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  • Quartz: triggering multiple jobs

    - by Phanindra
    In Quarts, can I use a single trigger to schedule multiple jobs, so that all the jobs gets executed in parallel. What is the best way to do this. Example, every hour execute Jobs j1, j2, ..., jn in parallel. Assuming that there is no dependency between the jobs.

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  • how to run TimerTask off main UI thread?

    - by huskyd97
    I am having trouble with a TimerTask Interfering with In App Purchasing (Async Tasks). I am weak with Threads, so I believe it is running on the main UI thread, eating up resources. How can I run this outside the UI thread? I have searched, and tried some suggestions using handlers. but seems like I get the same result, app gets really laggy. when I don't run this task (refreshes every 500mS), the activity runs smoothly, and there are no hangs during In app purchases. Your help is appreciated, code snippet below: public class DummyButtonClickerActivity extends Activity { protected Timer timeTicker = new Timer("Ticker"); private Handler timerHandler = new Handler(); protected int timeTickDown = 20; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.mainhd); // start money earned timer handler TimerTask tick = new TimerTask() { public void run() { myTickTask(); } }; timeTicker.scheduleAtFixedRate(tick, 0, 500); // 500 ms each } // End OnCreate protected void myTickTask() { if (timeTickDown == 0) { /// run my code here //total = total + _Rate; timerHandler.post(doUpdateTimeout); } else if(timeTickDown < 0) { // do nothing } timeTickDown--; } private Runnable doUpdateTimeout = new Runnable() { public void run() { updateTimeout(); } }; private void updateTimeout() { // reset tick timeTickDown = 2; // 2* 500ms == once a second } }

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  • JPanel superclass doesn't add the components of its subclasses..

    - by Acryl
    Well, I use a JFrame that adds two JPanels. Those JPanels are superclasses, because I find it easier to separate different areas of the GUI into different classes. But here's the problem: I add the (superclass) JPanel to the JFrame I set the layout of the superclass JPanel to new BorderLayout(); I add components in the subclasses, like this: JPanel panel = new JPanel(); panel.setLayout(new GridLayout(2,1)); panel.add(new JLabel("Label:"); panel.add(new JTextField(); add(panel, BorderLayout.NORTH); But it doesn't show. What do I do wrong? I've tried it without an additional JPanel in the subclasses, but it doesn't work either. I use jdk 1.6

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  • How to see full compile path in Eclipse?

    - by alleywayjack
    I have looked for an answer for this nearly every where that I can think of, but there doesn't seem to be any way to actually SEE what Eclipse "runs" to compile the projects (as it does need the JDK installed and visible to actually build). I ask because I imported a few jars into my project, and even though I've looked through all the javac documentation, I can't seem to figure out how to mimic it quite like Eclipse does. I really, really need to be able to compile on the command line in this case - Eclipse or any other IDE just isn't what is needed. I started to look through the Eclipse source, and although this sounds lazy, I just became overwhelmed and figured I would ask here first, hoping someone else had the same question at one point.

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  • Accessing variablss through a different class within the constructor of latter classes of an object

    - by Haxed
    In the code below, I've added two lines that print output. The first line prints junk as usual, but surprisingly the second one gives me a compilation error. Why? class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); // LINE 01: This compiles, although prints junk System.out.println(s[0]); // LINE 02: I get a error called cannot find symbol System.out.println(s[0].getName()); } public static void main(){ new StudentServer(); } } Many Thanks

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  • disable the Home Button and Back Button"

