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  • We're Back: I'm Here

    - by [email protected]
    After a busy Fall and Winter post-Oracle OpenWorld 2009 Oracle's Application Strategy Blog is back. More on what we've been up to shortly. Me, I'm blogging here for the first time. After nearly 6 years at Oracle working on the Oracle Fusion Middleware business I've recently joined the Oracle Applications team. For me, what's old is new again. Prior to working on applications infrastructure at Oracle...and at BEA Systems before that...I worked at PeopleSoft in a number of roles spanning Enterprise Performance Management, Supply Chain, Public Sector and Financial Services and more. Some of the acronyms are the same, there are (of course) some new ones too. But what I'm really excited about is the intersection of Enterprise Applications and Applications Infrastructure that's happening right now. "Aligning IT with Business Strategy" has been the buzzphrase for longer than we can all remember---but what I've seen over the past 5 months makes me start to believe that it's finally starting to happen.

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  • Breakout clone, how to handle/design for collision detection/physics between objects?

    - by Zolomon
    I'm working on a breakout clone, and I wish to create some realistic physics effects for collision - angles on the paddle should allow the ball to bounce, as well as doing curve balls etc. I could use per-pixel based collision detection, but then I thought it might be easier with line/circle intersection testing. So, then I naturally consider making a polygon class for the line-based objects and use the built-in circle class for the circular objects. That sounds like an OK approach, right? And then just check for collision using the specified algorithm based on the objects that might be within each other's range?

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  • OpenGL ES 2.0 gluUnProject

    - by secheung
    I've spent more time than I should trying to get my ray picking program working. I'm pretty convinced my math is solid with respect to line plane intersection, but I believe the problem lies with the changing of the mouse screen touch into 3D world space. Heres my code: public void passTouchEvents(MotionEvent e){ int[] viewport = {0,0,viewportWidth,viewportHeight}; float x = e.getX(), y = viewportHeight - e.getY(); float[] pos1 = new float[4]; float[] pos2 = new float[4]; GLU.gluUnProject( x, y, 0.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos1, 0); GLU.gluUnProject( x, y, 1.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos2, 0); } Just as a reference I've tried transforming the coordinates 0,0,0 and got an offset. It would be appreciated if you would answer using OpenGL ES 2.0 code.

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  • What library should I use for 2D Geometry? [closed]

    - by Luka
    I've been working on a 2D game in java, but found that java just didn't cut it for me and had forced me to a lot of bad design choices, so I've decided to port all my work to c++. The main reason I've decided change to c++ is that i had reached a point where i had 3 geometry libraries (the native, one from the game engine and one to handle "complex" polygons), none of witch worked very well together and i couldn't keep track of them. I'm new to c++, but i know all the basics. My question is, what would be a good geometry library to use, ideally it should be able to handle integer and decimal data types, have point, line, and polygon classes witch are able to check for intersection and contains. Thanks in advance, Luka

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  • How to detect and collide two elastic line segments?

    - by Tautrimas
    There are 4 moving physical nodes in 3D space. They are paired with two elastic line segments / strings (1 <- 2; 3 <- 4). Part I: How to detect the collision of two segments? Part II: On the moment of collision, fifth node is created at the intersection point and here you have the force-based graph. 5-th node (bend point) can slide among the strings as in a real world. Given the new coordinates of 4 nodes, how to calculate the position of the 5-th node on the next frame? I assume string force on the nodes to be F = -k * x where x is the string length. All I came up to is that the force between 5 and 1 equals 5 and 2 (the same with 3 and 4). What are the other properties?.

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  • Retrieve the coordinates of the *occluding* (closest/drawn) pixels during 3D overlap, using OpenGL?

