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Search found 224 results on 9 pages for 'credits'.

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• Question about MySQLdb, OS X 10.5, and authentication

  - by timpone

  I'm a noob at Python and have been having problems with MySQLdb and OS X Leopard 10.5. I have a php app that is doing db access just fine with pdo but also want to access with Python. When I use the same credentials with MySQLdb as php, I get the following error: File "build/bdist.macosx-10.5-i386/egg/MySQLdb/connections.py", line 188, in __init__ _mysql_exceptions.OperationalError: (1045, "Access denied for user 'arc_db'@'localhost' (using password: YES)") The authentication piece works fine on my ubuntu server (installed via apt-get) implying that it is something specific to my OS X MySQLdb install. Looking at some postings, I thought it would be my local build of MySQLdb which seems to be problematic with OS X. But I am able to import fine: Python 2.5.1 (r251:54863, Feb 6 2009, 19:02:12) [GCC 4.0.1 (Apple Inc. build 5465)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import MySQLdb >>> Also, wanting to create a positive, I am able to access and return results from a database tilted test_something (which presumably bypasses the MySQL's authtentication - not sure exactly how though). Trying to figure out a little more what is going on, I turn on logging for mysql and get the following (added my own comments): 100609 19:09:45 3 Connect Access denied for user 'arc_db'@'localhost' (using password: YES) //not worked 100609 19:10:02 4 Connect arc_db@localhost on arc_development //did work I'm not really sure what the 3 or 4 means but presumably a sucess or failue. So, I guess what would be the next step? Am I doing some obvious stupid python mistake (very likely)? Is there a better way for me to prove that this should / can be working? Is there any way to determine what MySQLdb is sending exactly in its authentication message to MySQL? thanks

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• Secure Webservice (WCF) without storing credentials on consumer application

  - by Pai Gaudêncio

  Howdy folks, I have a customer that sells a lottery analysis application. In this application, he consumes a webservice (my service, I mean, belongs to the company I work for now) to get statistical data about lottery results, bets made, amounts, etc., from all across the globe. The access to this webservice is paid, and each consult costs X credits. Some people have disassembled this lottery application and found the api key/auth key used to access the paid webservice, and started to use it. I would like to prevent this from happening again, but I can't find a way to authenticate on the webservice without storing the auth. keys on the application. Does anyone have any ideas on how to accomplish such task? ps1.Can't ask for the users to input any kind of credentials. Has to be transparent for them (they shouldn't know what is happening). ps2. Can't use digital certificates for the same reason above, not to mention it's easy to retrieve them and we would fall into the original problem. Thanks in advance.

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• virtualenv macosX --no-site-package ignored

  - by Tristram Gräbener

  Hello, I'm having problems with macOSX and virtualenv. It seems to ignore --no-site-package. Using exactly the same commands with linux (archlinux) it works. It it macOSX 10.5 with python 2.5 curl -o virtualenv.py 'http://bitbucket.org/ianb/virtualenv/raw/tip/virtualenv.py Create a new environment python virtualenv.py --no-site-packages foo New python executable in foo/bin/python Installing setuptools...........................done. Activate it source foo/bin/activate Try to install something in it. Despite virtualenv it looks for the system-wide install easy_install cherrypy Searching for cherrypy Best match: CherryPy 3.1.2 Adding CherryPy 3.1.2 to easy-install.pth file Using /Library/Python/2.5/site-packages Processing dependencies for cherrypy Finished processing dependencies for cherrypy Yet it doesn't find the module (foo)guidage-multimodal:~ tristram$ python Python 2.5.1 (r251:54863, Feb 6 2009, 19:02:12) [GCC 4.0.1 (Apple Inc. build 5465)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import cherrypy Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named cherrypy I tried PIP after looking at http://stackoverflow.com/questions/1382925/virtualenv-no-site-packages-and-pip-still-finding-global-packages However it fails installing psycopg2 (some problems with gcc). Also I would like to be able to have a setup.py (from distribute) that does the whole woork

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• Save PyML.classifiers.multi.OneAgainstRest(SVM()) object?

