Search Results

Search found 4842 results on 194 pages for 'computation expression'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 60/194 | < Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >

  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

    Read the article

  • How do I use a Lambda expression to sort INTEGERS inside a object?

    - by punkouter
    I have a collection of objects and I know that I can sort by NAME (string type) by saying collEquipment.Sort((x, y) = string.Compare(x.ItemName, y.ItemName)); that WORKS. But I want to sort by a ID (integer type) and there is no such thing as Int32.Compare So how do I do this? This doesnt work collEquipment.Sort((x, y) = (x.ID < y.ID); //error I know the answer is going to be really simple. Lambda expressions confuse me.

    Read the article

  • Should I use ICommand or Expression.Interactions InvokeCommand for MVVM in Silverlight 4?

    - by phejndorf
    I'm about to embark on a new project in Silverlight 4, and definitely want to take advantage of the MVVM pattern, now I've finally grasped the basics. For implementing commands in Silverlight 4 it seems there are rather a lot of options ranging from the new built-in Command/ICommand option on the Button, over the InvokeCommand defined in the Microsoft.Expressions.Interactivity namespace and on to the range of assisting MVVM frameworks (Prism, MVVMlight etc). Does anyone here have gotcha's, experience and wisdom to share on this subject?

    Read the article

  • Does having a longer string in a SQL Like expression allow hinder or help query executing speed?

    - by Allain Lalonde
    I have a db query that'll cause a full table scan using a like clause and came upon a question I was curious about... Which of the following should run faster in Mysql or would they both run at the same speed? Benchmarking might answer it in my case, but I'd like to know the why of the answer. The column being filtered contains a couple thousand characters if that's important. SELECT * FROM users WHERE data LIKE '%=12345%' or SELECT * FROM users WHERE data LIKE '%proileId=12345%' I can come up for reasons why each of these might out perform the other, but I'm curious to know the logic.

    Read the article

  • Why are these strings escaping from my regular expression in python?

    - by dohkoxar
    In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

    Read the article

  • Matching Line Boundaries in a Regular Expression (Pattern.MULTILINE/(?m)) is broken in Java?

    - by Mister M. Bean
    The example on http://www.exampledepot.com/egs/java.util.regex/Line.html gives false for me twice but should'nt! Why? CharSequence inputStr = "abc\ndef"; String patternStr = "abc$"; // Compile with multiline enabled Pattern pattern = Pattern.compile(patternStr, Pattern.MULTILINE); Matcher matcher = pattern.matcher(inputStr); boolean matchFound = matcher.find(); // true // Use an inline modifier to enable multiline mode matchFound = pattern.matches(".*abc$.*", "abc\r\ndef"); // false System.out.println(matchFound); // false matchFound = pattern.matches("(?m).*abc$.*", "abc\r\ndef"); // true System.out.println(matchFound);// false !!!!!

    Read the article

  • Best way to check for nullable bool in a condition expression (if ...)

    - by FireSnake
    I was wondering what was the most clean and understandable syntax for doing condition checks on nullable bools. Is the following good or bad coding style? Is there a way to express the condition better/more cleanly? bool? nullableBool = true; if (nullableBool ?? false) { ... } else { ... } especially the if (nullableBool ?? false) part. I don't like the if (x.HasValue && x.Value) style ... (not sure whether the question has been asked before ... couldn't find something similar with the search)

    Read the article

  • How to Get the F# Name of a Module, Function, etc. From Quoted Expression Match

    - by Stephen Swensen
    I continue to work on a printer for F# quoted expressions, it doesn't have to be perfect, but I'd like to see what is possible. The active patterns in Microsoft.FSharp.Quotations.Patterns and Microsoft.FSharp.Quotations.DerivedPatterns used for decomposing quoted expressions will typically provide MemberInfo instances when appropriate, these can be used to obtain the name of a property, function, etc. and their "declaring" type, such as a module or static class. The problem is, I only know how to obtain the CompiledName from these instances but I'd like the F# name. For example, > <@ List.mapi (fun i j -> i+j) [1;2;3] @> |> (function Call(_,mi,_) -> mi.DeclaringType.Name, mi.Name);; val it : string * string = ("ListModule", "MapIndexed") How can this match be rewritten to return ("List", "mapi")? Is it possible?

