Search Results

Search found 390 results on 16 pages for 'cin'.

Page 4/16 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

• How to make multiple wires quickly in Verilog?

  - by user1334858

  I am trying to make 24 wires in total very quickly but I keep getting the error: Error (10170): Verilog HDL syntax error at your_ALU_mux.v(81) near text "="; expecting ".", or an identifier Here is my code: module your_ALU_mux(your_out, operandA, operandB, opcode, switches, address); input [7:0] operandA, operandB, address; input [3:0] opcode, switches; output [7:0] your_out; wire [0:7] Bnot, newb, newa; wire Cin, Cout; not (Bnot[0], operandB[0]), (Bnot[1], operandB[1]), (Bnot[2], operandB[2]), (Bnot[3], operandB[3]), (Bnot[4], operandB[4]), (Bnot[5], operandB[5]), (Bnot[6], operandB[6]), (Bnot[7], operandB[7]); // Getting A' and B' if (address == 16'h00 || address == 16'h01) // Add A + B if (address == 16'h00) // newa = A newa[0] = operandA[0]; newa[1] = operandA[1]; newa[2] = operandA[2]; newa[3] = operandA[3]; newa[4] = operandA[4]; newa[5] = operandA[5]; newa[6] = operandA[6]; newa[7] = operandA[7]; // newb = B' newb[0] = Bnot[0]; newb[1] = Bnot[1]; newb[2] = Bnot[2]; newb[3] = Bnot[3]; newb[4] = Bnot[4]; newb[5] = Bnot[5]; newb[6] = Bnot[6]; newb[7] = Bnot[7]; // Carry in = 1 Cin = 1; // A-B else if (address == 16'h01) // newb = B newb[0] = operandB[0]; newb[1] = operandB[1]; newb[2] = operandB[2]; newb[3] = operandB[3]; newb[4] = operandB[4]; newb[5] = operandB[5]; newb[6] = operandB[6]; newb[7] = operandB[7]; // newa = A newa[0] = operandA[0]; newa[1] = operandA[1]; newa[2] = operandA[2]; newa[3] = operandA[3]; newa[4] = operandA[4]; newa[5] = operandA[5]; newa[6] = operandA[6]; newa[7] = operandA[7]; // Carry in = 0 Cin = 0; end RippleCarryAdd A+B(.S0(your_out[0]), .S1(your_out[1],.S2(your_out[2],.S3(your_out[3],.S4(your_out[4],.S5(your_out[5] S6.(your_out[6]), S7.(your_out[7], .Cout(Cout),.Cin(Cin), .A0(newa[0]),.A1(newa[1]),.A2(newa[2]),.A3(newa[3]),.A4(newa[4]),.A5(newa[5]), .A6(newa[6]),.A7(newa[7]), .B0(newb[0]),.B1(newb[1]),.B2(newb[2]),.B3(newb[3]),.B4(newb[4]), .B5(newb[5]),.B6(newb[6]),.B7(newb[7])); endmodule I also get in error saying: Error (10170): Verilog HDL syntax error at your_ALU_mux.v(66) near text "if"; expecting "endmodule" And the it brings me to my first if statement. Is this the wrong way of going about creating wires and them using them?

  Read the article

• Can i use a switch to hold a function?

  - by TIMOTHY

  I have a 3 file program, basically teaching myself c++. I have an issue. I made a switch to use the math function. I need and put it in a variable, but for some reason I get a zero as a result. Also another issue, when I select 4 (divide) it crashes... Is there a reason? Main file: #include <iostream> #include "math.h" #include <string> using namespace std; int opersel; int c; int a; int b; string test; int main(){ cout << "Welcome to Math-matrix v.34"<< endl; cout << "Shall we begin?" <<endl; //ASK USER IF THEY ARE READY TO BEGIN string answer; cin >> answer; if(answer == "yes" || answer == "YES" || answer == "Yes") { cout << "excellent lets begin..." << endl; cout << "please select a operator..." << endl << endl; cout << "(1) + " << endl; cout << "(2) - " << endl; cout << "(3) * " << endl; cout << "(4) / " << endl; cin >> opersel; switch(opersel){ case 1: c = add(a,b); break; case 2: c = sub(a,b); break; case 3: c = multi(a,b); break; case 4: c = divide(a,b); break; default: cout << "error... retry" << endl; }// end retry cout << "alright, how please select first digit?" << endl; cin >> a; cout << "excellent... and your second?" << endl; cin >> b; cout << c; cin >> test; }else if (answer == "no" || answer == "NO" || answer == "No"){ }//GAME ENDS }// end of int main Here is my math.h file #ifndef MATH_H #define MATH_H int add(int a, int b); int sub(int a, int b); int multi(int a, int b); int divide(int a, int b); #endif Here is my math.cpp: int add(int a, int b) { return a + b; } int sub(int a, int b) { return a - b; } int multi(int a, int b) { return a * b; } int divide(int a, int b) { return a / b; } }// end of int main

