send for next 50 years each day 2GB / (50 * 365) = cca 115kB of encrypted data in both directions. If they need more data to send, they simple use larger memory for keys for example with today 2TB harddiscs (1TB keys) is possible to exchange next 50years 60MB/day ! (thats practicaly lots of data for example with using compression its more than hour of high quality voice communication) It Seems to me there is no way for attacker to read encrypted message without keys even if they have infinitely fast computer. because even with infinitely fast computer with brute force they get ever possible message that can fit to length of message, but this is astronomical amount of messages and attacker dont know which of them is actual message. I am right? Is this communication schema really absolutely secure? And if its secure, has this communication method its own name? (I mean XOR encryption is well-known, but whats name of this concrete practical application with use large memories at both communication sides for keys? I am humbly expecting that this application has been invented someone before me :-) ) Note: If its absolutely secure then its amazing because with today low cost large memories it is practicaly much cheeper way of secure communication than expensive quantum cryptography and with equivalent security! EDIT: I think it will be more and more practical in future with lower a lower cost of memories. It can solve secure communication forever. Today you have no certainty if someone succesfuly atack to existing ciphers one year later and make its often expensive implementations unsecure. In many cases before comunication exist step where communicating sides meets personaly, thats time to generate large keys. I think its perfect for military communication for example for communication with submarines which can have installed harddrive with large keys and military central can have harddrive for each submarine they have. It can be also practical in everyday life for example for control your bank account because when you create your account you meet with bank etc.

    Read the article

  • Laptop screen blank after login when external monitor is not connected

    - by Ramon Suarez
    Ubuntu does not switch back automatically to only monitor present when booting after disconnecting external monitor. Here's a video showing what happens. I get to the login window and everything looks ok, then I type my password, the desktop image shows up and... everything goes blank. It does not happen when I just login as a guest. When possible I work with my laptop connected to an external screen via the VGA port. The problem comes when I boot the computer without that secondary screen connected: The login screen comes out ok. After login the screen goes black, but I can hear the login sound. If I hit ctr + alt + backwards-delete and login again sometimes it is fixed, but not all. If I log in as a different user everything is OK. Then I log in as my user and sometimes it works. To have a screen I have to plug a monitor. Although I have turned on the laptop display with that monitor on, if I reboot it goes blank again after login, even if I turn off the external monitor before turning off the computer. I've managed to get my screen back with my username after going into recovery mode, but only sometimes. Failsafe would not load after second screen asking me what I wanted to do (no mouse to click nor keyboard working). My computer is a LDLC Aurore BB1-i5 -8 -S1. Which is the configuration file that keeps the information about the monitors using Displays under lightgdm and where is it? I guess if I could edit it I may have a chance :) One of the things I tried following a solution in another post was removing my monitors.xml file, but it does not work and I don't know how to create a good one that I could use now. When doing DISPLAY=:0 xrandrI get: Screen 0: minimum 320 x 200, current 320 x 200, maximum 8192 x 8192 LVDS1 connected (normal left inverted right x axis y axis) 1366x768 60.0 + 1360x768 59.8 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 disconnected (normal left inverted right x axis y axis) DP1 disconnected (normal left inverted right x axis y axis) This is the full dmesg after activating sudo xdiagnoseas Bryce sugested. (If you tell me the relevant parts I will paste them here) When conecting the external monitor, only the external will work, although I can see using Displays that the computer thinks that both are working. I've asked the question in Launchpad but have it keeps on expiring without any feedback. In my opinion Ubuntu should be able to detect automatically that there is no external monitor present and switch to the laptop monitor. There's a similar question here, but it does not apply to my case External monitor set as primary even when disconnected from laptop Update: For clarification, the problem happens only with my user and once I log in. I even get to see the screensaver for about a second, and then it goes blank. Tried Bryce's example (see his answer below), but it did not work. This is the info I get from tty1 with Display=:0 xrandr: – Ramon Suarez Jul 9 at 16:36 Screen 0: minimum 320 x 200, current 320 x 200, maximum 8192 x 8192 LVDS1 connected (normal left inverted right x axis y axis) 1366x768 60.0 + 1360x768 59.8 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 disconnected (normal left inverted right x axis y axis) DP1 disconnected (normal left inverted right x axis y axis)

