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  • How to automate the java Applet(tree view) from my .NET application.

    - by rajeev-vj
    Hi I have a java applet (tree view) on Internet Explorer. when i Click on this applet (+) it collapes, as the information is based on this plus sign. I need to automate this java applet to click automatically from my C#.NET winforms application but am not able to get the details of the java applet. How to get the details of the java applet from browser and how to automate the java applet? Thanks

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  • help with boxplot needed

    - by kathy_BJ
    I am new to R, can anyone help me with boxplot for a dataset like: file1 col1 col2 col3 col4 col5 050350005 101 56.625 48.318 RED 051010002 106 50.625 46.990 GREEN 051190007 25 65.875 74.545 BLUE 051191002 246 52.875 57.070 RED 220050004 55 70 80.274 BLUE 220150008 75 67.750 62.749 RED 220170001 77 65.750 54.307 GREEN file2 col1 col2 col3 col4 col5 050350005 101 56.625 57 RED 051010002 106 50.625 77 GREEN 051190007 25 65.875 51.6 BLUE 051191002 246 52.875 55.070 RED 220050004 55 70 32 BLUE 220150008 75 67.750 32.49 RED 220170001 77 65.750 84.07 GREEN for each color (red,green and blue), I need to compare file1 and file2 by making box plot with MB and RMSE for (col4-col3) for file1 and file2 by dividing col2 in different group: if col2<20,20<=col2<50, 50 <= col2 <70, col2 =70. That is, for the boxplot, the x is (<20, 20-50,50-70, 70), while y is MB (and RMSE) of the difference of col4 and col3 I hope I didn't confuse anybody. Thank you so much.

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  • Confused about Huffman Trees

    - by ShrimpCrackers
    A quick tutorial on generating a huffman tree Confused about Huffman Trees. Near the end of that link above, it shows the tree with 2 elements left, and then the completed tree. I'm confused about the way that it is branched. Is there a specific way a huffman tree needs to be branched? For example, 57:* with its right child 35:* is branched off to the right. Could it have been 35 branched to the left with 22 branched to the right? Also, why wasn't 22:* paired up with 15:4 - it just paired with 20:5 to create a new tree. From initial obersvations it seems the tree does not need to be balanced or have any specific order other than that the frequencies of a leaf add up to the value of the parent node. Could two people creating a huffman tree with the same data end up with different encoding values?

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  • iPhone switch statement using enum

    - by Boris
    I have defined an enum in a header file of a class : typedef enum{ RED = 0, BLUE, Green } Colors; - (void) switchTest:(Colors)testColor; and in the implementation file I have : - (void) switchTest:(Colors)testColor{ if(testColor == RED){ NSLog(@"Red selected"); } switch(testColor){ case RED: NSLog(@"Red selected again !"); break; default: NSLog(@"default selected"); break; } } My code compiles correctly without warrnings. When calling the switchTest method with RED, the output is : "Red selected" but once the first line of the switch runs, the application quits unexpectedly and without warrnings/errors. I don't mind using if/else syntax but I would like to understand my mistake.

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  • List of generic algorithms and data structures

    - by Jake Petroules
    As part of a library project, I want to include a plethora of generic algorithms and data structures. This includes algorithms for searching and sorting, data structures like linked lists and binary trees, path-finding algorithms like A*... the works. Basically, any generic algorithm or data structure you can think of that you think might be useful in such a library, please post or add it to the list. Thanks! (NOTE: Because there is no single right answer I've of course placed this in community wiki... and also, please don't suggest algorithms which are too specialized to be provided by a generic library) The List: Data structures AVL tree B-tree B*-tree B+-tree Binary tree Binary heap Binary search tree Linked lists Singly linked list Doubly linked list Stack Queue Sorting algorithms Binary tree sort Bubble sort Heapsort Insertion sort Merge sort Quicksort Selection sort Searching algorithms

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  • Why does Color.IsNamedColor not work when I create a color using Color.FromArgb()?

