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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • jQuery sortable (how to customize the clickable area inside the sortable box)

    - by cvack
    I have this jQuery code: $(".right_box_holder").sortable({ update : function () { var order = $('.right_box_holder').sortable('serialize'); $.get("right_menu_functions.php?change_sortorder&"+order); } }); and this HTML code: <div class='right_box_holder'> <div class='right_box' id='box_0'> // sort box 0 </div> <div class='right_box' id='box_1'> // sort box 1 </div> <div class='right_box' id='box_2'> // sort box 2 </div> </div> As it is now, I can click anywhere inside .right_box and move it. I want to disable this and make a button / icon inside .right_box which the user have to click on to drag the box. Is this possible?

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  • Bucket sort for integers

    - by rafael
    Could anybody help me with bucket sort algorithm for integers ? It's often mistake when people say they have this algorithm, but this is counting sort ! Maybe it works similar, but it is something different. I hope you will help mi find the right way, 'cause now I have no idea (Cormen's book and Wikipedia are not so helpful). Thanks in advance for all your respones.

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  • Sort a data grid based on a specified column.

    - by o vamsi krishna
    Developed a winform project using VB 2008. I'm using a .xls sheet as source. My appln has 7 columns and unspecified rows. I want to sort all the columns based on a specified column and allot a serial number as per the sorted order. If two items in the specified column are same we should consider another column for the equal items and sort them in that order. plz help me in this issue.

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  • Getting Serial Port Information in C#

    - by Jim Fell
    I have some code that loads the serial ports into a combo-box: List<String> tList = new List<String>(); comboBoxComPort.Items.Clear(); foreach (string s in SerialPort.GetPortNames()) { tList.Add(s); } tList.Sort(); comboBoxComPort.Items.Add("Select COM port..."); comboBoxComPort.Items.AddRange(tList.ToArray()); comboBoxComPort.SelectedIndex = 0; I would like to add the port descriptions (similar to what are shown for the COM ports in the Device Manager) to the list and sort the items in the list that are after index 0 (solved: see above snippet). Does anyone have any suggestions for adding the port descriptions? I am using Microsoft Visual C# 2008 Express Edition (.NET 2.0). Any thoughts you may have would be appreciated. Thanks.

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  • LINQ OrderBy: best search results at top of results list

    - by p.campbell
    Consider the need to search a list of Customer by both first and last names. The desire is to have the results list sorted by the Customer with the most matches in the search terms. FirstName LastName ---------- --------- Foo Laurie Bar Jackson Jackson Bro Laurie Foo Jackson Laurie string[] searchTerms = new string[] {"Jackson", "Laurie"}; //want to find those customers with first, last or BOTH names in the searchTerms var matchingCusts = Customers .Where(m => searchTerms.Contains(m.FirstName) || searchTerms.Contains(m.LastName)) .ToList(); /* Want to sort for those results with BOTH FirstName and LastName matching in the search terms. Those that match on both First and Last should be at the top of the results, the rest who match on one property should be below. */ return matchingCusts.OrderBy(m=>m); Desired Sort: Jackson Laurie (matches on both properties) Foo Laurie Bar Jackson Jackson Bro Laurie Foo How can I achieve this desired functionality with LINQ and OrderBy / OrderByDescending?

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  • How to drag items between 2 sorted lists with jQuery?

    - by sa125
    Hi - I'm trying to implement drag/drop/sort between 2 list elements: <ul id="first"> <li>item 1</li> <li>item 2</li> <li>item 3</li> </ul> <ul id="second"> <li>item 4</li> <li>item 5</li> <li>item 6</li> </ul> Basically I just want to be able to pass items between the lists and sort the items in each list. What's the simplest way to implement this using jQuery?

