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• Comparing a time delta in python

  - by Alpesh Patel

  I have a variable which is <type 'datetime.timedelta'> and I would like to compare it against certain values. Lets say d produces this datetime.timedelta value 0:00:01.782000 I would like to compare it like this: #if d is greater than 1 minute if d>1:00: print "elapsed time is greater than 1 minute" I have tried converting datetime.timedelta.strptime() but that does seem to work. Is there an easier way to compare this value?

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• Flatten (an irregular) list of lists in Python

  - by telliott99

  Yes, I know this subject has been covered before (here, here, here, here), but AFAIK, all solutions save one choke on a list like this: L = [[[1, 2, 3], [4, 5]], 6] where the desired output is [1, 2, 3, 4, 5, 6] or perhaps even better, an iterator. The only solution I saw that works for an arbitrary nesting is from @Alabaster Codify here: def flatten(x): result = [] for el in x: if hasattr(el, "__iter__") and not isinstance(el, basestring): result.extend(flatten(el)) else: result.append(el) return result flatten(L) So to my question: is this the best model? Did I overlook something? Any problems?

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• python regex of a date in some text, enclosed by two keywords

  - by Horace Ho

  This is Part 2 of this question and thanks very much for David's answer. What if I need to extract dates which are bounded by two keywords? Example: text = "One 09 Jun 2011 Two 10 Dec 2012 Three 15 Jan 2015 End" Case 1 bounding keyboards: "One" and "Three" Result expected: ['09 Jun 2011', '10 Dec 2012'] Case 2 bounding keyboards: "Two" and "End" Result expected: ['10 Dec 2012', '15 Jan 2015'] Thanks!

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• Types in Python - Google Appengine

  - by Chris M

  Getting a bit peeved now; I have a model and a class thats just storing a get request in the database; basic tracking. class SearchRec(db.Model): WebSite = db.StringProperty()#required=True WebPage = db.StringProperty() CountryNM = db.StringProperty() PrefMailing = db.BooleanProperty() DateStamp = db.DateTimeProperty(auto_now_add=True) IP = db.StringProperty() class AddSearch(webapp.RequestHandler): def get(self): searchRec = SearchRec() searchRec.WebSite = self.request.get('WEBSITE') searchRec.WebPage = self.request.get('WEBPAGE') searchRec.CountryNM = self.request.get('COUNTRY') searchRec.PrefMailing = bool(self.request.get('MAIL')) searchRec.IP = self.request.get('IP') Bool has my biscuit; I thought that setting bool(self.reque....) would set the type of the string but no matter what I pass it it still stores it as TRUE in the database. I had the same issue with using required=True on strings for the model; the damn thing kept saying that nothing was being passed... but it had. Ta

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• logical operators evaluation in return statemnet in python

  - by table

  hi, how does this execute: **def f(x): return x0 and (x%2)+f(x/2) or 0** x is an array ,for instanse,[1, 1, 1, 3] thank u

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• Read a file on App Eninge with Python?

  - by PanosJee

  Is it possible to open a file on GAE just to read its contents and get the last modified tag? I get a IOError: [Errno 13] file not accessible: I know that i cannot delete or update but i believe reading should be possible Has anyone faced a similar problem? os.stat(f,'r').st_mtim

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• intersection of three sets in python?

  - by Phil Brown

  Currently I am stuck trying to find the intersection of three sets. Now these sets are really lists that I am converting into sets, and then trying to find the intersection of. Here's what I have so far: for list1 in masterlist: list1=thingList1 for list2 in masterlist: list2=thingList2 for list3 in masterlist: list3=thingList3 d3=[set(thingList1), set(thingList2), set(thingList3)] setmatches c= set.intersection(*map(set,d3)) print setmatches and I'm getting set([]) Script terminated. I know there's a much simpler and better way to do this, but I can't find one...

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• Drawing a Dragons curve in Python

  - by Connor Franzoni

  I am trying to work out how to draw the dragons curve, with pythons turtle using the An L-System or Lindenmayer system. I no the code is something like the Dragon curve; initial state = ‘F’, replacement rule – replace ‘F’ with ‘F+F-F’, number of replacements = 8, length = 5, angle = 60 But have no idea how to put that into code.

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• Python Script to backup a directory

  - by rgolwalkar

  Filename:backup_ver1 import os import time 1 Using list to specify the files and directory to be backed up source = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\Dr Py\Final_Py' 2 define backup directory destination = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\PyDevResourse' 3 Setting the backup name targetBackup = destination + time.strftime('%Y%m%d%H%M%S') + '.rar' rar_command = "rar.exe a -ag '%s' %s" % (targetBackup, ''.join(source)) i am sure i am doing something wrong here - rar command please let me know if os.system(rar_command) == 0: print 'Successful backup to', targetBackup else: print 'Backup FAILED' O/P:- Backup FAILED winrar is added to Path and CLASSPATH under Environment variables as well - anyone else with a suggestion for backing up the directory is most welcome

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• python to display the special characters

  - by Suhail

  Hi, I am facing issues with the special characters like ° and ® which represent the degreee Farenheit sign and the ® represent the registered sign, when i print the string the contains the special characters, it gives output like this: Preheat oven to 350&deg F Welcome to Lorem Ipsum Inc&reg is there a way i can output the exact characters and not their codes ? please let me know.

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• Python: list and string matching

  - by pete

  Hi All, I have following: temp = "aaaab123xyz@+" lists = ["abc", "123.35", "xyz", "AND+"] for list in lists if re.match(list, temp, re.I): print "The %s is within %s." % (list,temp) The re.match is only match the beginning of the string, How to I match substring in between too.

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• Python - List of Lists Slicing Behavior

  - by Dan Dobint

  When I define a list and try to change a single item like this: list_of_lists = [['a', 'a', 'a'], ['a', 'a', 'a'], ['a', 'a', 'a']] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It works as intended. But when I try to use list comprehension to create the list: row = ['a' for range in xrange(3)] list_of_lists = [row for range in xrange(3)] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It results in an entire column of items in the list being changed. Why is this? How can I achieve the desired effect with list comprehension?

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• Add entry to list and remove first one in Python

  - by wagglewax

  I have a list of about 40 entries. And I frequently want to append an item to the start of the list (with id 0) and want to delete the last entry (with id 40) of the list. how do i do this the best? like: (example with 5 entries) [0] = "herp" [1] = "derp" [2] = "blah" [3] = "what" [4] = "da..." after adding "wuggah" and deleting last it should be like: [0] = "wuggah" [1] = "herp" [2] = "derp" [3] = "blah" [4] = "what" or appending one and deleting first. And I don't want to end up manually moving them one after another all of the entries to the next id.

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• Python Numpy Structured Array (recarray) assigning values into slices

  - by user368877

  Hi, The following example shows what I want to do: >>> test rec.array([(0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0)], dtype=[('ifAction', '|i1'), ('ifDocu', '|i1'), ('ifComedy', '|i1')]) >>> test[['ifAction', 'ifDocu']][0] (0, 0) >>> test[['ifAction', 'ifDocu']][0] = (1,1) >>> test[['ifAction', 'ifDocu']][0] (0, 0) So, I want to assign the values (1,1) to test[['ifAction', 'ifDocu']][0]. (Eventually, I want to do something like test[['ifAction', 'ifDocu']][0:10] = (1,1), assigning the same values for for 0:10. I have tried many ways but never succeeded. Is there any way to do this? Thank you, Joon

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• how to create a dynamic sql statement w/ python and mysqldb

  - by Elias Bachaalany

  I have the following code: def sql_exec(self, sql_stmt, args = tuple()): """ Executes an SQL statement and returns a cursor. An SQL exception might be raised on error @return: SQL cursor object """ cursor = self.conn.cursor() if self.__debug_sql: try: print "sql_exec: " % (sql_stmt % args) except: print "sql_exec: " % sql_stmt cursor.execute(sql_stmt, args) return cursor def test(self, limit = 0): result = sql_exec(""" SELECT * FROM table """ + ("LIMIT %s" if limit else ""), (limit, )) while True: row = result.fetchone() if not row: break print row result.close() How can I nicely write test() so it works with or without 'limit' without having to write two queries?

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• Python re.IGNORECASE being dynamic

  - by Adam Nelson

  I'd like to do something like this: re.findall(r"(?:(?:\A|\W)" + 'Hello' + r"(?:\Z|\W))", 'hello world',re.I) And have re.I be dynamic, so I can do case-sensitive or insensitive comparisons on the fly. This works but is undocumented: re.findall(r"(?:(?:\A|\W)" + 'Hello' + r"(?:\Z|\W))", 'hello world',1) To set it to sensitive. Is there a Pythonic way to do this? My best thought so far is: if case_sensitive: regex_senstive = 1 else: regex_sensitive = re.I re.findall(r"(?:(?:\A|\W)" + 'Hello' + r"(?:\Z|\W))", 'hello world',regex_sensitive)

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• python lxml problem

  - by David ???

  I'm trying to print/save a certain element's HTML from a web-page. I've retrieved the requested element's XPath from firebug. All I wish is to save this element to a file. I don't seem to succeed in doing so. (tried the XPath with and without a /text() at the end) I would appreciate any help, or past experience. 10x, David import urllib2,StringIO from lxml import etree url='http://www.tutiempo.net/en/Climate/Londres_Heathrow_Airport/12-2009/37720.htm' seite = urllib2.urlopen(url) html = seite.read() seite.close() parser = etree.HTMLParser() tree = etree.parse(StringIO.StringIO(html), parser) xpath = "/html/body/table/tbody/tr/td[2]/div/table/tbody/tr[6]/td/table/tbody/tr/td[3]/table/tbody/tr[3]/td/table/tbody/tr/td/table/tbody/tr/td/table/tbody/text()" elem = tree.xpath(xpath) print elem[0].strip().encode("utf-8")

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• How to substitute into a regular expression group in Python

  - by peter

  >>> s = 'foo: "apples", bar: "oranges"' >>> pattern = 'foo: "(.*)"' I want to be able to substitute into the group like this: >>> re.sub(pattern, 'pears', s, group=1) 'foo: "pears", bar: "oranges"' Is there a nice way to do this?

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• Python dictionary to variable assignments based on key value to variable name

  - by Art

  Basically, I want to take a Dictionary like { "a":"bar", "b":"blah", "c":"abc", "d":"nada" } and use it to set variables (in an Object) which have the same name as a key in the dictionary. class Foo(Object) { self.a = "" self.b = "" self.c = "" } So in the the end self.a = "bar", self.b = "blah", etc... (and key "d" is ignored) Any ideas?

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• Python/PyParsing: Difficulty with setResultsName

  - by Rosarch

  I think I'm making a mistake in how I call setResultsName(): from pyparsing import * DEPT_CODE = Regex(r'[A-Z]{2,}').setResultsName("Dept Code") COURSE_NUMBER = Regex(r'[0-9]{4}').setResultsName("Course Number") COURSE_NUMBER.setParseAction(lambda s, l, toks : int(toks[0])) course = DEPT_CODE + COURSE_NUMBER course.setResultsName("course") statement = course From IDLE: >>> myparser import * >>> statement.parseString("CS 2110") (['CS', 2110], {'Dept Code': [('CS', 0)], 'Course Number': [(2110, 1)]}) The output I hope for: >>> myparser import * >>> statement.parseString("CS 2110") (['CS', 2110], {'Course': ['CS', 2110], 'Dept Code': [('CS', 0)], 'Course Number': [(2110, 1)]}) Does setResultsName() only work for terminals?

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• Python: Traffic-Simulation (cars on a road)

  - by kame

  Hello! I want to create a traffic simulator like here: http://www.doobybrain.com/wp-content/uploads/2008/03/traffic-simulation.gif But I didn't thougt very deep about this. I would create the class car. Every car has his own color, position and so on. And I could create the road with an array. But how to tell the car where to go? Could I hear your ideas? EDIT: Is it forbidden to get new ideas from good programmers? Why do some people want to close this thread? Or were to ask such questions? I dont understand them. :(

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• Exit Tks mainloop in Python?

  - by Olof

  I'm writing a slideshow program with Tkinter, but I don't know how to go to the next image without binding a key. import os, sys import Tkinter import Image, ImageTk import time root = Tkinter.Tk() w, h = root.winfo_screenwidth(), root.winfo_screenheight() root.overrideredirect(1) root.geometry("%dx%d+0+0" % (w, h)) root.focus_set() root.bind("<Escape>", lambda e: e.widget.quit()) image_path = os.path.join(os.getcwd(), 'images/') dirlist = os.listdir(image_path) for f in dirlist: try: image = Image.open(image_path+f) tkpi = ImageTk.PhotoImage(image) label_image = Tkinter.Label(root, image=tkpi) # ? label_image.place(x=0,y=0,width=w,height=h) root.mainloop(0) except IOError: pass root.destroy() I would like to add a time.sleep(10) "instead" of the root.mainloop(0) so that it would go to the next image after 10s. Now it changes when I press ESC. How can I have a timer there?

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• Python: override __init__ args in __new__

  - by EoghanM

  I have a __new__ method as follows: class MyClass(object): def __new__(cls, *args): new_args = [] args.sort() prev = args.pop(0) while args: next = args.pop(0) if prev.compare(next): prev = prev.combine(next) else: new_args.append(prev) prev = next if some_check(prev): return SomeOtherClass() new_args.append(prev) return super(MyClass, cls).__new__(cls, new_args) def __init__(self, *args): ... However, this fails with a deprecation warning: DeprecationWarning: object.__new__() takes no parameters SomeOtherClass can optionally get created as the args are processed, that's why they are being processed in __new__ and not in __init__ What is the best way to pass new_args to __init__? Otherwise, I'll have to duplicate the processing of args in __init__ (without some_check)

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• Algorithm detect repeating/similiar strings in a corpus of data -- say email subjects, in Python

  - by RizwanK

  I'm downloading a long list of my email subject lines , with the intent of finding email lists that I was a member of years ago, and would want to purge them from my Gmail account (which is getting pretty slow.) I'm specifically thinking of newsletters that often come from the same address, and repeat the product/service/group's name in the subject. I'm aware that I could search/sort by the common occurrence of items from a particular email address (and I intend to), but I'd like to correlate that data with repeating subject lines.... Now, many subject lines would fail a string match, but "Google Friends : Our latest news" "Google Friends : What we're doing today" are more similar to each other than a random subject line, as is: "Virgin Airlines has a great sale today" "Take a flight with Virgin Airlines" So -- how can I start to automagically extract trends/examples of strings that may be more similar. Approaches I've considered and discarded ('because there must be some better way'): Extracting all the possible substrings and ordering them by how often they show up, and manually selecting relevant ones Stripping off the first word or two and then count the occurrence of each sub string Comparing Levenshtein distance between entries Some sort of string similarity index ... Most of these were rejected for massive inefficiency or likelyhood of a vast amount of manual intervention required. I guess I need some sort of fuzzy string matching..? In the end, I can think of kludgy ways of doing this, but I'm looking for something more generic so I've added to my set of tools rather than special casing for this data set. After this, I'd be matching the occurring of particular subject strings with 'From' addresses - I'm not sure if there's a good way of building a data structure that represents how likely/not two messages are part of the 'same email list' or by filtering all my email subjects/from addresses into pools of likely 'related' emails and not -- but that's a problem to solve after this one. Any guidance would be appreciated.

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• Python: finding lowest integer

  - by sarah

  I have the following code: l = ['-1.2', '0.0', '1'] x = 100.0 for i in l: if i < x: x = i print x The code should find the lowest value in my list (-1.2) but instead when i print 'x' it finds the value is still 100.0 Where is my code going wrong?

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