    Read the article

  • How do I change text color on the selected row inside a ListView/GridView? (using Expression Dark th

    - by Thiado de Arruda
    I'm using theExpression Dark WPF Theme(http://wpfthemes.codeplex.com/) with a ListView(view property set to a GridView) to display some user data like the following : <ListView Grid.Row="1" ItemsSource="{Binding RegisteredUsers}" SelectedItem="{Binding SelectedUser}" > <ListView.View> <GridView> <GridViewColumn Header="Login" DisplayMemberBinding="{Binding Login}" Width="60"/> <GridViewColumn Header="Full Name" DisplayMemberBinding="{Binding FullName}" Width="180"/> <GridViewColumn Header="Last logon" DisplayMemberBinding="{Binding LastLogon}" Width="120"/> <GridViewColumn Header="Photo" Width="50"> <GridViewColumn.CellTemplate> <DataTemplate> <Image Source="{Binding Photo}" Width="30" Height="35"/> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> </GridView> </ListView.View> </ListView> The rows have white text with a dark background and white background when selected, however the text color doesnt change when selected and it makes very difficult to read, I would like the text to have a dark color when the row is selected. I have searched for a way to style the text color but with no success, here is the control template for the ListViewItem : <Border SnapsToDevicePixels="true" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" CornerRadius="2" x:Name="border"> <Grid Margin="2,0,2,0"> <Rectangle x:Name="Background" IsHitTestVisible="False" Opacity="0.25" Fill="{StaticResource NormalBrush}" RadiusX="1" RadiusY="1"/> <Rectangle x:Name="HoverRectangle" IsHitTestVisible="False" Opacity="0" Fill="{StaticResource NormalBrush}" RadiusX="1" RadiusY="1"/> <Rectangle x:Name="SelectedRectangle" IsHitTestVisible="False" Opacity="0" Fill="{StaticResource SelectedBackgroundBrush}" RadiusX="1" RadiusY="1"/> <GridViewRowPresenter SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" Margin="0,2,0,2" VerticalAlignment="Stretch" /> </Grid> </Border> The trigger that changes the background color simply applies an animation to change the 'SelectedRectangle' opacity, but I cant change the text color on the same trigger(I tried using a setter for the foreground color on the ListViewItem, but with no success). Does someone have a clue on that?

    Read the article

  • Whats the difference between \z and \Z in a regular expression and when and how do I use it?

    - by Mister M. Bean
    From http://java.sun.com/j2se/1.5.0/docs/api/java/util/regex/Pattern.html: \Z The end of the input but for the final terminator, if any \z The end of the input But what does it mean in practice? Can you give me an example when I use either the \Z or \z. In my test I thought that "StackOverflow\n".matches("StackOverflow\\z") will return true and "StackOverflow\n".matches("StackOverflow\\Z") returns false. But actually both return false. Where is the mistake?

    Read the article

  • Construction an logical expression which will count bits in a byte.

    - by danatel
    When interviewing new candidates, we usually ask them to write a piece of C code to count the number of bits with value 1 in a given byte variable (e.g. the byte 3 has two 1-bits). I know all the common answers, such as right shifting eight times, or indexing constant table of 256 precomputed results. But, is there a smarter way without using the precomputed table? What is the shortest combination of byte operations (AND, OR, XOR, +, -, binary negation, left and right shift) which computes the number of bites?

    Read the article

  • How do I insert format str and don't remove the matched regular expression in input string in boost:

    - by Yadollah
    I want to put space between punctuations and other words in a sentence. But boost::regex_replace() replaces the punctuation with space, and I want to keep a punctuation in the sentence! for example in this code the output should be "Hello . hi , " regex e1("[.,]"); std::basic_string<char> str = "Hello.hi,"; std::basic_string<char> fmt = " "; cout<<regex_replace(str, e1, fmt)<<endl; Can you help me?

