Search Results

Search found 32961 results on 1319 pages for 'java'.

Page 851/1319 | < Previous Page | 847 848 849 850 851 852 853 854 855 856 857 858  | Next Page >

  • Where to get streaming (live) video and audio from camera example app for Android?

    - by Ole Jak
    Where to get streaming (live) video and audio from camera example for Android? Suppose I want to create some live video streaming service app so I'll have some cool server at the back end. And I know how to do that part. Suppose I have some stand alone app for PCs now I want to go on to mobile devices. So I want to see some sample app grabing audio and video streams from Phone, Synchronizing them, encoding somehow, and sending LIVE stream to server. I need any Open-Source sample that will do this or something like this. Where can I get one?

    Read the article

  • add limited product to cart in android

    - by user1859172
    I have to develop one shopping cart app. Here i have to add the product only 5.otherwise have to display the message on alert dialog like 5 products only allowed. How can i develop this.please help me This is my code: ImageButton mImgAddCart = (ImageButton) findViewById(R.id.img_add); mImgAddCart.setOnClickListener(new OnClickListener() { public void onClick(View v) { // TODO Auto-generated method stub mTitle = txttitle.getText().toString(); mCost = text_cost_code.getText().toString(); mCost = mCost.replace("From ", ""); mTotal = txt_total.getText().toString(); mTotal = mTotal.replace("From ", ""); mQty = edit_qty_code.getText().toString(); if (Constants.mItem_Detail.size() <= 0) { HashMap<String, String> mTempObj = new HashMap<String, String>(); mTempObj.put(KEY_TITLE, mTitle); mTempObj.put(KEY_QTY, mQty); mTempObj.put(KEY_COST, mCost); mTempObj.put(KEY_TOTAL, mTotal); Constants.mItem_Detail.add(mTempObj); } else { for (int i = 0; i < Constants.mItem_Detail.size(); i++) { if (Constants.mItem_Detail.get(i).get(KEY_TITLE) .equals(mTitle)) { Constants.mItem_Detail.remove(i); break; } else { } } HashMap<String, String> mTempObj = new HashMap<String, String>(); mTempObj.put(KEY_TITLE, mTitle); mTempObj.put(KEY_QTY, mQty); mTempObj.put(KEY_COST, mCost); mTempObj.put(KEY_TOTAL, mTotal); Constants.mItem_Detail.add(mTempObj); } AlertDialog.Builder alertdialog = new AlertDialog.Builder( Small.this); alertdialog.setTitle(getResources() .getString(R.string.app_name)); alertdialog.setMessage("Add in ViewCart"); alertdialog.setPositiveButton("OK", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { // TODO Auto-generated method stub finish(); } }); alertdialog.show(); } }); How can i set the condition for this.please give me one idea.

    Read the article

  • Use HTTP PUT to create new cache (ehCache) running on the same Tomcat?