    - by Big Rich
    Hi, Sorry if the question is not worded well, I'm a new to both 3D and OpenGL. How could I go about obtaining the 3D coordinates of the occluding object, at the point where occlusion is happening (i.e. the 'intersection' of the object in front/closest to the screen)? Just to offer a [very] rudimentary, visual, example, if you were to form an index-finger cross, with your right hand closest to your face, I'd like to know the coordinates of the part of your right finger which obscures the other finger (obviously back within the OpenGL context - no jokers ;-) ). If there is a way to find out both about the occluder (hider) and the occluded (hidden) objects in OpenGL, then that would be of great use, also. Cheers Rich

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  • OpenGLES 2.0 gluunProject

    - by secheung
    I've spent more time than i should trying to get my ray picking program working. I'm pretty convinced my math is solid with respect to line plane intersection, but I believe the problem lies with the changing of the mouse screen touch into 3D world space. Heres my code public void passTouchEvents(MotionEvent e){ int[] viewport = {0,0,viewportWidth,viewportHeight}; float x = e.getX(), y = viewportHeight - e.getY(); float[] pos1 = new float[4]; float[] pos2 = new float[4]; GLU.gluUnProject( x, y, 0.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos1, 0); GLU.gluUnProject( x, y, 1.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos2, 0); } Just as a reference I've tried transforming the coordinates 0,0,0 and got an offset. It would be appreciated if you would answer using opengl es 2.0 code. Thanks

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  • Collisions and Lists

    - by user50635
    I've run into an issue that breaks my collisions. Here's my method: Gather Input Project Rectangle Check for intersection and ispassable Update The update method is built on object_position * seconds_passed * velocity * speed. Input changes velocity and is normalized if 1. This method works well with just one object comparison, however I pass a list or a for loop to the collision detector and velocity gets changed back to a non zero when the list hits an object that passes the test and the object can pass through. Any solutions would be much appreciated. Side note is there a more proper way to simulate movement?

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  • How can you identify duplicate CSS rules?

    - by DanMan
    I'm not talking about used/unused here. I have two stylesheets and some rules differ (either in selectors, rules or both) and some are exactly the same. So I'm looking for a way to extract and move those rules, which are the same in both files, into a third stylesheet. In other words: an intersection of two stylesheets. Strangely, I couldn't find a software for this. Would have expected this to be a more common problem. Background, for those who care: I'm converting a desktop website into a mobile one and I've started by duplicating the desktop stylesheet and changing it (throwing stuff out, adding to it).

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  • Binary Cosine Cofficient

