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  • j2me/BlackBerry - How to send Email with Attachment from Application?

    - by SWATI
    hey i am building an application in which user can send an email to a person. The user enters the email id of the person to whom email is to be sent in a Edit field and then presses a send button the email must be delivered with an attachment. how can i do it?????? i m really confused after googling. can someone tell me the exact way also,cant i send email from simulator if my cod file is unsigned thanks in advance

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  • Can an applet communicate with an instance of a servlet

    - by mithun1538
    Hello everyone, I have an applet that communicates with a servlet using Http (Not sockets). Currently, each instance of the applet (i.e. when each applet is run by a different client on a different computer), all the instances communicate with the same servlet. What I want is that each instance of the applet communicate with different instances of the same servlet. Is this possible?

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  • antlr: Best practice to integrate generated parser into the system

    - by green
    Here is the background, I am trying to create a DSL to allow customer write simple scripts to query into our mongodb based database. I choose antlr to implement the DSL. From my understanding (and pls let me know if it's not correct) there are 2 approaches to integrate antlr generated parser into the system: Embed code into the grammar file so that the generated parser could be used directly to make query to the database and return result in a certain format (e.g. json encoded) Keep the parser purely a parser, after feed the DSL file to it, and construct the query in another class by retrieving the AST from generated parser class So antlrers, which one do you think is the way I as an antlr newbie should go? Can you list the pros and cos of each approach, or you have other way to recommend?

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  • Why junit ComparisonFailure is not used by assertEquals(Object, Object) ?

    - by Philippe Blayo
    In Junit 4, do you see any drawback to throw a ComparisonFailure instead of an AssertionError when assertEquals(Object, Object) fails ? assertEquals(Object, Object) throws a ComparisonFailure if both expected and actual are String an AssertionError if either is not a String @Test(expected=ComparisonFailure.class ) public void twoString() { assertEquals("a String", "another String"); } @Test(expected=AssertionError.class ) public void oneString() { assertEquals("a String", new Object()); } The two reasons why I ask the question: ComparisonFailure provide far more readable way to spot the differences in dialog box of eclipse or Intellij IDEA (FEST-Assert throws this exception) Junit 4 already use String.valueOf(Object) to build message "expected ... but was ..." (format method invoqued by Assert.assertEquals(message, Object, Object) in junit-4.8.2): static String format(String message, Object expected, Object actual) { ... String expectedString= String.valueOf(expected); String actualString= String.valueOf(actual); if (expectedString.equals(actualString)) return formatted + "expected: " + formatClassAndValue(expected, expectedString) +" but was: " + formatClassAndValue(actual, actualString); else return formatted +"expected:<"+ expectedString +"> but was:<"+ actualString +">"; Isn't it possible in assertEquals(message, Object, Object) to replace fail(format(message, expected, actual)); by throw new ComparisonFailure(message, formatClassAndValue(expectedObject, expectedString), formatClassAndValue(actualObject, actualString)); Do you see any compatibility issue with other tool, any algorithmic problem with that... ?

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  • SensorManager method crashes program

    - by Aidan
    Hi guys, When I run the following method my Android application crashes. I can't find the error because I get a "Source Not Found" error. Anyone have any idea's what I'm doing wrong? public void bearing(){ SensorManager sm = (SensorManager)getSystemService(Context.SENSOR_SERVICE); Sensor aSensor = sm.getDefaultSensor(Sensor.TYPE_ACCELEROMETER); Sensor mfSensor = sm.getDefaultSensor(Sensor.TYPE_MAGNETIC_FIELD); sm.registerListener(myAccelerometerListener, aSensor, SensorManager.SENSOR_DELAY_UI); sm.registerListener(myMagneticFieldListener, mfSensor, SensorManager.SENSOR_DELAY_UI); float[] values = new float[3]; float[] R = new float[9]; SensorManager.getRotationMatrix(R, null, accelerometerValues, magneticFieldValues); SensorManager.getOrientation(R, values); //Convert from Radians to degrees values[0] = (float) Math.toDegrees(values[0]); values[1] = (float) Math.toDegrees(values[1]); values[2] = (float) Math.toDegrees(values[2]); }

