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• what is value of x for load and store

  - by Kevinniceguy

  This is some challenge On a single processor system, in which load and store are assumed to be atomic, what are all the possible values for x after both threads have completed in the following execution, assuming that x is initialised to O? Hint: you need to consider how this code might be compiled into machine language. for (int i = 0; i < 5; i++) : x = x + 1; for (int j = 0; j < 5; j++) : x = x + 1;

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• JRadio Menu buttons - JAVA

  - by user337465

  I have a relatively easy question. I have to create a java GUI to do math based calculations. I have to have a menu item that will double the variable that I am doing calculations with. For example variable = 1 if radio button = selected{ variable = variable * 2 } So, how would I achieve the if statement there? thankyou

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• speech recognition project

  - by sk

  hello im making my final year project i.e. speech recognition.but i dont have nay idea how to start.i will use c#.plz can anyone guide me how to start.what shoul be the first step? thnx

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• i see the file but when i open it nothing is in it in c++ i/o stream and dont know why

  - by user320950

  #include<iostream> #include<fstream> #include<cstdlib> #include<iomanip> using namespace std; int main() { ifstream in_stream; // reads ITEMSLIST.txt ofstream out_stream1; // writes in listWititems.txt ifstream in_stream2; // reads PRICELIST.txt ofstream out_stream3;// writes in listWitprices.txt ifstream in_stream4;// read display.txt ofstream out_stream5;// write showitems.txt double p1=0.0,p2=0.0; int wrong=0; int count =0; char next; in_stream.open("ITEMLIST.txt", ios::in); // list of avaliable items /*if( in_stream.fail() )// check to see if itemlist.txt is open { wrong++; // counts number of errors cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream1.open("listWititems.txt", ios::out); // list of avaliable items /* if( out_stream1.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream2.open("PRICELIST.txt", ios::in); /*if( in_stream2.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream3.open("listWitdollars.txt", ios::out); /*if( out_stream3.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ in_stream4.open("display.txt", ios::in); /*if( in_stream4.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; } */ out_stream5.open("showitems.txt", ios::out); /*if( out_stream5.fail() )// check to see if itemlist.txt is open { wrong++; cout << " the error occured here0, you have " << wrong++ << " errors" << endl; cout << "Error opening the file\n" << endl; exit(1); } else{ cout << " System ran correctly " << endl; }*/ in_stream.setf(ios::fixed); while(!in_stream.eof()) // reads to end of file and gets p1 which is itemnum, clears and gets next character { in_stream >> p1; cin.clear(); cin >> next; } out_stream1.setf(ios::fixed); while (!out_stream1.eof()) { out_stream1 << p1; cin.clear(); cin >> next; } in_stream2.setf(ios::fixed); in_stream2.setf(ios::showpoint); in_stream2.precision(2); while(!in_stream2.eof()) // reads file to end of file { in_stream2 >> p1 >> p2 >> count; // gets p1,p2, and count which is current total in_stream2 >> p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } out_stream3.setf(ios::fixed); out_stream3.setf(ios::showpoint); out_stream3.precision(2); while(!out_stream3.eof()) // reads file to end of file { out_stream3 << p1 << p2 << count; out_stream3 << p2; p1 += p2; p2++; cin.clear(); // allows more reading cin >> next; return p1, p2; } in_stream4.setf(ios::fixed); in_stream4.setf(ios::showpoint); in_stream4.precision(2); while (!in_stream4.eof()) { in_stream4 >> p1 >> p2 >> count; cin.clear(); cin >> next; } out_stream5.setf(ios::fixed); out_stream5.setf(ios::showpoint); out_stream5.precision(2); out_stream5 <<setw(5)<< " itemnum " <<setw(5)<<" price "<<setw(5)<<" curr_total " <<endl; // sends items and prices to receipt.txt out_stream5 << setw(5) << p1 << setw(5) <<p2 << setw(5)<< count; // sends items and prices to receipt.txt out_stream5 << " You have a total of " << wrong++ << " errors " << endl; in_stream.close(); // closing files. out_stream1.close(); in_stream2.close(); out_stream3.close(); in_stream4.close(); out_stream5.close(); system("pause"); }

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• help in security assignment

  - by scatman

  i have to write a program that sniffs network packets (part1-the simple part). and i have to update the program (part2) so that it will be able to terminate connections. the specific requirements are: construct raw packets by specifying data link layer and network layer information including appropriate source and destination MAC and IP addresses. These packets are intended to terminate the connection. To do so, you should used SOCK_RAW as the socket type to be able to set the header information by yourself. can anybody give me some ideas on the second part? should i hijack the session,apply a dos attack on one of the users?? all i need is some tips of how to terminate the connection. i am using c programming language. and this is a course assignment for the security course.