    - by socal_javaguy
    I am trying to send a HTTP PUT (in order to create a new cache and populate it with my generated JSON) to ehCache using my webservice which is on the same local tomcat instance. Am new to RESTful Web Services and am using JDK 1.6, Tomcat 7, ehCache, and JSON. I have my POJOs defined like this: Person POJO: import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class Person { private String firstName; private String lastName; private List<House> houses; // Getters & Setters } House POJO: import javax.xml.bind.annotation.XmlRootElement; @XmlRootElement public class House { private String address; private String city; private String state; // Getters & Setters } Using a PersonUtil class, I hardcoded the POJOs as follows: public class PersonUtil { public static Person getPerson() { Person person = new Person(); person.setFirstName("John"); person.setLastName("Doe"); List<House> houses = new ArrayList<House>(); House house = new House(); house.setAddress("1234 Elm Street"); house.setCity("Anytown"); house.setState("Maine"); houses.add(house); person.setHouses(houses); return person; } } Am able to create a JSON response per a GET request: @Path("") public class MyWebService{ @GET @Produces(MediaType.APPLICATION_JSON) public Person getPerson() { return PersonUtil.getPerson(); } } When deploying the war to tomcat and pointing the browser to http://localhost:8080/personservice/ Generated JSON: { "firstName" : "John", "lastName" : "Doe", "houses": [ { "address" : "1234 Elmstreet", "city" : "Anytown", "state" : "Maine" } ] } So far, so good, however, I have a different app which is running on the same tomcat instance (and has support for REST): http://localhost:8080/ehcache/rest/ While tomcat is running, I can issue a PUT like this: echo "Hello World" | curl -S -T - http://localhost:8080/ehcache/rest/hello/1 When I "GET" it like this: curl http://localhost:8080/ehcache/rest/hello/1 Will yield: Hello World What I need to do is create a POST which will put my entire Person generated JSON and create a new cache: http://localhost:8080/ehcache/rest/person And when I do a "GET" on this previous URL, it should look like this: { "firstName" : "John", "lastName" : "Doe", "houses": [ { "address" : "1234 Elmstreet", "city" : "Anytown", "state" : "Maine" } ] } So, far, this is what my PUT looks like: @PUT @Path("/ehcache/rest/person") @Produces(MediaType.APPLICATION_JSON) @Consumes(MediaType.APPLICATION_JSON) public Response createCache() { ResponseBuilder response = Response.ok(PersonUtil.getPerson(), MediaType.APPLICATION_JSON); return response.build(); } Question(s): (1) Is this the correct way to write the PUT? (2) What should I write inside the createCache() method to have it PUT my generated JSON into: http://localhost:8080/ehcache/rest/person (3) What would the command line CURL comment look like to use the PUT? Thanks for taking the time to read this...

    Read the article

  • Error in my web.xml

    - by Mercer
    Why i have an error in my web.xml when i want add servlet..? <servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>org.task.ClientServlet</servlet-class> <servlet-name>FactoryServlet</servlet-name> <servlet-class>org.task.FactoryServlet</servlet-class> <servlet-name>TraderServlet</servlet-name> <servlet-class>org.task.TraderServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> <servlet-name>FactoryServlet</servlet-name> <url-pattern>/FactoryServlet</url-pattern> <servlet-name>TraderServlet</servlet-name> <url-pattern>/TraderServlet</url-pattern> </servlet-mapping>

    Read the article

  • Spring MVC 3.0 Rest problem

    - by Gidogeek
    Hi Guys, I'm trying out Spring MVC 3.0 for the first time and like to make it RESTfull. This is my controller: @Controller @RequestMapping(value = "/product") @SessionAttributes("product") public class ProductController { @Autowired private ProductService productService; public void setProductValidator(ProductValidator productValidator, ProductService productService) { this.productService = productService; } @RequestMapping(method = RequestMethod.GET) public Product create() { //model.addAttribute(new Product()); return new Product(); } @RequestMapping(method = RequestMethod.POST) public String create(@Valid Product product, BindingResult result) { if (result.hasErrors()) { return "product/create"; } productService.add(product); return "redirect:/product/show/" + product.getId(); } @RequestMapping(value = "/show/{id}", method = RequestMethod.GET) public Product show(@PathVariable int id) { Product product = productService.getProductWithID(id); if (product == null) { //throw new ResourceNotFoundException(id); } return product; } @RequestMapping(method = RequestMethod.GET) public List<Product> list() { return productService.getProducts(); } } I have 2 questions about this. I'm a believer in Convention over Configuration and therefor my views are in jsp/product/ folder and are called create.jsp , list.jsp and show.jsp this works relatively well until I add the @PathVariable attribute. When I hit root/product/show/1 I get the following error: ../jsp/product/show/1.jsp" not found how do I tell this method to use the show.jsp view ? If I don't add the RequestMapping on class level my show method will be mapped to root/show instead of root/owner/show how do I solve this ? I'd like to avoid using the class level RequestMapping.

    Read the article

  • Tomcat startup logs - SEVERE: Error filterStart how to get a stack trace?

