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  • Fastest way to sort files

    - by Werner
    Hi, I have a huge text file with lines like: -568.563626 159 33 -1109.660591 -1231.295129 4.381508 -541.181308 159 28 -1019.279615 -1059.115975 4.632301 -535.370812 155 29 -1033.071786 -1152.907805 4.420473 -533.547101 157 28 -1046.218277 -1063.389677 4.423696 What I want is to sort the file, depending on the 5th column, so I would get -568.563626 159 33 -1109.660591 -1231.295129 4.381508 -535.370812 155 29 -1033.071786 -1152.907805 4.420473 -533.547101 157 28 -1046.218277 -1063.389677 4.423696 -541.181308 159 28 -1019.279615 -1059.115975 4.632301 For this I use: for i in file.txt ; do sort -k5n $i ; done I wonder if this is the fastest or more efficient way Thanks

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  • Is this a bad version of the Merge Sort algorithm?

    - by SebKom
    merge1(int low, int high, int S[], U[]) { int k = (high - low + 1)/2 for q (from low to high) U[q] = S[q] int j = low int p = low int i = low + k while (j <= low + k - 1) and (i <= high) do { if ( U[j] <= U[i] ) { S[p] := U[j] j := j+1 } else { S[p] := U[i] i := i+1 } p := p+1 } if (j <= low + k - 1) { for q from p to high do { S[q] := U[j] j := j+1 } } } merge_sort1(int low, int high, int S[], U[]) { if low < high { int k := (high - low + 1)/2 merge_sort1(low, low+k-1, S, U) merge_sort1(low+k, high, S, U) merge1(low, high, S, U) } } I am really sorry for the terrible formating, as you can tell I am not a regular visitor here. So, basically, this is on my lecture notes. I find it quite confusing in general but I understand the biggest part of it. What I don't understand is the need of the "if (j <= low + k - 1)" part. It looks like it checks if there are any elements "left" in the left part. Is that even possible when mergesorting?

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  • sort files by date in PHP

    - by sasori
    hi, I currently have an index.php file which allows me to output the list of files inside the same directory, the output shows the names then I used filemtime() function to show the date when the file was modified. my problem now is, how will I sort the output to show the latest modified file ?, I've been thinking for awhile how to do this. if only I am doing it with mysql interaction there will be no problem at all. please show me an example how to sort and output the list of files starting from the latest modified one. this is what i have for now if ($handle = opendir('.')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $lastModified = date('F d Y, H:i:s',filemtime($file)); if(strlen($file)-strpos($file,".swf")== 4){ echo "<tr><td><input type=\"checkbox\" name=\"box[]\"></td><td><a href=\"$file\" target=\"_blank\">$file</a></td><td>$lastModified</td></tr>"; } } } closedir($handle); }

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  • Unsort: remembering a permutation and undoing it.

    - by dreeves
    Suppose I have a function f that takes a vector v and returns a new vector with the elements transformed in some way. It does that by calling function g that assumes the vector is sorted. So I want f to be defined like so: f[v_] := Module[{s, r}, s = Sort[v]; (* remember the permutation applied in order to sort v *) r = g[s]; Unsort[r] (* apply the inverse of that permutation *) ] What's the best way to do the "Unsort"? Or could we get really fancy and have this somehow work: answer = Unsort[g[Sort[v]]]; ADDED: Let's make this concrete with a toy example. Suppose we want a function f that takes a vector and transforms it by adding to each element the next smallest element, if any. That's easy to write if we assume the vector is sorted, so let's write a helper function g that makes that assumption: g[v_] := v + Prepend[Most@v, 0] Now for the function we really want, f, that works whether or not v is sorted: f[v_] := (* remember the order; sort it; call g on it; put it back in the original order; return it *)

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  • Space requirements of a merge-sort

    - by Arkaitz Jimenez
    I'm trying to understand the space requirements for a Mergesort, O(n). I see that time requirements are basically, amount of levels(logn) * merge(n) so that makes (n log n). Now, we are still allocating n per level, in 2 different arrays, left and right. I do understand that the key here is that when the recursive functions return the space gets deallocated, but I'm not seeing it too obvious. Besides, all the info I find, just states space required is O(n) but don't explain it. Any hint? function merge_sort(m) if length(m) = 1 return m var list left, right, result var integer middle = length(m) / 2 for each x in m up to middle add x to left for each x in m after middle add x to right left = merge_sort(left) right = merge_sort(right) result = merge(left, right) return result

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  • Efficient way to maintain a sorted list of access counts in Python

