Search Results

Search found 13693 results on 548 pages for 'python metaprogramming'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 169/548 | < Previous Page | 165 166 167 168 169 170 171 172 173 174 175 176  | Next Page >

  • Number of elements in Python Set

    - by Tim
    I have a list of phone numbers that have been dialed (nums_dialed). I also have a set of phone numbers which are the number in a client's office (client_nums) How do I efficiently figure out how many times I've called a particular client (total) For example: >>>nums_dialed=[1,2,2,3,3] >>>client_nums=set([2,3]) >>>??? total=4 Problem is that I have a large-ish dataset: len(client_nums) ~ 10^5; and len(nums_dialed) ~10^3.

    Read the article

  • Checking if a string's characters are ascending alphabetically and its ascent is evenly spaced python

    - by FRU5TR8EDD
    So need to check if a string's characters are ascending alphabetically and if that ascent is evenly spaced. a = "abc" b = "ceg" So a is alphabetically ascending and it's spacing is 1 (if you convert to the ordinal values they are 97,98,99). And b is also alphabetically ascending and it's spacing is 2 (99,101,103). And I am sticking with the following code: a = 'jubjub' words1 = [] ords = [ord(letter) for letter in a] diff = ords[1] - ords[0] for ord_val in range(1, len(ords)-1): if diff > 0: if ords[ord_val + 1] - ords[ord_val] == diff: if a not in words1: words1.append((a, diff)) print words1 How come 'jubjub' works, 'ace' works, but 'catcat' doesn't?

    Read the article

  • Python sort strings started with digits

    - by vlad
    I have the next list: a = ['1th Word', 'Another Word', '10th Word'] print a.sort() >>> ['10th Word', '1th Word', 'Another Word'] But I need: ['1th Word', '10th Word','Another Word'] Is there an easy way to do this? I tried: r = re.compile(r'(\d+)') def sort_by_number(s): m = r.match(s) return m.group(0) x.sort(key=sort_by_number) But some strings do not have numbers and this leads to an errors. Thanks.

    Read the article

  • Normalising book titles - Python

    - by RadiantHex
    Hi folks, I have a list of books titles: "The Hobbit: 70th Anniversary Edition" "The Hobbit" "The Hobbit (Illustrated/Collector Edition)[There and Back Again]" "The Hobbit: or, There and Back Again" "The Hobbit: Gift Pack" and so on... I thought that if I normalised the titles somehow, it would be easier to implement an automated way to know what book each edition is referring to. normalised = ''.join([char for char in title if char in (string.ascii_letters + string.digits)]) or normalised = '' for char in title: if char in ':/()|': break normalised += char return normalised But obviously they are not working as intended, as titles can contain special characters and editions can basically have very different title layouts. Help would be very much appreciated! Thanks :)

    Read the article

  • Python: NameError: 'self' is not defined

    - by Rosarch
    I must be doing something stupid. I'm running this in Google App Engine: def render(self, template_name, template_data): path = os.path.join(os.path.dirname(__file__), 'static/templates/%s.html' % template_name) self.response.out.write(template.render(path, template_data)) This gives an error: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3192, in _HandleRequest self._Dispatch(dispatcher, self.rfile, outfile, env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3135, in _Dispatch base_env_dict=env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 516, in Dispatch base_env_dict=base_env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2394, in Dispatch self._module_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2304, in ExecuteCGI reset_modules = exec_script(handler_path, cgi_path, hook) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2200, in ExecuteOrImportScript exec module_code in script_module.__dict__ File "main.py", line 22, in <module> class MainHandler(webapp.RequestHandler): File "main.py", line 38, in MainHandler self.writeOut(template.render(path, template_data)) NameError: name 'self' is not defined What am I doing wrong?

    Read the article

  • Python unittest: Generate multiple tests programmatically?

