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  • Which is faster: in_array() or a bunch of expressions in PHP?

    - by Darryl Hein
    Is it faster to do the following: if ($var != 'test1' && $var != 'test2' && $var != 'test3' && $var != 'test4') { ... } Or: if (!in_array($var, array('test1', 'test2', 'test3', 'test4') { ... } Is there a number of values at which point it's faster to do one or the other? (In this case, the array used in the second option doesn't alreay exist.)

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  • Ray-box Intersection Theory

    - by Myx
    Hello: I wish to determine the intersection point between a ray and a box. The box is defined by its min 3D coordinate and max 3D coordinate and the ray is defined by its origin and the direction to which it points. Currently, I am forming a plane for each face of the box and I'm intersecting the ray with the plane. If the ray intersects the plane, then I check whether or not the intersection point is actually on the surface of the box. If so, I check whether it is the closest intersection for this ray and I return the closest intersection. The way I check whether the plane-intersection point is on the box surface itself is through a function bool PointOnBoxFace(R3Point point, R3Point corner1, R3Point corner2) { double min_x = min(corner1.X(), corner2.X()); double max_x = max(corner1.X(), corner2.X()); double min_y = min(corner1.Y(), corner2.Y()); double max_y = max(corner1.Y(), corner2.Y()); double min_z = min(corner1.Z(), corner2.Z()); double max_z = max(corner1.Z(), corner2.Z()); if(point.X() >= min_x && point.X() <= max_x && point.Y() >= min_y && point.Y() <= max_y && point.Z() >= min_z && point.Z() <= max_z) return true; return false; } where corner1 is one corner of the rectangle for that box face and corner2 is the opposite corner. My implementation works most of the time but sometimes it gives me the wrong intersection. I was wondering if the way I'm checking whether the intersection point is on the box is correct or if I should use some other algorithm. Thanks.

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  • javascript alarmclock script

    - by butteff
    it's work only once. at second button click, occured nothing. if I change budilnik variable at i_budilnik or var budilnik, occured nothing at first and other clicks! Where is the problem? <div><form name="alert"><input type="text" name="hour" /><input type="text" name="min"/><input type="button" value="ok" onclick="budilnik(this.form)"></form><font color=#660000 size=20 face=Tahoma><span id="hours"></span> </div> <script type="text/javascript"> function budilnik(form) { budilnik=1; min=form.min.value; hour=form.hour.value; } obj_hours=document.getElementById("hours"); function wr_hours() { time=new Date(); time_min=time.getMinutes(); time_hours=time.getHours(); time_wr=((time_hours<10)?"0":"")+time_hours; time_wr+=":"; time_wr+=((time_min<10)?"0":"")+time_min; time_wr=time_wr; obj_hours.innerHTML=time_wr; if (i_budilnik==1) { if (min==time_min) { if (hour==time_hours) { alert('welldone'); budilnik=0; } } } } wr_hours(); setInterval("wr_hours();",1000); </script>

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  • twitter bootstrap typeahead 2.0.4 ajax error

    - by Adam Levitt
    I have the following code which definitely returns a proper data result if I use the 2.0.0 version, but for some reason bootstrap's typeahead plugin is giving me an error. I pasted it below the code sample: <input id="test" type="text" /> $('#test').typeahead({ source: function(typeahead, query) { return $.post('/Profile/searchFor', { query: query }, function(data) { return typeahead.process(data); }); } }); When I run this example I'm getting a jQuery bug that says the following: ** item is undefined matcher(item=undefined)bootst...head.js (line 104) <br/>(?)(item=undefined)bootst...head.js (line 91) <br/>f(a=function(), b=function(), c=false)jquery....min.js (line 2) <br/>lookup(event=undefined)bootst...head.js (line 90) <br/>keyup(e=Object { originalEvent=Event keyup, type="keyup", timeStamp=145718131, more...})bootst...head.js (line 198) <br/>f()jquery....min.js (line 2) <br/>add(c=Object { originalEvent=Event keyup, type="keyup", timeStamp=145718131, <br/>more...})jquery....min.js (line 3) <br/>add(a=keyup charCode=0, keyCode=70)jquery....min.js (line 3) <br/>[Break On This Error] <br/>return item.toLowerCase().indexOf(this.query.toLowerCase())** Any thoughts? ... The same code works in the 2.0.0 version of the plugin, but fails to write to my knockout object model.

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  • Is possible to reuse subqueries?

