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  • Touchpad and Keyboard both stop working after long uptime

    - by Sepero
    I have an Asus N53SM laptop that I leave running for several weeks at a time. I never put it in hibernate or suspend, I only close the lid when I'm not using it. After a few days or weeks of running, the touchpad and keyboard will Both lock up (at the same time) for no apparent reason. I could be just surfing the internet when it happens. The touchpad and keyboard seem to only lock up when I'm actively using the laptop (not when idle), which may mean it's related to something I press, but I'm not sure? The touchpad never locks or unlocks when Pressing FN and the designated touchpad lock key (it does not seem to work on Linux). While the touchpad and keyboard are locked, I am able to plug in my USB mouse and successfully use it to control the screen cursor. I can also remotely get into the system with vnc and ssh, everything seems to run fine there as well. No processes appear out of control. It's just the laptops physical touchpad and keyboard that are locking up. How might I go about diagnosing this problem? What system logs to look at? (anything specific to look for in them?) Perhaps I should try reloading some modules? Any thing else I should inspect?

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  • How to work around the home directory changing to /root when using sudo?

    - by Nathanel Titane
    Hello everybody! With Natty coming out soon, I've been at work updating my deployment and self-config script to make my desktop on 11.04 run and look the way I want it to. One bummer is that dbus seems to have changed and does not permit, in the same manner Lucid and Maverick did, the authentication of the current user by terminal call using grep and cat. Ideally, to run the script, I would sudo -s and then launch it as # chmod +x install && ./install Instead of returning my user name.. it now returns root and applies changes to the root profile and aborts whenever paths do not correspond. Here is my script header: #!/bin/bash ON_USER=$(echo ~ | awk -F'/' '{ print $1 $2 $3 }' | sed 's/home//g') export $(grep -v "^#" ~/.dbus/session-bus/`cat /var/lib/dbus/machine-id`-0) if sudo -u $ON_USER test -z "$DBUS_SESSION_BUS_ADDRESS" ; then eval `sudo -u $ON_USER dbus-launch --sh-syntax --exit-with-session` fi RELEASE=$(lsb_release -cs) How could I make it return the actual user now that natty is coming? Thanks for the help

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  • Prevent one user from disconnecting an active remote desktop session

    - by Nick R
    I've got a server where a number of users are sharing user logins for a short period of time to prevent too many people from logging in at the same time. The users are connecting over remote desktop, but the problem is that when one user is busy doing something, another user logs in as the same user and disconnects the active session. Is there any way of preventing one user from logging in and disconnecting the same username who is already connected to somewhere else?

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  • Key Handling mechanics

    - by Max
    I am new to game development and am working on my first game using OpenGL and C++. I have a game class which handles everything necessary in an update() function. Now i want to handle keyboard inputs. I use GLFW which supports key callbacks. However i wonder how to deal with inputs. Should i record the keys pressed and poll on it the next time my game updates or should the callback immediately perform the necessary actions? And why? Thanks :)

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  • Intuitive "Take Screenshot" key mapping used by games?

    - by Hatoru Hansou
    I recently had a problem testing my game on Linux Ubuntu. The Print key is intercepted by the desktop environment and It never reaches the game. Rather than fighting this, I will simply use any other key or key combination to trigger the screen capture functionality. Now, using the PRINT key is very intuitive because people already expect this behavior. What other keys are a good idea to use to take screenshots? And if possible elaborate why, have other apps/games used that key?

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  • LWJGL: Camera distance from image plane?

