Search Results

Search found 32961 results on 1319 pages for 'java'.

Page 860/1319 | < Previous Page | 856 857 858 859 860 861 862 863 864 865 866 867  | Next Page >

  • Download Spring 2.5 sample applications

    - by Don
    Hi, I've seen various references to a couple of Spring MVC 2.5 example applications, named 'petclinic' and 'jpetstore'. I can't seem to find where to download these examples. Can anyone can provide a link to download them (ideally also with instructions for setup/deploying)? Thanks, Don

    Read the article

  • About GridLayout.

    - by Knowing me knowing you
    Hi, if I have code like so: class X extends JFrame { X() { setLayout(new GridLayout(3,3)); JButton b = new JButton("A-ha"); /*I would like to add this button in the center of this grid (2,2)*/ //How can I do it? } }; Thanks.

    Read the article

  • A beginner's JSF question about form validation

    - by Nitesh Panchal
    Hello, I am having a form and many input elements in that. I want certain fields to be validated, so i keep validateLenth etc on those. And i want some fields to not be validated. For example, i have contact information and address information both on the same page. I want to treat contact information as one group. So if some fields are invalid they should not be submitted and address information to be independent of contact information. Thus, if address information is corrected it should be submitted. I have one form only on the page but two buttons, one for address and one for contact. Simply put :- What is the equivalent of validationGroup of Asp.Net in JSF?

    Read the article

  • distinguishing a string with flex

    - by haluk
    Hi, I need to tokenize some strings which will be splitted of according to operators like = and !=. I was successful using regex until the string has != operator. In my case, string was seperated into two parts, which is expected but ! mark is in the left side even it is part of given operator. Therefore, I believe that regex is not suitable for it and I want to benefit from lex. Since I do not have enough knowledge and experience with lex, I am not sure whether it fits my work or not. Basically, I am trying to do replace the right hand side of the operators with actual values from other data. Do you people think that can it be helpful for my case? Thanks.

    Read the article

  • Finding duplicates in a list using recursion?

    - by user1760892
    I'm suppose to find if there is duplicates in a list and return true or false using recursion only (no loops). So if ArrayList of char is used, [a,b,c,d,e] should return false. [a,a,b,c,d] or [a,b,b,c,c,d] should return true. I've tried and tested different ways and it worked for some cases but not all. I changed my code around and this is what I have now. (Has problem at the last if statement) Can anyone give me some hints? Thanks. public static <T> boolean duplicate(List<T> list) throws NullPointerException { return duplicateHelper(list, list.get(0)); } public static <T> boolean duplicateHelper(List<T> list, T t){ if (list == null) throw new NullPointerException(); if(list.isEmpty()) return false; if(list.size() > 1){ if(t.equals(list.get(1))) return true; } if(list.size() == 1) return false; if(!duplicateHelper(list.subList(1,list.size()), t)){ return duplicate(list.subList(1,list.size())); } return false; }

    Read the article

  • Why is an anonymous inner class containing nothing generated from this code?

    - by Andrew Westberg
    When run through javac on the cmd line Sun JVM 1.6.0_20, this code produces 6 .class files OuterClass.class OuterClass$1.class OuterClass$InnerClass.class OuterClass$InnerClass2.class OuterClass$InnerClass$InnerInnerClass.class OuterClass$PrivateInnerClass.class When run through JDT in eclipse, it produces only 5 classes. OuterClass.class OuterClass$1.class OuterClass$InnerClass.class OuterClass$InnerClass2.class OuterClass$InnerClass$InnerInnerClass.class OuterClass$PrivateInnerClass.class When decompiled, OuterClass$1.class contains nothing. Where is this extra class coming from and why is it created? package com.test; public class OuterClass { public class InnerClass { public class InnerInnerClass { } } public class InnerClass2 { } //this class should not exist in OuterClass after dummifying private class PrivateInnerClass { private String getString() { return "hello PrivateInnerClass"; } } public String getStringFromPrivateInner() { return new PrivateInnerClass().getString(); } }

    Read the article

  • How to prevent the other threads from accessing a method when one thread is accessing a method?

