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  • How do you printf an unsigned long long int?

    - by superjoe30
    #include <stdio.h>int main() { unsigned long long int num = 285212672; //FYI: fits in 29 bits int normalInt = 5; printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt); return 0;} Output: My number is 8 bytes wide and its value is 285212672l. A normal number is 0. I assume this unexpected result is from printing the unsigned long long int. How do you printf an unsigned long long int?

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  • How is conversion of float/double to int handled in printf?

    - by Sandip
    Consider this program int main() { float f = 11.22; double d = 44.55; int i,j; i = f; //cast float to int j = d; //cast double to int printf("i = %d, j = %d, f = %d, d = %d", i,j,f,d); //This prints the following: // i = 11, j = 44, f = -536870912, d = 1076261027 return 0; } Can someone explain why the casting from double/float to int works correctly in the first case, and does not work when done in printf? This program was compiled on gcc-4.1.2 on 32-bit linux machine.

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  • How to debug/reformat C printf calls with lots of arguments in vim?

    - by Costi
    I have a function call in a program that I'm maintaining has 28 arguments for a printf call. It's printing a lot of data in a CSV file. I have problems following finding where what goes and I have some mismatches in the parameters types. I enabled -Wall in gcc and I get warnings like: n.c:495: warning: int format, pointer arg (arg 15) n.c:495: warning: format argument is not a pointer (arg 16) n.c:495: warning: double format, pointer arg (arg 23) The function is like this: fprintf (ConvFilePtr, "\"FORMAT3\"%s%04d%s%04d%s%s%s%d%s%c%s%d%c%s%s%s%s%s%s%s%11.lf%s%11.lf%s%11.lf%s%d\n", some_28_arguments_go_here); I would like to know if there is a vim plugin that highlights the printf format specifier when i go with the cursor over a variable. Other solutions? How to better reformat the code to make it more readable?

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  • How is prinf() implemented in c?

    - by Mask
    Disassembling printf doesn't give much info: (gdb) disas printf Dump of assembler code for function printf: 0x00401b38 <printf+0>: jmp *0x405130 0x00401b3e <printf+6>: nop 0x00401b3f <printf+7>: nop End of assembler dump. How is it implemented under the hood?

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  • Printing double variable contents

    - by Adil
    I tried following code snippet and output is surprising me: #include <stdio.h> #include <math.h> int main() { double num; unsigned char ch; ch = 19; num = 1.0E+20 ; num += ch * 1.0E+18; printf("E18 = %lf \n",num); printf("E18 = %e \n",num); num = 11.0E+21 ; num += ch * 1.0E+19; printf("E19 = %lf <------\n",num); printf("E19 = %e <------\n",num); num = 11.0E+22 ; num += ch * 1.0E+20; printf("E20 = %lf\n",num); printf("E20 = %e\n",num); num = 11.0E+23 ; num += ch * 1.0E+21; printf("E21 = %lf\n",num); printf("E21 = %e\n",num); num = 11.0E+24 ; num += ch * 1.0E+22; printf("E22 = %lf <------\n",num); printf("E22 = %e <------\n",num); return 0; } The output of the program: E18 = 119000000000000000000.000000 E18 = 1.190000e+20 E19 = 11190000000000000524288.000000 <------ E19 = 1.119000e+22 <------ E20 = 111900000000000001048576.000000 E20 = 1.119000e+23 E21 = 1119000000000000044040192.000000 E21 = 1.119000e+24 E22 = 11189999999999999366660096.000000 <------ E22 = 1.119000e+25 <------ Why the data corrupted when printed while in exponent form its OK

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  • C socket programming: connect() hangs

    - by Fantastic Fourier
    Hey all, I'm about to rip my hair out. I have this client that tries to connect to a server, everything seems to be fine, using gethostbyname(), socket(), bind(), but when trying toconnect()` it just hangs there and the server doesn't see anything from the client. I know that the server works because another client (also in C) can connect just fine. What causes the server to not see this incoming connection? I'm at the end of my wits here. The two different clients are pretty similar too so I'm even more lost. if (argc == 2) { host = argv[1]; // server address } else { printf("plz read the manual\n"); exit(1); } hserver = gethostbyname(host); if (hserver) { printf("host found: %p\n", hserver); printf("host found: %s\n", hserver->h_name ); } else { printf("host not found\n"); exit(1); } bzero((char * ) &server_address, sizeof(server_address)); // copy zeroes into string server_address.sin_family = AF_INET; server_address.sin_addr.s_addr = htonl(hserver->h_addr); server_address.sin_port = htons(SERVER_PORT); bzero((char * ) &client_address, sizeof(client_address)); // copy zeroes into string client_address.sin_family = AF_INET; client_address.sin_addr.s_addr = htonl(INADDR_ANY); client_address.sin_port = htons(SERVER_PORT); sockfd = socket(AF_INET, SOCK_STREAM, 0); if (sockfd < 0) exit(1); else { printf("socket is opened: %i \n", sockfd); info.sock_fd = sockfd; rv = fcntl(sockfd, F_SETFL, O_NONBLOCK); // socket set to NONBLOCK if(rv < 0) printf("nonblock failed: %i %s\n", errno, strerror(errno)); else printf("socket is set nonblock\n"); } timeout.tv_sec = 0; // seconds timeout.tv_usec = 500000; // micro seconds ( 0.5 seconds) setsockopt(sockfd, SOL_SOCKET, SO_RCVTIMEO, &timeout, sizeof(struct timeval)); rv = bind(sockfd, (struct sockaddr *) &client_address, sizeof(client_address)); if (rv < 0) { printf("MAIN: ERROR bind() %i: %s\n", errno, strerror(errno)); exit(1); } else printf("socket is bound\n"); rv = connect(sockfd, (struct sockaddr *) &server_address, sizeof(server_address)); printf("rv = %i\n", rv); if (rv < 0) { printf("MAIN: ERROR connect() %i: %s\n", errno, strerror(errno)); exit(1); } else printf("connected\n"); Any thoughts or insights are deeply greatly humongously appreciated. -Fourier

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  • escape sequence in c

    - by prp
    int main() { char *arr="\\0\1\8234\0"; int i=0; while(arr[i]) { switch(arr[i]) { case '0': printf("is no"); break; case '00': printf("is debugging\n"); break; case 0: printf("It is Avishkar\n"); break; case '\\': printf("This "); break; case '\1': printf("t s"); break; case '8': printf("o s"); break; case '2': printf("imp"); break; case '3': printf("le as"); break; case 2: case 3: case 4: case 8: printf("This "); break; default: printf(" it seems\n"); break;} i++; } } please explain the o/p ? i am not able to get it..