  - by Michael Aaron Safyan

  I'm using PYML to construct a multiclass linear support vector machine (SVM). After training the SVM, I would like to be able to save the classifier, so that on subsequent runs I can use the classifier right away without retraining. Unfortunately, the .save() function is not implemented for that classifier, and attempting to pickle it (both with standard pickle and cPickle) yield the following error message: pickle.PicklingError: Can't pickle : it's not found as __builtin__.PySwigObject Does anyone know of a way around this or of an alternative library without this problem? Thanks. Edit/Update I am now training and attempting to save the classifier with the following code: mc = multi.OneAgainstRest(SVM()); mc.train(dataset_pyml,saveSpace=False); for i, classifier in enumerate(mc.classifiers): filename=os.path.join(prefix,labels[i]+".svm"); classifier.save(filename); Notice that I am now saving with the PyML save mechanism rather than with pickling, and that I have passed "saveSpace=False" to the training function. However, I am still gettting an error: ValueError: in order to save a dataset you need to train as: s.train(data, saveSpace = False) However, I am passing saveSpace=False... so, how do I save the classifier(s)? P.S. The project I am using this in is pyimgattr, in case you would like a complete testable example... the program is run with "./pyimgattr.py train"... that will get you this error. Also, a note on version information: [michaelsafyan@codemage /Volumes/Storage/classes/cse559/pyimgattr]$ python Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. import PyML print PyML.__version__ 0.7.0

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• Gzip and subprocess' stdout in python

  - by pythonic metaphor

  I'm using python 2.6.4 and discovered that I can't use gzip with subprocess the way I might hope. This illustrates the problem: May 17 18:05:36> python Python 2.6.4 (r264:75706, Mar 10 2010, 14:41:19) [GCC 4.1.2 20071124 (Red Hat 4.1.2-42)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import gzip >>> import subprocess >>> fh = gzip.open("tmp","wb") >>> subprocess.Popen("echo HI", shell=True, stdout=fh).wait() 0 >>> fh.close() >>> [2]+ Stopped python May 17 18:17:49> file tmp tmp: data May 17 18:17:53> less tmp "tmp" may be a binary file. See it anyway? May 17 18:17:58> zcat tmp zcat: tmp: not in gzip format Here's what it looks like inside less HI ^_<8B>^H^Hh<C0><F1>K^B<FF>tmp^@^C^@^@^@^@^@^@^@^@^@ which looks like it put in the stdout as text and then put in an empty gzip file. Indeed, if I remove the "Hi\n", then I get this: May 17 18:22:34> file tmp tmp: gzip compressed data, was "tmp", last modified: Mon May 17 18:17:12 2010, max compression What is going on here?

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• Codeigniter: db data in controller

  - by Kevin Brown

  I'm confused about what to do... I'm working on a user's page where they can view certain things only if their supervisor has given them "money" or "credits". I need a simple way to get the person that is their supervisor by doing something like: $data['employer'] = $this->home_model->getEmployees(array('user_id'=>$manager_id)); Basically, get the user information about a person who's user_id matches the manager_id of the currently logged in member. I don't know how to set the variable $manager_id. Additional Information: The current user has an id, and a manager_id. I need the id of the manager. So, I need to grab the manager_id of the logged-in user and find the manager who's user_id is that of the manager_id. What's the process to do this? I can get each individually, but I don't know how to use one to get the other... I know it is confusing, but I'm confused! Thanks for the help!

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• "ImportError: cannot import name Exchange" when using Celery w/ Kombu installed

  - by alukach

  I'm trying to create a Celery worker node on an Amazon EC2 Windows2008 R2 instance. Due to a plugin we require for another Python module, we are required to user Python3. I've installed Python3.2 and necessary modules and run Celery, but for some reason it states that it can't import Exchange and Queue from Kombu, despite the face that Kombu is installed and can be imported by python. Microsoft Windows [Version 6.1.7601] Copyright (c) 2009 Microsoft Corporation. All rights reserved. C:\Users\Administrator>celery Traceback (most recent call last): File "C:\Python32\Scripts\celery-script.py", line 9, in <module> load_entry_point('celery==3.0.11', 'console_scripts', 'celery')() File "C:\Python32\lib\site-packages\celery\__main__.py", line 13, in main from celery.bin.celery import main File "C:\Python32\lib\site-packages\celery\bin\celery.py", line 21, in <module> from celery.utils import term File "C:\Python32\lib\site-packages\celery\utils\__init__.py", line 22, in <module> from kombu import Exchange, Queue ImportError: cannot import name Exchange C:\Users\Administrator>python Python 3.2 (r32:88445, Feb 20 2011, 21:29:02) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> from kombu import Exchange, Queue >>> print('WTF?!?') WTF?!? >>> This problem seems similar to this and this, but I have not been able to remedy the issue. Any ideas?

