C++0x: how to get variadic template parameters without reference?
- by Sydius
Given the following contrived (and yes, terrible) example:
template<typename... Args>
void something(Args... args)
{
std::tuple<Args...> tuple; // not initializing for sake of example
std::get<0>(tuple) = 5;
}
It works if you call it like so:
int x = 10;
something<int>(x);
However, it does not work if you call it like this:
int x = 10;
something<int&>(x);
Because of the assignment to 5. Assuming that I cannot, for whatever reason, initialize the tuple when it is defined, how might I get this to work when specifying the type as a reference?
Specifically, I would like the tuple to be std::tuple<int> even when Args... is int&.