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  • ruby on rails, searchlogic and refactoring

    - by JohnMerlino
    Hey all, I'mt not too familiar with searchlogic plugin for rails (I did view the railscasts but wasn't helpful in relation to the specific code below). Can anyone briefly describe how it is being used in the three methods below? Thanks for any response. def extract_order @order_by = if params[:order].present? field = params[:order].gsub(".", "_") field = field.starts_with?('-') ? 'descend_by_'+field[1..-1] : 'ascend_by_'+field field.to_sym else # Workaround 'searchlogic'.to_sym end end def find_resources @search_conditions = params[:search_conditions] || {} # See http://www.binarylogic.com/2008/11/30/searchlogic-1-5-7-complex-searching-no-longer-a-problem/ @resources = @resource_model.send(@order_by).searchlogic(:conditions => @search_conditions) end def apply_filters f = filter_by f.each do |filter_field| filter_constraints = params[filter_field.to_sym] if filter_constraints.present? # Apply searchlogic's scope @resources.send(filter_field,filter_constraints) end end end

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  • Searchlogic cannot sort search result

    - by jaycode
    Imagine a code: search = Project.search( :title_or_description_or_child_name_or_child_age_or_inspiration_or_decorating_style_or_favorite_item_or_others_like_any => keys, :galleries_id_like_any => @g, :styles_id_like_any => @st, :tags_like_any => @t ) search.all returns the rows correctly. But search.descend_by_views returns nil. Is this gem buggy? What else should I use then?

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  • How to Sort ip addresses and merge two files in efficent manner using perl or *nix commands?

    - by berkay
    (*) This problem should be done in perl or any *nix commands. i'm working on a program and efficiency matters.The file1 consists ip addresses and some other data: index ipsrc portsrc ip dest port src 8 128.3.45.10 2122 169.182.111.161 80 (same ip src and dst) 9 128.3.45.10 2123 169.182.111.161 22 (same ip src and dst) 10 128.3.45.10 2124 169.182.111.161 80 (same ip src and dst) 19 128.3.45.128 62256 207.245.43.126 80 and other file2 looks like (file1 and file2 are in different order) 128.3.45.10 ioc-sea-lm 169.182.111.161 microsoft-ds 0 0 3 186 3 186 128.3.45.10 hypercube-lm 169.182.111.161 https 0 0 3 186 3 186 128.3.44.112 pay-per-view 148.184.171.6 netbios-ssn 0 0 3 186 3 186 128.3.45.12 cadabra-lm 148.184.171.6 microsoft-ds 0 0 3 186 3 186 1- SORT file1 using IP address in second column and SORT file2 using IP address in first column 2- Merge the 1st, 3rd and 5th columns of File1 with File 2 i need to create a new file which will look: 128.3.45.10 ioc-sea-lm 169.182.111.161 microsoft-ds 0 0 3 186 3 186 --> 2122 80 8 128.3.45.10 hypercube-lm 169.182.111.161 https 0 0 3 186 3 186 --> 2123 22 9 128.3.44.112 pay-per-view 148.184.171.6 netbios-ssn 0 0 3 186 3 186 --> * * * 128.3.45.12 cadabra-lm 148.184.171.6 microsoft-ds 0 0 3 186 3 186 --> * * * basically port numbers and index number will be added.

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  • Sort algorithm with fewest number of operations

    - by luvieere
    What is the sort algorithm with fewest number of operations? I need to implement it in HLSL as part of a pixel shader effect v2.0 for WPF, so it needs to have a really small number of operations, considering Pixel Shader's limitations. I need to sort 9 values, specifically the current pixel and its neighbors.

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  • C# .NET: Descending comparison of a SortedDictionary?

    - by Rosarch
    I'm want a IDictionary<float, foo> that returns the larges values of the key first. private IDictionary<float, foo> layers = new SortedDictionary<float, foo>(new DescendingComparer<float>()); class DescendingComparer<T> : IComparer<T> where T : IComparable<T> { public int Compare(T x, T y) { return -y.CompareTo(x); } } However, this returns values in order of the smallest first. I feel like I'm making a stupid mistake here. Just to see what would happen, I removed the - sign from the comparator: public int Compare(T x, T y) { return y.CompareTo(x); } But I got the same result. This reinforces my intuition that I'm making a stupid error. This is the code that accesses the dictionary: foreach (KeyValuePair<float, foo> kv in sortedLayers) { // ... } UPDATE: This works, but is too slow to call as frequently as I need to call this method: IOrderedEnumerable<KeyValuePair<float, foo>> sortedLayers = layers.OrderByDescending(kv => kv.Key); foreach (KeyValuePair<float, ICollection<IGameObjectController>> kv in sortedLayers) { // ... } UPDATE: I put a break point in the comparator that never gets hit as I add and remove kv pairs from the dictionary. What could this mean?