    - by Rogem
    Let me paste some code before I ask the question... public static void createWindow(int[] args) { try { Display.setFullscreen(false); DisplayMode d[] = Display.getAvailableDisplayModes(); for (int i = 0; i < d.length; i++) { if (d[i].getWidth() == args[0] && d[i].getHeight() == args[1] && d[i].getBitsPerPixel() == 32) { displayMode = d[i]; break; } } Display.setDisplayMode(displayMode); Display.create(); } catch (Exception e) { e.printStackTrace(); System.exit(0); } } public static void initGL() { GL11.glEnable(GL11.GL_TEXTURE_2D); GL11.glShadeModel(GL11.GL_SMOOTH); GL11.glClearColor(0.0f, 0.0f, 0.0f, 0.0f); GL11.glClearDepth(1.0); GL11.glEnable(GL11.GL_DEPTH_TEST); GL11.glDepthFunc(GL11.GL_LEQUAL); GL11.glMatrixMode(GL11.GL_PROJECTION); GL11.glLoadIdentity(); GLU.gluPerspective(45.0f, (float) displayMode.getWidth() / (float) displayMode.getHeight(), 0.1f, 100.0f); GL11.glMatrixMode(GL11.GL_MODELVIEW); GL11.glHint(GL11.GL_PERSPECTIVE_CORRECTION_HINT, GL11.GL_NICEST); } So, with the camera and screen setup out of the way, I can now ask the actual question: How do I know what the camera distance is from the image plane? I also would like to know what the angle between the image plane's center normal and a line drawn from the middle of one of the edges to the camera position is. This will be used to consequently draw a vector from the camera's position through the player's click-coordinates to determine the world coordinates they clicked (or could've clicked). Also, when I set the camera coordinates, do I set the coordinates of the camera or do I set the coordinates of the image plane? Thank you for your help. EDIT: So, I managed to solve how to calculate the distance of the camera... Here's the relevant code... private static float getScreenFOV(int dim) { if (dim == 0) { float dist = (float) Math.tan((Math.PI / 2 - Math.toRadians(FOV_Y))/2) * 0.5f; float FOV_X = 2 * (float) Math.atan(getScreenRatio() * 0.5f / dist); return FOV_X; } else if (dim == 1) { return FOV_Y; } return 0; } FOV_Y is the Field of View that one defines in gluPerspective (float fovy in javadoc). This seems to be (and would logically be) for the height of the screen. Now I just need to figure out how to calculate that vector.

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  • GWT - occasional com.google.gwt.user.client.rpc.SerializationException

    - by user214984
    Hello we are haunted by occasional occurences of exceptions such as: com.google.gwt.user.client.rpc.SerializationException: Type 'xxx' was not assignable to 'com.google.gwt.user.client.rpc.IsSerializable' and did not have a custom field serializer.For security purposes, this type will not be serialized.: instance = xxx at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serialize(ServerSerializationStreamWriter.java:610) at com.google.gwt.user.client.rpc.impl.AbstractSerializationStreamWriter.writeObject(AbstractSerializationStreamWriter.java:129) at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter$ValueWriter$8.write(ServerSerializationStreamWriter.java:152) at com.google.gwt.user.server.rpc.impl.ServerSerializationStreamWriter.serializeValue(ServerSerializationStreamWriter.java:534) at com.google.gwt.user.server.rpc.RPC.encodeResponse(RPC.java:609) at com.google.gwt.user.server.rpc.RPC.encodeResponseForSuccess(RPC.java:467) at com.google.gwt.user.server.rpc.RPC.invokeAndEncodeResponse(RPC.java:564) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processCall(RemoteServiceServlet.java:188) at de.softconex.travicemanager.server.TraviceManagerServiceImpl.processCall(TraviceManagerServiceImpl.java:615) at com.google.gwt.user.server.rpc.RemoteServiceServlet.processPost(RemoteServiceServlet.java:224) at com.google.gwt.user.server.rpc.AbstractRemoteServiceServlet.doPost(AbstractRemoteServiceServlet.java:62) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.jboss.web.tomcat.filters.ReplyHeaderFilter.doFilter(ReplyHeaderFilter.java:96) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:230) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:175) at org.jboss.web.tomcat.security.SecurityAssociationValve.invoke(SecurityAssociationValve.java:179) at org.jboss.web.tomcat.security.JaccContextValve.invoke(JaccContextValve.java:84) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.jboss.web.tomcat.service.jca.CachedConnectionValve.invoke(CachedConnectionValve.java:157) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:262) at org.apache.coyote.ajp.AjpAprProcessor.process(AjpAprProcessor.java:419) at org.apache.coyote.ajp.AjpAprProtocol$AjpConnectionHandler.process(AjpAprProtocol.java:378) at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1508) at java.lang.Thread.run(Thread.java:619) The application is normally running fine. The indicated class implements Serializable (the whole object graph). So far the only patterns / observations are: we seem to have the issue only when the application is used inside an iframe the problem seems to happen when a new version of the application has been deployed running firefox in privacy mode (disabling all caches etc.) doesn't fix the problem Any ideas? Holger