    - by geeta
    I want to search for a string in 10 files and write the matching lines to a single file. I wrote the matching lines from each file to 10 output files(o/p file1,o/p file2...) and then copied those to a single file using 10 threads. But the output single file has mixed output(one line from o/p file1,another line from o/p file 2 etc...) because its accessed simultaneously by many threads. If I wait for all threads to complete and then write the single file it will be much slower. I want the output file to be written by one thread at a time. What should i do? My source code:(only writing to single file method) public void WriteSingle(File output_file,File final_output) throws IOException { synchronized(output_file){ System.out.println("Writing Single file"); FileOutputStream fo = new FileOutputStream(final_output,true); FileChannel fi = fo.getChannel(); FileInputStream fs = new FileInputStream(output_file); FileChannel fc = fs.getChannel(); int maxCount = (64 * 1024 * 1024) - (32 * 1024); long size = fc.size(); long position = 0; while (position < size) { position += fc.transferTo(position, maxCount, fi); } } }

    Read the article

  • Address calling class

    - by Samuel
    I have an abstract class Moveable with the method abstract void move() which is extended by the class Bullet and the abstract class Character, and Character is extended by the class Survivor and the class Zombie. In Survivor and Bullet the move() method doesnt require any parameters while in the class Zombie the move() method depends on the actual position of the survivor. The survivor and multiple zombies are created in the class Gui. I wanted to access the survivor in Zombie - what's the best way of doing this? In Gui i wrote a method getSurvivor() but i don't see how to access this method in Zombie? I am aware that as a workaround i could just pass a [Survivor survivor] as parameter in move() and ignore it in Bullet and Survivor, but that feels so ... bad practice.

    Read the article

  • Concept of creating static Map

    - by chetan
    I want to create a Map object that can lose value only if we explicitly delete it from map. I have created Map object like public static Map<Long,String> listUser =new HasMap<Long,String>(); but every time class object is created new instance of Map is also created that contain null value. I want to create a Map instance that contain value we stored before.

    Read the article

  • How do I remove the leaves of a binary tree?

    - by flopex
    I'm trying to remove all of the leaves. I know that leaves have no children, this is what I have so far. public void removeLeaves(BinaryTree n){ if (n.left == null && n.right == null){ n = null; } if (n.left != null) removeLeaves(n.left); if (n.right != null) removeLeaves(n.right); }

    Read the article

  • Resultset (getter/setter class) object not deleting old values at 2nd Time execution in swin

