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  • iPad SplitView changes main navigation bar color

    - by JustinXXVII
    Weird problem: After rotating my app to portrait, picking the toolbar item and exposing the uipopovercontroller, if I rotate back to landscape, the UINavigationController on the right side (objectAtIndex:0 of the SplitView) changes the color of the navigation bar. I am not sure why. I have it set in Interface Builder to be barStyle = UIBarStyleBlackOpaque; It turns silver after it returns to landscape mode. This only happens if I rotate it to portrait, create the popover, and select something in the navigation controller, which pushes another tableViewController. Even setting the properties in the viewDidLoad method does nothing. Anyone have an idea?

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  • Rotating a UIButton with a custom image (animation)

    - by Tiago
    Hi, I'm trying to rotate a button that I've connected to the controller from the Interface Builder. I've set it's image right from Interface Builder. I'm using this code on the method that runs when I click it: [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:2.0]; [UIView setAnimationRepeatCount:5]; updateButton.transform = CGAffineTransformMakeRotation( M_PI ); [UIView commitAnimations]; But this doesn't do anything. Can this be done, or should I create the button programmatically in order to get it to rotate?

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  • Trouble with onscreen keyboard orientation in iPhone OpenGL ES application.

    - by Plumenator
    I need to take keyboard input in my OpenGL ES application, so I just created an empty UITextView and added it as a subview to the main window along with the view that presents my content. I use the UITextview to control the keyboard and it works fine in a single orientation. I then changed my code to support all orientations by rotating the OpenGL content myself based on UIDeviceOrientation notifications. To rotate the keyboard, I overrode the shouldAutoRotateInterfaceOrientation method in the UITextView's controller. But I still see that the keyboard does not rotate according to the orientation. Any clues?

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  • Why can't I retrieve UIDeviceOrientation correctly while playing a movie in MPMoviePlayerController?

    - by Zelldweller
    Everything works fine while I'm not playing anything (I'm calling beginnotifications, etc, and using the orientation to rotate my view). But after I start playing with MPMoviePlayerController every time I try a... UIDeviceOrientation orientation = [[UIDevice currentDevice] orientation]; ...orientation gets a UIDeviceOrientationUnknown. Any clue? When the movie stops everything works alright again. I need this orientation to rotate the player's window, because Im using Iphone OS 3.1 so I can't directly use the view property inside MPMovie player controller.

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  • Change Sprite Anchorpoint without moving it?

    - by Oscar Gomez
    I am trying to change my Sprite anchor point so that I can rotate over a 0.0f,0.0f anchorpoint. At first my object is rotation at the default anchor point (0.5f,0.5f). However later on I need it to rotate over a 0.0,0.0 AnchorPoint. The problem is I cannot change the anchor point and change the position accordingly, so it stays on the same position, without the object appearing to quickly move and reposition to its original point. Is there a way I can set the anchor point and the position of my Sprite at once, without it moving at all?. Thank you. -Oscar

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  • How to manipulate and print a chart in MS Excel from AppleScript?

    - by Stu Thompson
    With an existing chart in a MS Excel for Mac 2008, in AppleScript, I am trying to do two things: Rotate a 3D chart 1° Save the chart as a image (png) From what I've found on the Intertubes, it seems possible. But AppleScript's awkward verbosity and the lack of non-trivial MS Excel AppleScript examples on the web are too much for me to overcome. Just for the saving part, this is what I have so far: tell application "Microsoft Excel" activate object worksheet "iozone-16" set cht to chart object 1 of active sheet tell cht #save as chart object [picture type enumeration] [file name Unicode text] #Argh!!! end tell end tell The 'rotate 1°' task seems to involve "internal objects", but that is as far as I've gotten.

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  • images are getting clipped when Jquery animate opacity is used in IE

    - by Raja
    I use the function given below: function rotate() { //Get the first image var current = ($('div#rotator ul li.show') ? $('div#rotator ul li.show') : $('div#rotator ul li:first')); //Get next image, when it reaches the end, rotate it back to the first image var next = ((current.next().length) ? ((current.next().hasClass('show')) ? $('div#rotator ul li:first') : current.next()) : $('div#rotator ul li:first')); //Set the fade in effect for the next image, the show class has higher z-index next.css({ opacity: 0.0 }) .addClass('show') .animate({ opacity: 1.0 }, 1000); //Hide the current image current.animate({ opacity: 0.0 }, 1000) .removeClass('show'); }; It does a slide show of images. It works perfect on Firefox and Google Chrome but clips the images in IE 7 and IE 8. Any help is much appreciated. Thanks in advance.

