How to split the definition of template friend funtion within template class?
- by ~joke
The following example compiles fine but I can't figure out how to separate declaration and definition of operator<<() is this particular case.
Every time I try to split the definition friend is causing trouble and gcc complains the operator<<() definition must take exactly one argument.
#include <iostream>
template <typename T>
class Test {
public:
Test(const T& value) : value_(value) {}
template <typename STREAM>
friend STREAM& operator<<(STREAM& os, const Test<T>& rhs) {
os << rhs.value_;
return os;
}
private:
T value_;
};
int main() {
std::cout << Test<int>(5) << std::endl;
}
