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  • Filtering SQLAlchemy query on attribute_mapped_collection field of relationship

    - by bsa
    I have two classes, Tag and Hardware, defined with a simple parent-child relationship (see the full definition at the end). Now I want to filter a query on Tag using the version field in Hardware through an attribute_mapped_collection, eg: def get_tags(order_code=None, hardware_filters=None): session = Session() query = session.query(Tag) if order_code: query = query.filter(Tag.order_code == order_code) if hardware_filters: for k, v in hardware_filters.iteritems(): query = query.filter(getattr(Tag.hardware, k).version == v) return query.all() But I get: AttributeError: Neither 'InstrumentedAttribute' object nor 'Comparator' object associated with Tag.hardware has an attribute 'baseband The same thing happens if I strip it back by hard-coding the attribute, eg: query.filter(Tag.hardware.baseband.version == v) I can do it this way: query = query.filter(Tag.hardware.any(artefact=k, version=v)) But why can't I filter directly through the attribute? Class definitions class Tag(Base): __tablename__ = 'tag' tag_id = Column(Integer, primary_key=True) order_code = Column(String, nullable=False) version = Column(String, nullable=False) status = Column(String, nullable=False) comments = Column(String) hardware = relationship( "Hardware", backref="tag", collection_class=attribute_mapped_collection('artefact'), ) __table_args__ = ( UniqueConstraint('order_code', 'version'), ) class Hardware(Base): __tablename__ = 'hardware' hardware_id = Column(Integer, primary_key=True) tag_id = Column(String, ForeignKey('tag.tag_id')) product_id = Column(String, nullable=True) artefact = Column(String, nullable=False) version = Column(String, nullable=False)

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  • Rails valiation among a three model relationship

    - by Andrew
    I'm working on a three model relationship with one aspect that I'm not sure how to approach. Here's the basic relationship: class Taxonomy has_many :terms # attribute: `inclusive`, default => false end class Term belongs_to :taxonomy has_and_belongs_to_many :photos end class Photo has_and_belongs_to_many :terms end This is pretty straightforward stuff except for one thing: A Taxonomy can be either 'Inclusive' or 'Exclusive'. Exclusive means the terms are mutually exclusive, Inclusive means they're not. So, if a Taxonomy is exclusive ie. taxonomy.inclusive = false, then there can only be one term from that taxonomy attached to a given photo. Now, I can handle this on the client-side without a problem, but I am not quite sure how to set up a validation on Photos (or somewhere else) that says basically: "validate that no more than one term from an exclusive taxonomy is associated with this record." Any ideas on how to do that?

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  • Live Support Webinar for Oracle Primavera Customers

    - by karl.prutzer
    Hi all, Our Customer Support team is hosting another Live Support Webinar for Oracle Primavera customers scheduled for May 6, 2010 at 11am Eastern Time. The webinar covers the following topics. Best Practices when submitting an SR My Oracle Support Overview Support Resources - lifetime support policy, My Oracle Support Speed training resources, etc. Both the conference key for the web conference and the audio passcode for the call is... Primavera Audio Conference Details Toll Free dial in number = 1.877.808.5067 International Toll dial in number = 1.706.902.0289 Web conference link https://strtc.oracle.com/imtapp/app/sch_mtg_details.uix?mID=6761278

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  • Webcor Builders Coordinates Construction Schedules and Mitigates Potential Delays More Efficiently with Integrated Project Management