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  • C socket programming: select() is returning 0 despite messages sent from server

    - by Fantastic Fourier
    Hey all, I'm using select() to recv() messages from server, using TCP/IP. When I send() messages from the server, it returns a reasonable number of bytes, saying it's sent successful. And it does get to the client successfully when I use while loop to just recv(). Everything is fine and dandy. while(1) recv() // obviously pseudocode However, when I try to use select(), select() returns 0 from timeout (which is set to 1 second) and for the life of me I cannot figure out why it doesn't see the messages sent from the server. I should also mention that when the server disconnects, select() doesn't see that either, where as if I were to use recv(), it would return 0 to indicate that the connection using the socket has been closed. Any inputs or thoughts are deeply appreciated. #include <arpa/inet.h> #include <errno.h> #include <fcntl.h> #include <netdb.h> #include <netinet/in.h> #include <pthread.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <strings.h> #include <sys/select.h> #include <sys/socket.h> #include <sys/time.h> #include <sys/types.h> #include <time.h> #include <unistd.h> #define SERVER_PORT 10000 #define MAX_CONNECTION 20 #define MAX_MSG 50 struct client { char c_name[MAX_MSG]; char g_name[MAX_MSG]; int csock; int host; // 0 = not host of a multicast group struct sockaddr_in client_address; struct client * next_host; struct client * next_client; }; struct fd_info { char c_name[MAX_MSG]; int socks_inuse[MAX_CONNECTION]; int sock_fd, max_fd; int exit; struct client * c_sys; struct sockaddr_in c_address[MAX_CONNECTION]; struct sockaddr_in server_address; struct sockaddr_in client_address; fd_set read_set; }; struct message { char c_name[MAX_MSG]; char g_name[MAX_MSG]; char _command[3][MAX_MSG]; char _payload[MAX_MSG]; struct sockaddr_in client_address; struct client peer; }; int main(int argc, char * argv[]) { char * host; char * temp; int i, sockfd; int msg_len, rv, ready; int connection, management, socketread; int sockfds[MAX_CONNECTION]; // for three threads that handle new connections, user inputs and select() for sockets pthread_t connection_handler, manager, socket_reader; struct sockaddr_in server_address, client_address; struct hostent * hserver, cserver; struct timeval timeout; struct message msg; struct fd_info info; info.exit = 0; // exit information: if exit = 1, threads quit info.c_sys = NULL; // looking up from the host database if (argc == 3) { host = argv[1]; // server address strncpy(info.c_name, argv[2], strlen(argv[2])); // client name } else { printf("plz read the manual, kthxbai\n"); exit(1); } printf("host is %s and hp is %p\n", host, hserver); hserver = gethostbyname(host); if (hserver) { printf("host found: %s\n", hserver->h_name ); } else { printf("host not found\n"); exit(1); } // setting up address and port structure information on serverside bzero((char * ) &server_address, sizeof(server_address)); // copy zeroes into string server_address.sin_family = AF_INET; memcpy(&server_address.sin_addr, hserver->h_addr, hserver->h_length); server_address.sin_port = htons(SERVER_PORT); bzero((char * ) &client_address, sizeof(client_address)); // copy zeroes into string client_address.sin_family = AF_INET; client_address.sin_addr.s_addr = htonl(INADDR_ANY); client_address.sin_port = htons(SERVER_PORT); // opening up socket sockfd = socket(AF_INET, SOCK_STREAM, 0); if (sockfd < 0) exit(1); else { printf("socket is opened: %i \n", sockfd); info.sock_fd = sockfd; } // sets up time out option for the bound socket timeout.tv_sec = 1; // seconds timeout.tv_usec = 0; // micro seconds ( 0.5 seconds) setsockopt(sockfd, SOL_SOCKET, SO_RCVTIMEO, &timeout, sizeof(struct timeval)); // binding socket to a port rv = bind(sockfd, (struct sockaddr *) &client_address, sizeof(client_address)); if (rv < 0) { printf("MAIN: ERROR bind() %i: %s\n", errno, strerror(errno)); exit(1); } else printf("socket is bound\n"); printf("MAIN: %li \n", client_address.sin_addr.s_addr); // connecting rv = connect(sockfd, (struct sockaddr *) &server_address, sizeof(server_address)); info.server_address = server_address; info.client_address = client_address; info.sock_fd = sockfd; info.max_fd = sockfd; printf("rv = %i\n", rv); if (rv < 0) { printf("MAIN: ERROR connect() %i: %s\n", errno, strerror(errno)); exit(1); } else printf("connected\n"); fd_set readset; FD_ZERO(&readset); FD_ZERO(&info.read_set); FD_SET(info.sock_fd, &info.read_set); while(1) { readset = info.read_set; printf("MAIN: %i \n", readset); ready = select((info.max_fd)+1, &readset, NULL, NULL, &timeout); if(ready == -1) { sleep(2); printf("TEST: MAIN: ready = -1. %s \n", strerror(errno)); } else if (ready == 0) { sleep(2); printf("TEST: MAIN: ready = 0. %s \n", strerror(errno)); } else if (ready > 0) { printf("TEST: MAIN: ready = %i. %s at socket %i \n", ready, strerror(errno), i); for(i = 0; i < ((info.max_fd)+1); i++) { if(FD_ISSET(i, &readset)) { rv = recv(sockfd, &msg, 500, 0); if(rv < 0) continue; else if(rv > 0) printf("MAIN: TEST: %s %s \n", msg._command[0], msg._payload); else if (rv == 0) { sleep(3); printf("MAIN: TEST: SOCKET CLOSEDDDDDD \n"); } FD_CLR(i, &readset); } } } info.read_set = readset; } // close connection close(sockfd); printf("socket closed. BYE! \n"); return(0); }

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  • C Named pipe (fifo). Parent process gets stuck

    - by Blitzkr1eg
    I want to make a simple program, that fork, and the child writes into the named pipe and the parent reads and displays from the named pipe. The problem is that it enters the parent, does the first printf and then it gets weird, it doesn't do anything else, does not get to the second printf, it just ways for input in the console. #include <string.h> #include <stdlib.h> #include <stdio.h> #include <unistd.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> void main() { char t[100]; mkfifo("myfifo",777); pid_t pid; pid = fork(); if (pid==0) { //execl("fifo2","fifo2",(char*)0); char r[100]; printf("scrie2->"); scanf("%s",r); int fp; fp = open("myfifo",O_WRONLY); write(fp,r,99); close(fp); printf("exit kid \n"); exit(0); } else { wait(0); printf("entered parent \n"); // <- this it prints // whats below this line apparently its not being executed int fz; printf("1"); fz = open("myfifo",O_RDONLY); printf("2"); printf("fd: %d",fz); char p[100]; int size; printf("------"); //struct stat *info; //stat("myfifo",info); printf("%d",(*info).st_size); read(fz,p,99); close(fz); printf("%s",p); printf("exit"); exit(0); } }

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  • Function not returning value at all - not a void [migrated]

    - by user105439
    I have this function that is not returning a function value. I've added some random testers to try and debug but no luck. Thanks! #include <stdio.h> #include <math.h> #include <time.h> #define N 100 float error(int a, int b); int main(){ printf("START\n"); srand(time(NULL)); int a, b, j, m; float plot[N+1]; printf("Lower bound for x: "); scanf("%d", &a); printf("Upper bound for x: "); scanf("%d", &b); printf("okay\n"); for(j = 0; j < N; j++) plot[j] = 0; printf("okay1\n"); m = error(a,b); printf("%f\n",m); return 0; } float error(int a, int b){ float product = a*b; printf("%f\n",product); return product; } so the m = error(a,b) always gives 0 no matter what! Please help. I apologise for not cleaning this up...