    - by Gothmog
    Hello, I'm having some problems trying to perform a query. I have two tables, one with elements information, and another one with records related with the elements of the first table. The idea is to get in the same row the element information plus several records information. Structure could be explain like this: table [ id, name ] [1, '1'], [2, '2'] table2 [ id, type, value ] [1, 1, '2009-12-02'] [1, 2, '2010-01-03'] [1, 4, '2010-01-03'] [2, 1, '2010-01-02'] [2, 2, '2010-01-02'] [2, 2, '2010-01-03'] [2, 3, '2010-01-07'] [2, 4, '2010-01-07'] And this is want I would like to achieve: result [id, name, Column1, Column2, Column3, Column4] [1, '1', '2009-12-02', '2010-01-03', , '2010-01-03'] [2, '2', '2010-01-02', '2010-01-02', '2010-01-07', '2010-01-07'] The following query gets the proper result, but it seems to me extremely inefficient, having to iterate table2 for each column. Would be possible in anyway to do a subquery and reuse it? SELECT a.id, a.name, (select min(value) from table2 t where t.id = subquery.id and t.type = 1 group by t.type) as Column1, (select min(value) from table2 t where t.id = subquery.id and t.type = 2 group by t.type) as Column2, (select min(value) from table2 t where t.id = subquery.id and t.type = 3 group by t.type) as Column3, (select min(value) from table2 t where t.id = subquery.id and t.type = 4 group by t.type) as Column4 FROM (SELECT distinct id FROM table2 t WHERE (t.type in (1, 2, 3, 4)) AND t.value between '2010-01-01' and '2010-01-07') as subquery LEFT JOIN table a ON a.id = subquery.id

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  • JQuery idleTimeout plugin: How to display the dialog after the session is timedout on ASP.NET MVC Pa

    - by Rita
    Hi I am working on migrating the ASP.NET apllication to MVC Framework. I have implemented session timeout for InActiveUser using JQuery idleTimeout plugin. I have set idletime for 30 min as below in my Master Page. So that After the user session is timedout of 30 Min, an Auto Logout dialog shows for couple of seconds and says that "You are about to be signed out due to Inactivity" Now after this once the user is logged out and redirected to Home Page. Here i again want to show a Dialog and should stay there saying "You are Logged out" until the user clicks on it. Here is my code in Master page: $(document).ready(function() { var SEC = 1000; var MIN = 60 * SEC; // http://philpalmieri.com/2009/09/jquery-session-auto-timeout-with-prompt/ <% if(HttpContext.Current.User.Identity.IsAuthenticated) {%> $(document).idleTimeout({ inactivity: 30 * MIN, noconfirm : 30 * SEC, redirect_url: '/Account/Logout', sessionAlive: 0, // 30000, //10 Minutes click_reset: true, alive_url: '', logout_url: '' }); <%} %> } Logout() Method in Account Controller: public virtual ActionResult Logout() { FormsAuthentication.SignOut(); return RedirectToAction(MVC.Home.Default()); } Appreciate your responses.

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  • Why does my simple strict XHTML file give errors when I include jquery?

    - by Colen
    I'm trying to make a simple strict HTML file that includes jquery: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <title>Test File</title> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script> </head> <body> </body> </html> But Firefox displays the following errors in the error console when I try to load it: Error: d.style is undefined Source File: http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js Line: 33 Error: jQuery is not defined Source File: http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js Line: 19 Help! I don't understand :(

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  • JSFiddle external resources not working

    - by Ahmed Kato
    I am new to jsfiddle and I am trying to link my external resources. I added them using the tab on the left side and then paste my code on the panes Here is my JSFiddle project but only html is shown without linking to javascript and css in the output what I am doing wrong ? this is my original <head> <link href="css/bootstrap.min.css" rel="stylesheet"> <link href="css/bootstrap-responsive.min.css" rel="stylesheet"> <link href="css/style.css" rel="stylesheet"> <script type="text/javascript" src="js/jquery.min.js"></script> <script type="text/javascript" src="js/bootstrap.min.js"></script> <script type="text/javascript" src="js/scripts.js"></script> <script type="text/javascript" src="js/bootstrap-datepicker.js"></script> <link rel="stylesheet" href="bootstrap-tagsinput.css"> <link rel="stylesheet" type="text/css" href="css/datepicker.css"> </head>

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  • Error in datatype (nvarchar instead of ntext)

