Search Results

Search found 39440 results on 1578 pages for 'possible homework'.

Page 37/1578 | < Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >

  • Running a Java program with input from a file

    - by Katy
    I am writing a program that reads the input from a file and then prints it to the screen. When I run it without taking the input from the file, it works perfectly fine. However, every time I try to run it from the file it gives me an "Exception in thread "main" java.util.NoSuchElementException: No line found at" error that occurs every place the input is suppose to be read. I have no idea what is going on.

    Read the article

  • match strings in python

    - by mesun
    Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

    Read the article

  • urgent..haskell mini interpreter

    - by mohamed elshikh
    i'm asked to implement this project and i have problems in part b which is the eval function this is the full describtion of the project You are required to implement an interpreter for mini-Haskell language. An interpreter is dened in Wikipedia as a computer program that executes, i.e. performs, instructions written in a programming language. The interpreter should be able to evaluate functions written in a special notation, which you will dene. A function is dened by: Function name Input Parameters : dened as a list of variables. The body of the function. The body of the function can be any of the following statements: a) Variable: The function may return any of the input variables. b) Arithmetic Expressions: The arithmetic expressions include input variables and addition, sub- traction, multiplication, division and modulus operations on arithmetic expressions. c) Boolean Expressions: The Boolean expressions include the ordering of arithmetic expressions (applying the relationships: <, =<, , = or =) and the anding, oring and negation of Boolean expressions. d) If-then-else statements: where the if keyword is followed by a Boolean expression. The then and else parts may be followed by any of the statements described here. e) Guarded expressions: where each case consists of a boolean expression and any of the statements described here. The expression consists of any number of cases. The rst case whose condition is true, its body should be evaluated. The guarded expression has to terminate with an otherwise case. f) Function calls: the body of the function may have a call to another function. Note that all inputs passed to the function will be of type Int. The output of the function can be of type Int or Bool. To implement the interpreter, you are required to implement the following: a) Dene a datatype for the following expressions: Variables Arithmetic expressions Boolean expressions If-then-else statements Guarded expressions Functions b) Implement the function eval which evaluates a function. It takes 3 inputs: The name of a function to be evaluated represented as a string. A list of inputs to that function. The arguments will always be of datatype Int. A list of functions. Each function is represented as instance of the datatype that you have created for functions. c) Implement the function get_type that returns the type of the function (as a string). The input to this function is the same as in part b. here is what i've done data Variable = v(char) data Arth= va Variable | Add Arth Arth | Sub Arth Arth | Times Arth Arth | Divide Arth Arth data Bol= Great Arth Arth | Small Arth Arth | Geq Arth Arth | Seq Arth Arth | And Bol Bol | Or Bol Bol | Neg Bol data Cond = data Guard = data Fun =cons String [Variable] Body data Body= bodycons(String) |Bol |Cond |Guard |Arth

    Read the article

  • i see the file but when i open it nothing is in it in c++ i/o stream and dont know why