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  • Insight into how things get printed onto the screen (cout,printf) and origin of really complex stuff

    - by sil3nt
    I've always wondered this, and still haven't found the answer. Whenever we use "cout" or "printf" how exactly is that printed on the screen?. How does the text come out as it does...(probably quite a vague question here, ill work with whatever you give me.). So basically how are those functions made?..is it assembly?, if so where does that begin?. This brings on more questions like how on earth have they made openGl/directx functions.. break it down people break it down.:)

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  • Solaris X86 64-bit Assembly Programming

    - by danx
    Solaris X86 64-bit Assembly Programming This is a simple example on writing, compiling, and debugging Solaris 64-bit x86 assembly language with a C program. This is also referred to as "AMD64" assembly. The term "AMD64" is used in an inclusive sense to refer to all X86 64-bit processors, whether AMD Opteron family or Intel 64 processor family. Both run Solaris x86. I'm keeping this example simple mainly to illustrate how everything comes together—compiler, assembler, linker, and debugger when using assembly language. The example I'm using here is a C program that calls an assembly language program passing a C string. The assembly language program takes the C string and calls printf() with it to print the string. AMD64 Register Usage But first let's review the use of AMD64 registers. AMD64 has several 64-bit registers, some special purpose (such as the stack pointer) and others general purpose. By convention, Solaris follows the AMD64 ABI in register usage, which is the same used by Linux, but different from Microsoft Windows in usage (such as which registers are used to pass parameters). This blog will only discuss conventions for Linux and Solaris. The following chart shows how AMD64 registers are used. The first six parameters to a function are passed through registers. If there's more than six parameters, parameter 7 and above are pushed on the stack before calling the function. The stack is also used to save temporary "stack" variables for use by a function. 64-bit Register Usage %rip Instruction Pointer points to the current instruction %rsp Stack Pointer %rbp Frame Pointer (saved stack pointer pointing to parameters on stack) %rdi Function Parameter 1 %rsi Function Parameter 2 %rdx Function Parameter 3 %rcx Function Parameter 4 %r8 Function Parameter 5 %r9 Function Parameter 6 %rax Function return value %r10, %r11 Temporary registers (need not be saved before used) %rbx, %r12, %r13, %r14, %r15 Temporary registers, but must be saved before use and restored before returning from the current function (usually with the push and pop instructions). 32-, 16-, and 8-bit registers To access the lower 32-, 16-, or 8-bits of a 64-bit register use the following: 64-bit register Least significant 32-bits Least significant 16-bits Least significant 8-bits %rax%eax%ax%al %rbx%ebx%bx%bl %rcx%ecx%cx%cl %rdx%edx%dx%dl %rsi%esi%si%sil %rdi%edi%di%axl %rbp%ebp%bp%bp %rsp%esp%sp%spl %r9%r9d%r9w%r9b %r10%r10d%r10w%r10b %r11%r11d%r11w%r11b %r12%r12d%r12w%r12b %r13%r13d%r13w%r13b %r14%r14d%r14w%r14b %r15%r15d%r15w%r15b %r16%r16d%r16w%r16b There's other registers present, such as the 64-bit %mm registers, 128-bit %xmm registers, 256-bit %ymm registers, and 512-bit %zmm registers. Except for %mm registers, these registers may not present on older AMD64 processors. Assembly Source The following is the source for a C program, helloas1.c, that calls an assembly function, hello_asm(). $ cat helloas1.c extern void hello_asm(char *s); int main(void) { hello_asm("Hello, World!"); } The assembly function called above, hello_asm(), is defined below. $ cat helloas2.s /* * helloas2.s * To build: * cc -m64 -o helloas2-cpp.s -D_ASM -E helloas2.s * cc -m64 -c -o helloas2.o helloas2-cpp.s */ #if defined(lint) || defined(__lint) /* ARGSUSED */ void hello_asm(char *s) { } #else /* lint */ #include <sys/asm_linkage.h> .extern printf ENTRY_NP(hello_asm) // Setup printf parameters on stack mov %rdi, %rsi // P2 (%rsi) is string variable lea .printf_string, %rdi // P1 (%rdi) is printf format string call printf ret SET_SIZE(hello_asm) // Read-only data .text .align 16 .type .printf_string, @object .printf_string: .ascii "The string is: %s.\n\0" #endif /* lint || __lint */ In the assembly source above, the C skeleton code under "#if defined(lint)" is optionally used for lint to check the interfaces with your C program--very useful to catch nasty interface bugs. The "asm_linkage.h" file includes some handy macros useful for assembly, such as ENTRY_NP(), used to define a program entry point, and SET_SIZE(), used to set the function size in the symbol table. The function hello_asm calls C function printf() by passing two parameters, Parameter 1 (P1) is a printf format string, and P2 is a string variable. The function begins by moving %rdi, which contains Parameter 1 (P1) passed hello_asm, to printf()'s P2, %rsi. Then it sets printf's P1, the format string, by loading the address the address of the format string in %rdi, P1. Finally it calls printf. After returning from printf, the hello_asm function returns itself. Larger, more complex assembly functions usually do more setup than the example above. If a function is returning a value, it would set %rax to the return value. Also, it's typical for a function to save the %rbp and %rsp registers of the calling function and to restore these registers before returning. %rsp contains the stack pointer and %rbp contains the frame pointer. Here is the typical function setup and return sequence for a function: ENTRY_NP(sample_assembly_function) push %rbp // save frame pointer on stack mov %rsp, %rbp // save stack pointer in frame pointer xor %rax, %r4ax // set function return value to 0. mov %rbp, %rsp // restore stack pointer pop %rbp // restore frame pointer ret // return to calling function SET_SIZE(sample_assembly_function) Compiling and Running Assembly Use the Solaris cc command to compile both C and assembly source, and to pre-process assembly source. You can also use GNU gcc instead of cc to compile, if you prefer. The "-m64" option tells the compiler to compile in 64-bit address mode (instead of 32-bit). $ cc -m64 -o helloas2-cpp.s -D_ASM -E helloas2.s $ cc -m64 -c -o helloas2.o helloas2-cpp.s $ cc -m64 -c helloas1.c $ cc -m64 -o hello-asm helloas1.o helloas2.o $ file hello-asm helloas1.o helloas2.o hello-asm: ELF 64-bit LSB executable AMD64 Version 1 [SSE FXSR FPU], dynamically linked, not stripped helloas1.o: ELF 64-bit LSB relocatable AMD64 Version 1 helloas2.o: ELF 64-bit LSB relocatable AMD64 Version 1 $ hello-asm The string is: Hello, World!. Debugging Assembly with MDB MDB is the Solaris system debugger. It can also be used to debug user programs, including assembly and C. The following example runs the above program, hello-asm, under control of the debugger. In the example below I load the program, set a breakpoint at the assembly function hello_asm, display the registers and the first parameter, step through the assembly function, and continue execution. $ mdb hello-asm # Start the debugger > hello_asm:b # Set a breakpoint > ::run # Run the program under the debugger mdb: stop at hello_asm mdb: target stopped at: hello_asm: movq %rdi,%rsi > $C # display function stack ffff80ffbffff6e0 hello_asm() ffff80ffbffff6f0 0x400adc() > $r # display registers %rax = 0x0000000000000000 %r8 = 0x0000000000000000 %rbx = 0xffff80ffbf7f8e70 %r9 = 0x0000000000000000 %rcx = 0x0000000000000000 %r10 = 0x0000000000000000 %rdx = 0xffff80ffbffff718 %r11 = 0xffff80ffbf537db8 %rsi = 0xffff80ffbffff708 %r12 = 0x0000000000000000 %rdi = 0x0000000000400cf8 %r13 = 0x0000000000000000 %r14 = 0x0000000000000000 %r15 = 0x0000000000000000 %cs = 0x0053 %fs = 0x0000 %gs = 0x0000 %ds = 0x0000 %es = 0x0000 %ss = 0x004b %rip = 0x0000000000400c70 hello_asm %rbp = 0xffff80ffbffff6e0 %rsp = 0xffff80ffbffff6c8 %rflags = 0x00000282 id=0 vip=0 vif=0 ac=0 vm=0 rf=0 nt=0 iopl=0x0 status=<of,df,IF,tf,SF,zf,af,pf,cf> %gsbase = 0x0000000000000000 %fsbase = 0xffff80ffbf782a40 %trapno = 0x3 %err = 0x0 > ::dis # disassemble the current instructions hello_asm: movq %rdi,%rsi hello_asm+3: leaq 0x400c90,%rdi hello_asm+0xb: call -0x220 <PLT:printf> hello_asm+0x10: ret 0x400c81: nop 0x400c85: nop 0x400c88: nop 0x400c8c: nop 0x400c90: pushq %rsp 0x400c91: pushq $0x74732065 0x400c96: jb +0x69 <0x400d01> > 0x0000000000400cf8/S # %rdi contains Parameter 1 0x400cf8: Hello, World! > [ # Step and execute 1 instruction mdb: target stopped at: hello_asm+3: leaq 0x400c90,%rdi > [ mdb: target stopped at: hello_asm+0xb: call -0x220 <PLT:printf> > [ The string is: Hello, World!. mdb: target stopped at: hello_asm+0x10: ret > [ mdb: target stopped at: main+0x19: movl $0x0,-0x4(%rbp) > :c # continue program execution mdb: target has terminated > $q # quit the MDB debugger $ In the example above, at the start of function hello_asm(), I display the stack contents with "$C", display the registers contents with "$r", then disassemble the current function with "::dis". The first function parameter, which is a C string, is passed by reference with the string address in %rdi (see the register usage chart above). The address is 0x400cf8, so I print the value of the string with the "/S" MDB command: "0x0000000000400cf8/S". I can also print the contents at an address in several other formats. Here's a few popular formats. For more, see the mdb(1) man page for details. address/S C string address/C ASCII character (1 byte) address/E unsigned decimal (8 bytes) address/U unsigned decimal (4 bytes) address/D signed decimal (4 bytes) address/J hexadecimal (8 bytes) address/X hexadecimal (4 bytes) address/B hexadecimal (1 bytes) address/K pointer in hexadecimal (4 or 8 bytes) address/I disassembled instruction Finally, I step through each machine instruction with the "[" command, which steps over functions. If I wanted to enter a function, I would use the "]" command. Then I continue program execution with ":c", which continues until the program terminates. MDB Basic Cheat Sheet Here's a brief cheat sheet of some of the more common MDB commands useful for assembly debugging. There's an entire set of macros and more powerful commands, especially some for debugging the Solaris kernel, but that's beyond the scope of this example. $C Display function stack with pointers $c Display function stack $e Display external function names $v Display non-zero variables and registers $r Display registers ::fpregs Display floating point (or "media" registers). Includes %st, %xmm, and %ymm registers. ::status Display program status ::run Run the program (followed by optional command line parameters) $q Quit the debugger address:b Set a breakpoint address:d Delete a breakpoint $b Display breakpoints :c Continue program execution after a breakpoint [ Step 1 instruction, but step over function calls ] Step 1 instruction address::dis Disassemble instructions at an address ::events Display events Further Information "Assembly Language Techniques for Oracle Solaris on x86 Platforms" by Paul Lowik (2004). Good tutorial on Solaris x86 optimization with assembly. The Solaris Operating System on x86 Platforms An excellent, detailed tutorial on X86 architecture, with Solaris specifics. By an ex-Sun employee, Frank Hofmann (2005). "AMD64 ABI Features", Solaris 64-bit Developer's Guide contains rules on data types and register usage for Intel 64/AMD64-class processors. (available at docs.oracle.com) Solaris X86 Assembly Language Reference Manual (available at docs.oracle.com) SPARC Assembly Language Reference Manual (available at docs.oracle.com) System V Application Binary Interface (2003) defines the AMD64 ABI for UNIX-class operating systems, including Solaris, Linux, and BSD. Google for it—the original website is gone. cc(1), gcc(1), and mdb(1) man pages.

