Search Results

Search found 2957 results on 119 pages for 'gridview sorting'.

Page 59/119 | < Previous Page | 55 56 57 58 59 60 61 62 63 64 65 66  | Next Page >

• Keeping DB Table sorted using multi-field formula (Microsoft SQL)

  - by user298167

  Hello Everybody. I have a Job Table which has two interesting columns: Creation Date and Importance (high - 3, medium 2, low - 1). Job's priority calculated like this: Priority = Importance * (time passed since creation). The problem is, Every time I would like to pick 200 jobs with highest priority, I dont want to resort the table. Is there a way to keep rows sorted? I was also thinking about having three tables one for High, Medium and Low and then sort those by Creation Date. Thanks

  Read the article

• barebones sort algorithm

  - by user309322

  i have been asked to make a simple sort aglorithm to sort a random series of 6 numbers into numerical order. However i have been asked to do this using "Barebones" a theoretical language put forward in the Book Computer Science an overview. Some information on the language can be found here http://www.brouhaha.com/~eric/software/barebones/ Just to clarify i am a student teacher and have been doing anaysis on "mini-programing languages" and their uses in a teaching environment, i suggested to my tutor that i look at barebones and asked what sort of exmaple program i should write . He suggested a simple sort algorithm. Now since looking at the language i cant understand how i can do this without using arrays and if statements. The code to swap the value of variables would be while a not 0 do; incr Aux1; decr a; end; while b not 0 do; incr Aux2 decr b end; while Aux1 not 0 do; incr a; decr Aux1; end; while Aux2 not 0 do; incr b; decr Aux2; end; however the language does not provide < or operators

  Read the article

• Implement Partial sorted query in sql server 2005

  - by Brij

  I have to show records in such a way that some selected records should come first. After this, another records come in sorted manner from the same table. For example, If I select state having stateID = 5 then the corresponding record should come first. after this another records should come in sorted manner. For this, I tried union but it shows all in sorted. select state from statemaster where stateid=5 union all select state from statemaster where not stateid =5 order by state Thanks

  Read the article

• How to strip specific contents of a String in Java

  - by user2974877

  So I have a string, and I want to strip out some parts of it using, for example, the firt and last characters of the "interesting" part. String dirty = "$!$!%!%$something interesting&!!$!%$something interesting2"; And the output something like: String clean = "something interesting:something interesting2"; Note: The code needs to work without knowing the random part, changing everytime the program runs. I researched and only found code that does it, but only knowing the random segment.

  Read the article

• Why doesn't java.lang.Number implement Comparable?

  - by Julien Chastang

  Does anyone know why java.lang.Number does not implement Comparable? This means that you cannot sort Numbers with Collections.sort which seems to me a little strange. Post discussion update: Thanks for all the helpful responses. I ended up doing some more research about this topic. The simplest explanation for why java.lang.Number does not implement Comparable is rooted in mutability concerns. For a bit of review, java.lang.Number is the abstract super-type of AtomicInteger, AtomicLong, BigDecimal, BigInteger, Byte, Double, Float, Integer, Long and Short. On that list, AtomicInteger and AtomicLong to do not implement Comparable. Digging around, I discovered that it is not a good practice to implement Comparable on mutable types because the objects can change during or after comparison rendering the result of the comparison useless. Both AtomicLong and AtomicInteger are mutable. The API designers had the forethought to not have Number implement Comparable because it would have constrained implementation of future subtypes. Indeed, AtomicLong and AtomicInteger were added in Java 1.5 long after java.lang.Number was initially implemented. Apart from mutability, there are probably other considerations here too. A compareTo implementation in Number would have to promote all numeric values to BigDecimal because it is capable of accommodating all the Number sub-types. The implication of that promotion in terms of mathematics and performance is a bit unclear to me, but my intuition finds that solution kludgy.

  Read the article

• How to sort an array or ArrayList<Point> ASC first by x and then by y?

  - by newba

  Hi everyone, I just want to use Collections.sort or Arrays.sort to sort a list of points (class Point) by x first and then by y. I have a class Ponto that implements Comparable like this: public int compareTo(Ponto obj) { Ponto tmp = obj; if (this.x < tmp.x) { return -1; } else if (this.x > tmp.x) { return 1; } return 0; } but now I want to sort by y too after x. How can I do that by modifying the above code? Or is that a better and "clean" way to do this? I also use to pass this code to C++, in which I've created a structure called Point with a equivalent comparable method.