    - by Sylvie MacKenzie, PMP
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";} With more than 40 years of commercial construction experience, Webcor Builders is a leading builder of distinguished, high-profile projects, including high-rise condominiums and hotels, laboratories, healthcare centers, and public works projects. Webcor is also known for its award-winning concrete, interior construction, historic restoration, and seismic renovation work. The company has completed more than 50 million square feet of projects to date. Considering the variety and complexity of the construction projects Webcor undertakes, an integrated project management solution is critical to ensuring optimal efficiency and completing client projects on time and on budget. The company previously used a number of scheduling systems for its various building projects. These packages provided different levels of schedule detail and required schedulers, engineers, and other employees to learn multiple systems. From an IT cost and complexity perspective, the company had to manage multiple scheduling systems and pay for multiple sets of licenses. The company looked to standardize on an enterprise project management system, and selected Oracle’s Primavera P6 Enterprise Project Portfolio Management. Webcor uses the solution’s advanced capabilities to schedule complex projects, analyze delays, model and propose multiple scenarios to demonstrate and mitigate delays and cost overruns, and process that information efficiently to deliver the scheduling precision that public and private projects require. In fact, the solution was instrumental in helping the company’s expansion into public sector projects during the recent economic downturn, and with Primavera P6 in place, it can deliver the precise schedule reporting required for large public projects. With Primavera P6 in place, the company could deliver the precise scheduling and milestone reporting capabilities required for large public projects. The solution is in managing the high-profile University of California – Berkeley Memorial Stadium project. Webcor was hired as construction manager and general contractor for the stadium renovation project, which is a fast-paced project located near the seismically active Hayward Fault Zone. Due to the University of California’s football schedule, meeting the Universities deadline for the coming season placed Webcor in a situation where risk awareness and early warnings of issues would be paramount. Webcor and the extended project team needed a solution that could instantly analyze alternate scenarios to mitigate potential delays; Primavera would deliver those answers.The team would also need to enable multiple stakeholders to use an internet-based platform to access the schedule from various locations, and model complicated sequencing requirements where swift decisions would be made to keep the project on track. The schedule is an integral part of Webcor’s construction management process for the stadium project. Rather than providing the client with the industry-standard monthly update, Webcor updates the critical path method (CPM) schedule on a weekly basis. The project team also reviews the schedule and updates weekly to confirm that progress and forecasted performance are accurate. Hired by the University for their ability to deliver in high risk environments The Webcor team was hit recently with a design supplement that could have added up to 70 days to the project. Using Oracle Primavera P6 the team sprung into action analyzing multiple “what if” scenarios to review mitigation means and methods.  Determined to make sure the Bears could take the field in the coming season the project team nearly eliminated the impact with their creative analysis in working the schedule. The total time from the issuance of the final design supplement to an agreed mitigation response was less than one week; leveraging the Oracle Primavera solution Webcor was able to deliver superior customer value With the ability to efficiently manage projects and schedules, Webcor can ensure it completes its projects on time and on budget, as well as inform clients about what changes to plans will mean in terms of delays and additional costs. Read the complete customer case study at :  http://www.oracle.com/us/corporate/customers/customersearch/webcor-builders-1-primavera-ss-1639886.html

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  • What would be the most efficient use of e-mail addresses for ecommerce

    - by user18323
    I am not sure if this is exactly the right section. What do you find the most efficient, clear and reachable use of e-mail addresses to use for the customer? I thought a standard 'sales, 'support' might work but it might look a little samey. Do users respond well when e-mails are replied by staff with named e-mail addresses such as [email protected] or a generic one? I am currently developing a small scale ecommerce website to gain some hands on insight into web retail. Any additional advice would be brilliant.

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  • BeansBinding Across Modules in a NetBeans Platform Application

    - by Geertjan
    Here's two TopComponents, each in a different NetBeans module. Let's use BeansBinding to synchronize the JTextField in TC2TopComponent with the data published by TC1TopComponent and received in TC2TopComponent by listening to the Lookup. The key to getting to the solution is to have the following in TC2TopComponent, which implements LookupListener: private BindingGroup bindingGroup = null; private AutoBinding binding = null; @Override public void resultChanged(LookupEvent le) { if (bindingGroup != null && binding != null) { bindingGroup.getBinding("customerNameBinding").unbind(); } if (!result.allInstances().isEmpty()){ Customer c = result.allInstances().iterator().next(); // put the customer into the lookup of this topcomponent, // so that it will remain in the lookup when focus changes // to this topcomponent: ic.set(Collections.singleton(c), null); bindingGroup = new BindingGroup(); binding = Bindings.createAutoBinding( // a two-way binding, i.e., a change in // one will cause a change in the other: AutoBinding.UpdateStrategy.READ_WRITE, // source: c, BeanProperty.create("name"), // target: jTextField1, BeanProperty.create("text"), // binding name: "customerNameBinding"); bindingGroup.addBinding(binding); bindingGroup.bind(); } } I must say that this solution is preferable over what I've been doing prior to getting to this solution: I would get the customer from the resultChanged, set a class-level field to that customer, add a document listener (or action listener, which is invoked when Enter is pressed) on the text field and, when a change is detected, set the new value on the customer. All that is not needed with the above bit of code. Then, in the node, make sure to use canRename, setName, and getDisplayName, so that when the user presses F2 on a node, the display name can be changed. In other words, when the user types something different in the node display name after pressing F2, the underlying customer name is changed, which happens, in the first place, because the customer name is bound to the text field's value, so that the text field's value will also change once enter is pressed on the changed node display name. Also set a PropertyChangeListener on the node (which implies you need to add property change support to the customer object), so that when the customer object changes (which happens, in the second place, via a change in the value of the text field, as defined in the binding defined above), the node display name is updated. In other words, there's still a bit of plumbing you need to include. But less than before and the nasty class-level field for storing the customer in the TC2TopComponent is no longer needed. And a listener on the text field, with a property change listener implented on the TC2TopComponent, isn't needed either. On the other hand, it's more code than I was using before and I've had to include the BeansBinding JAR, which adds a bit of overhead to my application, without much additional functionality over what I was doing originally. I'd lean towards not doing things this way. Seems quite expensive for essentially replacing a listener on a text field and a property change listener implemented on the TC2TopComponent for being notified of changes to the customer so that the text field can be updated. On the other other hand, it's kind of nice that all this listening-related code is centralized in one place now. So, here's a nice improvement over the above. Instead of listening for a customer, listen for a node, from which the customer can be obtained. Then, bind the node display name to the text field's value, so that when the user types in the text field, the node display name is updated. That saves you from having to listen in the node for changes to the customer's name. In addition to that binding, keep the previous binding, because the previous binding connects the customer name to the text field, so that when the customer display name is changed via F2 on the node, the text field will be updated. private BindingGroup bindingGroup = null; private AutoBinding nodeUpdateBinding; private AutoBinding textFieldUpdateBinding; @Override public void resultChanged(LookupEvent le) { if (bindingGroup != null && textFieldUpdateBinding != null) { bindingGroup.getBinding("textFieldUpdateBinding").unbind(); } if (bindingGroup != null && nodeUpdateBinding != null) { bindingGroup.getBinding("nodeUpdateBinding").unbind(); } if (!result.allInstances().isEmpty()) { Node n = result.allInstances().iterator().next(); Customer c = n.getLookup().lookup(Customer.class); ic.set(Collections.singleton(n), null); bindingGroup = new BindingGroup(); nodeUpdateBinding = Bindings.createAutoBinding( AutoBinding.UpdateStrategy.READ_WRITE, n, BeanProperty.create("name"), jTextField1, BeanProperty.create("text"), "nodeUpdateBinding"); bindingGroup.addBinding(nodeUpdateBinding); textFieldUpdateBinding = Bindings.createAutoBinding( AutoBinding.UpdateStrategy.READ_WRITE, c, BeanProperty.create("name"), jTextField1, BeanProperty.create("text"), "textFieldUpdateBinding"); bindingGroup.addBinding(textFieldUpdateBinding); bindingGroup.bind(); } } Now my node has no property change listener, while the customer has no property change support. As in the first bit of code, the text field doesn't have a listener either. All that listening is taken care of by the BeansBinding code.  Thanks to Toni for help with this, though he can't be blamed for anything that is wrong with it, only thanked for anything that is right with it. 