  Read the article

• using 'new' operator

  - by notLikeCpp

  I have simple task concerning 'new' operator. I need to create array of 10 chars and then input those chars using 'cin'. Should it look like this ? : char c = new char[10]; for(int i=0; i < 10; i++) { cin >> char[i] >> endl; }

  Read the article

• Caesar Cipher Program In C++ [migrated]

  - by xaliap81

  I am trying to write a caesar cipher program in c++. This is my codes template: int chooseKEY (){ //choose key shift from 1-26 } void encrypt (char * w, char *e, int key) { //Encryption function, *w is the text in the beginning, the *e is the encrypted text //Encryption in being made only in letters noy in numbers and punctuations // *e = *w + key } void decrypt (char * e, char *w, int key) { // Decryption function, *e is the text in the beginning, the *w is the decrypted text //Dencryption in being made only in letters no numbers and punctuations // *w = *e - key } void Caesar (char * inputFile, char * outputFile, int key, int mode) { // Read the inputfile which contains some data. If mode ==1 then the data is being //encrypted else if mode == 0 the data is being decrypted and is being written in //the output file } void main() { // call the Caesar function } The program has four functions, chooseKey function have to return an int as a shift key from 1-26. Encrypt function has three parameters, *w is the text in the beginning, *e is the encrypted text and the key is from the choosekey function.For encryption : Only letters have to be encrypted not numbers or punctuation and the letters are counting cyclic. Decrypt function has three parameters *e is the encrypted text, *w is the beginning text and the key. Caesar function has four parameters, inputfile which is the file that contains the beginning text, output file which contains the encrypted text, the key and the mode (if mode==1) encryption, (mode ==0) decryption. This is my sample code: #include <iostream> #include <fstream> using namespace std; int chooseKey() { int key_number; cout << "Give a number from 1-26: "; cin >> key_number; while(key_number<1 || key_number>26) { cout << "Your number have to be from 1-26.Retry: "; cin >> key_number; } return key_number; } void encryption(char *w, char *e, int key){ char *ptemp = w; while(*ptemp){ if(isalpha(*ptemp)){ if(*ptemp>='a'&&*ptemp<='z') { *ptemp-='a'; *ptemp+=key; *ptemp%=26; *ptemp+='A'; } } ptemp++; } w=e; } void decryption (char *e, char *w, int key){ char *ptemp = e; while(*ptemp){ if(isalpha(*ptemp)) { if(*ptemp>='A'&&*ptemp<='Z') { *ptemp-='A'; *ptemp+=26-key; *ptemp%=26; *ptemp+='a'; } } ptemp++; } e=w; } void Caesar (char *inputFile, char *outputFile, int key, int mode) { ifstream input; ofstream output; char buf, buf1; input.open(inputFile); output.open(outputFile); buf=input.get(); while(!input.eof()) { if(mode == 1){ encryption(&buf, &buf1, key); }else{ decryption(&buf1, &buf, key); } output << buf; buf=input.get(); } input.close(); output.close(); } int main(){ int key, mode; key = chooseKey(); cout << "1 or 0: "; cin >> mode; Caesar("test.txt","coded.txt",key,mode); system("pause"); } I am trying to run the code and it is being crashed (Debug Assertion Failed). I think the problem is somewhere inside Caesar function.How to call the encrypt and decrypt functions. But i don't know what exactly is. Any ideas?

