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  • Implement Negascout Algorithm with stack

    - by Dan
    I'm not familiar with how these stack exchange accounts work so if this is double posting I apologize. I asked the same thing on stackoverflow. I have added an AI routine to a game I am working on using the Negascout algorithm. It works great, but when I set a higher maximum depth it can take a few seconds to complete. The problem is it blocks the main thread, and the framework I am using does not have a way to deal with multi-threading properly across platforms. So I am trying to change this routine from recursively calling itself, to just managing a stack (vector) so that I can progress through the routine at a controlled pace and not lock up the application while the AI is thinking. I am getting hung up on the second recursive call in the loop. It relies on a returned value from the first call, so I don't know how to add these to a stack. My Working c++ Recursive Code: MoveScore abNegascout(vector<vector<char> > &board, int ply, int alpha, int beta, char piece) { if (ply==mMaxPly) { return MoveScore(evaluation.evaluateBoard(board, piece, oppPiece)); } int currentScore; int bestScore = -INFINITY; MoveCoord bestMove; int adaptiveBeta = beta; vector<MoveCoord> moveList = evaluation.genPriorityMoves(board, piece, findValidMove(board, piece, false)); if (moveList.empty()) { return MoveScore(bestScore); } bestMove = moveList[0]; for(int i=0;i<moveList.size();i++) { MoveCoord move = moveList[i]; vector<vector<char> > newBoard; newBoard.insert( newBoard.end(), board.begin(), board.end() ); effectMove(newBoard, piece, move.getRow(), move.getCol()); // First Call ****** MoveScore current = abNegascout(newBoard, ply+1, -adaptiveBeta, -max(alpha,bestScore), oppPiece); currentScore = - current.getScore(); if (currentScore>bestScore){ if (adaptiveBeta == beta || ply>=(mMaxPly-2)){ bestScore = currentScore; bestMove = move; }else { // Second Call ****** current = abNegascout(newBoard, ply+1, -beta, -currentScore, oppPiece); bestScore = - current.getScore(); bestMove = move; } if(bestScore>=beta){ return MoveScore(bestMove,bestScore); } adaptiveBeta = max(alpha, bestScore) + 1; } } return MoveScore(bestMove,bestScore); } If someone can please help by explaining how to get this to work with a simple stack. Example code would be much appreciated. While c++ would be perfect, any language that demonstrates how would be great. Thank You.

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  • Desktop Fun: Wolves Wallpaper Collection Series 2

    - by Asian Angel
    Early last year we shared a wonderful collection of wolves wallpapers with you and today we are back we more to increase the size of your ‘wolf pack’. Feel the call of the wild on your desktop with the second in our series of Wolves Wallpaper collections. 7 Ways To Free Up Hard Disk Space On Windows HTG Explains: How System Restore Works in Windows HTG Explains: How Antivirus Software Works

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  • Austin Texas - Linux Against Poverty 2010

    <b>Blog of Helios:</b> "It's spring time in Texas. The Bluebonnets are fixin' to get ready to bloom, today's temperature is going to be around 80 degrees Fahrenheit and a solid date for the second annual Linux Against Poverty is, with a fair amount of certainty... official."

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  • Novell Files Motion for Judgment and Motion to Strike

    <b>Groklaw:</b> "Novell points out that the only evidence SCO presented regarding malice is testimony by Maureen O'Gara of a conversation with Chris Stone, and no one corroborates her story, first of all, and second, O'Gara admitted she can't recall exactly what was said..."

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  • Detecting if someone is in a room in your house and sending you an email.

    - by mbcrump
    Let me setup this scenario: You are selling your house. You have small children. (Possibly 2 rug rats or more) The real estate company calls and says they have a showing for your house between the hours of 3pm-6pm. You have to keep the children occupied. You realize this is the 5th time you have shown your house this week. What is a programmer to do?……Setup a webcam, find a motion detection software that has support to launch a program and of course, Visual Studio 2010. First, comes the tools Some sort of webcam, I chose the WinBook because a friend of mine loaned it to me. It is a basic USB2.0 camera that supports 640x480 without software.  Next up was find webcam software that supports launching a program. WebcamXP support this. VS 2010 Console Application. A cell phone that you can check your email. You may be asking, why write code to send the email when a lot of commercial software motion detection packages include that as base functionality. Well, first it cost money and second I don’t want the picture of the person as that probably invades privacy and as a future buyer, I don’t want someone recording me in their house. Now onto the show... First, the code part. We are going to create a VS2010 or whatever version you have installed and use the following code snippet. Code Snippet using System; using System.Net.Mail; using System.Net;     namespace MotionDetectionEmailer {     class Program     {         static void Main(string[] args)         {             try             {                 MailMessage m = new MailMessage                    ("[email protected]",                     "[email protected]",                     "Motion Detected at " + DateTime.Now,                     "Someone is in the downstairs basement.");                 SmtpClient client = new SmtpClient("smtp.charter.net");                 client.Credentials = new NetworkCredential("mbcrump", "NOTTELLINGYOU");                 client.Send(m);             }               catch (SmtpException ex)             {                 Console.WriteLine("Who cares?? " + ex.ToString());             }         }       } } Second, Download and install wecamxp and select the option to launch an external program and you are finished. Now, when you are at MCDonalds and can check your email on your phone, you will see when they entered the house and you can go back home without waiting the full 3 hours. --- NICE!