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  • Il CRM è al passo con i tempi?

    - by antonella.buonagurio(at)oracle.com
    Il Social Customer Relationship Management è nato grazie alla rivoluzione portata dal Web 2.0, un cambiamento epocale nelle modalità di comunicazione che ha aggiunto una incredibile ricchezza alle conversazioni tra aziende e consumatori. Le aziende dispongono adesso di strumenti per comprendere il proprio mercato senza precedenti, i consumatori, a loro volta, hanno il potere di utilizzare nuovi canali per esprimere le proprie esigenze e per comunicare e condividere commenti ed esperienze. Ma il Web 2.0 non è il solo fattore che impatta sulle scelte strategiche in ambito CRM  che ogni azienda deve considerare per sostenere  questo nuovo rapporto con i propri consumatori.    Vuoi scoprire quali sono le forze (o fattori) che le aziende devono considerare affinchè i processi di gestione della relazione con i clienti stiano al passo con le mutate condizioni sociali ed economiche?   Per saperne di più:   Il whitepaper realizzato da Oracle, Paul Gillin ed  IT Business Edge  ne delinea alcuni: 1.      Il Business. Come è cambiato in funzione dell'esperienza multicanale ora possible, della centralità del cliente e dei social networking che dominano le relazioni on line? 2.      La tecnologiaLe aziende oggi per guadagnare vantaggio competitivo devono dotarsi delle più innovative tecnologie per dare maggior valore al proprio business e per ridurre al minimo i costi di infrastruttura. Quali sono e quali sono gli effettivi vantaggi?   e altri ancora ...... leggendo il white paper "Is your CRM solution keeping up with the times?"

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  • Netretail's online retail operation benefits from personal contact

    - by christopher.jones
    Hot on oracle.com is a snapshot of Netretail Holding B.V. profiling their use of PHP and Oracle technology such as Oracle RAC cluster database to become a leading online retailer across Central and Eastern Europe. We've also just refreshed our key PHP Scalability and High Availability whitepaper which talks about connection pooling (DRCP) and Fast Application Notification (FAN). We brought it up to date for 11gR2 and PHP 5.3. It now includes the new 11gR2 V$CPOOL_CONN_INFO view, the new columns for DBA_CPOOL_INFO, information about LOGOFF triggers, and information about the support for Client Result Caching with DRCP. Back to Netretail. Two of their secrets to success are keeping technically up to date, and networking. That is, networking in the business sense. I had the pleasure of meeting Michal Táborský (@whizz), the Chief System Architect, when he was in California for a Velocity conference. Michal took time to visit Oracle HQ and talk with our developers about his then current architecture and future needs. I also met his manager at last year's Oracle OpenWorld conference. Having built up a relationship with us, Netretail now has access to Oracle Development staff. While this will never bypass Oracle Support (which have tools, systems etc that are needed and useful for resolving issues), it makes communication easier for some classes of questions. It helps discussions that will let us improve Oracle products, and make Netretail stronger. I like this. And there's no reason why you can't talk with us too. You know where to email me.