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  • Sharepoint user details not visible to other users

    - by richardoz
    I am managing a SharePoint site that uses Form Based Authentication. We have several generic lists, document libraries and active task lists that users can create update and delete. Users can use the people pickers to select/search for everyone. But the users cannot see other users names, email addresses etc. in display lists or the people pickers. If I log in as the site collection administrator, I can see everyones details. So I know the data is available. Updated details on this problem (non-administrators) SharePoint users cannot see other users information. Example: User A assigns a task to user B. User A creates a new task and uses the people picker to find user B. User B is only visible by the login name “bname” and any information about user B is not visible or searchable within the people picker. Once user B is assigned the task, user A no longer sees the name in the task list – even though user A created it. No modified by, created by, assigned to or owner field data is visible to non-administrator users. Facts: Extranet site is configured to use Forms Based Authentication. Intranet uses windows based authentication Users of both the intranet and extranet have the same problem All databases are local The site uses SSRS integration SharePoint WSS on Windows 2003 Std -- After activating the verbose logging it looks like SharePoint is definately asking SQL server for only the user info for the currently logged in user: SELECT TOP 6 /lots-of-columns/ FROM UserData INNER MERGE JOIN Docs AS t1 ON ( 1 = 1 AND UserData.[tp_RowOrdinal] = 0 AND t1.SiteId = UserData.tp_SiteId AND t1.SiteId = @L2 AND t1.DirName = UserData.tp_DirName AND t1.LeafName = UserData.tp_LeafName AND t1.Level = UserData.tp_Level AND t1.IsCurrentVersion = 1 AND (1 = 1) ) LEFT OUTER JOIN AllUserData AS t2 ON ( UserData.[tp_Author]=t2.[tp_ID] AND UserData.[tp_RowOrdinal] = 0 AND t2.[tp_RowOrdinal] = 0 AND ( (t2.tp_IsCurrent = 1) ) AND t2.[tp_CalculatedVersion] = 0 AND t2.[tp_DeleteTransactionId] = 0x AND t2.tp_ListId = @L3 AND UserData.tp_ListId = @L4 AND t2.[tp_Author]=162 /* this is the currently logged in user */ ) WHERE (UserData.tp_IsCurrent = 1) AND UserData.tp_SiteId=@L2 AND (UserData.tp_DirName=@DN) AND UserData.tp_RowOrdinal=0 AND ( ( (UserData.[datetime1] IS NULL ) OR (UserData.[datetime1] = @L5DTP) ) AND t1.SiteId=@L2 AND (t1.DirName=@DN) ) ORDER BY UserData.[tp_Modified] Desc, UserData.[tp_ID] Asc Again, any ideas would be appreciated.

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  • SQL problem - select accross multiple tables (user groups)