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  • How to determine if a List is sorted in Java?

    - by FarmBoy
    I would like a method that takes a List<T> where T implements Comparable and returns true or false depending on whether the list is sorted or not. What is the best way to implement this in Java? It's obvious that generics and wildcards are meant to be able to handle such things easily, but I'm getting all tangled up. It would also be nice to have an analogous method to check if the list is in reverse order.

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  • Delphi : Sorted List

    - by Sethu
    I need to sort close to a 1,00,000 floating point entries in delphi. I am new to delphi and would like to know if there are any readymade solutions available. I tried a few language provided constructs and they take an inordinate amount of time to run to completion.(a 5-10 sec execution time is fine for the application)

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  • XSLT Global count of grouped items

    - by Chris
    Hi there, I have a set of items which i am grouping using the muenchian method using keys. This is working great however when i try to do things with the first x number of items it is doing it on the x number of items in each group rather than across the whole set of results. How would i get the individual position of each item accross the whole collection? <xsl:key name="pictures-by-productid" match="/dsQueryResponse/Rows/Row" use="@ProductId" /> <xsl:template match="/"> <div style="border:1px solid red; float:left;"> <xsl:apply-templates select="/" mode="sub"> </xsl:apply-templates> </div> </xsl:template> and the second template <xsl:template match="/" mode="sub"> <xsl:for-each select="/dsQueryResponse/Rows/Row[count(. | key('pictures-by-productid', @ProductId)[1]) = 1]"> <xsl:for-each select="key('pictures-by-productid', @ProductId)"> <xsl:sort select="@PictureType" /> <div style="float:left; margin:2px;"> <img src="{@ThumbNailUrl}" width="58" /> <br /> Download <xsl:number value="position()" format="1. " /> <xsl:value-of select="." /> </div> </xsl:for-each> </xsl:for-each> </xsl:template> Thanks Chris

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  • Exclude one or more elements from being connected (using connectWith) in jQuery's sortable lists

    - by Lev
    I have two lists, one with an ID of "vlist" and one with an ID of "hlist". The "vlist" holds elements which should be visible, while the "hlist" holds items that should remain hidden. The idea here is to allow the administrator of the system to specify which elements/fields should be shown on a sign-up page, and which shouldn't. The two lists are connected using "connectWith", so the administrator can drag items from the visible list to the hidden list (or vice versa). My dilemma is that there are a few fields I want locked into the visible list, but still sortable within that one list. For example, the "username", "email" and "password" fields should be locked within the visible list (as they always need to be used for registration). Is this even possible? Perhaps it is a no-brainer that I simply haven't discovered yet. I've looked around through jQuery's documentation for a while and can't seem to find anything related to this scenario. I have found how you can "cancel" specific elements in the list from being sortable altogether or even disabled from being a dropable target, but this doesn't do it. The user should still have the ability to drag these items within the "visible" list, in case they want to adjust the ordering of the locked fields. I'm also aware that you can contain sortable elements within a specific element or DOM object, but this also can't be used as this only seems to apply to the whole sortable list, and not specific elements of that list. I've even tried to see if something like this would work after I built the sortable listing(s): $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); Obviously, that didn't work either or I wouldn't be posting this. In case it might help, I thought I'd throw in the code I'm using now; here is the jQuery code: $(function() { $('#vlist, #hlist').sortable ({ connectWith: '.signup-set_flist', forcePlaceholderSize: true, receive: function (event, ui) { var itemID = ui.item.attr('id'); var fID = itemID.replace(/slist-li-/g, ''); var hID = 'slist-' + fID; if (ui.sender.attr('id') == 'vlist') { $('#'+hID).val(''); } else { $('#'+hID).val(fID); } } }).disableSelection(); $('#vlist > #slist-li-username').sortable('option', 'containment', '#vlist'); }); And as for the HTML, I'll upload it to here (since StackOverflow seems to break when I paste it in here - even in code mode): http://sikosoft.net/jquery-sort-connect.html Any help would greatly be appreciated! :) Oh, and be gentle as this is my first question here. ;)