    - by prabu R
    I am importing data from excel(.xls) to SQL Server 2008 using SSIS. I have included IMEX=1 in the connection string of excel connection manager. But a column consists of a value as below: 4-Hour Engineer Dispatch ASPP Engr Dispatch 1: Up to 1 dispatch (8 hours) per year. Hours exceeding allocation billed @ 1.5x hourly rate w/ 8-hr min Engr Dispatch: 8-hrs to arrive on-site from Ciena's determination of need On-Site Engineer Dispatch - 8 Hour ASPP Engr Dispatch 8: Up to 8 dispatch (64 hours) per year. Hours exceeding allocation billed @ 1.5x hourly rate w/ 8-hr min Engr Dispatch: NBD to dispatch from Ciena's determination of need Per Incident On Site Support ASPP Engr Dispatch 12: Up to 12 dispatch (96 hours) per year. Hours exceeding allocation billed @ 1.5x hourly rate w/ 8-hr min Engr Dispatch: Next day to arrive on-site from Ciena's determination of need Resident Engineer Engr Dispatch: 2-hrs to arrive on-site from Ciena's determination of need Engr Dispatch: 4-hrs to arrive on-site from Ciena's determination of need ASPP Engr Dispatch 2: Up to 2 dispatch (16 hours) per year. Hours exceeding allocation billed @ 1.5x hourly rate w/ 8-hr min N Actually there are about 600 rows in that excel file. But the above mentioned value is present after 450 rows only. So, the datatype of that column is taken as nvarchar(255) as default instead of ntext and so i am getting error. Anybody please help out... Thanks in advance...

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  • how to get the real bounds with google maps when fully zoomed out

    - by brad
    I have a map that shows location points based on the gbounds of the map. For example, any time the map is moved/zoomed, i find the bounds and query for locations that fall within those bounds. Unfortunately I'm unable to display all my locations when fully zoomed out. Reason being, gmaps reports the min/max long as whatever is at the edge of the map, but if you zoom out enough, you can get a longitudinal range that excludes visible locations. For instance, if you zoom your map so that you see NorthAmerica twice, on the far left and far right. The min/max long are around: -36.5625 to 170.15625. But this almost completely excludes NorthAmerica which lies in the -180 to -60 range. Obviously this is bothersome as you can actually see the continent NorthAmerica (twice), but when I query my for locations in the range from google maps, NorthAmerica isn't returned. My code for finding the min/max long is: bounds = gmap.getBounds(); min_lat = bounds.getSouthWest().lat() max_lat = bounds.getNorthEast().lat() Has anyone encountered this and can anyone suggest a workaround? Off the top of my head I can only thing of a hack: to check the zoom level and hardcode the min/max lats to -180/180 if necessary, which is definitely unacceptable.

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  • using mod-rewrite to redirect requests for jquery.js to GoogleAPI cache

    - by Aditya Advani
    Hi All, Our Linux server with Apache 2.x, Plesk 8.x hosts a number of e-commerce websites. To take advantage of browser caching we would like to use Google's provided copy of jquery.js. Hence in the vhost.conf file of each we can use the following RewriteRule RewriteCond %{REQUEST_FILENAME} jquery.min.js [nc] RewriteRule . http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js [L] And in vhost_ssl.conf RewriteCond %{REQUEST_FILENAME} jquery.min.js [nc] RewriteRule . https://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js [L] OK now these rules work fine in the individual vhost.conf files of each domain. However we host over 200 domains, I would like for them to work but cannot seem to get them to work globally in the httpd.conf file. Challenges are the following: Get the rewriterule to work in httpd.conf Detect if HTTPS is on, and if it is and the is is a secure page, rewrite to ... Each individual domain will still have it's own custom mod-rewrite rules. Which rules take precedence - global or per-domain? Do they combine? Is it ok if I have the "RewriteEngine On" directive in the global httpd.conf and then again in the vhost.conf? Please let me know what your guys' suggestions are. Desperate for a solution to this problem.

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  • CMYK + CMYK = ? CMYK / 2 = ?

    - by Pete
    Suppose there are two colors defined in CMYK: color1 = 30, 40, 50, 60 color2 = 50, 60, 70, 80 If they were to be printed what values would the resulting color have? color_new = min(cyan1 + cyan2, 100), min(magenta1 + magenta2, 100), min(yellow1 + yellow2, 100), min(black1 + black2, 100)? Suppose there is a color defined in CMYK: color = 40, 30, 30, 100 It is possible to print a color at partial intensity, i.e. as a tint. What values would have a 50% tint of that color? color_new = cyan / 2, magenta / 2, yellow / 2, black / 2? I'm asking this to better understand the "tintTransform" function in PDF Reference 1.7, 4.5.5 Special Color Spaces, DeviceN Color Spaces Update: To better clarify: I'm not entirely concerned with human perception or how the CMYK dyies react to the paper. If someone specifies 90% tint which, when printed, looks like full intensity colorant, that's ok. In other words, if I asking how to compute 50% of cmyk(40, 30, 30, 100) I'm asking how to compute the new values, regardless of whether the result looks half-dark or not. Update 2: I'm confused now. I checked this in InDesign and Acrobat. For example Pantone 3005 has CMYK 100, 34, 0, 2, and its 25% tint has CMYK 25, 8.5, 0, 0.5. Does it mean I can "monkey around in a linear way"?

