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• finding the missing values in a range using any scripting language - perl, python or shell script

  - by manu

  Hi everyone I got stuck in one problem of finding the missing values in a range and the range is also variable for the successive rows. Ex. =================== inpt ==================== 673 673 673 676 676 680 2667 2667 2668 2670 2671 2674 ===================== output should be like this =================== 674 675 677 678 679 2669 2672 2673 ======================== This is just one part and the row values can be more also If there is any clarification plz let me know. thanx in advance manu

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• Exclude a string from wildcard search in a shell

  - by steigers

  Hello everybody I am trying to exclude a certain string from a file search. Suppose I have a list of files: file_Michael.txt, file_Thomas.txt, file_Anne.txt. I want to be able and write something like ls *<and not Thomas>.txt to give me file_Michael.txt and file_Anne.txt, but not file_Thomas.txt. The reverse is easy: ls *Thomas.txt Doing it with a single character is also easy: ls *[^s].txt But how to do it with a string? Sebastian

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• What's the best way to check that environment variables are set in Unix shellscript

  - by AndrewR

  I've got a few Unix shell scripts where I need to check that certain environment variables are set before I start doing stuff, so I do this sort of thing: if [ -z "$STATE" ]; then echo "Need to set STATE" exit 1 fi if [ -z "$DEST" ]; then echo "Need to set DEST" exit 1 fi which is a lot of typing. Is there a more elegant idiom for checking that a set of environment variables is set? EDIT: I should mention that these variables have no meaningful default value - the script should error out if any are unset.

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• Linux: Merging multiple files, each on a new line

  - by Marco

  I am using cat *.txt to merge multiple txt files into one, but I need each file to be on a separate line. What is the best way to merge files with each file appearing on a new line?

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• How to do a join of 3 files with awk by first Column?

  - by noinflection

  i have three similar files, they are all like this: ID1 Value1a ID2 Value2a . . . IDN Value2n and i want an output like this ID1 Value1a Value1b Value1c ID2 Value2a Value2b Value2c ..... IDN ValueNa ValueNb ValueNc Looking to the first line i want value1A to be the value of id1 in fileA, value1B the value of id1 in fileB, etc, i think of it like a nice sql join. I've tried several things but none of them where even close.

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• sed to insert on first match only

  - by SS.

  UPDATED: Using sed, how can I insert (NOT SUBSTITUTE) a new line on only the first match of keyword for each file. Currently I have the following but this inserts for every line containing Matched Keyword and I want it to only insert the New Inserted Line for only the first match found in the file: sed -ie '/Matched Keyword/ i\New Inserted Line' *.* For example: Myfile.txt: Line 1 Line 2 Line 3 This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6 changed to: Line 1 Line 2 Line 3 New Inserted Line This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6

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• bruteforce script

  - by oshirowanen

  I have forgotten my passphrase for my gpg key on linux. Can someone please help me write a simple script to use bruteforce to crack the key? I remember show of the words which MIGHT be in the passphrase, so hopefully, it will not take long for my computer to bruteforce it. All is not lost of I can't recover the passphrase, it just means I will not be able to work on my project for the next 10 days until I get back to work to get another copy of the files, but this time with a new key for which I will remember to passphrase.

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• Uninstall Git completely on Ubuntu?

  - by Millisami

  I installed Git on Ubuntu Lucid (latest) manually as following. cd ~/tmp wget http://kernel.org/pub/software/scm/git/git-1.7.0.6.tar.gz tar -xzvf git-1.7.0.6.tar.gz cd git-1.7.0.6.tar.gz ./configure sudo make sudo make install Now, how can I completely uninstall it?

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• select fields with sed

  - by Samantha

  Hey, Using only grep and sed, is there a way I can tranform the output of ls -l * into this : -rw-r--r-- agenda.txt -rw-r--r-- annuaire.txt Thanks!

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• How to create program that can be run by: #service myservice start

  - by Saif Bechan

  I am new to Linux and want to know what kind of programs can be run by using. #service myservice start And the programs stays on until stopped. Are they normal c++ programs or are they different. In some tutorials i have seen that they use ./myprogram to start a program. Another thing I have seen is the usage of .sh files. One last type of program i see is executed by the command: #/usr/bin/myprogramm Can someone explain the difference between these or point me to a basic tutorial/guide.