    - by Jon B
    In my app I allow the user to build a color, and then show him the name or value of the color later on. If the user picks red (full red, not red-ish), I want to show him "red". If he picks some strange color, then the hex value would be just fine. Here's sample code that demonstrates the problem: static string GetName(int r, int g, int b) { Color c = Color.FromArgb(r, g, b); // Note that specifying a = 255 doesn't make a difference if (c.IsNamedColor) { return c.Name; } else { // return hex value } } Even with very obvious colors like red IsNamedColor never returns true. Looking at the ARGB values for my color and Color.Red, I see no difference. However, calling Color.Red.GetHashCode() returns a different hash code than Color.FromArgb(255, 0, 0).GetHashCode(). How can I create a color using user specified RGB values and have the Name property come out right?

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  • Django: url and content creation results in 500 and no apache error log entry

    - by user1684082
    If i try to open a created url i get an 500 error. My procedure was: First python manage.py startapp black I added in project/settings.py under INSTALLED_APPS 'black', I added in project/urls.py url(r'^test/', include('black.urls')), Content of black/urls.py is: from django.conf.urls import patterns, url from black import views urlpatterns = patterns('', url(r'^$', views.index, name='index') ) And content of black/views.py: from django.http import HttpResponse def index(request): return HttpResponse("SHOW ME: BLACK") After all i synced the database. I can't see any error in apache-error-log and also not in my posted django files. What could cause this?

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  • R scatterplot overplotting color

    - by rgeekay
    So far I have this: qplot(df[[1]], as.numeric(rownames(df)), group=df[[2]], color=df[[2]], ylab="") I want to use different colors for the points in the 2 groups - perhaps a lighter shade for the what's in black now and a darker - say, red for what's in blue. Also, I want to use hexbin kind of thing for group=0 but not for group=1. I'm not able to get the syntax to get this working. In the current plot 0 is in black and 1 is in blue. Added: I worked on it some more, and by using factor and scale_colour_manual, I got the grey color for 0 and red for 1: > palette1 [1] "grey" "red" "blue" "violet" "black" fy=factor(y, labels=c('grey', 'red')) qplot(x, seq(1:length(x)),col=fy, ylab="") + geom_point() + scale_colour_manual(values=palette1) Pending questions are: How to first plot all the grey and then red on top (some of the red is now hidden because the grey is plotted over). How to apply the hexbin logic for group0 i.e. the grey points only and not for the red.

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  • SortedDictionary and SortedList