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  • R: outlier cleaning for each column in a dataframe by using quantiles 0.05 and 0.95

    - by Rainer
    hi, I am a R-novice. I want to do some outlier cleaning and over-all-scaling from 0 to 1 before putting the sample into a random forest. g<-c(1000,60,50,60,50,40,50,60,70,60,40,70,50,60,50,70,10) If i do a simple scaling from 0 - 1 the result would be: > round((g - min(g))/abs(max(g) - min(g)),1) [1] 1.0 0.1 0.0 0.1 0.0 0.0 0.0 0.1 0.1 0.1 0.0 0.1 0.0 0.1 0.0 0.1 0.0 So my idea is to replace the values of each column that are greater than the 0.95-quantile with the next value smaller than the 0.95-quantile - and the same for the 0.05-quantile. So the pre-scaled result would be: g<-c(**70**,60,50,60,50,40,50,60,70,60,40,70,50,60,50,70,**40**) and scaled: > round((g - min(g))/abs(max(g) - min(g)),1) [1] 1.0 0.7 0.3 0.7 0.3 0.0 0.3 0.7 1.0 0.7 0.0 1.0 0.3 0.7 0.3 1.0 0.0 I need this formula for a whole dataframe, so the functional implementation within R should be something like: > apply(c, 2, function(x) x[x`<quantile(x, 0.95)]`<-max(x[x, ... max without the quantile(x, 0.95)) Can anyone help? Spoken beside: if there exists a function that does this job directly, please let me know. I already checked out cut and cut2. cut fails because of not-unique breaks; cut2 would work, but only gives back string values or the mean value, and I need a numeric vector from 0 - 1. for trial: a<-c(100,6,5,6,5,4,5,6,7,6,4,7,5,6,5,7,1) b<-c(1000,60,50,60,50,40,50,60,70,60,40,70,50,60,50,70,10) c<-cbind(a,b) c<-as.data.frame(c) Regards and thanks for help, Rainer

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  • jQuery UI Rang Slider show divs based on selected range

    - by andi_sf
    I have set up a range slider that should show/hide divs based on their range values - meaning if the range of the one specifies in the div falls into the selected range in the slider it should show - the others hide. Somehow it does not work correctly - if anybody could help that would be greatly appreciated. My code so far: $("#slider").slider({ range: true, min: 150, max: 280, step: 5, values: [150, 280], slide: function(event, ui) { $("#amount").val('Min. Value' + ui.values[0] + ' - Max. Value' + ui.values[1]); }, change: function(event, ui) { $('#col-2 div').each(function(){ var valueS = parseInt($(this).attr("class")); var valueX = parseInt($(this).attr("title")); if (valueS < ui.values[0] && valueX <= ui.values[1] || valueS ui.values[0] && valueX = ui.values[1] ) { $(this).stop().animate({opacity: 0.25}, 500) } else { $(this).stop().animate({opacity: 1.0}, 500) $("#amount").val('Min. Value' + ui.values[0] + ' - Max. Value' + ui.values[1]); } }); } }); $("#amount").val('Min. Value' + $("#slider").slider("values", 0) + ' - Max. Value' + $("#slider").slider("values", 1)); }); I have also posted a sample at: http://www.webdesigneroakland.com/slider/444range_slider.html

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  • RBG to CbyCr conversion code

    - by user1446688
    I am wondering why this code does not work. Basically it is supposed to convert between RGB and CbYCr. When I convert from RGB to CbYCr then back to RGB I do not get the original RGB values. What is wrong with this code? #define MIN(a,b) (((a)<(b))?(a):(b)) #define MAX(a,b) (((a)(b))?(a):(b)) struct _rgb { int R; int G; int B; }; typedef struct _rgb rgb; struct _cbycr { int Cb; int Y; int Cr; }; typedef struct _cbycr cbycr; void cbycr2rgb(rgb *c, double Y, double Cb, double Cr) { int r = (int)(Y + 1.40200 * (Cr - 0x80)); int g = (int)(Y - 0.34414 * (Cb - 0x80) - 0.71414 * (Cr - 0x80)); int b = (int)(Y + 1.77200 * (Cb - 0x80)); c->R = MAX(0, MIN(255, r)); c->G = MAX(0, MIN(255, g)); c->B = MAX(0, MIN(255, b)); } void rgb2cbycr(cbycr *c, int R, int G, int B) { c->Y = (int)(0.299 * R + 0.587 * G + 0.114 * B); c->Cb = (int)(-0.16874 * R - 0.33126 * G + 0.50000 * B); c->Cr =(int)(0.50000 * R - 0.41869 * G - 0.08131 * B); } int main() { cbycr _cbycr; rgb _rgb; _rgb.R = 50; _rgb.G = 50; _rgb.B = 50; rgb2cbycr(&_cbycr, _rgb.R, _rgb.G, _rgb.B); cbycr2rgb(&_rgb, _cbycr.Y, _cbycr.Cb, _cbycr.Cr); printf("rgb=%d %d %d\n", _rgb.R, _rgb.G, _rgb.B); return 0; } output: rgb=0 185 0

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • When I include only the jQuery 1.4 Library, I get an exception, why?