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  • Differences between "apache"'s installations

    - by JustTrying
    Are there any differences between installing Apache httpd using sudo apt-get install apache2 (as the guide of Ubuntu says - https://help.ubuntu.com/12.04/serverguide/httpd.html ) or following the steps on the Apache documentation (http://httpd.apache.org/docs/2.4/install.html#overview)? I tried both ways; in the first case (using apt-get) the server seems to work - I open a browser page and I got it. In the second case I need other packages (apr, apr-util and pcre) and so I abandoned the attempt.

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  • .net Interviews

    - by pdiddy
    When interviewing a .net candidate what do you look for? Let's say for a senior candidate. What kind of memorable interview have you experience, good or bad? This is going to be my first time I'll be the Interviewer. This is my second job and so I haven't got a lot of interview experience. Sure I can ask lots of .net technical questions, but what other questions can I ask and what can it bring by asking that question? Thanks,

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  • Python class representation under the hood

    - by decentralised
    OK, here is a simple Python class: class AddSomething(object): __metaclass__ = MyMetaClass x = 10 def __init__(self, a): self.a = a def add(self, a, b): return a + b We have specified a metaclass, and that means we could write something like this: class MyMetaClass(type): def __init__(cls, name, bases, cdict): # do something with the class Now, the cdict holds a representation of AddSomething: AddSomething = type('AddSomething', (object,), {'x' : 10, '__init__': __init__, 'add': add}) So my question is simple, are all Python classes represented in this second format internally? If not, how are they represented? EDIT - Python 2.7

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  • The First Annual Crappy Code Games

    - by Testas
    SQLBits announced some super-exciting news! A tie-up with our platinum sponsor, Fusion-io. Together we'll be running a series of events called "The Crappy Code Games" where SQL Server developers will compete to write the worst-performing code and win some very cool prizes including:   •        Gold: A hands-on, high performance flying day for two at Ultimate High plus Fusion-io flight jackets•        Silver: One day racing experience at Palmer Sports where you will drive seven different high performance cars•        Bronze: Pure Tech Racing 10 person package at PTR’s F1 racing facility includes FI tees, food and drinks. …plus iPods, Windows Mobile phones, X-box 360s, t-shirts and much more. There will be two qualifying events in Manchester on March 17th and London on March 31st, and the third qualifier as well as the grand finale will be held in the evening of Thursday April 7th at SQLBits. And if that isn’t cool enough, Fusion-io's Chief Scientist Steve Wozniak (yes, that Steve Wozniak, tech industry legend and co-founder of Apple) will be on hand in Brighton to hand out the prizes! If you'd like to take part you'll need to register, and since places are limited we recommend you do so right away. For more details and to register, go to http://www.crappycodegames.com/ The Games: In conjunction with SQL Bits, dbA-thletes (that’s you) will compete  head-to-head in one of three separate qualifying events to be held in Manchester, London and Brighton.  Four separate SQL  rounds make up the evening’s Games, and will challenge you to write code that pushes the boundaries of SQL performance.  The four events are: ?  The High Jump: Generate the highest I/O per second ?  The 100 m dash: Cumulative highest number of I/O’s in 60 seconds ?  The SSIS-athon: Load one billion row fact table in the shortest time ?  The Marathon: Generate the highest MB per second in 60 seconds

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  • Nyquist won't play audio

    - by erjiang
    I downloaded Nyquist, and am having trouble playing sounds from it. If I run it normally, I get: Nyquist -- A Language for Sound Synthesis and Composition Copyright (c) 1991,1992,1995 by Roger B. Dannenberg Version 2.29 > (play (osc 60)) Saving sound file to ./eric-temp.wav error: snd_save -- could not open audio output > If I wrap it by running padsp ny, the sound plays fine for about half a second, and then I get garbage fed to my speakers. Any solutions?