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  • OpenGL ES view: how to orient it to landscape?

    - by Steph Thirion
    Looking for clues about orienting an OpenGL ES app in landscape, most information I found dates back from 2008, most of it refering to the early versions of the SDK. Apparently, back in the days, in the case of GL it was recommended to not rotate the view, but instead to apply the rotation as a GL transformation. Is it still the case with the current SDKs? It would be so much simpler to simply rotate the window: all the touch events would be in sync with the rotation. In other words: how to set up an OpenGL view in landscape mode?

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  • WPF, animate over container boundaries

    - by ImIan
    Hi, I'm learning WPF and have a specific goal. Imagine you have a grid (3 rows by 3 columns), and a control, say a simple blue rectangle fills the middle cell. When I click on the cell I want the square to rotate smoothly through 180 degrees. The specific issue I have at the moment is; as the rectangle rotates, it won't change its dimensions, so it will extend beyond the boundary of the cell. I don't want it to clip, i want it to appear on top, partially obscuring surrounding cells. The second part of this is, if there is one cell that fills the entire window, and I click on the blue rectangle in that cell, can I make the rectangle rotate and extend beyond the sides of the form? If that doesn't make sense, please ask. I'm finding it hard to google because I don't know the exact terms I should be using. Thank you

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  • How to find vector for the quaternion from X Y Z rotations

    - by can poyrazoglu
    I am creating a very simple project on OpenGL and I'm stuck with rotations. I am trying to rotate an object indepentdently in all 3 axes: X, Y, and Z. I've had sleepless nights due to the "gimbal lock" problem after rotating about one axis. I've then learned that quaternions would solve my problem. I've researched about quaternions and implementd it, but I havent't been able to convert my rotations to quaternions. For example, if I want to rotate around Z axis 90 degrees, I just create the {0,0,1} vector for my quaternion and rotate it around that axis 90 degrees using the code here: http://iphonedevelopment.blogspot.com/2009/06/opengl-es-from-ground-up-part-7_04.html (the most complicated matrix towards the bottom) That's ok for one vector, but, say, I first want to rotate 90 degrees around Z, then 90 degrees around X (just as an example). What vector do I need to pass in? How do I calculate that vector. I am not good with matrices and trigonometry (I know the basics and the general rules, but I'm just not a whiz) but I need to get this done. There are LOTS of tutorials about quaternions, but I seem to understand none (or they don't answer my question). I just need to learn to construct the vector for rotations around more than one axis combined. UPDATE: I've found this nice page about quaternions and decided to implement them this way: http://www.cprogramming.com/tutorial/3d/quaternions.html Here is my code for quaternion multiplication: void cube::quatmul(float* q1, float* q2, float* resultRef){ float w = q1[0]*q2[0] - q1[1]*q2[1] - q1[2]*q2[2] - q1[3]*q2[3]; float x = q1[0]*q2[1] + q1[1]*q2[0] + q1[2]*q2[3] - q1[3]*q2[2]; float y = q1[0]*q2[2] - q1[1]*q2[3] + q1[2]*q2[0] + q1[3]*q2[1]; float z = q1[0]*q2[3] + q1[1]*q2[2] - q1[2]*q2[1] + q1[3]*q2[0]; resultRef[0] = w; resultRef[1] = x; resultRef[2] = y; resultRef[3] = z; } Here is my code for applying a quaternion to my modelview matrix (I have a tmodelview variable that is my target modelview matrix): void cube::applyquat(){ float& x = quaternion[1]; float& y = quaternion[2]; float& z = quaternion[3]; float& w = quaternion[0]; float magnitude = sqrtf(w * w + x * x + y * y + z * z); if(magnitude == 0){ x = 1; w = y = z = 0; }else if(magnitude != 1){ x /= magnitude; y /= magnitude; z /= magnitude; w /= magnitude; } tmodelview[0] = 1 - (2 * y * y) - (2 * z * z); tmodelview[1] = 2 * x * y + 2 * w * z; tmodelview[2] = 2 * x * z - 2 * w * y; tmodelview[3] = 0; tmodelview[4] = 2 * x * y - 2 * w * z; tmodelview[5] = 1 - (2 * x * x) - (2 * z * z); tmodelview[6] = 2 * y * z - 2 * w * x; tmodelview[7] = 0; tmodelview[8] = 2 * x * z + 2 * w * y; tmodelview[9] = 2 * y * z + 2 * w * x; tmodelview[10] = 1 - (2 * x * x) - (2 * y * y); tmodelview[11] = 0; glMatrixMode(GL_MODELVIEW); glPushMatrix(); glLoadMatrixf(tmodelview); glMultMatrixf(modelview); glGetFloatv(GL_MODELVIEW_MATRIX, tmodelview); glPopMatrix(); } And my code for rotation (that I call externally), where quaternion is a class variable of the cube: void cube::rotatex(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = sinf(ang/2); quat[2] = 0; quat[3] = 0; quatmul(quat, quaternion, quaternion); applyquat(); } void cube::rotatey(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = 0; quat[2] = sinf(ang/2); quat[3] = 0; quatmul(quat, quaternion, quaternion); applyquat(); } void cube::rotatez(int angle){ float quat[4]; float ang = angle * PI / 180.0; quat[0] = cosf(ang / 2); quat[1] = 0; quat[2] = 0; quat[3] = sinf(ang/2); quatmul(quat, quaternion, quaternion); applyquat(); } I call, say rotatex, for 10-11 times for rotating only 1 degree, but my cube gets rotated almost 90 degrees after 10-11 times of 1 degree, which doesn't make sense. Also, after calling rotation functions in different axes, My cube gets skewed, gets 2 dimensional, and disappears (a column in modelview matrix becomes all zeros) irreversibly, which obviously shouldn't be happening with a correct implementation of the quaternions.