    - by user2384525
    I have summarizeData() method and called so many time for value retrieve. but first time is working file but 2nd time execution value is increasing in HashMap. void summarizeData() { HashMap outerMap = new HashMap(); ArrayList list = new ArrayList(dataClass.getData()); for (int indx = 0; indx < list.size(); indx++) { System.out.println("indx : " + indx); Resultset rs = new Resultset(); rs = (Resultset) list.get(indx); if (rs != null) { int id = rs.getTestCaseNumber(); if (id > 0) { Object isExists = outerMap.get(id); if (isExists != null) { //System.out.println("found entry so updating"); Resultset inRs = new Resultset(); inRs = (Resultset) isExists; if (inRs != null) { int totExec = inRs.getTestExecution(); int totPass = inRs.getTestCasePass(); int totFail = inRs.getTestCaseFail(); // System.out.println("totE :" + totExec + " totP:" + totPass + " totF:" + totFail); int newRsStat = rs.getTestCasePass(); if (newRsStat == 1) { totPass++; inRs.setTestCasePass(totPass); } else { totFail++; inRs.setTestCaseFail(totFail); } totExec++; // System.out.println("id : "+id+" totPass: "+totPass+" totFail:"+totFail); // System.out.println("key : " + id + " val : " + inRs.getTestCaseNumber() + " " + inRs.getTestCasePass() + " " + inRs.getTestCaseFail()); inRs.setTestExecution(totExec); outerMap.put(id, inRs); } } else { // System.out.println("not exist so new entry" + " totE:" + rs.getTestExecution() + " totP:" + rs.getTestCasePass() + " totF:" + rs.getTestCaseFail()); outerMap.put(id, rs); } } } else { System.out.println("rs null"); } } Output at 1st Execution: indx : 0 indx : 1 indx : 2 indx : 3 indx : 4 indx : 5 indx : 6 indx : 7 indx : 8 indx : 9 indx : 10 totE :1 totP:1 totF:0 indx : 11 totE :1 totP:1 totF:0 indx : 12 totE :1 totP:1 totF:0 indx : 13 totE :1 totP:1 totF:0 indx : 14 totE :1 totP:1 totF:0 indx : 15 totE :1 totP:1 totF:0 indx : 16 totE :1 totP:1 totF:0 indx : 17 totE :1 totP:1 totF:0 indx : 18 totE :1 totP:1 totF:0 indx : 19 totE :1 totP:1 totF:0 Output at 2nd Execution: indx : 0 indx : 1 indx : 2 indx : 3 indx : 4 indx : 5 indx : 6 indx : 7 indx : 8 indx : 9 indx : 10 totE :2 totP:2 totF:0 indx : 11 totE :2 totP:2 totF:0 indx : 12 totE :2 totP:2 totF:0 indx : 13 totE :2 totP:2 totF:0 indx : 14 totE :2 totP:2 totF:0 indx : 15 totE :2 totP:2 totF:0 indx : 16 totE :2 totP:2 totF:0 indx : 17 totE :2 totP:2 totF:0 indx : 18 totE :2 totP:2 totF:0 indx : 19 totE :2 totP:2 totF:0 while i required same output on every execution.

    Read the article

  • Get the screen height in Android

    - by Dan Bray
    How can I get the available height of the screen in Android? I need to the height minus the status bar / menu bar or any other decorations that might be on screen and I need it to work for all devices. Also, I need to know this in the onCreate function. I know this question has been asked before but I have already tried their solutions and none of them work. Here are some of the things I have tried: I have tested this code on API 7 - 17. Unfortunately, on API 13 there is extra space at bottom both horizontally and vertically and on API 10, 8, and 7 there is not enough space at the bottom both horizontally and vertically. (I have not tested on obsolete API's): Display display = getWindowManager().getDefaultDisplay(); DisplayMetrics metrics = new DisplayMetrics(); display.getMetrics(metrics); screenWidth = metrics.widthPixels; screenHeight = metrics.heightPixels; TypedValue tv = new TypedValue(); if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB) { if (getTheme().resolveAttribute(android.R.attr.actionBarSize, tv, true)) screenHeight -= TypedValue.complexToDimensionPixelSize(tv.data,getResources().getDisplayMetrics()); } int resourceId = getResources().getIdentifier("status_bar_height", "dimen", "android"); if (resourceId > 0) screenHeight -= getResources().getDimensionPixelSize(resourceId); This does not take into account the status bar / menu bar: Display display = getWindowManager().getDefaultDisplay(); screenWidth = display.getWidth(); screenHeight = display.getHeight(); Neither does this: Point size = new Point(); getWindowManager().getDefaultDisplay().getSize(size); screenWidth = size.x; screenHeight = size.y; Nor this: Point size = new Point(); getWindowManager().getDefaultDisplay().getRealSize(size); screenWidth = size.x; screenHeight = size.y; This does not work: Display display = getWindowManager().getDefaultDisplay(); DisplayMetrics metrics = new DisplayMetrics(); display.getMetrics(metrics); // since SDK_INT = 1; screenWidth = metrics.widthPixels; screenHeight = metrics.heightPixels; try { // used when 17 > SDK_INT >= 14; includes window decorations (statusbar bar/menu bar) screenWidth = (Integer) Display.class.getMethod("getRawWidth").invoke(display); screenHeight = (Integer) Display.class.getMethod("getRawHeight").invoke(display); } catch (Exception ignored) { // Do nothing } try { // used when SDK_INT >= 17; includes window decorations (statusbar bar/menu bar) Point realSize = new Point(); Display.class.getMethod("getRealSize", Point.class).invoke(display, realSize); screenWidth = realSize.x; screenHeight = realSize.y; } catch (Exception ignored) { // Do nothing } I then used the following code to subtract the height of the status bar and menu bar from the screen height: int result = 0; int resourceId = getResources().getIdentifier("status_bar_height", "dimen", "android"); if (resourceId > 0) result = getResources().getDimensionPixelSize(resourceId); screenHeight -= result; result = 0; if (screenHeight >= screenWidth) resourceId = getResources().getIdentifier("navigation_bar_height", "dimen", "android"); else resourceId = getResources().getIdentifier("navigation_bar_height_landscape", "dimen", "android"); if (resourceId > 0) result = getResources().getDimensionPixelSize(resourceId); screenHeight -= result; On API 17 it correctly calculates the height of the status bar and menu bar in portrait but not in landscape. On API 10, it returns 0. I need it to work ideally on all devices or minimum API 7. Any help would be greatly appreciated.