    - by user320950
    #include<iostream> #include<fstream> #include<cstdlib> #include<iomanip> using namespace std; int main() { ifstream in_stream; // reads ITEMSLIST.txt ofstream out_stream1; // writes in listWititems.txt ifstream in_stream2; // reads PRICELIST.txt ofstream out_stream3;// writes in listWitprices.txt ifstream in_stream4;// read display.txt ofstream out_stream5;// write showitems.txt double p1=0.0,p2=0.0; int wrong=0; int count =0; char next; in_stream.open("ITEMLIST.txt", ios::in); // list of avaliable items /*if( in_stream.fail() )// check to see if itemlist.txt is open { wrong++; // counts number of errors cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream1.open("listWititems.txt", ios::out); // list of avaliable items /* if( out_stream1.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream2.open("PRICELIST.txt", ios::in); /*if( in_stream2.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream3.open("listWitdollars.txt", ios::out); /*if( out_stream3.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream4.open("display.txt", ios::in); /*if( in_stream4.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream5.open("showitems.txt", ios::out); /*if( out_stream5.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; }*/ in_stream.setf(ios::fixed); while(!in_stream.eof()) // reads to end of file and gets p1 which is itemnum, clears and gets next character { in_stream >> p1; cin.clear(); cin >> next; } out_stream1.setf(ios::fixed); while (!out_stream1.eof()) { out_stream1 << p1; cin.clear(); cin >> next; } in_stream2.setf(ios::fixed); in_stream2.setf(ios::showpoint); in_stream2.precision(2); while(!in_stream2.eof()) // reads file to end of file { in_stream2 >> p1 >> p2 >> count; // gets p1,p2, and count which is current total in_stream2 >> p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } out_stream3.setf(ios::fixed); out_stream3.setf(ios::showpoint); out_stream3.precision(2); while(!out_stream3.eof()) // reads file to end of file { out_stream3 << p1 << p2 << count; out_stream3 << p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } in_stream4.setf(ios::fixed); in_stream4.setf(ios::showpoint); in_stream4.precision(2); while (!in_stream4.eof()) { in_stream4 >> p1 >> p2 >> count; cin.clear(); cin >> next; } out_stream5.setf(ios::fixed); out_stream5.setf(ios::showpoint); out_stream5.precision(2); out_stream5 <<setw(5)<< " itemnum " <<setw(5)<<" price "<<setw(5)<<" curr_total " <<endl; // sends items and prices to receipt.txt out_stream5 << setw(5) << p1 << setw(5) <<p2 << setw(5)<< count; // sends items and prices to receipt.txt out_stream5 << " You have a total of " << wrong++ << " errors " << endl; in_stream.close(); // closing files. out_stream1.close(); in_stream2.close(); out_stream3.close(); in_stream4.close(); out_stream5.close(); system("pause"); }

    Read the article

  • help in security assignment

    - by scatman
    i have to write a program that sniffs network packets (part1-the simple part). and i have to update the program (part2) so that it will be able to terminate connections. the specific requirements are: construct raw packets by specifying data link layer and network layer information including appropriate source and destination MAC and IP addresses. These packets are intended to terminate the connection. To do so, you should used SOCK_RAW as the socket type to be able to set the header information by yourself. can anybody give me some ideas on the second part? should i hijack the session,apply a dos attack on one of the users?? all i need is some tips of how to terminate the connection. i am using c programming language. and this is a course assignment for the security course.

    Read the article

  • from loop to Nested loops ?

    - by WM
    I have this program that returns a factorial of N. For example, when entering 4,,, it will give 1! , 2! , 3! How could I convert this to use nested loops? public class OneForLoop { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a number : "); int N = input.nextInt(); int factorial = 1; for(int i = 1; i < N; i++) { factorial *= i; System.out.println(i + "! = " + factorial); } } }

    Read the article

  • How to solve this problem with lists?

    - by osabri
    what i don't understand in my task here what kind of list i can use, and if it should have 2 attributes key and value ? or only value? with pointers to another node ofc the task: "design a function which create a list using input from the keyboard _ the prefered solution. Assume that some magic stops the input; so the length of a list is not known in advance.(alternative solution: a function which creates explicitly a fixed list. However, all other function can not assume any knowledge about the length of lists). Necessary utilities( additional functions to be created): a function which deallocates the memory used for lists and a function which prints the content of the list. let the element of lists contain a letter. Design a function which create a copy of such list. can't also understand the list line !!!!!???

    Read the article

  • How do I output the preorder traversal of a tree given the inorder and postorder tranversal?

    - by user342580
    Given the code for outputing the postorder traversal of a tree when I have the preorder and the inorder traversal in an interger array. How do I similarily get the preorder with the inorder and postorder array given? void postorder( int preorder[], int prestart, int inorder[], int inostart, int length) { if(length==0) return; //terminating condition int i; for(i=inostart; i<inostart+length; i++) if(preorder[prestart]==inorder[i])//break when found root in inorder array break; postorder(preorder, prestart+1, inorder, inostart, i-inostart); postorder(preorder, prestart+i-inostart+1, inorder, i+1, length-i+inostart-1); cout<<preorder[prestart]<<" "; } Here is the prototype for preorder() void preorder( int inorderorder[], int inostart, int postorder[], int poststart, int length)

    Read the article

  • C++ String manipulation isn't making sense to me...