    - by morpheous
    I have a db schema which looks something like this: create table user (id int, name varchar(32)); create table group (id int, name varchar(32)); create table group_member (foobar_id int, user_id int, flag int); I want to write a query that allows me to so the following: Given a valid user id (UID), fetch the ids of all users that are in the same group as the specified user id (UID) AND have group_member.flag=3. Rather than just have the SQL. I want to learn how to think like a Db programmer. As a coder, SQL is my weakest link (since I am far more comfortable with imperative languages than declarative ones) - but I want to change that. Anyway here are the steps I have identified as necessary to break down the task. I would be grateful if some SQL guru can demonstrate the simple SQL statements - i.e. atomic SQL statements, one for each of the identified subtasks below, and then finally, how I can combine those statements to make the ONE statement that implements the required functionality. Here goes (assume specified user_id [UID] = 1): //Subtask #1. Fetch list of all groups of which I am a member Select group.id from user inner join group_member where user.id=group_member.user_id and user.id=1 //Subtask #2 Fetch a list of all members who are members of the groups I am a member of (i.e. groups in subtask #1) Not sure about this ... select user.id from user, group_member gm1, group_member gm2, ... [Stuck] //Subtask #3 Get list of users that satisfy criteria group_member.flag=3 Select user.id from user inner join group_member where user.id=group_member.user_id and user.id=1 and group_member.flag=3 Once I have the SQL for subtask2, I'd then like to see how the complete SQL statement is built from these subtasks (you dont have to use the SQL in the subtask, it just a way of explaining the steps involved - also, my SQL may be incorrect/inefficient, if so, please feel free to correct it, and point out what was wrong with it). Thanks

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  • antlr3StringStreamNew string input error [ at offset 0, at <EOF> : cannot match to any predicted input... ]

    - by Embeguru
    I'm using ANTLR 3.4 with simplecTreeParser example and want to give string input from main.c I'v modified input in main as mentioned bellow pANTLR3_UINT8 input_string = (pANTLR3_UINT8)"int a;"; input = antlr3StringStreamNew(input_string, ANTLR3_ENC_8BIT, sizeof(input_string),(pANTLR3_UINT8)"ABCD"); Apparently getting following error -end of input-(1) : error 3 : 23:1: declaration : ( variable | functionHeader ';' - ^( FUNC_DECL functionHeader ) | functionHeader block - ^( FUNC_DEF functionHeader block ) );, at offset 0, at : cannot match to any predicted input... The parser returned 1 errors, tree walking aborted. Any other way to give String input Regards

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  • Input system reference trouble

    - by Ockonal
    Hello, I'm using SFML for input system in my application. size_t WindowHandle; WindowHandle = ...; // Here I get the handler sf::Window InputWindow(WindowHandle); const sf::Input *InputHandle = &InputWindow.GetInput(); // [x] Error At the last lines I have to get reference for the input system. Here is declaration of GetInput from documentation: const Input & sf::Window::GetInput () const The problem is: >invalid conversion from ‘const sf::Input*’ to ‘sf::Input*’ What's wrong?

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  • input file cannot be found

    - by Eric Smith
    I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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  • ASP.Net: User control with content area, it's clearly possible but I need some details.

    - by bert
    I have seen two suggestions for my original question about whether it is possible to define a content area inside a user control and there are some helpful suggestions i.e. http://stackoverflow.com/questions/1971498/passing-in-content-to-asp-net-user-control and http://stackoverflow.com/questions/1912283/asp-net-user-control-inner-content Now, I like the theory of the latter better than the former just for aesthetic reasons. It seems to make more sense to me but the example given uses two variables content and templateContent that the answerer has not defined in their example code. Without these details I have found that the example does not work. I guess they are properties of the control? Or some such? The former example seems workable but I'd prefer to go with the latter if someone could fill in the blanks for me. Thanks.

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  • Font-awesome, input type 'submit'

    - by denis.peplin
    It seems no class for input type 'submit' in font-awesome. Is it possible to use some class from font-awesome for button input? I've added icons to all buttons (which actually links with class 'btn' from twitter-bootstrap) in my applications, but can't add icons on 'input type submit'. Or, how to use this code: input#image-button{ background: #ccc url('icon.png') no-repeat top left; padding-left: 16px; height: 16px; } html: <input type="submit" id="image-button">Text</input> (which I took from HTML: How to make a submit button with text + image in it?) with font-awesome?

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  • Where should I store user config data? Specificaly the path to the data file?

    - by jamone
    I have an app using a SQLite db, and I need the ability for the user to move the data file and point the app to where it moved to. I used the Entity Framework to create the model, and by default it puts the connection string in the App.Config file. From what I've read if I make changes to the connection string there then they won't take effect until the app is restarted. That seems a bit clunky for my use. I see how I can init my model and pass in a custom string but I'm unsure what the best practice is in where to store basic user prefrences such as this? Ini, Registry, somewhere else? I don't want the user to have to "Open" the file each time, just when it relocates and then the app will try to auto open from then on.

