Search Results

Search found 5140 results on 206 pages for 'crazy bash'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 78/206 | < Previous Page | 74 75 76 77 78 79 80 81 82 83 84 85  | Next Page >

  • How to create program that can be run by: #service myservice start

    - by Saif Bechan
    I am new to Linux and want to know what kind of programs can be run by using. #service myservice start And the programs stays on until stopped. Are they normal c++ programs or are they different. In some tutorials i have seen that they use ./myprogram to start a program. Another thing I have seen is the usage of .sh files. One last type of program i see is executed by the command: #/usr/bin/myprogramm Can someone explain the difference between these or point me to a basic tutorial/guide.

    Read the article

  • grep 5 seconds of input from the serial port inside a shell-script

    - by pica
    I've got a device that I'm operating next to my PC and as it runs it's spitting log lines out it's serial port. I have this wired to my PC and I can see the log lines fine if I'm using either minicom or something like: ttylog -b 115200 -d /dev/ttyS0 I want to write 5 seconds of the device serial output to a temp file (or assign it to a variable) and then later grep that file for keywords that will let me know how the device is operating. I've already tried redirecting the output to a file while running the command in the background, and then sleeping 5 seconds and killing the process, but the log lines never get written to my temp file. Example: touch tempFile ttylog -b 115200 -d /dev/ttyS0 >> tempFile & serialPID=$! sleep 5 #kill ${serialPID} #does not work, gets wrong PID killall ttylog cat tempFile The file gets created but never filled with any data. I can also replace the ttylog line with: ttylog -b 115200 -d /dev/ttyS0 |tee -a tempFile & In neither case do I ever see any log lines logged to stdout or the log file unless I have multiple versions of ttylog running by mistake (see commented out line, D'oh). I have no idea what's going on here. It seems to be a failure of redirection within my script. Am I on the right track? Is there a better way to sample 5 seconds of the serial port?

    Read the article

  • Replace delimited block of text in file with the contents of another file

    - by rmarimon
    I need to write a simple script to replace a block of text in a configuration file with the contents of another file. Let's assume with have the following simplified files: server.xml <?xml version='1.0' encoding='UTF-8'?> <Server port="8005" shutdown="SHUTDOWN"> <Service name="Catalina"> <Connector port="80" protocol="HTTP/1.1"/> <Engine name="Catalina" defaultHost="localhost"> <!-- BEGIN realm --> <sometags/> <sometags/> <!-- END realm --> <Host name="localhost" appBase="webapps"/> </Engine> </Service> </Server> realm.xml <Realm className="org.apache.catalina.realm.UserDatabaseRealm" resourceName="UserDatabase"/> I want to run a script and have realm.xml replace the contents between the <!-- BEGIN realm --> and <!-- END realm --> lines. If realm.xml changes then whenever the script is run again it will replace the lines again with the new contents of realm.xml. This is intended to be run in /etc/init.d/tomcat on startup of the service on multiple installations on which the realm is going to be different. I'm not so sure how can I do this simply with awk or sed.

    Read the article

  • Using a dictionary file with sed

    - by Winston
    I have a blacklist.txt file that contains keywords I want to remove using sed. Here's what the blacklist.txt file contain winston@linux ] $ cat blacklist.txt obscure keywords here ... And here's what I have so far, but currently doesn't work. blacklist=$(cat blacklist.txt); output="filtered_file.txt" for i in $blacklist; do cat $input | sed 's/$i//g' >> $output done

    Read the article

  • Dymanic if statement evaluation problem with string comparison

    - by Mani
    I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

    Read the article

  • I write barely functional scripts that tend to not be resuable and make the baby jesus cry. Please h