    - by Andrew Bolster
    I am trying some of the Stanford SEE courses online to learn some new languages; this particular assignment has to do with removing substrings from strings. What I've got so far is below, but if text = "hello hello" and remove ="el", it gets stuck in a loop, but if i change text to text = "hello hllo", it works, making me think I'm doing something obviously stupid. There is a stipulation in the assignment not to modify the incoming strings, and instead to return a new string. string CensorString1(string text, string remove){ string returned; size_t found=0, lastfound=0; found = (text.substr(lastfound,text.size())).find(remove); while (string::npos != found ){ returned += text.substr(lastfound,found); lastfound = found + remove.size(); found = (text.substr(lastfound,text.size())).find(remove); } returned += text.substr(lastfound,found); return returned; } Guidance would be appreciated :-) Thanks

    Read the article

  • Simplest way of creating java next/previous buttons

    - by Holly
    I know that when creating buttons, like next and previous, that the code can be somewhat long to get those buttons to function. My professor gave us this example to create the next button: private void jbtnNext_Click() { JOptionPane.showMessageDialog(null, "Next" ,"Button Pressed", JOptionPane.INFORMATION_MESSAGE); try { if (rset.next()) { fillTextFields(false); }else{ //Display result in a dialog box JOptionPane.showMessageDialog(null, "Not found"); } } catch (SQLException ex) { ex.printStackTrace(); } } Though, I do not really understand how that short and simple if statement is what makes the next button function. I see that the fillTextFields(false) uses a boolean value and that you need to initialize that boolean value in the beginning of the code I believe. I had put private fillTextFields boolean = false; but this does not seem to be right... I'm just hoping someone could explain it better. Thanks :)

    Read the article

  • How do you search a document for a string in c++?

    - by Jeff
    Here's my code so far: #include<iostream> #include<string> #include<fstream> using namespace std; int main() { int count = 0; string fileName; string keyWord; string word; cout << "Please make sure the document is in the same file as the program, thank you!" << endl << "Please input document name: " ; getline(cin, fileName); cout << endl; cout << "Please input the word you'd like to search for: " << endl; cin >> keyWord; cout << endl; ifstream infile(fileName.c_str()); while(infile.is_open()) { getline(cin,word); if(word == keyWord) { cout << word << endl; count++; } if(infile.eof()) { infile.close(); } } cout << count; } I'm not sure how to go to the next word, currently this infinite loops...any recommendation? Also...how do I tell it to print out the line that that word was on? Thanks in advance!

    Read the article

  • Java - Removing duplicates in an ArrayList

    - by Will
    I'm working on a program that uses an ArrayList to store Strings. The program prompts the user with a menu and allows the user to choose an operation to perform. Such operations are adding Strings to the List, printing the entries etc. What I want to be able to do is create a method called removeDuplicates().This method will search the ArrayList and remove any duplicated values. I want to leave one instance of the duplicated value(s) within the list. I also want this method to return the total number of duplicates removed. I've been trying to use nested loops to accomplish this but I've been running into trouble because when entries get deleted, the indexing of the ArrayList gets altered and things don't work as they should. I know conceptually what I need to do but I'm having trouble implementing this idea in code. Here is some pseudo code: start with first entry; check each subsequent entry in the list and see if it matches the first entry; remove each subsequent entry in the list that matches the first entry; after all entries have been examined, move on to the second entry; check each entry in the list and see if it matches the second entry; remove each entry in the list that matches the second entry; repeat for entry in the list Here's the code I have so far: public int removeDuplicates() { int duplicates = 0; for ( int i = 0; i < strings.size(); i++ ) { for ( int j = 0; j < strings.size(); j++ ) { if ( i == j ) { // i & j refer to same entry so do nothing } else if ( strings.get( j ).equals( strings.get( i ) ) ) { strings.remove( j ); duplicates++; } } } return duplicates; }

    Read the article

  • C programming - How to print numbers with a decimal component using only loops?