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  • Supersede users need to press enter after inputting a string in python 3.0

    - by Cimex
    I've been attempting to create a simple Rock, Paper, Scissors game in python 3.0 -- very standard task for anybody learning programming. But, as I finish up to a point, I think,"wow, that'd be awesome", or,"it'd be cool to do this!" So anyways, I keep building upon the project... I've developed a menu, a single player game vs the computer, and just finished the multiplayer game. But, I've realized, that the multiplayer game isn't very effective. It just dosen't work like the analog version of the game. Currently, it'll ask for player1's input, then player2's input, compare them, and spit out the result and the current score. What I'd rather have happen is that the program asks for both players input at the same time and both players input their choice at the same time. I understand that I can easily do that by just grabbing the index of the first and second answer and compare the 2 inputs -- easy. But what I'd rather have happen is that after both players enter their one character answers at the same time (r for rock, p for paper, or s for scissors), then the program will auto enter the input. Not needing someone to press enter. The input would be dictated by the fact that 2 characters have been entered. I guess my question is: Is there any way to dictate what can be used as an input for 'enter'?

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  • HTML javascript form submitted when image input button

    - by DreamU
    I have a form that contains this single input field, which is nothing more than a button to Print the current web page: <div align="center"> <input type="image" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> After the printing, the page re-submits itself (to itself). Why does it do this and can I stop it? If I just change the type to "input", this code does not re-submit itself after printing: <div align="center"> <input type="input" src="../Images/print.jpg" value="Print" onclick="printpage();" /></div> </div> Unfortunately, our style conventions require me to use that button image rather than the standard input button.

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  • Use JQuery to check a checkbox in a parent list-item?

    - by Daniel O'Connor
    Hey Everyone, I'm brand new to Javascript and JQuery, so I've been reading up on it and am trying to check (and set inactive) a checkbox in a parent list-item when one of the children are checked. If this doesn't make any sense, take a look at the list structure. <ul> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 1</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 2 <ul> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 1</li> <li><input type="checkbox" name="items[]" value="21312341" id="21312341" /> Child 2</li> </ul> </li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 3</li> <li><input type="checkbox" name="items[]" value="88712003" id="88712003" /> Parent 4</li> </ul> If Child 1 or Child 2 is checked, I want the input in Parent 2 to be checked and set inactive. I've started working on it, but got stuck here: $(function(){ $('.child').click(function() { $(this).parent().parent().parent().toggle(); }); }); As you can see, I didn't make it far. Any help would be appreciated. Thanks!

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  • identify the input that is multiple of 11 and odd or even java

    - by Bolor Ch
    i am trying to write code to determine the nature of input using if statement only. The nature of input could be following: a multiple of 11 even or odd. For the code below, when I enter my input, it does not display the result as "input:NOT:ODD". Also how can I check multiple conditions with if statement? (else is not considered) import java.util.Scanner; public class test { public static void main( String args[] ) { Scanner input = new Scanner( System.in ); int x; int EO; int Mult; System.out.print ( "Enter value: " ); x = input.nextInt(); EO = x % 2; Mult = x % 11; if (EO > 0 && Mult > 0) { System.out.printf ("%d:NOT:ODD"); } } }

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  • Limit user in sql plus to a single record in a table.

    - by BFK
    I have one employee table...this table has 5 coloumns (empname, empgsm, empsal, empaddr, empdep)...it has 10 records. i've created 10 users equivelent to the empnames coloumn in the table. When a user logs in with his empname aka username & password, he will be able to see only his record from the table. eg.Smith is an employee, a user called smith was created. when this user is in session, and types "Select * from Employee_table" he only gets the record that belongs to him, where empname is smith. how do i do this using privileges? thanks in advance

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  • User Interface. Multiple select with priority.