    - by maxxpower
    I received a request to add around 100 users to a linux box the users are already in ldap so I can't just use newusers and point it at a text file. Another admin is taking care of the ldap piece so all I have to do is create all the home directories and chown them to the correct user once he adds the users to the box. creating the directories isn't a problem, but I'd like a more elegant script for chowning them to the correct user. what I have currently basically looks like chown -R testuser1 testgroup1 /home/tetsuser1; chown -R testuser2 testgroup2 /home/testgroup2; chown -R testsuser3 testgroup1 /home/testuser3 bascially I took the request that the user name and group name popped it into excel added a column of "chown -R" to the front, then added a column of "/", copied and pasted the username column after it and then added a column of ";" and dragged it down to the second to last row. Popped it into notepad ran some quick find and replaces and in less than a minute I have a completed request and a sad empty feeling. I know this was a really ghetto method and I'm trying to get away from using excel to avoid learning new scripting techniques so here's my real question. tl;dr I made 100 home directories and chowned them to the correct users, but it was ugly. Actual question below. You have a file named idlist that looks like this (only with say 1000 users and real usernames and groups) testuser1 testgroup1 testuser2 testgroup2 testuser3 testgroup1 write a script that creates home directories for all the users and chowns the created directories to the correct user and group. To make the directories I used the following(feel free to flame/correct me on this as well. ) var= 'cut -f1 -d" " idlist' (I used backticks not apostrophes around the cut command) mkdir $var

    Read the article

  • Parsing the first column of a csv file to a new file.

    - by S1syphus
    Operating System: OSX Method: From the command line, so using sed, cut, gawk, although preferably no installing modules. Essentially I am trying to take the first column of a csv file and parse it to a new file. Example input file EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 Desire output EXAMPLEfoo EXAMPLEbar EXAMPLE1 EXAMPLE2 EXAMPLE3 EXAMPLE4 So I want the first column. Here is what I have tried so far: awk -F"," '{print $1}' in.csv > out.txt awk -F"," '{for (i=2;i<=NF;i++)}' in.csv > out.txt awk -F"," 'BEGIN { OFS="," }' '{print $1}' in.csv > out.txt cat in.csv | cut -d \, -f 1 > out.txt None seem to work, either they just print the first line or nothing at all, so I would assume it's failing to read line by line.

    Read the article

  • Trouble with piping through sed

    - by Joel
    I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

    Read the article

  • Script telnet on webserver

    - by Kami
    Hi I would like to script telnet to test my website inputs handling. I can do it manually : telnet localhost 8888 ... GET / HTTP/1.1\n Host: localhost ...html response But I can pass command to telnet in my shell script ! I've tried : (echo "GET / HTTP/1.1\n"; echo "Host: localhost \n\n"; sleep 1) | telnet localhost 8888 It produces no results at all !

    Read the article

  • How can I prevent default_environment variables from getting set by Capistrano's sudo action?

    - by Logan Koester
    My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

    Read the article

  • cmake source and out-of-source navigation

    - by idimba
    Hi, cmake advises to use out-of-source builds. While in general I like the idea I find it not comfortable to navigate from out-of-source sub directory to the corresponding source directory. I frequently need the code to perform some actions with code (e.g. grep, svn command etc.). Is there an easy way in shell to navigate from out-of-source sub directory to the corresponding source directory? Thanks Dima

    Read the article

  • strange behavior

    - by lego69
    I wrote simple script test echo hello <-- inside test if I press one time enter after hello, my script will run, if I don't press - it will not, if two times I'll receive my hello and + command was not found, can somebody please explain me this behavior thanks in advance

    Read the article

  • Redirect PHP-Shell-Script output

    - by Corelgott
    Hi Folks, i have got a php-script foo.php #!/usr/bin/php -c /etc/php5/cli/php.ini -q <?php echo 'hello'; // & do some stuff ?> I call this script not wrapped by a sh-script but using it directly in a cron job. To get rid of it's output i normally would just create a sh-file which calls /usr/bin/php -c /etc/php5/cli/php.ini -q foo.php > /dev/null 2 > /dev/null now i'd like to do this in the interpreter-declaration of the php file it self... so i am looking for the syntax for: #!/usr/bin/php -args [file's content] > /redirect 2 > /redirect i have kind of a hard time googleing for it... so if anybody could point me into the right direction i would really appreciate it! Thx in advance Corelgott

    Read the article

  • What happened to the TMP environment variable?

    - by Mark0978
    I always heard that the proper way to find the temporary folder on a UNIX machine was to look at the TMP environment variable. When writing code that worked on Windows as well as Linux, I would check for TEMP and TMP. Today, I discovered that my Ubuntu install does not have that environment variable at all. I know it seems you can always count on /tmp being there to put your temporary files in, but I understood that TMP was the way the user could tell you to put the temporary files someplace else. Is that still the case?