    - by Rosarch
    I have a function to test, under_test, and a set of expected input/output pairs: [ (2, 332), (234, 99213), (9, 3), # ... ] I would like each one of these input/output pairs to be tested in its own test_* method. Is that possible? This is sort of what I want, but forcing every single input/output pair into a single test: class TestPreReqs(unittest.TestCase): def setUp(self): self.expected_pairs = [(23, 55), (4, 32)] def test_expected(self): for exp in self.expected_pairs: self.assertEqual(under_test(exp[0]), exp[1]) if __name__ == '__main__': unittest.main()

    Read the article

  • Sort a list numerically in Python

    - by Matthew
    So I have this list, we'll call it listA. I'm trying to get the [3] item in each list e.g. ['5.01','5.88','2.10','9.45','17.58','2.76'] in sorted order. So the end result would start the entire list over again with Santa at the top. Does that make any sense? [['John Doe', u'25.78', u'20.77', '5.01'], ['Jane Doe', u'21.08', u'15.20', '5.88'], ['James Bond', u'20.57', u'18.47', '2.10'], ['Michael Jordan', u'28.50', u'19.05', '9.45'], ['Santa', u'31.13', u'13.55', '17.58'], ['Easter Bunny', u'17.20', u'14.44', '2.76']]

    Read the article

  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

    Read the article

  • Python Frequently Asked Questions

    - by Casebash
    After seeing this suggestion for creating tag homepages/FAQs, I thought it'd be best to go on ahead and start collecting links to frequently asked questions to demonstrate how this would work. Object Oriented Metaclasses Missing features Enums Tools Available IDEs?

    Read the article

  • Python matching some characters into a string

    - by roaksoax
    Hi All I'm trying to extract/match data from a string using regular expression but I don't seem to get it. I wan't to extract the highlighted characters from the following string: /xubuntu/daily/current/lucid-alternate-**i386**.iso This should also work in case of: /xubuntu/daily/current/lucid-alternate-**amd64**.iso Thanks a lot for your help.

    Read the article

  • From Dictionary To File Python

    - by user3600560
    I am basically trying to write this information from my dictionary to this file. I have this dictionary named files = {} and it is for a filing system I am making. Anyhow it is always being update with new items, and I want those items to be uploaded to the file. Then if you exit the program the files are loaded back to the dictionary files = {}. Here is the code I have so far: file = {} for i in files: g = open(i, 'r') g.read(i) g.close() EDIT I want the contents of the dictionary to be written to a file. The items inside the dictionary are all stored like this: files[filename] = {filedate:filetext} where filename is the file's name, filedate is the date that the file was made on, and the filetext is the files contents.

    Read the article

  • Python frequency detection

    - by Tsuki
    Ok what im trying to do is a kind of audio processing software that can detect a prevalent frequency an if the frequency is played for long enough (few ms) i know i got a positive match. i know i would need to use FFT or something simiral but in this field of math i suck, i did search the internet but didn not find a code that could do only this. the goal im trying to accieve is to make myself a custom protocol to send data trough sound, need very low bitrate per sec but im also very limited on the transmiting end so the recieving software will need to be able custom (cant use an actual hardware/software modem) also i want this to be software only (no additional hardware except soundcard) thanks alot for the help.

    Read the article

  • python mock side_effect or return_value dependent on call_count

    - by user18380
    To test a polling function I want to mock the calling of a sub function so that the first time it is called it will fail, and the second time it is called it will succeed. Here's a very simplified version of it: poll_function(var1): value = sub_function(var1) # First call will return None while not value: time.sleep(POLLING_INTERVAL) value = sub_function(var1) # A subsequent call will return a string, e.g "data" return value Is this possible to do with a Mock object from the mock framework? I know Mock objects have a call_count attribute I should be able to use somehow. Right now I've solved it by creating a custom mock object that I use to monkey patch sub_function(), but I feel there should be a better less verbose way of doing it: def test_poll(): class MyMock(object): def __init__(self, *args): self.call_count = 0 def sub_function(self, *args, **kwargs): if self.call_count > 1: return "data" else: self.call_count += 1 return None my_mock = MyMock() with patch('sub_function', my_mock.sub_function): ok_(poll_function())