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• I write barely functional scripts that tend to not be resuable and make the baby jesus cry. Please h

  - by maxxpower

  I received a request to add around 100 users to a linux box the users are already in ldap so I can't just use newusers and point it at a text file. Another admin is taking care of the ldap piece so all I have to do is create all the home directories and chown them to the correct user once he adds the users to the box. creating the directories isn't a problem, but I'd like a more elegant script for chowning them to the correct user. what I have currently basically looks like chown -R testuser1 testgroup1 /home/tetsuser1; chown -R testuser2 testgroup2 /home/testgroup2; chown -R testsuser3 testgroup1 /home/testuser3 bascially I took the request that the user name and group name popped it into excel added a column of "chown -R" to the front, then added a column of "/", copied and pasted the username column after it and then added a column of ";" and dragged it down to the second to last row. Popped it into notepad ran some quick find and replaces and in less than a minute I have a completed request and a sad empty feeling. I know this was a really ghetto method and I'm trying to get away from using excel to avoid learning new scripting techniques so here's my real question. tl;dr I made 100 home directories and chowned them to the correct users, but it was ugly. Actual question below. You have a file named idlist that looks like this (only with say 1000 users and real usernames and groups) testuser1 testgroup1 testuser2 testgroup2 testuser3 testgroup1 write a script that creates home directories for all the users and chowns the created directories to the correct user and group. To make the directories I used the following(feel free to flame/correct me on this as well. ) var= 'cut -f1 -d" " idlist' (I used backticks not apostrophes around the cut command) mkdir $var

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• Using a dictionary file with sed

  - by Winston

  I have a blacklist.txt file that contains keywords I want to remove using sed. Here's what the blacklist.txt file contain winston@linux ] $ cat blacklist.txt obscure keywords here ... And here's what I have so far, but currently doesn't work. blacklist=$(cat blacklist.txt); output="filtered_file.txt" for i in $blacklist; do cat $input | sed 's/$i//g' >> $output done

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• Replace delimited block of text in file with the contents of another file

  - by rmarimon

  I need to write a simple script to replace a block of text in a configuration file with the contents of another file. Let's assume with have the following simplified files: server.xml <?xml version='1.0' encoding='UTF-8'?> <Server port="8005" shutdown="SHUTDOWN"> <Service name="Catalina"> <Connector port="80" protocol="HTTP/1.1"/> <Engine name="Catalina" defaultHost="localhost"> <!-- BEGIN realm --> <sometags/> <sometags/> <!-- END realm --> <Host name="localhost" appBase="webapps"/> </Engine> </Service> </Server> realm.xml <Realm className="org.apache.catalina.realm.UserDatabaseRealm" resourceName="UserDatabase"/> I want to run a script and have realm.xml replace the contents between the <!-- BEGIN realm --> and <!-- END realm --> lines. If realm.xml changes then whenever the script is run again it will replace the lines again with the new contents of realm.xml. This is intended to be run in /etc/init.d/tomcat on startup of the service on multiple installations on which the realm is going to be different. I'm not so sure how can I do this simply with awk or sed.

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• Dymanic if statement evaluation problem with string comparison

  - by Mani

  I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

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• grep 5 seconds of input from the serial port inside a shell-script

  - by pica

  I've got a device that I'm operating next to my PC and as it runs it's spitting log lines out it's serial port. I have this wired to my PC and I can see the log lines fine if I'm using either minicom or something like: ttylog -b 115200 -d /dev/ttyS0 I want to write 5 seconds of the device serial output to a temp file (or assign it to a variable) and then later grep that file for keywords that will let me know how the device is operating. I've already tried redirecting the output to a file while running the command in the background, and then sleeping 5 seconds and killing the process, but the log lines never get written to my temp file. Example: touch tempFile ttylog -b 115200 -d /dev/ttyS0 >> tempFile & serialPID=$! sleep 5 #kill ${serialPID} #does not work, gets wrong PID killall ttylog cat tempFile The file gets created but never filled with any data. I can also replace the ttylog line with: ttylog -b 115200 -d /dev/ttyS0 |tee -a tempFile & In neither case do I ever see any log lines logged to stdout or the log file unless I have multiple versions of ttylog running by mistake (see commented out line, D'oh). I have no idea what's going on here. It seems to be a failure of redirection within my script. Am I on the right track? Is there a better way to sample 5 seconds of the serial port?