    - by Benju
    When I start Tomcat I get the following error: Jun 10, 2010 5:17:25 PM org.apache.catalina.core.StandardContext start SEVERE: Error filterStart Jun 10, 2010 5:17:25 PM org.apache.catalina.core.StandardContext start SEVERE: Context [/mywebapplication] startup failed due to previous errors It seems odd that the logs for Tomcat would not include a stack trace. Does somebody have a suggestion for how to increase the logging in Tomcat to get stack traces for errors like this?

    Read the article

  • Linking Apache to Tomcat with multiple domains.

    - by Royce Thigpen
    Okay, so I've been working for a while on this, and have been searching, but so far I have not found any answers that actually answer what I want to know. I'm a little bit at the end of my rope with this one, but I'm hoping I can figure this out sometime soon. So I have Apache 2 installed and serving up standard webpages, but I also have that linked to a Tomcat instance for one of my domains currently supported. However, I want to add another domain to the server via Apache that points to a separate code base from the one I already have. I have been coming at this from several different angles, and I have determined that I just don't know enough about setting up these servers to really do what I want to do. Little information on my server: Currently running a single Tomcat5.5 instance with Apache 2, using mod_jk to connect them together. I have a worker in workers.properties that points it's "host" field to "localhost" with the correct port my Tomcat instance, so that all works. In my Tomcat server.xml file, I have a host defined as "localhost" that points at my webapp that I am currently serving up, with that host set as the defaultHost as well. One thought I had was that I could add a new worker with a different host than "localhost" (i.e. host2) and then define a new host in my server.xml file called "host2" to match it, but after reading around some on the internet, It seems the "host" of the worker must point to a server, and not a hostname in the Tomcat instance, is this correct? Again, a simple rundown of what I want: Setup in apache/tomcat combo such that www.domain1.com points at "webapp1" and www.domain2.com points at "webapp2".

    Read the article

  • How to implement thread timeout in J2ME?

    - by lilo
    I am using Connector in J2ME and found that sometimes it take a very long time to send a request, and sometime it may halt the whole process. So I try to put code related to Connector in a thread and try to set timeout to the thread. But I found out that it's very difficult to do this in J2ME because there's no join(long) in J2ME. Is there any way to do this? Or any better way to deal with network connection in J2ME? Thanks a lot in advance.

    Read the article

  • Overriding a method in statically created objects

    - by I82Much
    All, Due to a bug in a library I'm using, I need to override the dispose() method on all objects extending a certain class and make it a NO-OP. I know that if I'm making new instances of the classes directly, this is easy to do: layerManager = new LayerManagerLayer(wwd) { @Override public void dispose() {} }; The problem is that a lot of the object instances I get are not directly constructed by my client code, but instead are created via static library method calls. // Here I want to override the dispose method, but I cannot. Layer l = ShapefileLoader.makeShapefileLayer(this.getClass().getResource("polylines10.shp")); Is there a way I can inject my dispose method into that statically created object without modifying the original sourcecode?

    Read the article

  • Is Catching a Null Pointer Exception a Code Smell?

    - by Drew
    Recently a co-worker of mine wrote in some code to catch a null pointer exception around an entire method, and return a single result. I pointed out how there could've been any number of reasons for the null pointer, so we changed it to a defensive check for the one result. However, catching NullPointerException just seemed wrong to me. In my mind, Null pointer exceptions are the result of bad code and not to be an expected exception in the system. Are there any cases where it makes sense to catch a null pointer exception?

    Read the article

  • How to put PrintWriter object content in to table cell

    - by user3599482
    I have a small problem about a content returning from servlet to put in table cell. In javascript I am calling servlet method using post, it returns some content and I have to put it in two different <td> cells. here is my code, In javascript, $.post('<%=request.getContextPath()%>/controller/UserLockController',{'userName':userName,'status':status}, function(data) { document.getElementById("status_"+userName).innerHTML=data; document.getElementById("td_"+userName).innerHTML=data; }); in servlet it writes as, out.println("<td id=\"status_"+inputParam+"\">Locked</td>"); out.println("<td id=\"td_"+inputParam+"\"><a href=\"#\" class=\"btn btn-sm btn-primary unlockBtn\" id=\"togBtn_"+inputParam+"\" onClick=\"LockAccount('"+inputParam+"','"+status+"')\">UnLock</td>"); Here content is returning but problem is the both <td> return from servlet will fit in single cell of html table. how to solve this please help me.