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  • xpath: determining if the customer has orders

    - by deostroll
    There is an xml dump of the Northwind database here. Document structure is something like: <NorthWind> <Customers></Customers> <Customers></Customers> . . . <Orders></Orders> <Orders></Orders> . . . </NorthWind> Each Customers tag will hold one customer information. Now while I select all Customers how do I furnish a field such that it indicates whether the customer has orders or not; something like a boolean field

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  • Upsides of a timebox for a customer

    - by Ivo
    So I have a customer with a potential big project that (ofcourse) does not know what they want exactly. The size of this project can be more that 4 or 5 months so that is a big risk. Thats why I want to sell a timebox. For me that takes away the risk of spending 10 months instead of 5 for the same price. The problem is that I can't comeup with good arguments to convince the customer that a timebox is better for them. Any suggestions? How do you people handle this/

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  • deliver c++ application for the final customer

    - by Nebrass
    I am working on a c++ windows application on visual studio 2010. I want to deliver my application to my customer so he can use it easly, without the obligation of installing visual runtime fx. And to be executed every where. How do I set up the installer so that the customer does not need to separately install any required Visual Studio runtime libraries? Please i want a solution for this problem, because my costumers are so far from computing, they love just "next, next, install, finish" system. Thank you for your help.

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  • Uralelektrostroy Improves Turnaround Times for Engineering and Construction Projects by Approximately 50% with Better Project Data Management

    - by Melissa Centurio Lopes
    LLC Uralelektrostroy was established in 1998, to meet the growing demand for reliable energy supply, which included the deployment and operation of a modern power grid system for Russia’s booming economy and industrial sector. To rise to the challenge, the country required a company with a strong reputation and the ability to strategically operate energy production and distribution facilities. As a renowned energy expert, Uralelektrostroy successfully embarked on the mission—focusing on the design, construction, and operation of power grids, transmission lines, and generation facilities. Today, Uralelektrostroy leads the Russian utilities industry with operations across the country, particularly in the Ural, Western Siberia, and Moscow regions. Challenges: Track work progress through all engineering project development stages with ease—from planning and start-up operations, to onsite construction and quality assurance—to enhance visibility into complex projects, such as power grid and power-transmission-line construction Implement and execute engineering projects faster—for example, designing and building power generation and distribution facilities—by better monitoring numerous local subcontractors Improve alignment of project schedules with project owners’ requirements—awarding federal and regional authorities—to avoid incurring fines for missing deadlines Solutions: Used Oracle’s Primavera P6 Enterprise Project Portfolio Management 8.1 to streamline communication with customers and subcontractors through better data management and harmonized reporting, reducing construction project implementation and turnaround times by approximately 50%, on average Enabled fast generation of work-in-progress reports that track project schedules, budgets, materials, and staffing—from approval and material procurement, to construction and delivery Reduced the number of construction sites by nearly 30% (from 35 to 25) by identifying unprofitable sites—streamlining operations at the company’s construction site network and increasing profitability Improved project visibility by enabling managers to efficiently track project status, ensuring on-time reporting and punctual project deliveries to federal customers to reduce delay penalties to zero “Oracle’s Primavera P6 Enterprise Project Portfolio Management 8.1 drastically changed the way we run our business. We’ve reduced the number of redundant assets, streamlined project implementation and execution, and improved collaboration with our customers and contractors. Overall, the Oracle deployment helped to increase our profitability.” – Roman Aleksandrovich Naumenko, Head of Information Technology, LLC Uralelektrostroy Read the complete customer snapshot here.

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  • Using SQLXML Bulk Load in .NET Environment - Error with One to Many relationship on Complex Type

    - by user331111
    Hi, I have an error when I am importing an XML file using SQLXMLBulkLoad, wondering if anyone could help. Error: Data mapping to column 'Attribute' was already found in the data. Make sure that no two schema definitions map to the same column Full files and details can be found here http://www.experts-exchange.com/Microsoft/Development/MS-SQL-Server/SQL-Server-2005/Q_26102239.html Exert from XSD: <sql:relationship name="EnvironmentDECAttributes" parent="Environment" parent-key="intEnvironmentID" child="DECAttributes" child-key="intEnvironmentID"/> <complexType name="Environment"> <sequence> <element name="ESANumber" minOccurs="0"> <annotation> <documentation> Environmentally Sensitive Area Number </documentation> </annotation> <simpleType> <restriction base="string"> <maxLength value="15"/> <whiteSpace value="collapse"/> </restriction> </simpleType> </element> <element name="Conditions" minOccurs="0" sql:relation="Conditions" sql:relationship="EnvironmentConditions"> <complexType> <sequence> <element name="Condition" type="vms:EnvironmentalConditions" minOccurs="0" maxOccurs="5"/> </sequence> </complexType> </element> <element name="DECDistrict" minOccurs="0"> <annotation> <documentation> Department of Environment &amp; Conservation District </documentation> </annotation> <simpleType> <restriction base="string"> <maxLength value="31"/> <whiteSpace value="collapse"/> </restriction> </simpleType> </element> <element name="DECAttributes" minOccurs="0" maxOccurs="1" sql:relation="DECAttributes" sql:relationship="EnvironmentDECAttributes"> <complexType> <sequence> <element name="Attribute" type="vms:DECAttributes" minOccurs="0" maxOccurs="unbounded" sql:field="Attribute"> <annotation> <documentation> Department of Environment &amp; Conservation attributes. </documentation> </annotation> </element> </sequence> </complexType> </element> </sequence> </complexType> Exert from XML: <Environment> <DECAttributes> <Attribute>WA</Attribute> <Attribute>SA</Attribute> </DECAttributes> </Environment> Any help/ comments would be appreciated Thanks C

