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  • XSLT: use parameters in xls:sort attributes

    - by fireeyedboy
    How do I apply a parameter to a select and order attribute in a xsl:sort element? I'ld like to do this dynamic with PHP with something like this: $xsl = new XSLTProcessor(); $xslDoc = new DOMDocument(); $xslDoc->load( $this->_xslFilePath ); $xsl->importStyleSheet( $xslDoc ); $xsl->setParameter( '', 'sortBy', 'viewCount' ); $xsl->setParameter( '', 'order', 'descending' ); But I'ld first have to now how to get this to work. I tried the following, but it gives me a 'compilation error' : 'invalid value $order for order'. $sortBy doesn't seem to do anything either: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes"/> <xsl:param name="sortBy" select="viewCount"/> <xsl:param name="order" select="descending"/> <xsl:template match="/"> <media> <xsl:for-each select="media/medium"> <xsl:sort select="$sortBy" order="$order"/> // <someoutput> </xsl:for-each> </media> </xsl:template> </xsl:stylesheet>

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  • Java Collections Sort not accepting comparator constructor with arg

    - by harmzl
    I'm getting a compiler error for this line: Collections.sort(terms, new QuerySorter_TFmaxIDF(myInteger)); My customized Comparator is pretty basic; here's the signature and constructor: public class QuerySorter_TFmaxIDF implements Comparator<Term>{ private int numberOfDocs; QuerySorter_TFmaxIDF(int n){ super(); numberOfDocs = n; } } Is there an error because I'm passing an argument into the Comparator? I need to pass an argument...

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  • OS X contains heapsort in stdlib.h which conflicts with heapsort in sort library

    - by CryptoQuick
    I'm using Ariel Faigon's sort library, found here: http://www.yendor.com/programming/sort/ I was able to get all my code working on Linux, but unfortunately, when trying to compile with GCC on Mac, its default stdlib.h contains another heapsort, which unfortunately results in a conflicting types error. Here's the man page for Apple heapsort: http://developer.apple.com/library/mac/#documentation/Darwin/Reference/ManPages/man3/heapsort.3.html Commenting out the heapsort in the sort library header causes a whole heap of problems. (pardon the pun) I also briefly thought of commenting out my use of stdlib.h, but I use malloc and realloc, so that won't work at all. Any ideas?

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  • Code golf: combining multiple sorted lists into a single sorted list

    - by Alabaster Codify
    Implement an algorithm to merge an arbitrary number of sorted lists into one sorted list. The aim is to create the smallest working programme, in whatever language you like. For example: input: ((1, 4, 7), (2, 5, 8), (3, 6, 9)) output: (1, 2, 3, 4, 5, 6, 7, 8, 9) input: ((1, 10), (), (2, 5, 6, 7)) output: (1, 2, 5, 6, 7, 10) Note: solutions which concatenate the input lists then use a language-provided sort function are not in-keeping with the spirit of golf, and will not be accepted: sorted(sum(lists,[])) # cheating: out of bounds! Apart from anything else, your algorithm should be (but doesn't have to be) a lot faster! Clearly state the language, any foibles and the character count. Only include meaningful characters in the count, but feel free to add whitespace to the code for artistic / readability purposes. To keep things tidy, suggest improvement in comments or by editing answers where appropriate, rather than creating a new answer for each "revision". EDIT: if I was submitting this question again, I would expand on the "no language provided sort" rule to be "don't concatenate all the lists then sort the result". Existing entries which do concatenate-then-sort are actually very interesting and compact, so I won't retro-actively introduce a rule they break, but feel free to work to the more restrictive spec in new submissions. Inspired by http://stackoverflow.com/questions/464342/combining-two-sorted-lists-in-python

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  • LINQ Quicksort is Unstable Except When Cascading

    - by Mystagogue
    On page 64 of "LINQ To Objects Using C# 4.0" (Tony Magennis) he states that LINQ's quicksort ordering algorithm is unstable... ...although this is simply solved by cascading the result into a ThenBy or ThenByDescending operator. Huh? Why would cascading an unstable sortation into another sortation fix the result? In fact, I'd say that isn't possible. The original order, once passed through an unstable sort, is simply lost. What am I missing here?

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  • XSLT Sort Alphabetically & Numerically Problem

    - by Bryan
    I have a group of strings ie g:lines = '9,1,306,LUCY,G,89' I need the output to be: 1,9,89,306,G,LUCY This is my current code: <xsl:for-each select="$all_alerts[g:problem!='normal_service'][g:service='bus']"> <xsl:sort select="g:line"/> <xsl:sort select="number(g:line)" data-type="number"/> <xsl:value-of select="normalize-space(g:line)" /><xsl:text/> <xsl:if test="position()!=last()"><xsl:text>,&#160;</xsl:text></xsl:if> </xsl:for-each> I can get it to only display '1, 12, 306, 38, 9, G, LUCY' because the 2nd sort isn't being picked up. Anyone able help me out?

