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• Understanding The Convolution Matrix

  - by Ryan Naddy

  I am learning about the Convolution Matrix, and I understand how they work, but I don't understand how to know before hand what the output of a Matrix will look like. For example lets say I want to add a blur to an image, I could guess 10,000+ different combinations of numbers before I get the correct one. I do know though that this formula will give me a blur effect, but I have no idea why. float[] sharpen = new float[] { 1/9f, 1/9f, 1/9f, 1/9f, 1/9f, 1/9f, 1/9f, 1/9f, 1/9f }; Can anyone either explain to me how this works or point me to some article, that explains this? I would like to know before hand what a possible output of the matrix will be without guessing. Basically I would like to know why do we put that number in the filed, and why not some other number?

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• Checkbox in a Crystal Report

  - by JosephStyons

  What is the best way to display a checkbox in a Crystal Report? Example: My report has a box for "Male" and "Female", and one should be checked. My current workaround is to draw a small graphical square, and line it up with a formula which goes like this: if {table.gender} = "M" then "X" else " " This is a poor solution, because changing the font misaligns my "X" and the box around it, and it is absurdly tedious to squint at the screen and get a pixel-perfect alignment for every box (there are dozens). Does anyone have a better solution? I've thought about using the old-style terminal characters, but I'm not sure if they display properly in Crystal. Edit: I'm using Crystal XI.

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• PHP given a series of arbitrary numbers, how can I choose a logical max value on a line graph?

  - by stormist

  I am constructing a line graph in PHP. I was setting the max value of the line graph to the max value of my collection of items, but this ended up making the graph less readable you are unable to view the highest line on the graph as it intersects with the top of it. So what I need is basically a formula to take a set of numbers and calculate what the logical max value of on the line graph should be.. so some examples 3500 250 10049 45394 434 312 Max value on line graph should probably be 50000 493 412 194 783 457 344 max value on line graph would ideally be 1000 545 649 6854 5485 11545 In this case, 12000 makes sense as max value So something as simple as rounding upward to the nearest thousandth might work but I'd need it to progressively increase as the numbers got bigger. (50000 instead of 46,000 in first example) The maximum these numbers will ever be is about a million. Any recommendations would be greatly appreciated, thank you.

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• choose the best class if 2 class have same P (c|d), naive bayes

  - by ryandi

  Hello I have some question about naive bayes classifier . In my project I have to classify a text into a class from 4 available class. In naive bayes we have formula like cmap=argmax.P(d|c).P(c) I have standarize the amount of training document of each class, so I got a same P(c) value for each class (0.25). Here's my question: What if a testing document token doesn't have any token which belong to any of those 4 class(in document training)? Resulted to all of the class have same value of P(d|c).P(c). Which class should i pick? What if the token exist, and 2 class or more have same value of P(d|c).P(c) what should I do? Thank you..

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• What does the following FORTRAN code do?

  - by Jon Skeet

  C AREA OF A TRIANGLE WITH A STANDARD SQUARE ROOT FUNCTION C INPUT - CARD READER UNIT 5, INTEGER INPUT C OUTPUT - LINE PRINTER UNIT 6, REAL OUTPUT C INPUT ERROR DISPLAY ERROR OUTPUT CODE 1 IN JOB CONTROL LISTING READ (5, 501) IA, IB, IC 501 FORMAT (3I5) C IA, IB, AND IC MAY NOT BE NEGATIVE C FURTHERMORE, THE SUM OF TWO SIDES OF A TRIANGLE C IS GREATER THAN THE THIRD SIDE, SO WE CHECK FOR THAT, TOO IF (IA) 777, 777, 701 701 IF (IB) 777, 777, 702 702 IF (IC) 777, 777, 703 703 IF (IA+IB-IC) 777,777,704 704 IF (IA+IC-IB) 777,777,705 705 IF (IB+IC-IA) 777,777,799 777 STOP 1 C USING HERON'S FORMULA WE CALCULATE THE C AREA OF THE TRIANGLE 799 S = FLOATF (IA + IB + IC) / 2.0 AREA = SQRT( S * (S - FLOATF(IA)) * (S - FLOATF(IB)) * + (S - FLOATF(IC))) WRITE (6, 601) IA, IB, IC, AREA 601 FORMAT (4H A= ,I5,5H B= ,I5,5H C= ,I5,8H AREA= ,F10.2, + 13H SQUARE UNITS) STOP END plz i need to know soon!!!!!

