Search Results

Search found 32961 results on 1319 pages for 'java'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 880/1319 | < Previous Page | 876 877 878 879 880 881 882 883 884 885 886 887  | Next Page >

  • Android 2.1 How to get Phone Numbers of contacts.

    - by Brandon Delany
    Hi, I am new to Android and have been working on an app that needs to get all of the user's contact's phone numbers. Apparently the code I have does not work with the 2.1 SDK. So far here is the code I am using: String[] projection = new String[] { Phone.NUMBER }; Cursor c = managedQuery( Phone.CONTENT_URI, projection, null, null, null ); int colIndex = -1; try { colIndex = c.getColumnIndexOrThrow( Phone.NUMBER ); } catch( Exception e ) { print( e.getMessage() ); } print( "Column Index = " + colIndex ); //count is equal to 3 for( int i = 0; i < count; i++ ){ try { print( c.getString( 2 ) ); //the 2 used to be colIndex } catch ( Exception e ) { print( e.getMessage() ); } } It seems that no matter what I pass into c.getString() it keeps telling me that I passed in -1. But I even hardcoded the 2, and it says the same thing. Any help would be much appreciated.

    Read the article

  • save input from text file to array

    - by Jessy
    How to save txt file content to different arrays? my txt file content is like this; 12 14 16 18 13 17 14 18 10 23 pic1 pic2 pic3 pic4 pic5 pic6 pic7 pic8 pic9 pic10 left right top left right right top top left right 100 200 300 400 500 600 700 800 900 1000 how can I save each line into different array? e.g. line 1 will be saved in an array1 line 2 will be saved in an array2 line 3 will be saved in an array3 line 4 will be saved in an array4 Thanks you

    Read the article

  • Batch processing JDBC

    - by Wai Hein
    I am practicing JDBC batch processing and having errors: error 1: Unsupported feature error 2: Execute cannot be empty or null Property files include: itemsdao.updateBookName = Update Books set bookname = ? where books.id = ? itemsdao.updateAuthorName = Update books set authorname = ? where books.id = ? I know I can execute about DML statements in one update, but I am practicing batch processing in JDBC. Below is my method public void update(Item item) { String query = null; try { connection = DbConnector.getConnection(); property = SqlPropertiesLoader.getProperties("dml.properties"); connection.setAutoCommit(false); if ( property == null ) { Logging.log.debug("dml.properties does not exist. Check property loader or file name is spelled right"); return; } query = property.getProperty("itemsdao.updateBookName"); statement = connection.prepareStatement(query); statement.setString(1, item.getBookName()); statement.setInt(2, item.getId()); statement.addBatch(query); query = property.getProperty("itemsdao.updateAuthorName"); statement = connection.prepareStatement(query); statement.setString(1, item.getAuthorName()); statement.setInt(2, item.getId()); statement.addBatch(query); statement.executeBatch(); connection.commit(); }catch (ClassNotFoundException e) { Logging.log.error("Connection class does not exist", e); } catch (SQLException e) { Logging.log.error("Violating PK constraint",e); } //helper class th finally { DbUtil.close(connection); DbUtil.closePreparedStatement(statement); }

    Read the article

  • schedule task with spring mvc

    - by user3586352
    I want to run the following method every specific time in spring mvc project it works fine and print first output but it doesn't access the database so it doesn't display list the method public class ScheduleService { @Autowired private UserDetailService userDetailService; public void performService() throws IOException { System.out.println("first output"); List<UserDetail> list=userDetailService.getAll(); System.out.println(list); } config file <!-- Spring's scheduling support --> <task:scheduled-tasks scheduler="taskScheduler"> <task:scheduled ref="ScheduleService" method="performService" fixed-delay="2000"/> </task:scheduled-tasks> <!-- The bean that does the actual work --> <bean id="ScheduleService" class="com.ctbllc.ctb.scheduling.ScheduleService" /> <!-- Defines a ThreadPoolTaskScheduler instance with configurable pool size. --> <task:scheduler id="taskScheduler" pool-size="1"/>

    Read the article

  • How to listen to JComboBox's width changes?

    - by agnieszka
    I tried PropertyChangeListener with property set to "width", "Width", "size" and "Size". PropertyChangeListener widthChangeListener = new PropertyChangeListener() { @Override public void propertyChange(PropertyChangeEvent evt) { //code } }; streamsComboBox.addPropertyChangeListener("width", widthChangeListener); projectsComboBox.addPropertyChangeListener("width", widthChangeListener); vobsComboBox.addPropertyChangeListener("width", widthChangeListener); Nothing works - the handler method is never fired. What should I do to handle JComboBox's size change? Where does the property name come from anyway?