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• When is someone else's code I use from the internet "mine"?

  - by robault

  I'm building a library from methods that I've found on the internet. Some are free to use or modify with no requirements, others say that if I leave a comment in the code it's okay to use, others say when I use the code I have to attribute the use of someone's code in my application (in the credits for my app I guess). What I've been doing is reorganizing classes, renaming methods, adding descriptions (code comments), renaming the parameters and names inside the methods to something meaningful, optimizing loops if applicable, changing return types, adding try/catch/throw blocks, adding parameter checks and cleaning up resources in the methods. For example; I didn't come up with the algorithm for blurring a Bitmap but I've taken the basic example of iterating through the pixels and turned it into a decent library method (applying the aforementioned modifications). I understand how to go about building it now myself but I didn't actually hit the keystrokes to make it and I couldn't have come up with it before learning from their example. What about code people get in answers on Stackoverflow or examples from Codeproject? At what point can I drop their requirements because at n% their code became mine? FWIW I intend on using the libraries to create products that I will sell.

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• How to convert from hex-encoded string to a "human readable" string?

  - by John Jensen

  I'm using the Net-SNMP bindings for python and I'm attempting to grab an ARP cache from a Brocade switch. Here's what my code looks like: #!/usr/bin/env python import netsnmp def get_arp(): oid = netsnmp.VarList(netsnmp.Varbind('ipNetToMediaPhysAddress')) res = netsnmp.snmpwalk(oid, Version=2, DestHost='10.0.1.243', Community='public') return res arp_table = get_arp() print arp_table The SNMP code itself is working fine. Output from snmpwalk looks like this: <snip> IP-MIB::ipNetToMediaPhysAddress.128.10.200.6.158 = STRING: 0:1b:ed:a3:ec:c1 IP-MIB::ipNetToMediaPhysAddress.129.10.200.6.162 = STRING: 0:1b:ed:a4:ac:c1 IP-MIB::ipNetToMediaPhysAddress.130.10.200.6.166 = STRING: 0:1b:ed:38:24:1 IP-MIB::ipNetToMediaPhysAddress.131.10.200.6.170 = STRING: 74:8e:f8:62:84:1 </snip> But my output from the python script yields a tuple of hex-encoded strings that looks like this: ('\x00$8C\x98\xc1', '\x00\x1b\xed;_A', '\x00\x1b\xed\xb4\x8f\x81', '\x00$86\x15\x81', '\x00$8C\x98\x81', '\x00\x1b\xed\x9f\xadA', ...etc) I've spent some time googling and came across the struct module and the .decode("hex") string method, but the .decode("hex") method doesn't seem to work: Python 2.7.3 (default, Apr 10 2013, 06:20:15) [GCC 4.6.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> hexstring = '\x00$8C\x98\xc1' >>> newstring = hexstring.decode("hex") Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.7/encodings/hex_codec.py", line 42, in hex_decode output = binascii.a2b_hex(input) TypeError: Non-hexadecimal digit found >>> And the documentation for struct is a bit over my head.

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• Execute a BASH command in Python-- in the same process

  - by Baldur

  I need to execute the command . /home/db2v95/sqllib/db2profile before I can import ibm_db_dbi in Python 2.6. Executing it before I enter Python works: baldurb@gigur:~$ . /home/db2v95/sqllib/db2profile baldurb@gigur:~$ python Python 2.6.4 (r264:75706, Dec 7 2009, 18:45:15) [GCC 4.4.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import ibm_db_dbi >>> but executing it in Python using os.system(". /home/db2v95/sqllib/db2profile") or subprocess.Popen([". /home/db2v95/sqllib/db2profile"]) results in an error. What am I doing wrong? Edit: this is the error I receive: > Traceback (most recent call last): > File "<file>.py", line 8, in > <module> > subprocess.Popen([". /home/db2v95/sqllib/db2profile"]) > File > "/usr/lib/python2.6/subprocess.py", > line 621, in __init__ > errread, errwrite) File "/usr/lib/python2.6/subprocess.py", > line 1126, in _execute_child > raise child_exception OSError: [Errno 2] No such file or directory

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• How do I configure multiple Ubuntu Python installations to avoid App Engine's SSL error?

