Search Results

Search found 6031 results on 242 pages for 'imaginary numbers'.

Page 47/242 | < Previous Page | 43 44 45 46 47 48 49 50 51 52 53 54  | Next Page >

  • Saving CSV in cocoa

    - by happyCoding25
    Hello, I need to make a cvs file in cocoa. To see how to set it up I created one in Numbers and opened it with text edit it looked like this: Results,,,,,,,,,,,, ,,,,,,,,,,,, A,10,,,,,,,,,,, B,10,,,,,,,,,,, C,10,,,,,,,,,,, D,10,,,,,,,,,,, E,10,,,,,,,,,,, So to replicate this in cocoa I used: NSString *CVSData = [NSString stringWithFormat:@"Results\n,,,,,,,,,,,,\nA,%@,,,,,,,,,,,\nB,%@,,,,,,,,,,,\nC,%@,,,,,,,,,,,\nD,%@,,,,,,,,,,,\nE,%@,,,,,,,,,,,",[dataA stringValue], [dataB stringValue], [dataC stringValue], [dataD stringValue], [dataE stringValue]]; Then [CVSData writeToFile:[savePanel filename] atomically:YES]; But when I try to open the saved file with Numbers I get the error “Untitled.cvs” could not be handled because Numbers cannot open files in the “Numbers Document” format. Could this be something with the way cocoa is encoding the file? Thanks for any help

    Read the article

  • PHP Sum Array - sum only elemants of an array

    - by Homer_J
    Hi all, I have have an array as follows: $row[6] This section of the array has 4 numbers within it that I can display and use without any problems, what I'd like to be able to do is sum the first two numbers and the last two numbers separately. Is there any way to do this? Thanks in advance, Homer.

    Read the article

  • preg_replace only part of match

    - by Tony Vipros
    Hi, I'm using preg_replace to create urls for modrewrite based paging links. I use: $nextURL = preg_replace('%/([\d]+)/%','/'.($pageNumber+1).'/',$currentURL); which works fine, however I was wondering if there is a better way without having to include the '/' in the replacement parameter. I need to match the number as being between two / as the URLs can sometimes contain numbers other than the page part. These numbers are never only numbers however, so have /[\d]+/ stops them from getting replaced.

    Read the article

  • Ruby: How to loop through an object that may or may not be an array?

    - by Shpigford
    I have an each method that is run on some user-submitted data. Sometimes it will be an array, other times it won't be. Example submission: <numbers> <number>12345</number> </numbers> Another example: <numbers> <number>12345</number> <number>09876</number> </numbers> I have been trying to do an each do on that, but when there is only one number I get a TypeError (Symbol as array index) error.

    Read the article

  • nSticky/static variable references in for loops

    - by pthulin
    In this example I create three buttons 'one' 'two' 'three'. When clicked I want them to alert their number: <html> <head> <script type="application/javascript" src="jquery.js"></script> <script type="application/javascript"> $(document).ready(function() { var numbers = ['one', 'two', 'three']; for (i in numbers) { var nr = numbers[i]; var li = $('<li>' + nr + '</li>'); li.click(function() { var newVariable = String(nr); alert(i); // 2 alert(nr); // three alert(newVariable); // three alert(li.html()); // three }); $('ul').append(li); } }); </script> </head> <body> <ul> </ul> </body> </html> The problem is, when any of these are clicked, the last value of the loop's variables is used, i.e. alert box always says 'three'. In JavaScript, variables inside for-loops seem to be 'static' in the C language sense. Is there some way to create separate variables for each click function, i.e. not using the same reference? Thanks! Edit: The solution is to use jQuery.data to associate arbitrary data with each element: <html> <head> <script type="application/javascript" src="jquery.js"></script> <script type="application/javascript"> $(document).ready(function() { var numbers = ['one', 'two', 'three']; for (i in numbers) { var nr = numbers[i]; var li = $('<li>' + nr + '</li>'); li.data('nr', nr); li.click(function() { alert($(this).data('nr')); }); $('ul').append(li); } }); </script> </head> <body> <ul> </ul> </body> </html>

    Read the article

  • mysql: can I do a for-each on a comma separated field?