    Read the article

  • Find all possible starting positions of a regular expression match in perl, including overlapping matches?

    - by jonderry
    Is there a way to find all possible start positions for a regex match in perl? For example, if your regex was "aa" and the text was "aaaa", it would return 0, 1, and 2, instead of, say 0 and 2. Obviously, you could just do something like return the first match, and then delete all characters up to and including that starting character, and perform another search, but I'm hoping for something more efficient.

    Read the article

  • Regular expression to match non-negative integers in PHP?

    - by kavoir.com
    I seem to get it to work with the following regexp by preg_match(): @^(?:[1-9][0-9]*)|0$@ Yet it's weird that it matches '-0', considering there are no '-' allowed at all in the regexp. Why? What's more weird is that if you switch the parts divided by |: @^0|(?:[1-9][0-9]*)$@ It matches all negative integers such as '-2' and '-10', etc. What am I missing here? Any better regexp for non-negative integer?

    Read the article

  • Is there a more concise regular expression to accomplish this task?

    - by mpminnich
    First off, sorry for the lame title, but I couldn't think of a better one. I need to test a password to ensure the following: Passwords must contain at least 3 of the following: upper case letters lower case letters numbers special characters Here's what I've come up with (it works, but I'm wondering if there is a better way to do this): Dim lowerCase As New Regex("[a-z]") Dim upperCase As New Regex("[A-Z]") Dim numbers As New Regex("\d") Dim special As New Regex("[\\\.\+\*\?\^\$\[\]\(\)\|\{\}\/\'\#]") Dim count As Int16 = 0 If Not lowerCase.IsMatch(txtUpdatepass.Text) Then count += 1 End If If Not upperCase.IsMatch(txtUpdatepass.Text) Then count += 1 End If If Not numbers.IsMatch(txtUpdatepass.Text) Then count += 1 End If If Not special.IsMatch(txtUpdatepass.Text) Then count += 1 End If If at least 3 of the criteria have not been met, I handle it. I'm not well versed in regular expressions and have been reading numerous tutorials on the web. Is there a way to combine all 4 regexes into one? But I guess doing that would not allow me to check if at least 3 of the criteria are met. On a side note, is there a site that has an exhaustive list of all characters that would need to be escaped in the regex (those that have special meaning - eg. $, ^, etc.)? As always, TIA. I can't express enough how awesome I think this site is.

    Read the article

  • why can't I call methods on a for-yield expression?

    - by 1984isnotamanual
    Say I have some scala code like this: // outputs 1, 4, 9, 16, 25, 36, 49, 64, 81, 100 println( squares ) def squares = { val s = for ( count <- 1 to 10 ) yield { count * count } s.mkString(", "); } Why do I have to use the temporary val s? I tried this: def squares = for ( count <- 1 to 10 ) yield { count * count }.mkString(", ") That fails to compile with this error message: error: value mkString is not a member of Int def squares = for ( count <- 1 to 10 ) yield { count * count }.mkString(", ") Shouldn't mkString be called on the collection returned by the for loop?

    Read the article

  • Regular expression to match text that doesn't start with substring?

    - by Steven
    I have text with file names scattered throughout. The filenames appear in the text like this: |test.txt| |usr01.txt| |usr02.txt| |foo.txt| I want to match the filenames that don't start with usr. I came up with (?<=\|).*\.txt(?=\|) to match the filenames, but it doesn't exclude the ones starting with usr. Is this possible with regular expressions?

    Read the article

  • Annoyed by the expression "Moving Forward". Why do people use it? [closed]

    - by craig
    What does “Moving Forward” mean to you? “Moving Forward”: A.To acknowledge the past but in essence, encourage a positive, professional environment to do our personal best in relation to issue that was criticized. B.To acknowledge the past and learn from case examples to develop continually updated and open sources of information. Specifically, policies and procedures or best practices. C.To dismiss the past to put behind fears of retribution. D.Combination of above choices E._____< Open Answer

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 56 57 58 59 60 61 62 63 64 65 66 67  | Next Page >