  - by Linc

  I have Karmic Koala which has Python 2.6 installed by default. However I can't run any Python App Engine projects because they require Python 2.5 and python ssl. To install ssl I installed python2.5-dev first while following some instructions I found elsewhere. sudo apt-get install libssl-dev sudo apt-get install python-setuptools sudo apt-get install python2.5-dev sudo easy_install-2.5 pyopenssl However, I am afraid this is not good for my Ubuntu installation since Ubuntu expects to see version 2.6 of Python when you type 'python' on the command line. Instead, it says '2.5.5'. I tried to revert to the original default version of Python by doing this: sudo apt-get remove python2.5-dev But that didn't seem to do anything either - when I type 'python' on the command line it still say 2.5.5. And App Engine still doesn't work after all this. I continue to get an SSL-related error whenever I try to run my Python app: AttributeError: 'module' object has no attribute 'HTTPSHandler' UPDATE: Just checked whether SSL actually installed as a result of those commands by typing this: $ python2.5 Python 2.5.5 (r255:77872, Apr 29 2010, 23:59:20) [GCC 4.4.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import ssl Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named ssl >>> As you can see, SSL is still not installed, which explains the continuing App Engine error. If anyone knows how I can dig myself out of this hole, I would appreciate it.

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• Multiple websites, Single sign-on design

  - by Yannis

  Hi all, I have a question. A client I have been doing some work recently has a range of websites with different login mechanisms. He is looking to slowly migrate to a single sign-on mechanism for his websites (all written in asp.net mvc). I am looking at my options here, so here is a list of requirements: 1) It has to be secure (duh) 2) It needs to support extra user properties over and above the usual name, address stuff (such as money or credits for a user) 3) It has to provide a centralized user management web console for his convenience (I understand that this will be a small project on top of whatever design solution I choose to go for) 4) It has to integrate with the existing websites without re-engineering the whole product (I understand that this depends on the current product implementation). 5) It has to deal with emailing the user when he registers (in order for him to activate his account) 6) It has to deal with activating the user when he clicks the activate me link in the email (I understand that 5 and 6 require some form of email templating system to support different emails per application) I was thinking of creating a library working together with forms authentication that exposes whatever methods are required (e.g. login, logout, activate, etc. and a small restful service to implement activation from email, registration processing etc. Taking into account that loads of things have been left out to make this question brief and to the point, does this sound like a good design? But this looks like a very common problem so arent there any existing projects that I could use? Thanks for reading.

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• Macports and virtualenv site-packages Fallback

  - by Streeter

  I've installed django and python as this link suggested with macports. However, I'd like to use virtualenv to install more packages. My understanding is that if I do not pass in the --no-site-packages to virtualenv, I should get the currently installed packages in addition to whatever packages I install into the virtual environment. Is this correct? As an example, I've installed django through macports and then create a virtual environment, but I cannot import django from within that virtual environment: [streeter@mordecai]:~$ mkvirtualenv django-test New python executable in django-test/bin/python Installing setuptools............done. ... (django-test)[streeter@mordecai]:~$ pip install django-debug-toolbar Downloading/unpacking django-debug-toolbar Downloading django-debug-toolbar-0.8.4.tar.gz (80Kb): 80Kb downloaded Running setup.py egg_info for package django-debug-toolbar Installing collected packages: django-debug-toolbar Running setup.py install for django-debug-toolbar Successfully installed django-debug-toolbar Cleaning up... (django-test)[streeter@mordecai]:~$ python Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import django Traceback (most recent call last): File "<stdin>", line 1, in <module> ImportError: No module named django >>> So I can install packages into the virtual environment, but it isn't picking up the global site-packages. Or am I not doing something correctly / missing something / misunderstanding how virtualenv works? I've got Mac OS 10.6 (Snow Leopard), have updated my macports packages and am using macports' python26 (via python_select python26).

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• Why can't I display a unicode character in the Python Interpreter on Mac OS X Terminal.app?