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• re.sub emptying list

  - by jmau5

  def process_dialect_translation_rules(): # Read in lines from the text file specified in sys.argv[1], stripping away # excess whitespace and discarding comments (lines that start with '##'). f_lines = [line.strip() for line in open(sys.argv[1], 'r').readlines()] f_lines = filter(lambda line: not re.match(r'##', line), f_lines) # Remove any occurances of the pattern '\s*<=>\s*'. This leaves us with a # list of lists. Each 2nd level list has two elements: the value to be # translated from and the value to be translated to. Use the sub function # from the re module to get rid of those pesky asterisks. f_lines = [re.split(r'\s*<=>\s*', line) for line in f_lines] f_lines = [re.sub(r'"', '', elem) for elem in line for line in f_lines] This function should take the lines from a file and perform some operations on the lines, such as removing any lines that begin with ##. Another operation that I wish to perform is to remove the quotation marks around the words in the line. However, when the final line of this script runs, f_lines becomes an empty lines. What happened? Requested lines of original file: ## English-Geek Reversible Translation File #1 ## (Moderate Geek) ## Created by Todd WAreham, October 2009 "TV show" <=> "STAR TREK" "food" <=> "pizza" "drink" <=> "Red Bull" "computer" <=> "TRS 80" "girlfriend" <=> "significant other"

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• C programming - How to print numbers with a decimal component using only loops?

  - by californiagrown

  I'm currently taking a basic intro to C programming class, and for our current assignment I am to write a program to convert the number of kilometers to miles using loops--no if-else, switch statements, or any other construct we haven't learned yet are allowed. So basically we can only use loops and some operators. The program will generate three identical tables (starting from 1 kilometer through the input value) for one number input using the while loop for the first set of calculations, the for loop for the second, and the do loop for the third. I've written the entire program, however I'm having a bit of a problem with getting it to recognize an input with a decimal component. Here is what I have for the while loop conversions: #include <stdio.h> #define KM_TO_MILE .62 main (void) { double km, mi, count; printf ("This program converts kilometers to miles.\n"); do { printf ("\nEnter a positive non-zero number"); printf (" of kilometers of the race: "); scanf ("%lf", &km); getchar(); }while (km <= 1); printf ("\n KILOMETERS MILES (while loop)\n"); printf (" ========== =====\n"); count = 1; while (count <= km) { mi = KM_TO_MILE * count; printf ("%8.3lf %14.3lf\n", count, mi); ++count; } getchar(); } The code reads in and converts integers fine, but because the increment only increases by 1 it won't print a number with a decimal component (e.g. 3.2, 22.6, etc.). Can someone point me in the right direction on this? I'd really appreciate any help! :)

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• from loop to Nested loops ?

  - by WM

  I have this program that returns a factorial of N. For example, when entering 4,,, it will give 1! , 2! , 3! How could I convert this to use nested loops? public class OneForLoop { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a number : "); int N = input.nextInt(); int factorial = 1; for(int i = 1; i < N; i++) { factorial *= i; System.out.println(i + "! = " + factorial); } } }

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• Problem with python class

  - by Tasbeer

  Hi I am new to Python and as a part of my assignment I have written the following class import nltk.stem.api class BanglaStemmer(nltk.stem.api.StemmerI): suffixList = ['\xef\xbb\xbf\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x87\xe0\xa6\x9b\n', '\xe0\xa6\xbf\xe0\xa7\x9f\xe0\xa7\x8b\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa7\x87\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa7\x87\xe0\xa6\x9b\n', '\xe0\xa6\xa4\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\xe0\xa7\x87\n', '\xe0\xa6\x9a\xe0\xa7\x8d\xe0\xa6\x9b\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb2\n', '\xe0\xa6\x9b\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\x9b\xe0\xa6\xbf\n', '\xe0\xa6\x9b\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\x9b\n', '\xe0\xa6\xa4\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa6\xa4\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xb2\xe0\xa6\xbe\xe0\xa6\xae\n', '\xe0\xa6\xb2\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xa4\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xac\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa7\x87\xe0\xa6\xa8\n', '\xe0\xa6\xbf\xe0\xa6\xb8\n', '\xe0\xa7\x81\xe0\xa6\xa8\n', '\xe0\xa7\x81\xe0\xa6\x95\n', '\xe0\xa6\xb2\xe0\xa7\x87\n', '\xe0\xa6\xac\xe0\xa7\x87\n', '\xe0\xa6\xb2\xe0\xa6\xbf\n', '\xe0\xa6\xac\xe0\xa6\xbf\n', '\xe0\xa6\xa4\xe0\xa6\xbf\n', '\xe0\xa6\xb2\n', '\xe0\xa6\xa4\n', '\xe0\xa7\x8b\n', '\xe0\xa6\xbf\n', '\xe0\xa7\x87\n', '\xe0\xa7\x8d\n', '\xe0\xa6\x87\n', '\xe0\xa6\xac\n', '\xe0\xa6\xb8\n', '\xe0\xa6\xa8\n', '\xe0\xa6\x95\n', '\xe0\xa6\x93\n', '\xe0\xa7\x9f\n'] def stem(self,token): for suffix in suffixList: if token.endswith(suffix): return token[:-len(suffix)] return token The problem is that when I try to compile run it by creating an instance and calling the stem() function with a parameter , it says that the suffixList is not defined. Couldn't figure out what's the problem. Is there a different way in which the class variables have to be declared ? please help

