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  • Creating an Order Column for encrypted data

    - by SetiSeeker
    I am saving encrypted data to a database. Is there a way I can create a "hashcode" or fingerprint or checksum of the plain text data, that if I sort / order by on the "hashcode" the order would be the same as if I had saved the plain text data and perform the same sort / order by operation on it? I basically need a SOUNDEX() type function that will give me a value that will maintain the order of the plain text data. I would then save both encrypted data and the "hashcode" and when querying the data order by the "hashcode" field. I need to perform this in the application and preferably not in the SQL DB if at all possible. I am using Entity Framework and SQL 2008 and C# 4.0.

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  • sort files by date in PHP

    - by sasori
    hi, I currently have an index.php file which allows me to output the list of files inside the same directory, the output shows the names then I used filemtime() function to show the date when the file was modified. my problem now is, how will I sort the output to show the latest modified file ?, I've been thinking for awhile how to do this. if only I am doing it with mysql interaction there will be no problem at all. please show me an example how to sort and output the list of files starting from the latest modified one. this is what i have for now if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $lastModified = date('F d Y, H:i:s',filemtime($file)); if(strlen($file)-strpos($file,".swf")== 4){ echo "<tr><td><input type=\"checkbox\" name=\"box[]\"></td><td><a href=\"$file\" target=\"_blank\">$file</a></td><td>$lastModified</td></tr>"; } } } closedir($handle); }

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  • How to sort the row contents on table cell by using date

    - by MS Nathan
    Hi i am new to iphone application development.i am developing RSS feed Reader it has number of different RSS feeds. In my application (XML parsing), i want to display the content of the row on cell for particular date and with their corresponding title, description (in my application, i am using three labels for displaying title, date and description) on table view cell after parsing xml data. And i want to sort the all kinds of RSS feeds row contents(title, date, description) depends upon the date in single another UIViewController and for each RSS feed has a separate ViewController. thanks in advance.

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  • Space requirements of a merge-sort

    - by Arkaitz Jimenez
    I'm trying to understand the space requirements for a Mergesort, O(n). I see that time requirements are basically, amount of levels(logn) * merge(n) so that makes (n log n). Now, we are still allocating n per level, in 2 different arrays, left and right. I do understand that the key here is that when the recursive functions return the space gets deallocated, but I'm not seeing it too obvious. Besides, all the info I find, just states space required is O(n) but don't explain it. Any hint? function merge_sort(m) if length(m) = 1 return m var list left, right, result var integer middle = length(m) / 2 for each x in m up to middle add x to left for each x in m after middle add x to right left = merge_sort(left) right = merge_sort(right) result = merge(left, right) return result

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  • Is there anything like memcached, but for sorted lists?

    - by depesz
    I have a situation where I could really benefit from having system like memcached, but with the ability to store (per each key) sorted list of elements, and modifying the list by addition of values. For example: something.add_to_sorted_list( 'topics_list_sorted_by_title', 1234, 'some_title') something.add_to_sorted_list( 'topics_list_sorted_by_title', 5436, 'zzz') something.add_to_sorted_list( 'topics_list_sorted_by_title', 5623, 'aaa') Which I then could use like this: something.get_list_size( 'topics_list_sorted_by_title' ) // returns 3 something.get_list_elements( 'topics_list_sorted_by_title', 1, 10 ) // returns: 5623, 1234, 5436 Required system would allow me to easily get items count in every array, and fetch any number of values from the array, with the assumption that the values are sorted using attached value. I hope that the description is clear. And the question is relatively simple: is there any such system?