    Read the article

  • Error when feeding a mysql db with a python-parsed data

    - by Barnabe
    I use this bit of code to feed some data i have parsed from a web page to a mysql database c=db.cursor() c.executemany( """INSERT INTO data (SID, Time, Value1, Level1, Value2, Level2, Value3, Level3, Value4, Level4, Value5, Level5, ObsDate) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)""", clean_data ) The parsed data looks like this (there are several hundred such lines) clean_data = [(161,00:00:00,8.19,1,4.46,4,7.87,4,6.54,null,4.45,6,2010-04-12),(162,00:00:00,7.55,1,9.52,1,1.90,1,4.76,null,0.14,1,2010-04-12),(164,00:00:00,8.01,1,8.09,1,0,null,8.49,null,0.20,2,2010-04-12),(166,00:00:00,8.30,1,4.77,4,10.99,5,9.11,null,0.36,2,2010-04-12)] if i hard code the data as above mySQL accepts my request (except for some quibbles about formatting) but if the variable clean_data is instead defined as the result of the parsing code, like this: cleaner = [(""" $!!'""", ')]'),(' $!!', ') etc etc] def processThis(str,lst): for find, replace in lst: str = str.replace(find, replace) return str clean_data = processThis(data,cleaner) then i get the dreaded "TypeError: not enough arguments for format string" After playing with formatting options for a few hours (I am very new to this) I am confused... what is the difference between the hard coded data and the result of the processThis function as fas as mySQL is concerned? Any idea greatly appreciated...

    Read the article

  • Perfom python unit tests via a web interface

    - by 47
    Is it possible to perform unittest tests via a web interface...and if so how? EDIT: For now I want the results...for the tests I want them to be automated...possibly every time I make a change to the code. Sorry I forgot to make this more clear

    Read the article

  • Python built-in id() not consistent:

    - by Dannellyz
    Hoping someone can explain the following discrepancy: >>> s1 = "Cyber security" >>> s2 = "Cyber security" >>> id(s1) == id(s1) True >>> id(s1) == id(s2) False >>> s1 = "cyber" >>> s2 = "cyber" >>> id(s1) == id(s2) True >>> s2 = "cyber " >>> s2 = "cyber " >>> id(s1) == id(s2) False Why does the space make the id() False, yet different variables with no spaces are True?

    Read the article

  • Python structure mistake

    - by jaddy123
    I'm writing a program in which I can Reverse the sequence and Replace all As with Ts, all Cs with Gs, all Gs with Cs, and all Ts with As. the program is to read a sequence of bases and output the reverse complement sequence. I am having trouble to do it so can anyone please help me with this by having a look on my code: word = raw_input("Enter sequence: ") a = word.replace('A', 'T') b = word.replace('C', 'G') c = word.replace('G', 'C') d = word.replace('T', 'A') if a == word and b == word and c == word and d == word: print "Reverse complement sequence: ", word And I want this sort of output: Enter sequence: CGGTGATGCAAGG Reverse complement sequence: CCTTGCATCACCG Regards

    Read the article

  • Python get raw_input but manually decide when string is done

    - by Jasie
    I want someone to type words in the console, and autocomplete from a list when they hit "tab" key. However, raw_input won't return a string until someone hits [Enter]. How do I read characters into a variable until the user hits [Enter]? *Note: I don't want to use import readline for autocompletion because of OS issues.

    Read the article

  • difference between 2 pieces Python code

    - by draw
    Hello, I'm doing an exercise as following: # B. front_x # Given a list of strings, return a list with the strings # in sorted order, except group all the strings that begin with 'x' first. # e.g. ['mix', 'xyz', 'apple', 'xanadu', 'aardvark'] yields # ['xanadu', 'xyz', 'aardvark', 'apple', 'mix'] # Hint: this can be done by making 2 lists and sorting each of them # before combining them. sample solution: def front_x(words): listX = [] listO = [] for w in words: if w.startswith('x'): listX.append(w) else: listO.append(w) listX.sort() listO.sort() return listX + listO my solution: def front_x(words): listX = [] for w in words: if w.startswith('x'): listX.append(w) words.remove(w) listX.sort() words.sort() return listX + words as I tested my solution, the result is a little weird. Here is the source code with my solution: http://dl.dropbox.com/u/559353/list1.py. You might want to try it out.

    Read the article

  • Python: combine two neighbor list components

    - by kame
    When i use this code I get elements wich containing one number or letter. How to combine two neighbors? data = '4D41544C414220352E30204D41542D66696C652C20506C6174666F726D3A20504357494E2C2043726561746564206F6E3A20576564204D61792030352031363A31393A3337203230313020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020200001494D0F00000026000000789CE36360607000623620E680D220C00AE53343312310BA00692620E604F351010025BE00C8' data2 = list(data) print data2

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 165 166 167 168 169 170 171 172 173 174 175 176  | Next Page >