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  • C++ file input/output search

    - by Brian J
    Hi I took the following code from a program I'm writing to check a user generated string against a dictionary as well as other validation. My problem is that although my dictionary file is referenced correctly,the program gives the default "no dictionary found".I can't see clearly what I'm doing in error here,if anyone has any tips or pointers it would be appreciated, Thanks. //variables for checkWordInFile #define gC_FOUND 99 #define gC_NOT_FOUND -99 // static bool certifyThat(bool condition, const char* error) { if(!condition) printf("%s", error); return !condition; } //method to validate a user generated password following password guidelines. void validatePass() { FILE *fptr; char password[MAX+1]; int iChar,iUpper,iLower,iSymbol,iNumber,iTotal,iResult,iCount; //shows user password guidelines printf("\n\n\t\tPassword rules: "); printf("\n\n\t\t 1. Passwords must be at least 9 characters long and less than 15 characters. "); printf("\n\n\t\t 2. Passwords must have at least 2 numbers in them."); printf("\n\n\t\t 3. Passwords must have at least 2 uppercase letters and 2 lowercase letters in them."); printf("\n\n\t\t 4. Passwords must have at least 1 symbol in them (eg ?, $, £, %)."); printf("\n\n\t\t 5. Passwords may not have small, common words in them eg hat, pow or ate."); //gets user password input get_user_password: printf("\n\n\t\tEnter your password following password rules: "); scanf("%s", &password); iChar = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iUpper = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iLower =countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iSymbol =countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iNumber = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); iTotal = countLetters(password,&iUpper,&iLower,&iSymbol,&iNumber,&iTotal); if(certifyThat(iUpper >= 2, "Not enough uppercase letters!!!\n") || certifyThat(iLower >= 2, "Not enough lowercase letters!!!\n") || certifyThat(iSymbol >= 1, "Not enough symbols!!!\n") || certifyThat(iNumber >= 2, "Not enough numbers!!!\n") || certifyThat(iTotal >= 9, "Not enough characters!!!\n") || certifyThat(iTotal <= 15, "Too many characters!!!\n")) goto get_user_password; iResult = checkWordInFile("dictionary.txt", password); if(certifyThat(iResult != gC_FOUND, "Password contains small common 3 letter word/s.")) goto get_user_password; iResult = checkWordInFile("passHistory.txt",password); if(certifyThat(iResult != gC_FOUND, "Password contains previously used password.")) goto get_user_password; printf("\n\n\n Your new password is verified "); printf(password); //writing password to passHistroy file. fptr = fopen("passHistory.txt", "w"); // create or open the file for( iCount = 0; iCount < 8; iCount++) { fprintf(fptr, "%s\n", password[iCount]); } fclose(fptr); printf("\n\n\n"); system("pause"); }//end validatePass method int checkWordInFile(char * fileName,char * theWord){ FILE * fptr; char fileString[MAX + 1]; int iFound = -99; //open the file fptr = fopen(fileName, "r"); if (fptr == NULL) { printf("\nNo dictionary file\n"); printf("\n\n\n"); system("pause"); return (0); // just exit the program } /* read the contents of the file */ while( fgets(fileString, MAX, fptr) ) { if( 0 == strcmp(theWord, fileString) ) { iFound = -99; } } fclose(fptr); return(0); }//end of checkwORDiNFile

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  • Pointer to 2D array. Why does this example work?