  - by apphacker

  If I try to paste a unicode character such as the middle dot: · in my python interpreter it does nothing. I'm using Terminal.app on Mac OS X and when I'm simply in in bash I have no trouble: :~$ · But in the interpreter: :~$ python Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> ^^ I get nothing, it just ignores that I just pasted the character. If I use the escape \xNN\xNN representation of the middle dot '\xc2\xb7', and try to convert to unicode, trying to show the dot causes the interpreter to throw an error: >>> unicode('\xc2\xb7') Traceback (most recent call last): File "<stdin>", line 1, in <module> UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 0: ordinal not in range(128) I have setup 'utf-8' as my default encoding in sitecustomize.py so: >>> sys.getdefaultencoding() 'utf-8' What gives? It's not the Terminal. It's not Python, what am I doing wrong?! This question is not related to this question, as that indivdiual is able to paste unicode into his Terminal.

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• pythonpath issue? "python2.5: can't open file 'dev_appserver.py': [Errno 2] No such file or director

  - by Linc

  I added this line to my .bashrc (Ubuntu 9.10): export PYTHONPATH=/opt/google_appengine/ And then I ran the dev_appserver through python2.5 on Ubuntu like this: $ python2.5 dev_appserver.py guestbook/ python2.5: can't open file 'dev_appserver.py': [Errno 2] No such file or directory As you can see, it can't find dev_appserver.py even though it's in my /opt/google_appengine/ directory. Just to make sure it's not a permissions issue I did this: sudo chmod a+rwx dev_appserver.py To check whether it's been added to the system path for python2.5 I did this: $ python2.5 Python 2.5.5 (r255:77872, Apr 29 2010, 23:59:20) [GCC 4.4.1] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> for line in sys.path: print line ... /usr/local/lib/python2.5/site-packages/setuptools-0.6c9-py2.5.egg /opt/google_appengine/demos /opt/google_appengine /usr/local/lib/python25.zip ... The directory shows up in this list so I don't understand why it can't be found when I type: $ python2.5 dev_appserver.py guestbook/ I'm new to Python so I would appreciate any help. Thanks.

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• Django: DatabaseError column does not exist

  - by Rosarch

  I'm having a problem with Django 1.2.4. Here is a model: class Foo(models.Model): # ... ftw = models.CharField(blank=True) bar = models.ForeignKey(Bar) Right after flushing the database, I use the shell: Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from apps.foo.models import Foo >>> Foo.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 67, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 82, in __len__ self._result_cache.extend(list(self._iter)) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 271, in iterator for row in compiler.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 677, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 732, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 15, in execute return self.cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) DatabaseError: column foo_foo.bar_id does not exist LINE 1: ...t_omg", "foo_foo"."ftw", "foo_foo... What am I doing wrong here?

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• Find the order among tasks in a company by using prolog?

  - by Cem

  First of all,I wish a happy new year for everyone.I searched more and worked a lot but I could not solve this question.I am quite a new in prolog and I must do this homework. In my homework,the question is like this: Write a prolog program that determines a valid order for the tasks to be carried out in a company. The prolog program will consist of a set of "before" predicates which denotes the order between task pairs. Here is an example; before(a,b). before(a,e). before(d,c). before(b,c). before(c,e). Here, task a should be carried before tasks b and e, d before c and so on. Hence a valid ordering of the tasks would be [a, b, d, c, e]. The order predicate in your program will be queried as follows. ?- order([a,b,c,d,e],X). X = [a, b, d, c, e] ; X = [a, d, b, c, e] ; X = [d, a, b, c, e] ; false. Hint: Try to generate different orders for the tasks (permutation) and then check if the order is consistent with the "before" relationships given. Even if you can generate a single valid order, you will get reasonable partial credits.

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• Python base classes share attributes?

  - by tad

  Code in test.py: class Base(object): def __init__(self, l=[]): self.l = l def add(self, num): self.l.append(num) def remove(self, num): self.l.remove(num) class Derived(Base): def __init__(self, l=[]): super(Derived, self).__init__(l) Python shell session: Python 2.6.5 (r265:79063, Apr 1 2010, 05:22:20) [GCC 4.4.3 20100316 (prerelease)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> import test >>> a = test.Derived() >>> b = test.Derived() >>> a.l [] >>> b.l [] >>> a.add(1) >>> a.l [1] >>> b.l [1] >>> c = test.Derived() >>> c.l [1] I was expecting "C++-like" behavior, in which each derived object contains its own instance of the base class. Is this still the case? Why does each object appear to share the same list instance?