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  • Line up swing components by edges

    - by rasen58
    Is it possible to line up swing components? The components are in separate panels which both use flow layout. These two panels are in another panel which is using a grid layout. As you can see there is a subtle difference and I find it annoying. I know that all of the jlabels [the rectangles in blue/purple all have the same size, so i think it might be because of the '+' and '*', but I'm not sure because the left sides of the first two boxes aren't lined up. the panels JPanel panel2 = new JPanel(new GridLayout(4, 1)); JPanel panel2a = new JPanel(new FlowLayout()); JPanel panel2b = new JPanel(new FlowLayout()); the first two rectangles (purple) add1 = new JLabel("", JLabel.CENTER); add1.setTransferHandler(new TransferHandler("text")); add1.setBorder(b2); add2 = new JLabel("", JLabel.CENTER); add2.setTransferHandler(new TransferHandler("text")); add2.setBorder(b2); the two blue rectangles textFieldA = new JTextField(); textFieldA.setHorizontalAlignment(JTextField.CENTER); textFieldA.setEditable(false); textFieldA.setBorder(new LineBorder(Color.blue)); textFieldM = new JTextField(); textFieldM.setHorizontalAlignment(JTextField.CENTER); textFieldM.setEditable(false); textFieldM.setBorder(new LineBorder(Color.blue)); the + and * opA = new JLabel("+", JLabel.CENTER); opS = new JLabel("*", JLabel.CENTER); Showing that the rectangles are the same size Dimension d = card1.getPreferredSize(); int width = d.width + 100; int height = d.height + 50; add1.setPreferredSize(new Dimension(width, height)); add2.setPreferredSize(new Dimension(width, height)); mult1.setPreferredSize(new Dimension(width, height)); mult2.setPreferredSize(new Dimension(width, height)); textFieldA.setPreferredSize(new Dimension(width, height)); textFieldM.setPreferredSize(new Dimension(width, height)); Adding to the panels panel2a.add(add1); panel2a.add(opA); panel2a.add(add2); panel2a.add(enterA); panel2a.add(textFieldA); panel2c.add(mult1); panel2c.add(opM); panel2c.add(mult2); panel2c.add(enterM); panel2c.add(textFieldM); panel2.add(panel2a); panel2.add(panel2c);

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  • Can't referr to my get method

    - by chility
    I have this amazing and good looking class: public class SayingsHolder extends Application{ ArrayList<String> SayingsList = new ArrayList<String>(){{ SayingsList.add("1"); SayingsList.add("2"); }}; public ArrayList<String> getSayingsList() { return SayingsList; } } Now I'm trying to call the getSayingsList method inside of my activity's FragmentStatePagerAdapter by: private class ScreenSlidePagerAdapter extends FragmentStatePagerAdapter { final SayingsHolder holder = (SayingsHolder).getApplication(); } Everything fine for now, but when I make my code like this: private class ScreenSlidePagerAdapter extends FragmentStatePagerAdapter { final SayingsHolder holder = (SayingsHolder).getApplication(); holder.getSayingsList(); } it says: Syntax error on token "getSayingsList", Identifier expected after this token The problem is that holder is not functional at all. What I mean is that when i type the this holder. the getSayingsList is not showing at all. What am I missing here? I know that it is an extremely small issue, but it seems that I can't spot it. My activity extends FragmentActivity if it's important It seems that I'm missing something here. I can't call my method anywhere in my activity. I'm starting a bounty, because I need an example.