    - by Tillebeck
    Just ran into a problem I know these integers, $integers: 3,5,15,20 I only want to select the rows from this following table where all comma separated INT's from the field NUMBERS are found. TABLE: number_table Uid Numbers ------------------------ 1 3,5,15 OK, since all of NUMBERS are in $integers 2 5,15,20 OK, since all of NUMBERS are in $integers 3 3,4,5,15 NOT OK, since 4 is not found in $integers 4 2,15,20,25 NOT OK, since 2 and 25 is not found in $integers Is it possible to to a "for-each" on a comma separated string or another way to do this SELECT?

    Read the article

  • determine if intersection of a set with conjunction of two other sets is empty

    - by koen
    For any three given sets A, B and C: is there a way to determine (programmatically) whether there is an element of A that is part of the conjunction of B and C? example: A: all numbers greater than 3 B: all numbers lesser than 7 C: all numbers that equal 5 In this case there is an element in set A, being the number 5, that fits. I'm implementing this as specifications, so this numerical range is just an example. A, B, C could be anything.

    Read the article

  • How do you encrypt parts of a file separately using pgp?

    - by Collin Anderson
    I would like to encrypt credit card numbers on a web server as they come in using PGP. I would then like to be able to export all of the credit card numbers and other information in one file that can be easily decrypted using standard PGP software. Is it possible to take the encrypted credit card numbers and join them with other encrypted data and be able to decrypt the entire file? Basically is this true? D(E(x) + E(y)) = x + y Where '+' means string concatenation.

    Read the article

  • Regex to match card code input

    - by kate
    How can I write a regex to match strings following these rules? 1 letter followed by 4 letters or numbers, then 5 letters or numbers, then 3 letters or numbers followed by a number and one of the following signs: ! & @ ? I need to allow input as a 15-character string or as 3 groups of 5 chars separated by one space. I'm implementing this in JavaScript.

    Read the article

  • Print an array elements

    - by 1ace1
    Hello guys, this is my first post and im still a beginner in the programming world so bare with me. I just created an array with 100 initialized values and i want to print out 10 elements on each line so it would be somthing like this 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 ...26 this is the code i used and i managed to do it for the first 10 elements but i couldnt figure out how to do it for the rest public static void main(String[] args) { int[] numbers = { 0,1,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17}; int i, count = 0; for (i = 0; i < numbers.length; i++) { System.out.print(numbers[i] + " "); count++; if (count == 9) for (i = 9; i < numbers.length; i++) System.out.println(numbers[i] + " "); } } thanks!

    Read the article

  • Newb Question: scanf() in C

    - by riemannliness
    So I started learning C today, and as an exercise i was told to write a program that asks the user for numbers until they type a 0, then adds the even ones and the odd ones together. Here is is (don't laugh at my bad style): #include <stdio.h>; int main() { int esum = 0, osum = 0; int n, mod; puts("Please enter some numbers, 0 to terminate:"); scanf("%d", &n); while (n != 0) { mod = n % 2; switch(mod) { case 0: esum += n; break; case 1: osum += n; } scanf("%d", &n); } printf("The sum of evens:%d,\t The sum of odds:%d", esum, osum); return 0; } My question concerns the mechanics of the scanf() function. It seems that when you enter several numbers at once separated by spaces (eg. 1 22 34 2 8), the scanf() function somehow remembers each distinct numbers in the line, and steps through the while loop for each one respectively. Why/how does this happen? Example interaction within command prompt: - Please enter some numbers, 0 to terminate: 42 8 77 23 11 (enter) 0 (enter) - The sum of evens:50, The sum of odds:111 I'm running the program through the command prompt, it's compiled for win32 platforms with visual studio.

    Read the article

  • Reading a text file in c++

    - by Yavuz Karacabey
    string numbers; string fileName = "text.txt"; ifstream inputFile; inputFile.open(fileName.c_str(),ios_base::in); inputFile >> numbers; inputFile.close(); cout << numbers; And my text.txt file is: 1 2 3 4 5 basically a set of integers separated by tabs. The problem is the program only reads the first integer in the text.txt file and ignores the rest for some reason. If I remove the tabs between the integers it works fine, but with tabs between them, it won't work. What causes this? As far as I know it should ignore any white space characters or am I mistaken? If so is there a better way to get each of these numbers from the text file?