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• Cocos2d and MPMoviePlayerViewController - NSNotificationCenter not working

  - by digi_0315

  I'm using cocos2d with MPMoviePlayerViewController class, but when I tryed to catch notification status when the movie is finished I got this error: Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[NSCFString movieFinishedCallback]: unrecognized selector sent to instance 0x5d23730' my playVideoController.m are: @implementation PlayVideoViewController +(id) scene{ CCScene *scene = [CCScene node]; CCLayer *layer = [credits node]; [scene addChild: layer]; return scene; } -(id)initWithPath:(NSString *)moviePath{ if ((self = [super init])){ movieURL = [NSURL fileURLWithPath:moviePath]; [movieURL retain]; playerViewController = [[MPMoviePlayerViewController alloc] initWithContentURL:movieURL]; player = [playerViewController moviePlayer]; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(movieFinishedCallback) name:MPMoviePlayerPlaybackDidFinishNotification object:player]; [[[CCDirector sharedDirector] openGLView] addSubview:playerViewController.view]; [player play]; } return self; } -(void)movieFinishedCallback{ CCLOG(@"video finished!!"); } in .h: #import <UIKit/UIKit.h> #import "cocos2d.h" #import <MediaPlayer/MediaPlayer.h> @interface PlayVideoViewController : CCLayer { NSURL *movieURL; MPMoviePlayerViewController *playerViewController; MPMoviePlayerController *player; } +(id) scene; @end and I call it in appDelegate.m: - (void) applicationDidFinishLaunching:(UIApplication*)application { CC_DIRECTOR_INIT(); CCDirector *director = [CCDirector sharedDirector]; [director setDeviceOrientation:kCCDeviceOrientationLandscapeLeft]; EAGLView *glView = [director openGLView]; [glView setMultipleTouchEnabled:YES]; [CCTexture2D setDefaultAlphaPixelFormat:kTexture2DPixelFormat_RGBA8888];//kEAGLColorFormatRGBA8 NSString *path = [[NSBundle mainBundle] pathForResource:@"intro" ofType:@"mov" inDirectory:nil]; vi ewController = [[[PlayVideoViewController alloc] initWithPath:path] autorelease]; } what i'm doing wrong? anyone can help me please?? I'm try to solve it since a lot of hours ago but I can't!

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• Python Interactive Interpreter always returns "Invalid syntax" on Windows

  - by user559217

  I've encountered an extremely confusing problem. Whatever I type into the Python interpreter returns "Invalid Syntax". See examples below. I've tried fooling around with the code page of the prompt I run the interpreter from, but it doesn't seem to help at all. Furthermore, I haven't been able to find this particular, weird bug elsewhere online. Any assistance anyone could provide would be lovely. I've already tried reinstalling Python, but I didn't have any luck - the problem is also there in both 3.13 and 2.7. Running: Python version 3.1.3, Windows XP SP3. Getting: C:\Program Files\Python31>.\python Python 3.1.3 (r313:86834, Nov 27 2010, 18:30:53) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. >>> 2+2 File "<stdin>", line 1 2+2 ^ SyntaxError: invalid syntax >>> x = "Oh, fiddlesticks." File "<stdin>", line 1 x = "Oh, fiddlesticks." ^ SyntaxError: invalid syntax

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• Jython & Mysql - what is the current practice for connection?

  - by Sector7B

  Just trying jython for the first time, because something came up at work that would fit for this perfect for it. I assume jython can make mysql jdbc connection using the mysql jdbc driver. After googling and reading, however I am having problems and it seems jython specific and probably simple. so i do jython: Jython 2.5.1 (Release_2_5_1:6813, Sep 26 2009, 13:47:54) [Java HotSpot(TM) 64-Bit Server VM (Apple Inc.)] on java1.6.0_17 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/JYTHONPATH/mysql-connector-java-5.1.10-bin.jar', '/WorkArea/Apps/jython/jython2.5.1/Lib', '__classpath__', '__pyclasspath__/', '/WorkArea/Apps/jython/jython2.5.1/Lib/site-packages'] >>> code i'm running from java.lang import * from java.sql import * driverName="com.mysql.jdbc.Driver" Class.forName(driverName) url = "jdbc:mysql://localhost/test?user=jgreenaw&password=" con = DriverManager.getConnection(url) stmt = con.createStatement() output riux:Desktop$ jython pymysql.py Traceback (most recent call last): File "pymysql.py", line 7, in <module> Class.forName(driverName) at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) java.lang.ClassNotFoundException: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver any advice? thanks

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• Has anyone ever had OpenCV work with Python 2.7 on MacOS 10.6?

