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  • Calculating the correct particle angle in an outwards explosion

    - by Sun
    I'm creating a simple particle explosion but am stuck in finding the correct angle to rotate my particle. The effect I'm going for is similar to this: Where each particle is going outwards from the point of origin and at the correct angle. This is what I currently have: As you can see, each particle is facing the same angle, but I'm having a little difficulty figuring out the correct angle. I have the vector for the point of emission and the new vector for each particle, how can I use this to calculate the angle? Some code for reference: private Particle CreateParticle() { ... Vector2 velocity = new Vector2(2.0f * (float)(random.NextDouble() * 2 - 1), 2.0f * (float)(random.NextDouble() * 2 - 1)); direction = velocity - ParticleLocation; float angle = (float)Math.Atan2(direction.Y, direction.X); ... return new Particle(texture, position, velocity, angle, angularVelocity, color, size, ttl, EmitterLocation); } I am then using the angle created as so in my particles Draw method: spriteBatch.Draw(Texture, Position, null, Color, Angle, origin, Size, SpriteEffects.None, 0f);

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  • Rotating wheel with touch (adding momentum and slowing down the initial rate it can be moved

    - by Lewis
    I have a wheel control in a game which is setup like so: - (void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; CGPoint location = [touch locationInView:[touch view]]; location = [[CCDirector sharedDirector] convertToGL:location]; if (CGRectContainsPoint(wheel.boundingBox, location)) { CGPoint firstLocation = [touch previousLocationInView:[touch view]]; CGPoint location = [touch locationInView:[touch view]]; CGPoint touchingPoint = [[CCDirector sharedDirector] convertToGL:location]; CGPoint firstTouchingPoint = [[CCDirector sharedDirector] convertToGL:firstLocation]; CGPoint firstVector = ccpSub(firstTouchingPoint, wheel.position); CGFloat firstRotateAngle = -ccpToAngle(firstVector); CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle); CGPoint vector = ccpSub(touchingPoint, wheel.position); CGFloat rotateAngle = -ccpToAngle(vector); CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle); wheelRotation += (currentTouch - previousTouch) * 0.6; //limit speed 0.6 } } Now once the user lets go of the wheel I want it to rotate back to where it was before but not without taking into account the momentum of the swipe the user has done. This is the bit I really can't get my head around. So if the swipe generates a lot of momentum then the wheel will carry on moving slightly in that direction until the overall force which pulls the wheel back to the starting position kicks in. Any ideas/code snippets?

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  • So what is Active GridLink for RAC?

    - by Ruma Sanyal
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 I had referred to Active GridLink for RAC in my blog yesterday and since then got several questions on this topic. So I decided to re-visit Active GridLink. With the release of version 11g, Oracle WebLogic Server started to provide strong support for the Real Application Clusters (RAC) features in Oracle Database 11g, minimizing database access time while allowing transparent access to rich pooling management functions that maximizes both connection performance and availability. WebLogic is the only application server in the marketplace which has been fully integrated and certified with Oracle Database RAC 11g without losing any rich functionality. Active GridLink provides Fast Connection Failover (FCF), Runtime Connection Load-Balancing (RCLB), and RAC instance graceful shutdown. With the key foundation for providing deeper integration with Oracle RAC, this single data source implementation in Oracle WebLogic Server supports the full and unrestricted use of database services as the connection target for a data source. For more details and to understand how our customer NEC leverages this capability, read the whitepapers on this topic. Get in depth ‘how-to’ details from this youtube video from our resident expert, Frances Zhao.

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  • Multiple domains for different products?

    - by alexandertr
    I have a website with software applications. Is it good for SEO to choose one keyword rich domain name for each of our software products or should we stick to a single domain? From a user's perspective I think it would be easier to remember a domain that is keyword rich as the user will instantly know what this product is for. But I have read articles that the latest trend in SEO is to stick to one domain for all of your products and invest on this single domain website. Is that true? What do you advise? Should I register a separate domain for each of our products or should I use only one single domain? Should I do a 301 redirect with a .htaccess to a single domain? And what about the sitemaps? Should I register all sites in Google Webmaster Tools and post a separate sitemap for each one of them? should my main site sitemap include all pages or should separate domains have their own sitemaps?