    Read the article

  • How can I set the Jbuttons in a preferred order?

    - by Umzz Mo
    I have a grid of 30 buttons, and I want to have it from left to right then goes down, right to left, down again left to right. Basically the numbering would be as follow: 1 2 3 4 5 6 7 8 9 10 20 19 18 17 16 15 14 13 12 11 21 22 23 24 25 26 27 28 29 30 So if I have a piece on the button 10 and I instruct it to move up 2 bits it would land on 12 not 19. Below is my Code: //Creates the button using the loop, adds it into the panel and frame. JPanel panel = new JPanel(); panel.setLayout(new GridLayout(3,10)); JButton [] buttons = new JButton[30]; for(int i=0;i<30;i++){ buttons[i] = new JButton("label" + i); buttons[i].setBackground(Color.white); //Puts the player 1 piece on button 1,3,5,7,9 and player 2 piece on button 2,4,6,8,10 if (i < 10) { if (i%2 == 0) { buttons[i].setIcon(piece1); } else { buttons[i].setIcon(piece2); } } panel.add(buttons[i]); } frame.add(panel, BorderLayout.CENTER);

    Read the article

  • Reflection: take values from an unknown running alpplication

    - by Dr.Lesh
    I'm writing an application that searchs for Semaphore types in the fields of unknown classes in unknown application (passed by user). I made it using Reflection and it worked. Now I want to fill up these semaphores with values, taking them from a running instance of this unknown application. So i took the class with "main" method of this unknown application, made a newInstance, and passed it when invoking the main method to start the application: Class mainClass = getItSomeWhere(); Object instance = mainClass.newInstance(); Method mainMethod = mainClass.getDeclaredMethod("main", new Class[]{String[].class}); mainMethod.invoke(instance, new Object[]{args}); and it worked fine. Now, how can I get the semaphore values, taking them from the classes of this running application, when I only have an instance of the main class? Many thanks for the answers.

    Read the article

  • How do you set a double value to a "non-value"

    - by Ankur
    I have two double data elements in an object. Sometimes they are set with a proper value and sometimes not. When the form field from which they values are received is not filled I want to set them to some value that tells me, during the rest of the code that the form fields were left empty. I can't set the values to null as that gives an error, is there some way I can make them 'Undefined'. PS. Not only am I not sure that this is possible, it might not also make sense. But if there is some best practice for such a situation I would be keen to hear it.

    Read the article

  • Can I find out which thread is running using Eclipse?

    - by Roman
    I close my application by pressing a "Close" button. But in the Eclipse I see a red square indicating that something is still running. When I press this red square, I kill my application completely. Is it possible to find out what is still running (which method, which loop) using Eclipse? P.S. I am a newbie. So, it would be nice to have a simple solution. I also might not understand your answer if you use "technical" words which I do not know.

    Read the article

  • Why do encodeXxx methods in UIComponent accept FacesContext parameter?

    - by Roman
    I haven't ever before created custom components in JSF so I've noticed only now that methods like encodeBegin(), encodeEnd() etc accept FacesContext parameter. FacesContext instance can usually be received with FacesContext.getCurrentInstance(). So, I wonder whether these methods have FacesContext parameter just for convenience or some different objects can be passed there (maybe from external resources..). If the latter is possible then could you give an example pls.