    - by californiagrown
    I'm currently taking a basic intro to C programming class, and for our current assignment I am to write a program to convert the number of kilometers to miles using loops--no if-else, switch statements, or any other construct we haven't learned yet are allowed. So basically we can only use loops and some operators. The program will generate three identical tables (starting from 1 kilometer through the input value) for one number input using the while loop for the first set of calculations, the for loop for the second, and the do loop for the third. I've written the entire program, however I'm having a bit of a problem with getting it to recognize an input with a decimal component. Here is what I have for the while loop conversions: #include <stdio.h> #define KM_TO_MILE .62 main (void) { double km, mi, count; printf ("This program converts kilometers to miles.\n"); do { printf ("\nEnter a positive non-zero number"); printf (" of kilometers of the race: "); scanf ("%lf", &km); getchar(); }while (km <= 1); printf ("\n KILOMETERS MILES (while loop)\n"); printf (" ========== =====\n"); count = 1; while (count <= km) { mi = KM_TO_MILE * count; printf ("%8.3lf %14.3lf\n", count, mi); ++count; } getchar(); } The code reads in and converts integers fine, but because the increment only increases by 1 it won't print a number with a decimal component (e.g. 3.2, 22.6, etc.). Can someone point me in the right direction on this? I'd really appreciate any help! :)

    Read the article

  • Problem with python class

    - by Tasbeer
    Hi I am new to Python and as a part of my assignment I have written the following class import nltk.stem.api class BanglaStemmer(nltk.stem.api.StemmerI): suffixList = ['\xef\xbb\xbf\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x8b\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa7\x87\xe0\xa6\x9b\n', '\xe0\xa6\xa4\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9b\n', '\xe0\xa6\xa4\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\xa4\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xa4\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xac\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa7\x81\xe0\xa6\xa8\n', '\xe0\xa7\x81\xe0\xa6\x95\n', '\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\xac\xe0\xa7\x87\n', '\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\xac\xe0\xa6\xbf\n', '\xe0\xa6\xa4\xe0\xa6\xbf\n', '\xe0\xa6\xb2\n', '\xe0\xa6\xa4\n', '\xe0\xa7\x8b\n', '\xe0\xa6\xbf\n', '\xe0\xa7\x87\n', '\xe0\xa7\x8d\n', '\xe0\xa6\x87\n', '\xe0\xa6\xac\n', '\xe0\xa6\xb8\n', '\xe0\xa6\xa8\n', '\xe0\xa6\x95\n', '\xe0\xa6\x93\n', '\xe0\xa7\x9f\n'] def stem(self,token): for suffix in suffixList: if token.endswith(suffix): return token[:-len(suffix)] return token The problem is that when I try to compile run it by creating an instance and calling the stem() function with a parameter , it says that the suffixList is not defined. Couldn't figure out what's the problem. Is there a different way in which the class variables have to be declared ? please help

    Read the article

  • Adding the sum of numbers using a loop statement

    - by Deonna
    I need serious help dividing the positive numbers and the negative numbers. I am to accumulate the total of the negative values and separately accumulate the total of the positive values. After the loop, you are then to display the sum of the negative values and the sum of the positive values. The data is suppose to look like this: -2.3 -1.9 -1.5 -1.1 -0.7 -0.3 0.1 0.5 0.9 1.3 1.7 2.1 2.5 2.9 Sum of negative values: -7.8 Sum of positive values: 12 So far I have this: int main () { int num, num2, num3, num4, num5, sum, count, sum1; int tempVariable = 0; int numCount = 100; int newlineCount = 0, newlineCount1 = 0; float numCount1 = -2.3; while (numCount <= 150) { cout << numCount << " "; numCount += 2; newlineCount ++; if(newlineCount == 6) { cout<< " " << endl; newlineCount = 0; } } **cout << "" << endl; while (numCount1 <=2.9 ) { cout << numCount1 << " "; numCount1 += 0.4; newlineCount1 ++; } while ( newlineCount1 <= 0 && newlineCount >= -2.3 ); cout << "The sum is " << newlineCount1 << endl;** return 0; }

    Read the article

  • How do you determine using stat() whether a file is a symbolic link?