    - by hairyyak
    I was given the following forumulae for calculating this sim=|QnD| / v|Q|v|D| I went ahed and implemented a class to compare strings consisting of a series of words #pragma once #include <vector> #include <string> #include <iostream> #include <vector> using namespace std; class StringSet { public: StringSet(void); StringSet( const string the_strings[], const int no_of_strings); ~StringSet(void); StringSet( const vector<string> the_strings); void add_string( const string the_string); bool remove_string( const string the_string); void clear_set(void); int no_of_strings(void) const; friend ostream& operator <<(ostream& outs, StringSet& the_strings); friend StringSet operator *(const StringSet& first, const StringSet& second); friend StringSet operator +(const StringSet& first, const StringSet& second); double binary_coefficient( const StringSet& the_second_set); private: vector<string> set; }; #include "StdAfx.h" #include "StringSet.h" #include <iterator> #include <algorithm> #include <stdexcept> #include <iostream> #include <cmath> StringSet::StringSet(void) { } StringSet::~StringSet(void) { } StringSet::StringSet( const vector<string> the_strings) { set = the_strings; } StringSet::StringSet( const string the_strings[], const int no_of_strings) { copy( the_strings, &the_strings[no_of_strings], back_inserter(set)); } void StringSet::add_string( const string the_string) { try { if( find( set.begin(), set.end(), the_string) == set.end()) { set.push_back(the_string); } else { //String is already in the set. throw domain_error("String is already in the set"); } } catch( domain_error e) { cout << e.what(); exit(1); } } bool StringSet::remove_string( const string the_string) { //Found the occurrence of the string. return it an iterator pointing to it. vector<string>::iterator iter; if( ( iter = find( set.begin(), set.end(), the_string) ) != set.end()) { set.erase(iter); return true; } return false; } void StringSet::clear_set(void) { set.clear(); } int StringSet::no_of_strings(void) const { return set.size(); } ostream& operator <<(ostream& outs, StringSet& the_strings) { vector<string>::const_iterator const_iter = the_strings.set.begin(); for( ; const_iter != the_strings.set.end(); const_iter++) { cout << *const_iter << " "; } cout << endl; return outs; } //This function returns the union of the two string sets. StringSet operator *(const StringSet& first, const StringSet& second) { vector<string> new_string_set; new_string_set = first.set; for( unsigned int i = 0; i < second.set.size(); i++) { vector<string>::const_iterator const_iter = find(new_string_set.begin(), new_string_set.end(), second.set[i]); //String is new - include it. if( const_iter == new_string_set.end() ) { new_string_set.push_back(second.set[i]); } } StringSet the_set(new_string_set); return the_set; } //This method returns the intersection of the two string sets. StringSet operator +(const StringSet& first, const StringSet& second) { //For each string in the first string look though the second and see if //there is a matching pair, in which case include the string in the set. vector<string> new_string_set; vector<string>::const_iterator const_iter = first.set.begin(); for ( ; const_iter != first.set.end(); ++const_iter) { //Then search through the entire second string to see if //there is a duplicate. vector<string>::const_iterator const_iter2 = second.set.begin(); for( ; const_iter2 != second.set.end(); const_iter2++) { if( *const_iter == *const_iter2 ) { new_string_set.push_back(*const_iter); } } } StringSet new_set(new_string_set); return new_set; } double StringSet::binary_coefficient( const StringSet& the_second_set) { double coefficient; StringSet intersection = the_second_set + set; coefficient = intersection.no_of_strings() / sqrt((double) no_of_strings()) * sqrt((double)the_second_set.no_of_strings()); return coefficient; } However when I try and calculate the coefficient using the following main function: // Exercise13.cpp : main project file. #include "stdafx.h" #include <boost/regex.hpp> #include "StringSet.h" using namespace System; using namespace System::Runtime::InteropServices; using namespace boost; //This function takes as input a string, which //is then broken down into a series of words //where the punctuaction is ignored. StringSet break_string( const string the_string) { regex re; cmatch matches; StringSet words; string search_pattern = "\\b(\\w)+\\b"; try { // Assign the regular expression for parsing. re = search_pattern; } catch( regex_error& e) { cout << search_pattern << " is not a valid regular expression: \"" << e.what() << "\"" << endl; exit(1); } sregex_token_iterator p(the_string.begin(), the_string.end(), re, 0); sregex_token_iterator end; for( ; p != end; ++p) { string new_string(p->first, p->second); String^ copy_han = gcnew String(new_string.c_str()); String^ copy_han2 = copy_han->ToLower(); char* str2 = (char*)(void*)Marshal::StringToHGlobalAnsi(copy_han2); string new_string2(str2); words.add_string(new_string2); } return words; } int main(array<System::String ^> ^args) { StringSet words = break_string("Here is a string, with some; words"); StringSet words2 = break_string("There is another string,"); cout << words.binary_coefficient(words2); return 0; } I get an index which is 1.5116 rather than a value from 0 to 1. Does anybody have a clue why this is the case? Any help would be appreciated.

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  • .NET Geometry Library

    - by dewald
    Does anyone know of a good (efficient, nice API, etc.) geometry open source library for .NET? Some of the operations needed: Data Structures Vectors (2D and 3D with floats and doubles) Lines (2D and 3D) Rectangles / Squares / Cubes / Boxes Spheres / Circles N-Sided Polygon Matrices (floats and doubles) Algorithms Intersection calculations Area / Volume calculations

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  • Are there any implementations of multiset for .Net?

    - by dangph
    I'm looking for a .Net implementation of a multiset. Can anyone recommend a good one? (A multiset, or bag, is a set that can have duplicate values, and on which you can do set operations: intersection, difference, etc. A shopping cart for instance could be thought of as a multiset because you can have multiple occurrences of the same product.)