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  • Desktop Fun: Grasslands Wallpaper Collection Series 2

    - by Asian Angel
    This past year we shared a terrific collection of grasslands wallpapers with you and today we return with more of these wonderful ‘inland seas’ of waving grass. Travel these ‘land-based seas’ of green and gold on your desktop with the second in our series of Grasslands Wallpaper collections. 6 Ways Windows 8 Is More Secure Than Windows 7 HTG Explains: Why It’s Good That Your Computer’s RAM Is Full 10 Awesome Improvements For Desktop Users in Windows 8

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  • Array Multiplication and Division

    - by Narfanator
    I came across a question that (eventually) landed me wondering about array arithmetic. I'm thinking specifically in Ruby, but I think the concepts are language independent. So, addition and subtraction are defined, in Ruby, as such: [1,6,8,3,6] + [5,6,7] == [1,6,8,3,6,5,6,7] # All the elements of the first, then all the elements of the second [1,6,8,3,6] - [5,6,7] == [1,8,3] # From the first, remove anything found in the second and array * scalar is defined: [1,2,3] * 2 == [1,2,3,1,2,3] But What, conceptually, should the following be? None of these are (as far as I can find) defined: Array x Array: [1,2,3] * [1,2,3] #=> ? Array / Scalar: [1,2,3,4,5] / 2 #=> ? Array / Scalar: [1,2,3,4,5] % 2 #=> ? Array / Array: [1,2,3,4,5] / [1,2] #=> ? Array / Array: [1,2,3,4,5] % [1,2] #=> ? I've found some mathematical descriptions of these operations for set theory, but I couldn't really follow them, and sets don't have duplicates (arrays do). Edit: Note, I do not mean vector (matrix) arithmetic, which is completely defined. Edit2: If this is the wrong stack exchange, tell me which is the right one and I'll move it. Edit 3: Add mod operators to the list. Edit 4: I figure array / scalar is derivable from array * scalar: a * b = c => a = b / c [1,2,3] * 3 = [1,2,3]+[1,2,3]+[1,2,3] = [1,2,3,1,2,3,1,2,3] => [1,2,3] = [1,2,3,1,2,3,1,2,3] / 3 Which, given that programmer's division ignore the remained and has modulus: [1,2,3,4,5] / 2 = [[1,2], [3,4]] [1,2,3,4,5] % 2 = [5] Except that these are pretty clearly non-reversible operations (not that modulus ever is), which is non-ideal. Edit: I asked a question over on Math that led me to Multisets. I think maybe extensible arrays are "multisets", but I'm not sure yet.

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  • Applications: How to create a custom dialog box for Windows Mobile 6 (native)