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  • Eager/Lazy loaded member always empty with JPA one-to-many relationship

    - by Kaleb Pederson
    I have two entities, a User and Role with a one-to-many relationship from user to role. Here's what the tables look like: mysql> select * from User; +----+-------+----------+ | id | name | password | +----+-------+----------+ | 1 | admin | admin | +----+-------+----------+ 1 row in set (0.00 sec) mysql> select * from Role; +----+----------------------+---------------+----------------+ | id | description | name | summary | +----+----------------------+---------------+----------------+ | 1 | administrator's role | administrator | Administration | | 2 | editor's role | editor | Editing | +----+----------------------+---------------+----------------+ 2 rows in set (0.00 sec) And here's the join table that was created: mysql> select * from User_Role; +---------+----------+ | User_id | roles_id | +---------+----------+ | 1 | 1 | | 1 | 2 | +---------+----------+ 2 rows in set (0.00 sec) And here's the subset of orm.xml that defines the tables and relationships: <entity class="User" name="User"> <table name="User" /> <attributes> <id name="id"> <generated-value strategy="AUTO" /> </id> <basic name="name"> <column name="name" length="100" unique="true" nullable="false"/> </basic> <basic name="password"> <column length="255" nullable="false" /> </basic> <one-to-many name="roles" fetch="EAGER" target-entity="Role" /> </attributes> </entity> <entity class="Role" name="Role"> <table name="Role" /> <attributes> <id name="id"> <generated-value strategy="AUTO"/> </id> <basic name="name"> <column name="name" length="40" unique="true" nullable="false"/> </basic> <basic name="summary"> <column name="summary" length="100" nullable="false"/> </basic> <basic name="description"> <column name="description" length="255"/> </basic> </attributes> </entity> Yet, despite that, when I retrieve the admin user, I get back an empty collection. I'm using Hibernate as my JPA provider and it shows the following debug SQL: select user0_.id as id8_, user0_.name as name8_, user0_.password as password8_ from User user0_ where user0_.name=? limit ? When the one-to-many mapping is lazy loaded, that's the only query that's made. This correctly retrieves the one admin user. I changed the relationship to use eager loading and then the following query is made in addition to the above: select roles0_.User_id as User1_1_, roles0_.roles_id as roles2_1_, role1_.id as id9_0_, role1_.description as descript2_9_0_, role1_.name as name9_0_, role1_.summary as summary9_0_ from User_Role roles0_ left outer join Role role1_ on roles0_.roles_id=role1_.id where roles0_.User_id=? Which results in the following results: +----------+-----------+--------+----------------------+---------------+----------------+ | User1_1_ | roles2_1_ | id9_0_ | descript2_9_0_ | name9_0_ | summary9_0_ | +----------+-----------+--------+----------------------+---------------+----------------+ | 1 | 1 | 1 | administrator's role | administrator | Administration | | 1 | 2 | 2 | editor's role | editor | Editing | +----------+-----------+--------+----------------------+---------------+----------------+ 2 rows in set (0.00 sec) Hibernate obviously knows about the roles, yet getRoles() still returns an empty collection. Hibernate also recognized the relationship sufficiently to put the data in the first place. What problems can cause these symptoms?

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  • How do I code this relationship in SQLAlchemy?