    Read the article

  • Laptop monitor stopped working and can't be re-enabled on a Dell Latitude E6410

    - by xektrum
    I'm using Ubuntu 12.04 (upgraded from 11.10), everything seemed to work fine until today when my laptop monitor suddenly stopped working. Here are the facts: My laptop is a Dell Latitude E6410, Intel graphics. External Monitor is attached through a docking station. Everything worked fine for about 6-7 month, then upgraded to 12.04 Issue started today after a week of upgrade. I think the issue started after I ran CounterStrike 1.6, both monitors blinked and then only the attached monitor which is connected to a docking station continued to work I thought at first that was a transient issue but then I've rebooted, removed the battery but the same happens. Laptop Monitor and external monitor work fine up to login screen, but after I login it goes black Whenever I try to re-enable laptop monitor from Display Manager I get errors: The selected configuration for displays could not be applied could not set the configuration for CRTC 63 Not sure what technical details are required but here are some: $ xrandr Screen 0: minimum 320 x 200, current 3120 x 1050, maximum 8192 x 8192 eDP1 connected (normal left inverted right x axis y axis) 1440x900 60.0 + 40.0 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 connected 1680x1050+0+0 (normal left inverted right x axis y axis) 474mm x 296mm 1680x1050 60.0*+ 1280x1024 75.0 60.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 DP1 disconnected (normal left inverted right x axis y axis) HDMI2 disconnected (normal left inverted right x axis y axis) DP2 disconnected (normal left inverted right x axis y axis) $ tail /var/log/Xorg.0.log [ 8367.132] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.132] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.174] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.174] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.174] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.174] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.265] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.265] (WW) intel(0): Page flip failed: Device or resource busy [ 8367.265] (WW) intel(0): flip queue failed: Device or resource busy [ 8367.265] (WW) intel(0): Page flip failed: Device or resource busy I'm using gnome-shell, and the only ways I've been able to get both display working have been: 1) Booting with laptop disconnected from docking and then re attach external with VGA instead of DVI, but only worked for a session. 2) Removing xserver-xorg-video-intel, but then I gnome-shell is gone as well as dri I would appreciate any suggestions. Regards, ============================= WORKAROUND FOUND ============================= So I have tried few things and here is what worked: I've installed a newer version of xserver-xorg-video-intel (2.19 vs 2.17) from ppa:xorg-edgers/ppa, it didn't work at first, it was only showing low graphics mode, so I tried with a different linux-image 3.0.0-19-generic-pae instead of 3.2.0-24-generic-pae, which I believe is 12.04 precise default, then everything started to work again, Now I've installed 3.4.0-1-generic-pae from same ppa and everything goes flawless so I believe the issue is either with linux-image 3.0.0-19-generic-pae or xserver-xorg-video-intel 2.17. Hope this helps someone in the future. PS: Now xrandr shows multiple modes for my laptop monitor $ xrandr Screen 0: minimum 320 x 200, current 3120 x 1050, maximum 8192 x 8192 eDP1 connected 1440x900+1680+0 (normal left inverted right x axis y axis) 303mm x 189mm 1440x900 60.0*+ 59.9 40.0 1360x768 59.8 60.0 1152x864 60.0 1024x768 60.0 800x600 60.3 56.2 640x480 59.9 VGA1 disconnected (normal left inverted right x axis y axis) HDMI1 connected 1680x1050+0+0 (normal left inverted right x axis y axis) 474mm x 296mm 1680x1050 60.0*+ 1280x1024 75.0 60.0 1152x864 75.0 1024x768 75.1 60.0 800x600 75.0 60.3 640x480 75.0 60.0 720x400 70.1 DP1 disconnected (normal left inverted right x axis y axis) HDMI2 disconnected (normal left inverted right x axis y axis) DP2 disconnected (normal left inverted right x axis y axis)