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  • rule based file parsing

    - by user359490
    I need to parse a file line by line on given rules. Here is a requirement. file can have multiple lines with different data.. 01200344545143554145556524341232131 1120034454514355414555652434123213101200344545143554145556524341232131 2120034454514 and rules can be like this. if byte[0,1] == "0" then extract this line to /tmp/record0.dat if byte[0,1] == "1" then extract this line to /tmp/record1.dat if byte[0,1] == "2" then extract this line to /tmp/record2.dat I am looking for any language which can do this in a fast manner with a very long file size like 2 GB. Appreciate all the help in advance. Thanks

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  • Is there a simpliest way of doing this?

    - by Tom Brito
    Is there a simpler way of implement this? Or a implemented method in JDK or other lib? /** * Convert a byte array to 2-byte-size hexadecimal String. */ public static String to2DigitsHex(byte[] bytes) { String hexData = ""; for (int i = 0; i < bytes.length; i++) { int intV = bytes[i] & 0xFF; // positive int String hexV = Integer.toHexString(intV); if (hexV.length() < 2) { hexV = "0" + hexV; } hexData += hexV; } return hexData; } public static void main(String[] args) { System.out.println(to2DigitsHex(new byte[] {8, 10, 12})); } the output is: "08 0C 0A" (without the spaces)

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  • Ordering the results of a Hibernate Criteria query by using information of the child entities of the

    - by pkainulainen
    I have got two entities Person and Book. Only one instance of a specific book is stored to the system (When a book is added, application checks if that book is already found before adding a new row to the database). Relevant source code of the entities is can be found below: @Entity @Table(name="persons") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Person extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @ManyToMany(targetEntity=Book.class) @JoinTable(name="persons_books", joinColumns = @JoinColumn( name="person_id"), inverseJoinColumns = @JoinColumn( name="book_id")) private List<Book> ownedBooks = new ArrayList<Book>(); } @Entity @Table(name="books") @SequenceGenerator(name="id_sequence", sequenceName="hibernate_sequence") public class Book extends BaseModel { @Id @Column(name = "id") @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "id_sequence") private Long id = null; @Column(name="name") private String name = null; } My problem is that I want to find persons, which are owning some of the books owned by a specific persons. The returned list of persons should be ordered by using following logic: The person owning most of the same books should be at the first of the list, second person of the the list does not own as many books as the first person, but more than the third person. The code of the method performing this query is added below: @Override public List<Person> searchPersonsWithSimilarBooks(Long[] bookIds) { Criteria similarPersonCriteria = this.getSession().createCriteria(Person.class); similarPersonCriteria.add(Restrictions.in("ownedBooks.id", bookIds)); //How to set the ordering? similarPersonCriteria.addOrder(null); return similarPersonCriteria.list(); } My question is that can this be done by using Hibernate? And if so, how it can be done? I know I could implement a Comparator, but I would prefer using Hibernate to solve this problem.

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  • Transparently storing class state without exposing implementation

    - by RoToRa
    I have a model (MVC) class whose internal state (which basically contains of private int fields) I want to store. The program is running on Android (for now) so I need to store the in a Bundle, but I'll be using the same class later in a desktop application where I'll have to store the state some other way, so I can't reference Bundle directly in my class. So my question is: What is the best way to store (and retrieve) the state of a class without exposing it's implementation? The best I could think of removing the private access modifier so that the fields become package accessible and create read/write helper classes in the same package, but that somehow seems wrong.

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  • How to force Maven to download maven-metadata.xml from the central repository?

    - by Alceu Costa
    What I want to do is to force Maven to download the 'maven-metadata.xml' for each artifact that I have in my local repository. The default Maven behaviour is to download only metadata from remote repositories (see this question). Why I want to do that: Currently I have a remote repository running in a build machine. By remote repository I mean a directory located in the build machine that contains all dependencies that I need to build my Maven projects. Note that I'm not using a repository manager like Nexus, the repository is just a copy of a local repository that I have uploaded to my build machine. However, since my local repository did not contain the 'maven-metadata.xml' files, these metadata files are also missing in the build machine repository. If I could retrieve the metadata files from the central repository, then it would be possible to upload a working remote repository to my build machine.