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• Parsing the first column of a csv file to a new file.

  - by S1syphus

  Operating System: OSX Method: From the command line, so using sed, cut, gawk, although preferably no installing modules. Essentially I am trying to take the first column of a csv file and parse it to a new file. Example input file EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 Desire output EXAMPLEfoo EXAMPLEbar EXAMPLE1 EXAMPLE2 EXAMPLE3 EXAMPLE4 So I want the first column. Here is what I have tried so far: awk -F"," '{print $1}' in.csv > out.txt awk -F"," '{for (i=2;i<=NF;i++)}' in.csv > out.txt awk -F"," 'BEGIN { OFS="," }' '{print $1}' in.csv > out.txt cat in.csv | cut -d \, -f 1 > out.txt None seem to work, either they just print the first line or nothing at all, so I would assume it's failing to read line by line.

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• Invoking shell from java, it complaints "stty: standard input: Invalid argument"

  - by solotim

  Hi, everybody. I invoked shell command by Process class of java and it gave "stty: standard input: Invalid argument" no matter the command is right or wrong (normal output of shell command is shown too). If I run the shell command in shell, no such error message shows. I can't figure out why. Thanks

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• Trouble with piping through sed

  - by Joel

  I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

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• Script telnet on webserver

  - by Kami

  Hi I would like to script telnet to test my website inputs handling. I can do it manually : telnet localhost 8888 ... GET / HTTP/1.1\n Host: localhost ...html response But I can pass command to telnet in my shell script ! I've tried : (echo "GET / HTTP/1.1\n"; echo "Host: localhost \n\n"; sleep 1) | telnet localhost 8888 It produces no results at all !

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• Is there an API for calling system scripts/programs?

  - by Zeratul

  Hi, is there something like API built atop the standard ProcessBuilder for calling system programs? I won't argue that scripts can be ported to Java but utilities like arping and netstat are good-to-go in Linux.

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• strange behavior

  - by lego69

  I wrote simple script test echo hello <-- inside test if I press one time enter after hello, my script will run, if I don't press - it will not, if two times I'll receive my hello and + command was not found, can somebody please explain me this behavior thanks in advance

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• cmake source and out-of-source navigation

  - by idimba

  Hi, cmake advises to use out-of-source builds. While in general I like the idea I find it not comfortable to navigate from out-of-source sub directory to the corresponding source directory. I frequently need the code to perform some actions with code (e.g. grep, svn command etc.). Is there an easy way in shell to navigate from out-of-source sub directory to the corresponding source directory? Thanks Dima

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• How can I prevent default_environment variables from getting set by Capistrano's sudo action?

  - by Logan Koester

  My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

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• Redirect PHP-Shell-Script output

  - by Corelgott

  Hi Folks, i have got a php-script foo.php #!/usr/bin/php -c /etc/php5/cli/php.ini -q <?php echo 'hello'; // & do some stuff ?> I call this script not wrapped by a sh-script but using it directly in a cron job. To get rid of it's output i normally would just create a sh-file which calls /usr/bin/php -c /etc/php5/cli/php.ini -q foo.php > /dev/null 2 > /dev/null now i'd like to do this in the interpreter-declaration of the php file it self... so i am looking for the syntax for: #!/usr/bin/php -args [file's content] > /redirect 2 > /redirect i have kind of a hard time googleing for it... so if anybody could point me into the right direction i would really appreciate it! Thx in advance Corelgott

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• What happened to the TMP environment variable?

  - by Mark0978

  I always heard that the proper way to find the temporary folder on a UNIX machine was to look at the TMP environment variable. When writing code that worked on Windows as well as Linux, I would check for TEMP and TMP. Today, I discovered that my Ubuntu install does not have that environment variable at all. I know it seems you can always count on /tmp being there to put your temporary files in, but I understood that TMP was the way the user could tell you to put the temporary files someplace else. Is that still the case?

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