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  • Can someone explain the (reasons for the) implications of colum vs row major in multiplication/concatenation?

    - by sebf
    I am trying to learn how to construct view and projection matrices, and keep reaching difficulties in my implementation owing to my confusion about the two standards for matrices. I know how to multiply a matrix, and I can see that transposing before multiplication would completely change the result, hence the need to multiply in a different order. What I don't understand though is whats meant by only 'notational convention' - from the articles here and here the authors appear to assert that it makes no difference to how the matrix is stored, or transferred to the GPU, but on the second page that matrix is clearly not equivalent to how it would be laid out in memory for row-major; and if I look at a populated matrix in my program I see the translation components occupying the 4th, 8th and 12th elements. Given that: "post-multiplying with column-major matrices produces the same result as pre-multiplying with row-major matrices. " Why in the following snippet of code: Matrix4 r = t3 * t2 * t1; Matrix4 r2 = t1.Transpose() * t2.Transpose() * t3.Transpose(); Does r != r2 and why does pos3 != pos for: Vector4 pos = wvpM * new Vector4(0f, 15f, 15f, 1); Vector4 pos3 = wvpM.Transpose() * new Vector4(0f, 15f, 15f, 1); Does the multiplication process change depending on whether the matrices are row or column major, or is it just the order (for an equivalent effect?) One thing that isn't helping this become any clearer, is that when provided to DirectX, my column major WVP matrix is used successfully to transform vertices with the HLSL call: mul(vector,matrix) which should result in the vector being treated as row-major, so how can the column major matrix provided by my math library work?

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  • Predictive firing (in a tile-based game)

    - by n00bster
    I have a (turn-based) tile-based game, in which you can shoot at entities. You can move around with mouse and keyboard, it's all tile-based, except that bullets move "freely". I've got it all working just fine except that when I move, and the creatures shoot towards the player, they shoot towards the previous tiles.. resulting in ugly looking "miss hits" or lag. I think I need to implement some kind of predictive firing based on the bullet speed and the distance, but I don't quite know how to implement such a thing... Here's a simplified snip of my firing code. class Weapon { public void fire(int x, int y) { ... ... ... Creature owner = getOwner(); Tile targetTile = Zone.getTileAt(x, y); float dist = Vector.distance(owner.getCenterPosition(), targetTile.getCenterPosition()); Bullet b = new Bullet(); b.setPosition(owner.getCenterPosition()); // Take dist into account in the duration to get constant speed regardless of distance float duration = dist / 600f; // Moves the bullet to the centre of the target tile in the given amount of time (in seconds) b.moveTo(targetTile.getCenterPosition(), duration); // This is what I'm after // Vector v = predict the position // b.moveTo(v, duration); Zone.add(bullet); // Now the bullet gets "ticked" and moveTo will be implemented } } Movement of creatures is as simple as setting the position variable. If you need more information, just ask.

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  • What is the best way to store a table in C++

    - by Topo
    I'm programming a decision tree in C++ using a slightly modified version of the C4.5 algorithm. Each node represents an attribute or a column of your data set and it has a children per possible value of the attribute. My problem is how to store the training data set having in mind that I have to use a subset for each node so I need a quick way to only select a subset of rows and columns. The main goal is to do it in the most memory and time efficient possible (in that order of priority). The best way I have thought of is to have an array of arrays (or std::vector), or something like that, and for each node have a list (array, vector, etc) or something with the column,line(probably a tuple) pairs that are valid for that node. I now there should be a better way to do this, any suggestions? UPDATE: What I need is something like this: In the beginning I have this data: Paris 4 5.0 True New York 7 1.3 True Tokio 2 9.1 False Paris 9 6.8 True Tokio 0 8.4 False But for the second node I just need this data: Paris 4 5.0 New York 7 1.3 Paris 9 6.8 And for the third node: Tokio 2 9.1 Tokio 0 8.4 But with a table of millions of records with up to hundreds of columns. What I have in mind is keep all the data in a matrix, and then for each node keep the info of the current columns and rows. Something like this: Paris 4 5.0 True New York 7 1.3 True Tokio 2 9.1 False Paris 9 6.8 True Tokio 0 8.4 False Node 2: columns = [0,1,2] rows = [0,1,3] Node 3: columns = [0,1,2] rows = [2,4] This way on the worst case scenario I just have to waste size_of(int) * (number_of_columns + number_of_rows) * node That is a lot less than having an independent data matrix for each node.