    - by codeninja
    I keep getting this error all over the place where I only have jquery 1.3 or 1.4 included. "setting a property that has only a getter" and a long list of warnings in the Firefox Error Console. What's going on? I can't find any information on this issue =/ <!DOCTYPE HTML PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-US"> <head> <title>Demo</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <link rel="shortcut icon" href="images/favicon.ico"> <link rel="stylesheet" href="css/common.css" type="text/css" /> <link rel="stylesheet" href="css/modules.css" type="text/css" /> <script type="text/javascript" src="js/jquery-1.4.2.min.js"></script> </head> Just some Warning snippets: Warning: reference to undefined property a[++e] Source File: /js/jquery-1.4.2.min.js Line: 30 Warning: reference to undefined property a[0] Source File: /js/jquery-1.4.2.min.js Line: 30 Warning: function oa does not always return a value Source File: /js/jquery-1.4.2.min.js Line: 18, Column: 165 Source Code: th;n<r;n++){j=d[n];a.currentTarget=j.elem;a.data=j.handleObj.data;a.handleObj=j.handleObj;if(j.handleObj.origHandler.apply(j.elem,e)===false){b=false;break}}return b}}function pa(a,b){return"live."+(a&&a!=="*"?a+".":"")+b.replace(/\./g,"`").replace(/ /g,

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  • jQuery UI - Sortable isn't firing?

    - by Kenny Bones
    Hi, I'm trying to get the jQuery UI sortable plugin to work and I've created a list that looks like this: <ul id="sortable"> <li>Item 1</li> <li>Item 2</li> <li>Item 3</li> <li>Item 4</li> <li>Item 5</li> </ul> And I've included the plugin script files: $(function() { $("#sortable").sortable(); alert('test'); $("#sortable").disableSelection(); }); So I just tried putting the alert box before .sortable is run and the alertbox is showing. But putting it after .sortable isn't working. Which means that .sortable is failing right? I've included the scripts and put them in the head of the html document. <script type="text/javascript" src="js/jquery.ui.core.min.js"></script> <script type="text/javascript" src="js/jquery.ui.mouse.min.js"></script> <script type="text/javascript" src="js/jquery.ui.sortable.min.js"></script> <script type="text/javascript" src="js/jquery.ui.widget.min.js"></script> Which is correct right? And the function that actually runs .sortable is in a merged js file along with all other js snippets and plugins.

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  • How use unobtrusive validation without a model

    - by Ross Cyrus
    i have simple a form wich made by htmlHelper(mvc3) then inside of it i have 2 input field 1:type=text 2:type=submit to submit the form. there is no model behind.so i need to perfom a clientside validation on the textfield before submit it to the server.but i dont know how. i tried this puting manualy the 'data-* artibute , but does not work : @using( Html.BeginForm()) { <label for="UserName" >User Name</label> <div class="editor-field"> <input type="text" data-val="true" data-val-requierd="You must provide an user Name" id="userName" name="userName" placeholder="Enter Your User Name" /> </div> <input type="submit" value="Recover" /> } the "jquery.validate.min.js" and jquery.validate.unobtrusive.min.js and jquery.validate.min.js and jquery.validate.unobtrusive.min.js are loaded to the page. It doesnt let me to answer my self ,so i put it here : I solve it my self,just made an other view wich has its own model and Required on its propertyis and then just copy the renderd html to my own,and i got this and works : <input data-val="true" data-val-required="You must provide an user Name" id="UserName" name="UserName" type="text" value="" placeholder="Enter your User Name"/> <span class="field-validation-valid" data-valmsg-for="UserName" data-valmsg-replace="true"></span> And there is no type="Required".any way thank you guys.

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  • How can I show print statements in debug mode of OPNET Modeler?