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• C++ String manipulation isn't making sense to me...

  - by Andrew Bolster

  I am trying some of the Stanford SEE courses online to learn some new languages; this particular assignment has to do with removing substrings from strings. What I've got so far is below, but if text = "hello hello" and remove ="el", it gets stuck in a loop, but if i change text to text = "hello hllo", it works, making me think I'm doing something obviously stupid. There is a stipulation in the assignment not to modify the incoming strings, and instead to return a new string. string CensorString1(string text, string remove){ string returned; size_t found=0, lastfound=0; found = (text.substr(lastfound,text.size())).find(remove); while (string::npos != found ){ returned += text.substr(lastfound,found); lastfound = found + remove.size(); found = (text.substr(lastfound,text.size())).find(remove); } returned += text.substr(lastfound,found); return returned; } Guidance would be appreciated :-) Thanks

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• Returning multiple aggregate functions as rows

  - by SDLFunTimes

  I need some help formulating a select statement. I need to select the total quantity shipped for each part with a distinct color. So the result should be a row with the color name and the total. Here's my schema: create table s ( sno char(5) not null, sname char(20) not null, status smallint, city char(15), primary key (sno) ); create table p ( pno char(6) not null, pname char(20) not null, color char(6), weight smallint, city char(15), primary key (pno) ); create table sp ( sno char(5) not null, pno char(6) not null, qty integer not null, primary key (sno, pno) );

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• Java - Removing duplicates in an ArrayList

  - by Will

  I'm working on a program that uses an ArrayList to store Strings. The program prompts the user with a menu and allows the user to choose an operation to perform. Such operations are adding Strings to the List, printing the entries etc. What I want to be able to do is create a method called removeDuplicates().This method will search the ArrayList and remove any duplicated values. I want to leave one instance of the duplicated value(s) within the list. I also want this method to return the total number of duplicates removed. I've been trying to use nested loops to accomplish this but I've been running into trouble because when entries get deleted, the indexing of the ArrayList gets altered and things don't work as they should. I know conceptually what I need to do but I'm having trouble implementing this idea in code. Here is some pseudo code: start with first entry; check each subsequent entry in the list and see if it matches the first entry; remove each subsequent entry in the list that matches the first entry; after all entries have been examined, move on to the second entry; check each entry in the list and see if it matches the second entry; remove each entry in the list that matches the second entry; repeat for entry in the list Here's the code I have so far: public int removeDuplicates() { int duplicates = 0; for ( int i = 0; i < strings.size(); i++ ) { for ( int j = 0; j < strings.size(); j++ ) { if ( i == j ) { // i & j refer to same entry so do nothing } else if ( strings.get( j ).equals( strings.get( i ) ) ) { strings.remove( j ); duplicates++; } } } return duplicates; }

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• why concat() is not working here? , java

  - by soma sekhar

  Consider the code below, String s = "TEST"; String s2 = s.trim(); s.concat("ING"); System.out.println("S = "+s); System.out.println("S2 = "+s2); Output obtained : S = TEST S2 = TEST BUILD SUCCESSFUL (total time: 0 seconds) Why "ING" is not concatenated?

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• Simplest way of creating java next/previous buttons

  - by Holly

  I know that when creating buttons, like next and previous, that the code can be somewhat long to get those buttons to function. My professor gave us this example to create the next button: private void jbtnNext_Click() { JOptionPane.showMessageDialog(null, "Next" ,"Button Pressed", JOptionPane.INFORMATION_MESSAGE); try { if (rset.next()) { fillTextFields(false); }else{ //Display result in a dialog box JOptionPane.showMessageDialog(null, "Not found"); } } catch (SQLException ex) { ex.printStackTrace(); } } Though, I do not really understand how that short and simple if statement is what makes the next button function. I see that the fillTextFields(false) uses a boolean value and that you need to initialize that boolean value in the beginning of the code I believe. I had put private fillTextFields boolean = false; but this does not seem to be right... I'm just hoping someone could explain it better. Thanks :)

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• How to iterate through a tree in spiral order ???

  - by Nidhi

  1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 the output in spiral order should be 1 3 2 4 5 6 7 15 14 13 12 11 10 9 8

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• How do I output the preorder traversal of a tree given the inorder and postorder tranversal?

  - by user342580

  Given the code for outputing the postorder traversal of a tree when I have the preorder and the inorder traversal in an interger array. How do I similarily get the preorder with the inorder and postorder array given? void postorder( int preorder[], int prestart, int inorder[], int inostart, int length) { if(length==0) return; //terminating condition int i; for(i=inostart; i<inostart+length; i++) if(preorder[prestart]==inorder[i])//break when found root in inorder array break; postorder(preorder, prestart+1, inorder, inostart, i-inostart); postorder(preorder, prestart+i-inostart+1, inorder, i+1, length-i+inostart-1); cout<<preorder[prestart]<<" "; } Here is the prototype for preorder() void preorder( int inorderorder[], int inostart, int postorder[], int poststart, int length)

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• Recursive Enumeration in Java

  - by Harm De Weirdt

  Hello everyone. I still have a question about Enumerations. Here's a quick sketch of the situation. I have a class Backpack that has a Hashmap content with as keys a variable of type long, and as value an ArrayList with Items. I have to write an Enumeration that iterates over the content of a Backpack. But here's the catch: in a Backpack, there can also be another Backpack. And the Enumeration should also be able to iterate over the content of a backpack that is in the backpack. (I hope you can follow, I'm not really good at explaining..) Here is the code I have: public Enumeration<Object> getEnumeration() { return new Enumeration<Object>() { private int itemsDone = 0; //I make a new array with all the values of the HashMap, so I can use //them in nextElement() Collection<Long> keysCollection = getContent().keySet(); Long [] keys = keysCollection.toArray(new Long[keysCollection.size()]); public boolean hasMoreElements() { if(itemsDone < getContent().size()) { return true; }else { return false; } } public Object nextElement() { ArrayList<Item> temporaryList= getContent().get(keys[itemsDone]); for(int i = 0; i < temporaryList.size(); i++) { if(temporaryList.get(i) instanceof Backpack) { return temporaryList.get(i).getEnumeration(); }else { return getContent().get(keys[itemsDone++]); } } } }; Will this code work decently? It's just the "return temporaryList.get(i).getEnumeration();" I'm worried about. Will the users still be able to use just the hasMoreElemens() and nextElement() like he would normally do? Any help is appreciated, Harm De Weirdt

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• delete same lines from text file by c#

  - by salamonti

  how to delete same lines in file .txt but keep one of them using c# ?

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• c program triangle [closed]

  - by Johnathon

  C program that accepts three integer values from the user representing the three sides of a triangle. echo whether the 3 numbers makes a equilateral, scalene or isosceles triangle.

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• How do you determine using stat() whether a file is a symbolic link?

  - by hora

  I basically have to write a clone of the UNIX ls command for a class, and I've got almost everything working. One thing I can't seem to figure out how to do is check whether a file is a symbolic link or not. From the man page for stat(), I see that there is a mode_t value defined, S_IFLNK. This is how I'm trying to check whether a file is a sym-link, with no luck (note, stbuf is the buffer that stat() returned the inode data into): switch(stbuf.st_mode & S_IFMT){ case S_IFLNK: printf("this is a link\n"); break; case S_IFREG: printf("this is not a link\n"); break; } My code ALWAYS prints this is not a link even if it is, and I know for a fact that the said file is a symbolic link since the actual ls command says so, plus I created the sym-link... Can anyone spot what I may be doing wrong? Thanks for the help!

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• How do you search a document for a string in c++?

  - by Jeff

  Here's my code so far: #include<iostream> #include<string> #include<fstream> using namespace std; int main() { int count = 0; string fileName; string keyWord; string word; cout << "Please make sure the document is in the same file as the program, thank you!" << endl << "Please input document name: " ; getline(cin, fileName); cout << endl; cout << "Please input the word you'd like to search for: " << endl; cin >> keyWord; cout << endl; ifstream infile(fileName.c_str()); while(infile.is_open()) { getline(cin,word); if(word == keyWord) { cout << word << endl; count++; } if(infile.eof()) { infile.close(); } } cout << count; } I'm not sure how to go to the next word, currently this infinite loops...any recommendation? Also...how do I tell it to print out the line that that word was on? Thanks in advance!

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• Optimally reducing maximum flow

  - by ArIck

  Given a parameter k, I'm trying to delete k edges from a directed graph such that the maximum flow is reduced by as much as possible. The graph has a source s and a sink t, and the capacity of each edge is one. The graph may or may not contain cycles. My proposed solution would be to first perform a topological sorting on the graph, using an algorithm that "forgives" cycles -- perhaps by ignoring edges that lead us back to the source. Then (assuming k = 1): i = 0 for each vertex u order by topological(u) for each edge (u, v) order by topological(v) descending if topological(v) > topological(u) then delete (u, v) if ++i = k then return else // edge doesn't contribute to max flow, ignore Would this work, or am I totally off-track here?

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• Questions on runtime analysis properties

  - by ryanxu

  Am I wondering if the follow are true. If f(n) is O(g(n)) and f(n) is also O(g(n)) that means f(n) is also big T(g(n)) right? Also if either of the 2 above are false, then f(n) is not big T(g(n))?

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• plane bombing problems- help

  - by peiska

  I'm training code problems, and on this one I am having problems to solve it, can you give me some tips how to solve it please. The problem is something like this: Your task is to find the sequence of points on the map that the bomber is expected to travel such that it hits all vital links. A link from A to B is vital when its absence isolates completely A from B. In other words, the only way to go from A to B (or vice versa) is via that link. Notice that if we destroy for example link (d,e), it becomes impossible to go from d to e,m,l or n in any way. A vital link can be hit at any point that lies in its segment (e.g. a hit close to d is as valid as a hit close to e). Of course, only one hit is enough to neutralize a vital link. Moreover, each bomb affects an exact circle of radius R, i.e., every segment that intersects that circle is considered hit. Due to enemy counter-attack, the plane may have to retreat at any moment, so the plane should follow, at each moment, to the closest vital link possible, even if in the end the total distance grows larger. Given all coordinates (the initial position of the plane and the nodes in the map) and the range R, you have to determine the sequence of positions in which the plane has to drop bombs. This sequence should start (takeoff) and finish (landing) at the initial position. Except for the start and finish, all the other positions have to fall exactly in a segment of the map (i.e. it should correspond to a point in a non-hit vital link segment). The coordinate system used will be UTM (Universal Transverse Mercator) northing and easting, which basically corresponds to a Euclidian perspective of the world (X=Easting; Y=Northing). Input Each input file will start with three floating point numbers indicating the X0 and Y0 coordinates of the airport and the range R. The second line contains an integer, N, indicating the number of nodes in the road network graph. Then, the next N (<10000) lines will each contain a pair of floating point numbers indicating the Xi and Yi coordinates (1 No two links will ever cross with each other. Output The program will print the sequence of coordinates (pairs of floating point numbers with exactly one decimal place), each one at a line, in the order that the plane should visit (starting and ending in the airport). Sample input 1 102.3 553.9 0.2 14 342.2 832.5 596.2 638.5 479.7 991.3 720.4 874.8 744.3 1284.1 1294.6 924.2 1467.5 659.6 1802.6 659.6 1686.2 860.7 1548.6 1111.2 1834.4 1054.8 564.4 1442.8 850.1 1460.5 1294.6 1485.1 17 1 2 1 3 2 4 3 4 4 5 4 6 6 7 7 8 8 9 8 10 9 10 10 11 6 11 5 12 5 13 12 13 13 14 Sample output 1 102.3 553.9 720.4 874.8 850.1 1460.5 102.3 553.9

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• Custom control packaging

  - by CSharpened

  Quick question: You are building a setup for your application. The application contains a custom control developed by you, which will be shared across multiple applications. How should you package the custom control? Package the control in a Merge Module (.msm) and add the .msm file to a Windows Installer project. Package the control into a cabinet project (.cab) and add the .cab file to a Windows Installer project. Create a separate directory for the control and then package it in a Windows Installer project along with the rest of the project files. Package the control as a Web setup project and create a link to that project from the Windows Installer project. Any ideas?

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