    - by David
    Let's say I have a list of objects. (All together now: "I have a list of objects.") In the web application I'm writing, each time a request comes in, I pick out up to one of these objects according to unspecified criteria and use it to handle the request. Basically like this: def handle_request(req): for h in handlers: if h.handles(req): return h return None Assuming the order of the objects in the list is unimportant, I can cut down on unnecessary iterations by keeping the list sorted such that the most frequently used (or perhaps most recently used) objects are at the front. I know this isn't something to be concerned about - it'll make only a miniscule, undetectable difference in the app's execution time - but debugging the rest of the code is driving me crazy and I need a distraction :) so I'm asking out of curiosity: what is the most efficient way to maintain the list in sorted order, descending, by the number of times each handler is chosen? The obvious solution is to make handlers a list of (count, handler) pairs, and each time a handler is chosen, increment the count and resort the list. def handle_request(req): for h in handlers[:]: if h[1].handles(req): h[0] += 1 handlers.sort(reverse=True) return h[1] return None But since there's only ever going to be at most one element out of order, and I know which one it is, it seems like some sort of optimization should be possible. Is there something in the standard library, perhaps, that is especially well-suited to this task? Or some other data structure? (Even if it's not implemented in Python) Or should/could I be doing something completely different?

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  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

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  • getting userbase vote average and individual user's vote in the same query?

    - by Andrew Heath
    Here goes: T1 [id] [desc] 1 lovely 2 ugly 3 slender T2 [id] [userid] [vote] 1 1 3 1 2 5 1 3 2 2 1 1 2 2 4 2 3 4 In one query (if possible) I'd like to return: T1.id, T1.desc, AVG(T2.vote), T2.vote (for user viewing the page) I can get the first 3 items with: SELECT T1.id, T1.desc, AVG(T2.vote) FROM T1 LEFT JOIN T2 ON T1.id=T2.id GROUP BY T1.id and I can get the first, second, and fourth items with: SELECT T1.id, T1.desc, T2.vote FROM T1 LEFT JOIN T2 ON T1.id=T2.id WHERE T2.userid='1' GROUP BY T1.id but I'm at a loss as to how to get all four items in one query. I tried inserting a select as the fourth term: SELECT T1.id, T1.desc, AVG(T2.vote), (SELECT T2.vote FROM T2 WHERE T2.userid='1') AS userVote etc etc but I get an error that the select returns more than one row... Help? My reason for wanting to do this in one query instead of two is that I want to be able to sort the data within MySQL rather than one it's been split into a number of arrays.

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  • Best way to Sort-n-Concatenate 5 columns

    - by SDReyes
    Having five columns containing numeric values A | B | C | D | E ------------------- 2 | 3 | 4 | 1 | 5 3 | 6 | 1 | 5 | 4 4 | 5 | 7 | 1 | 3 I want to obtain the concatenation of the values after sort them: ABCDE ----------- 1 2 3 4 5 1 3 4 5 6 1 3 4 5 7 What is the best way to do it?

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  • An O(1) Sort ~~~

    - by FlySwat
    Before you stone me for being a heretic, There is a sort that proclaims to be O(1), called "Bead Sort" (http://en.wikipedia.org/wiki/Bead_sort) , however that is pure theory, when actually applied I found that it was actually O(N * M), which is pretty pathetic. That said, Lets list out some of the fastest sorts, and their best case and worst case speed in Big O notation. ~~ FlySwat ~~

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  • Sort a list of pointers.

    - by YuppieNetworking
    Hello all, Once again I find myself failing at some really simple task in C++. Sometimes I wish I could de-learn all I know from OO in java, since my problems usually start by thinking like Java. Anyways, I have a std::list<BaseObject*> that I want to sort. Let's say that BaseObject is: class BaseObject { protected: int id; public: BaseObject(int i) : id(i) {}; virtual ~BaseObject() {}; }; I can sort the list of pointer to BaseObject with a comparator struct: struct Comparator { bool operator()(const BaseObject* o1, const BaseObject* o2) const { return o1->id < o2->id; } }; And it would look like this: std::list<BaseObject*> mylist; mylist.push_back(new BaseObject(1)); mylist.push_back(new BaseObject(2)); // ... mylist.sort(Comparator()); // intentionally omitted deletes and exception handling Until here, everything is a-ok. However, I introduced some derived classes: class Child : public BaseObject { protected: int var; public: Child(int id1, int n) : BaseObject(id1), var(n) {}; virtual ~Child() {}; }; class GrandChild : public Child { public: GrandChild(int id1, int n) : Child(id1,n) {}; virtual ~GrandChild() {}; }; So now I would like to sort following the following rules: For any Child object c and BaseObject b, b<c To compare BaseObject objects, use its ids, as before. To compare Child objects, compare its vars. If they are equal, fallback to rule 2. GrandChild objects should fallback to the Child behavior (rule 3). I initially thought that I could probably do some casts in Comparator. However, this casts away constness. Then I thought that probably I could compare typeids, but then everything looked messy and it is not even correct. How could I implement this sort, still using list<BaseObject*>::sort ? Thank you