  Read the article

• python how to find the median of a list

  - by user3450574

  I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

  Read the article

• Creating an Order Column for encrypted data

  - by SetiSeeker

  I am saving encrypted data to a database. Is there a way I can create a "hashcode" or fingerprint or checksum of the plain text data, that if I sort / order by on the "hashcode" the order would be the same as if I had saved the plain text data and perform the same sort / order by operation on it? I basically need a SOUNDEX() type function that will give me a value that will maintain the order of the plain text data. I would then save both encrypted data and the "hashcode" and when querying the data order by the "hashcode" field. I need to perform this in the application and preferably not in the SQL DB if at all possible. I am using Entity Framework and SQL 2008 and C# 4.0.

  Read the article

• Organizing a random list of objects in Python.

  - by Saebin

  So I have a list that I want to convert to a list that contains a list for each group of objects. ie ['objA.attr1', 'objC', 'objA.attr55', 'objB.attr4'] would return [['objA.attr1', 'objA.attr55'], ['objC'], ['objB.attr4']] currently this is what I use: givenList = ['a.attr1', 'b', 'a.attr55', 'c.attr4'] trgList = [] objNames = [] for val in givenList: obj = val.split('.')[0] if obj in objNames: id = objNames.index(obj) trgList[id].append(val) else: objNames.append(obj) trgList.append([val]) #print trgList It seems to run a decent speed when the original list has around 100,000 ids... but I am curious if there is a better way to do this. Order of the objects or attributes does not matter. Any ideas?

  Read the article

• Is there a good radixsort-implementation for floats in C#

  - by CommuSoft

  I have a datastructure with a field of the float-type. A collection of these structures needs to be sorted by the value of the float. Is there a radix-sort implementation for this. If there isn't, is there a fast way to access the exponent, the sign and the mantissa. Because if you sort the floats first on mantissa, exponent, and on exponent the last time. You sort floats in O(n).

  Read the article

• Array of pointers in Objective-C using NSArray

  - by Amir

  Hello, I am writting program for my iphone and have a qestion. lets say i have class named my_obj class my_obj { NSString *name; NSinteger *id; NSinteger *foo; NSString *boo; } now i allocate 100 objects from type my_obj and insert them to array from type NSArray. then i want to sort the Array in two different ways. one by the name and the second by the id. i want to allocate another two arrays from type NSArray *arraySortByName *arraySortById what i need to do if i just want the sorted arrays to be referenced to the original array so i will get two sorted arrays that point to the original array (that didnt changed!) i other word i dont want to allocate another 100 objects to each sorted array.

  Read the article

• How can I get a first element from a sorted list?

  - by Roman

  I used Collections.sort(playersList); to sort a list. So, I think playersList is sorted now. But how can I get the first element of the list? playersList[0] does not work.

  Read the article

• How to implement a collection (list, map?) of complicated strings in Java?

  - by Alex Cheng

  Hi all. I'm new here. Problem -- I have something like the following entries, 1000 of them: args1=msg args2=flow args3=content args4=depth args6=within ==> args5=content args1=msg args2=flow args3=content args4=depth args6=within args7=distance ==> args5=content args1=msg args2=flow args3=content args6=within ==> args5=content args1=msg args2=flow args3=content args6=within args7=distance ==> args5=content args1=msg args2=flow args3=flow ==> args4=flowbits args1=msg args2=flow args3=flow args5=content ==> args4=flowbits args1=msg args2=flow args3=flow args6=depth ==> args4=flowbits args1=msg args2=flow args3=flow args6=depth ==> args5=content args1=msg args2=flow args4=depth ==> args3=content args1=msg args2=flow args4=depth args5=content ==> args3=content args1=msg args2=flow args4=depth args5=content args6=within ==> args3=content args1=msg args2=flow args4=depth args5=content args6=within args7=distance ==> args3=content I'm doing some sort of suggestion method. Say, args1=msg args2=flow args3=flow == args4=flowbits If the sentence contains msg, flow, and another flow, then I should return the suggestion of flowbits. How can I go around doing it? I know I should scan (whenever a character is pressed on the textarea) a list or array for a match and return the result, but, 1000 entries, how should I implement it? I'm thinking of HashMap, but can I do something like this? <"msg,flow,flow","flowbits" Also, in a sentence the arguments might not be in order, so assuming that it's flow,flow,msg then I can't match anything in the HashMap as the key is "msg,flow,flow". What should I do in this case? Please help. Thanks a million!

  Read the article

• How to sort a list by the 2nd tuple element in python and C#

  - by user350468

  I had a list of tuples where every tuple consists of two integers and I wanted to sort by the 2nd integer. After looking in the python help I got this: sorted(myList, key=lambda x: x[1]) which is great. My question is, is there an equally succinct way of doing this in C# (the language I have to work in)? I know the obvious answer involving creating classes and specifying an anonymous delegate for the whole compare step but perhaps there is a linq oriented way as well. Thanks in advance for any suggestions.

  Read the article

• Data structure for an ordered set with many defined subsets; retrieve subsets in same order

  - by Aaron

  I'm looking for an efficient way of storing an ordered list/set of items where: The order of items in the master set changes rapidly (subsets maintain the master set's order) Many subsets can be defined and retrieved The number of members in the master set grow rapidly Members are added to and removed from subsets frequently Must allow for somewhat efficient merging of any number of subsets Performance would ideally be biased toward retrieval of the first N items of any subset (or merged subset), and storage would be in-memory (and maybe eventually persistent on disk)

  Read the article

• Overriding Ruby's spaceship operator <=>

  - by ericsteen1

  I am trying to override Ruby's <= (spaceship) operator to sort apples and oranges so that apples come first sorted by weight, and oranges second, sorted by sweetness. Like so: module Fruity attr_accessor :weight, :sweetness def <=>(other) # use Array#<=> to compare the attributes [self.weight, self.sweetness] <=> [other.weight, other.sweetness] end include Comparable end class Apple include Fruity def initialize(w) self.weight = w end end class Orange include Fruity def initialize(s) self.sweetness = s end end fruits = [Apple.new(2),Orange.new(4),Apple.new(6),Orange.new(9),Apple.new(1),Orange.new(22)] p fruits #should work? p fruits.sort But this does not work, can someone tell what I am doing wrong here, or a better way to do this?

  Read the article

• how to sort xml data in jQuery

  - by pixeltocode

  how can i sort all officers based on their ranks jQuery $.get('officers.xml', function(grade){ $(grade).find('officer').each(function(){ var $rank = $(this).attr('rank'); }); }); XML (officer.xml) <grade> <officer rank="2"></student> <officer rank="3"></student> <officer rank="1"></student> </grade> thanks.

  Read the article

• Efficient way to maintain a sorted list of access counts in Python

  - by David

  Let's say I have a list of objects. (All together now: "I have a list of objects.") In the web application I'm writing, each time a request comes in, I pick out up to one of these objects according to unspecified criteria and use it to handle the request. Basically like this: def handle_request(req): for h in handlers: if h.handles(req): return h return None Assuming the order of the objects in the list is unimportant, I can cut down on unnecessary iterations by keeping the list sorted such that the most frequently used (or perhaps most recently used) objects are at the front. I know this isn't something to be concerned about - it'll make only a miniscule, undetectable difference in the app's execution time - but debugging the rest of the code is driving me crazy and I need a distraction :) so I'm asking out of curiosity: what is the most efficient way to maintain the list in sorted order, descending, by the number of times each handler is chosen? The obvious solution is to make handlers a list of (count, handler) pairs, and each time a handler is chosen, increment the count and resort the list. def handle_request(req): for h in handlers[:]: if h[1].handles(req): h[0] += 1 handlers.sort(reverse=True) return h[1] return None But since there's only ever going to be at most one element out of order, and I know which one it is, it seems like some sort of optimization should be possible. Is there something in the standard library, perhaps, that is especially well-suited to this task? Or some other data structure? (Even if it's not implemented in Python) Or should/could I be doing something completely different?

  Read the article

• Is this a bad version of the Merge Sort algorithm?

  - by SebKom

  merge1(int low, int high, int S[], U[]) { int k = (high - low + 1)/2 for q (from low to high) U[q] = S[q] int j = low int p = low int i = low + k while (j <= low + k - 1) and (i <= high) do { if ( U[j] <= U[i] ) { S[p] := U[j] j := j+1 } else { S[p] := U[i] i := i+1 } p := p+1 } if (j <= low + k - 1) { for q from p to high do { S[q] := U[j] j := j+1 } } } merge_sort1(int low, int high, int S[], U[]) { if low < high { int k := (high - low + 1)/2 merge_sort1(low, low+k-1, S, U) merge_sort1(low+k, high, S, U) merge1(low, high, S, U) } } I am really sorry for the terrible formating, as you can tell I am not a regular visitor here. So, basically, this is on my lecture notes. I find it quite confusing in general but I understand the biggest part of it. What I don't understand is the need of the "if (j <= low + k - 1)" part. It looks like it checks if there are any elements "left" in the left part. Is that even possible when mergesorting?

  Read the article

• A good Sorted List for Java

  - by Phuong Nguyen de ManCity fan

  I'm looking for a good sorted list for java. Googling around give me some hints about using TreeSet/TreeMap. But these components is lack of one thing: random access to an element in the set. For example, I want to access nth element in the sorted set, but with TreeSet, I must iterate over other n-1 elements before I can get there. It would be a waste since I would have upto several thousands elements in my Set. Basically, I'm looking for some thing similar to a sorted list in .NET, with ability to add element fast, remove element fast, and have random access to any element in the list. Has this kind of sorted list implemented somewhere? Thanks.