    Read the article

  • Refactoring a long method that simply populates

    - by Jeune
    I am refactoring a method which is over 500 lines (don't ask me why) The method basically queries a list of maps from the database and for each map in the list does some computation and adds the value of that computation to the map. There are however too many computations and puts being done that the code has reached over 500 lines already! Here's a sample preview: public List<Hashmap> getProductData(...) { List<Hashmap> products = productsDao.getProductData(...); for (Product product: products) { product.put("Volume",new BigDecimanl(product.get("Height")* product.get("Width")*product.get("Length")); if (some condition here) { //20 lines worth of product.put(..,..) } else { //20 lines worth of product.put(..,..) } //3 more if-else statements like the one above try { product.put(..,..) } catch (Exception e) { product.put("",..) } //over 8 more try-catches of the form above } Any ideas on how to go about refactoring this?

    Read the article

  • Client for restful web service

    - by Ish
    I'd like to create a http-centric client for a restful web service created using CXF. To that end: Does any one know the (maven) dependencies for ONLY the CXF clients (Proxy & HTTP)? Is there any advantage to using CXF's built-in clients over say, Apache HttpClient?

    Read the article

  • How to represent a Many-To-Many relationship in XML or other simple file format?

    - by CSharperWithJava
    I have a list management appliaction that stores its data in a many-to-many relationship database. I.E. A note can be in any number of lists, and a list can have any number of notes. I also can export this data to and XML file and import it in another instance of my app for sharing lists between users. However, this is based on a legacy system where the list to note relationship was one-to-many (ideal for XML). Now a note that is in multiple lists is esentially split into two identical rows in the DB and all relation between them is lost. Question: How can I represent this many-to-many relationship in a simple, standard file format? (Preferably XML to maintain backwards compatibility)

    Read the article

  • Best practice for passing configuration to each GUI object

    - by Laimoncijus
    Hi, I am writing an application, where I do have few different windows implemented, where each window is a separate class. Now I need somehow to pass a single configuration object to all of them. My GUI is designed in way, where I have one main window, which may create some child windows of its own, and these child windows can have their own childs (so there is no possibility to create all windows in initialization part and feed the config object to all of them from the very beginning)... What would be best practice for sharing this configuration object between them? Always passing via constructor or maybe making it somewhere as final public static and let each window object to access it when needed? Thanks

    Read the article

  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

    Read the article

  • Why Hibernates ignores the name attribute of the @Column annotation?

    - by svachon
    Using Hibernate 3.3.1 and Hibernate Annotations 3.4, the database is DB2/400 V6R1, running that on WebSphere 7.0.0.9 I have the following class @Entity public class Ciinvhd implements Serializable { @Id private String ihinse; @Id @Column(name="IHINV#") private BigDecimal ihinv; .... } For reasons I can't figure, Hibernate ignores the specified column name and uses 'ihinv' to generate the SQL: select ciinvhd0_.ihinse as ihinse13_, ciinvhd0_.ihinv as ihinv13_, ... Which of course gives me the following error: Column IHINV not in table CIINVHD Did anyone had this problem before? I have other entities that are very alike in the way that they are using # in their database field names and that are part of the PK and I don't have this problem with them.

    Read the article

  • need an empty XML while unmarshalling a JAXB annotated class

    - by sswdeveloper
    I have a JAXB annotated class Customer as follows @XmlRootElement(namespace = "http://www.abc.com/customer") public class Customer{ private String name; private Address address; @XmlTransient private HashSet set = new HashSet<String>(); public String getName(){ return name; } @XmlElement(name = "Name", namespace = "http://www.abc.com/customer" ) public void setName(String name){ this.name = name; set.add("name"); } public String getAddress(){ return address; } @XmlElement(name = "Address", namespace = "http://www.abc.com/customer") public void setAddress(Address address){ this.address = address; set.add("address"); } public HashSet getSet(){ return set; } } I need to return an empty XML representing this to the user, so that he may fill the necesary values in the XML and send a request So what I require is : <Customer> <Name></Name> <Address></Address> </Customer> If i simply create an empty object Customer cust = new Customer() ; marshaller.marshall(cust,sw); all I get is the toplevel element since the other fields of the class are unset. What can I do to get such an empty XML? I tried adding the nillable=true annotation to the elements however, this returns me an XML with the xsi:nil="true" which then causes my unmarshaller to ignore this. How do I achieve this?

    Read the article

  • Tomcat does not persist Session during restart

    - by mabuzer
    How to force Tomcat to serialize Session so that the user is kept logged in when Tomcat has restarted? Right now the user has to login again everytime. Added the following lines into web-app context.xml: <Manager className="org.apache.catalina.session.PersistentManager"> <Store className="org.apache.catalina.session.FileStore"/> </Manager> but still I see login page after Tomcat restart, I use Tomcat 6.0.24

    Read the article

  • Android: sending xml as document object, POST method

    - by juro
    i am new at programming and i need some help with that please =/ web service is already written but not by me. so all i have to do is send xml as document object by post method through web service. my code: public class send extends application { @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://app.local/test/"); try { DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder = documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement("packet"); rootElement.setAttribute("version", "1.2"); document.appendChild(rootElement); Element em = document.createElement("imei"); em.appendChild(document.createTextNode("000000000000000")); rootElement.appendChild(em); em = document.createElement("username"); em.appendChild(document.createTextNode("5555")); rootElement.appendChild(em); HttpResponse response = httpclient.execute(httppost); } catch (Exception e) { System.out.println("XML Pasing Excpetion = " + e); } } }

    Read the article

  • Can JAXB store the class name in the XML so that the the deserialize code doesn't need knowledge of the class?