    - by michael
    i want way to disable the Home Button & Back Button when click on checkbox in application , my application on version 4.2.2 i have code but not work when click on checkbox work stop to application public void HardButtonOnClick(View v) { boolean checked1 = ((CheckBox) v).isChecked(); if(checked1) { SQLiteDatabase db; db = openOrCreateDatabase("Saftey.db", SQLiteDatabase.CREATE_IF_NECESSARY, null); db.setVersion(1); db.setLocale(Locale.getDefault()); db.setLockingEnabled(true); ContentValues values = new ContentValues(); values.put("hardBtn", "YES"); db.update("Setting", values, "id = ?", new String[] { "1" }); Toast.makeText(this, "Hard Button Locked", Toast.LENGTH_LONG).show(); //SharedPreferences pref = getSharedPreferences("pref",0); //SharedPreferences.Editor edit = pref.edit(); //edit.putString("hard","yes"); //edit.commit(); /* String Lock="yes" ; Bundle bundle = new Bundle(); bundle.putString("key", Lock); Intent a = new Intent(Change_setting.this, ChildMode.class); a.putExtras(bundle); startActivity(a);*/ super.onAttachedToWindow(); this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD); isLock = true; } else { SQLiteDatabase db; db = openOrCreateDatabase("Saftey.db", SQLiteDatabase.CREATE_IF_NECESSARY, null); db.setVersion(1); db.setLocale(Locale.getDefault()); db.setLockingEnabled(true); ContentValues values = new ContentValues(); values.put("hardBtn", "NO"); db.update("Setting", values, "id = ?", new String[] { "1" }); //SharedPreferences pref = getSharedPreferences("pref",0); //SharedPreferences.Editor edit = pref.edit(); //edit.putString("hard","no"); //edit.commit(); Toast.makeText(this, "Hard Button Un-Locked", Toast.LENGTH_LONG).show(); isLock = false; } } how can work it??

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  • doubt in Exceptions

    - by Ajay Singh
    class MyException extends Exception { MyException() {} MyException(String msg) { super(msg);} } public class NewException { static void f() throws MyException { System.out.println("throwing exception from f()"); throw new ClassCastException(); } static void g() throws MyException { System.out.println("throwing exception from g()"); throw new MyException("parametrized "); } public static void main(String ...strings ) { try { f(); } catch(MyException e) { e.printStackTrace(System.out); } try { g(); } catch(MyException e) { e.printStackTrace(System.out); } } } In the function f() iam specifying that "MyException " exception will be thrown and actually iam throwing some other exception which has no relation with MyException but still the compiler does not report any complain.Why is it so??

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  • Advice on creating simple web service

    - by London
    Hi all, I want to build simple SOAP web service. So far I've only worked with existing SOAP/Rest services. And now I'd like to create my own, simple one for starters. For example create simple hello + string web service where I provide the string in request from SOAP ui or similar tool. I have Jboss server installed already, what is the "simplest" possible way to achieve this? I realize I need interface, interfaceImpl, and a wsdl file(generated possibly). Does anyone have some useful advice for me ? thank you

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  • Servlet File Upload Memory Consumption

    - by Scott
    Hi, I'm using a servlet to do a multi fileupload (using apache commons fileupload to help). A portion of my code is posted below. My problem is that if I upload several files at once, the memory consumption of the app server jumps rather drastically. This is probably OK if it were only until the file upload is finished, but the app server seems to hang on to the memory and never return it to the OS. I'm worried that when I put this into production I'll end up getting an out of memory exception on the server. Any ideas on why this is happening? I'm thinking the server may have started a session and will give the memory back after it expires, but I'm not 100% positive. if(ServletFileUpload.isMultipartContent(request)) { ServletFileUpload upload = new ServletFileUpload(); FileItemIterator iter = upload.getItemIterator(request); while(iter.hasNext()) { FileItemStream license = iter.next(); if(license.getFieldName().equals("upload_button") || license.getName().equals("")) continue; //DataInputStream stream = new DataInputStream(license.openStream()); InputStream stream = license.openStream(); ArrayList<Integer> byteArray = new ArrayList<Integer>(); int tempByte; do { tempByte = stream.read(); byteArray.add(tempByte); }while(tempByte != -1); stream.close(); byteArray.remove(byteArray.size()-1); byte[] bytes = new byte[byteArray.size()]; int i = 0; for(Integer tByte : byteArray) { bytes[i++] = tByte.byteValue(); } Thanks in advanced!!