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  • Get the largest value from Json object with Javascript

    - by neilc
    Hi This should be an easy one. I just cant figure it out. How do I get the largest value from this piece of JSON with javascript. {"data":{"one":21,"two":35,"three":24,"four":2,"five":18},"meta":{"title":"Happy with the service"}} The key and value I need is: "two":35 as it is the highest thanks

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  • How to sort in-place using the merge sort algorithm?

    - by eSKay
    I know the question is too open. All I want is someone to tell me how to convert a normal merge sort into an in-place merge sort (or a merge sort with constant extra space overhead). All I can find (on the net) is pages saying "it is too complex" or "out of scope of this text". "The only known ways to merge in-place (without any extra space) are too complex to be reduced to practical program." (from here) Even if it is too complex, can somebody outline the basic concept of how to make the merge sort in-place?

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  • sort given set of colors in VIBGYOR order

    - by Vijay Selvaraj
    Hi, how do i order a given set of colors from the rainbow in VIBGYOR order. say i input the seven colors in the following order { red, blue, green, yellow, indigo, violet, orange} and i should print the output as {violet, indigo, blue, green, yellow, orange, red}, irrespective of the order i give the output should be as above. Can someone suggest me about implementing this in java program? Thanks, -Vijay

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  • sort data in c language

    - by ANIL MANE
    Hello C experts, I need little help on following requirement, as I know very little about C syntaxes. I have data in a file like this 73 54 57 [52] 75 73 65 [23] 65 54 57 [22] 22 59 71 [12] 22 28 54 [2] 65 22 54 73 [12] 65 28 54 73 [52] 22 28 65 73 [42] 65 54 57 73 [22] 22 28 54 73 [4] Where values in bracket denotes the occurrence of that series. I need to sort this data based on the occurrence of the data descending with maximum elements on the top as follows 65 28 54 73 [52] 22 28 65 73 [42] 65 54 57 73 [22] 65 22 54 73 [12] 22 28 54 73 [4] 28 59 71 [122] 73 54 57 [52] 22 28 65 [26] .. . . . and so on... Can someone give me a quick code for this. Thanks in advance.

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  • Sort Hash Tables Glibc - qsort

    - by Mike
    I'm trying to sort a GLibc hash table by id that looks something like: key - id { "Red", 2, "BLue", 4, "Yellow", 5, "Orange", 8 } I'm just not sure how to approach this because GLibc does not have a sort method. I was thinking to use qsort or GCompareFunc Any ideas will be appreciate it!

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  • Sort by an object's type

    - by Richard Levasseur
    Hi all, I have code that statically registers (type, handler_function) pairs at module load time, resulting in a dict like this: HANDLERS = { str: HandleStr, int: HandleInt, ParentClass: HandleCustomParent, ChildClass: HandleCustomChild } def HandleObject(obj): for data_type in sorted(HANDLERS.keys(), ???): if isinstance(obj, data_type): HANDLERS[data_type](obj) Where ChildClass inherits from ParentClass. The problem is that, since its a dict, the order isn't defined - but how do I introspect type objects to figure out a sort key? The resulting order should be child classes follow by super classes (most specific types first). E.g. str comes before basestring, and ChildClass comes before ParentClass. If types are unrelated, it doesn't matter where they go relative to each other.

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  • How to order a TimeZone list in .NET?

    - by reallyJim
    I have an ASP.NET web application that requires users to select their appropriate time zone so that it can correctly show local times for events. In creating a simple approach for selecting the time zone, I started by just using the values from TimeZoneInfo.GetSystemTimeZones(), and showing that list. The only problem with this is that since our application is primarily targeted at the United States, I'd like to show those entries first, basically starting with Eastern Time and working backwards (West) until I reach Atlantic time. What's a good approach to do this in code?

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  • How do you sort a C# dictionary by value?

    - by kurious
    I often have a Dictionary of keys & values and need to sort it by value. For example, I have a hash of words and their frequencies, and want to order them by frequency. There's SortedList which is good for a single value (frequency), but I want to map it back to the word. SortedDictionary orders by key, not value. Some resort to a custom class, but what's the cleanest way?

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  • How to sort objects in a many-to-many relationship in ruby on rails?