    Read the article

  • How to generate a number in arbitrary range using random()={0..1} preserving uniformness and density?

    - by psihodelia
    Generate a random number in range [x..y] where x and y are any arbitrary floating point numbers. Use function random(), which returns a random floating point number in range [0..1] from P uniformly distributed numbers (call it "density"). Uniform distribution must be preserved and P must be scaled as well. I think, there is no easy solution for such problem. To simplify it a bit, I ask you how to generate a number in interval [-0.5 .. 0.5], then in [0 .. 2], then in [-2 .. 0], preserving uniformness and density? Thus, for [0 .. 2] it must generate a random number from P*2 uniformly distributed numbers. The obvious simple solution random() * (x - y) + y will generate not all possible numbers because of the lower density for all abs(x-y)>1.0 cases. Many possible values will be missed. Remember, that random() returns only a number from P possible numbers. Then, if you multiply such number by Q, it will give you only one of P possible values, scaled by Q, but you have to scale density P by Q as well.

    Read the article

  • Regex Question ...

    - by kate
    Hi, Could someone help me with the following RegEx query: based on the following rules: 1) 1 letter followed by 4 letters or numbers, then 2) 5 letters or numbers, then 3) 3 letters or numbers followed by a number and one of the following signs: ! & @ ? You will have to allow customers to input the fidelity card code as a 15-character string, or as 3 groups of 5 chars, separated by one space.

    Read the article

  • How do I send the mutable string to the NSTextField properly?

    - by Merle
    So I have all this code that I have debugged and it seems to be fine. I made a mutable string and for some reason I can not get it to be displayed on my label. the debugger says "2010-04-22 22:50:26.126 Fibonacci[24836:10b] * -[NSTextField setString:]: unrecognized selector sent to instance 0x130150" What is wrong with this? When I just send the string to NSLog, it comes out fine. here's all my code, any help would be appreciated. "elementNum" is a comboBox and "display" is a Label. Thanks #import "Controller.h" @implementation Controller - (IBAction)computeNumber:(id)sender { int x = 1; int y = 1; NSMutableString *numbers = [[NSMutableString alloc] init]; [numbers setString:@"1, 1,"]; int num = [[elementNum objectValueOfSelectedItem]intValue]; int count = 1; while (count<=num) { int z = y; y+=x; x=z; [numbers appendString:[NSString stringWithFormat:@" %d,", y]]; count++; } [display setString:numbers]; NSLog(numbers); } @end `

    Read the article

  • Convert month number to month short name

    - by Roland
    I have a variable with the following value $month = 201002; the first 4 numbers represent the year, and the last 2 numbers represent the month. I need to get the last 2 numbers in the month string name eg. Feb My code looks like this <?php echo date('M',substr($month,4,6)); ?> I can I go about to obtain the month name

    Read the article

  • controlling bluetooth connection in matlab

    - by Mehreen Shahid
    we have a project in which we have to pick randomly generated numbers from a remote device, say mobile. there is a simple java application to generate numbers. next, we have to recieve those numbers in our matlab program via bluetooth connection with the device. assuming those numbers are temperature readings, we want to recieve a new number after every 10 sec and display the number on our matlab GUI program. the problem is do we implement bluetooth protocol through our programming? or use the matlab templates? because otherwise whenever we want to transfer file from a mobile to computer, we have to manually click "recieve a file" in blutooth wizard , just like we normally do to transfer a file. we want to enable the connection once, and then recieve text files after every 10 seconds to be read in our matlab program. can anyone please tell is it even possible in matlab? if yes, how do we establish such an automatic real time connection?