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  • Rotating a sprite to touch

    - by user1691659
    I know this has been asked before and Ive looked through peoples questions and answers all over the internet and I just cant get it to work. Im sure its down to my inexperience. Ive got an arrow attached to a sprite, this sprite appears when touched but I want the arrow to point where the sprite will launch. I have had the arrow moving but it was very erratic and not pointing as it should. Its not moving at the moment but this is what I have. - (void)update:(ccTime)delta { arrow.rotation = dialRotation; } -(void) ccTouchMoved:(UITouch*)touch withEvent:(UIEvent *)event { pt1 = [self convertTouchToNodeSpace:touch]; CGPoint firstVector = ccpSub(pt, arrow.position); CGFloat firstRotateAngle = -ccpToAngle(firstVector); CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle); CGPoint vector = ccpSub(pt1, arrow.position); CGFloat rotateAngle = -ccpToAngle(vector); CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle); dialRotation += currentTouch - previousTouch; } I have got pt from ccTouchBegan the same way as pt1 Thanks

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  • WPF Blurry Images - Bitmap Class

    - by Luke
    I am using the following sample at http://blogs.msdn.com/dwayneneed/archive/2007/10/05/blurry-bitmaps.aspx within VB.NET. The code is shown below. I am having a problem when my application loads the CPU is pegging 50-70%. I have determined that the problem is with the Bitmap class. The OnLayoutUpdated() method is calling the InvalidateVisual() continously. This is because some points are not returning as equal but rather, Point(0.0,-0.5) Can anyone see any bugs within this code or know a better implmentation for pixel snapping a Bitmap image so it is not blurry? p.s. The sample code was in C#, however I believe that it was converted correctly. Imports System Imports System.Collections.Generic Imports System.Windows Imports System.Windows.Media Imports System.Windows.Media.Imaging Class Bitmap Inherits FrameworkElement ' Use FrameworkElement instead of UIElement so Data Binding works as expected Private _sourceDownloaded As EventHandler Private _sourceFailed As EventHandler(Of ExceptionEventArgs) Private _pixelOffset As Windows.Point Public Sub New() _sourceDownloaded = New EventHandler(AddressOf OnSourceDownloaded) _sourceFailed = New EventHandler(Of ExceptionEventArgs)(AddressOf OnSourceFailed) AddHandler LayoutUpdated, AddressOf OnLayoutUpdated End Sub Public Shared ReadOnly SourceProperty As DependencyProperty = DependencyProperty.Register("Source", GetType(BitmapSource), GetType(Bitmap), New FrameworkPropertyMetadata(Nothing, FrameworkPropertyMetadataOptions.AffectsRender Or FrameworkPropertyMetadataOptions.AffectsMeasure, New PropertyChangedCallback(AddressOf Bitmap.OnSourceChanged))) Public Property Source() As BitmapSource Get Return DirectCast(GetValue(SourceProperty), BitmapSource) End Get Set(ByVal value As BitmapSource) SetValue(SourceProperty, value) End Set End Property Public Shared Function FindParentWindow(ByVal child As DependencyObject) As Window Dim parent As DependencyObject = VisualTreeHelper.GetParent(child) 'Check if this is the end of the tree If parent Is Nothing Then Return Nothing End If Dim parentWindow As Window = TryCast(parent, Window) If parentWindow IsNot Nothing Then Return parentWindow Else ' Use recursion until it reaches a Window Return FindParentWindow(parent) End If End Function Public Event BitmapFailed As EventHandler(Of ExceptionEventArgs) ' Return our measure size to be the size needed to display the bitmap pixels. ' ' Use MeasureOverride instead of MeasureCore so Data Binding works as expected. ' Protected Overloads Overrides Function MeasureCore(ByVal availableSize As Size) As Size Protected Overloads Overrides Function MeasureOverride(ByVal availableSize As Size) As Size Dim measureSize As New Size() Dim bitmapSource As BitmapSource = Source If bitmapSource IsNot Nothing Then Dim ps As PresentationSource = PresentationSource.FromVisual(Me) If Me.VisualParent IsNot Nothing Then Dim window As Window = window.GetWindow(Me.VisualParent) If window IsNot Nothing Then ps = PresentationSource.FromVisual(window.GetWindow(Me.VisualParent)) ElseIf FindParentWindow(Me) IsNot Nothing Then ps = PresentationSource.FromVisual(FindParentWindow(Me)) End If End If ' If ps IsNot Nothing Then Dim fromDevice As Matrix = ps.CompositionTarget.TransformFromDevice Dim pixelSize As New Vector(bitmapSource.PixelWidth, bitmapSource.PixelHeight) Dim measureSizeV As Vector = fromDevice.Transform(pixelSize) measureSize = New Size(measureSizeV.X, measureSizeV.Y) Else measureSize = New Size(bitmapSource.PixelWidth, bitmapSource.PixelHeight) End If End If