    - by Andrew
    It seems the standard approach for deserializing JAXB XML is to specify the package name when creating the context. Then, JAXB looks up the class based on the root element: JAXBContext jc = JAXBContext.newInstance("com.foo"); Unmarshaller u = jc.createUnmarshaller(); Object o = u.unmarshal(new StringReader("...")); I'm looking for a more flexible approach where I don't have to specify the package name and could still deserialize any object. This would be as simple as JAXB storing the package in the XML, but I can't seem to find out how to do this. I can write the code to do it myself but that would be unpleasant. It would like JAXB to do it, if possible. BTW, I am not using schemas, just Annotations and marshal/unmarshal. Any ideas?

    Read the article

  • [Android] XML Parser

    - by lemon
    I'm trying to extract n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= using w3c dom <html> <div id='token' style='display:none;'> n0Y7ezLlIYA8R0K54rEmHaTOraBQVSPDjQaGlQxlGso4jdVN1kRxtcfskEs= </div> </html> but I seem to be stuck DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); Document doc = builder.parse(con.getInputStream()); NodeList list = doc.getElementsByTagName("div"); Can someone please point me to some basic tutorials that would help me solve my dilemma. Thanks.

    Read the article

  • why does .apk is not getting installed in android emulator ?

    - by Saravana
    I tried the following code with android 2.3.3 (AVD). When i run this code it waits saying Waiting for HOME ('android.process.acore') to be launched... but keeps on waiting. So i tried running second time .. this time it says [2011-03-04 12:28:39 - DialANumber] Uploading DialANumber.apk onto device 'emulator-5554' [2011-03-04 12:28:39 - DialANumber] Installing DialANumber.apk... [2011-03-04 12:29:14 - DialANumber] HOME is up on device 'emulator-5554' [2011-03-04 12:29:14 - DialANumber] Uploading DialANumber.apk onto device 'emulator-5554' [2011-03-04 12:29:14 - DialANumber] Installing DialANumber.apk... and after some time fails with [2011-03-04 12:31:37 - DialANumber] Failed to install DialANumber.apk on device 'emulator-5554! [2011-03-04 12:31:37 - DialANumber] (null) [2011-03-04 12:31:39 - DialANumber] Launch canceled! the code follows: package com.DialANumber; import android.app.Activity; import android.content.Intent; import android.net.Uri; import android.os.Bundle; import android.view.KeyEvent; import android.view.View; import android.widget.Button; import android.widget.EditText; import android.widget.LinearLayout; public class DialANumber extends Activity { EditText mEditText_number = null; LinearLayout mLinearLayout_no_button = null; Button mButton_dial = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); mLinearLayout_no_button = new LinearLayout(this); mEditText_number = new EditText(this); mEditText_number.setText("5551222"); mLinearLayout_no_button.addView(mEditText_number); mButton_dial = new Button(this); mButton_dial.setText("Dial!"); mLinearLayout_no_button.addView(mButton_dial); mButton_dial.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { performDial(); } }); setContentView(mLinearLayout_no_button); } public boolean onKeyDown(int keyCode, KeyEvent event) { if (keyCode == KeyEvent.KEYCODE_CALL) { performDial(); return true; } return false; } public void performDial(){ if(mEditText_number!=null){ try { startActivity(new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + mEditText_number.getText()))); } catch (Exception e) { e.printStackTrace(); } }//if } } I am just starting to learn developing android apps. please help me out.. Thanks.

    Read the article

  • How can I get a project type on Netbeans Platform?

    - by Fabio
    Hi folks, Is there a way to know the type of a selected project? I would like to do some specific actions depending of the project type like a J2SE project. Below is the only way that I found to do that: public final class MyAction extends CookieAction { @Override public boolean isEnabled() { if(this.getActivatedNodes() == null || this.getActivatedNodes().length != 1) { return false; } Lookup lookup = this.getActivatedNodes()[0].getLookup(); // gets the selected project Project currentProject = lookup.lookup(Project.class); // checks if the selected project is a J2SE Project or a Maven Project if(currentProject != null && (currentProject.getClass().getSimpleName().equals("J2SEProject") || currentProject.getClass().getSimpleName().equals("NbMavenProjectImpl"))) { return true; } return false; }}

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 876 877 878 879 880 881 882 883 884 885 886 887  | Next Page >