    Read the article

  • hibernate insert to a collection causes a delete then all the items in the collection to be inserted

    - by Mark
    I have a many to may relationship CohortGroup and Employee. Any time I insert an Employee into the CohortGroup hibernate deletes the group from the resolution table and inserts all the members again, plus the new one. Why not just add the new one? The annotation in the Group: @ManyToMany(cascade = { PERSIST, MERGE, REFRESH }) @JoinTable(name="MYSITE_RES_COHORT_GROUP_STAFF", joinColumns={@JoinColumn(name="COHORT_GROUPID")}, inverseJoinColumns={@JoinColumn(name="USERID")}) public List<Employee> getMembers(){ return members; } The other side in the Employee @ManyToMany(mappedBy="members",cascade = { PERSIST, MERGE, REFRESH } ) public List<CohortGroup> getMemberGroups(){ return memberGroups; } Code snipit Employee emp = edao.findByID(cohortId); CohortGroup group = cgdao.findByID(Long.decode(groupId)); group.getMembers().add(emp); cgdao.persist(group); below is the sql reported in the log delete from swas.MYSITE_RES_COHORT_GROUP_STAFF where COHORT_GROUPID=? insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) insert into swas.MYSITE_RES_COHORT_GROUP_STAFF (COHORT_GROUPID, USERID) values (?, ?) This seams really inefficient and is causing some issues. If sevral requests are made to add an employee to the group then some get over written.

    Read the article

  • Run Jav-applets directly

    - by PleaseHelpMe
    Hello guys. I have a problem. how i can run my hava-aplet directly without embendend in my web page? If i answer on this question in a few minutes i will pass exam else i going out from university!!! please guys help!!

    Read the article

  • Persistence store in blackberry

    - by arunabha
    i am trying to save a simple string value "1".If i go back from one screen to another,its saving,but when i exit the app,and start again,i dont see that value being saved.I am implementing persistable interface.Can anyone suggest me where i am getting wrong import net.rim.device.api.util.Persistable; import net.rim.device.api.system.PersistentObject; import net.rim.device.api.system.PersistentStore; public class Persist implements Persistable { public static PersistentObject abc; public static String b; static { abc = PersistentStore.getPersistentObject(0xb92c8fe20b256b82L); } public static void data(){ synchronized (abc) { abc.setContents(1+""); abc.commit(); } } public static String getCurrQuestionNumber() { synchronized (abc) { System.out.println("new title is"+b); b= (String)abc.getContents(); System.out.println("title is"+b); return b; } } }

    Read the article

  • req.getParameter returns values wrong character encoding

    - by coder247
    I'm trying to get values from a JSP using getParameter which includes ü,é,à etc. But get wrong values in servlet. I've checked the content type with firebug and found that Content-Type text/html;charset=UTF-8 checked the POST section with firebug and found the correct value there, when I try to access it in servlet it is wrong. Gives ö instead of ö req.getCharacterEncoding(); returns null. Tried with setting req.setCharacterEncoding("UTF-8"); at the beginning of servlet but didn't help.