Return measureSize End Function Protected Overloads Overrides Sub OnRender(ByVal dc As DrawingContext) Dim bitmapSource As BitmapSource = Me.Source If bitmapSource IsNot Nothing Then _pixelOffset = GetPixelOffset() ' Render the bitmap offset by the needed amount to align to pixels. dc.DrawImage(bitmapSource, New Rect(_pixelOffset, DesiredSize)) End If End Sub Private Shared Sub OnSourceChanged(ByVal d As DependencyObject, ByVal e As DependencyPropertyChangedEventArgs) Dim bitmap As Bitmap = DirectCast(d, Bitmap) Dim oldValue As BitmapSource = DirectCast(e.OldValue, BitmapSource) Dim newValue As BitmapSource = DirectCast(e.NewValue, BitmapSource) If ((oldValue IsNot Nothing) AndAlso (bitmap._sourceDownloaded IsNot Nothing)) AndAlso (Not oldValue.IsFrozen AndAlso (TypeOf oldValue Is BitmapSource)) Then RemoveHandler DirectCast(oldValue, BitmapSource).DownloadCompleted, bitmap._sourceDownloaded RemoveHandler DirectCast(oldValue, BitmapSource).DownloadFailed, bitmap._sourceFailed ' ((BitmapSource)newValue).DecodeFailed -= bitmap._sourceFailed; // 3.5 End If If ((newValue IsNot Nothing) AndAlso (TypeOf newValue Is BitmapSource)) AndAlso Not newValue.IsFrozen Then AddHandler DirectCast(newValue, BitmapSource).DownloadCompleted, bitmap._sourceDownloaded AddHandler DirectCast(newValue, BitmapSource).DownloadFailed, bitmap._sourceFailed ' ((BitmapSource)newValue).DecodeFailed += bitmap._sourceFailed; // 3.5 End If End Sub Private Sub OnSourceDownloaded(ByVal sender As Object, ByVal e As EventArgs) InvalidateMeasure() InvalidateVisual() End Sub Private Sub OnSourceFailed(ByVal sender As Object, ByVal e As ExceptionEventArgs) Source = Nothing ' setting a local value seems scetchy... RaiseEvent BitmapFailed(Me, e) End Sub Private Sub OnLayoutUpdated(ByVal sender As Object, ByVal e As EventArgs) ' This event just means that layout happened somewhere. However, this is ' what we need since layout anywhere could affect our pixel positioning. Dim pixelOffset As Windows.Point = GetPixelOffset() If Not AreClose(pixelOffset, _pixelOffset) Then InvalidateVisual() End If End Sub ' Gets the matrix that will convert a Windows.Point from "above" the ' coordinate space of a visual into the the coordinate space ' "below" the visual. Private Function GetVisualTransform(ByVal v As Visual) As Matrix If v IsNot Nothing Then Dim m As Matrix = Matrix.Identity Dim transform As Transform = VisualTreeHelper.GetTransform(v) If transform IsNot Nothing Then Dim cm As Matrix = transform.Value m = Matrix.Multiply(m, cm) End If Dim offset As Vector = VisualTreeHelper.GetOffset(v) m.Translate(offset.X, offset.Y) Return m End If Return Matrix.Identity End Function Private Function TryApplyVisualTransform(ByVal Point As Windows.Point, ByVal v As Visual, ByVal inverse As Boolean, ByVal throwOnError As Boolean, ByRef success As Boolean) As Windows.Point success = True If v IsNot Nothing Then Dim visualTransform As Matrix = GetVisualTransform(v) If inverse Then If Not throwOnError AndAlso Not visualTransform.HasInverse Then success = False Return New Windows.Point(0, 0) End If visualTransform.Invert() End If Point = visualTransform.Transform(Point) End If Return Point End Function Private Function ApplyVisualTransform(ByVal Point As Windows.Point, ByVal v As Visual, ByVal inverse As Boolean) As Windows.Point Dim success As Boolean = True Return TryApplyVisualTransform(Point, v, inverse, True, success) End Function Private Function GetPixelOffset() As Windows.Point Dim pixelOffset As New Windows.Point() Dim ps As PresentationSource = PresentationSource.FromVisual(Me) If ps IsNot Nothing Then Dim rootVisual As Visual = ps.RootVisual ' Transform (0,0) from this element up to pixels. pixelOffset = Me.TransformToAncestor(rootVisual).Transform(pixelOffset) pixelOffset = ApplyVisualTransform(pixelOffset, rootVisual, False) pixelOffset = ps.CompositionTarget.TransformToDevice.Transform(pixelOffset) ' Round the origin to the nearest whole pixel. pixelOffset.X = Math.Round(pixelOffset.X) pixelOffset.Y = Math.Round(pixelOffset.Y) ' Transform the whole-pixel back to this element. pixelOffset = ps.CompositionTarget.TransformFromDevice.Transform(pixelOffset) pixelOffset = ApplyVisualTransform(pixelOffset, rootVisual, True) pixelOffset = rootVisual.TransformToDescendant(Me).Transform(pixelOffset) End If Return pixelOffset End Function Private Function AreClose(ByVal Point1 As Windows.Point, ByVal Point2 As Windows.Point) As Boolean Return AreClose(Point1.X, Point2.X) AndAlso AreClose(Point1.Y, Point2.Y) End Function Private Function AreClose(ByVal value1 As Double, ByVal value2 As Double) As Boolean If value1 = value2 Then Return True End If Dim delta As Double = value1 - value2 Return ((delta < 0.00000153) AndAlso (delta > -0.00000153)) End Function End Class