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  • servlet connection to DB

    - by underW
    Initially, after reading books on the subject, I firmly believed that the algorithm for working with a database from a servlet is as follows: create a connection - connect to the database - form a request - send the request to the database - get the query results - process them - close connection - OK. Now, with a better understanding of the practical side, I realized that nobody does it that way, and everything happens through a connection pool according to the following algorithm: initialize the servlet - create a connection pool - a request comes from a user - take a free connection from the pool - form a request - send the request to the database - get the query results - process them - return the connection back to the pool - ok. Now I have this problem: We have 100 users, they are divided into 10 groups, each group has it's own username and password to connect to the database. Moreover, each group may have different rights to the database. How am I supposed to use a connection pool in this situation? If I understand correctly, a pool is nothing more than just a group of similar connections with a single login and password. And here I have 10 pairs of username / password. It looks like I cannot use the pool in this situation. What should I do?

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  • Android - Fill Layout with Buttons

    - by GuyNoir
    Just a quick question about how you would go about implementing this. I want there to be buttons at the bottom of the screen, but if the screen size is larger, more buttons would be added. For example, at a small screen size, there might be 4-5 buttons at the bottom, but if you ran it on a tablet or something similar, there would be maybe 20 buttons. Any suggestions? It can't scroll either, it just has to dynamically fill the layout with buttons. Thanks.

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  • Problem using FormLayout in Swing

    - by Dimitri
    Hi I am using the FormLayout. I just discovered it and it's powerful layout manager. I would like to layout 4 components (outlined, properties, tgraph, library) in 3 columns. I want to layout my library component on top of the outlined component in one column, the graph and the properties component in one column. But it doesn't work. Maybe I miss something. Here is my code : private void layoutComponent() { JPanel panel = new JPanel(); FormLayout layout = new FormLayout( "right:p,10dlu,300dlu,left:max(50dlu;p)", "top:pref,center:p,p"); layout.setRowGroups(new int[][]{{1,3}}); PanelBuilder builder = new PanelBuilder(layout,panel); builder.setDefaultDialogBorder(); CellConstraints constraints = new CellConstraints(); builder.add(library, constraints.xy(1, 1)); builder.add(outline,constraints.xy(1, 3)); builder.add(tgraph,constraints.xy(3, 1)); builder.add(properties,constraints.xy(4, 1)); getContentPane().add(panel);r code here } Can someone help plz. Thx :)

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  • How to add clear option to this whiteboard?

    - by swift
    i have to add clear screen option to my whiteboard application, usual procedure is to draw a fill rect to the sizeof the image. But in my app i have transparent panels added one above the other i.e as layers, if i follow the usual procedure the drawing from the underlying panel wont be visible. please tell me any logic to do this. public void createFrame() { JFrame frame = new JFrame(); JLayeredPane layerpane=frame.getLayeredPane(); board= new Whiteboard(client); //board is a transparent panel // tranparent image: board.image = new BufferedImage(590,690, BufferedImage.TYPE_INT_ARGB); board.setBounds(74,23,590,690); board.setImage(image); virtualboard.setImage(image); //virtualboardboard is a transparent panel virtualboard.setBounds(74,23,590,690); JPanel background=new JPanel(); background.setBackground(Color.white); background.setBounds(74,25,590,685); layerpane.add(board,new Integer(5)); layerpane.add(virtualboard,new Integer(4));//Panel where remote user draws layerpane.add(background,new Integer(3)); layerpane.add(board.colourButtons(),new Integer(2)); layerpane.add(board.shapeButtons(),new Integer(1)); layerpane.add(board.createEmptyPanel(),new Integer(0)); }

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  • why isn't the input text file being read into the ArrayList<String>, diary?