    - by Simon Cooper
    Apart from Dictionary<TKey, TValue>, there's two other dictionaries in the BCL - SortedDictionary<TKey, TValue> and SortedList<TKey, TValue>. On the face of it, these two classes do the same thing - provide an IDictionary<TKey, TValue> interface where the iterator returns the items sorted by the key. So what's the difference between them, and when should you use one rather than the other? (as in my previous post, I'll assume you have some basic algorithm & datastructure knowledge) SortedDictionary We'll first cover SortedDictionary. This is implemented as a special sort of binary tree called a red-black tree. Essentially, it's a binary tree that uses various constraints on how the nodes of the tree can be arranged to ensure the tree is always roughly balanced (for more gory algorithmical details, see the wikipedia link above). What I'm concerned about in this post is how the .NET SortedDictionary is actually implemented. In .NET 4, behind the scenes, the actual implementation of the tree is delegated to a SortedSet<KeyValuePair<TKey, TValue>>. One example tree might look like this: Each node in the above tree is stored as a separate SortedSet<T>.Node object (remember, in a SortedDictionary, T is instantiated to KeyValuePair<TKey, TValue>): class Node { public bool IsRed; public T Item; public SortedSet<T>.Node Left; public SortedSet<T>.Node Right; } The SortedSet only stores a reference to the root node; all the data in the tree is accessed by traversing the Left and Right node references until you reach the node you're looking for. Each individual node can be physically stored anywhere in memory; what's important is the relationship between the nodes. This is also why there is no constructor to SortedDictionary or SortedSet that takes an integer representing the capacity; there are no internal arrays that need to be created and resized. This may seen trivial, but it's an important distinction between SortedDictionary and SortedList that I'll cover later on. And that's pretty much it; it's a standard red-black tree. Plenty of webpages and datastructure books cover the algorithms behind the tree itself far better than I could. What's interesting is the comparions between SortedDictionary and SortedList, which I'll cover at the end. As a side point, SortedDictionary has existed in the BCL ever since .NET 2. That means that, all through .NET 2, 3, and 3.5, there has been a bona-fide sorted set class in the BCL (called TreeSet). However, it was internal, so it couldn't be used outside System.dll. Only in .NET 4 was this class exposed as SortedSet. SortedList Whereas SortedDictionary didn't use any backing arrays, SortedList does. It is implemented just as the name suggests; two arrays, one containing the keys, and one the values (I've just used random letters for the values): The items in the keys array are always guarenteed to be stored in sorted order, and the value corresponding to each key is stored in the same index as the key in the values array. In this example, the value for key item 5 is 'z', and for key item 8 is 'm'. Whenever an item is inserted or removed from the SortedList, a binary search is run on the keys array to find the correct index, then all the items in the arrays are shifted to accomodate the new or removed item. For example, if the key 3 was removed, a binary search would be run to find the array index the item was at, then everything above that index would be moved down by one: and then if the key/value pair {7, 'f'} was added, a binary search would be run on the keys to find the index to insert the new item, and everything above that index would be moved up to accomodate the new item: If another item was then added, both arrays would be resized (to a length of 10) before the new item was added to the arrays. As you can see, any insertions or removals in the middle of the list require a proportion of the array contents to be moved; an O(n) operation. However, if the insertion or removal is at the end of the array (ie the largest key), then it's only O(log n); the cost of the binary search to determine it does actually need to be added to the end (excluding the occasional O(n) cost of resizing the arrays to fit more items). As a side effect of using backing arrays, SortedList offers IList Keys and Values views that simply use the backing keys or values arrays, as well as various methods utilising the array index of stored items, which SortedDictionary does not (and cannot) offer. The Comparison So, when should you use one and not the other? Well, here's the important differences: Memory usage SortedDictionary and SortedList have got very different memory profiles. SortedDictionary... has a memory overhead of one object instance, a bool, and two references per item. On 64-bit systems, this adds up to ~40 bytes, not including the stored item and the reference to it from the Node object. stores the items in separate objects that can be spread all over the heap. This helps to keep memory fragmentation low, as the individual node objects can be allocated wherever there's a spare 60 bytes. In contrast, SortedList... has no additional overhead per item (only the reference to it in the array entries), however the backing arrays can be significantly larger than you need; every time the arrays are resized they double in size. That means that if you add 513 items to a SortedList, the backing arrays will each have a length of 1024. To conteract this, the TrimExcess method resizes the arrays back down to the actual size needed, or you can simply assign list.Capacity = list.Count. stores its items in a continuous block in memory. If the list stores thousands of items, this can cause significant problems with Large Object Heap memory fragmentation as the array resizes, which SortedDictionary doesn't have. Performance Operations on a SortedDictionary always have O(log n) performance, regardless of where in the collection you're adding or removing items. In contrast, SortedList has O(n) performance when you're altering the middle of the collection. If you're adding or removing from the end (ie the largest item), then performance is O(log n), same as SortedDictionary (in practice, it will likely be slightly faster, due to the array items all being in the same area in memory, also called locality of reference). So, when should you use one and not the other? As always with these sort of things, there are no hard-and-fast rules. But generally, if you: need to access items using their index within the collection are populating the dictionary all at once from sorted data aren't adding or removing keys once it's populated then use a SortedList. But if you: don't know how many items are going to be in the dictionary are populating the dictionary from random, unsorted data are adding & removing items randomly then use a SortedDictionary. The default (again, there's no definite rules on these sort of things!) should be to use SortedDictionary, unless there's a good reason to use SortedList, due to the bad performance of SortedList when altering the middle of the collection.