    Read the article

  • Guice expert question

    - by Roman
    Hi All I am wondering if someone would be such an expert in guice that he even would know how to implement that : I have an injection annotation (@ConfParam)with some parameters , like that : class TestClass { private final int intValue; @Inject public TestClass(@ConfParam(section = "test1", key = "1") int intValue{ this.intValue = intValue; } public int getIntValue() { return intValue; } } The ConfParam is my custom annotation. Now , when the injection value is requested , I would like guice to create a dynamic binding, to resolve the value. For that binding I will need the parameters inside the annotation. Some example could be , I will have to look in the database in some table where the section is ? and the key is ?. All the trouble is that the data is not available when the injector is created and could be also be added at runtime. Ps. I static solution is easy. ( just have a look at the Names class)

    Read the article

  • Doubt in abstract classes

    - by mohit
    public abstract class Person { private String name; public Person(String name) { this.name = name; System.out.println("Person"); } public String getName() { return name; } abstract public String getDescription(); } public class Student extends Person { private String major; public Student(String name, String major) { super(name); this.major = major; } public String getMajor() { return major; } @Override public String getDescription() { return "student" + super.getName() + " having" + major; } } public class PersonTest { public static void main(String[] args) { Person person = new Student("XYZ", "ABC"); System.out.println(person.getDescription()); } } Ques: We cannot create objects of abstract classes, then why Person Constructor has been invoked, even its an abstract class?

    Read the article

  • how to write own serializer/deserializer?

    - by joseph
    Hello, I need to save objects - instances of classes - in my app like some filetype. How I can write own serializer/deserializer for it? Or exist some easier way how to save objects to some filetype? Using of io.serialization was commented as not so good solution for "real" app. Why?

    Read the article

  • How to get all n sets of three consecutives elements in an array or arraylist with a for statement ?

    - by newba
    Hi, I'm trying to do a convex hull approach and the little problem is that I need to get all sets of three consecutive vertices, like this: private void isConvexHull(Ponto[] points) { Arrays.sort(points); for (int i = 0; i <points.length; i++) { isClockWise(points[i],points[i+1],points[i+2]); } //... } I always do something that I don't consider clean code. Could please help me find one or more ways to this? I want it to be circular, i.e., if my fisrt point of the a set is the last element in the array, the 2nd element will be the 3rd in the list and the 3rd in that set will be the the 2nd element in the list, and so on. They must be consecutive, that's all.

    Read the article

  • Why can't i create a RESTful web service in ejb module?

    - by Nitesh Panchal
    Hello, I am using Netbeans 6.8. I can see an option to create a web service in my independent ejb module but i can't seem to find an option to create a RESTful based web service in my ejb module. Is there any kind of restriction in ejb module that i can only create SOAP based web service and not RESTful? or is it the bug of Netbeans 6.8?

    Read the article

  • Using custom detectors with FindBugs Maven plugin

    - by Lóránt Pintér
    I have a nice JAR of some custom FindBugs detectors I'd like to use with the FindBugs Maven plugin. There is a way to do this with the plugin via the <pluginList> configuration parameter, but that only accepts local files, URLs, or resources. The only way I found for doing so is to somehow copy my JAR to a local file (maybe via the Dependency plugin) and then configure the FindBugs plugin something like this: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>findbugs-maven-plugin</artifactId> <version>2.3.1</version> <configuration> <pluginList>${project.build.directory}/my-detectors.jar</pluginList> </configuration> </plugin> But this is not very flexible. Is there a way to use Maven's dependency management features together with FindBugs' plugins? I'd like to use something like this: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>findbugs-maven-plugin</artifactId> <dependencies> <dependency> <groupId>com.lptr.findbugs</groupId> <artifactId>my-detectors</artifactId> <version>1.0</version> </dependency> </dependencies> </plugin> ...but this simply overrides the core FindBugs detectors.

    Read the article

  • Error in creating alias in formula tag

    - by Senthilnathan
    Hi all I have a sql query in formula tag inside property tag. In that query i am creating alias name but the hibernate appends table name and throwing me error. select sum(e.salary) as sal from employee e but hibernate changes to select sum(e.salary) as employee.sal from employee e how to avoid this .... it should recognise as sal inside of employee.sal !!!

    Read the article

< Previous Page | 847 848 849 850 851 852 853 854 855 856 857 858  | Next Page >