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  • Remote tomcat deployment

    - by Hrushi
    I could set up the environment in my local host, But I have no choice like deploying my war file as its shared server, my admin ask me to extract the war file and upload through FTP. Now the problem is I am new to remote server. Please guide me with the remote environment file system and complete directory structure in remote tomcat. And how to use FTP for deployment ?

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  • OutOfMemoryError creating a tree recursively?

    - by Alexander Khaos Greenstein
    root = new TreeNode(N); constructTree(N, root); private void constructTree(int N, TreeNode node) { if (N > 0) { node.setLeft(new TreeNode(N-1)); constructTree(N-1, node.getLeft()); } if (N > 1) { node.setMiddle(new TreeNode(N-2)); constructTree(N-2, node.getMiddle()); } if (N > 2) { node.setRight(new TreeNode(N-3)); constructTree(N-3, node.getRight()); } Assume N is the root number, and the three will create a left middle right node of N-1, N-2, N-3. EX: 5 / | \ 4 3 2 /|\ 3 2 1 etc. My GameNode class has the following variables: private int number; private GameNode left, middle, right; Whenever I construct a tree with an integer greater than 28, I get a OutOfMemoryError. Is my recursive method just incredibly inefficient or is this natural? Thanks!

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  • JComboBox to string

    - by gabrielle fregil
    I have a String array of names, and then I added it into an editable JComboBox. The user can either pick his/her name from the choices or just input his/her name if not in the choices. How do I put the user input into a new string variable? String [] chooseName = { Mark, John, Allison, Jessica }; JComboBox combo = new JComboBox (chooseName); combo.setEditable(true); String chosenName = /* how do i place what the user inputed here? */

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  • How do I add an object to a binary tree based on the value of a member variable?

    - by Max
    How can I get a specific value from an object? I'm trying to get a value of an instance for eg. ListOfPpl newListOfPpl = new ListOfPpl(id, name, age); Object item = newListOfPpl; How can I get a value of name from an Object item?? Even if it is easy or does not interest you can anyone help me?? Edited: I was trying to build a binary tree contains the node of ListOfPpl, and need to sort it in the lexicographic. Here's my code for insertion on the node. Any clue?? public void insert(Object item){ Node current = root; Node follow = null; if(!isEmpty()){ root = new Node(item, null, null); return; }boolean left = false, right = false; while(current != null){ follow = current; left = false; right = false; //I need to compare and sort it if(item.compareTo(current.getFighter()) < 0){ current = current.getLeft(); left = true; }else { current = current.getRight(); right = true; } }if(left) follow.setLeft(new Node(item, null, null)); else follow.setRight(new Node(item, null, null)); }

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  • Spring Controller redirect to another page

    - by user1386375
    Hey I got the following problem. This is the content of the jspx file: function postSMTH() { $.ajax({ type: "POST", url: document.getElementById("urltxt").value, data: parameters, }); } <input type="hidden" value="${pageContext.request.contextPath}/foo/foo2/foodat" name="urltxt" id="urltxt"/> <div class="foodat"><a href="javascript:postSMTH();"><spring:message code="foo_foo2_foodat_text" text="FOODAT"/></a></div> So if I push the submit button, the postSMTH function is called and the ajax object is paste to the Controller which look like this: @Controller @RequestMapping(value="/foo") public class FooController { .............. @RequestMapping(value="/foo2", method=RequestMethod.POST) public String homePOST(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2", method=RequestMethod.GET) public String homeGET(HttpServletRequest request) { ........ } @RequestMapping(value="/foo2/foodat", method=RequestMethod.POST) public String doTHAT(HttpServletRequest request) { // check authorization Map fooMap = request.getParameterMap(); // do something in the Database, depending on the paramMap return "redirect:/foo/foo1"; } } Everything is working fine regarding the Database, but the Problem is, that the redirect at the end DOESN'T work. It just stays at the page foo2. I'm new to Spring, maybe its a little mistake somewhere. I just cant make it out by myself. Would be nice if someone would have some hint. Thanks

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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