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  • Export JPG out of Dicom File With mDCM

    - by Ross Peoples
    Hello, I'm using mDCM with C# to view dicom tags, but I'm trying to convert the pixel data to a Bitmap and eventually out to a JPG file. I have read all of the posts on the mDCM Google Group on the subject and all of the code examples either don't work or are missing important lines of code. The image I am working with is a 16 bit monochrome1. I have tried using LockBits, SetPixel, and unsafe code in order to convert the pixel data to a Bitmap but all attempts fail. Does anyone have any code that could make this work. Thanks in advance P.S. Before anyone suggests trying something else like ClearCanvas, know that mDCM is the only library that suits my needs and ClearCanvas is WAY too bloated for what I need to do.

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  • Resizing JPEG image during decoding

    - by Thomas
    I'm working on a program that creates thumbnails of JPEG images on the fly. Now I was thinking: since a JPEG image is built from 8x8-pixel blocks (Wikipedia has a great explanation), would it be possible to skip part of the decoding? Let's say that my thumbnails are at least 8 times smaller than the original image. We could then map each 8x8 block in the input file to 1 pixel in the decoding output, by including only the constant term of the discrete cosine transform. Most of the image data can be discarded right away, and need not be processed. Moreover, the memory usage is reduced by a factor of 64. I don't want to implement this from scratch; that'll easily take a week. Is there any code out there that can do this? If not, is this because this approach isn't worthwhile, or simply because nobody has thought of it yet?

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  • Fastest Algorithm to scale down 32Bit RGB IMAGE.