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• How do I introduce row names to a function in R

  - by Tahnoon Pasha

  Hi I have a utility function I've put together to insert rows into a dataframe below. If I was writing out the formula by hand I would put something like newframe=rbind(oldframe[1:rownum,],row_to_insert=row_to_insert,oldframe[(rownum+1:nrow(oldframe),] to name row_to_insert. Could someone tell me how to do this in a function? Thanks insertrows=function (x, y, rownum) { newframe = rbind(y[1:rownum, ], x, y[(rownum + 1):nrow(y), ]) return(data.frame(newframe)) } MWE of some underlying data added below financials=data.frame(sales=c(100,150,200,250),some.direct.costs=c(25,30,35,40),other.direct.costs=c(15,25,25,35),indirect.costs=c(40,45,45,50)) oldframe=t(financials) colnames(oldframe)=make.names(seq(2000,2003,1)) total.direct.costs=oldframe['some.direct.costs',]+oldframe['other.direct.costs',] newframe=total.direct.costs n=rownum=3 oldframe=insertrows(total.direct.costs=newframe,oldframe,n)

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• calculate next line numbers

  - by osomanden

  Weird question I guess.. But I am not very math wiz - soo here goes.. I am trying to create a patterne (or variable patterns based on selection) based on x and y numbers (2 rows and 4 columns) and the direction of the counting of x numbers like: 1-2-3-4 5-6-7-8 That one is easy, when number of x-columns is reached, next line and continue x count. But with eg. this one (still 2 rows and 4 columns): 1-2-3-4 8-7-6-5 upsie.. what if it is eg. 3++ rows and still 4 columns? 1-2-3-4 8-7-6-5 9-10-11-12 what would be the formula for this - or other possible variations (teaser for variations): 9-10-11-12 8-7-6-5 1-2-3-4 or reversed

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• Built in raytracing?

  - by acidzombie24

  Relating to this question i was wondering if .NET has any libs (or a function) i can use to detect if one point collides with another. I am not sure what angles i should use but is there some function like this func(point src, rect target, angle, distanceOfVision, listPointOrRectOfWalls) Pretty unlikely but i dont know a formula or how to start. Its a quick and dirty prototype. I am thinking of writing the func about but dropping angle and just make line of sight a rectangle and check if any points is between src and target.

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• newline character on text area

  - by Prady

  I have a custom field called Current_Address__c which is of datatype textarea. I need to populate this field in the format below. ie a newline char after street and another newline after zip. street City state Zip Country The values of city state zip country etc are been taken from contact object. I dont want to use this as a formula field. So i need to populate it in my controller and display it on my VF page. I am trying to add a newline char by using the code below this.customobj.Current_Address__c = currentStreet + '\\n ' + currentCity + ' ' + currentState + ' ' + currentZIP + '\\n ' + currentCountry ; i had also used \n instead of \n. It still show the field in one line instead of 3 lines

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• What RegEx should I use to return parameter names wrapped within brackets in an expression?

  - by burak ozdogan

  Hi, I have a set of expressions representing some formula with some parameters inside. Like: "[parameter1] * [parameter2] * [multiplier]" and many others like this. I want to use a regEx so that I can get a list of strings (List<string> ) which will have [paramter1] [paramter2] [multiplier] inside. I am not using regular expressions so often; if you have already used something like this I would appreciate if you can share. Thanks!

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• How to make this C++ code more DRY?

  - by Macha

  I have these two methods on a class that differ only in one method call. Obviously, this is very un-DRY, especially as both use the same formula. int PlayerCharacter::getAttack() { attack = 1 + this.level; for(int i = 0; i <= current_equipment; i++) { attack += this.equipment[i].getAttack(); } attack *= sqrt(this.level); return attack; } int PlayerCharacter::getDefense() { defense = 1 + this.level; for(int i = 0; i <= current_equipment; i++) { defense += this.equipment[i].getDefense(); } defense *= sqrt(this.level); return defense; } How can I tidy this up in C++?

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• Stuck with the math in a Flash project, would parsing engine help?

  - by VideoDnd

  I've been stuck with the math in a Flash project? It's a loose design pattern my director formulated. My goal is to keep the project object oriented, and get 'non Flash obstacles' off my plate. Do you recommend using parsing engines for processing math? XML values going to AS3, updating a changing acceleration formula. I don't hate math, but it just doesn't seem OOP or good project planning to have the math stuck in Flash. Your comments are welcome.