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  • UIButtons work when rotated right, but not when rotated left. Huh?

    - by Ben Collins
    I have a view that is added to the current view when the device is rotated to a LandscapeLeft or LandscapeRight orientation. This view has 4 buttons on it that are all connected to outlets and each have the "touch up inside" event hooked up to the same action. If rotated to a LandscapeLeft orientation, I transform my added view to rotate -90 degrees, and everything works fine. If rotated to a LandscapeRight orientation, I transform the added view to rotate 90 degrees, and the buttons don't work! Highlighting doesn't happen, and the action isn't called. I am at a bit of a loss as to why this might be. Any ideas?

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  • Rotation Matrix calculates by column not by row

    - by pinnacler
    I have a class called forest and a property called fixedPositions that stores 100 points (x,y) and they are stored 250x2 (rows x columns) in MatLab. When I select 'fixedPositions', I can click scatter and it will plot the points. Now, I want to rotate the plotted points and I have a rotation matrix that will allow me to do that. The below code should work: theta = obj.heading * pi/180; apparent = [cos(theta) -sin(theta) ; sin(theta) cos(theta)] * obj.fixedPositions; But it wont. I get this error. ??? Error using == mtimes Inner matrix dimensions must agree. Error in == landmarkslandmarks.get.apparentPositions at 22 apparent = [cos(theta) -sin(theta) ; sin(theta) cos(theta)] * obj.fixedPositions; When I alter forest.fixedPositions to store the variables 2x250 instead of 250x2, the above code will work, but it wont plot. I'm going to be plotting fixedPositions constantly in a simulation, so I'd prefer to leave it as it, and make the rotation work instead. Any ideas? Also, fixed positions, is the position of the xy points as if you were looking straight ahead. i.e. heading = 0. heading is set to 45, meaning I want to rotate points clockwise 45 degrees. Here is my code: classdef landmarks properties fixedPositions %# positions in a fixed coordinate system. [x, y] heading = 45; %# direction in which the robot is facing end properties (Dependent) apparentPositions end methods function obj = landmarks(numberOfTrees) %# randomly generates numberOfTrees amount of x,y coordinates and set %the array or matrix (not sure which) to fixedPositions obj.fixedPositions = 100 * rand([numberOfTrees,2]) .* sign(rand([numberOfTrees,2]) - 0.5); end function obj = set.apparentPositions(obj,~) theta = obj.heading * pi/180; [cos(theta) -sin(theta) ; sin(theta) cos(theta)] * obj.fixedPositions; end function apparent = get.apparentPositions(obj) %# rotate obj.positions using obj.facing to generate the output theta = obj.heading * pi/180; apparent = [cos(theta) -sin(theta) ; sin(theta) cos(theta)] * obj.fixedPositions; end end end P.S. If you change one line to this: obj.fixedPositions = 100 * rand([2,numberOfTrees]) .* sign(rand([2,numberOfTrees]) - 0.5); Everything will work fine... it just wont plot.