    - by Louise
    I have this code example, but I don't understand why changing the values in the array inside outputUsingArray() are changing the original array. I would have expected changing the values of the array in outputUsingArray() would only be for a local copy of the array. Why isn't that so? However, this is the behaviour I would like, but I don't understand why it work. #include <stdlib.h> #include <stdio.h> void outputUsingArray(int array[][4], int n_rows, int n_cols) { int i, j; printf("Output Using array\n"); for (i = 0; i < n_rows; i++) { for (j = 0; j < n_cols; j++) { // Either can be used. //printf("%2d ", array[i][j] ); printf("%2d ", *(*(array+i)+j)); } printf("\n"); } printf("\n"); array[0][0] = 100; array[2][3] = 200; } void outputUsingPointer(int (*array)[4], int n_rows, int n_cols) { int i, j; printf("Output Using Pointer to Array i.e. int (*array)[4]\n"); for (i = 0; i < n_rows; i++) { for (j = 0; j < n_cols; j++) { printf("%2d ", *(*(array+i) + j )); } printf("\n"); } printf("\n"); } int main() { int array[3][4] = { { 0, 1, 2, 3 }, { 4, 5, 6, 7 }, { 8, 9, 10, 11 } }; outputUsingPointer((int (*)[4])array, 3, 4); outputUsingArray(array, 3, 4); printf("0,0: %i\n", array[0][0]); printf("2,3: %i\n", array[2][3]); return 0; }

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  • Program execution stop at scanf???

    - by Mohit Deshpande
    main.c (with all the headers like stdio, stdlib, etc): int main() { int input; while(1) { printf("\n"); printf("\n1. Add new node"); printf("\n2. Delete existing node"); printf("\n3. Print all data"); printf("\n4. Exit"); printf("Enter your option -> "); scanf("%d", &input); string key = ""; string tempKey = ""; string tempValue = ""; Node newNode; Node temp; switch (input) { case 1: printf("\nEnter a key: "); scanf("%s", tempKey); printf("\nEnter a value: "); scanf("%s", tempValue); //execution ternimates here newNode.key = tempKey; newNode.value = tempValue; AddNode(newNode); break; case 2: printf("\nEnter the key of the node: "); scanf("%s", key); temp = GetNode(key); DeleteNode(temp); break; case 3: printf("\n"); PrintAllNodes(); break; case 4: exit(0); break; default: printf("\nWrong option chosen!\n"); break; } } return 0; } storage.h: #ifndef DATABASEIO_H_ #define DATABASEIO_H_ //typedefs typedef char *string; /* * main struct with key, value, * and pointer to next struct * Also typedefs Node and NodePtr */ typedef struct Node { string key; string value; struct Node *next; } Node, *NodePtr; //Function Prototypes void AddNode(Node node); void DeleteNode(Node node); Node GetNode(string key); void PrintAllNodes(); #endif /* DATABASEIO_H_ */ I am using Eclipse CDT, and when I enter 1, then I enter a key. Then the console says . I used gdb and got this error: Program received signal SIGSEGV, Segmentation fault. 0x00177024 in _IO_vfscanf () from /lib/tls/i686/cmov/libc.so.6 Any ideas why?

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  • Switch case assembly level code

    - by puffadder
    Hi All, I am programming C on cygwin windows. After having done a bit of C programming and getting comfortable with the language, I wanted to look under the hood and see what the compiler is doing for the code that I write. So I wrote down a code block containing switch case statements and converted them into assembly using: gcc -S foo.c Here is the C source: switch(i) { case 1: { printf("Case 1\n"); break; } case 2: { printf("Case 2\n"); break; } case 3: { printf("Case 3\n"); break; } case 4: { printf("Case 4\n"); break; } case 5: { printf("Case 5\n"); break; } case 6: { printf("Case 6\n"); break; } case 7: { printf("Case 7\n"); break; } case 8: { printf("Case 8\n"); break; } case 9: { printf("Case 9\n"); break; } case 10: { printf("Case 10\n"); break; } default: { printf("Nothing\n"); break; } } Now the resultant assembly for the same is: movl $5, -4(%ebp) cmpl $10, -4(%ebp) ja L13 movl -4(%ebp), %eax sall $2, %eax movl L14(%eax), %eax jmp *%eax .section .rdata,"dr" .align 4 L14: .long L13 .long L3 .long L4 .long L5 .long L6 .long L7 .long L8 .long L9 .long L10 .long L11 .long L12 .text L3: movl $LC0, (%esp) call _printf jmp L2 L4: movl $LC1, (%esp) call _printf jmp L2 L5: movl $LC2, (%esp) call _printf jmp L2 L6: movl $LC3, (%esp) call _printf jmp L2 L7: movl $LC4, (%esp) call _printf jmp L2 L8: movl $LC5, (%esp) call _printf jmp L2 L9: movl $LC6, (%esp) call _printf jmp L2 L10: movl $LC7, (%esp) call _printf jmp L2 L11: movl $LC8, (%esp) call _printf jmp L2 L12: movl $LC9, (%esp) call _printf jmp L2 L13: movl $LC10, (%esp) call _printf L2: Now, in the assembly, the code is first checking the last case (i.e. case 10) first. This is very strange. And then it is copying 'i' into 'eax' and doing things that are beyond me. I have heard that the compiler implements some jump table for switch..case. Is it what this code is doing? Or what is it doing and why? Because in case of less number of cases, the code is pretty similar to that generated for if...else ladder, but when number of cases increases, this unusual-looking implementation is seen. Thanks in advance.

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  • Espeak SAPI/dll usage on Windows ?