    - by Sunny
    which algorithm to use to scale down 32Bit RGB IMAGE to custom resolution? Algorithm should average pixels. for example If I have 100x100 image and I want new Image of size 20x50. Avg of first five pixels of first source row will give first pixel of dest, And avg of first two pixels of first source column will give first dest column pixel. Currently what I do is first scale down in X resolution, and after that I scale down in Y resolution. I need one temp buffer in this method. Is there any optimized method that you know?

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  • Web service creates stack overflow

    - by mouthpiec
    I have an application that when executed as a windows application works fine, but when converted to a web service, in some instances (which were tested successfully) by the windows app) creates a stack overflow. Do you have an idea of what can cause this? (Note that it works fine when the web service is placed on the localhost). Could it be that the stack size of a Web Service is smaller than that of a Window Application? UPDATE The below is the code in which I am getting a stack overflow error private bool CheckifPixelsNeighbour(Pixel c1, Pixel c2, int DistanceAllowed) { bool Neighbour = false; if ((Math.Abs(c1.X - c2.X) <= DistanceAllowed) && Math.Abs(c1.Y - c2.Y) <= DistanceAllowed) { Neighbour = true; } return Neighbour; }

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  • Novel fitness measure for evolutionary image matching simulation

    - by Nick Johnson
    I'm sure many people have already seen demos of using genetic algorithms to generate an image that matches a sample image. You start off with noise, and gradually it comes to resemble the target image more and more closely, until you have a more-or-less exact duplicate. All of the examples I've seen, however, use a fairly straightforward pixel-by-pixel comparison, resulting in a fairly predictable 'fade in' of the final image. What I'm looking for is something more novel: A fitness measure that comes closer to what we see as 'similar' than the naive approach. I don't have a specific result in mind - I'm just looking for something more 'interesting' than the default. Suggestions?

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  • Winforms Hotkey, Help?

    - by Di4g0n4leye
    namespace WebBrowser { public partial class MainForm : Form { public MainForm() { InitializeComponent(); } int GetPixel(int x, int y) { Bitmap bmp = new Bitmap(1, 1, PixelFormat.Format32bppPArgb); Graphics grp = Graphics.FromImage(bmp); grp.CopyFromScreen(new Point(x,y), Point.Empty, new Size(1,1)); grp.Save(); return bmp.GetPixel(0, 0).ToArgb(); } void Button1Click(object sender, EventArgs e) { int x = Cursor.Position.X; int y = Cursor.Position.Y; int pixel = GetPixel(x,y); textBox1.Text = pixel.ToString(); } void MainFormLoad(object sender, EventArgs e) { webBrowser1.Navigate("http://google.com"); } } } } i want to add a hotkey that call Button1 on Press, How can that be done?

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  • How does glClear() improve performance?

    - by Jon-Eric
    Apple's Technical Q&A on addressing flickering (QA1650) includes the following paragraph. (Emphasis mine.) You must provide a color to every pixel on the screen. At the beginning of your drawing code, it is a good idea to use glClear() to initialize the color buffer. A full-screen clear of each of your color, depth, and stencil buffers (if you're using them) at the start of a frame can also generally improve your application's performance. On other platforms, I've always found it to be an optimization to not clear the color buffer if you're going to draw to every pixel. (Why waste time filling the color buffer if you're just going to overwrite that clear color?) How can a call to glClear() improve performance?

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  • How can I encode four unsigned bytes (0-255) to a float and back again using HLSL?

    - by Statement
    Hello! I am facing a task where one of my hlsl shaders require multiple texture lookups per pixel. My 2d textures are fixed to 256*256, so two bytes should be sufficient to address any given texel given this constraint. My idea is then to put two xy-coordinates in each float, giving me eight xy-coordinates in pixel space when packed in a Vector4 format image. These eight coordinates are then used to sample another texture(s). The reason for doing this is to save graphics memory and an attempt to optimize processing time, since then I don't require multiple texture lookups. By the way: Does anyone know if encoding/decoding 16 bytes from/to 4 floats using 1 sampling is slower than 4 samplings with unencoded data?

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  • How can I use a Shader in XNA to color single pixels?