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  • Jquery Automatic Image Slider w/ CSS & jQuery

    - by Jacinto
    This is Automatic Image Slider w/ CSS & jQuery by Soh Tanaka I am trying to customize it to show .desc when the mouse hover overs the slider but it does not seem to work any help? //Set Default State of each portfolio piece $(".paging").show(); $(".paging a:first").addClass("active"); //Get size of images, how many there are, then determin the size of the image reel. var imageWidth = $(".window").width(); var imageSum = $(".image_reel ul.examples").size(); var imageReelWidth = imageWidth * imageSum; //Adjust the image reel to its new size $(".image_reel").css({'width' : imageReelWidth}); //Paging + Slider Function rotate = function(){ var triggerID = $active.attr("rel") - 1; //Get number of times to slide var image_reelPosition = triggerID * imageWidth; //Determines the distance the image reel needs to slide $(".paging a").removeClass('active'); //Remove all active class $active.addClass('active'); //Add active class (the $active is declared in the rotateSwitch function) //Slider Animation $(".image_reel").animate({ left: -image_reelPosition }, 500 ); }; //Rotation + Timing Event rotateSwitch = function(){ play = setInterval(function(){ //Set timer - this will repeat itself every 3 seconds $active = $('.paging a.active').next(); if ( $active.length === 0) { //If paging reaches the end... $active = $('.paging a:first'); //go back to first } rotate(); //Trigger the paging and slider function }, 7000); //Timer speed in milliseconds (3 seconds) }; rotateSwitch(); //Run function on launch //On Hover $(".image_reel").hover(function() { clearInterval(play); //Stop the rotation }, function() { rotateSwitch(); //Resume rotation }); //Hide the tooglebox when page load $(".desc").hide(); //slide up and down when hover over heading 2 $(".image_reel").hover(function(){ // slide toggle effect set to slow you can set it to fast too. $(this).next(".desc").slideToggle("slow"); return true; }); //On Click $(".paging a").click(function() { $active = $(this); //Activate the clicked paging //Reset Timer clearInterval(play); //Stop the rotation rotate(); //Trigger rotation immediately rotateSwitch(); // Resume rotation return false; //Prevent browser jump to link anchor });

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  • How do I remove those rotation artefacts from my CATiledLayer?

    - by Felix
    Hello all, I have a CATiledLayer into which I render content in the following method - (void)drawLayer:(CALayer *)layer inContext:(CGContextRef)ctx I used the QuartzDemo code to draw a pattern. This works very well until I apply a rotation transform to the layer's parentLayer (a UIView): rotated: These zigzag artefacts become worse when I start drawing lines and texts into the CATiledLayer. I applied the transform as follows (I also tried using an affine transform on the view itself): self.containerView.layer.transform = CATransform3DMakeRotation(angleRadians, 0.0f, 0.0f, 1.0f); I transform the containerView rather than the layer itself, as I have several layers in that view that I would like to rotate at the same time without changing the relative positions. I did not have problems when rotating UIImageViews in the past. Is there a way that I can rotate the CATiledLayer without these problems? Any help would be greatly appreciated. Yours, Felix

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  • UILabel reset after Autorotate

    - by MB
    Hi, I have a UILabel in a view that is set by calling a method against my view controller. The app is a TABBar app and the VC is in the MORE section. When I rotate the phone the label disappears (don't mind that) when I rotate back the label is showing all .......... (the value it is set to in the XIB) I added a line to set the label in the shouldAutoRotateToOrientation method lblProductTxt.titleLabel.text = self.productText; when autorotating what viewcontroller methods are being called. ?? the shouldAutoRotateToOrientation method doesn't get called when the VC is in the More section but when I move it it does get called but has no affect on the labeltext

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  • UINavigationController + shouldAutoRotate + no subclassing

    - by ACBurk
    I have a navigation driven app. I need that app to rotate. The UINavigationController is the root controller/view in the window. I know (and have experienced why) it is a no-no to subclass UINavigationController. I know all i have to do is insert: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return YES; } into the UINavigationController and it will rotate fine. So my question is: how do I enable rotation on the root view controller (UINavigationController) WITHOUT subclassing it?