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  • Groovy list.sort by first, second then third elements

    - by Ying
    Hi, I have a groovy list of lists i.e. list = [[2, 0, 1], [1, 5, 2], [1, 0, 3]] I would like sort it by order of the first element, then second, then third. Expected assert list == [[1, 0, 3], [1, 5, 2], [2, 0, 1]] I started with list = list.sort{ a,b -> a[0] <=> b[0] } but that only sorts the first element. How do you finish? Thanks

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  • Fastest way to sort files

    - by Werner
    Hi, I have a huge text file with lines like: -568.563626 159 33 -1109.660591 -1231.295129 4.381508 -541.181308 159 28 -1019.279615 -1059.115975 4.632301 -535.370812 155 29 -1033.071786 -1152.907805 4.420473 -533.547101 157 28 -1046.218277 -1063.389677 4.423696 What I want is to sort the file, depending on the 5th column, so I would get -568.563626 159 33 -1109.660591 -1231.295129 4.381508 -535.370812 155 29 -1033.071786 -1152.907805 4.420473 -533.547101 157 28 -1046.218277 -1063.389677 4.423696 -541.181308 159 28 -1019.279615 -1059.115975 4.632301 For this I use: for i in file.txt ; do sort -k5n $i ; done I wonder if this is the fastest or more efficient way Thanks

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  • C# - How to implement multiple comparers for an IComparable<T> class?

    - by Gary Willoughby
    I have a class that implements IComparable. public class MyClass : IComparable<MyClass> { public int CompareTo(MyClass c) { return this.whatever.CompareTo(c.whatever); } etc.. } I then can call the sort method of a generic list of my class List<MyClass> c = new List<MyClass>(); //Add stuff, etc. c.Sort(); and have the list sorted according to my comparer. How do i specify further comparers to sort my collection different ways according to the other properties of MyClass in order to let users sort my collection in a number of different ways?

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  • python how to find the median of a list

    - by user3450574
    I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

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  • An O(1) Sort ~~~

    - by FlySwat
    Before you stone me for being a heretic, There is a sort that proclaims to be O(1), called "Bead Sort" (http://en.wikipedia.org/wiki/Bead_sort) , however that is pure theory, when actually applied I found that it was actually O(N * M), which is pretty pathetic. That said, Lets list out some of the fastest sorts, and their best case and worst case speed in Big O notation. ~~ FlySwat ~~

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  • How to properly sort MPTT hierarchy data into multidimensional array ?

    - by DiegoMax
    Helo there, im trying to figure out how to write a function that returns a multidimensional array, based on the data below: I know how to write the function using the "category_parent" value, but im just trying to write a function that can create a multidimensional array by JUST using the left and right keys. Any help greatly appreciated! array(71) { [0]=> array(9) { ["id"]=> string(1) "1" ["category_name"]=> string(6) "Rubros" ["category_parent"]=> string(1) "0" ["category_slug"]=> string(6) "rubros" ["category_image"]=> NULL ["category_totals"]=> NULL ["category_lft"]=> string(1) "1" ["category_rgt"]=> string(3) "142" } [1]=> array(9) { ["id"]=> string(4) "1000" ["category_name"]=> string(12) "Restaurantes" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(12) "restaurantes" ["category_image"]=> string(16) "restaurantes.png" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "2" ["category_rgt"]=> string(2) "13" } [2]=> array(9) { ["id"]=> string(1) "3" ["category_name"]=> string(21) "Restaurantes de Campo" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(21) "restaurantes-de-campo" ["category_image"]=> NULL ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "3" ["category_rgt"]=> string(1) "4" } [3]=> array(9) { ["id"]=> string(2) "37" ["category_name"]=> string(25) "Restaurantes en la Ciudad" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(19) "restaurantes-ciudad" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "6" ["category_lft"]=> string(1) "5" ["category_rgt"]=> string(1) "6" } [4]=> array(9) { ["id"]=> string(2) "41" ["category_name"]=> string(21) "Servicios de Catering" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(8) "catering" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "7" ["category_rgt"]=> string(1) "8" } [5]=> array(9) { ["id"]=> string(2) "48" ["category_name"]=> string(10) "Rotiserias" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(10) "rotiserias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(1) "9" ["category_rgt"]=> string(2) "10" } [6]=> array(9) { ["id"]=> string(2) "62" ["category_name"]=> string(10) "Pizzerías" ["category_parent"]=> string(4) "1000" ["category_slug"]=> string(9) "pizzerias" ["category_image"]=> string(0) "" ["category_totals"]=> string(1) "1" ["category_lft"]=> string(2) "11" ["category_rgt"]=> string(2) "12" } [7]=> array(9) { ["id"]=> string(1) "2" ["category_name"]=> string(13) "Profesionales" ["category_parent"]=> string(1) "1" ["category_slug"]=> string(13) "profesionales" ["category_image"]=> string(17) "profesionales.png" ["category_totals"]=> string(1) "2" ["category_lft"]=> string(2) "14" ["category_rgt"]=> string(2) "35" } [8]=> array(9) { ["id"]=> string(2) "29" ["category_name"]=> string(11) "Arquitectos" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(11) "arquitectos" ["category_image"]=> NULL ["category_totals"]=> string(1) "0" ["category_lft"]=> string(2) "15" ["category_rgt"]=> string(2) "16" } [9]=> array(9) { ["id"]=> string(2) "30" ["category_name"]=> string(8) "Abogados" ["category_parent"]=> string(1) "2" ["category_slug"]=> string(8) "abogados" ["category_image"]=> NULL ["category_totals"]=> string(1) "6" ["category_lft"]=> string(2) "17" ["category_rgt"]=> string(2) "18" } }