    - by Quandary
    Question: I am trying to use the espeak text-to-speech engine. So for I got it working wounderfully on linux (code below). Now I wanted to port this basic program to windows, too, but it's nearly impossible... Part of the problem is that the windows dll only allows for AUDIO_OUTPUT_SYNCHRONOUS, which means it requires a callback, but I can't figure out how to play the audio from the callback... First it crashed, then I realized, I need a callback function, now I get the data in the callback function, but I don't know how to play it... as it is neither a wav file nor plays automatically as on Linux. The sourceforge site is rather useless, because it basically says use the SAPI version, but then there is no example on how to use the sapi espeak dll... Anyway, here's my code, can anybody help? #ifdef __cplusplus #include <cstdio> #include <cstdlib> #include <cstring> else #include <stdio.h> #include <stdlib.h> #include <string.h> endif include include //#include "speak_lib.h" include "espeak/speak_lib.h" // libespeak-dev: /usr/include/espeak/speak_lib.h // apt-get install libespeak-dev // apt-get install libportaudio-dev // g++ -o mine mine.cpp -lespeak // g++ -o mine mine.cpp -I/usr/include/espeak/ -lespeak // gcc -o mine mine.cpp -I/usr/include/espeak/ -lespeak char voicename[40]; int samplerate; int quiet = 0; static char genders[4] = {' ','M','F',' '}; //const char *data_path = "/usr/share/"; // /usr/share/espeak-data/ const char *data_path = NULL; // use default path for espeak-data int strrcmp(const char *s, const char *sub) { int slen = strlen(s); int sublen = strlen(sub); return memcmp(s + slen - sublen, sub, sublen); } char * strrcpy(char *dest, const char *source) { // Pre assertions assert(dest != NULL); assert(source != NULL); assert(dest != source); // tk: parentheses while((*dest++ = *source++)) ; return(--dest); } const char* GetLanguageVoiceName(const char* pszShortSign) { #define LANGUAGE_LENGTH 30 static char szReturnValue[LANGUAGE_LENGTH] ; memset(szReturnValue, 0, LANGUAGE_LENGTH); for (int i = 0; pszShortSign[i] != '\0'; ++i) szReturnValue[i] = (char) tolower(pszShortSign[i]); const espeak_VOICE **voices; espeak_VOICE voice_select; voices = espeak_ListVoices(NULL); const espeak_VOICE *v; for(int ix=0; (v = voices[ix]) != NULL; ix++) { if( !strrcmp( v->languages, szReturnValue) ) { strcpy(szReturnValue, v->name); return szReturnValue; } } // End for strcpy(szReturnValue, "default"); return szReturnValue; } // End function getvoicename void ListVoices() { const espeak_VOICE **voices; espeak_VOICE voice_select; voices = espeak_ListVoices(NULL); const espeak_VOICE *v; for(int ix=0; (v = voices[ix]) != NULL; ix++) { printf("Shortsign: %s\n", v->languages); printf("age: %d\n", v->age); printf("gender: %c\n", genders[v->gender]); printf("name: %s\n", v->name); printf("\n\n"); } // End for } // End function getvoicename int main() { printf("Hello World!\n"); const char* szVersionInfo = espeak_Info(NULL); printf("Espeak version: %s\n", szVersionInfo); samplerate = espeak_Initialize(AUDIO_OUTPUT_PLAYBACK,0,data_path,0); strcpy(voicename, "default"); // espeak --voices strcpy(voicename, "german"); strcpy(voicename, GetLanguageVoiceName("DE")); if(espeak_SetVoiceByName(voicename) != EE_OK) { printf("Espeak setvoice error...\n"); } static char word[200] = "Hello World" ; strcpy(word, "TV-fäns aufgepasst, es ist 20 Uhr 15. Zeit für Rambo 3"); strcpy(word, "Unnamed Player wurde zum Opfer von GSG9"); int speed = 220; int volume = 500; // volume in range 0-100 0=silence int pitch = 50; // base pitch, range 0-100. 50=normal // espeak.cpp 625 espeak_SetParameter(espeakRATE, speed, 0); espeak_SetParameter(espeakVOLUME,volume,0); espeak_SetParameter(espeakPITCH,pitch,0); // espeakRANGE: pitch range, range 0-100. 0-monotone, 50=normal // espeakPUNCTUATION: which punctuation characters to announce: // value in espeak_PUNCT_TYPE (none, all, some), espeak_VOICE *voice_spec = espeak_GetCurrentVoice(); voice_spec->gender=2; // 0=none 1=male, 2=female, //voice_spec->age = age; espeak_SetVoiceByProperties(voice_spec); espeak_Synth( (char*) word, strlen(word)+1, 0, POS_CHARACTER, 0, espeakCHARS_AUTO, NULL, NULL); espeak_Synchronize(); strcpy(voicename, GetLanguageVoiceName("EN")); espeak_SetVoiceByName(voicename); strcpy(word, "Geany was fragged by GSG9 Googlebot"); strcpy(word, "Googlebot"); espeak_Synth( (char*) word, strlen(word)+1, 0, POS_CHARACTER, 0, espeakCHARS_AUTO, NULL, NULL); espeak_Synchronize(); espeak_Terminate(); printf("Espeak terminated\n"); return EXIT_SUCCESS; } /* if(espeak_SetVoiceByName(voicename) != EE_OK) { memset(&voice_select,0,sizeof(voice_select)); voice_select.languages = voicename; if(espeak_SetVoiceByProperties(&voice_select) != EE_OK) { fprintf(stderr,"%svoice '%s'\n",err_load,voicename); exit(2); } } */ The above code is for Linux. The below code is about as far as I got on Vista x64 (32 bit emu): #ifdef __cplusplus #include <cstdio> #include <cstdlib> #include <cstring> else #include <stdio.h> #include <stdlib.h> #include <string.h> endif include include include "speak_lib.h" //#include "espeak/speak_lib.h" // libespeak-dev: /usr/include/espeak/speak_lib.h // apt-get install libespeak-dev // apt-get install libportaudio-dev // g++ -o mine mine.cpp -lespeak // g++ -o mine mine.cpp -I/usr/include/espeak/ -lespeak // gcc -o mine mine.cpp -I/usr/include/espeak/ -lespeak char voicename[40]; int iSampleRate; int quiet = 0; static char genders[4] = {' ','M','F',' '}; //const char *data_path = "/usr/share/"; // /usr/share/espeak-data/ //const char *data_path = NULL; // use default path for espeak-data const char *data_path = "C:\Users\Username\Desktop\espeak-1.43-source\espeak-1.43-source\"; int strrcmp(const char *s, const char *sub) { int slen = strlen(s); int sublen = strlen(sub); return memcmp(s + slen - sublen, sub, sublen); } char * strrcpy(char *dest, const char *source) { // Pre assertions assert(dest != NULL); assert(source != NULL); assert(dest != source); // tk: parentheses while((*dest++ = *source++)) ; return(--dest); } const char* GetLanguageVoiceName(const char* pszShortSign) { #define LANGUAGE_LENGTH 30 static char szReturnValue[LANGUAGE_LENGTH] ; memset(szReturnValue, 0, LANGUAGE_LENGTH); for (int i = 0; pszShortSign[i] != '\0'; ++i) szReturnValue[i] = (char) tolower(pszShortSign[i]); const espeak_VOICE **voices; espeak_VOICE voice_select; voices = espeak_ListVoices(NULL); const espeak_VOICE *v; for(int ix=0; (v = voices[ix]) != NULL; ix++) { if( !strrcmp( v->languages, szReturnValue) ) { strcpy(szReturnValue, v->name); return szReturnValue; } } // End for strcpy(szReturnValue, "default"); return szReturnValue; } // End function getvoicename void ListVoices() { const espeak_VOICE **voices; espeak_VOICE voice_select; voices = espeak_ListVoices(NULL); const espeak_VOICE *v; for(int ix=0; (v = voices[ix]) != NULL; ix++) { printf("Shortsign: %s\n", v->languages); printf("age: %d\n", v->age); printf("gender: %c\n", genders[v->gender]); printf("name: %s\n", v->name); printf("\n\n"); } // End for } // End function getvoicename /* Callback from espeak. Directly speaks using AudioTrack. */ define LOGI(x) printf("%s\n", x) static int AndroidEspeakDirectSpeechCallback(short *wav, int numsamples, espeak_EVENT *events) { char buf[100]; sprintf(buf, "AndroidEspeakDirectSpeechCallback: %d samples", numsamples); LOGI(buf); if (wav == NULL) { LOGI("Null: speech has completed"); } if (numsamples > 0) { //audout->write(wav, sizeof(short) * numsamples); sprintf(buf, "AudioTrack wrote: %d bytes", sizeof(short) * numsamples); LOGI(buf); } return 0; // continue synthesis (1 is to abort) } static int AndroidEspeakSynthToFileCallback(short *wav, int numsamples,espeak_EVENT *events) { char buf[100]; sprintf(buf, "AndroidEspeakSynthToFileCallback: %d samples", numsamples); LOGI(buf); if (wav == NULL) { LOGI("Null: speech has completed"); } // The user data should contain the file pointer of the file to write to //void* user_data = events->user_data; FILE* user_data = fopen ( "myfile1.wav" , "ab" ); FILE* fp = static_cast<FILE *>(user_data); // Write all of the samples fwrite(wav, sizeof(short), numsamples, fp); return 0; // continue synthesis (1 is to abort) } int main() { printf("Hello World!\n"); const char* szVersionInfo = espeak_Info(NULL); printf("Espeak version: %s\n", szVersionInfo); iSampleRate = espeak_Initialize(AUDIO_OUTPUT_SYNCHRONOUS, 4096, data_path, 0); if (iSampleRate <= 0) { printf("Unable to initialize espeak"); return EXIT_FAILURE; } //samplerate = espeak_Initialize(AUDIO_OUTPUT_PLAYBACK,0,data_path,0); //ListVoices(); strcpy(voicename, "default"); // espeak --voices //strcpy(voicename, "german"); //strcpy(voicename, GetLanguageVoiceName("DE")); if(espeak_SetVoiceByName(voicename) != EE_OK) { printf("Espeak setvoice error...\n"); } static char word[200] = "Hello World" ; strcpy(word, "TV-fäns aufgepasst, es ist 20 Uhr 15. Zeit für Rambo 3"); strcpy(word, "Unnamed Player wurde zum Opfer von GSG9"); int speed = 220; int volume = 500; // volume in range 0-100 0=silence int pitch = 50; // base pitch, range 0-100. 50=normal // espeak.cpp 625 espeak_SetParameter(espeakRATE, speed, 0); espeak_SetParameter(espeakVOLUME,volume,0); espeak_SetParameter(espeakPITCH,pitch,0); // espeakRANGE: pitch range, range 0-100. 0-monotone, 50=normal // espeakPUNCTUATION: which punctuation characters to announce: // value in espeak_PUNCT_TYPE (none, all, some), //espeak_VOICE *voice_spec = espeak_GetCurrentVoice(); //voice_spec->gender=2; // 0=none 1=male, 2=female, //voice_spec->age = age; //espeak_SetVoiceByProperties(voice_spec); //espeak_SetSynthCallback(AndroidEspeakDirectSpeechCallback); espeak_SetSynthCallback(AndroidEspeakSynthToFileCallback); unsigned int unique_identifier; espeak_ERROR err = espeak_Synth( (char*) word, strlen(word)+1, 0, POS_CHARACTER, 0, espeakCHARS_AUTO, &unique_identifier, NULL); err = espeak_Synchronize(); /* strcpy(voicename, GetLanguageVoiceName("EN")); espeak_SetVoiceByName(voicename); strcpy(word, "Geany was fragged by GSG9 Googlebot"); strcpy(word, "Googlebot"); espeak_Synth( (char*) word, strlen(word)+1, 0, POS_CHARACTER, 0, espeakCHARS_AUTO, NULL, NULL); espeak_Synchronize(); */ // espeak_Cancel(); espeak_Terminate(); printf("Espeak terminated\n"); system("pause"); return EXIT_SUCCESS; }