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  • Performance Optimization for Matrix Rotation

    - by Summer_More_More_Tea
    Hello everyone: I'm now trapped by a performance optimization lab in the book "Computer System from a Programmer's Perspective" described as following: In a N*N matrix M, where N is multiple of 32, the rotate operation can be represented as: Transpose: interchange elements M(i,j) and M(j,i) Exchange rows: Row i is exchanged with row N-1-i A example for matrix rotation(N is 3 instead of 32 for simplicity): ------- ------- |1|2|3| |3|6|9| ------- ------- |4|5|6| after rotate is |2|5|8| ------- ------- |7|8|9| |1|4|7| ------- ------- A naive implementation is: #define RIDX(i,j,n) ((i)*(n)+(j)) void naive_rotate(int dim, pixel *src, pixel *dst) { int i, j; for (i = 0; i < dim; i++) for (j = 0; j < dim; j++) dst[RIDX(dim-1-j, i, dim)] = src[RIDX(i, j, dim)]; } I come up with an idea by inner-loop-unroll. The result is: Code Version Speed Up original 1x unrolled by 2 1.33x unrolled by 4 1.33x unrolled by 8 1.55x unrolled by 16 1.67x unrolled by 32 1.61x I also get a code snippet from pastebin.com that seems can solve this problem: void rotate(int dim, pixel *src, pixel *dst) { int stride = 32; int count = dim >> 5; src += dim - 1; int a1 = count; do { int a2 = dim; do { int a3 = stride; do { *dst++ = *src; src += dim; } while(--a3); src -= dim * stride + 1; dst += dim - stride; } while(--a2); src += dim * (stride + 1); dst -= dim * dim - stride; } while(--a1); } After carefully read the code, I think main idea of this solution is treat 32 rows as a data zone, and perform the rotating operation respectively. Speed up of this version is 1.85x, overwhelming all the loop-unroll version. Here are the questions: In the inner-loop-unroll version, why does increment slow down if the unrolling factor increase, especially change the unrolling factor from 8 to 16, which does not effect the same when switch from 4 to 8? Does the result have some relationship with depth of the CPU pipeline? If the answer is yes, could the degrade of increment reflect pipeline length? What is the probable reason for the optimization of data-zone version? It seems that there is no too much essential difference from the original naive version. EDIT: My test environment is Intel Centrino Duo processor and the verion of gcc is 4.4 Any advice will be highly appreciated! Kind regards!

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  • willAnimateSecondHalfOfRotationFromInterfaceOrientation not called in root view controller

    - by pJosh
    I have created the one rootviewcontroller , and then make that geosensitive by writing - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return YES; } In rootviewcontroller willAnimateSecondHalfOfRotationFromInterfaceOrientation method is called and images are resizing. I also have some views on it, but when I rotate the screen the view will be rotate but the images are not resizing though I have used the same -(void)willAnimateSecondHalfOfRotationFromInterfaceOrientation:(UIInterfaceOrientation)fromInterfaceOrientation duration:(NSTimeInterval)duration { UIInterfaceOrientation toOrientation = self.interfaceOrientation; } method but it cannot called. So, what can I do? Please help me.

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  • How to make awkward pivot of sql table in MS SQL Server 2005?

    - by Oliver
    I have to rotate a given table from an sql server but a normal pivot just doesn't work (as far as i tried). So has anybody an idea how to rotate the table into the desired format? Just to make the problem more complicated, the list of given labels can vary and it is possible that a new label name can come into at any given time. Given Data ID | Label | Numerator | Denominator | Ratio ---+-----------------+-------------+---------------+-------- 1 | LabelNameOne | 41 | 10 | 4,1 1 | LabelNameTwo | 0 | 0 | 0 1 | LabelNameThree | 21 | 10 | 2,1 1 | LabelNameFour | 15 | 10 | 1,5 2 | LabelNameOne | 19 | 19 | 1 2 | LabelNameTwo | 0 | 0 | 0 2 | LabelNameThree | 15 | 16 | 0,9375 2 | LabelNameFive | 19 | 19 | 1 2 | LabelNameSix | 17 | 17 | 1 3 | LabelNameOne | 12 | 12 | 1 3 | LabelNameTwo | 0 | 0 | 0 3 | LabelNameThree | 11 | 12 | 0,9167 3 | LabelNameFour | 12 | 12 | 1 3 | LabelNameSix | 0 | 1 | 0 Wanted result ID | ValueType | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix ---+-------------+--------------+--------------+----------------+---------------+---------------+-------------- 1 | Numerator | 41 | 0 | 21 | 15 | | 1 | Denominator | 10 | 0 | 10 | 10 | | 1 | Ratio | 4,1 | 0 | 2,1 | 1,5 | | 2 | Numerator | 19 | 0 | 15 | | 19 | 17 2 | Denominator | 19 | 0 | 16 | | 19 | 17 2 | Ratio | 1 | 0 | 0,9375 | | 1 | 1 3 | Numerator | 12 | 0 | 11 | 12 | | 0 3 | Denominator | 12 | 0 | 12 | 12 | | 1 3 | Ratio | 1 | 0 | 0,9167 | 1 | | 0