  Read the article

• Populate struct values with function argument

  - by adohertyd

  I am working on a program and part of it requires me to create a struct called DETAILS with the fields name, age, and height. I want to populate the record with data using a function argument. When I run my code I get compiler errors. I have put the errors in comment form beside the lines it is returned for but I can't fix them. Really could do with some help here guys thanks so much. Here is my code: #include <cstdlib> #include <iostream> #include <iomanip> using namespace std; const int LEN=100; struct DETAILS { char name[LEN]; int age; double height; }; person fillperson(struct DETAILS, char[LEN], int, double); int main() { struct person David; fillperson(David, "David Greene", 38, 180.0); //deprecated conversion from string constant to char * [-Wwrite-Strings] } person fillperson(struct DETAILS, char[LEN] name, int age, double height) //expected , or ... before 'name' { cin>>David.name>>name; cin>>David.age>>age; cin>>David.height>>height; cout<<"Done"<<endl; }

  Read the article

• Excel VBA Macro for Pivot Table with Dynamic Data Range

  - by John Ziebro

  CODE IS WORKING! THANKS FOR THE HELP! I am attempting to create a dynamic pivot table that will work on data that varies in the number of rows. Currently, I have 28,300 rows, but this may change daily. Example of data format as follows: Case Number Branch Driver 1342 NYC Bob 4532 PHL Jim 7391 CIN John 8251 SAN John 7211 SAN Mary 9121 CLE John 7424 CIN John Example of finished table: Driver NYC PHL CIN SAN CLE Bob 1 0 0 0 0 Jim 0 1 0 0 0 John 0 0 2 1 1 Mary 0 0 0 1 0 Code as follows: Sub CreateSummaryReportUsingPivot() ' Use a Pivot Table to create a static summary report ' with model going down the rows and regions across Dim WSD As Worksheet Dim PTCache As PivotCache Dim PT As PivotTable Dim PRange As Range Dim FinalRow As Long Dim FinalCol As Long Set WSD = Worksheets("PivotTable") 'Name active worksheet as "PivotTable" ActiveSheet.Name = "PivotTable" ' Delete any prior pivot tables For Each PT In WSD.PivotTables PT.TableRange2.Clear Next PT ' Define input area and set up a Pivot Cache FinalRow = WSD.Cells(Application.Rows.Count, 1).End(xlUp).Row FinalCol = WSD.Cells(1, Application.Columns.Count). _ End(xlToLeft).Column Set PRange = WSD.Cells(1, 1).Resize(FinalRow, FinalCol) Set PTCache = ActiveWorkbook.PivotCaches.Add(SourceType:= _ xlDatabase, SourceData:=PRange) ' Create the Pivot Table from the Pivot Cache Set PT = PTCache.CreatePivotTable(TableDestination:=WSD. _ Cells(2, FinalCol + 2), TableName:="PivotTable1") ' Turn off updating while building the table PT.ManualUpdate = True ' Set up the row fields PT.AddFields RowFields:="Driver", ColumnFields:="Branch" ' Set up the data fields With PT.PivotFields("Case Number") .Orientation = xlDataField .Function = xlCount .Position = 1 End With With PT .ColumnGrand = False .RowGrand = False .NullString = "0" End With ' Calc the pivot table PT.ManualUpdate = False PT.ManualUpdate = True End Sub

  Read the article

• How do you search a document for a string in c++?

  - by Jeff

  Here's my code so far: #include<iostream> #include<string> #include<fstream> using namespace std; int main() { int count = 0; string fileName; string keyWord; string word; cout << "Please make sure the document is in the same file as the program, thank you!" << endl << "Please input document name: " ; getline(cin, fileName); cout << endl; cout << "Please input the word you'd like to search for: " << endl; cin >> keyWord; cout << endl; ifstream infile(fileName.c_str()); while(infile.is_open()) { getline(cin,word); if(word == keyWord) { cout << word << endl; count++; } if(infile.eof()) { infile.close(); } } cout << count; } I'm not sure how to go to the next word, currently this infinite loops...any recommendation? Also...how do I tell it to print out the line that that word was on? Thanks in advance!