    - by Andrew Florko
    I'm designing user interface and want to ask your advises how to make it more user-friendly. Please tell any suggestions and if you have ever seen implementation of something familiar please share the link. University. There are 40+ specialities grouped into 5 faculties. User choose several he is interested in and than orders them by priority. For example I am interested in "programming microcontrollers", "system analysis" and "experimental physic". I must find them quickly in "programming faculty", select them and then order - what I prefer most and what I prefer less then others I select. Any ideas welcome :)

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  • HTML5 Search Input: No Background Image in Chrome?

    - by Jason
    I have been pulling my hair out trying to get Chrome to style my search input with a background image. Firefox has no problem, but I fear it's because it treats the input as a regular text input. Is this simply not possible? Try this as a demo: <input type="search" /> ?input[type="search"] { background: transparent url(http://google.com/intl/en_ALL/images/srpr/logo1w.png) no-repeat 0 0; }?????? If it worked correctly, it should put Google's logo (or part of it) as the background image for the "Search" input. But as you will see when you look at this in Chrome, it DOES NOT WORK. Any ideas, or is this just one of HTML5's quirks? :\

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  • The User Profile Service

    - by Daryl Gill
    I tried logging into my computer after an "ungraceful" shutdown due to a power cut.. I got prompted with a message stating the user profile service failed the login. After reading a k/b on Microsoft I managed to re-login to the "corrupt" account by making registery edits.. But the next step (After having the ability to logon) is a major concern for me.. Would the guys at superuser suggest: 1) Carry on using said account 2) Re-install Windows to eliminate the possible chance of a reoccouring problem 3) Migrate all user data over to a new account and with that being said above. I had to issue the command line: net user administrator /active:yes to activate the hidden adminstrator account, would it be recommended/secure to disable the account or leave it active?

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  • Login to OS X Server User Account from Local Computer

    - by Brod Wilkinson
    I have OS X Server installed on a mac mini. I've created several User accounts, one of which is Account Name: Bob Password: abc123 From the Mac Mini's login screen I can choose "Server" (main account) "Bob" (Bobs account) and "Other..." OS X Server Accounts, from "Other..." if I input Bobs credentials it will log me in. I also have a macbook air, I would like to be able to select from the Login Screen "Other..." input Bobs credentials and have it login to Bobs account, or any other User Account for that matter. My Server is setup as private with the server address: server.network.private Following some googled instructions as well as apples very own instructions I have: Setup an Open Directory with Username: diradmin Password: abc123 Then on the macbook air gone into System Preferences > Users & Groups > Login Options and clicked Join next to Network Account Server, input my server (server.network.private) with diradmin credentials and its connected. Great. I've also ticked Allow Network Users to Login and Login Window and selected All Users. I was assuming this would allow my macbook air to login to the "Bob" account by selecting "Other..." from the login window although there is no "Other..." option. I then setup a VPN, basic credentials, logged into it on the macbook air and still not much has changed. I am able to share screens with the "Bob" account form my macbook air by logging in by clicking Share Screen... from the Finder under Shared > Network Server and then clicking Login In but this obviously requires the macbook air to already be logged into an account before it can share screens which is not suitable. Is there any way to simply login to the OS X Server User Account from the macbook air's login screen via the "Other..." like it does on the mac mini's login screen? Thanks in advance. Operating System: OS X 10.9 Mavericks OS X Server: Version 3

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  • How to switch to user perspective in Blender

    - by Cyanophage
    I've just started using Blender (v2.63) for the first time. I have used a lot of 3d modelling programs in the past but Blender's controls seem to be set up differently and it's taking a while to get used to it. The thing that is really bugging me at the moment is switching from user perspective to front/side/top views. I have my view in perspective mode and I want to switch to front view in orthographic mode and then switch back to the view I had before. It seems that the only way is to press numpad-0 to go to camera view, rotate the screen a bit to get rid of the annoying black outline and then switch it back to perspective mode. Then sometimes when I go back to front view it's in perspective mode which is annoying as you never want front view in perspective, only orthographic mode. My question: Is there a way I can be in my user view in perspective mode, switch to front/side/top views in orthographic mode and then switch back to where I was before in my user mode and be back in perspective mode?

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