    - by hmg
    Here's my code: public void readFile() throws IOException { System.out.println("Input file name: "); Scanner in = new Scanner(System.in); String readName = in.nextLine(); Scanner reader = new Scanner(new File(readName)); System.out.println("Reading file..."); while (reader.hasNextLine()) { System.out.println(reader.nextLine()); } System.out.println("File read."); Scanner inAgain = new Scanner(System.in); System.out.println("Would you like to read this into the current Diary?"); System.out.println("Warning: This will overwrite your current Diary!"); String readFileConfirm = inAgain.nextLine(); ArrayList<String> readData = new ArrayList<String>(); if (readFileConfirm.equalsIgnoreCase("yes")) { for (int i = 0; i < readData.size(); i++) { readData.add(reader.nextLine()); } System.out.println("Data added to extra array..."); System.out.println("Here are the contents."); for (int i = 0; i < readData.size(); i++) { System.out.println(readData.get(i)); } System.out.println("Contents read."); System.out.println("Now overwriting current Diary with read file..."); diary.clear(); for (int i = 0; i < diary.size(); i++) { diary.add(readData.get(i)); } System.out.println("New Diary created!"); System.out.println("Use 'recall' to see your new Diary!"); } else { System.out.println("Very well, returning to first command entry."); } } Thanks in advance! -h

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  • Converting a soap message to a document using wssj

    - by ellander
    I have been supplied with a jar file that should enable me to connect to a 3rd party system. When I run the necessary class I get an error which states that the namespace for the prefix "SOAPENV" has not been declared. Using jad I have decompiled the class files to try suss out what is going on and the error seems to occur when a soap message is being converted to a document. Unfortunately I don't know much about wssj. Can anyone suggest what the problem might be? I'm wondering if it's an incompatibility issue as it's not a recently created jar file and the decompiled code looks different to all the examples I can find. For example, in this section the examples have addNamesSpaceDeclaration rather than addAttribute... MessageFactory factory = MessageFactory.newInstance(); SOAPFactory sf = SOAPFactory.newInstance(); SOAPMessage msg = factory.createMessage(); MimeHeaders headers = msg.getMimeHeaders(); headers.addHeader("Content-Type", "text/xml"); SOAPEnvelope env = msg.getSOAPPart().getEnvelope(); env.addAttribute(sf.createName("xmlns:xsi"), "http://www.w3.org/2001/XMLSchema-instance");

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  • How can I configure a Hudson job to use a specific JDK?

    - by rewbs
    I have a number of projects running on a Hudson slave. I'd like one of them to run Ant under Java6, rather than the default (which is Java5 in my environment). In the project configuration view, I was hoping to find either: An explicit option allowing me to set a custom JDK location to use for this project. A way to set custom environment variables for this project, which would allow me to set JAVA_HOME to the JDK6 location. The would make Ant pick up and run on Java6 as desired. Is there a way to do either of the above? If one of those facilities is available, I can't see how to access it. I'm running on Hudson 1.285. I would rather avoid using an "execute shell" operation instead of the "invoke Ant" operation if possible: my slave is on z/OS and Hudson doesn't seem to create the temporary shell scripts properly on this platform (probably an encoding issue).

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  • Move the position in JEditorPane

    - by Joe
    Hi, I've a JEditorPane inside a JDialog. I'm loading a web page when this JDialog is loading. This web page is larger then the JEditorPane size. So I want to display a certain position in the web page by default. For example, I've a 175x200 size jdialog and JEditorPane. I want to display the web page sontent around 150 pixels down. Is there any solutions for this? Or is there any other component which I can used to display web pages and can move to a certain position of the web page at loading time.

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  • How to use a photo that has just been uploaded to Tomcat v6?

    - by Zombie_Colonel
    In an android application a user can upload a picture to a Tomcat server v6 in (Projet\WebContent\images) A second user can come at the same time display the picture thing not work it shows me: The requested resource is not available. I did what? I have to reboot the server? refresh? in a PHP page I upload pictures and then they are simply viewed by the user, for cons there I find difficulty with JEE

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