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  • UIImage Rotation

    - by Kamchatka
    I display an image in a UIImageView (within a UIScrollView) which is also stored in CoreData. In the interface, I want the user to be able to rotate the picture by 90 degrees. I also want it to be saved in CoreData. What should I rotate in the display? the scrollview, the uiimageview or the image itself? (If possible I would like the rotation to be animated) But then I also have to save the picture to CoreData. I thought about changing the image orientation but this property is readonly.

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  • Why does CGPDFPageGetDrawingTransform() crash with SIGABRT when specifying a rotation?

    - by David
    When I call CGPDFPageGetDrawingTransform() with a rotation argument, the application crashes. If I specify no rotation, there is no crash. Here is my drawLayer:inContext: method: - (void)drawLayer:(CALayer*)layer inContext:(CGContextRef)context { CGContextSetRGBFillColor(context, 1.0, 1.0, 1.0, 1.0); CGRect boundingBox = CGContextGetClipBoundingBox(context); CGContextFillRect(context, boundingBox); //convert to UIKit native coodinate system CGContextTranslateCTM(context, 0.0, self.bounds.size.height); CGContextScaleCTM(context, 1.0, -1.0); //Rotate the pdf_page CGAffineTransform pfd_transform = CGPDFPageGetDrawingTransform(self.page, kCGPDFCropBox, self.frame, 58.46f, true); CGContextSaveGState (context); CGContextConcatCTM (context, pfd_transform); CGContextClipToRect (context, self.frame); CGContextDrawPDFPage (context, self.page); CGContextRestoreGState (context); } In the long run, I would like to rotate the pdf dynamically to follow a users heading. Maybe I am going at this all wrong... Thank you for your time.

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  • How to make awkward pivot of sql table in SQL Server 2005?

    - by Oliver
    I have to rotate a given table from an SQL Server but a normal pivot just doesn't work (as far as i tried). So has anybody an idea how to rotate the table into the desired format? Just to make the problem more complicated, the list of given labels can vary and it is possible that a new label name can come into at any given time. Given Data ID | Label | Numerator | Denominator | Ratio ---+-----------------+-------------+---------------+-------- 1 | LabelNameOne | 41 | 10 | 4,1 1 | LabelNameTwo | 0 | 0 | 0 1 | LabelNameThree | 21 | 10 | 2,1 1 | LabelNameFour | 15 | 10 | 1,5 2 | LabelNameOne | 19 | 19 | 1 2 | LabelNameTwo | 0 | 0 | 0 2 | LabelNameThree | 15 | 16 | 0,9375 2 | LabelNameFive | 19 | 19 | 1 2 | LabelNameSix | 17 | 17 | 1 3 | LabelNameOne | 12 | 12 | 1 3 | LabelNameTwo | 0 | 0 | 0 3 | LabelNameThree | 11 | 12 | 0,9167 3 | LabelNameFour | 12 | 12 | 1 3 | LabelNameSix | 0 | 1 | 0 Wanted result ID | ValueType | LabelNameOne | LabelNameTwo | LabelNameThree | LabelNameFour | LabelNameFive | LabelNameSix ---+-------------+--------------+--------------+----------------+---------------+---------------+-------------- 1 | Numerator | 41 | 0 | 21 | 15 | | 1 | Denominator | 10 | 0 | 10 | 10 | | 1 | Ratio | 4,1 | 0 | 2,1 | 1,5 | | 2 | Numerator | 19 | 0 | 15 | | 19 | 17 2 | Denominator | 19 | 0 | 16 | | 19 | 17 2 | Ratio | 1 | 0 | 0,9375 | | 1 | 1 3 | Numerator | 12 | 0 | 11 | 12 | | 0 3 | Denominator | 12 | 0 | 12 | 12 | | 1 3 | Ratio | 1 | 0 | 0,9167 | 1 | | 0

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  • Change Sprite Anchorpoint without moving it?