    - by hora
    I basically have to write a clone of the UNIX ls command for a class, and I've got almost everything working. One thing I can't seem to figure out how to do is check whether a file is a symbolic link or not. From the man page for stat(), I see that there is a mode_t value defined, S_IFLNK. This is how I'm trying to check whether a file is a sym-link, with no luck (note, stbuf is the buffer that stat() returned the inode data into): switch(stbuf.st_mode & S_IFMT){ case S_IFLNK: printf("this is a link\n"); break; case S_IFREG: printf("this is not a link\n"); break; } My code ALWAYS prints this is not a link even if it is, and I know for a fact that the said file is a symbolic link since the actual ls command says so, plus I created the sym-link... Can anyone spot what I may be doing wrong? Thanks for the help!

    Read the article

  • JRadio Menu buttons - JAVA

    - by user337465
    I have a relatively easy question. I have to create a java GUI to do math based calculations. I have to have a menu item that will double the variable that I am doing calculations with. For example variable = 1 if radio button = selected{ variable = variable * 2 } So, how would I achieve the if statement there? thankyou

    Read the article

  • Returning multiple aggregate functions as rows

    - by SDLFunTimes
    I need some help formulating a select statement. I need to select the total quantity shipped for each part with a distinct color. So the result should be a row with the color name and the total. Here's my schema: create table s ( sno char(5) not null, sname char(20) not null, status smallint, city char(15), primary key (sno) ); create table p ( pno char(6) not null, pname char(20) not null, color char(6), weight smallint, city char(15), primary key (pno) ); create table sp ( sno char(5) not null, pno char(6) not null, qty integer not null, primary key (sno, pno) );

    Read the article

  • How to store multiple variables from a File Input of unknown size in Java?

    - by AlphaOmegaStrife
    I'm a total beginner with my first programming assignment in Java. For our programming assignment, we will be given a .txt file of students like so: 3 345 Lisa Miller 890238 Y 2 <-(Number of classes) Mathematics MTH345 4 A Physics PHY357 3 B Bill Wilton 798324 N 2 English ENG378 3 B Philosophy PHL534 3 A Dandy Goat 746333 Y 1 History HIS101 3 A" The teacher will give us a .txt file on the day of turning it in with a list of unknown students. My problem is: I have a specific class for turning the data from the file into variables to be used for a different class in printing it to the screen. However, I do not know of a good way to get the variables from the input file for the course numbers, since that number is not predetermined. The only way I can think of to iterate over that unknown amount is using a loop, but that would just overwrite my variables every time. Also, the teacher has requested that we not use any JCL classes (I don't really know what this means.) Sorry if I have done a poor job of explaining this, but I can't think of a better way to conceptualize it. Let me know if I can clarify. Edit: public static void analyzeData() { Scanner inputStream = null; try { inputStream = new Scanner(new FileInputStream("Programming Assignment 1 Data.txt")); } catch (FileNotFoundException e) { System.out.println("File Programming Assignment 1 Data.txt could not be found or opened."); System.exit(0); } int numberOfStudents = inputStream.nextInt(); int tuitionPerHour = inputStream.nextInt(); String firstName = inputStream.next(); String lastname = inputStream.next(); String isTuitionPaid = inputStream.next(); int numberOfCourses = inputStream.nextInt(); String courseName = inputStream.next(); String courseNumber = inputStream.next(); int creditHours = inputStream.nextInt(); String grade = inputStream.next(); To show the methods I am using now, I am just using a Scanner to read from the file and for Scanner inputStream, I am using nextInt() or next() to get variables from the file. Obviously this will not work when I do not know exactly how many classes each student will have.

    Read the article

< Previous Page | 33 34 35 36 37 38 39 40 41 42 43 44  | Next Page >