    - by TechTwaddle
    Ashraf, on the MSDN forum, asks, “Is there a way to make a default choice for the messagebox that happens after a period of time if the user doesn't choose (Clicked ) Yes or No buttons.” To elaborate, the requirement is to show a message box to the user with certain options to select, and if the user does not respond within a predefined time limit (say 8 seconds) then the message box must dismiss itself and select a default option. Now such a functionality is not available with the MessageBox() api, you will have to write your own custom dialog box. Surely, creating a dialog box is quite a simple task using the DialogBox() api, and we have been creating full screen dialog boxes all the while. So how will this custom message box be any different? It’s not much different from a regular dialog box except for a few changes in its properties. First, it has a title bar but no buttons on the title bar (no ‘x’ or ‘ok’ button on the title bar), it doesn’t occupy full screen and it contains the controls that you put into it, thus justifying the title ‘custom’. So in this post we create a custom dialog box with two buttons, ‘Black’ and ‘White’. The user is given 8 seconds to select one of those colours, if the user doesn’t make a selection in 8 seconds, the default option ‘Black’ is selected. Before going into the implementation here is a video of how the dialog box works; Custom dialog box To start off, add a new dialog resource into your application, size it appropriately and add whatever controls you need to the dialog. In my case, I added two static text labels and two buttons, as below; Now we need to write up the window procedure for this dialog, here is the complete function; BOOL CALLBACK CustomDialogProc(HWND hDlg, UINT uMessage, WPARAM wParam, LPARAM lParam) {     int wmID, wmEvent;     PAINTSTRUCT ps;     HDC hdc;     static int timeCount = 0;     switch(uMessage)     {         case WM_INITDIALOG:             {                 SHINITDLGINFO shidi;                 memset(&shidi, 0, sizeof(shidi));                 shidi.dwMask = SHIDIM_FLAGS;                 //shidi.dwFlags = SHIDIF_DONEBUTTON | SHIDIF_SIPDOWN | SHIDIF_SIZEDLGFULLSCREEN | SHIDIF_EMPTYMENU;                 shidi.dwFlags = SHIDIF_SIPDOWN | SHIDIF_EMPTYMENU;                 shidi.hDlg = hDlg;                 SHInitDialog(&shidi);                 SHDoneButton(hDlg, SHDB_HIDE);                 timeCount = 0;                 SetWindowText(GetDlgItem(hDlg, IDC_STATIC_TIME_REMAINING), L"Time remaining: 8 second(s)");                 SetTimer(hDlg, MY_TIMER, 1000, NULL);             }             return TRUE;         case WM_COMMAND:             {                 wmID = LOWORD(wParam);                 wmEvent = HIWORD(wParam);                 switch(wmID)                 {                     case IDC_BUTTON_BLACK:                         KillTimer(hDlg, MY_TIMER);                         EndDialog(hDlg, IDC_BUTTON_BLACK);                         break;                     case IDC_BUTTON_WHITE:                         KillTimer(hDlg, MY_TIMER);                         EndDialog(hDlg, IDC_BUTTON_WHITE);                         break;                 }             }             break;         case WM_TIMER:             {                 if (wParam == MY_TIMER)                 {                     WCHAR wszText[128];                     memset(&wszText, 0, sizeof(wszText));                     timeCount++;                     //8 seconds are over, dismiss the dialog, select def value                     if (timeCount >= 8)                     {                         KillTimer(hDlg, MY_TIMER);                         EndDialog(hDlg, IDC_BUTTON_BLACK_DEF);                     }                     wsprintf(wszText, L"Time remaining: %d second(s)", 8-timeCount);                     SetWindowText(GetDlgItem(hDlg, IDC_STATIC_TIME_REMAINING), wszText);                     UpdateWindow(GetDlgItem(hDlg, IDC_STATIC_TIME_REMAINING));                 }             }             break;         case WM_PAINT:             {                 hdc = BeginPaint(hDlg, &ps);                 EndPaint(hDlg, &ps);             }             break;     }     return FALSE; } The MSDN documentation mentions that you need to specify the flag WS_NONAVDONEBUTTON, but I got an error saying that the value could not be found, so we can ignore this for now. Next up, while calling SHInitDialog() for your custom dialog, make sure that you don’t specify SHDIF_DONEBUTTON in the dwFlags member of the SHINITDIALOG structure, this member makes the ‘ok’ button appear on the dialog title bar. Finally, we need to call SHDoneButton() with SHDB_HIDE flag to, well, hide the Done button. The ‘Done’ button is the same as the ‘ok’ button, so this step might seem redundant, and the dialog works fine without calling SHDoneButton() too, but it’s better to stick with the documentation (; So you can see that we have followed all these steps above, under WM_INITDIALOG. We also setup a few things like a variable to keep track of the time, and setting off a one second timer. Every time the timer fires, we receive a WM_TIMER message. We then update the static label displaying the amount of time left to the user. If 8 seconds go by without the user selecting any option, we kill the timer and end the dialog with IDC_BUTTON_BLACK_DEF. This is just a #define’d integer value, make sure it’s unique. You’ll see why this is important. If the user makes a selection, either Black or White, we kill the timer and end the dialog with corresponding selection the user made, that is, either IDC_BUTTON_BLACK or IDC_BUTTON_WHITE. Ok, so now our custom dialog is ready to be used. I invoke the custom dialog from a menu entry in the main windows as below, case IDM_MENU_CUSTOMDLG:     {         int ret = DialogBox(g_hInst, MAKEINTRESOURCE(IDD_CUSTOM_DIALOG), hWnd, CustomDialogProc);         switch(ret)         {             case IDC_BUTTON_BLACK_DEF:                 SetWindowText(g_hStaticSelection, L"You Selected: Black (default)");                 break;             case IDC_BUTTON_BLACK:                 SetWindowText(g_hStaticSelection, L"You Selected: Black");                 break;             case IDC_BUTTON_WHITE:                 SetWindowText(g_hStaticSelection, L"You Selected: White");                 break;         }         UpdateWindow(g_hStaticSelection);     }     break; So you see why ending the dialog with the corresponding value was important, that’s what the DialogBox() api returns with. And in the main window I update a static text label to show which option was selected. I cranked this out in about an hour, and unfortunately don’t have time for a managed C# version. That will have to be another post, if I manage to get it working that is (;