  Read the article

• binary_search not working for a vector<string>

  - by VaioIsBorn

  #include <iostream> #include <string> #include <vector> #include <algorithm> using namespace std; int main(void) { string temp; vector<string> encrypt, decrypt; int i,n, co=0; cin >> n; for(i=0;i<n;i++) { cin >> temp; encrypt.push_back(temp); } for(i=0;i<n;i++) { cin >> temp; decrypt.push_back(temp); } for(i=0;i<n;i++) { temp = encrypt[i]; if((binary_search(decrypt.begin(), decrypt.end(), temp)) == true) ++co; } cout << co << endl; return 0; } It reads two equal lists of strings and should print out how many of the words in the first list are also found in the second list, simple. Not giving me the expexted results and i think the problem is in binary_search. Can you tell me why ?

  Read the article

• Reverse String Error?

  - by R41nB0w M47r1z

  I am creating this revese string App but i get a error if i include a space in the string ! #include <iostream> #include <string> using namespace std; int main() { int inputa; cout<<"%%%%%%%%%%%%%%%%%%String Reversing App%%%%%%%%%%%%%%%%%%%%%%%%"<<endl<<endl; cout<<"\nEnter 1 to continue and 0 to exit"<<endl<<endl; cin>>inputa; if(inputa!=0) { do { string a,c=""; cout<<"\nEnter the string you want to Reverse : "; cin>>a; for(int x=a.length()-1; x>=0; x--) { c=c+a.substr(x,1); } cout<<"\nThe Reverse String is : "<<c<<endl; cout<<"\nEnter 1 to continue and 0 to exit"<<endl<<endl; cin>>inputa; } while(inputa!=0); } //not my home work } If I type the following string like "abc def" there i get an error . But otherwise it works perfectly ! Is there some mistake with the codes ! I am new to CPP so it would be helpful if you could help me !

  Read the article

• Finding the Largest and Smallest Integers In A Set- Basic

  - by Ka112324

  I'm kind of on the right track, however my output is not quite right. The program asks for the number of integers you have and then it asks for those numbers. For an example is says please enter the number of integers, you can put 3. And then you enter 3 numbers. I can't use arrays because I am a beginner student and we have not learned those yet. Using count is the only way that allows me to input integers. What do I need to add to my program? Again I am a general computer science student so I can't use anything advanced. I used include iostream, namespace int main and all that you just cant see it int data; int num; int count=0; int max=0; do { cout<<"Enter the number of intergers"<<endl; cin>>num; while (count<num) { cout<<"Please enter a number"<<endl; cin>>data; count++; if (data<min) { min=data; } if (data>max) { max=data; } } cout<<"Smallest integer:"<<min<<endl; cout<<"Largest integer:"<<max<<endl; cout<<"Would you like to continue?"<<endl; cin>>ans; } while ((ans=='y')||(ans=='Y')); return 0; }

  Read the article

• array multiplication task

  - by toby

  I am tying to get around how you will multiply the values in 2 arrays (as an input) to get an output. The problem I have is the how to increment the loops to achieve the task shown below #include <iostream> using namespace std; main () { int* filter1, *signal,fsize1=0,fsize2=0,i=0; cout<<" enter size of filter and signal"<<endl; cin>> fsize1 >> fsize2; filter1= new int [fsize1]; signal= new int [fsize2]; cout<<" enter filter values"<<endl; for (i=0;i<fsize1;i++) cin>>filter1[i]; cout<<" enter signal values"<<endl; for (i=0;i<fsize2;i++) cin>>signal[i]; /* the two arrays should be filled by users but use the arrays below for test int array1[6]={2,4,6,7,8,9}; int array2[3]={1,2,3}; The output array should be array3[9]={1*2,(1*4+2*2),(1*6+2*4+3*2),........,(1*9+2*8+3*7),(2*9+3*8),3*9} */ return 0; } This is part of a bigger task concerning filter of a sampled signal but it is this multiplication that i cant get done.

  Read the article

• Program instantly closing [migrated]

  - by Ben Clayton

  I made this program and when I compiled it there were no errors but the program just instantly closed, any answers would be appreciated. #include <iostream> //Main commands #include <string> // String commands #include <windows.h> // Sleep using namespace std; int main () { //Declaring variables float a; bool end; std::string input; end = false; // Making sure program doesn't end instantly cout << "Enter start then the number you want to count down from." << ".\n"; while (end = false){ cin >> input; cout << ".\n"; if (input.find("end") != std::string::npos) // Ends the program if user types end end = true; else if (input.find("start" || /* || is or operator*/ "restart") != std::string::npos) // Sets up the countdown timer if the user types start { cin >> a; cout << ".\n"; while (a>0){ Sleep(100); a = a - 0.1; cout << a << ".\n"; } cout << "Finished! Enter restart and then another number, or enter end to close the program" << ".\n"; } else // Tells user to start program cout << "Enter start"; } return 0; // Ends program when (end = true) }

  Read the article

• How can I draw a line with a variable of width?