    Read the article

  • Tile Engine: Entity location wrong

    - by Trizicus
    I've made a tile engine that has 30px by 30px. I've ran into a problem with an object for example. I've loaded an object 20px by 20px and when I do a collision check I have to use x/y position which is top left in Java2D. How can I do collision detection based on the entire object? This is relevant code: boolean checkCol() { int currentGridX = ship.getX()/30; int currentGridY = ship.getY()/30; if(test[currentGridX][currentGridY] == 0) return true; System.out.println("collision"); return false; }

    Read the article

  • How hide some nodes in Richfaces Tree (do not render nodes by condition)?

    - by VestniK
    I have a tree of categories and courses in my SEAM application. Courses may be active and inactive. I want to be able to show only active or all courses in my tree. I've decided to always build complete tree in my PAGE scope component since building this tree is quite expensive operation. I have boolean flag courseActive in the data wrapped by TreeNode<T>. Now I can't find the way to show courses node only if this flag is true. The best result I've achieved with the following code: <h:outputLabel for="showInactiveCheckbox" value="show all courses: "/> <h:selectBooleanCheckbox id="showInactiveCheckbox" value="#{categoryTreeEditorModel.showAllCoursesInTree}"> <a4j:support event="onchange" reRender="categoryTree"/> </h:selectBooleanCheckbox> <rich:tree id="categoryTree" value="#{categoryTree}" var="item" switchType="ajax" ajaxSubmitSelection="true" reRender="categoryTree,controls" adviseNodeOpened="#{categoryTreeActions.adviseRootOpened}" nodeSelectListener="#{categoryTreeActions.processSelection}" nodeFace="#{item.typeName}"> <rich:treeNode type="Category" icon="..." iconLeaf="..."> <h:outputText value="#{item.title}"/> </rich:treeNode> <rich:treeNode type="Course" icon="..." iconLeaf="..." rendered="#{item.courseActive or categoryTreeEditorModel.showAllCoursesInTree}"> <h:outputText rendered="#{item.courseActive}" value="#{item.title}"/> <h:outputText rendered="#{not item.courseActive}" value="#{item.title}" style="color:#{a4jSkin.inactiveTextColor}"/> </rich:treeNode> </rich:tree> the only problem is if some node is not listed in any rich:treeNode it just still shown with title obtained by Object.toString() method insted of being hidden. Does anybody know how to not show some nodes in the Richfases tree according to some condition?

    Read the article

  • regex: trim all strings directly preceeded by digit except if string belongs to predefined set of st

    - by Geert-Jan
    I've got addresses I need to clean up for matching purposes. Part of the process is trimming unwanted suffices from housenumbers, e.g: mainstreet 4a --> mainstreet 4. However I don't want: 618 5th Ave SW --> 618 5 Ave SW in other words there are some strings (for now: st, nd, rd, th) which I don't want to strip. What would be the best method of doing this (regex or otherwise) ? a wokring regex without the exceptions would be: a = a.replaceAll("(^| )([0-9]+)[a-z]+($| )","$1$2$3"); //replace 1a --> 1 I thought about first searching and substiting the special cases with special characters while keeping the references in a map, then do the above regex, and then doing the reverse substitute using the reference map, but I'm looking for a simpler solution. Thanks

    Read the article

< Previous Page | 856 857 858 859 860 861 862 863 864 865 866 867  | Next Page >