    Read the article

  • Shell - Run additional command on failure

    - by Shawn
    I have this script that I am currently running that works great for all instances but one: #!/bin/sh pdfopt test.pdf test.opt.pdf &>/dev/null pdf2swf test.opt.pdf test.swf [ "$?" -ne 0 ] && exit 2 More lines to execute follow the above code ... How would I go about changing this script to run "pdf2swf test.pdf test.swf" if "pdf2swf test.opt.pdf test.swf" fails? If the second attempt fails, then I would "exit 2". Thanks

    Read the article

  • Escaping Code for Different Shells

    - by Jon Purdy
    Question: What characters do I need to escape in a user-entered string to securely pass it into shells on Windows and Unix? What shell differences and version differences should be taken into account? Can I use printf "%q" somehow, and is that reliable across shells? Backstory (a.k.a. Shameless Self-Promotion): I made a little DSL, the Vision Web Template Language, which allows the user to create templates for X(HT)ML documents and fragments, then automatically fill them in with content. It's designed to separate template logic from dynamic content generation, in the same way that CSS is used to separate markup from presentation. In order to generate dynamic content, a Vision script must defer to a program written in a language that can handle the generation logic, such as Perl or Python. (Aside: using PHP is also possible, but Vision is intended to solve some of the very problems that PHP perpetuates.) In order to do this, the script makes use of the @system directive, which executes a shell command and expands to its output. (Platform-specific generation can be handled using @unix or @windows, which only expand on the proper platform.) The problem is obvious, I should think: test.htm: <!-- ... --> <form action="login.vis" method="POST"> <input type="text" name="USERNAME"/> <input type="password" name="PASSWORD"/> </form> <!-- ... --> login.vis: #!/usr/bin/vision # Think USERNAME = ";rm -f;" @system './login.pl' { USERNAME; PASSWORD } One way to safeguard against this kind of attack is to set proper permissions on scripts and directories, but Web developers may not always set things up correctly, and the naive developer should get just as much security as the experienced one. The solution, logically, is to include a @quote directive that produces a properly escaped string for the current platform. @system './login.pl' { @quote : USERNAME; @quote : PASSWORD } But what should @quote actually do? It needs to be both cross-platform and secure, and I don't want to create terrible problems with a naive implementation. Any thoughts?

    Read the article

  • Getting ssh to execute a command in the background on target machine

    - by dagorym
    This is a follow-on question to the How do you use ssh in a shell script? question. If I want to execute a command on the remote machine that runs in the background on that machine, how do I get the ssh command to return? When I try to just include the ampersand (&) at the end of the command it just hangs. The exact form of the command looks like this: ssh user@target "cd /some/directory; program-to-execute &" Any ideas? One thing to note is that logins to the the target machine always produce a text banner and I have ssh keys set up so no password is required.

    Read the article

  • How do I write an alias for grep -R?

    - by numerodix
    I end up typing grep -Rni pattern . and awful lot. How do I make this into an alias like alias gr='grep -Rni $@ .' Running that gives: $ gr pattern grep: pattern: No such file or directory Even though the alias looks fine: $ type gr gr is aliased to `grep -R $@ .' It seems that the $@ and the . get swapped when it's actually executed.

    Read the article

  • storing passed arguments in separate variables -shell scripting

    - by Nathan Pk
    In my script "script.sh" , I want to store 1st and 2nd argument to some variable and rest to another separate variable. What command I must use to implement this task? Number of arguments that is passed to a script is random) When I run the command in console ./script.sh abc def ghi jkl mn o p qrs xxx #It can have any number of arguments In this case, I want my script to store "abc" and "def" in one variable. "ghi jkl mn o p qrs xxx" should be stored in another variable.

    Read the article

  • Problem with Ruby script output being stored into a file

    - by nickf
    I have a Ruby script that outputs a heap of text. As an example: puts "line 1" puts "line 2" puts "line 3" # etc... (obviously, this isn't how my script works..) There's not a lot of data - perhaps about 8kb of character data in total. When I run the script on the command line, it works as expected: $ ./my-script.rb line 1 line 2 line 3 But, when I push it into a file, the output is truncated at exactly 4096 bytes: $ ./my-script.rb > output.txt What would cause it to stop at 4kb?

    Read the article

  • Exit SSH from the script

    - by Kimi
    I Want to exit ssh: Does the below line work: ssh -f -T ${USAGE_2_USER}@${USAGE_2_HOST} Or do i need to write it some other way . Please tell should I use exit with ssh an how?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 74 75 76 77 78 79 80 81 82 83 84 85  | Next Page >