    - by George Johnston
    I have a standard 800x600 window in my XNA project. My goal is to color each individual pixel based on a rectangle array which holds boolean values. Currently I am using a 1x1 Texture and drawing each sprite in my array. I am very new to XNA and come from a GDI background, so I am doing what I would have done in GDI, but it doesn't scale very well. I have been told in another question to use a Shader, but after much research, I still haven't been able to find out how to accomplish this goal. My application loops through the X and Y coordinates of my rectangular array, does calculations based on each value, and reassigns/moves the array around. At the end, I need to update my "Canvas" with the new values. A smaller sample of my array would look like: 0,0,0,0,0,0,0 0,0,0,0,0,0,0 0,0,0,0,0,0,0 1,1,1,1,1,1,1 1,1,1,1,1,1,1 How can I use a shader to color each pixel?

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  • Faster way to iterate through a jaggad array?

    - by George Johnston
    I would like to iterate through an array that covers every pixel on my screen. i.e: for (int y = 598; y > 0; y--) { for (int x = 798; x > 0; x--) { if (grains[x][y]) { spriteBatch.Draw(Grain, new Vector2(x,y), Color.White); } } } ...my texture is a 1x1 pixel image that is drawn to the screen when the array value is true. It runs decent -- but there is definitely lag the more screen I cover. Is there a better way to accomplish what I am trying to achieve?

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  • Finding distance travelled by robot using Optical Flow

    - by user280454
    Hi, I'm working on a project right now in which we are developing an autonomous robot. I have to basically find out the distance travelled by the robot between any 2 intervals. I'm using OpenCV, and using the Optical Flow functions of OpenCV, I'm able to find out the velocity/distance of each pixel in 2 different images. Using this information, I want to be able to find out the distance travelled by the robot in the interval between those 2 images. I thought of a way in which we could develop an input output mapping between the distance travelled by pixels and the distance travelled by the bot (using some tests). In this way, using neural networks, we would be able to find the relationship. However, the optical flow would depend on the distance of the camera from the pixel, which would cause problems. Is there any way to solve this problem?

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  • Faster way to iterate through a jagged array?

    - by George Johnston
    I would like to iterate through an array that covers every pixel on my screen. i.e: for (int y = 598; y > 0; y--) { for (int x = 798; x > 0; x--) { if (grains[x][y]) { spriteBatch.Draw(Grain, new Vector2(x,y), Color.White); } } } ...my texture is a 1x1 pixel image that is drawn to the screen when the array value is true. It runs decent -- but there is definitely lag the more screen I cover. Is there a better way to accomplish what I am trying to achieve?

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  • Screen Capture with Open GL using glReadPixels

    - by Raja
    Hi, I created a CGRegisterScreenRefreshCallback(refreshCallback, NULL) and in the refreshCallback method get the list of rectangles which have changed. I am getting the rectangle data from frameBuffer using OpenGL glReadPixels. Is there a better way of screen capture either with/without opengl and also using OpenGL can I skip reading pixel by pixel ? I have looked at glGetTexImage and glCopyTexSubImage2D. Any simple code block which can explain how to use these functions to get the changed rectangle data would be very helpful ? Thanks, Raja.

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  • 3ds collada UV mapping problem in Papervision

    - by MonsieurOreilles
    Hi everyone, as I briefly explained in the title, my prblem concerns texturing a collada export in papervision. Basically I was exporting collada models from Cinema 4d with its uv map. I was able to see everything, but the texture was not displaying properly (hidden polygons). So I decided to try with 3dsMax. I used the same code to display the texture : var materials:MaterialsList = new MaterialsList(); var torusMaterial:BitmapFileMaterial = new BitmapFileMaterial("model/tex.png"); torusMaterial.precise = true; materials.addMaterial(torusMaterial, "ID1"); Again, I can see every elements, but this time my model uses only one pixel of my texture. So if I use a red texture and if I color only the pixel at the left bottom corner in green, all my model will be green. Any advice about how to properly wrap the texture around a 3ds export model ? Thank you.

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  • Blurry text in WPF even with ClearTypeHinting enabled?