    - by Martin Del Vecchio
    I am new to SQLAlchemy (and SQL, for that matter). I can't figure out how to code the idea I have in my head. I am creating a database of performance-test results. A test run consists of a test type and a number (this is class TestRun below) A test suite consists the version string of the software being tested, and one or more TestRun objects (this is class TestSuite below). A test version consists of all test suites with the given version name. Here is my code, as simple as I can make it: from sqlalchemy import * from sqlalchemy.ext.declarative import declarative_base from sqlalchemy.orm import relationship, backref, sessionmaker Base = declarative_base() class TestVersion (Base): __tablename__ = 'versions' id = Column (Integer, primary_key=True) version_name = Column (String) def __init__ (self, version_name): self.version_name = version_name class TestRun (Base): __tablename__ = 'runs' id = Column (Integer, primary_key=True) suite_directory = Column (String, ForeignKey ('suites.directory')) suite = relationship ('TestSuite', backref=backref ('runs', order_by=id)) test_type = Column (String) rate = Column (Integer) def __init__ (self, test_type, rate): self.test_type = test_type self.rate = rate class TestSuite (Base): __tablename__ = 'suites' directory = Column (String, primary_key=True) version_id = Column (Integer, ForeignKey ('versions.id')) version_ref = relationship ('TestVersion', backref=backref ('suites', order_by=directory)) version_name = Column (String) def __init__ (self, directory, version_name): self.directory = directory self.version_name = version_name # Create a v1.0 suite suite1 = TestSuite ('dir1', 'v1.0') suite1.runs.append (TestRun ('test1', 100)) suite1.runs.append (TestRun ('test2', 200)) # Create a another v1.0 suite suite2 = TestSuite ('dir2', 'v1.0') suite2.runs.append (TestRun ('test1', 101)) suite2.runs.append (TestRun ('test2', 201)) # Create another suite suite3 = TestSuite ('dir3', 'v2.0') suite3.runs.append (TestRun ('test1', 102)) suite3.runs.append (TestRun ('test2', 202)) # Create the in-memory database engine = create_engine ('sqlite://') Session = sessionmaker (bind=engine) session = Session() Base.metadata.create_all (engine) # Add the suites in version1 = TestVersion (suite1.version_name) version1.suites.append (suite1) session.add (suite1) version2 = TestVersion (suite2.version_name) version2.suites.append (suite2) session.add (suite2) version3 = TestVersion (suite3.version_name) version3.suites.append (suite3) session.add (suite3) session.commit() # Query the suites for suite in session.query (TestSuite).order_by (TestSuite.directory): print "\nSuite directory %s, version %s has %d test runs:" % (suite.directory, suite.version_name, len (suite.runs)) for run in suite.runs: print " Test '%s', result %d" % (run.test_type, run.rate) # Query the versions for version in session.query (TestVersion).order_by (TestVersion.version_name): print "\nVersion %s has %d test suites:" % (version.version_name, len (version.suites)) for suite in version.suites: print " Suite directory %s, version %s has %d test runs:" % (suite.directory, suite.version_name, len (suite.runs)) for run in suite.runs: print " Test '%s', result %d" % (run.test_type, run.rate) The output of this program: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 Version v1.0 has 1 test suites: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Version v1.0 has 1 test suites: Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Version v2.0 has 1 test suites: Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 This is not correct, since there are two TestVersion objects with the name 'v1.0'. I hacked my way around this by adding a private list of TestVersion objects, and a function to find a matching one: versions = [] def find_or_create_version (version_name): # Find existing for version in versions: if version.version_name == version_name: return (version) # Create new version = TestVersion (version_name) versions.append (version) return (version) Then I modified my code that adds the records to use it: # Add the suites in version1 = find_or_create_version (suite1.version_name) version1.suites.append (suite1) session.add (suite1) version2 = find_or_create_version (suite2.version_name) version2.suites.append (suite2) session.add (suite2) version3 = find_or_create_version (suite3.version_name) version3.suites.append (suite3) session.add (suite3) Now the output is what I want: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 Version v1.0 has 2 test suites: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Version v2.0 has 1 test suites: Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 This feels wrong to me; it doesn't feel right that I am manually keeping track of the unique version names, and manually adding the suites to the appropriate TestVersion objects. Is this code even close to being correct? And what happens when I'm not building the entire database from scratch, as in this example. If the database already exists, do I have to query the database's TestVersion table to discover the unique version names? Thanks in advance. I know this is a lot of code to wade through, and I appreciate the help.

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  • Linq 2 SQL One to Zero or One relationship possible?

    - by Mr. Flibble
    Is it possible to create a one to zero or one relationship in Linq2SQL? My understanding is that to create a one to one relationship you create a FK relationship on the PK of each table. But you cannot make the PK nullable, so I don't see how to make a one to zero or one relationship work? I'm using the designer to automatically create the model - so I would like to know how to set up the SQL tables to induce the relationship - not some custom ORM code.

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  • How do you model roles / relationships with Domain Driven Design in mind?

    - by kitsune
    If I have three entities, Project, ProjectRole and Person, where a Person can be a member of different Projects and be in different Project Roles (such as "Project Lead", or "Project Member") - how would you model such a relationship? In the database, I currently have the following tablers: Project, Person, ProjectRole Project_Person with PersonId & ProjectId as PK and a ProjectRoleId as a FK Relationship. I'm really at a loss here since all domain models I come up with seem to break some "DDD" rule. Are there any 'standards' for this problem? I had a look at a Streamlined Object Modeling and there is an example what a Project and ProjectMember would look like, but AddProjectMember() in Project would call ProjectMember.AddProject(). So Project has a List of ProjectMembers, and each ProjectMember in return has a reference to the Project. Looks a bit convoluted to me. update After reading more about this subject, I will try the following: There are distinct roles, or better, model relationships, that are of a certain role type within my domain. For instance, ProjectMember is a distinct role that tells us something about the relationship a Person plays within a Project. It contains a ProjectMembershipType that tells us more about the Role it will play. I do know for certain that persons will have to play roles inside a project, so I will model that relationship. ProjectMembershipTypes can be created and modified. These can be "Project Leader", "Developer", "External Adviser", or something different. A person can have many roles inside a project, and these roles can start and end at a certain date. Such relationships are modeled by the class ProjectMember. public class ProjectMember : IRole { public virtual int ProjectMemberId { get; set; } public virtual ProjectMembershipType ProjectMembershipType { get; set; } public virtual Person Person { get; set; } public virtual Project Project { get; set; } public virtual DateTime From { get; set; } public virtual DateTime Thru { get; set; } // etc... } ProjectMembershipType: ie. "Project Manager", "Developer", "Adviser" public class ProjectMembershipType : IRoleType { public virtual int ProjectMembershipTypeId { get; set; } public virtual string Name { get; set; } public virtual string Description { get; set; } // etc... }