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  • Change specificity by child

    - by jim red
    hi I'd like to integrate a theme tag to my elements so they appear in diffrent colours. But since the css selectors have the same css specificity the latest overrides the earlier defined rule. this is an example that shows my problem: .... <div class="red"> <div class="box">This should be red</div> <div class="yellow"> ... <div class="box">This should be yellow (nested in x levels under the div.yellow)</div> ... </div> .... and here my css .box { width: 100px; height: 100px; } .yellow { background-color: yellow; } .red { background-color: red; } the box should be listed somewhere, but as soon as it is a sub child of another color definition it should been overwritten. thanks for any help! //jim

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  • Excel 2007 Conditional Formatting is not properly using custom formula provided

    - by Charles
    In Excel 2007, I want to conditionally color a row if it is odd numbered and then vary the coloring depending on if a specific cell (in column E) in that row contains a number (green) or empty(red). E.g. if E15 has a value of 2 and E13 has no entry, I would expect row 15 to be green and row 13 to be red. My two formulas are: To color red: =IF((MOD(ROW(),2) = 1),NOT(ISNUMBER(INDIRECT("$E$"&ROW()))), FALSE) To color green: =IF((MOD(ROW(),2) = 1),ISNUMBER(INDIRECT("E"&ROW())), FALSE) If I paste these formulas into cells on the worksheet I get the expected values. For row 15 the "red" equation is false and the "green" equation is true. For Row 13 the "red" equation is true and the "green equation is false. However if I use these formulas in the conditional formating use formula feature, all of my rows are red, any thoughts?

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  • Why does my Opengl es android testbed app not render anything besides a red screen?

    - by nathan
    For some reason my code here (this is the entire thing) doesnt actually render anything besides a red screen.. can anyone tell me why? package com.ntu.way2fungames.earth.testbed; import java.nio.FloatBuffer; import javax.microedition.khronos.egl.EGLConfig; import javax.microedition.khronos.opengles.GL10; import android.app.Activity; import android.content.Context; import android.opengl.GLSurfaceView; import android.opengl.GLSurfaceView.Renderer; import android.os.Bundle; public class projectiles extends Activity { GLSurfaceView lGLView; Renderer lGLRenderer; float projectilesX[]= new float[5001]; float projectilesY[]= new float[5001]; float projectilesXa[]= new float[5001]; float projectilesYa[]= new float[5001]; float projectilesTheta[]= new float[5001]; float projectilesSpeed[]= new float[5001]; private static FloatBuffer drawBuffer; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); SetupProjectiles(); Context mContext = this.getWindow().getContext(); lGLView= new MyView(mContext); lGLRenderer= new MyRenderer(); lGLView.setRenderer(lGLRenderer); setContentView(lGLView); } private void SetupProjectiles() { int i=0; for (i=5000;i>0;i=i-1){ projectilesX[i] = 240; projectilesY[i] = 427; float theta = (float) ((i/5000)*Math.PI*2); projectilesXa[i] = (float) Math.cos(theta); projectilesYa[i] = (float) Math.sin(theta); projectilesTheta[i]= theta; projectilesSpeed[i]= (float) (Math.random()+1); } } public class MyView extends GLSurfaceView{ public MyView(Context context) { super(context); // TODO Auto-generated constructor stub } } public class MyRenderer implements Renderer{ private float[] projectilecords = new float[] { .0f, .5f, 0, -.5f, 0f, 0, .5f, 0f, 0, 0, -5f, 0, }; @Override public void onDrawFrame(GL10 gl) { gl.glClear(GL10.GL_COLOR_BUFFER_BIT); gl.glMatrixMode(GL10.GL_MODELVIEW); //gl.glLoadIdentity(); gl.glEnableClientState(GL10.GL_VERTEX_ARRAY); for (int i=5000;i>4500;i=i-1){ //drawing section gl.glLoadIdentity(); gl.glColor4f(.9f, .9f,.9f,.9f); gl.glTranslatef(projectilesY[i], projectilesX[i],1); gl.glVertexPointer(3, GL10.GL_FLOAT, 0, drawBuffer); gl.glDrawArrays(GL10.GL_TRIANGLE_STRIP, 0, 12); //physics section projectilesX[i]=projectilesX[i]+projectilesXa[i]; projectilesY[i]=projectilesY[i]+projectilesYa[i]; } gl.glDisableClientState(GL10.GL_VERTEX_ARRAY); } @Override public void onSurfaceChanged(GL10 gl, int width, int height) { if (height == 0) height = 1; // draw on the entire screen gl.glViewport(0, 0, width, height); // setup projection matrix gl.glMatrixMode(GL10.GL_PROJECTION); gl.glLoadIdentity(); gl.glOrthof(0,width,height,0, -100, 100); } @Override public void onSurfaceCreated(GL10 gl, EGLConfig arg1) { gl.glShadeModel(GL10.GL_SMOOTH); gl.glClearColor(1f, .01f, .01f, 1f); gl.glClearDepthf(1.0f); gl.glEnable(GL10.GL_DEPTH_TEST); gl.glDepthFunc(GL10.GL_LEQUAL); gl.glHint(GL10.GL_PERSPECTIVE_CORRECTION_HINT, GL10.GL_NICEST); drawBuffer = FloatBuffer.wrap(projectilecords); } } }