  - by user1729944

  #include <iostream> #include <cmath> #include "graph1.h" using namespace std; int main() { int diameter = 0; int height = 0; double rate = 0; char repeat = 'y'; int obj_num = 0; displayGraphics(); obj_num = drawRect(0,0,50,400); setColor(obj_num,200,200,200); obj_num = drawRect(0,400,640,79); setColor(obj_num,71,35,35); obj_num = drawLine(50,50,150,50,5); setColor(obj_num,80,80,80); displayBMP("faucet.bmp",150,12); do { do { cout << "Enter the diamater of the cylinder <in inches > 0 but <= 300: "; cin >> diameter; if((diameter<0) || (diameter>300)) { cout << "Incorrect diamater entered; value must be between 1 and 300" << endl; } }while((diameter<0) || (diameter>300)); do { cout << "Enter the height of the cylinder <in inches > 0 but <= 325: "; cin >> height; if((height<0) || (height>325)) { cout << "Incorrect height entered; value must be between 1 and 325" << endl; } }while((height<0) || (height>325)); do { cout << "Enter the facet water's rate: <gallons/minute> "; cin >> rate; if((rate<0) || (rate>100)) { cout << "Incorrect rate entered; value must be between 1 and 100" << endl; } }while((rate<0) || (rate>100)); //I need to draw the lines here. The graphics window has a faucet that is supposed to fill //up a cylinder made out of 3 lines. I don't know how to make the lines vary from the users //input since lines are hard coded with points and all i am receiving is the width for the //bottom line and the height for the left and right lines. cout << "Repeat program? (y/n): "; cin >> repeat; clearGraphics(); }while ( (repeat == 'y') || (repeat == 'Y') ); return 0; } Here is a screenshot for reference:

  Read the article

• Undeclared Scope in Rock Paper Scissors Simple Game

  - by Rianelle

  #include <iostream> #include <string> #include <cstdlib> #include <ctime> using namespace std; bool win; int winnings; int draws; int loses; string comChoice; string playerChoice; void winGame () { cout << "You won! Play again?" <<endl; cout << "Type y/n" <<endl; char x; cin >> x; if (x == 'y') { beginGame(); } else if ('n'){ cout << "Game Stopped." <<endl; cout << "Number of Draws: " <<draws << endl; cout << "Number of Loses: " <<loses << endl; cout << "Number of Wins: " << winnings << endl; win = true; } } void drawGame (){ ++draws; cout << "Draw! Try again" << endl; return; } void lose () { cout << "You lose! Try again?" <<endl; cout << "Type y/n" <<endl; char feedback; cin >> feedback; if (feedback == 'y') { beginGame(); } else if ('n'){ cout << "Game Stopped." <<endl; cout << "Number of Draws: " <<draws << endl; cout << "Number of Loses: " <<loses << endl; cout << "Number of Wins: " << winnings << endl; } } void beginGame() { cout << "Welcome to the Rock, Paper and Scissors Game!" <<endl; cout << "Let's begin. Type <rock, paper, scissors> for your choice!" <<endl; cin >> playerChoice; srand(time(0)); int randomizer = 1+(rand()%3); if (randomizer == 1) comChoice = "rock"; if (randomizer == 2) comChoice = "paper"; if (randomizer == 3) comChoice = "scissors"; do { if (playerChoice == comChoice) { drawGame(); } if (playerChoice == "rock" && comChoice == "paper") ++loses; lose(); if (playerChoice == "rock" && comChoice == "scissors") ++winnings; winGame(); if (playerChoice == "paper" && comChoice == "rock") ++winnings; winGame(); if (playerChoice == "paper" && comChoice == "scissors") ++loses; lose(); if (playerChoice == "scissors" && comChoice == "rock") ++loses; lose(); if (playerChoice == "scissors" && comChoice == "paper") ++winnings; winGame(); }while (win != true); } int main () { beginGame(); return 0; }