    Read the article

  • JavaScript: Rounding to two decimal places. Not less than two

    - by Abs
    Hello all, I have this line of code which rounds my numbers to 2 decimal places. But the thing is I get numbers like this. 10.8, 2.4 etc. These are not my idea of 2 decimal places so how I can improve this: Math.round(price*Math.pow(10,2))/Math.pow(10,2); I want numbers like 10.80, 2.40 etc. Use of JQuery is fine with me. Thanks for any help.

    Read the article

  • removing phone number from a document.

    - by Grant Collins
    Hi, I've got a challenge that I am hoping that the SO community is able to help me with. I trying to parse a lot of html documents in my PHP application to remove personal details, such as names, addresses and phone numbers. I can remove most of these details without too much trouble, however the phone number is a real problem for me. My idea is to take the text from these documents and the use a regex to identify the phone numbers and replace them with another value such as 'xxxx'. I've got 2 regex that I am using one for UK landline numbers and one for UK cell/mobile numbers. However when I try and run them against the text it just returns an empty string. I am using the following preg_replace code: $pattens = array( '/^(((\+44\s?\d{4}|\(?0\d{4}\)?)\s?\d{3}\s?\d{3})|((\+44\s?\d{3}|\(?0\d{3}\)?)\s?\d{3}\s?\d{4})|((\+44\s?\d{2}|\(?0\d{2}\)?)\s?\d{4}\s?\d{4}))(\s?\#(\d{4}|\d{3}))?$/', '/^(\+44\s?7\d{3}|\(?07\d{3}\)?)\s?\d{3}\s?\d{3}$/' ); $replace = array('xxxxx', 'xxxxx'); //do the search for the numbers. $updatedContents = preg_replace($pattens, $replace, $htmlContents); At the moment this is causing me a lot of head scratching as I thought that I had this nailed, but at the moment I can't see what's wrong?? I am sure that it is something really simple. Thanks, Grant

    Read the article

  • Ruby on Rails: How do you add add zeros in front of a number if it's under 10?

    - by sjsc
    I'm looking to convert single digit numbers to two-digit numbers like so: 9 ==> 09 5 ==> 05 12 == 12 4 ==> 04 I figure I could put a bunch of if-else statements (if number is under 10, then do a gsub) but figure that's horrible coding. I know Rails has number_with_precision but I see that it only applies to decimal numbers. Any ideas on how to convert single-digits to two-digits?

    Read the article

  • Using FOR XML AUTO against a synonym

    - by Rick
    We've just switched to synonyms for linked server stuff, and noticed that our FOR XML output is no longer correct. When returning XML results from a view, we could alias the view and that would be assigned as the element name. With synonyms, however, it seems to ignore the alias? We're still mostly on SQL 2005 - this bug doesn't seem to happen on our 2008 instance. Is this a known problem, and any ideas for work-arounds? For example, this is what we used to be able to do: select top 3 number from Numbers as elementname for xml auto <elementname number="0"/><elementname number="1"/><elementname number="2"/> And this is what happens with a synonym: select top 3 number from Numbers_synonym as elementname for xml auto <dbo.Numbers number="0"/><dbo.Numbers number="1"/><dbo.Numbers number="2"/> As you can see, SQL Server seems to use the name of the actual referenced object instead of the alias. This gets worse for cross server queries, because you get the four-part name instead of the nice alias. (eg: <rick_server.rick_database.dbo.Numbers number="0"/>...)

    Read the article

  • Implement loops for python 3

    - by Alex
    Implement this loop: total up the product of the numbers from 1 to x. Implement this loop: total up the product of the numbers from a to b. Implement this loop: total up the sum of the numbers from a to b. Implement this loop: total up the sum of the numbers from 1 to x. Implement this loop: count the number of characters in a string s. i'm very lost on implementing loops these are just some examples that i am having trouble with-- if someone could help me understand how to do them that would be awesome

    Read the article

  • Compare versions as strings

    - by Dmitriy
    Comparing version numbers as strings is not so easy... "1.0.0.9" "1.0.0.10", but it's not correct. Obvious way to do it properly is parse these strings, convert to numbers and compare as numbers. Is it other way to do it more "elegant"? For example, boost::string_algo...

    Read the article

< Previous Page | 43 44 45 46 47 48 49 50 51 52 53 54  | Next Page >