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  • How to construct LambdaExpression with conversion

    - by nerijus
    I need to sort in ajax response grid by column name. Column value is number stored as a string. Let's say some trivial class (in real-life situation there is no possibility to modify this class): class TestObject { public TestObject(string v) { this.Value = v; } public string Value { get; set; } } then simple test: [Test] public void LambdaConstructionTest() { var queryable = new List<TestObject> { new TestObject("5"), new TestObject("55"), new TestObject("90"), new TestObject("9"), new TestObject("09"), new TestObject("900"), }.AsQueryable(); var sortingColumn = "Value"; ParameterExpression parameter = Expression.Parameter(queryable.ElementType); MemberExpression property = Expression.Property(parameter, sortingColumn); //// tried this one: var c = Expression.Convert(property, typeof(double)); LambdaExpression lambda = Expression.Lambda(property, parameter); //// constructs: o=>o.Value var callExpression = Expression.Call(typeof (Double), "Parse", null, property); var methodCallExpression = Expression.Call( typeof(Queryable), "OrderBy", new[] { queryable.ElementType, property.Type }, queryable.Expression, Expression.Quote(lambda)); // works, but sorts by string values. //Expression.Quote(callExpression)); // getting: System.ArgumentException {"Quoted expression must be a lambda"} var querable = queryable.Provider.CreateQuery<TestObject>(methodCallExpression); // return querable; // <- this is the return of what I need. } Sorry for not being clear in my first post as @SLaks answer was correct but I do not know how to construct correct lambda expression in this case.

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  • C/GCC - Is it possible to sort arrays using preprocessor?

    - by psihodelia
    I have a number of very long arrays. No run-time sort is possible. It is also time consuming to sort them manually. Moreover, new elements can be added in any order later, so I would like to sort them by value using C preprocessor or maybe there is any compilers flag (GCC)? For example: sometype S[] = { {somevals, "BOB", someothervals}, {somevals, "ALICE", someothervals}, {somevals, "TIM", someothervals}, } must be sorted so: sometype S[] = { {somevals, "ALICE", someothervals}, {somevals, "BOB", someothervals}, {somevals, "TIM", someothervals}, }

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  • XSLT: use parameters in xls:sort attributes

    - by fireeyedboy
    How do I apply a parameter to a select and order attribute in a xsl:sort element? I'ld like to do this dynamic with PHP with something like this: $xsl = new XSLTProcessor(); $xslDoc = new DOMDocument(); $xslDoc->load( $this->_xslFilePath ); $xsl->importStyleSheet( $xslDoc ); $xsl->setParameter( '', 'sortBy', 'viewCount' ); $xsl->setParameter( '', 'order', 'descending' ); But I'ld first have to now how to get this to work. I tried the following, but it gives me a 'compilation error' : 'invalid value $order for order'. $sortBy doesn't seem to do anything either: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:param name="sortBy" select="viewCount"/> <xsl:param name="order" select="descending"/> <xsl:template match="/"> <media> <xsl:for-each select="media/medium"> <xsl:sort select="$sortBy" order="$order"/> // <someoutput> </xsl:for-each> </media> </xsl:template> </xsl:stylesheet>

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  • User sumbitted top 5 and sort by popularity

    - by Bundy
    Hi, Database setup (MySQL) table: top_fives id, uid, first, second, third, fourth, fifth, creation_date 1, 1, cheese, eggs, ham, bacon, ketchup, 2010-03-17 2, 2, mayonaise, cheese, ketchup, eggs, bacon, 2010-03-17 Users can submit their top 5 of a certain subject. Now I would like a summary of the top fives ordered by popularity. Each column has it's own point value. column 'first' is rewarded 5 points, 'second' four points, 'third' three points, and so on... So, in my example it should be something like this: 1 Cheese (9 points = 5 + 4 -> 1 time in 'first' column and 1 time in 'second' column) 2 Eggs (6 points) 3 Mayonaise (5 points) 4 Ketchup (4 points) 5 Bacon (3 points) 6 Ham (3 points) What would be the easiest solution (PHP) for this kind of situation? Thanks in advance

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