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• Generate (in R) a matrix of all possible outcomes for throwing n dice (ignoring order)

  - by Brani

  In cases where order does matter, it's rather easy to generate the matrix of all possible outcomes. One way for doing this is using expand.grid as shown here. What if it doesn't? If I'm right, the number of possible combinations is (S+N-1)!/S!(N-1)!, where S is the number of dice, each with N sides numbered 1 through N. (It is different from the well known combinations formula because it is possible for the same number to appear on more than one dice). For example, when throwing four six-sided dice, N=6 and S=4, so the number of possible combinations is (4+6-1)!/4!(6-1)! = 9!/4!x5! = 126. How can I generate a matrix of these 126 possible outcomes? Thank you.

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• rewrite image URLs

  - by Don

  Hi, I'm writing a Maven plugin that merges CSS files together. So all the CSS files that match /foo/bar/*.css might get merged to /foo/merged.css. A concern is that in a file such as /foo/bar/baz.css there might be a property such as: background: url("images/pic.jpg") So when the file is merged into /foo/merged.css this will need to be changed to background: url("bar/images/pic.jpg") The recalculated URL obviously depends on 3 factors: original URL original CSS file location merged CSS file location Assuming that the original and merged CSS files are both on the same filesystem, is there a general formula (or Java library) that can be used to calculate the new url given these 3 inputs? Thanks, Don

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• lookahead and group

  - by Istao

  Hi, In Java, on a text like foo <on> bar </on> thing <on> again</on> now, I should want a regex with groups wich give me with a find "foo", "bar", empty string, then "thing", "again", "now". If I do (.*?)<on>(.*?)</on>(?!<on>), I get only two group (foo bar, thing again, and I've not the end "now"). if I do (.*?)<on>(.*?)</on>((?!<on>)) I get foo bar empty string, then thing again and empty string (here I should want "now"). Please what is the magical formula ? Thanks.

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• Determining if a coordinate is on a line

  - by TGCBraun

  I´m coding a little app that allows the user to draw multiple shapes and then remove or resize them. It´s working perfectly on rectangles and ovals, but I´m having issues with lines. Here´s a method that I wrote to find if the clicked spot on the screen is part of a specific line: public boolean containsLocation(int x, int y) { int m = (getY2() - getY()) / (getX2() - getX()); int b = getY() - (m * getX()); if (y == (m * x) + b) { return true; } return false; I´m using the famous y = mx + b formula and replacing y and x to find if the clicked spot is part of the line. The problem is when I click on the screen to remove the line, it only works if I click on the very fist coordinate (x,y) where the line starts. Nothing happens when I click anywhere else along the line. Can anyone shed a light on what I´m doing wrong? Thanks a lot.

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• O(N log N) Complexity - Similar to linear?

  - by gav

  Hey All, So I think I'm going to get buried for asking such a trivial but I'm a little confused about something. I have implemented quicksort in Java and C and I was doing some basic comparissons. The graph came out as two straight lines, with the C being 4ms faster than the Java counterpart over 100,000 random integers. The code for my tests can be found here; android-benchmarks I wasn't sure what an (n log n) line would look like but I didn't think it would be straight. I just wanted to check that this is the expected result and that I shouldn't try to find an error in my code. I stuck the formula into excel and for base 10 it seems to be a straight line with a kink at the start. Is this because the difference between log(n) and log(n+1) increases linearly? Thanks, Gav

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• Number distribution

  - by Carra

  Problem: We have x checkboxes and we want to check y of them evenly. Example 1: select 50 checkboxes of 100 total. [-] [x] [-] [x] ... Example 2: select 33 checkboxes of 100 total. [-] [-] [x] [-] [-] [x] ... Example 3: select 66 checkboxes of 100 total: [-] [x] [x] [-] [x] [x] ... But we're having trouble to come up with a formula to check them in code, especially once you go 11/111 or something similar. Anyone has an idea?

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• Probability Question

  - by Juddling

  if i pick 10 numbers from a possible 80. what is the probablity for someone else picking the same 10 numbers as me? or just 4 numbers? or no numbers? i think it's no matches: 10/80 one match: 10*9/80*79 so the formula would be (10!/matches!)/(80!/matches!) is this right? i've only just started doing this at A-level and i need it for a game script i'm making.

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• Generate a matrix of all possible outcomes for throwing n dice (ignoring order)

  - by Brani

  In cases where order does matter, it's rather easy to generate the matrix of all possible outcomes. One way for doing this is using expand.grid as shown here. What if it doesn't? If I'm right, the number of possible combinations is (S+N-1)!/S!(N-1)!, where S is the number of dice, each with N sides numbered 1 through N. (It is different from the well known combinations formula because it is possible for the same number to appear on more than one dice). For example, when throwing four six-sided dice, N=6 and S=4, so the number of possible combinations is (4+6-1)!/4!(6-1)! = 9!/4!x5! = 126. How can I generate a matrix of these 126 possible outcomes? Thank you.