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  • C++ linked list based tree structure. Sanely copy nodes between lists.

    - by krunk
    edit Clafification: The intention is not to remove the node from the original list. But to create an identical node (data and children wise) to the original and insert that into the new list. In other words, a "move" does not imply a "remove" from the original. endedit The requirements: Each Node in the list must contain a reference to its previous sibling Each Node in the list must contain a reference to its next sibling Each Node may have a list of child nodes Each child Node must have a reference to its parent node Basically what we have is a tree structure of arbitrary depth and length. Something like: -root(NULL) --Node1 ----ChildNode1 ------ChildOfChild --------AnotherChild ----ChildNode2 --Node2 ----ChildNode1 ------ChildOfChild ----ChildNode2 ------ChildOfChild --Node3 ----ChildNode1 ----ChildNode2 Given any individual node, you need to be able to either traverse its siblings. the children, or up the tree to the root node. A Node ends up looking something like this: class Node { Node* previoius; Node* next; Node* child; Node* parent; } I have a container class that stores these and provides STL iterators. It performs your typical linked list accessors. So insertAfter looks like: void insertAfter(Node* after, Node* newNode) { Node* next = after->next; after->next = newNode; newNode->previous = after; next->previous = newNode; newNode->next = next; newNode->parent = after->parent; } That's the setup, now for the question. How would one move a node (and its children etc) to another list without leaving the previous list dangling? For example, if Node* myNode exists in ListOne and I want to append it to listTwo. Using pointers, listOne is left with a hole in its list since the next and previous pointers are changed. One solution is pass by value of the appended Node. So our insertAfter method would become: void insertAfter(Node* after, Node newNode); This seems like an awkward syntax. Another option is doing the copying internally, so you'd have: void insertAfter(Node* after, const Node* newNode) { Node *new_node = new Node(*newNode); Node* next = after->next; after->next = new_node; new_node->previous = after; next->previous = new_node; new_node->next = next; new_node->parent = after->parent; } Finally, you might create a moveNode method for moving and prevent raw insertion or appending of a node that already has been assigned siblings and parents. // default pointer value is 0 in constructor and a operator bool(..) // is defined for the Node bool isInList(const Node* node) const { return (node->previous || node->next || node->parent); } // then in insertAfter and friends if(isInList(newNode) // throw some error and bail I thought I'd toss this out there and see what folks came up with.

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  • C# wpf helix scale based mesh parenting using Transform3DGroup