    - by Here now
    I'm writing C++ code in OPNET Modeler. I try to simulate my scenario in debugger mode & I need to trace the function that I wrote it. I need to show print statements which I put it in my code. I used in debugger mode: ***ltr function_name()*** then ***c*** But the result looks like: Type 'help' for Command Summary ODB> ltr enqueue_packet() Added trace #0: trace on label (enqueue_packet()) ODB> c |-----------------------------------------------------------------------------| | Progress: Time (1 min. 52 sec.); Events (500,002) | | Speed: Average (82,575 events/sec.); Current (82,575 events/sec.) | | Time : Elapsed (6.1 sec.) | | DES Log: 28 entries | |-----------------------------------------------------------------------------| |-----------------------------------------------------------------------------| | Progress: Time (1 min. 55 sec.); Events (1,000,002) | | Speed: Average (69,027 events/sec.); Current (59,298 events/sec.) | | Time : Elapsed (14 sec.) | | DES Log: 28 entries | |-----------------------------------------------------------------------------| |-----------------------------------------------------------------------------| | Progress: Time (1 min. 59 sec.); Events (1,500,002) | | Speed: Average (51,464 events/sec.); Current (34,108 events/sec.) | | Time : Elapsed (29 sec.) | | DES Log: 28 entries | |-----------------------------------------------------------------------------| |-----------------------------------------------------------------------------| | Simulation Completed - Collating Results. | | Events: Total (1,591,301); Average Speed (48,803 events/sec.) | | Time : Elapsed (33 sec.); Simulated (2 min. 0 sec.) | | DES Log: 29 entries | |-----------------------------------------------------------------------------| |-----------------------------------------------------------------------------| | Reading network model. | |-----------------------------------------------------------------------------| I need to show the print statements in my code. Where it has to be appeared? Is there any step before run the simulation to insure that OPNET debugger using Visual Studio & go through my code??

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  • Auto fit iframe

    - by kevin
    I have a difficulty on design a web page layout. This is my layout structure. <style> #left { float:left; width:600px; min-height:400px; } #right { float:right; width:200px; min-height:400px; } </style> <body> <center> <div id="page"> <div id="left"> <iframe /> </div> <div id="right">right panel</div> <div id="footer">footer</div> </center> </div> </body> How can i make the both left & right div grow when the right div's child increase more than the min height? How can i make the both left & right div grow when the content in the iframe is longer than the min height?

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  • How do I write this GROUP BY in mysql UNION query

    - by user1652368
    Trying to group the results of two queries together. When I run this query: SELECT pr_id, pr_sbtcode, pr_sdesc, od_quantity, od_amount FROM ( SELECT `bgProducts`.`pr_id`, `bgProducts`.`pr_sbtcode`, `bgProducts`.`pr_sdesc`, SUM(`od_quantity`) AS `od_quantity`, SUM(`od_amount`) AS `od_amount`, MIN(UNIX_TIMESTAMP(`or_date`)) AS `or_date` FROM `bgOrderMain` JOIN `bgOrderData` JOIN `bgProducts` WHERE `bgOrderMain`.`or_id` = `bgOrderData`.`or_id` AND `od_pr` = `pr_id` AND UNIX_TIMESTAMP(`or_date`) >= '1262322000' AND UNIX_TIMESTAMP(`or_date`) <= '1346990399' AND (`pr_id` = '415' OR `pr_id` = '1088') GROUP BY `bgProducts`.`pr_id` UNION SELECT `bgProducts`.`pr_id`, `bgProducts`.`pr_sbtcode`, `bgProducts`.`pr_sdesc`,SUM(`od_quantity`) AS `od_quantity`, SUM(`od_amount`) AS `od_amount`, MIN(UNIX_TIMESTAMP(`or_date`)) AS `or_date` FROM `npOrderMain` JOIN `npOrderData` JOIN `bgProducts` WHERE `npOrderMain`.`or_id` = `npOrderData`.`or_id` AND `od_pr` = `pr_id` AND UNIX_TIMESTAMP(`or_date`) >= '1262322000' AND UNIX_TIMESTAMP(`or_date`) <= '1346990399' AND (`pr_id` = '415' OR `pr_id` = '1088') GROUP BY `bgProducts`.`pr_id` ) TEMPTABLE3; it produces this result +-------+------------+--------------------------+-------------+-----------+ | pr_id | pr_sbtcode | pr_sdesc | od_quantity | od_amount +-------+------------+--------------------------+-------------+-----------+ | 415 | NP13 | Product 13 | 5 | 125 | 1088 | NPAW | Product AW | 4 | 100 | 415 | NP13 | Product 13 | 5 | 125 | 1088 | NPAW | Product AW | 2 | 50 +-------+------------+--------------------------+-------------+-----------+</pre> What I want to get a result that combines those into 2 lines: +-------+------------+--------------------------+-------------+-----------+ | pr_id | pr_sbtcode | pr_sdesc | od_quantity | od_amount +-------+------------+--------------------------+-------------+-----------+ | 415 | NP13 | Product 13 | 10 | 250 | 1088 | NPAW | Product AW | 6 | 150 +-------+------------+--------------------------+-------------+-----------+</pre> So I added GROUP BY pr_id to the end of the query: SELECT pr_id, pr_sbtcode, pr_sdesc, od_quantity, od_amount FROM ( SELECT `bgProducts`.`pr_id`, `bgProducts`.`pr_sbtcode`, `bgProducts`.`pr_sdesc`, SUM(`od_quantity`) AS `od_quantity`, SUM(`od_amount`) AS `od_amount`, MIN(UNIX_TIMESTAMP(`or_date`)) AS `or_date` FROM `bgOrderMain` JOIN `bgOrderData` JOIN `bgProducts` WHERE `bgOrderMain`.`or_id` = `bgOrderData`.`or_id` AND `od_pr` = `pr_id` AND UNIX_TIMESTAMP(`or_date`) >= '1262322000' AND UNIX_TIMESTAMP(`or_date`) <= '1346990399' AND (`pr_id` = '415' OR `pr_id` = '1088') GROUP BY `bgProducts`.`pr_id` UNION SELECT `bgProducts`.`pr_id`, `bgProducts`.`pr_sbtcode`, `bgProducts`.`pr_sdesc`,SUM(`od_quantity`) AS `od_quantity`, SUM(`od_amount`) AS `od_amount`, MIN(UNIX_TIMESTAMP(`or_date`)) AS `or_date` FROM `npOrderMain` JOIN `npOrderData` JOIN `bgProducts` WHERE `npOrderMain`.`or_id` = `npOrderData`.`or_id` AND `od_pr` = `pr_id` AND UNIX_TIMESTAMP(`or_date`) >= '1262322000' AND UNIX_TIMESTAMP(`or_date`) <= '1346990399' AND (`pr_id` = '415' OR `pr_id` = '1088') GROUP BY `bgProducts`.`pr_id` ) TEMPTABLE3 GROUP BY pr_id; But that just gives me this: +-------+------------+--------------------------+-------------+-----------+ | pr_id | pr_sbtcode | pr_sdesc | od_quantity | od_amount +-------+------------+--------------------------+-------------+-----------+ | 415 | NP13 | Product 13 | 5 | 125 | 1088 | NPAW | Product AW | 4 | 100 +-------+------------+--------------------------+-------------+-----------+ What am I missing here??