    - by rFactor
    I have a grid with this template and styles in WPF/XAML: <Setter Property="TextOptions.TextFormattingMode" Value="Display" /> <Setter Property="RenderOptions.ClearTypeHint" Value="Enabled" /> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type DataGridCell}"> <Border Padding="{TemplateBinding Padding}" BorderBrush="{TemplateBinding BorderBrush}" BorderThickness="{TemplateBinding BorderThickness}" Background="{TemplateBinding Background}" SnapsToDevicePixels="True"> <ContentPresenter x:Name="CellContent" SnapsToDevicePixels="{TemplateBinding SnapsToDevicePixels}" RenderOptions.ClearTypeHint="Enabled" /> </Border> <ControlTemplate.Triggers> <Trigger Property="IsSelected" Value="True"> <Setter TargetName="CellContent" Property="TextOptions.TextFormattingMode" Value="Display" /> <Setter TargetName="CellContent" Property="RenderOptions.ClearTypeHint" Value="Enabled" /> <Setter TargetName="CellContent" Property="Effect"> <Setter.Value> <DropShadowEffect ShadowDepth="2" BlurRadius="2" Color="Black" RenderingBias="Quality" /> </Setter.Value> </Setter> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Setter.Value> </Setter> The DropShadowEffect I have when you select a grid row, seems to make the text rendering blurry (gray anti-aliasing): When I remove the drop shadow effect, it looks clear because it now uses ClearType and not gray sub-pixel anti-aliasing: I have tried applying RenderOptions.ClearTypeHint="Enabled" to the ContentPresenter as seen above, but it does not help. How do I force WPF to render the text that gets displayed with drop shadow effect to retain Cleartype anti-aliasing, instead of that ugly blurry gray sub-pixel anti-aliasing? Some believe it's blurry because of the drop shadow -- this is not true. It's blurry only because ClearType is not used. This is how it looks like in Firefox when shadow AND ClearType: ClearType enabled text is colorful -- but that blurry text is not, because it does not use ClearType -- it uses gray sub-pixel anti-aliasing and that's not how ClearType works: http://en.wikipedia.org/wiki/ClearType The question is: how do I enable ClearType for this text?

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  • I've got my 2D/3D conversion working perfectly, how to do perspective

    - by user346992
    Although the context of this question is about making a 2d/3d game, the problem i have boils down to some math. Although its a 2.5D world, lets pretend its just 2d for this question. // xa: x-accent, the x coordinate of the projection // mapP: a coordinate on a map which need to be projected // _Dist_ values are constants for the projection, choosing them correctly will result in i.e. an isometric projection xa = mapP.x * xDistX + mapP.y * xDistY; ya = mapP.x * yDistX + mapP.y * yDistY; xDistX and yDistX determine the angle of the x-axis, and xDistY and yDistY determine the angle of the y-axis on the projection (and also the size of the grid, but lets assume this is 1-pixel for simplicity). x-axis-angle = atan(yDistX/xDistX) y-axis-angle = atan(yDistY/yDistY) a "normal" coordinate system like this --------------- x | | | | | y has values like this: xDistX = 1; yDistX = 0; xDistY = 0; YDistY = 1; So every step in x direction will result on the projection to 1 pixel to the right end 0 pixels down. Every step in the y direction of the projection will result in 0 steps to the right and 1 pixel down. When choosing the correct xDistX, yDistX, xDistY, yDistY, you can project any trimetric or dimetric system (which is why i chose this). So far so good, when this is drawn everything turns out okay. If "my system" and mindset are clear, lets move on to perspective. I wanted to add some perspective to this grid so i added some extra's like this: camera = new MapPoint(60, 60); dx = mapP.x - camera.x; // delta x dy = mapP.y - camera.y; // delta y dist = Math.sqrt(dx * dx + dy * dy); // dist is the distance to the camera, Pythagoras etc.. all objects must be in front of the camera fac = 1 - dist / 100; // this formula determines the amount of perspective xa = fac * (mapP.x * xDistX + mapP.y * xDistY) ; ya = fac * (mapP.x * yDistX + mapP.y * yDistY ); Now the real hard part... what if you got a (xa,ya) point on the projection and want to calculate the original point (x,y). For the first case (without perspective) i did find the inverse function, but how can this be done for the formula with the perspective. May math skills are not quite up to the challenge to solve this. ( I vaguely remember from a long time ago mathematica could create inverse function for some special cases... could it solve this problem? Could someone maybe try?)

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