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  • mysql Delete and Database Relationships

    - by Colin
    If I'm trying to delete multiple rows from a table and one of those rows can't be deleted because of a database relationship, what will happen? Will the rows that aren't constrained by a relationship still be deleted? Or will the entire delete fail? Thanks, Colin

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  • Is It possible to use the second part of this code for repository patterns and generics

    - by newToCSharp
    Is there any issues in using version 2,to get the same results as version 1. Or is this just bad coding. Any Ideas public class Customer { public int CustomerID { get; set; } public string EmailAddress { get; set; } int Age { get; set; } } public interface ICustomer { void AddNewCustomer(Customer Customer); void AddNewCustomer(string EmailAddress, int Age); void RemoveCustomer(Customer Customer); } public class BALCustomer { private readonly ICustomer dalCustomer; public BALCustomer(ICustomer dalCustomer) { this.dalCustomer = dalCustomer; } public void Add_A_New_Customer(Customer Customer) { dalCustomer.AddNewCustomer(Customer); } public void Remove_A_Existing_Customer(Customer Customer) { dalCustomer.RemoveCustomer(Customer); } } public class CustomerDataAccess : ICustomer { public void AddNewCustomer(Customer Customer) { // MAKE DB CONNECTION AND EXECUTE throw new NotImplementedException(); } public void AddNewCustomer(string EmailAddress, int Age) { // MAKE DB CONNECTION AND EXECUTE throw new NotImplementedException(); } public void RemoveCustomer(Customer Customer) { // MAKE DB CONNECTION AND EXECUTE throw new NotImplementedException(); } } // VERSION 2 public class Customer_New : DataRespository<CustomerDataAccess> { public int CustomerID { get; set; } public string EmailAddress { get; set; } public int Age { get; set; } } public class DataRespository<T> where T:class,new() { private T item = new T(); public T Execute { get { return item; } set { item = value; } } public void Update() { //TO BE CODED } public void Save() { //TO BE CODED } public void Remove() { //TO BE CODED } } class Program { static void Main(string[] args) { Customer_New cus = new Customer_New() { Age = 10, EmailAddress = "[email protected]" }; cus.Save(); cus.Execute.RemoveCustomer(new Customer()); // Repository Version Customer customer = new Customer() { EmailAddress = "[email protected]", CustomerID = 10 }; BALCustomer bal = new BALCustomer(new CustomerDataAccess()); bal.Add_A_New_Customer(customer); } } }

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  • Spring-Hibernate: How to submit a for when the object has one-to-many relations?

    - by Czar
    Hi, I have a form changeed the properties of my object CUSTOMER. Each customer has related ORDERS. The ORDER's table has a column customer_id which is used for the mapping. All works so far, I can read customers without any problem. When I now e.g. change the name of the CUSTOMER in the form (which does NOT show the orders), after saving the name is updated, but all relations in the ORDERS table are set to NULL (the customer_id for the items is set to NULL. How can I keep the relationship working? THX

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  • Getting fields_for and accepts_nested_attributes_for to work with a belongs_to relationship

    - by Billy Gray
    I cannot seem to get a nested form to generate in a rails view for a belongs_to relationship using the new accepts_nested_attributes_for facility of Rails 2.3. I did check out many of the resources available and it looks like my code should be working, but fields_for explodes on me, and I suspect that it has something to do with how I have the nested models configured. The error I hit is a common one that can have many causes: '@account[owner]' is not allowed as an instance variable name Here are the two models involved: class Account < ActiveRecord::Base # Relationships belongs_to :owner, :class_name => 'User', :foreign_key => 'owner_id' accepts_nested_attributes_for :owner has_many :users end class User < ActiveRecord::Base belongs_to :account end Perhaps this is where I am doing it 'rong', as an Account can have an 'owner', and may 'users', but a user only has one 'account', based on the user model account_id key. This is the view code in new.html.haml that blows up on me: - form_for :account, :url => account_path do |account| = account.text_field :name - account.fields_for :owner do |owner| = owner.text_field :name And this is the controller code for the new action: class AccountsController < ApplicationController # GET /account/new def new @account = Account.new end end When I try to load /account/new I get the following exception: NameError in Accounts#new Showing app/views/accounts/new.html.haml where line #63 raised: @account[owner] is not allowed as an instance variable name If I try to use the mysterious 'build' method, it just bombs out in the controller, perhaps because build is just for multi-record relationships: class AccountsController < ApplicationController # GET /account/new def new @account = Account.new @account.owner.build end end You have a nil object when you didn't expect it! The error occurred while evaluating nil.build If I try to set this up using @account.owner_attributes = {} in the controller, or @account.owner = User.new, I'm back to the original error, "@account[owner] is not allowed as an instance variable name". Does anybody else have the new accepts_nested_attributes_for method working with a belongs_to relationship? Is there something special or different you have to do? All the official examples and sample code (like the great stuff over at Ryans Scraps) is concerned with multi-record associations.