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  • Desktop Fun: Starscapes Wallpaper Collection Series 2

    - by Asian Angel
    New worlds filled with alien ruins, covered in perpetual twilight, ripe with agricultural harvests, and more are waiting for intrepid explorers like you to explore them. Journey to the far ends of the cosmos and experience new wonders on your desktop with the second in our series of Starscapes Wallpaper collections. How to Factory Reset Your Android Phone or Tablet When It Won’t Boot Our Geek Trivia App for Windows 8 is Now Available Everywhere How To Boot Your Android Phone or Tablet Into Safe Mode

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  • More Fun With Math

    - by PointsToShare
    More Fun with Math   The runaway student – three different ways of solving one problem Here is a problem I read in a Russian site: A student is running away. He is moving at 1 mph. Pursuing him are a lion, a tiger and his math teacher. The lion is 40 miles behind and moving at 6 mph. The tiger is 28 miles behind and moving at 4 mph. His math teacher is 30 miles behind and moving at 5 mph. Who will catch him first? Analysis Obviously we have a set of three problems. They are all basically the same, but the details are different. The problems are of the same class. Here is a little excursion into computer science. One of the things we strive to do is to create solutions for classes of problems rather than individual problems. In your daily routine, you call it re-usability. Not all classes of problems have such solutions. If a class has a general (re-usable) solution, it is called computable. Otherwise it is unsolvable. Within unsolvable classes, we may still solve individual (some but not all) problems, albeit with different approaches to each. Luckily the vast majority of our daily problems are computable, and the 3 problems of our runaway student belong to a computable class. So, let’s solve for the catch-up time by the math teacher, after all she is the most frightening. She might even make the poor runaway solve this very problem – perish the thought! Method 1 – numerical analysis. At 30 miles and 5 mph, it’ll take her 6 hours to come to where the student was to begin with. But by then the student has advanced by 6 miles. 6 miles require 6/5 hours, but by then the student advanced by another 6/5 of a mile as well. And so on and so forth. So what are we to do? One way is to write code and iterate it until we have solved it. But this is an infinite process so we’ll end up with an infinite loop. So what to do? We’ll use the principles of numerical analysis. Any calculator – your computer included – has a limited number of digits. A double floating point number is good for about 14 digits. Nothing can be computed at a greater accuracy than that. This means that we will not iterate ad infinidum, but rather to the point where 2 consecutive iterations yield the same result. When we do financial computations, we don’t even have to go that far. We stop at the 10th of a penny.  It behooves us here to stop at a 10th of a second (100 milliseconds) and this will how we will avoid an infinite loop. Interestingly this alludes to the Zeno paradoxes of motion – in particular “Achilles and the Tortoise”. Zeno says exactly the same. To catch the tortoise, Achilles must always first come to where the tortoise was, but the tortoise keeps moving – hence Achilles will never catch the tortoise and our math teacher (or lion, or tiger) will never catch the student, or the policeman the thief. Here is my resolution to the paradox. The distance and time in each step are smaller and smaller, so the student will be caught. The only thing that is infinite is the iterative solution. The race is a convergent geometric process so the steps are diminishing, but each step in the solution takes the same amount of effort and time so with an infinite number of steps, we’ll spend an eternity solving it.  This BTW is an original thought that I have never seen before. But I digress. Let’s simply write the code to solve the problem. To make sure that it runs everywhere, I’ll do it in JavaScript. function LongCatchUpTime(D, PV, FV) // D is Distance; PV is Pursuers Velocity; FV is Fugitive’ Velocity {     var t = 0;     var T = 0;     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     t = d / pv;     while (t > 0.000001) //a 10th of a second is 1/36,000 of an hour, I used 1/100,000     {         T = T + t;         d = t * fv;         t = d / pv;     }     return T;     } By and large, the higher the Pursuer’s velocity relative to the fugitive, the faster the calculation. Solving this with the 10th of a second limit yields: 7.499999232000001 Method 2 – Geometric Series. Each step in the iteration above is smaller than the next. As you saw, we stopped iterating when the last step was small enough, small enough not to really matter.  When we have a sequence of numbers in which the ratio of each number to its predecessor is fixed we call the sequence geometric. When we are looking at the sum of sequence, we call the sequence of sums series.  Now let’s look at our student and teacher. The teacher runs 5 times faster than the student, so with each iteration the distance between them shrinks to a fifth of what it was before. This is a fixed ratio so we deal with a geometric series.  We normally designate this ratio as q and when q is less than 1 (0 < q < 1) the sum of  + … +  is  – 1) / (q – 1). When q is less than 1, it is easier to use ) / (1 - q). Now, the steps are 6 hours then 6/5 hours then 6/5*5 and so on, so q = 1/5. And the whole series is multiplied by 6. Also because q is less than 1 , 1/  diminishes to 0. So the sum is just  / (1 - q). or 1/ (1 – 1/5) = 1 / (4/5) = 5/4. This times 6 yields 7.5 hours. We can now continue with some algebra and take it back to a simpler formula. This is arduous and I am not going to do it here. Instead let’s do some simpler algebra. Method 3 – Simple Algebra. If the time to capture the fugitive is T and the fugitive travels at 1 mph, then by the time the pursuer catches him he travelled additional T miles. Time is distance divided by speed, so…. (D + T)/V = T  thus D + T = VT  and D = VT – T = (V – 1)T  and T = D/(V – 1) This “strangely” coincides with the solution we just got from the geometric sequence. This is simpler ad faster. Here is the corresponding code. function ShortCatchUpTime(D, PV, FV) {     var d = parseFloat(D);     var pv = parseFloat (PV);     var fv = parseFloat (FV);     return d / (pv - fv); } The code above, for both the iterative solution and the algebraic solution are actually for a larger class of problems.  In our original problem the student’s velocity (speed) is 1 mph. In the code it may be anything as long as it is less than the pursuer’s velocity. As long as PV > FV, the pursuer will catch up. Here is the really general formula: T = D / (PV – FV) Finally, let’s run the program for each of the pursuers.  It could not be worse. I know he’d rather be eaten alive than suffering through yet another math lesson. See the code run? Select  “Catch Up Time” in www.mgsltns.com/games.htm The host is running on Unix, so the link is case sensitive. That’s All Folks

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  • Binary on the Coat of Arms of the Governor General of Canada

    - by user132636
    Can you help me further this investigation? Here is about 10% of the work I have done on it. I present it only to see if there are any truly curious people among you. I made a video a few weeks ago showing some strange things about the Governor General's Coat of Arms and the binary on it. Today, I noticed something kinda cool and thought I would share. Here is the binary as it appears on the COA: 110010111001001010100100111010011 As DEC: 6830770643 (this is easily found on the web) Take a close look at that number. What do you notice about it? It has a few interesting features, but here is the one no one has pointed out... Split it down the middle and you have 68307 70643. The first digit is double the value of the last digit. The second digit is double the second last digit. The third digit is half of the third to last digit. And the middle ones are even or neutral. At first, I thought of it as energy. ++-nnnn+-- But actually you can create something else with it using the values. 221000211. See how that works. You may be asking why that is significant. Bare with me. I know 99% are rolling their eyes. 221000211 as base3 gives you this as binary: 100011101000111 100011101000111 as HEX is 4747, which converts to "GG". Initials of Governor General. GG.ca is his website. When you convert to base 33 (there are 33 digits in the original code) you get "GOV" Interesting? :D There is a lot more to it. I'll continue to show some strange coincidences if anyone is interested. Sorry if I am not explaining this correctly. By now you have probably figured out that I have no background in this. Which is why I am here. Thank you.

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  • Juju MySQL adding units vs adding new service with relation

    - by user2291975
    What's the point of adding units to MySQL? Why not just create a new service with relation to the master node? MySQL doesn't support multi-master node so adding units to one MySQL service doesn't make any sense. If I create a second service as a slave and add units to that to act as multiple slaves still doesn't make sense because if the primary slave server dies all the unites attached to it become useless as well. Can anyone explain why I should add units to MySQL?

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  • Overwrite previous output in Bash instead of appending it

    - by NES
    For a bash timer i use this code: #!/bin/bash sek=60 echo "60 Seconds Wait!" echo -n "One Moment please " while [ $sek -ge 1 ] do echo -n "$sek " sleep 1 sek=$[$sek-1] done echo echo "ready!" That gives me something like that One Moment please: 60 59 58 57 56 55 ... Is there a possibility to replace the last value of second by the most recent so that the output doesn't generate a large trail but the seconds countdown like a real time at one position? (Hope you understand what i mean :))

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  • AJAX event, prevents other page actions

    - by cobaltduck
    Here's a fairly average scenario, using JSF as an example, but this same concept I have observed in ASP.NET, Apache Wicket, and other frameworks with ajax capabilities. <h:inputText id="text1" value="#{myBacker.myBean.myStringVar}" styleClass="goodCSS"> <f:ajax event="change" listener="#{myBacker.text1ChangeEventMethod}" update="someOtherField" /> </h:inputText> <h:selectBooleanCheckbox id="check1" value="#{myBacker.myBean.myBoolVar}" /> Let's suppose that the 'text1ChangeEventListener' is essential to 'someOtherField' and perhaps toggles its disabled attribute, or changes its available options, based on the value of 'myStringVar.' The particulars aren't important, let's just accept that for some reason we need an ajax call when the 'text1' value is changed. So Jane User is working her way down the form. She arrives at the 'text1' field and types some value. The cursor focus is still in the text field, as she moves her mouse to the 'check1' box and clicks. It appears to her that nothing has happened. She clicks again, and this time the checkbox highlights and the icon indicating a selection appears in the box. Jane has to do several entries in the form today, and sees this happen every time, and it becomes very frustrating for her. Likewise, Jeff Admin is also perusing this form, and begins to type in 'text1.' He then realizes he doesn't really want to enter this data, and so moves his mouse to the "cancel" button elsewhere on the page, and clicks. Nothing seems to happen. Jeff clicks again, and after confirming he really does want to cancel, is returned to the home page. Jeff scratches his head. The problem is simply that the first thing the system does after 'text1' looses focus is run the listener and perform the ajax operation. It may only take a fraction of a second, but still, you can click other buttons all you want, but until that ajax has finished, everything else is ignored. I've spent the morning searching and reading, and it seems no one else has even noticed this. I could find not one article, blog, past question here or at SO, or anyting that addresses this obvious and glaring deficiency in ajax. So first of all, am I truly alone in thinking this is a big problem? Second, does anyone have a solution?

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  • Desktop Fun: Cloud Chaser Wallpaper Collection Series 2

    - by Asian Angel
    Last year we shared a wonderful collection of cloud wallpapers with you and today we are back with more cloudy goodness. Float away with the clouds on your desktop with the second in our series of Cloud Chaser Wallpaper collections. 8 Deadly Commands You Should Never Run on Linux 14 Special Google Searches That Show Instant Answers How To Create a Customized Windows 7 Installation Disc With Integrated Updates

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  • System cant mount root

    - by Tony Parkes
    Im running ubuntu 12.10, i have installed NETKIT as i need it for my university work. It is installed fine and the NETKIT configuration is ok when checked but when i try to launch a virtual machine it appears on screen for about half a second and then vanishes. I did a verbose launch and im told that the system cant mount root, i can however launch an xterm...any help would be greatly appreciated. Tony

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  • Desktop Fun: Auroras Wallpaper Collection Series 2

    - by Asian Angel
    Auroras are truly a one of a kind visual experience that can leave you breathless and filled with wonder. Turn your desktop into a phenomenal display of color and light with the second in our series of Auroras Wallpaper collections. HTG Explains: What is the Windows Page File and Should You Disable It? How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems

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  • The SSIS tuning tip that everyone misses