    Read the article

  • Switching my collision detection to array lists caused it to stop working

    - by Charlton Santana
    I have made a collision detection system which worked when I did not use array list and block generation. It is weird why it's not working but here's the code, and if anyone could help I would be very grateful :) The first code if the block generation. private static final List<Block> BLOCKS = new ArrayList<Block>(); Random rnd = new Random(System.currentTimeMillis()); int randomx = 400; int randomy = 400; int blocknum = 100; String Title = "blocktitle" + blocknum; private Block block; public void generateBlocks(){ if(blocknum > 0){ int offset = rnd.nextInt(250) + 100; //500 is the maximum offset, this is a constant randomx += offset;//ofset will be between 100 and 400 int randomyoff = rnd.nextInt(80); //500 is the maximum offset, this is a constant randomy = platformheighttwo - 6 - randomyoff;//ofset will be between 100 and 400 block = new Block(BitmapFactory.decodeResource(getResources(), R.drawable.block2), randomx, randomy); BLOCKS.add(block); blocknum -= 1; } The second is where the collision detection takes place note: the block.draw(canvas); works perfectly. It's the blocks that don't work. for(Block block : BLOCKS) { block.draw(canvas); if (sprite.bottomrx < block.bottomrx && sprite.bottomrx > block.bottomlx && sprite.bottomry < block.bottommy && sprite.bottomry > block.topry ){ Log.d(TAG, "Collided!!!!!!!!!!!!1"); } // bottom left touching block? if (sprite.bottomlx < block.bottomrx && sprite.bottomlx > block.bottomlx && sprite.bottomly < block.bottommy && sprite.bottomly > block.topry ){ Log.d(TAG, "Collided!!!!!!!!!!!!1"); } // top right touching block? if (sprite.toprx < block.bottomrx && sprite.toprx > block.bottomlx && sprite.topry < block.bottommy && sprite.topry > block.topry ){ Log.d(TAG, "Collided!!!!!!!!!!!!1"); } //top left touching block? if (sprite.toprx < block.bottomrx && sprite.toprx > block.bottomlx && sprite.topry < block.bottommy && sprite.topry > block.topry ){ Log.d(TAG, "Collided!!!!!!!!!!!!1"); } } The values eg bottomrx are in the block.java file..

    Read the article

  • Representing Mauritius in the 2013 Bench Games

    Only by chance I came across an interesting option for professionals and enthusiasts in IT, and quite honestly I can't even remember where I caught attention of Brainbench and their 2013 Bench Games event. But having access to 600+ free exams in a friendly international intellectual competition doesn't happen to be available every day. So, it was actually a no-brainer to sign up and browse through the various categories. Most interestingly, Brainbench is not only IT-related. They offer a vast variety of fields in their Test Center, like Languages and Communication, Office Skills, Management, Aptitude, etc., and it can be a little bit messy about how things are organised. Anyway, while browsing through their test offers I added a couple of exams to 'My Plan' which I would give a shot afterwards. Self-assessments Actually, I took the tests based on two major aspects: 'Fun Factor' and 'How good would I be in general'... Usually, you have to pay for any kind of exams and given this unique chance by Brainbench to simply train this kind of tests was already worth the time. Frankly speaking, the tests are very close to the ones you would be asked to do at Prometric or Pearson Vue, ie. Microsoft exams, etc. Go through a set of multiple choice questions in a given time frame. Most of the tests I did during the Bench Games were based on 40 questions, each with a maximum of 3 minutes to answer. Ergo, one test in maximum 2 hours - that sounds feasible, doesn't it? The Measure of Achievement While the 2013 Bench Games are considered a worldwide friendly competition of knowledge I was really eager to get other Mauritians attracted. Using various social media networks and community activities it all looked quite well at the beginning. Mauritius was listed on rank #19 of Most Certified Citizens and rank #10 of Most Master Level Certified Nation - not bad, not bad... Until... the next update of the Bench Games Leaderboard. The downwards trend seemed to be unstoppable and I couldn't understand why my results didn't show up on the Individual Leader Board. First of all, I passed exams that were not even listed and second, I had better results on some exams listed. After some further information from the organiser it turned out that my test transcript wasn't available to the public. Only then results are considered and counted in the competition. During that time, I actually managed to hold 3 test results on the Individuals... Other participants were merciless, eh, more successful than me, produced better test results than I did. But still I managed to stay on the final score board: An 'exotic' combination of exam, test result, country and person itself Representing Mauritius and the Visual FoxPro community in that fun event. And although I mainly develop in Visual FoxPro 9.0 SP2 and C# using .NET Framework from 2.0 to 4.5 since a couple of years I still managed to pass on Master Level. Hm, actually my Microsoft Certified Programmer (MCP) exams are dated back in June 2004 - more than 9 years ago... Look who got lucky... As described above I did a couple of exams as time allowed and without any preparations, but still I received the following mail notification: "Thank you for recently participating in our Bench Games event.  We wanted to inform you that you obtained a top score on our test(s) during this event, and as a result, will receive a free annual Brainbench subscription.  Your annual subscription will give you access to all our tests just like Bench Games, but for an entire year plus additional benefits!" -- Leader Board Notification from Brainbench Even fun activities get rewarded sometimes. Thanks to @Brainbench_com for the free annual subscription based on my passed 2013 Bench Games Master Level exam. It would be interesting to know about the total figures, especially to see how many citizens of Mauritius took part in this year's Bench Games. Anyway, I'm looking forward to be able to participate in other challenges like this in the future.