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  • Displaying Many-To-Many Database relationship in VB.NET 2008 with DataGrid, MS SQL 2008

    - by user337501
    Computer bombed while posting this, couldnt find a duplicate question but if there is one, forgive me. So, I've run into a wall. And rather than use a ladder to avoid it, I'd like go through it. I'm setting up what I can best describe as a many-to-many relationship in a database. To examplify, imagine I have three primary tables: Items, Categories, Sections(nevermind the potential redundancy) Then I have another table, Properties. Items, Categories, and Sections can be associated with many properties. A single property can be associated with one, all, or none of the other tables. The best way I can figure to do this is to have join tables make the relationship. i.e. tblItems----(Foreign Key)----tblItems_To_Properties----(Foreign Key)----tblProperties In this example, tblItems simply has an "ItemID" Primary Key. tblItems_To_Properties has its own Primary Key(tblItems_To_PropertiesID), a Foreign Key to the Item(ItemID) and a Foreign key to the Property(PropertyID). The Properties table simply has its primary key(PropertyID) I hope this example isnt too confusing...if I have to I can find a way to put a diagram up or something. My problem is, I want to display this in a DataGrid using the Master-Detail method(DevExpress GridControl). I use the tblItems as a test, and I can see the Items in the parent view, but in the child view I see(understandably) the join table and that is it. My goal is to make it so the Grid ignores the join table and shows the Properties table as the only child. Any help on this method or insight into another solution would be muuuuuuuch appreciat

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  • Fluent NHibernate - Cascade delete a child object when no explicit parent->child relationship exists

    - by John Price
    I've got an application that keeps track of (for the sake of an example) what drinks are available at a given restaurant. My domain model looks like: class Restaurant { public IEnumerable<RestaurantDrink> GetRestaurantDrinks() { ... } //other various properties } class RestaurantDrink { public Restaurant Restaurant { get; set; } public Drink { get; set; } public string DrinkVariety { get; set; } //"fountain drink", "bottled", etc. //other various properties } class Drink { public string Name { get; set; } public string Manufacturer { get; set; } //other various properties } My db schema is (I hope) about what you'd expect; "RestaurantDrinks" is essentially a mapping table between Restaurants and Drinks with some extra properties (like "DrinkVariety" tacked on). Using Fluent NHibernate to set up mappings, I've set up a "HasMany" relationship from Restaurants to RestaurantDrinks that causes the latter to be deleted when its parent Restaurant is deleted. My question is, given that "Drink" does not have any property on it that explicitly references RestaurantDrinks (the relationship only exists in the underlying database), can I set up a mapping that will cause RestaurantDrinks to be deleted if their associated Drink is deleted? Update: I've been trying to set up the mapping from the "RestaurantDrink" end of things using References(x => x.Drink) .Column("DrinkId") .Cascade.All(); But this doesn't seem to work (I still get an FK violation when deleting a Drink).

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  • CakePHP belongsTo relationship with a variable 'model' field.

    - by gomezuk
    I've got a problem with a belongsTo relationship in CakePHP. I've got an "Action" model that uses the "actions" table and belongs to one of two other models, either "Transaction" or "Tag". The idea being that whenever a user completes a transaction or adds a tag, the action model is created to keep a log of it. I've got that part working, whenever a Transaction or Tag is saved, the aftersave() method also adds an Action record. The problem comes when I try to do a find('all') on the Action model, the related Transaction or Tag record is not being returned. actions: id model model_id created I thought I could use the "conditions" parameter in the belongsTo relationship like this: <?php class Action extends AppModel { var $name = 'Action'; var $actsAs = array('Containable'); var $belongsTo = array( 'Transaction' => array( 'foreignKey' => 'model_id', 'conditions' => array("Action.model"=>"Transaction") ), 'User' => array( 'fields' => array('User.username') ), 'Recommendation' => array( 'conditions' => array("Action.model"=>"Recommendation"), 'foreignKey' => 'model_id' ) ); } ?> But that doesn't work. Am I missing something here, are my relationships wrong (I suspect so)? After Googling this problem I cam across something called Polymorphic Behaviour but I'm not sure this will help me.

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