  Read the article

• BouncyCastle GCM/CCM Exceprion in JAVA

  - by 4r1y4n

  can anyone give me an example for using GCM and/or CCM modes with AES in BouncyCastle? My code is this: SecretKeySpec key = new SecretKeySpec(keyBytes, "AES"); IvParameterSpec ivSpec = new IvParameterSpec(ivBytes); Cipher cipher = Cipher.getInstance("AES/AEAD/PKCS5Padding", "BC"); byte[] block = new byte[1048576]; int i; long st,et; cipher.init(Cipher.ENCRYPT_MODE, key, ivSpec); BufferedInputStream bIn=new BufferedInputStream(new ProgressMonitorInputStream(null,"Encrypting ...",new FileInputStream("input"))); CipherInputStream cIn = new CipherInputStream(bIn, cipher); BufferedOutputStream bOut=new BufferedOutputStream(new FileOutputStream("output.enc")); int ch; while ((i = cIn.read(block)) != -1) { bOut.write(block, 0, i); } cIn.close(); bOut.close(); Thread.sleep(5000); cipher.init(Cipher.DECRYPT_MODE, key, ivSpec); BufferedInputStream fis=new BufferedInputStream(new ProgressMonitorInputStream(null,"Decrypting ...",new FileInputStream("output.enc"))); //FileInputStream fis=new FileInputStream("output.enc"); //FileOutputStream ro=new FileOutputStream("regen.plain"); BufferedOutputStream ro=new BufferedOutputStream(new FileOutputStream("regen.plain")); CipherInputStream dcIn = new CipherInputStream(fis, cipher); while ((i = dcIn.read(block)) != -1) { ro.write(block, 0, i); } dcIn.close(); ro.close(); but it throws this exception when decrypting in GCM mode (line 70 is bOut.write(block, 0, i);): Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException at java.lang.System.arraycopy(Native Method) at org.bouncycastle.crypto.modes.CCMBlockCipher.processPacket(Unknown Source) at org.bouncycastle.crypto.modes.CCMBlockCipher.doFinal(Unknown Source) at org.bouncycastle.jcajce.provider.symmetric.util.BaseBlockCipher$AEADGenericBlockCipher.doFinal(Unknown Source) at org.bouncycastle.jcajce.provider.symmetric.util.BaseBlockCipher.engineDoFinal(Unknown Source) at javax.crypto.Cipher.doFinal(DashoA13*..) at javax.crypto.CipherInputStream.a(DashoA13*..) at javax.crypto.CipherInputStream.read(DashoA13*..) at javax.crypto.CipherInputStream.read(DashoA13*..) at enctest.Main.main(Main.java:70) And this Exception when encrypting in CCM mode (line 70 is bOut.write(block, 0, i);): Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException at java.lang.System.arraycopy(Native Method) at org.bouncycastle.crypto.modes.CCMBlockCipher.processPacket(Unknown Source) at org.bouncycastle.crypto.modes.CCMBlockCipher.doFinal(Unknown Source) at org.bouncycastle.jcajce.provider.symmetric.util.BaseBlockCipher$AEADGenericBlockCipher.doFinal(Unknown Source) at org.bouncycastle.jcajce.provider.symmetric.util.BaseBlockCipher.engineDoFinal(Unknown Source) at javax.crypto.Cipher.doFinal(DashoA13*..) at javax.crypto.CipherInputStream.a(DashoA13*..) at javax.crypto.CipherInputStream.read(DashoA13*..) at javax.crypto.CipherInputStream.read(DashoA13*..) at enctest.Main.main(Main.java:70)

  Read the article

• Cannot enter input with gdb. Help!