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  • VB looping complication

    - by user1819469
    I have to come up with a program that shifts names in a text box a random amount of times. I have gotten everything up to the point where the names shifts a random amount of times. It only shifts its once, but my messagebox appears through the code as many times as the names should be shifting once i click ok. Does anyone know why the loop is not working for the name shifts. I was thinking maybe the messagebox needs to control the loop, but I have searched endlessly and cannot find how that would be done. Any suggestions or referrals to other sites would be nice thanks. My code is below. Public Class Form1 Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim RandomNumber As Integer Dim min, max As Integer Dim temp, temp2, temp3, temp4, temp5, temp6 As String Dim i As Integer min = 3 max = 11 Randomize() RandomNumber = Int((max - min + 1) * Rnd() + min) temp = n1.Text temp2 = n2.Text temp3 = n3.Text temp4 = n4.Text temp5 = n5.Text temp6 = n6.Text For i = 0 To RandomNumber - 1 n1.Text = temp6 n2.Text = temp n3.Text = temp2 n4.Text = temp3 n5.Text = temp4 n6.Text = temp5 MessageBox.Show("Shift " & i & " of " & RandomNumber & " complete") Next End Sub End Class

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  • List of running minimum values

    - by scarle88
    Given a sorted list of: new []{1, 2, -1, 3, -2, 1, 1, 2, -1, -3} I want to be able to iterate over the list and at each element return the smallest value iterated so far. So given the list above the resultant list would look like: 1 1 -1 -1 -2 -2 -2 -2 -2 -3 My rough draft code looks like: var items = new []{1, 2, -1, 3, -2, 1, 1, 2, -1, -3}; var min = items.First(); var drawdown = items.Select(i => { if(i < min) { min = i; return i; } else { return min; } }); foreach(var i in drawdown) { Console.WriteLine(i); } But this is not very elegant. Is there an easier to read (linq?) way of doing this? I looked into Aggregate but it seemed to be the wrong tool. Ultimately the list of items will be very long, in the many thousands. So good performance will be an issue to.