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  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

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  • Best way to Sort-n-Concatenate 5 columns

    - by SDReyes
    Having five columns containing numeric values A | B | C | D | E ------------------- 2 | 3 | 4 | 1 | 5 3 | 6 | 1 | 5 | 4 4 | 5 | 7 | 1 | 3 I want to obtain the concatenation of the values after sort them: ABCDE ----------- 1 2 3 4 5 1 3 4 5 6 1 3 4 5 7 What is the best way to do it?

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  • Sort a list of pointers.

    - by YuppieNetworking
    Hello all, Once again I find myself failing at some really simple task in C++. Sometimes I wish I could de-learn all I know from OO in java, since my problems usually start by thinking like Java. Anyways, I have a std::list<BaseObject*> that I want to sort. Let's say that BaseObject is: class BaseObject { protected: int id; public: BaseObject(int i) : id(i) {}; virtual ~BaseObject() {}; }; I can sort the list of pointer to BaseObject with a comparator struct: struct Comparator { bool operator()(const BaseObject* o1, const BaseObject* o2) const { return o1->id < o2->id; } }; And it would look like this: std::list<BaseObject*> mylist; mylist.push_back(new BaseObject(1)); mylist.push_back(new BaseObject(2)); // ... mylist.sort(Comparator()); // intentionally omitted deletes and exception handling Until here, everything is a-ok. However, I introduced some derived classes: class Child : public BaseObject { protected: int var; public: Child(int id1, int n) : BaseObject(id1), var(n) {}; virtual ~Child() {}; }; class GrandChild : public Child { public: GrandChild(int id1, int n) : Child(id1,n) {}; virtual ~GrandChild() {}; }; So now I would like to sort following the following rules: For any Child object c and BaseObject b, b<c To compare BaseObject objects, use its ids, as before. To compare Child objects, compare its vars. If they are equal, fallback to rule 2. GrandChild objects should fallback to the Child behavior (rule 3). I initially thought that I could probably do some casts in Comparator. However, this casts away constness. Then I thought that probably I could compare typeids, but then everything looked messy and it is not even correct. How could I implement this sort, still using list<BaseObject*>::sort ? Thank you

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  • Change index order in array (php)

    - by Trikks
    Hi Been kind of stuck on this one for a while now, so any help would be appreciated. I have one array (left) that contains a list of elements, the goal is to sort another arrays (right) keys with the values from the left array. The left array Array ( [0] => ID [1] => FirstName [2] => LastName [3] => Address ) The right array Array ( [0] => Array ( [FirstName] => Pim [Address] => Finland [LastName] => Svensson [ID] => 3 ) [1] => Array ( [FirstName] => Emil [Address] => Sweden [LastName] => Malm [ID] => 5 ) ) What I'm trying to accomplish would be similar to this Array ( [0] => Array ( [ID] => 3 [FirstName] => Pim [LastName] => Svensson [Address] => Finland ) Anyone? :) Oh, I'm running php 5.3, if it helps!