    - by OscarMk
    Hello, I am trying to change my Sprite anchor point so that I can rotate over a 0.0f,0.0f anchorpoint. At first my object is rotation at the default anchor point (0.5f,0.5f). However later on I need it to rotate over a 0.0,0.0 AnchorPoint. The problem is I cannot change the anchor point and change the position accordingly, so it stays on the same position, without the object appearing to quickly move and reposition to its original point. Is there a way I can set the anchor point and the position of my Sprite at once, without it moving at all?. Thank you. -Oscar

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  • can not access MovieClip properties in flashDevelop

    - by numerical25
    I know there is something I am doing wrong. In my controls I have keydown events that control my hero. As of right now, I am trying to rotate my hero but he refuses to turn . Below is my Hero Class, my control class, and gameobject class. pretty much all the classes associate with the controls class. package com.Objects { import com.Objects.GameObject; /** * ... * @author Anthony Gordon */ [Embed(source='../../../bin/Assets.swf', symbol='OuterRim')] public class Hero extends GameObject { public function Hero() { } } } Here is my Controls class. This is the class where I am trying to rotate my hero but he doesnt. The keydown event does work cause I trace it. package com.Objects { import com.Objects.Hero; import flash.events.*; import flash.display.MovieClip; /** * ... * @author Anthony Gordon */ public class Controls extends GameObject { private var aKeyPress:Array; public var ship:Hero; public function Controls(ship:Hero) { this.ship = ship; IsDisplay = false; aKeyPress = new Array(); engine.sr.addEventListener(KeyboardEvent.KEY_DOWN, keyDownListener); engine.sr.addEventListener(KeyboardEvent.KEY_UP,keyUpListener); } private function keyDownListener(e:KeyboardEvent):void { //trace("down e.keyCode=" + e.keyCode); aKeyPress[e.keyCode] = true; trace(e.keyCode); } private function keyUpListener(e:KeyboardEvent):void { //trace("up e.keyCode=" + e.keyCode); aKeyPress[e.keyCode]=false; } override public function UpdateObject():void { Update(); } private function Update():void { if (aKeyPress[37])//Key press left ship.rotation += 3,trace(ship.rotation ); ///DOESNT ROtate }//End Controls } } Here is GameObject Class package com.Objects { import com.Objects.Engine; import com.Objects.IGameObject; import flash.display.MovieClip; /** * ... * @author Anthony Gordon */ public class GameObject extends MovieClip implements IGameObject { private var isdisplay:Boolean = true; private var garbage:Boolean; public static var engine:Engine; public var layer:Number = 0; public function GameObject() { } public function UpdateObject():void { } public function GarbageCollection():void { } public function set Garbage(garb:Boolean):void { garbage = garb; } public function get Garbage():Boolean { return garbage } public function get IsDisplay():Boolean { return isdisplay; } public function set IsDisplay(display:Boolean):void { isdisplay = display; } public function set Layer(l:Number):void { layer = l; } public function get Layer():Number { return layer } } }

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  • CAAnimation rotation did not give last stage?

    - by Mikhail Naimy
    hi, i am using following code to rotate the UIView through Swipe gesture .it works fine.but after rotation, it goes to beginning angle or Fromvalue.anyone can help to stop the view in last stage.if i rotate again, it must go from last stage. rotationAnimation = [CABasicAnimation animationWithKeyPath:@"transform.rotation.z"]; rotationAnimation.fromValue = [NSNumber numberWithFloat:0.0 * M_PI]; rotationAnimation.toValue = [NSNumber numberWithFloat:0.5 * M_PI]; //rotationAnimation.toValue = [NSNumber numberWithFloat: 2.5 * 3.15 ]; rotationAnimation.duration = 1.5; //rotationAnimation.cumulative = YES; rotationAnimation.removedOnCompletion = NO; rotationAnimation.repeatCount = 0.0; rotationAnimation.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionLinear]; [self.view.layer addAnimation:rotationAnimation forKey:@"rotationAnimate"];

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