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  • c program pointer

    - by sandy101
    Hello , I am trying some programs in c face a problem with this program #include<stdio.h> int main() { int a=9,*x; float b=3.6,*y; char c='a',*z; printf("the value is %d\n",a); printf("the value is %f\n",b); printf("the value is %c\n",c); x=&a; y=&b; z=&c; printf("%u\n",a); printf("%u\n",b); printf("%u\n",c); x++; y++; z++; printf("%u\n",a); printf("%u\n",b); printf("%u\n",c); return 0; } can any one tell me what is the problem with this and i also want to know that when in the above case if the pointer value is incremented then will it over write the previous value address as suppose that the value we got in the above program (without the increment in the pointer value )is 65524 65520 65519 and after the increment the value of the pointer is 65526(as 2 increment for the int ) 65524(as 4 increment for the float ) 65520(as 1 increment for the char variable ) then if in that case will the new pointer address overwrite the content of the previous address and what value be contained at the new address ......plz help

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  • Pointers and Addresses in C

    - by Mohit
    #include "stdio.h" main() { int i=3,*x; float j=1.5,*y; char k='c',*z; x=&i; y=&j; z=&k; printf("\nAddress of x= %u",x); printf("\nAddress of y= %u",y); printf("\nAddress of z= %u",z); x++; y++;y++;y++;y++; z++; printf("\nNew Address of x= %u",x); printf("\nNew Address of y= %u",y); printf("\nNew Address of z= %u",z); printf("\nNew Value of i= %d",i); printf("\nNew Value of j= %f",j); printf("\nNew Value of k= %c\n",k); } Output: Address of x= 3219901868 Address of y= 3219901860 Address of z= 3219901875 New Address of x= 3219901872 New Address of y= 3219901876 New Address of z= 3219901876 New Value of i= 3 New Value of j= 1.500000 New Value of k= c The new address of variable y and z are same. How can two variables have same address and et have different values? Note: I used gcc compiler on Ubuntu 9.04

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  • checking every digit in a number for oddness

    - by tryt
    Hello. I was writing a function which checks if every digit in a number is odd. I came accross this weird behaviour. Why does the second function return different (incorrect) results, eventhough its basically the same? (implemented in an opposite way) #include <stdio.h> int all_odd_1(int n) { if (n == 0) return 0; if (n < 0) n = -n; while (n > 0) { if (n&1 == 1) n /= 10; else return 0; } return 1; } int all_odd_2(int n) { if (n == 0) return 0; if (n < 0) n = -n; while (n > 0) { if (n&1 == 0) return 0; else n /= 10; } return 1; } int main() { printf("all_odd_1\n"); printf("%d\n", all_odd_1(-131)); printf("%d\n", all_odd_1(121)); printf("%d\n", all_odd_1(2242)); printf("-----------------\n"); printf("all_odd_2\n"); printf("%d\n", all_odd_2(131)); printf("%d\n", all_odd_2(121)); printf("%d\n", all_odd_2(2242)); return 0; }

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  • Reading a child process's /proc/pid/mem file from the parent