  Read the article

• How can I possibly sort this in JavaScript?

  - by orokusaki

  I've been pounding my head on the wall trying to figure out how to sort this in JavaScript (I have to work with it in this format unfortunately). I need to sort it based on Small, Medium, Large, XL, XXL (Small ranking the highest) in each variationValues size field. The problem is that I need to sort the variationCosts and variationInventories at the same time to match the new order (since each value in order corresponds to the values in the other fields :( Input I have to work with var m = { variationNames: ["Length", "Size" ], variationValues: [ ["26.5\"", "XXL"], ["25\"", "Large"], ["25\"", "Medium"], ["25\"", "Small"], ["25\"", "XL"], ["25\"", "XXL"], ["26.5\"", "Large"], ["26.5\"", "Small"], ["26.5\"", "XL"] ], variationCosts: [ 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00 ], variationInventories: [ 10, 60, 51, 10, 15, 10, 60, 10, 15 ], parentCost: 20.00 }; Desired output var m = { variationNames: ["Length", "Size" ], variationValues: [ ["25\"", "Small"], ["26.5\"", "Small"], ["25\"", "Medium"], ["25\"", "Large"], ["26.5\"", "Large"], ["25\"", "XL"], ["26.5\"", "XL"] ["25\"", "XXL"], ["26.5\"", "XXL"], ], variationCosts: [ 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00, 20.00 ], variationInventories: [ 10, 10, 51, 60, 15, 15, 15, 10, 10 ], parentCost: 20.00 };

  Read the article

• Why is my List.Sort method in C# reversing the order of my list?

  - by Fiona Holder

  I have a list of items in a generic list: A1 (sort index 1) A2 (sort index 2) B1 (sort index 3) B2 (sort index 3) B3 (sort index 3) The comparator on them takes the form: this.sortIndex.CompareTo(other.sortIndex) When I do a List.Sort() on the list of items, I get the following order out: A1 A2 B3 B2 B1 It has obviously worked in the sense that the sort indexes are in the right order, but I really don't want it to be re-ordering the 'B' items. Is there any tweak I can make to my comparator to fix this?

  Read the article

• Flex ArrayCollection bubble item up or down by one position

  - by asawilliams

  I have an ArrayCollection where I want to be able to bubble items up or down by one position. What is the best way to do this?

  Read the article

• T-SQL: how to sort table rows based on 2 columns

  - by Criss Nautilus

  I'm quite stuck with this problem for sometime now.. How do I sort column A depending on the contents of Column B? I have this sample: ID count columnA ColumnB 12 1 A B 13 2 C D 14 3 B C I want to sort it like this: ID count ColumnA ColumnB 12 1 A B 14 3 B C 13 2 C D so I need to sort the rows if the previous row of ColumnB = the next row of ColumnA I'm thinking a loop? but can't quite imagine how it will work... I was thinking it will go like this (maybe) SELECT a.ID, a.ColumnA, a.ColumnB FROM TableA WITH a (NOLOCK) LEFT JOIN TableA b WITH (NOLOCK) ON a.ID = b.ID and a.counts = b.counts Where a.columnB = b.ColumnA the above code isn't working though and I was thinking more on the lines of... DECLARE @counts int = 1 DECLARE @done int = 0 --WHILE @done = 0 BEGIN SELECT a.ID, a.ColumnA, a.ColumnB FROM TableA WITH a (NOLOCK) LEFT JOIN TableA b WITH (NOLOCK) ON a.ID = b.ID and a.counts = @counts Where a.columnB = b.ColumnA set @count = @count +1 END If this was a C code, would be easier for me but t-sql's syntax is making it a bit harder for a noobie like me.

  Read the article

• Is there anything like memcached, but for sorted lists?

  - by depesz

  I have a situation where I could really benefit from having system like memcached, but with the ability to store (per each key) sorted list of elements, and modifying the list by addition of values. For example: something.add_to_sorted_list( 'topics_list_sorted_by_title', 1234, 'some_title') something.add_to_sorted_list( 'topics_list_sorted_by_title', 5436, 'zzz') something.add_to_sorted_list( 'topics_list_sorted_by_title', 5623, 'aaa') Which I then could use like this: something.get_list_size( 'topics_list_sorted_by_title' ) // returns 3 something.get_list_elements( 'topics_list_sorted_by_title', 1, 10 ) // returns: 5623, 1234, 5436 Required system would allow me to easily get items count in every array, and fetch any number of values from the array, with the assumption that the values are sorted using attached value. I hope that the description is clear. And the question is relatively simple: is there any such system?

  Read the article

< Previous Page | 55 56 57 58 59 60 61 62 63 64 65 66  | Next Page >