  - by Carlos Nunez

  Hi, all. I've been having a tough time entering input with gdb using XCode or Eclipse. Every time the debugger hits std::cin, it looks like its waiting for input, but fails to accept it. I've scoured the internet for more information, but am having trouble finding anything. What do I need to do to get cin to work with gdb? For reference, I'm using XCode 3.2.2 and Eclipse Galileo. Thanks! -Carlos Nunez

  Read the article

• stringstream problem - vector iterator not dereferencable

  - by andreas

  Hello I've got a problem with the following code snippet. It is related to the stringstream "stringstream css(cv.back())" bit. If it is commented out the program will run ok. It is really weird, as I keep getting it in some of my programs, but if I just create a console project the code will run fine. In some of my Win32 programs it will and in some it won't (then it will return "vector iterator not dereferencable" but it will compile just fine). Any ideas at all would be really appreciated. Thanks! vector<double> cRes(2); vector<double> pRes(2); int readTimeVects2(vector<double> &cRes, vector<double> &pRes){ string segments; vector<string> cv, pv, chv, phv; ifstream cin("cm.txt"); ifstream pin("pw.txt"); ifstream chin("hm.txt"); ifstream phin("hw.txt"); while (getline(cin,segments,'\t')) { cv.push_back(segments); } while (getline(pin,segments,'\t')) { pv.push_back(segments); } while (getline(chin,segments,'\t')) { chv.push_back(segments); } while (getline(phin,segments,'\t')) { phv.push_back(segments); } cin.close(); pin.close(); chin.close(); phin.close(); stringstream phss(phv.front()); phss >> pRes[0]; phss.clear(); stringstream chss(chv.front()); chss >> cRes[0]; chss.clear(); stringstream pss(pv.back()); pss >> pRes[1]; pss.clear(); stringstream css(cv.back()); css >> cRes[1]; css.clear(); return 0; }

  Read the article

• How do I get the next token in a Cstring if I want to use it as an int? (c++)

  - by Van

  My objective is to take directions from a user and eventually a text file to move a robot. The catch is that I must use Cstrings(such as char word[];) rather than the std::string and tokenize them for use. the code looks like this: void Navigator::manualDrive() { char uinput[1]; char delim[] = " "; char *token; cout << "Enter your directions below: \n"; cin.ignore(); cin.getline (uinput, 256); token=strtok(uinput, delim); if(token == "forward") { int inches; inches=token+1; travel(inches); } } I've never used Cstrings I've never tokenized anything before, and I don't know how to write this. Our T.A.'s expect us to google and find all the answers because they are aware we've never been taught these methods. Everyone in my lab is having much more trouble than usual. I don't know the code to write but I know what I want my program to do. I want it to execute like this: 1) Ask for directions. 2) cin.getline the users input 3) tokenize the inputed string 4) if the first word token == "forward" move to the next token and find out how many inches to move forward then move forward 5) else if the first token == "turn" move to the next token. if the next token == "left" move to the next token and find out how many degrees to turn left I will have to do this for forward x, backward x, turn left x, turn right x, and stop(where x is in inches or degrees). I already wrote functions that tell the robot how to move forward an inch and turn in degrees. I just need to know how to convert the inputted strings to all lowercase letters and move from token to token and convert or extract the numbers from the string to use them as integers. If all is not clear you can read my lab write up at this link: http://www.cs.utk.edu/~cs102/robot_labs/Lab9.html If anything is unclear please let me know, and I will clarify as best I can.

  Read the article

• Good style for handling constructor failure of critical object

  - by mtlphil

  I'm trying to decide between two ways of instantiating an object & handling any constructor exceptions for an object that is critical to my program, i.e. if construction fails the program can't continue. I have a class SimpleMIDIOut that wraps basic Win32 MIDI functions. It will open a MIDI device in the constructor and close it in the destructor. It will throw an exception inherited from std::exception in the constructor if the MIDI device cannot be opened. Which of the following ways of catching constructor exceptions for this object would be more in line with C++ best practices Method 1 - Stack allocated object, only in scope inside try block #include <iostream> #include "simplemidiout.h" int main() { try { SimpleMIDIOut myOut; //constructor will throw if MIDI device cannot be opened myOut.PlayNote(60,100); //..... //myOut goes out of scope outside this block //so basically the whole program has to be inside //this block. //On the plus side, it's on the stack so //destructor that handles object cleanup //is called automatically, more inline with RAII idiom? } catch(const std::exception& e) { std::cout << e.what() << std::endl; std::cin.ignore(); return 1; } std::cin.ignore(); return 0; } Method 2 - Pointer to object, heap allocated, nicer structured code? #include <iostream> #include "simplemidiout.h" int main() { SimpleMIDIOut *myOut; try { myOut = new SimpleMIDIOut(); } catch(const std::exception& e) { std::cout << e.what() << std::endl; delete myOut; return 1; } myOut->PlayNote(60,100); std::cin.ignore(); delete myOut; return 0; } I like the look of the code in Method 2 better, don't have to jam my whole program into a try block, but Method 1 creates the object on the stack so C++ manages the object's life time, which is more in tune with RAII philosophy isn't it? I'm still a novice at this so any feedback on the above is much appreciated. If there's an even better way to check for/handle constructor failure in a siatuation like this please let me know.