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  • std::ifstream buffer caching

    - by ledokol
    Hello everybody, In my application I'm trying to merge sorted files (keeping them sorted of course), so I have to iterate through each element in both files to write the minimal to the third one. This works pretty much slow on big files, as far as I don't see any other choice (the iteration has to be done) I'm trying to optimize file loading. I can use some amount of RAM, which I can use for buffering. I mean instead of reading 4 bytes from both files every time I can read once something like 100Mb and work with that buffer after that, until there will be no element in buffer, then I'll refill the buffer again. But I guess ifstream is already doing that, will it give me more performance and is there any reason? If fstream does, maybe I can change size of that buffer? added My current code looks like that (pseudocode) // this is done in loop int i1 = input1.read_integer(); int i2 = input2.read_integer(); if (!input1.eof() && !input2.eof()) { if (i1 < i2) { output.write(i1); input2.seek_back(sizeof(int)); } else input1.seek_back(sizeof(int)); output.write(i2); } } else { if (input1.eof()) output.write(i2); else if (input2.eof()) output.write(i1); } What I don't like here is seek_back - I have to seek back to previous position as there is no way to peek 4 bytes too much reading from file if one of the streams is in EOF it still continues to check that stream instead of putting contents of another stream directly to output, but this is not a big issue, because chunk sizes are almost always equal. Can you suggest improvement for that? Thanks.

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  • Javascript: sort objects

    - by tom
    function Player() { var score; this.getScore = function() { return score; } this.setScore = function(sc) { score = sc; } } function compare(playerA, playerB) { return playerA.getScore() - playerB.getScore(); } var players = []; players['player1'] = new Player(); players['player2'] = new Player(); Array(players).sort(compare); I have code that is similar to the above. When I step through the code with a debugger, the compare function never gets called and the array isn't sorted. I'm not sure what's wrong with my code?

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  • T-SQL: how to sort table rows based on 2 columns

    - by Criss Nautilus
    I'm quite stuck with this problem for sometime now.. How do I sort column A depending on the contents of Column B? I have this sample: ID count columnA ColumnB 12 1 A B 13 2 C D 14 3 B C I want to sort it like this: ID count ColumnA ColumnB 12 1 A B 14 3 B C 13 2 C D so I need to sort the rows if the previous row of ColumnB = the next row of ColumnA I'm thinking a loop? but can't quite imagine how it will work... I was thinking it will go like this (maybe) SELECT a.ID, a.ColumnA, a.ColumnB FROM TableA WITH a (NOLOCK) LEFT JOIN TableA b WITH (NOLOCK) ON a.ID = b.ID and a.counts = b.counts Where a.columnB = b.ColumnA the above code isn't working though and I was thinking more on the lines of... DECLARE @counts int = 1 DECLARE @done int = 0 --WHILE @done = 0 BEGIN SELECT a.ID, a.ColumnA, a.ColumnB FROM TableA WITH a (NOLOCK) LEFT JOIN TableA b WITH (NOLOCK) ON a.ID = b.ID and a.counts = @counts Where a.columnB = b.ColumnA set @count = @count +1 END If this was a C code, would be easier for me but t-sql's syntax is making it a bit harder for a noobie like me.

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  • Building a linked list with LINQ

    - by FreshCode
    What is the fastest way to order an unordered list of elements by predecessor (or parent) element index using LINQ? Each element has a unique ID and the ID of that element's predecessor (or parent) element, from which a linked list can be built to represent an ordered state. Example ID | Predecessor's ID --------|-------------------- 20 | 81 81 | NULL 65 | 12 12 | 20 120 | 65 The sorted order is {81, 20, 12, 65, 120}. An (ordered) linked list can easily be assembled iteratively from these elements, but can it be done in fewer LINQ statements? Edit: I should have specified that IDs are not necessarily sequential. I chose 1 to 5 for simplicity. See updated element indices which are random.