    Read the article

  • View all ntext column text in SQL Server Management Studio for SQL CE database

    - by Dave
    I often want to do a "quick check" of the value of a large text column in SQL Server Management Studio (SSMS). The maximum number of characters that SSMS will let you view, in grid results mode, is 65535. (It is even less in text results mode.) Sometimes I need to see something beyond that range. Using SQL Server 2005 databases, I often used the trick of converting it to XML, because SSMS lets you view much larger amounts of text that way: SELECT CONVERT(xml, MyCol) FROM MyTable WHERE ... But now I am using SQL CE, and there is no Xml data type. There is still a "Maximum Characters Retreived XML" value under Options; I suppose this is useful when connecting to other data sources. I know I can just get the full value by running a little console app or something, but is there a way within SSMS to see the entire ntext column value? [Edit] OK, this didn't get much attention the first time around (18 views?!). It's not a huge concern, but maybe I'm just obsessed with it. There has to be some good way around this, doesn't there? So a modest bounty is active. What I am willing to accept as answers, in order from best-to-worst: A solution that works just as easy as the XML trick in SQL CE. That is, a single function (convert, cast, etc.) that does the job. A not-too-invasive way to hack SSMS to get it to display more text in the results. An equivalent SQL query (perhaps something that creatively uses SUBSTRING and generates multiple ad-hoc columns??) to see the results. The solution should work with nvarchar and ntext columns of any length in SQL CE from SSMS. Any ideas?

    Read the article

  • Stresstesting ASP.NET/IIS with WCAT

    - by MartinHN
    I'm trying to setup a stress/load test using the WCAT toolkit included in the IIS Resources. Using LogParser, I've processed a UBR file with configuration. It looks something like this: [Configuration] NumClientMachines: 1 # number of distinct client machines to use NumClientThreads: 100 # number of threads per machine AsynchronousWait: TRUE # asynchronous wait for think and delay Duration: 5m # length of experiment (m = minutes, s = seconds) MaxRecvBuffer: 8192K # suggested maximum received buffer ThinkTime: 0s # maximum think-time before next request WarmupTime: 5s # time to warm up before taking statistics CooldownTime: 6s # time to cool down at the end of the experiment [Performance] [Script] SET RequestHeader = "Accept: */*\r\n" APP RequestHeader = "Accept-Language: en-us\r\n" APP RequestHeader = "User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.2; .NET CLR 1.0.3705)\r\n" APP RequestHeader = "Host: %HOST%\r\n" NEW TRANSACTION classId = 1 NEW REQUEST HTTP ResponseStatusCode = 200 Weight = 45117 verb = "GET" URL = "http://Url1.com" NEW TRANSACTION classId = 3 NEW REQUEST HTTP ResponseStatusCode = 200 Weight = 13662 verb = "GET" URL = "http://Url1.com/test.aspx" Does it look OK? I execute the controller with this command: wcctl -z StressTest.ubr -a localhost The Client(s) is executed like this: wcclient localhost When the client is executed, I get this error: main client thread Connect Attempt 0 Failed. Error = 10061 Has anyone in this world ever used WCAT?