    - by Kenji Kina
    I've been trying to deal with this problem for a couple of hours now and haven't been able to come up with a clean solution. It seems I'm not too good with rails... Anyway, I have the following: In code: class Article < ActiveRecord::Base has_many :line_aspects, :dependent => :destroy has_many :aspects, :through => :line_aspects #plus a name field end class LineAspect < ActiveRecord::Base belongs_to :article belongs_to :aspect end class Aspect < ActiveRecord::Base belongs_to :data_type has_many :line_aspects has_many :articles, :through => :line_aspects end Now, what I would like to do, is to sort these in two steps. First list of Articles by their Articles.name, and then inside sort them by Aspect.name (note, not the middleman). For instance, alphabetically (sorry if the notation is not correct): [{ article => 'Apple', line_aspects => [ {:value => 'red'}, #corresponding to the Attribute with :name => 'color' {:value => 'small'} #corresponding to the Attribute with :name => 'shape' ] },{ article => 'Watermelon', line_aspects => [ {:value => 'green'}, #corresponding to the Attribute with :name => 'color' {:value => 'big'} #corresponding to the Attribute with :name => 'shape' ] }] Again, note that these are ordered by the aspect name (color before shape) instead of the specific values of each line (red before green). (NOTE: My intention is to displaye these in a table in the view) I have not found a good way to do this in rails yet (without resorting to N queries). Can anyone tell me a good way to do it?

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  • Riddle: Spot the serious bug in this bubble sort implementation

    - by ripper234
    (No, this isn't a homework assignment, I just found the bug and thought it might be useful to share it here) import java.util.List; public class BubbleSorter { public <T extends Comparable<T>> void sort(List<T> list) { while (true) { boolean didWork = false; for (int i = 0; i < list.size() - 1; ++i) { if (list.get(i).compareTo(list.get(i + 1)) > 0) { swap(list, i, i + 1); didWork = true; break; } } if (!didWork) return; } } private static <T> void swap(List<T> list, int i, int j) { T tmp = list.get(i); list.set(i, list.get(j)); list.set(j, tmp); } }

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  • string categorization strategies

    - by Andrew Heath
    I'm the one-man dev team on a fledgling military history website. One aspect of the site is a catalog of ~1,200 individual battles, including the nations & formations (regiments, divisions, etc) which took part. The formation information (as well as the other battle info) was manually imported from a series of books by a 10-man volunteer team. The formations were listed in groups with varying formatting and abbreviation patterns. At the time I set up the data collection forms I couldn't think of a good way to process that data... and elected to store it all as strings in the MySQL database and sort it out later. Well, "later" - as it tends to happen - has arrived. :-) Each battle has 2+ records in the database - one for each nation that participated. Each record has a formations text string listing the formations present as the volunteer chose to add them. Some real examples: 39th Grenadier Rgmt, 26th Volksgrenadier Division 2nd Luftwaffe Field Division, 246th Infantry Division 247th Rifle Division, 255th Tank Brigade 2nd Luftwaffe Field Division, SS Cavalry Division 28th Tank Brigade, 158th Rifle Division, 135th Rifle Division, 81st Tank Brigade, 242nd Tank Brigade 78th Infantry Division 3rd Kure Special Naval Landing Force, Tulagi Seaplane Base personnel 1st Battalion 505th Infantry Regiment The ultimate goal is for each individual force to have an ID, so that its participation can be traced throughout the battle database. Formation hierarchy, such as the final item above 1st Battalion (of the) 505th Infantry Regiment also needs to be preserved. In that case, 1st Battalion and 505th Infantry Regiment would be split, but 1st Battalion would be flagged as belonging to the 505th. In database terms, I think I want to pull the formation field out of the current battle info table and create three new tables: FORMATION [id] [name] FORMATION_HIERARCHY [id] [parent] [child] FORMATION_BATTLE [f_id] [battle_id] It's simple to explain, but complicated to enact. What I'm looking for from the SO community is just some tips on how best to tackle this problem. Ideally there's some sort of method to solving this that I'm not aware of. However, as a last resort, I could always code a classification framework and call my volunteers back to sort through 2,500+ records...

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  • Mysql: i need to get the offset of a item in a query.

    - by user305270
    Mysql: i need to get the offset of a item in a query. I have a image gallery: this show 6 image per stack, so when i request image 22 it shows images from 18 to 24. It should first get the offset of the image 22, then get the images from 18 to 24. Another example: i request the image number 62(and offset 62), it will select images with offset from 60 to 66. Is possible with a single query? Thanks ;)

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • Efficient method to calculate the rank vector of a list in Python

    - by Tamás
    I'm looking for an efficient way to calculate the rank vector of a list in Python, similar to R's rank function. In a simple list with no ties between the elements, element i of the rank vector of a list l should be x if and only if l[i] is the x-th element in the sorted list. This is simple so far, the following code snippet does the trick: def rank_simple(vector): return [rank for rank in sorted(range(n), key=vector.__getitem__)] Things get complicated, however, if the original list has ties (i.e. multiple elements with the same value). In that case, all the elements having the same value should have the same rank, which is the average of their ranks obtained using the naive method above. So, for instance, if I have [1, 2, 3, 3, 3, 4, 5], the naive ranking gives me [0, 1, 2, 3, 4, 5, 6], but what I would like to have is [0, 1, 3, 3, 3, 5, 6]. Which one would be the most efficient way to do this in Python? Footnote: I don't know if NumPy already has a method to achieve this or not; if it does, please let me know, but I would be interested in a pure Python solution anyway as I'm developing a tool which should work without NumPy as well.

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