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• Bouncing a ball off a surface

  - by Sagekilla

  Hi all, I'm currently in the middle of writing a game like Breakout, and I was wondering how I could properly bounce a ball off a surface. I went with the naive way of rotating the velocity by 180 degrees, which was: [vx, vy] -> [-vy, vx] Which (unsurprisingly) didn't work so well. If I know the position and veocity of the ball, as well as the point the ball would hit (but is going to instead bounce off of) how can I bounce it off that point? I don't need any language specific code. If anyone could provide a small, mathematical formula on how to properly do this that would work fine for me. I also need this to work with integer positions and velocity (I can't use floating point anywhere). Thanks!

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• recursive program

  - by wilson88

  I am trying to make a recursive program that calculates interest per year.It prompts the user for the startup amount (1000), the interest rate (10%)and number of years(1).(in brackets are samples) Manually I realised that the interest comes from the formula YT(1 + R)----- interest for the first year which is 1100. 2nd year YT(1 + R/2 + R2/2) //R squared 2nd year YT(1 + R/3 + R2/3 + 3R3/) // R cubed How do I write a recursive program that will calculate the interest? Below is the function which I tried //Latest after editing double calculateInterest2(double start, double rate, int duration) { if (0 == duration) { return start; } else { return (1+rate) * calculateInterest2(start, rate, duration - 1); } }

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• getting the value of a filter at an arbitrary time

  - by Andiih

  Context: I'm trying to improve the values returned by the iPhone CLLocationManager, although this is a more generally applicable problem. The key is that CLLocationManger returns data on current velocity as and when it feels like it, rather than at a fixed sample rate. I'd like to use a feedback equation to improve accuracy v=(k*v)+(1-k)*currentVelocity where currentVelocity is the speed returned by didUpdateToLocation:fromLocation: and v is the output velocity (and also used for the feedback element). Because of the "as and when" nature of didUpdateToLocation:fromLocation: I could calculate the time interval since it was last called, and do something like for (i=0;i<timeintervalsincelastcalled;i++) v=(k*v)+(1-k)*currentVelocity which would work, but is wasteful of cycles. Especially as I probably want timeintervalsincelastcalled to be measured as 10ths of a second. Is there a way to solve this without the loop ? i.e. rework (integrate?) the formula so I put an interval into the equation and get the same answer as I would have by iteration ?

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• How do I suppress this output?

  - by David

  I have a code chunk in an R Markdown file. ```{r} library(UsingR) ``` Using knitHTML to compile causes the following output, which never happened before I updated to the latest versions of R and RStudio: ## Loading required package: MASS ## Loading required package: HistData ## Loading required package: Hmisc ## Loading required package: grid ## Loading required package: lattice ## Loading required package: survival ## Loading required package: splines ## Loading required package: Formula ## ## Attaching package: 'Hmisc' ## ## The following objects are masked from 'package:base': ## ## format.pval, round.POSIXt, trunc.POSIXt, units ## ## Loading required package: aplpack ## Loading required package: tcltk ## Loading required package: quantreg ## Loading required package: SparseM ## ## Attaching package: 'SparseM' ## ## The following object is masked from 'package:base': ## ## backsolve ## ## ## Attaching package: 'quantreg' ## ## The following object is masked from 'package:Hmisc': ## ## latex ## ## The following object is masked from 'package:survival': ## ## untangle.specials ## ## ## Attaching package: 'UsingR' ## ## The following object is masked from 'package:survival': ## ## cancer How can I suppress this output? Note: echo=FALSE did not work.

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• How to fetch managed objects sorted by calculated value

  - by Marcin Zbijowski

  Hello, I'm working on the app that uses CoreData. There is location entity that holds latitude and longitude values. I'd like to fetch those entities sorted by distance to the user's location. I tried to set sort descriptor to distance formula sqrt ((x1 - x2)^2 + (y1 - y2)^2) but it fails with exception "... keypath ... not found in entity". NSString *distanceFormula = [NSString stringWithFormat:@"sqrt(((latitude - %f) * (latitude - %f)) + ((longitude - %f) * (longitude - %f)))", location.coordinate.latitude, location.coordinate.latitude, location.coordinate.longitude, location.coordinate.longitude]; NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:distanceFormula ascending:YES]; [fetchRequest setSortDescriptors:[NSArray arrayWithObject:sortDescriptor]]; NSError *error; NSArray *result = [[self managedObjectContext] executeFetchRequest:fetchRequest error:&error]; I'd like to fetch already sorted objects rather then fetch them all and then sort in the code. Any tips appreciated.

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