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  • php sort properties of object

    - by lannoo
    I want to sort the properties of an object so I can loop through them in a defined order. for example: I have an object 'book' with the following properties: 'id', 'title', 'author', 'date'. Now i want to loop through these properties like this: foreach($book as $prop=>$val) //do something now the order of the loop has to be 'title', then 'author', 'date' and 'id' How would one do this? (I can't change the order of the properties in the class of the object because there arent any properties defined there, I get the object from the database with 'MyActiveRecord')

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  • How to sort the row contents on table cell by using date

    - by MS Nathan
    Hi i am new to iphone application development.i am developing RSS feed Reader it has number of different RSS feeds. In my application (XML parsing), i want to display the content of the row on cell for particular date and with their corresponding title, description (in my application, i am using three labels for displaying title, date and description) on table view cell after parsing xml data. And i want to sort the all kinds of RSS feeds row contents(title, date, description) depends upon the date in single another UIViewController and for each RSS feed has a separate ViewController. thanks in advance.

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  • Creating an Order Column for encrypted data

    - by SetiSeeker
    I am saving encrypted data to a database. Is there a way I can create a "hashcode" or fingerprint or checksum of the plain text data, that if I sort / order by on the "hashcode" the order would be the same as if I had saved the plain text data and perform the same sort / order by operation on it? I basically need a SOUNDEX() type function that will give me a value that will maintain the order of the plain text data. I would then save both encrypted data and the "hashcode" and when querying the data order by the "hashcode" field. I need to perform this in the application and preferably not in the SQL DB if at all possible. I am using Entity Framework and SQL 2008 and C# 4.0.

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  • C# - How to implement multiple comparers for an IComparable<T> class?

    - by Gary Willoughby
    I have a class that implements IComparable. public class MyClass : IComparable<MyClass> { public int CompareTo(MyClass c) { return this.whatever.CompareTo(c.whatever); } etc.. } I then can call the sort method of a generic list of my class List<MyClass> c = new List<MyClass>(); //Add stuff, etc. c.Sort(); and have the list sorted according to my comparer. How do i specify further comparers to sort my collection different ways according to the other properties of MyClass in order to let users sort my collection in a number of different ways?

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  • Custom sort logic in OrderBy using LINQ

    - by Bala R
    What would be the right way to sort a list of strings where I want items starting with an underscore '_', to be at the bottom of the list, otherwise everything is alphabetical. Right now I'm doing something like this, autoList.OrderBy(a => a.StartsWith("_") ? "ZZZZZZ"+a : a ) EDIT: I ended up using something like this; optimization suggestions welcome! private class AutoCompleteComparer : IComparer<String> { public int Compare(string x, string y) { if (x.StartsWith("_") && y.StartsWith("_") || (!x.StartsWith("_") && !y.StartsWith("_"))) { return x.CompareTo(y); } else if (x.StartsWith("_")) { return 1; } else if (y.StartsWith("_")) { return -1; } return 0; } }

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  • Data structure for an ordered set with many defined subsets; retrieve subsets in same order

    - by Aaron
    I'm looking for an efficient way of storing an ordered list/set of items where: The order of items in the master set changes rapidly (subsets maintain the master set's order) Many subsets can be defined and retrieved The number of members in the master set grow rapidly Members are added to and removed from subsets frequently Must allow for somewhat efficient merging of any number of subsets Performance would ideally be biased toward retrieval of the first N items of any subset (or merged subset), and storage would be in-memory (and maybe eventually persistent on disk)

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  • Initial state of autoCreateRowSorter in Swing JTable

    - by Nazgulled
    I have this JTable on my Swing app with the autoCreateRowSorter enabled. My table only has 3 columns, two strings and one int, it works well for all of them when I click the column headers. However, I'm looking for way to do it programatically. I wanted to set the "initial state" for this table. With the Windows look and feel, the column header (when sorted) has a little arrow showing the sort order. But at startup that doesn't show, I have to do one initial click. How can I do that by code?