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  • php sort properties of object

    - by lannoo
    I want to sort the properties of an object so I can loop through them in a defined order. for example: I have an object 'book' with the following properties: 'id', 'title', 'author', 'date'. Now i want to loop through these properties like this: foreach($book as $prop=>$val) //do something now the order of the loop has to be 'title', then 'author', 'date' and 'id' How would one do this? (I can't change the order of the properties in the class of the object because there arent any properties defined there, I get the object from the database with 'MyActiveRecord')

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  • How to iterate through an XDocument's Nodes

    - by Ed R
    I am trying to iterate through my xml document's nodes to get the value for <username>Ed</username> in each node. I am using Linq to sort the XDocument first, then attempting to loop through the nodes. I can't seem to find the correct foreach loop to achieve this. Any help is appreciated. var doc = XDocument.Load("files\\config.xml"); var newDoc = new XDocument(new XElement("Config", from p in doc.Element("Config").Elements("Profile") orderby int.Parse(p.Element("order").Value) select p)); foreach (XElement xe in newDoc.Nodes()) { MessageBox.Show(xe.Element("username").Value); }

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  • What does P mean in Sort(Expression<Func<T, P>> expr, ListSortDirection direction)?

    - by Grasshopper
    I am attempting to use the answer in post: How do you sort an EntitySet<T> to expose an interface so that I can sort an EntitySet with a Binding list. I have created the class below and I get the following compiler error: "The type or namespace 'P' could not be found (are you missing a using directive or assembly reference?). Can someone tell me what the P means and which namespace I need to include to get the method below to compile? I am very new to delegates and lamba expressions. Also, can someone confirm that if I create a BindingList from my EntitySet that any modifications I make to the BindingList will be made to the EntitySet? Basically, I have an EntitySet that I need to sort and make changes to. Then, I will need to persist these changes using the original Entity that the BindingList came from. public class EntitySetBindingWrapper<T> : BindingList<T> { public EntitySetBindingWrapper(BindingList<T> root) : base(root) { } public void Sort(Expression<Func<T, P>> expr, ListSortDirection direction) { if (expr == null) base.RemoveSortCore(); MemberExpression propExpr = expr as MemberExpression; if (propExpr == null) throw new ArgumentException("You must provide a property", "expr"); PropertyDescriptorCollection descriptorCol = TypeDescriptor.GetProperties(typeof(T)); IEnumerable<PropertyDescriptor> descriptors = descriptorCol.Cast<PropertyDescriptor>(); PropertyDescriptor descriptor = descriptors.First(pd => pd.Name == propExpr.Member.Name); base.ApplySortCore(descriptor, direction); } }

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  • How can I sort an array, yet exclude certain elements (to be kept at the same position in the array)

    - by calumbrodie
    This will be implemented in Javascript (jQuery) but I suppose the method could be used in any language. I have an array of items and I need to perform a sort. However there are some items in the array that have to be kept in the same position (same index). The array in question is build from a list of <li> elements and I'm using .data() values attached to the list item as the value on which to sort. What approach would be best here? <ul id="fruit"> <li class="stay">bananas</li> <li>oranges</li> <li>pears</li> <li>apples</li> <li class="stay">grapes</li> <li>pineapples</li> </ul> <script type="text/javascript"> var sugarcontent = new Array('32','21','11','45','8','99'); $('#fruit li').each(function(i,e){ $(this).data(sugarcontent[i]); }) </script> I want the list sorted with the following result... <ul id="fruit"> <li class="stay">bananas</li> <!-- score = 32 --> <li>pineapples</li> <!-- score = 99 --> <li>apples</li> <!-- score = 45 --> <li>oranges</li> <!-- score = 21 --> <li class="stay">grapes</li> <!-- score = 8 --> <li>pears</li> <!-- score = 11 --> </ul> Thanks!

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