    Read the article

  • UIImageJPEGRepresentation - memory release issue

    - by FredM
    On a iPhone app, I need to send a jpg by mail with a maximum size of 300Ko (I don't no the maximum size mail.app can have, but it's another problem). To do that, I'm trying to decrease quality until obtain an image under 300Ko. In order to obtain the good value of the quality (compressionLevel) who give me a jpg under 300Ko, I have made the following loop. It's working, but each time time the loop is executed, the memory increase of the size of the original size of my jpg (700Ko) despite the "[tmpImage release];". float compressionLevel = 1.0f; int size = 300001; while (size 300000) { UIImage *tmpImage =[[UIImage alloc] initWithContentsOfFile:[self fullDocumentsPathForTheFile:@"countOpix_imageToAnalyse.jpg"]]; size = [UIImageJPEGRepresentation(tmpImage, compressionLevel) length]; [tmpImage release]; //In the following line, the 0.001f decrement is choose just in order test the increase of the memory //compressionLevel = compressionLevel - 0.001f; NSLog(@"Compression: %f",compressionLevel); } Any ideas about how can i get it off, or why it happens? thanks

    Read the article

  • Help improving a simple assembly function

    - by MPelletier
    I just handed in this function in an assignment. It is done (hence no homework tag). But I would like to see how this can be improved. Essentially, the function sums the squares of all the integers between 1 and the given number, using the following formula: n(n+1)(2n+1)/6 Where n is the maximum number. The function below is made to catch any overflow and return 0 should any occur. UInt32 sumSquares(const UInt32 number) { int result = 0; __asm { mov eax, number //move number in eax mov edx, 2 //move 2 in edx mul edx //multiply (2n) jo end //jump to end if overflow add eax, 1 //addition (2n+1) jo end //jump to end if overflow mov ecx, eax //move (2n+1) in ecx mov ebx, number //move number in ebx add ebx, 1 //addition (n+1) jo end //jump to end if overflow mov eax, number //move number in eax for multiplication mul ebx //multiply n(n+1) jo end //jump to end if overflow mul ecx //multiply n(n+1)(2n+1) jo end //jump to end if overflow mov ebx, 6 //move 6 in ebx div ebx //divide by 6, the result will be in eax mov result, eax //move eax in result end: } return result; } Basically, I want to know what I can improve in there. In terms of best-practices mostly. One thing sounds obvious: smarter overflow check (with a single check for whatever maximum input would cause an overflow).

    Read the article

  • Filemaker to SQL Server via SSIS

    - by TexasT
    I'm using SSIS and trying to import data from Filelmaker into SQL Server. In the Solution Explorer, I right click on "SSIS Packages" and select SQL Server Import and Export Wizard". During the process, I use my DSN as the source, SQL Server as the destination, use a valid query to pull data from Filemaker, and set the mappings. Each time I try to run the package, I receive the following message: The "output column "LastNameFirst" (12)" has a length that is not valide. The length must be between 0 and 4000. I do not understand this error exactly, but in the documentation for ODBC: http://www.filemaker.com/downloads/pdf/fm9%5Fodbc%5Fjdbc%5Fguide%5Fen.pdf (page 47) it states: "The maximum column length of text is 1 million characters, unless you specify a smaller Maximum number of characters for the text field in FileMaker. FileMaker returns empty strings as NULL." I'm thinking that the data type is too large when trying to convert it to varchar. But even after using a query of SUBSTR(LastNameFirst, 1, 2000), I get the same error. Any suggestions?

    Read the article

< Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >