Search Results

Search found 895 results on 36 pages for 'scatter plot'.

Page 15/36 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

• Control the size of points in an R scatterplot?

  - by Nick

  In R, the plot() function takes a pch argument that controls the appearance of the points in the plot. I'm making scatterplots with tens of thousands of points and prefer a small, but not too small dot. Basically, I find pch='.' to be too small, but pch=19 to be too fat. Is there something in the middle or some way to scale the dots down somehow?

  Read the article

• Gnuplot - splot matrix csv data

  - by Jakub Czaplicki

  How can I plot (a 3D plot) a matrix in Gnuplot having such data structure. I cannot find a way to use the first row and column as a x and y ticks (or to ignore them) ,5,6,7,8 1,-6.20,-6.35,-6.59,-6.02 2,-6.39,-6.52,-6.31,-6.00 3,-6.36,-6.48,-6.15,-5.90 4,-5.79,-5.91,-5.87,-5.46 Is the splot 'data.csv' matrix the correct parameter to use ?

  Read the article

• Combining graphs in Mathematica

  - by pizziaolo

  Any idea how I can overlay the following two functions to compare them? ln[1]:= p1 = Plot[(E^((Pi/6)^(1/3)/x) (Pi/6)^(2/3))/((-1 + E^((Pi/6)^(1/3)/x))^2 x^2), {x, -2.2, 2.2}] ln[2]:= p2 = Plot[(E^((Pi/6)^(1/3)/t) (Pi/6)^(2/3))/((-1 + E^((Pi/6)^(1/3)/t))^2 t^2), {t, 0, 2.0}] When I try Show[p1,p2] it doesn't work

  Read the article

• Plotting Bessel function in MatLab

  - by 4alala

  In MatLab how do you plot f(r) = { 2*J1(a*r) / r }^2 where a = 2*pi and J1 is Bessel function of the 1st kind and r = sqrt(x^2 + y^2) This should plot in 3D, i.e. kind of be like a bubble (not sure how to do this)

  Read the article

• How do I set selection to Nothing when programming Excel using VBA?

  - by Curt

  When I create a graph after using range.copy and range.paste it leaves the paste range selected, and then when I create a graph a few lines later, it uses the selection as the first series in the plot. I can delete the series, but is there a more elegant way to do this? I tried Set selection = nothing but it won't let me set selection. I also tried selection.clear, but that just cleared the last cells that were selected, and still added an extra series to the plot. Curt

  Read the article

• MATLAB clear current figure

  - by rlbond

  I want to clear MATLAB's global CurrentFigure property, because I need a plot that I make to not be overwritten if a careless user uses plot without opening a new figure. I tried set(0, 'CurrentFigure', []); But it doesn't seem to work. Is this impossible?

  Read the article

• Python: Set window focus on terminal

  - by janoliver

  Hey, I have a python application that opens some plots for me and then asks the user for input. The problem is, that after opening the plot, the focus isn't on the terminal anymore, so you have to click or tab to it manually. I would like to set the focus to the terminal window with python - is that possible? I'm using gnuplot.py, maybe there is an option to open the plot in the background? Thanks!

  Read the article

• plotting stem with a continuous line

  - by Abruzzo Forte e Gentile

  Hi All I need to plot a stem plot of my signal using python and matplotlib. I saw the example and the code but the line connecting the black big dot and the x-axis is not a continous line. Do you know whether is possible and how to get a straight line instead? Thank you very much AFG #!/usr/bin/env python from pylab import * x = linspace(0.1, 2*pi, 10) markerline, stemlines, baseline = stem(x, cos(x), '-.') setp(markerline, 'markerfacecolor', 'b') setp(baseline, 'color','r', 'linewidth', 2) show()

  Read the article

• What does the symbol ::: mean in R

  - by Milktrader

  I came across this in the following context from B. Pfaff's "Analysis of Integrated and Cointegrated Time Series in R" ## Impulse response analysis of SVAR A-type model 1 args (vars ::: irf.svarest) 2 irf.svara <- irf (svar.A, impulse = ”y1 ” , 3 response = ”y2 ” , boot = FALSE) 4 args (vars ::: plot.varirf) 5 plot (irf.svara)

  Read the article

• Plotting horizontal and vertical lines in Mathematica

  - by karlsbad

  In Mathematica, how do you plot a horizontal line at a given number? How do you plot a vertical line at a given number?

  Read the article

• How to use an excel data-set for a multi-line ggplot in R?

  - by user1299887

  I have a data set in excel that I am trying to create a multiple line plot with on R. The data set contains 7 food groups and the calories consumed daily associated to the groups. As well, there is that set of data over 38 years (from 1970-2008) and I am attempting to use this data set to create a multiple line plot on R. I have tried for hours on end but can not seem to get R to recognize the variables within the data set.

  Read the article

• Using the MSChart ActiveX Control with VB.NET

  The MSChart control is an ActiveX control that lets you to add charting capabilities to your applications. We can create 2D or 3D charts in different styles. It will support almost all type of chart like Line Chart, Bar Chart, Pie Chart, Step, Combination, XY (Scatter) etc  read moreBy Anoop SDid you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

  Read the article

• Drawing random smooth lines contained in a square [migrated]

  - by Doug Mercer

  I'm trying to write a matlab function that creates random, smooth trajectories in a square of finite side length. Here is my current attempt at such a procedure: function [] = drawroutes( SideLength, v, t) %DRAWROUTES Summary of this function goes here % Detailed explanation goes here %Some parameters intended to help help keep the particles in the box RandAccel=.01; ConservAccel=0; speedlimit=.1; G=10^(-8); % %Initialize Matrices Ax=zeros(v,10*t); Ay=Ax; vx=Ax; vy=Ax; x=Ax; y=Ax; sx=zeros(v,1); sy=zeros(v,1); % %Define initial position in square x(:,1)=SideLength*.15*ones(v,1)+(SideLength*.7)*rand(v,1); y(:,1)=SideLength*.15*ones(v,1)+(SideLength*.7)*rand(v,1); % for i=2:10*t %Measure minimum particle distance component wise from boundary %for each vehicle BorderGravX=[abs(SideLength*ones(v,1)-x(:,i-1)),abs(x(:,i-1))]'; BorderGravY=[abs(SideLength*ones(v,1)-y(:,i-1)),abs(y(:,i-1))]'; rx=min(BorderGravX)'; ry=min(BorderGravY)'; % %Set the sign of the repulsive force for k=1:v if x(k,i)<.5*SideLength sx(k)=1; else sx(k)=-1; end if y(k,i)<.5*SideLength sy(k)=1; else sy(k)=-1; end end % %Calculate Acceleration w/ random "nudge" and repulive force Ax(:,i)=ConservAccel*Ax(:,i-1)+RandAccel*(rand(v,1)-.5*ones(v,1))+sx*G./rx.^2; Ay(:,i)=ConservAccel*Ay(:,i-1)+RandAccel*(rand(v,1)-.5*ones(v,1))+sy*G./ry.^2; % %Ad hoc method of trying to slow down particles from jumping outside of %feasible region for h=1:v if abs(vx(h,i-1)+Ax(h,i))<speedlimit vx(h,i)=vx(h,i-1)+Ax(h,i); elseif (vx(h,i-1)+Ax(h,i))<-speedlimit vx(h,i)=-speedlimit; else vx(h,i)=speedlimit; end end for h=1:v if abs(vy(h,i-1)+Ay(h,i))<speedlimit vy(h,i)=vy(h,i-1)+Ay(h,i); elseif (vy(h,i-1)+Ay(h,i))<-speedlimit vy(h,i)=-speedlimit; else vy(h,i)=speedlimit; end end % %Update position x(:,i)=x(:,i-1)+(vx(:,i-1)+vx(:,i))/2; y(:,i)=y(:,i-1)+(vy(:,i-1)+vy(:,1))/2; % end %Plot position clf; hold on; axis([-100,SideLength+100,-100,SideLength+100]); cc=hsv(v); for j=1:v plot(x(j,1),y(j,1),'ko') plot(x(j,:),y(j,:),'color',cc(j,:)) end hold off; % end My original plan was to place particles within a square, and move them around by allowing their acceleration in the x and y direction to be governed by a uniformly distributed random variable. To keep the particles within the square, I tried to create a repulsive force that would push the particles away from the boundaries of the square. In practice, the particles tend to leave the desired "feasible" region after a relatively small number of time steps (say, 1000)." I'd love to hear your suggestions on either modifying my existing code or considering the problem from another perspective. When reading the code, please don't feel the need to get hung up on any of the ad hoc parameters at the very beginning of the script. They seem to help, but I don't believe any beside the "G" constant should truly be necessary to make this system work. Here is an example of the current output: Many of the vehicles have found their way outside of the desired square region, [0,400] X [0,400].

  Read the article

• iPhone Audio Queue Service sample units

  - by pion

  I am looking at Audio Queue Services document specifically on the following code: // Writing an audio queue buffer to disk AudioFileWritePackets ( // 1 pAqData->mAudioFile, // 2 false, // 3 inBuffer->mAudioDataByteSize, // 4 inPacketDesc, // 5 pAqData->mCurrentPacket, // 6 &inNumPackets, // 7 inBuffer->mAudioData // 8 ); inBuffer-mAudioDataByteSize is the number of bytes of audio data being written. inBuffer-mAudioData is the new audio data to write to the audio file. Assuming the sample rate is 44100. AudioStreamBasicDescription mDataFormat; mDataFormat.mSampleRate = 44100.0f; mDataFormat.mBitsPerChannel = 16; ... NSInteger numberSamples = inBuffer->mAudioDataByteSize / 2; SInt16 *audioSample = (SInt16 *)inBuffer->mAudioData; I use core-plot to plot the above where x axis is number of sample [1 .. numberSamples] and the y axis is audioSample[0] .. audioSample[numberSamples]. I can see the chart in "real-time" where the y axis goes up and down depending the loudness of my voice. Beginner questions: What does the audioSample represent? What am I looking at here? What is the unit of audioSample? What do I need to do if I just want to plot the range between 50 - 100 Hz? Thanks in advance for your help.

  Read the article

• jqGrid - edit function never getting called

  - by dcp

  I'm having a problem with JQGrid using ASP.NET MVC. I'm trying to follow this example (after you go to that link, over on the left side of the page please click Live Data Manipulation, then Edit Row), but my edit function is never getting called (i.e. it's never getting into the $("#bedata").click(function(). Does anyone know what could be the problem? <script type="text/javascript"> var lastsel2; jQuery(document).ready(function() { jQuery("#editgrid").jqGrid({ url: '/Home/GetMovieData/', datatype: 'json', mtype: 'GET', colNames: ['id', 'Movie Name', 'Directed By', 'Release Date', 'IMDB Rating', 'Plot', 'ImageURL'], colModel: [ { name: 'id', index: 'Id', width: 55, sortable: false, hidden: true, editable: false, editoptions: { readonly: true, size: 10} }, { name: 'Movie Name', index: 'Name', width: 250, editable: true, editoptions: { size: 10} }, { name: 'Directed By', index: 'Director', width: 250, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Release Date', index: 'ReleaseDate', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'IMDB Rating', index: 'IMDBUserRating', width: 100, align: 'right', editable: true, editoptions: { size: 10} }, { name: 'Plot', index: 'Plot', width: 150, hidden: false, editable: true, editoptions: { size: 30} }, { name: 'ImageURL', index: 'ImageURL', width: 55, hidden: true, editable: false, editoptions: { readonly: true, size: 10} } ], pager: jQuery('#pager'), rowNum: 5, rowList: [5, 10, 20], sortname: 'id', sortorder: "desc", height: '100%', width: '100%', viewrecords: true, imgpath: '/Content/jqGridCss/redmond/images', caption: 'Movies from 2008', editurl: '/Home/EditMovieData/', caption: 'Movie List' }); }); $("#bedata").click(function() { var gr = jQuery("#editgrid").jqGrid('getGridParam', 'selrow'); if (gr != null) jQuery("#editgrid").jqGrid('editGridRow', gr, { height: 280, reloadAfterSubmit: false }); else alert("Hey dork, please select a row"); }); </script> The relevant HTML is here: <table id="editgrid"> </table> <div id="pager" style="text-align: center;"> </div> <input type="button" id="bedata" value="Edit Selected" />

  Read the article

• Linq to find pair of points with longest length?

  - by Chris

  I have the following code: foreach (Tuple<Point, Point> pair in pointsCollection) { var points = new List<Point>() { pair.Value1, pair.Value2 }; } Within this foreach, I would like to be able to determine which pair of points has the most significant length between the coordinates for each point within the pair. So, let's say that points are made up of the following pairs: (1) var points = new List<Point>() { new Point(0,100), new Point(100,100) }; (2) var points = new List<Point>() { new Point(150,100), new Point(200,100) }; So I have two sets of pairs, mentioned above. They both will plot a horizontal line. I am interested in knowing what the best approach would be to find the pair of points that have the greatest distance between, them, whether it is vertically or horizontally. In the two examples above, the first pair of points has a difference of 100 between the X coordinate, so that would be the point with the most significant difference. But if I have a collection of pairs of points, where some points will plot a vertical line, some points will plot a horizontal line, what would be the best approach for retrieving the pair from the set of points whose difference, again vertically or horizontally, is the greatest among all of the points in the collection? Thanks! Chris

  Read the article

• Using GNU Octave FFT functions

  - by CFP

  Hello world! I'm playing with octave's fft functions, and I can't really figure out how to scale their output: I use the following (very short) code to approximate a function: function y = f(x) y = x .^ 2; endfunction; X=[-4096:4095]/64; Y = f(X); # plot(X, Y); F = fft(Y); S = [0:2047]/2048; function points = approximate(input, count) size = size(input)(2); fourier = [fft(input)(1:count) zeros(1, size-count)]; points = ifft(fourier); endfunction; Y = f(X); plot(X, Y, X, approximate(Y, 10)); Basically, what it does is take a function, compute the image of an interval, fft-it, then keep a few harmonics, and ifft the result. Yet I get a plot that is vertically compressed (the vertical scale of the output is wrong). Any ideas? Thanks!

  Read the article

• Exception on inserting into Access 2010 in C Sharp

  - by slao.it

  Hello, I am getting this exception when inserting into a Access 2010 database. Ex: System.Data.OleDb.OleDbException (0x80040E14): Syntax error in string in query expression ''CityName ?'. at System.Data.OleDb.OleDbCommand.ExecuteCommandTextErrorHandling(OleDbHResult hr) at System.Data.OleDb.OleDbCommand.ExecuteCommandTextForSingleResult(tagDBPARAMS dbParams, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommandText(Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteCommand(CommandBehavior behavior, Object& executeResult) at System.Data.OleDb.OleDbCommand.ExecuteReaderInternal(CommandBehavior behavior, String method) at System.Data.OleDb.OleDbCommand.ExecuteNonQuery() at ReadingData.Program.Main(String[] args) in C:\Users\user\documents\visual studio 2010\Projects\ReadingData\ReadingData\Program.cs:line 238 INSERT INTO CranbrookMain (ID,BlockNo,Plot,SubPlot,Code,Type,LastName,FirstName,ServiceHome,ServiceAddress,ServiceCity,Notes) VALUES ('1','Y','37','DS','C2','O','SMITH','John','Service Inc.','520B SLATER ROAD N.W.','CityName','CityName ? ') insertSQL = "INSERT INTO CranbrookMain (ID,BlockNo,Plot,SubPlot,Code,Type,LastName," + "FirstName,ServiceHome,ServiceAddress,ServiceCity,Notes) VALUES (" + "'"+id+ "','" + blockNo + "','" + plot + "','" + subPlot + "','" + code + "','" + type + "','" + lastname + "','" + firstname + "','" + serviceHome + "','" + serviceAddress + "','" + serviceCity + "','" + notes +"')"; Console.WriteLine(); OleDbCommand cmd = new OleDbCommand(insertSQL, con); // creating query command cmd.ExecuteNonQuery(); The error occurs in cmd.ExecuteNonQuery() function call. The above SQL INSERT statement works fine if I directly execute in the Access 2010 file.

  Read the article

• pylab.savefig() and pylab.show() image difference

  - by Jack1990

  I'm making an script to automatically create plots from .xvg files, but there's a problem when I'm trying to use pylab's savefig() method. Using pylab.show() and saving from there, everything's fine. Using pylab.show() Using pylab.savefig() def producePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): fc = sp.interp1d(timestep[::jump], energy_values[::jump],kind='cubic') xnew = numpy.linspace(0, finish, finish*2) pylab.plot(xnew, fc(xnew),type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def produceSimplePlot(timestep, energy_values,type_line = 'r', jump = 1,finish = 100): pylab.plot(timestep, energy_values,type_line) pylab.xlabel('Time in ps ') pylab.ylabel('kJ/mol') pylab.xlim(xmin=0, xmax=finish) def linearRegression(timestep, energy_values, type_line = 'g'): #, jump = 1,finish = 100): from scipy import stats import numpy #print 'fuck' timestep = numpy.asarray(timestep) slope, intercept, r_value, p_value, std_err = stats.linregress(timestep,energy_values) line = slope*timestep+intercept pylab.plot(timestep, line, type_line) def plottingTime(Title,file_name, timestep, energy_values ,loc, jump , finish): pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) linearRegression(timestep,energy_values) import numpy Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2f" %(Average),'Linear Reg'),loc) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4], bbox_inches= None, pad_inches=0) #if __name__ == '__main__': #plottingTime(Title,timestep1, energy_values, jump =10, finish = 4800) def specialCase(Title,file_name, timestep, energy_values,loc, jump, finish): #print 'Working here ...?' pylab.title(Title) producePlot(timestep,energy_values, 'b',jump, finish) import numpy from pylab import * Average = numpy.average(energy_values) #print Average pylab.legend(("Average = %.2g" %(Average), Title),loc) locs,labels = yticks() yticks(locs, map(lambda x: "%.3g" % x, locs)) #pylab.show() pylab.savefig('%s.jpg' %file_name[:-4] , bbox_inches= None, pad_inches=0) Thanks in advance, John

  Read the article

• Matlab fft function

  - by CTZStef

  The code below is from the Matlab 2011a help about fft function. I think there is a problem here : why do they multiply t(1:50) by Fs, and then say it's time in millisecond ? Certainly, it happens to be true in this very particular case, but change the value of Fs to, say, 2000, and it won't work anymore, obviously because of this factor of 2. Right ? Quite misleading, isn't it ? What do I miss ? Fs = 1000; % Sampling frequency T = 1/Fs; % Sample time L = 1000; % Length of signal t = (0:L-1)*T; % Time vector % Sum of a 50 Hz sinusoid and a 120 Hz sinusoid x = 0.7*sin(2*pi*50*t) + sin(2*pi*120*t); y = x + 2*randn(size(t)); % Sinusoids plus noise plot(Fs*t(1:50),y(1:50)) title('Signal Corrupted with Zero-Mean Random Noise') xlabel('time (milliseconds)') Clearer with this : fs = 2000; % Sampling frequency T = 1 / fs; % Sample time L = 1000; % Length of signal t2 = (0:L-1)*T; % Time vector f = 50; % signal frequency s2 = sin(2*pi*f*t2); figure, plot(fs*t2(1:50),s2(1:50)); % NOT good figure, plot(t2(1:50),s2(1:50)); % good

  Read the article

• Android : start intent in setOnClickListener

  - by Derek

  I have a button, and this button is going to get the values from EditText, then using this value to start a new Intent protected void onCreate(Bundle savedInstanceState) { textDay = (EditText) findViewById(R.id.textDay); textMonth = (EditText) findViewById(R.id.textMonth); textYear = (EditText) findViewById(R.id.textYear); gen = (Button) findViewById(R.id.getGraph); gen.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { getthisIntent(); } public Intent getthisIntent(Context context) { day = textDay.getText(); month = textMonth.getText(); year = textYear.getText(); date = day + "/" + month + "/" + year; . .// Plot graph using AchartEngine, then return an Intent // . } } }); but i get the error "The method getthisIntent(Context) in the type new View.OnClickListener(){} is not applicable for the arguments ()" Can i get some help? or do i have another alternative solution, when i click the button, then the button pass the values to the new intent, and start it without having a new xxx.java file? Edit This is basically what I am doing now, i need to get the things inserted by user, and plot a graph, the only way i know how to plot graph using AchartEngine is create a new activity with define this public Intent getthisIntent(Context context) To be honest, i dont really know what the hell I am doing, please correct me...

  Read the article

• drawing graphs in php

  - by user434885

  i am using php to generate graphs from arrays. I wish to create multiple graphs on the same page as i need to design a summary report from answers extracted from a database. Currently i am using this code and am only able to get one single graph. what additions to the code do i need to make to get multiple graphs? <?php function draw_graph($values) { // Get the total number of columns we are going to plot $columns = count($values); // Get the height and width of the final image $width = 300; $height = 200; // Set the amount of space between each column $padding = 5; // Get the width of 1 column $column_width = $width / $columns ; // Generate the image variables $im = imagecreate($width,$height); $gray = imagecolorallocate ($im,0xcc,0xcc,0xcc); $gray_lite = imagecolorallocate ($im,0xee,0xee,0xee); $gray_dark = imagecolorallocate ($im,0x7f,0x7f,0x7f); $white = imagecolorallocate ($im,0xff,0xff,0xff); // Fill in the background of the image imagefilledrectangle($im,0,0,$width,$height,$white); $maxv = 0; // Calculate the maximum value we are going to plot for($i=0;$i<$columns;$i++)$maxv = max($values[$i],$maxv); // Now plot each column for($i=0;$i<$columns;$i++) { $column_height = ($height / 100) * (( $values[$i] / $maxv) *100); $x1 = $i*$column_width; $y1 = $height-$column_height; $x2 = (($i+1)*$column_width)-$padding; $y2 = $height; imagefilledrectangle($im,$x1,$y1,$x2,$y2,$gray_dark); } header ("Content-type: image/png"); imagepng($im); imagedestroy($im); } $values = array("23","32","35","57","12"); $values2 = array("123","232","335","157","102"); draw_graph($values2); draw_graph($values);//no output is coming draw_graph($values2);//no output is coming draw_graph($values);//no output is coming ?>

  Read the article

• How to calculate the y-pixels of someones weight on a graph? (math+programming question)

  - by RexOnRoids

  I'm not that smart like some of you geniuses. I need some help from a math whiz. My app draws a graph of the users weight over time. I need a surefire way to always get the right pixel position to draw the weight point at for a given weight. For example, say I want to plot the weight 80.0(kg) on the graph when the range of weights is 80.0 to 40.0kg. I want to be able to plug in the weight (given I know the highest and lowest weights in the range also) and get the pixel result 400(y) (for the top of the graph). The graph is 300 pixels high (starts at 100 and ends at 400). The highest weight 80kg would be plot at 400 while the lowest weight 40kg would be plot at 100. And the intermediate weights should be plotted appropriately. I tried this but it does not work: -(float)weightToPixel:(float)theWeight { float graphMaxY = 400; //The TOP of the graph float graphMinY = 100; //The BOTTOM of the graph float yOffset = 100; //Graph itself is offset 100 pixels in the Y direction float coordDiff = graphMaxY-graphMinY; //The size in pixels of the graph float weightDiff = self.highestWeight-self.lowestWeight; //The weight gap float pixelIncrement = coordDiff/weightDiff; float weightY = (theWeight*pixelIncrement)-(coordDiff-yOffset); //The return value return weightYpixel; }

  Read the article

• How would i down-sample a .wav file then reconstruct it using nyquist? - in matlab [closed]

  - by martin

  This is all done in MatLab 2010 My objective is to show the results of: undersampling, nyquist rate/ oversampling First i need to downsample the .wav file to get an incomplete/ or impartial data stream that i can then reconstuct. Heres the flow chart of what im going to be doing So the flow is analog signal - sampling analog filter - ADC - resample down - resample up - DAC - reconstruction analog filter what needs to be achieved: F= Frequency F(Hz=1/s) E.x. 100Hz = 1000 (Cyc/sec) F(s)= 1/(2f) Example problem: 1000 hz = Highest frequency 1/2(1000hz) = 1/2000 = 5x10(-3) sec/cyc or a sampling rate of 5ms This is my first signal processing project using matlab. what i have so far. % Fs = frequency sampled (44100hz or the sampling frequency of a cd) [test,fs]=wavread('test.wav'); % loads the .wav file left=test(:,1); % Plot of the .wav signal time vs. strength time=(1/44100)*length(left); t=linspace(0,time,length(left)); plot(t,left) xlabel('time (sec)'); ylabel('relative signal strength') **%this is were i would need to sample it at the different frequecys (both above and below and at) nyquist frequency.*I think.*** soundsc(left,fs) % shows the resaultant audio file , which is the same as original ( only at or above nyquist frequency however) Can anyone tell me how to make it better, and how to do the various sampling at different frequencies?

  Read the article

• Labeling values in a GNUplot heatmap

  - by andremo

  I am trying to generate a heat map using gnu plot. set title "Heat Map" plot '-' matrix with image 10 20 30 40 50 60 70 80 90 100 20 30 40 50 60 70 80 90 100 0 30 40 50 60 70 80 90 100 0 0 40 50 60 70 80 90 100 0 0 0 50 60 70 80 90 100 0 0 0 0 60 70 80 90 100 0 0 0 0 0 70 80 90 100 0 0 0 0 0 0 80 90 100 0 0 0 0 0 0 0 90 100 0 0 0 0 0 0 0 0 100 0 0 0 0 0 0 0 0 0 e Along the axes I get values -2 0 2 4 6 8 10, and I would like to replace those with a custom string. I cannot find out how to do this.

  Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >