operator << : std::cout << i << (i << 1);
- by Oops
Hi,
I use the stream operator << and the bit shifting operator << in one line.
I am a bit confused, why does code A) not produce the same output than code B)?
A)
int i = 4;
std::cout << i << " " << (i << 1) << std::endl; //4 8
B)
myint m = 4;
std::cout << m << " " << (m << 1) << std::endl; //8 8
class myint:
class myint {
int i;
public:
myint(int ii) {
i = ii;
}
inline myint operator <<(int n){
i = i << n;
return *this;
}
inline operator int(){
return i;
}
};
thanks in advance
Oops