    - by Rick2047
    I am using https://helixtoolkit.codeplex.com/ as a 3D framework. I want to move black mesh relative to the green mesh as shown in the attached image below. I want to make green mesh parent to the black mesh as the change in scale of the green mesh also will result in motion of the black mesh. It could be partial parenting or may be more. I need 3D rotation and 3D transition + transition along green mesh's length axis for the black mesh relative to the green mesh itself. Suppose a variable green_mesh_scale causing scale for the green mesh along its length axis. The black mesh will use that variable in order to move along green mesh's length axis. How to go about it. I've done as follows: GeometryModel3D GreenMesh, BlackMesh; ... double green_mesh_scale = e.NewValue; Transform3DGroup forGreen = new Transform3DGroup(); Transform3DGroup forBlack = new Transform3DGroup(); forGreen.Children.Add(new ScaleTransform3D(new Vector3D(1, green_mesh_scale , 1))); // ... transforms for rotation n transition GreenMesh.Transform = forGreen ; forBlack = forGreen; forBlack.Children.Add(new TranslateTransform3D(new Vector3D(0, green_mesh_scale, 0))); BlackMesh.Transform = forBlack; The problem with this is the scale transform will also be applied to the black mesh. I think i just need to avoid the scale part. I tried keeping all the transforms but scale, on another Transform3DGroup variable but that also not behaving as expected. Can MatrixTransform3D be used here some how? Also please suggest if this question can be posted somewhere else in stackexchange.

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  • Team Schedule

    - by THE
    .conf td{ width: 350px; border: 1px solid black; background-color: #ffcccc; } .myt table { border: 1px solid black; } .myt tr { border: 0px solid black; } .mytg td{ border: 1px solid black; padding: 5px; background-color:#808080; } .myt td{ border: 1px solid black; padding: 5px; } .myt th{ border: 1px solid black; padding: 5px; background-color:#c0c0c0; } So you want to meet the Proactive Support Technology Team?Here is where we can be found next: Conference Date Member link Oracle User Group Conference EPM & Hyperion 2012 23+24 October 2012 Maurice Bauhahn Grzegorz Reizer info Advisor Webcast: New features of HFM 17 November 2012 Grzegorz Reizer info OUG Ireland BI & EPM SIG Meeting 20 November 2012 Maurice Bauhahn info UKOUG 2012 Conference: ICC, Birmingham 3–5 December 2012 Ian Bristow info You will find this schedule via the link in the upper right section of this blog under "meet the team", or you can bookmark this post

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  • Ubuntu touch flashing failed/taking to long. Black screen! Redeploy help!

    - by Marius Rye
    So i'm brand new to the whole unlock, root and flashing thing. I just tried flashing Ubuntu touch on my Galaxy Nexus (international GSM/HSPA+) and everything seamed fine until the very end when i got this ERROR message. ERROR:phablet-flash:Installation is taking too long or an error occured along the way. I didn't know what to do so i disconnected my device (which was in Ubuntu recovery) and tried rebooting it from there, it worked "sort of". i got the Google logo with the unlocked icon then it continued to a black screen. In the installation guide on http://www.ubuntu.com/phone/install said i should: "try wiping the /data partition on your device and redeploy". the problem is that i don't know how to do this and i'm basically sitting here with a useless phone right now. I would be extremely grateful for some proffeexpert help.

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  • Estudio de caso: CFO de At&T le apunta a la tecnología para transformar las Finanzas Globales