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  • How can I use a php array in a mysql search query?

    - by ThinkingInBits
    I was going to use the scuttle solution on: http://www.pui.ch/phred/archives/2005/04/tags-database-schemas.html for handling searches on my website. I was wondering how I could take the search input from a user and turn it into a single query. For instance, let's say a user inputted 'blue dogs' in their search query... How could I dynamically update the query to include ('blue', 'dogs') in union and intersection queries?

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  • standard rectangle class

    - by Neil G
    I have a project that has a GUI (written in QT) and a command-line version. I made use of the rectangle class included in QT: QRect. I would like to break the command-line version's dependency on QT, so I need a drop-in rectangle class that supports intersection and union. I could write one, but I'd prefer including one if possible. Any ideas?

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  • How do I integrate a BSDF into a ray caster.

    - by pelb
    I'm trying to implement sub surface scattering at isosurfaces and looked up how a BSDF works mathematically. Implementing the reflective and diffuse part seems to be quite easy as i just have to evaluate phong at the isosurface intersection, but how do you I apply the transmissive part of the BSDF? In what way do i have to modify the ray direction. Any pointers to a practical implementation are welcome. Thanks and So long!

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  • How to correctly highlight cursor line in VIM?

    - by Eye of Hell
    Hello. VIM can be configured to highlight current line via :hi cursorline guibg=green and set cursorline commands. But if I enable tabs display via: :hi specialkey guifg=grey guibg=grey :set listchars="tab" :set list Cursor line highlight will corrupt tabs display: Any hints how i can avoid corruption so may tabs are highlighted with one color and cursor line is highlighted with another color without any ^I displayed at intersection?

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  • Get more than 7 dimensions in google analytics

    - by Paritosh Singh
    I am fetching my data from google analytics core api. I came to know that we can fetch only 7 dimensions using api, But here I need to fetch more than 7 dimensions with correct metrics. Is there anyway (other than using paid google analytics) to fetch more than 7 dmensions with correct metrics from google analytics. If not, then is there any mathematical formula through which we can find intersection of dimensions fetched using 2 different dimensions having one dimension in common. Thanks

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  • Determining if two lines intersect

    - by Faken
    I have two lines that extend to infinity but both have a starting point. They are both described by a starting point and a vector in the direction of the line extending to infinity. I want to find out if the two lines intersect but i don't need to know where they intersect (its part of a collision detection algorithm). Everything i have looked at so far describes finding the intersection point of two lines or line segments. Anyone know a fast algorithm to solve this?

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  • iPhone. How to get the rect of parent view?

    - by flexbyte
    Hi, My application creates two views: topView (CGRect = 0,0, 320,60) bottomView (CGRect = 0,60, 320,480) Bottom view creates UITabBarController with UIViewControllers: ListViewController etc... ListViewController has own views that are created in viewDidLoad method: background = [[UIImageView alloc] initWithFrame: rect ]; So my question is how to get the bottomView rect inside ListViewController? I want to layout all controller views without intersection with topView. Thank you.

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  • How to group by having the same id?

    - by simpatico
    Hello, I want the customerid who bought product X and Y and Z, from the following schema: Sales(customerid, productName, rid); I could do the intersection: select customerid from sales where productName='X' INTERSECT select customerid from sales where productName='X' INTERSTECT select customerid from sales where productName='Z' Is this the best I could do?

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  • Looking for a chart of Wpf Bindings

    - by BSalita
    I'm probably typical in being bewildered by the many syntaxes of Wpf binding. Does anyone know of a chart that lays out all the possibilities. Across one axis is all the variations of binding syntaxes (Static, Dynamic, Self, ...), the other axis are all the variations of scoping and type. The intersection of the axis show an example. Surely someone, some author has done this, eh?

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  • linked-list interview question

    - by giri
    Hi This was the question asked in interview.Can anybody help me out it in implementing in java Given 2 linked lists(which need not have unique elements) find intersection point in the form of Y.(it can be anywhere--middle or tail)

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