    - by Amittai Aviram
    In the program below, I am trying to cause the following to happen: Process A assigns a value to a stack variable a. Process A (parent) creates process B (child) with PID child_pid. Process B calls function func1, passing a pointer to a. Process B changes the value of variable a through the pointer. Process B opens its /proc/self/mem file, seeks to the page containing a, and prints the new value of a. Process A (at the same time) opens /proc/child_pid/mem, seeks to the right page, and prints the new value of a. The problem is that, in step 6, the parent only sees the old value of a in /proc/child_pid/mem, while the child can indeed see the new value in its /proc/self/mem. Why is this the case? Is there any way that I can get the parent to to see the child's changes to its address space through the /proc filesystem? #include <fcntl.h> #include <stdbool.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #include <sys/types.h> #include <sys/stat.h> #include <sys/wait.h> #include <unistd.h> #define PAGE_SIZE 0x1000 #define LOG_PAGE_SIZE 0xc #define PAGE_ROUND_DOWN(v) ((v) & (~(PAGE_SIZE - 1))) #define PAGE_ROUND_UP(v) (((v) + PAGE_SIZE - 1) & (~(PAGE_SIZE - 1))) #define OFFSET_IN_PAGE(v) ((v) & (PAGE_SIZE - 1)) # if defined ARCH && ARCH == 32 #define BP "ebp" #define SP "esp" #else #define BP "rbp" #define SP "rsp" #endif typedef struct arg_t { int a; } arg_t; void func1(void * data) { arg_t * arg_ptr = (arg_t *)data; printf("func1: old value: %d\n", arg_ptr->a); arg_ptr->a = 53; printf("func1: address: %p\n", &arg_ptr->a); printf("func1: new value: %d\n", arg_ptr->a); } void expore_proc_mem(void (*fn)(void *), void * data) { off_t frame_pointer, stack_start; char buffer[PAGE_SIZE]; const char * path = "/proc/self/mem"; int child_pid, status; int parent_to_child[2]; int child_to_parent[2]; arg_t * arg_ptr; off_t child_offset; asm volatile ("mov %%"BP", %0" : "=m" (frame_pointer)); stack_start = PAGE_ROUND_DOWN(frame_pointer); printf("Stack_start: %lx\n", (unsigned long)stack_start); arg_ptr = (arg_t *)data; child_offset = OFFSET_IN_PAGE((off_t)&arg_ptr->a); printf("Address of arg_ptr->a: %p\n", &arg_ptr->a); pipe(parent_to_child); pipe(child_to_parent); bool msg; int child_mem_fd; char child_path[0x20]; child_pid = fork(); if (child_pid == -1) { perror("fork"); exit(EXIT_FAILURE); } if (!child_pid) { close(child_to_parent[0]); close(parent_to_child[1]); printf("CHILD (pid %d, parent pid %d).\n", getpid(), getppid()); fn(data); msg = true; write(child_to_parent[1], &msg, 1); child_mem_fd = open("/proc/self/mem", O_RDONLY); if (child_mem_fd == -1) { perror("open (child)"); exit(EXIT_FAILURE); } printf("CHILD: child_mem_fd: %d\n", child_mem_fd); if (lseek(child_mem_fd, stack_start, SEEK_SET) == (off_t)-1) { perror("lseek"); exit(EXIT_FAILURE); } if (read(child_mem_fd, buffer, sizeof(buffer)) != sizeof(buffer)) { perror("read"); exit(EXIT_FAILURE); } printf("CHILD: new value %d\n", *(int *)(buffer + child_offset)); read(parent_to_child[0], &msg, 1); exit(EXIT_SUCCESS); } else { printf("PARENT (pid %d, child pid %d)\n", getpid(), child_pid); printf("PARENT: child_offset: %lx\n", child_offset); read(child_to_parent[0], &msg, 1); printf("PARENT: message from child: %d\n", msg); snprintf(child_path, 0x20, "/proc/%d/mem", child_pid); printf("PARENT: child_path: %s\n", child_path); child_mem_fd = open(path, O_RDONLY); if (child_mem_fd == -1) { perror("open (child)"); exit(EXIT_FAILURE); } printf("PARENT: child_mem_fd: %d\n", child_mem_fd); if (lseek(child_mem_fd, stack_start, SEEK_SET) == (off_t)-1) { perror("lseek"); exit(EXIT_FAILURE); } if (read(child_mem_fd, buffer, sizeof(buffer)) != sizeof(buffer)) { perror("read"); exit(EXIT_FAILURE); } printf("PARENT: new value %d\n", *(int *)(buffer + child_offset)); close(child_mem_fd); printf("ENDING CHILD PROCESS.\n"); write(parent_to_child[1], &msg, 1); if (waitpid(child_pid, &status, 0) == -1) { perror("waitpid"); exit(EXIT_FAILURE); } } } int main(void) { arg_t arg; arg.a = 42; printf("In main: address of arg.a: %p\n", &arg.a); explore_proc_mem(&func1, &arg.a); return EXIT_SUCCESS; } This program produces the output below. Notice that the value of a (boldfaced) differs between parent's and child's reading of the /proc/child_pid/mem file. In main: address of arg.a: 0x7ffffe1964f0 Stack_start: 7ffffe196000 Address of arg_ptr-a: 0x7ffffe1964f0 PARENT (pid 20376, child pid 20377) PARENT: child_offset: 4f0 CHILD (pid 20377, parent pid 20376). func1: old value: 42 func1: address: 0x7ffffe1964f0 func1: new value: 53 PARENT: message from child: 1 CHILD: child_mem_fd: 4 PARENT: child_path: /proc/20377/mem CHILD: new value 53 PARENT: child_mem_fd: 7 PARENT: new value 42 ENDING CHILD PROCESS.

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  • Logic error for Gauss elimination

    - by iwanttoprogram
    Logic error problem with the Gaussian Elimination code...This code was from my Numerical Methods text in 1990's. The code is typed in from the book- not producing correct output... Sample Run: SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS USING GAUSSIAN ELIMINATION This program uses Gaussian Elimination to solve the system Ax = B, where A is the matrix of known coefficients, B is the vector of known constants and x is the column matrix of the unknowns. Number of equations: 3 Enter elements of matrix [A] A(1,1) = 0 A(1,2) = -6 A(1,3) = 9 A(2,1) = 7 A(2,2) = 0 A(2,3) = -5 A(3,1) = 5 A(3,2) = -8 A(3,3) = 6 Enter elements of [b] vector B(1) = -3 B(2) = 3 B(3) = -4 SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS The solution is x(1) = 0.000000 x(2) = -1.#IND00 x(3) = -1.#IND00 Determinant = -1.#IND00 Press any key to continue . . . The code as copied from the text... //Modified Code from C Numerical Methods Text- June 2009 #include <stdio.h> #include <math.h> #define MAXSIZE 20 //function prototype int gauss (double a[][MAXSIZE], double b[], int n, double *det); int main(void) { double a[MAXSIZE][MAXSIZE], b[MAXSIZE], det; int i, j, n, retval; printf("\n \t SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS"); printf("\n \t USING GAUSSIAN ELIMINATION \n"); printf("\n This program uses Gaussian Elimination to solve the"); printf("\n system Ax = B, where A is the matrix of known"); printf("\n coefficients, B is the vector of known constants"); printf("\n and x is the column matrix of the unknowns."); //get number of equations n = 0; while(n <= 0 || n > MAXSIZE) { printf("\n Number of equations: "); scanf ("%d", &n); } //read matrix A printf("\n Enter elements of matrix [A]\n"); for (i = 0; i < n; i++) for (j = 0; j < n; j++) { printf(" A(%d,%d) = ", i + 1, j + 1); scanf("%lf", &a[i][j]); } //read {B} vector printf("\n Enter elements of [b] vector\n"); for (i = 0; i < n; i++) { printf(" B(%d) = ", i + 1); scanf("%lf", &b[i]); } //call Gauss elimination function retval = gauss(a, b, n, &det); //print results if (retval == 0) { printf("\n\t SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS\n"); printf("\n\t The solution is"); for (i = 0; i < n; i++) printf("\n \t x(%d) = %lf", i + 1, b[i]); printf("\n \t Determinant = %lf \n", det); } else printf("\n \t SINGULAR MATRIX \n"); return 0; } /* Solves the system of equations [A]{x} = {B} using */ /* the Gaussian elimination method with partial pivoting. */ /* Parameters: */ /* n - number of equations */ /* a[n][n] - coefficient matrix */ /* b[n] - right-hand side vector */ /* *det - determinant of [A] */ int gauss (double a[][MAXSIZE], double b[], int n, double *det) { double tol, temp, mult; int npivot, i, j, l, k, flag; //initialization *det = 1.0; tol = 1e-30; //initial tolerance value npivot = 0; //mult = 0; //forward elimination for (k = 0; k < n; k++) { //search for max coefficient in pivot row- a[k][k] pivot element for (i = k + 1; i < n; i++) { if (fabs(a[i][k]) > fabs(a[k][k])) { //interchange row with maxium element with pivot row npivot++; for (l = 0; l < n; l++) { temp = a[i][l]; a[i][l] = a[k][l]; a[k][l] = temp; } temp = b[i]; b[i] = b[k]; b[k] = temp; } } //test for singularity if (fabs(a[k][k]) < tol) { //matrix is singular- terminate flag = 1; return flag; } //compute determinant- the product of the pivot elements *det = *det * a[k][k]; //eliminate the coefficients of X(I) for (i = k; i < n; i++) { mult = a[i][k] / a[k][k]; b[i] = b[i] - b[k] * mult; //compute constants for (j = k; j < n; j++) //compute coefficients a[i][j] = a[i][j] - a[k][j] * mult; } } //adjust the sign of the determinant if(npivot % 2 == 1) *det = *det * (-1.0); //backsubstitution b[n] = b[n] / a[n][n]; for(i = n - 1; i > 1; i--) { for(j = n; j > i + 1; j--) b[i] = b[i] - a[i][j] * b[j]; b[i] = b[i] / a[i - 1][i]; } flag = 0; return flag; } The solution should be: 1.058824, 1.823529, 0.882353 with det as -102.000000 Any insight is appreciated...

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