    - by RED League Heroes-Oracle
    AT&T es una de las pocas multinacionales modernas que han participado de todas las etapas anteriores de la innovación de las telecomunicaciones, de Alexander Graham Bell como inventor solitario, a Bell Labs, a los lanzamientos acelerados en las fundiciones de AT&T. La tecnología es el corazón de todo lo que AT&T hace, incluyendo sus inversiones en innovaciones tecnológicas para permitir que las finanzas de AT&T trabajen más estratégicamente con los negocios para asegurar que las inversiones en las iniciativas de crecimiento sean exitosas. Según John Stephens, Vicepresidente Ejecutivo y director financiero de AT&T, la empresa ha trazado un plan de inversión de tres años para mejorar y aumentar sus redes IP de banda ancha alámbricas e inalámbricas. El plan incluye la implementación del servicio 4G LTE para 300 millones de personas en los Estados Unidos, expansión de IP de banda ancha de alta velocidad a unos 57 millones de hogares de clientes y una expansión de la fibra a 1 millón de clientes corporativos adicionales en su área de servicio de telefonía fija. "La necesidad de velocidad es mayor que nunca, y este proyecto es nuestro paso hacia la innovación para ofrecer tal velocidad," dice Stephens. Como AT&T moderniza su infraestructura global, sus procesos operacionales se hacen tan poderosos como su red. Ha sido una tarea grande y compleja, pero Stephens se complace al decir que el departamento de finanzas de AT&T ha adoptado su papel de catalizador corporativo. Empezó con un concepto simple: "Vamos a hacer que todos hablen en el mismo idioma". Esto llevó a la consolidación de sistemas financieros heredados de las empresas adquiridas. No fue una tarea sencilla, dado que la empresa pasó por más de cinco adquisiciones importantes y un sinfín de otras transacciones. En 2007, AT&T tenía 17 aplicaciones apenas en la función de cuentas por pagar. Hoy, el número se ha reducido a dos. Asimismo, hubo 50 sistemas de reportes gerenciales oficiales y ahora hay tres, con planes de excluir uno de ellos. Al tener un único lenguaje volcado a las Finanzas en toda la empresa, el equipo de finanzas de AT&T ha eliminado las varias versiones de los mismos datos, reduciendo la posible confusión en las discusiones y en las decisiones de estrategia de negocios. Estos pasos también han reducido los costos y aceleraron la toma de decisiones. "Lo lindo de los sistemas es que permiten que la gente talentosa con habilidades analíticas usen su tiempo en esa zona, en vez de gastar tiempo en recolección, agregación y organización de los datos," señala Stephens. "Tenemos un proceso eficiente y eficaz que hace que nosotros, dejemos a la gente libre para dedicarse a aquello en que son realmente buenos. Y tenemos un equipo de alta calidad y ellos están en su mejor punto cuando son capaces de hacer su función para apoyar a la unidad de negocio”AT&T es una de las pocas multinacionales modernas que han participado de todas las etapas anteriores de la innovación de las telecomunicaciones, de Alexander Graham Bell como inventor solitario, a Bell Labs, a los lanzamientos acelerados en las fundiciones de AT&T. La tecnología es el corazón de todo lo que AT&T hace, incluyendo sus inversiones en innovaciones tecnológicas para permitir que las finanzas de AT&T trabajen más estratégicamente con los negocios para asegurar que las inversiones en las iniciativas de crecimiento sean exitosas.  Según John Stephens, Vicepresidente Ejecutivo y director financiero de AT&T, la empresa ha trazado un plan de inversión de tres años para mejorar y aumentar sus redes IP de banda ancha alámbricas e inalámbricas. El plan incluye la implementación del servicio 4G LTE para 300 millones de personas en los Estados Unidos, expansión de IP de banda ancha de alta velocidad a unos 57 millones de hogares de clientes y una expansión de la fibra a 1 millón de clientes corporativos adicionales en su área de servicio de telefonía fija. "La necesidad de velocidad es mayor que nunca, y este proyecto es nuestro paso hacia la innovación para ofrecer tal velocidad," dice Stephens. Como AT&T moderniza su infraestructura global, sus procesos operacionales se hacen tan poderosos como su red. Ha sido una tarea grande y compleja, pero Stephens se complace al decir que el departamento de finanzas de AT&T ha adoptado su papel de catalizador corporativo. Empezó con un concepto simple: "Vamos a hacer que todos hablen en el mismo idioma". Esto llevó a la consolidación de sistemas financieros heredados de las empresas adquiridas. No fue una tarea sencilla, dado que la empresa pasó por más de cinco adquisiciones importantes y un sinfín de otras transacciones. En 2007, AT&T tenía 17 aplicaciones apenas en la función de cuentas por pagar. Hoy, el número se ha reducido a dos. Asimismo, hubo 50 sistemas de reportes gerenciales oficiales y ahora hay tres, con planes de excluir uno de ellos. Al tener un único lenguaje volcado a las Finanzas en toda la empresa, el equipo de finanzas de AT&T ha eliminado las varias versiones de los mismos datos, reduciendo la posible confusión en las discusiones y en las decisiones de estrategia de negocios. Estos pasos también han reducido los costos y aceleraron la toma de decisiones. "Lo lindo de los sistemas es que permiten que la gente talentosa con habilidades analíticas usen su tiempo en esa zona, en vez de gastar tiempo en recolección, agregación y organización de los datos," señala Stephens. "Tenemos un proceso eficiente y eficaz que hace que nosotros, dejemos a la gente libre para dedicarse a aquello en que son realmente buenos. Y tenemos un equipo de alta calidad y ellos están en su mejor punto cuando son capaces de hacer su función para apoyar a la unidad de negocio”

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  • Which hidden files and directories do I need?