  - by ?????

  I've been trying on and off for the past 6 months to get OpenCV to work with Python on MacOS. Every time there's a new release, I try again and fail. I've tried both 64-bit and 32-bit, and both the xcode gcc and gcc installed via macports. I just spend the past two days on it, hopeful that the latest OpenCV release, that appears to include Python support directly would work. It doesn't. I've also tried and failed to use this: http://code.google.com/p/pyopencv/ I've been using OpenCV with C++ or Microsoft C++/CLI for the past few years, but I'd love to use it with Python on a Mac because that is my primary development environment. I'd love to hear from anyone who's actually been able to get the opencv python examples to run under Mac OS 10.6, either 32 or 64-bit. My last attempt was to follow the instructions on this page http://recursive-design.com/blog/2010/12/14/face-detection-with-osx-and-python/ with a clean, fresh install of 10.6 on a 64-bit capable Mac. My PYTHONPATH is set, and I can see the cv library in it. But an "import cv" from python fails. Previously, the closest I've ever gotten (again, staring on a clean, fresh 10.6 install) was this: Python 2.7.1 (r271:86882M, Nov 30 2010, 10:35:34) [GCC 4.2.1 (Apple Inc. build 5664)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import cv Fatal Python error: Interpreter not initialized (version mismatch?) Abort trap thrilllap-2:~ swirsky$ I've seen a lot of folks answering similar questions here, but have never seen an definitive answer for it.

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• Open Source Licenses, which one?

  - by sam

  recently I created a java class " Custom Layout Manager ", which I want to make it open-source and distribute it. So it's not really a "product", nor a "complete program". Here's the list of permissions and specifications: You are free to use and modify with some limitations (packages and classes names, should remain the same, if you want another name, extend this class. - The .jar file, project name is ok to change). You don't need to share your modifications. You can't modify and then sell it to others. You can use it as part of your commercial software (For example: It's OK if: you created an instant messaging program, that uses my "Layout", since your "core bussiness" isn't the "Layout", but the msg program. It's NOT OK if: you created another "Layout" by extending it, added some features and sell it.) You can't remove the author's name nor the author's website address. You are free to donate. :D Basically, it's free and it's Ok as you give me credits and don't make money with it. I guess it might be a little bit complex, since you use it "commercially" but cannot sell it separately. I have seeked almost all the licenses, and the closest one was MIT license, but it says that you can sell it, so I don't really want to use this one. Is there any license that fits all these permissions I stated? Thanks.

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• Supervisord appears to be running, but monitored programs aren't launched

  - by Brad Montgomery

  I've got supervisord 3.0a8 installed from the system package on ubuntu 10.04 (64bit). The supervisor service appears to be running, but it's not launching the configured programs. Interestingly enough, this exact configuration is running on another system, and is working as expected. The main config file looks like this: ; /etc/supervisor/supervisord.conf [unix_http_server] chmod=0700 file=/var/run/supervisor.sock [supervisord] logfile=/var/log/supervisor/supervisord.log childlogdir=/var/log/supervisor pidfile=/var/run/supervisord.pid [rpcinterface:supervisor] supervisor.rpcinterface_factory = supervisor.rpcinterface:make_main_rpcinterface [supervisorctl] serverurl=unix:///var/run/supervisor.sock [include] files = /etc/supervisor/conf.d/*.conf A sample program config looks like this: ; /etc/supervisor/conf.d/sample.conf [program:sample] directory=/opt/sample command=/opt/sample/run.sh Where, the /opt/sample/run.sh is: #!/bin/bash while true; do T=`date` echo "[$T] Running!" >> /var/log/sample.log sleep 1 done And, here's some additional information regarding the running instance of supervisord: root@myhost:~# supervisorctl version 3.0a8 root@myhost:~# which supervisorctl /usr/bin/supervisorctl root@myhost:~# which supervisord /usr/bin/supervisord root@myhost:~# supervisorctl status # NOTE that there's no output! root@myhost:~# supervisorctl avail root@myhost:~# service supervisor status is running root@myhost:~# ps aux | grep supervisor root 21740 0.1 0.4 40772 10056 ? Ss 11:28 0:00 /usr/bin/python /usr/bin/supervisord root 21749 0.0 0.0 7624 932 pts/2 S+ 11:28 0:00 grep --color=auto supervisor root@myhost:~# cat /var/log/supervisor/supervisord.log 2012-04-26 11:28:22,483 CRIT Supervisor running as root (no user in config file) 2012-04-26 11:28:22,536 INFO RPC interface 'supervisor' initialized 2012-04-26 11:28:22,536 WARN cElementTree not installed, using slower XML parser for XML-RPC 2012-04-26 11:28:22,536 CRIT Server 'unix_http_server' running without any HTTP authentication checking 2012-04-26 11:28:22,539 INFO daemonizing the supervisord process 2012-04-26 11:28:22,539 INFO supervisord started with pid 21740 root@myhost:~# ll /etc/supervisor/conf.d/ total 28 drwxr-xr-x 2 root root 4096 2012-04-26 11:31 ./ drwxr-xr-x 3 root root 4096 2012-04-25 18:38 ../ -rw-r--r-- 1 root root 66 2012-04-26 11:31 sample.conf root@myhost:~# ll /opt/sample/ total 12 drwxr-xr-x 2 root root 4096 2012-04-26 11:32 ./ drwxr-xr-x 4 root root 4096 2012-04-26 11:31 ../ -rwxr-xr-x 1 root root 97 2012-04-26 11:32 run.sh* root@myhost:~# python Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> Any help is greatly appreciated!

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• how to diagnosis and resolve: /usr/lib64/libz.so.1: no version information available

  - by matchew

  I had a hell of a time installing lxml for python2.7 on centOs5.6. For some background, python2.7 is an alternative installation of python on centOS5.6 which comes with python2.4 installed. it was bulit from source per its instrucitons ./configure make make altinstall However, after about 20 hours of trying I managed to find a workable solution and was able to install lxml. Until, I notice the following error at the top of the interpreter: python2.7: /usr/lib64/libz.so.1: no version information available (required by python2.7) Python 2.7.2 (default, Jun 30 2011, 18:55:26) [GCC 4.1.2 20080704 (Red Hat 4.1.2-50)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> print 'Sheeeeut!' this error is printed out everytime I run a script. For example: $ ./test.py /usr/local/bin/python2.7: /usr/lib64/libz.so.1: no version information available (required by /usr/local/bin/python2.7) the script runs flawlessly, but this error is bothersome. After some digging I have seem to believe I have a wrong version of libz installed, that it is either an older version or built for a different platform. I'm not quite sure how, I've only installed libz through yum, as far as I know. Although, I can't quite remember every little thing I tried in my twenty hours of trying. You may also be intereted in what my lib64 folder looks like, here is some information $ ls -ltrh libz* -rwxr-xr-x 1 root root 84K Jan 9 2007 libz.so.1.2.3 -rwxr-xr-x 1 root root 107K Jan 9 2007 libz.a -rwxr-xr-x 1 root root 154K Feb 22 23:30 libzdb.so.7.0.2 lrwxrwxrwx 1 root root 13 Apr 20 20:46 libz.so.1 -> libz.so.1.2.3 lrwxrwxrwx 1 root root 15 Jun 30 18:43 libzdb.so.7 -> libzdb.so.7.0.2 lrwxrwxrwx 1 root root 13 Jul 1 11:35 libz.so -> libz.so.1.2.3 lrwxrwxrwx 1 root root 15 Jul 1 11:35 libzdb.so -> libzdb.so.7.0.2 notice: the items that Say Jul 1st or Jun 30th are from me. I had initially moved these files into a backup folder as they seeemed to be 1. duplicates and 2. had a date after/during my problems I alluded to earlier that I had with lxml One inclination is to completely remove python2.7 and re-install. I think having it install to /usr/local/ was a poor default choice. However, without the make uninstall option being present it seems to be a time consuming task for a solution I am not quite sure would solve my problem.

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