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  • Calculated Fields - Idiosyncracies

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved Calculated Fields and some of their Idiosyncrasies Did you try to write a calculate field formula directly into the screen? Good Luck – You’ll need it! Calculated Fields are a sophisticated OOB feature of SharePoint, so you could think that they are best left to the end users – at least to the power users. But they reach their limits before the “Professionals “do, and the tough ones come back to us anyway. Back to business; the simpler the formula, the easier it is. Still, use your favorite editor to write it, then cut it and paste it to the ridiculously small window. What about complex formulae? Write them in steps! Here is a case in point and an idiosyncrasy or two. Our welders need to be certified and recertified every two years. Some of them are certifiable…., but I digress. To be certified you need to pass an eye exam, and two more tests – test A and test B. for each of those you have an expiry date. When renewed, each expiry date is advanced by two years from the date of renewal. My users wanted a visual clue so that when the supervisor looks at the list, she’ll have a KPI symbol telling her if anything expired (Red), is going to expire within the next 90 days (Yellow) or is not to be worried about (green). Not all the dates are filled and any blank date implies a complete lack of certification in the particular requirement. Obviously, I needed to figure the minimal of these 3 dates – a simple enough formula: =MIN([Date_EyeExam], {Date_TestA], [Date_TestB]). Aha! Here is idiosyncrasy #1. When one of the dates is a null, MIN(Date1, Date2) returns the non null date. Null is construed as “Far, far away”. The funny thing is that when you compare it to Today, the null is the lesser one. So a null it is less than today, but not when MIN is calculated. Now, to me the fact that the welder does not have an exam date, is synonymous with his exam being prehistoric, or at least past due. So here is what I did: Solution: Let’s set a blank date to 1/1/1800. How will we do that? Use the IF. IF([Field] rel relValue, TrueValue, FalseValue). rel is any relationship operator <, >, <=, >=, =, <>. If the field is related to the relValue as prescribed, the “IF” returns the TrueValue, otherwise it returns the FalseValue. Thus: =IF([SomeDate]="",1/1/1800,[SomeDate]) will return 1/1/1800 if the date is blank and the date itself if not. So, using this formula, if the welder missed an exam, the returned exam date will be far in the past. It would be nice if we could take such a formula and make it into a reusable function. Alas, here is a calculated field serious shortcoming: You cannot write subs and functions!! Aha, but we can use interim calculated fields! So let’s create 3 calculated fields as follows: 1: c_DateTestA as a calculated field of the date type, with the formula:  IF([Date_TestA]="",1/1/1800,[Date_TestA]) 2: c_DateTestB as a calculated field of the date type, with the formula:  IF([Date_TestB]="",1/1/1800,[Date_TestB]) 3: c_DateEyeExam as a calculated field of the date type, with the formula:  IF([Date_EyeExam]="",1/1/1800,[Date_EyeExam]) And now use these to get c_MinDate. This is again a calculated field of type date with the formula: MIN(c_DateTestA, cDateTestB, c_DateEyeExam) Note that I missed the square parentheses. In “properly named fields – where there are no embedded spaces, we don’t need the square parentheses. I actually strongly recommend using underscores in place of spaces in all the field names in your lists. Among other things, it makes using CAML much simpler. Now, we still need to apply the KPI to this minimal date. I am going to use the available KPI graphics that come with SharePoint and are always available in your 12 hive. "/_layouts/images/kpidefault-2.gif" is the Red KPI "/_layouts/images/kpidefault-1.gif" is the Yellow KPI "/_layouts/images/kpidefault-0.gif" is the Green KPI And here is the nested IF formula that will do the trick: =IF(c_MinDate<=Today,"/_layouts/images/kpidefault-2.gif", IF(cMinDate<Today+90,"/_layouts/images/kpidefault-1.gif","/_layouts/images/kpidefault-0.gif")) Nice! BUT when I tested, it did not work! This is Idiosyncrasy #2: A calculated field based on a calculated field based on a calculated field does not work. You have to stop at two levels! Back to the drawing board: We have to reduce by one level. How? We’ll eliminate the c_DateX items in the formula and replace them with the proper IF formulae. Notice that this needs to be done with precision. You are much better off in doing it in your favorite line editor, than inside the cramped space that SharePoint gives you. So here is the result: MIN(IF([Date_TestA]="",1/1/1800,[ Date_TestA]), IF([Date_TestB]="",1/1/1800,[ Date_TestB]), 1/1/1800), IF([Date_EyeExam]="",1/1/1800,[Date_EyeExam])) Note that I bolded the parentheses and painted them red. They have to match for this formula to work. Now we can leave the KPI formula as is and test again. This time with SUCCESS! Conclusion: build the inner functions first, and then embed them inside the outer formulae. Do this as long as necessary. Use your favorite line editor. Limit yourself to 2 levels. That’s all folks! Almost! As soon as I finished doing all of the above, my users added yet another level of complexity. They added another test, a test that must be passed, but never expires and asked for yet another KPI, this time in Black to denote that any test is not just past due, but altogether missing. I just finished this. Let’s hope it ends here! And OH, the formula  =IF(c_MinDate<=Today,"/_layouts/images/kpidefault-2.gif",IF(cMinDate<Today+90,"/_layouts/images/kpidefault-1.gif","/_layouts/images/kpidefault-0.gif")) Deals with “Today” and this is a subject deserving a discussion of its own!  That’s all folks?! (and this time I mean it)

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