    - by Sammy Black
    In a previous question, I explained my situation/plan: backing up home directory on external drive, reformatting laptop drive, installing 14.04, putting home directory back. (It hasn't happened yet because I can't seem to find the down time, in case things aren't working right away.) It occurred to me that maybe I don't want all of those hidden files and directories (e.g. .local/share/ubuntuone/syncdaemon/, .cache/google-chrome/, etc.) Just judging by the amount of time in copying, I can tell that some of these hidden directories are large. Question: Are there any hidden directories that I obviously don't need/want when I have the laptop running an updated distribution? Will they cause conflicts? (I plan on copying the backed-up directory tree back onto the laptop with the --no-clobber option.)

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  • QTreeWidget insertTopLevelItem - index given not accurately displayed in Tree?

    - by mleep
    I am unable to properly insert a QTreeWidgetItem at a specific index, in this case I am removing all QTreeWidgetItems from the tree, doing a custom sort on their Date Objects and then inserting them back into the QTreeWidget. However, upon inserting (even one at a time) the QTreeWidgetItem is not inserted into the correct place. The code below prints out: index 0: 0 index 0: 1 index 1: 0 index 0: 2 index 1: 1 index 2: 0 index 0: 3 index 1: 2 index 2: 0 index 3: 1 index 0: 4 index 1: 2 index 2: 0 index 3: 1 index 4: 3 print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]) self.insertTopLevelItem(0, childrenList[1]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]) self.insertTopLevelItem(0, childrenList[2]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ', \ self.indexOfTopLevelItem(childrenList[2]) self.insertTopLevelItem(0, childrenList[3]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]), ' index 1: ',\ self.indexOfTopLevelItem(childrenList[1]), ' index 2: ',\ self.indexOfTopLevelItem(childrenList[2]), 'index 3: ',\ self.indexOfTopLevelItem(childrenList[3]) self.insertTopLevelItem(0, childrenList[4]) print 'index 0: ', self.indexOfTopLevelItem(childrenList[0]),\ ' index 1: ', self.indexOfTopLevelItem(childrenList[1]),\ ' index 2: ', self.indexOfTopLevelItem(childrenList[2]),\ 'index 3: ', self.indexOfTopLevelItem(childrenList[3]),\ 'index 4: ', self.indexOfTopLevelItem(childrenList[4])

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  • How to change a grouped UITableView cell's background to black (or non-white)?

    - by Meltemi
    Just want to make sure I'm not overlooking something obvious... It seems like it should be trivial to set the background color (black is fine) of a UITableView's cell to something other than white or completely transparent so that you can display your data with white text. However, with my attempts I lose the corners on my grouped table view and it all looks like crap. I've seen & understand the methods described by Matt Gallagher about customizing TableView cells with exotic gradients, etc. but wanted to be certain before heading down that path...

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  • How can I generate an Expression tree that queries an object with List<T> as a property?

    - by David Robbins
    Forgive my clumsy explanation, but I have a class that contains a List: public class Document { public int OwnerId { get; set; } public List<User> Users { get; set; } public Document() { } } public class User { public string UserName { get; set; } public string Department { get; set; } } Currently I use PredicateBuilder to perform dynmica queries on my objects. How can I turn the following LINQ statement into an Expression Tree: var predicate= PredicateBuilder.True<User>(); predicate= predicate.And<User>(user => user.Deparment == "HR"); var deptDocs = documents.AsQueryable() .Where(doc => doc.Users .AsQueryable().Count(predicate) > 0) .ToList(); In other words var deptDocs = documents.HasUserAttributes("Department", "HR").ToList();

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