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  • python how to find the median of a list

    - by user3450574
    I'm trying to write a function named median that takes a list as an input and returns the median value of the list. I'm working with Python 2.7.2 The list can be of any size and the numbers are not guaranteed to be in any particular order. If the list contains an even number of elements, the function should return the average of the middle two. This is the code I'm starting with: def median(list): print(median([7,12,3,1,6,9]))

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  • std::ifstream buffer caching

    - by ledokol
    Hello everybody, In my application I'm trying to merge sorted files (keeping them sorted of course), so I have to iterate through each element in both files to write the minimal to the third one. This works pretty much slow on big files, as far as I don't see any other choice (the iteration has to be done) I'm trying to optimize file loading. I can use some amount of RAM, which I can use for buffering. I mean instead of reading 4 bytes from both files every time I can read once something like 100Mb and work with that buffer after that, until there will be no element in buffer, then I'll refill the buffer again. But I guess ifstream is already doing that, will it give me more performance and is there any reason? If fstream does, maybe I can change size of that buffer? added My current code looks like that (pseudocode) // this is done in loop int i1 = input1.read_integer(); int i2 = input2.read_integer(); if (!input1.eof() && !input2.eof()) { if (i1 < i2) { output.write(i1); input2.seek_back(sizeof(int)); } else input1.seek_back(sizeof(int)); output.write(i2); } } else { if (input1.eof()) output.write(i2); else if (input2.eof()) output.write(i1); } What I don't like here is seek_back - I have to seek back to previous position as there is no way to peek 4 bytes too much reading from file if one of the streams is in EOF it still continues to check that stream instead of putting contents of another stream directly to output, but this is not a big issue, because chunk sizes are almost always equal. Can you suggest improvement for that? Thanks.

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  • Sort Java List/Map by order in which items are in an XML File

    - by Brandon Smith
    Hello everyone, What I'm looking to do is to sorta a Java List or Map in the order the items are in a XML File. For Example I have a list of function names as so: functionOne functionThree functionTwo The XML File looks like this: <xml> <function>functionOne</function> <function>functionTwo</function> <function>functionThree</function> </xml> So I would like to sort the list so the function names are as so: functionOne functionTwo functionThree Now Im trying to do this for Variables as well, so there are around 500+ unique 'items'. Does anyone have any idea how I can go about doing this? Now for the file that determines that sort order doesn't have to be XML it just what I use the most, it can be anything that can get the job done. Thanks in advance for your time.

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  • I need to sort the facets that come back from SOLR by relevancy

    - by Pinguthepenguin
    I have within my SOLR index song objects which belong to a higher level album object. An example is shown below: <song> <album title>Blood Sugar Sex Magic</album title> <song title>Under the Bridge</song title> <description>A sad song about junkies</description> </song> What I can do at the moment is create a facet on the album title so that a search on songs will also show me what albums contain hits for that keyword. The default behaviour for SOLR is that the facets are shown in the order of most hits to least. However what I want to achieve is the facet list to be sorted according to the relevancy of the top hit for that album. For example a search on the word "sad" may show a facet with one hit for "Blood Sugar Sex Magic" and there may also be an album called "Sad Clown songs" where there are 10 hits. "Sad clown songs" will show as the first facet even though it may be that "Under the bridge" comes up as the most relevant song. My question is how can I get all the facets back but then have them ordered by the relevancy of the songs within them? If I would need to change or extend some underlying SOLR code what would that be? Thanks in advance.

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  • What does P mean in Sort(Expression<Func<T, P>> expr, ListSortDirection direction)?

    - by Grasshopper
    I am attempting to use the answer in post: How do you sort an EntitySet<T> to expose an interface so that I can sort an EntitySet with a Binding list. I have created the class below and I get the following compiler error: "The type or namespace 'P' could not be found (are you missing a using directive or assembly reference?). Can someone tell me what the P means and which namespace I need to include to get the method below to compile? I am very new to delegates and lamba expressions. Also, can someone confirm that if I create a BindingList from my EntitySet that any modifications I make to the BindingList will be made to the EntitySet? Basically, I have an EntitySet that I need to sort and make changes to. Then, I will need to persist these changes using the original Entity that the BindingList came from. public class EntitySetBindingWrapper<T> : BindingList<T> { public EntitySetBindingWrapper(BindingList<T> root) : base(root) { } public void Sort(Expression<Func<T, P>> expr, ListSortDirection direction) { if (expr == null) base.RemoveSortCore(); MemberExpression propExpr = expr as MemberExpression; if (propExpr == null) throw new ArgumentException("You must provide a property", "expr"); PropertyDescriptorCollection descriptorCol = TypeDescriptor.GetProperties(typeof(T)); IEnumerable<PropertyDescriptor> descriptors = descriptorCol.Cast<PropertyDescriptor>(); PropertyDescriptor descriptor = descriptors.First(pd => pd.Name == propExpr.Member.Name); base.ApplySortCore(descriptor, direction); } }

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  • How to strip specific contents of a String in Java

    - by user2974877
    So I have a string, and I want to strip out some parts of it using, for example, the firt and last characters of the "interesting" part. String dirty = "$!$!%!%$something interesting&!!$!%$something interesting2"; And the output something like: String clean = "something interesting:something interesting2"; Note: The code needs to work without knowing the random part, changing everytime the program runs. I researched and only found code that does it, but only knowing the random segment.

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