    - by Rob Farley
    I know that everyone misses this, because I’m yet to find someone who doesn’t have a bit of an epiphany when I describe this. When tuning Data Flows in SQL Server Integration Services, people see the Data Flow as moving from the Source to the Destination, passing through a number of transformations. What people don’t consider is the Source, getting the data out of a database. Remember, the source of data for your Data Flow is not your Source Component. It’s wherever the data is, within your database, probably on a disk somewhere. You need to tune your query to optimise it for SSIS, and this is what most people fail to do. I’m not suggesting that people don’t tune their queries – there’s plenty of information out there about making sure that your queries run as fast as possible. But for SSIS, it’s not about how fast your query runs. Let me say that again, but in bolder text: The speed of an SSIS Source is not about how fast your query runs. If your query is used in a Source component for SSIS, the thing that matters is how fast it starts returning data. In particular, those first 10,000 rows to populate that first buffer, ready to pass down the rest of the transformations on its way to the Destination. Let’s look at a very simple query as an example, using the AdventureWorks database: We’re picking the different Weight values out of the Product table, and it’s doing this by scanning the table and doing a Sort. It’s a Distinct Sort, which means that the duplicates are discarded. It'll be no surprise to see that the data produced is sorted. Obvious, I know, but I'm making a comparison to what I'll do later. Before I explain the problem here, let me jump back into the SSIS world... If you’ve investigated how to tune an SSIS flow, then you’ll know that some SSIS Data Flow Transformations are known to be Blocking, some are Partially Blocking, and some are simply Row transformations. Take the SSIS Sort transformation, for example. I’m using a larger data set for this, because my small list of Weights won’t demonstrate it well enough. Seven buffers of data came out of the source, but none of them could be pushed past the Sort operator, just in case the last buffer contained the data that would be sorted into the first buffer. This is a blocking operation. Back in the land of T-SQL, we consider our Distinct Sort operator. It’s also blocking. It won’t let data through until it’s seen all of it. If you weren’t okay with blocking operations in SSIS, why would you be happy with them in an execution plan? The source of your data is not your OLE DB Source. Remember this. The source of your data is the NCIX/CIX/Heap from which it’s being pulled. Picture it like this... the data flowing from the Clustered Index, through the Distinct Sort operator, into the SELECT operator, where a series of SSIS Buffers are populated, flowing (as they get full) down through the SSIS transformations. Alright, I know that I’m taking some liberties here, because the two queries aren’t the same, but consider the visual. The data is flowing from your disk and through your execution plan before it reaches SSIS, so you could easily find that a blocking operation in your plan is just as painful as a blocking operation in your SSIS Data Flow. Luckily, T-SQL gives us a brilliant query hint to help avoid this. OPTION (FAST 10000) This hint means that it will choose a query which will optimise for the first 10,000 rows – the default SSIS buffer size. And the effect can be quite significant. First let’s consider a simple example, then we’ll look at a larger one. Consider our weights. We don’t have 10,000, so I’m going to use OPTION (FAST 1) instead. You’ll notice that the query is more expensive, using a Flow Distinct operator instead of the Distinct Sort. This operator is consuming 84% of the query, instead of the 59% we saw from the Distinct Sort. But the first row could be returned quicker – a Flow Distinct operator is non-blocking. The data here isn’t sorted, of course. It’s in the same order that it came out of the index, just with duplicates removed. As soon as a Flow Distinct sees a value that it hasn’t come across before, it pushes it out to the operator on its left. It still has to maintain the list of what it’s seen so far, but by handling it one row at a time, it can push rows through quicker. Overall, it’s a lot more work than the Distinct Sort, but if the priority is the first few rows, then perhaps that’s exactly what we want. The Query Optimizer seems to do this by optimising the query as if there were only one row coming through: This 1 row estimation is caused by the Query Optimizer imagining the SELECT operation saying “Give me one row” first, and this message being passed all the way along. The request might not make it all the way back to the source, but in my simple example, it does. I hope this simple example has helped you understand the significance of the blocking operator. Now I’m going to show you an example on a much larger data set. This data was fetching about 780,000 rows, and these are the Estimated Plans. The data needed to be Sorted, to support further SSIS operations that needed that. First, without the hint. ...and now with OPTION (FAST 10000): A very different plan, I’m sure you’ll agree. In case you’re curious, those arrows in the top one are 780,000 rows in size. In the second, they’re estimated to be 10,000, although the Actual figures end up being 780,000. The top one definitely runs faster. It finished several times faster than the second one. With the amount of data being considered, these numbers were in minutes. Look at the second one – it’s doing Nested Loops, across 780,000 rows! That’s not generally recommended at all. That’s “Go and make yourself a coffee” time. In this case, it was about six or seven minutes. The faster one finished in about a minute. But in SSIS-land, things are different. The particular data flow that was consuming this data was significant. It was being pumped into a Script Component to process each row based on previous rows, creating about a dozen different flows. The data flow would take roughly ten minutes to run – ten minutes from when the data first appeared. The query that completes faster – chosen by the Query Optimizer with no hints, based on accurate statistics (rather than pretending the numbers are smaller) – would take a minute to start getting the data into SSIS, at which point the ten-minute flow would start, taking eleven minutes to complete. The query that took longer – chosen by the Query Optimizer pretending it only wanted the first 10,000 rows – would take only ten seconds to fill the first buffer. Despite the fact that it might have taken the database another six or seven minutes to get the data out, SSIS didn’t care. Every time it wanted the next buffer of data, it was already available, and the whole process finished in about ten minutes and ten seconds. When debugging SSIS, you run the package, and sit there waiting to see the Debug information start appearing. You look for the numbers on the data flow, and seeing operators going Yellow and Green. Without the hint, I’d sit there for a minute. With the hint, just ten seconds. You can imagine which one I preferred. By adding this hint, it felt like a magic wand had been waved across the query, to make it run several times faster. It wasn’t the case at all – but it felt like it to SSIS.

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