  Read the article

• how I can overcome this error C2679: binary '>>' : no operator found which takes a right-hand oper

  - by hussein abdullah

  #include <iostream> using std::cout; using std::cin; using std::endl; #include <cstring> void initialize(char[],int*); void input(const char[] ,int&); void print ( const char*,const int); void growOlder (const char [], int* ); bool comparePeople(const char* ,const int*,const char*,const int*); int main(){ char name1[25]; char name2[25]; int age1; int age2; initialize (name1,&age1); initialize (name2,&age2); print(name1,age1); print(name2,age2); input(name1,age1); input(name2,age2); print(name1,age1); print(name2,age2); growOlder(name2,&age2); if(comparePeople(name1,&age1,name2,&age2)) cout<<"Both People have the same name and age "<<endl; return 0; } void input(const char name[],int &age) { cout<<"Enter a name :"; cin>>name ; cout<<"Enter an age:"; cin>>age; cout<<endl; } void initialize ( char name[],int *age) { name[0]='\0'; *age=0; } void print ( const char name[],const int age ) { cout<<"The Value stored in variable name is :" <<name<<endl <<"The Value stored in variable age is :" <<age<<endl<<endl; } void growOlder(const char name[],int *age) { cout<< name <<" has grown one year older\n\n"; *age++; } bool comparePeople (const char *name1,const int *age1, const char *name2,const int *age2) { return(*age1==*age2 && !strcmp(name1,name2)); }

  Read the article

• C++ program Telephone Directory from a file

  - by Stacy Doyle

  I am writing a program for a phone directory. The user inputs a name and the program searches the file and either outputs the number or an error because the persons name is not in the file. The program should also ask the user if they would like to continue using the program and look up another number. So far runs and asks for the name and then prints the error message that I put in place saying that the name is not in the database. I am guessing that I must not really be having my program look in the file but not sure what to do also don't know how to get the program to run again if the user chooses to continue. #include <iostream> #include <fstream> #include <string> #include <iomanip> using namespace std; char chr; int main() { string first; string last; string number; string firstfile; string lastfile; string numberfile; int cont; ifstream infile; infile.open("name and numbers.dat"); //opening the file infile>>firstfile>>lastfile>>numberfile; cout<<"Enter a first and last name."<<endl; //Asking user for the input cin>>first>>last; //input the data { if(first==firstfile && last==lastfile) //if the entered information matches the information in the file cout<<first<<" "<<last<<"'s number is "<<numberfile<<endl; //this is printed else cout<<"Sorry that is not in our database."<<endl; //if the information doesn't match this is printed } cout<<"Would you like to search for another name? Y or N"<<endl; //user is asked if they would like to continue cin>>cont; infile.close(); //close file cin>>chr; return 0; }

  Read the article

• Void in main and keeping Dos program from dying

  - by TimothyTech

  Alright, so im using bloodshed complier, first thing i should note is im using a 2001 edition C++ for the aboslute beginner, was there any changes to C++ since 2001 that would effect the validity of this book? i ask because i know php has php5 and now php6 but i havent seen any C++3. now for the reason i asked that, in this code it uses, void main (void) why would i want an arguement to be void? what does this do. But when i run the " void main (void) in my compiler it says that main must have a "int" before it. so i cant have "void" main (void); also, once the code runs through, as long as there isnt a "cin" the program closes. is this normal behavior, is there a better way to stop this besides making a cin at the end of my program.

  Read the article

• C++ run error: pointer being freed was not allocated

  - by Dale Reves

  I'm learning c++ and am working on a program that keeps giving me a 'pointer being freed was not allocated' error. It's a grocery store program that inputs data from a txt file, then user can enter item# & qty. I've read through similar questions but what's throwing me off is the 'pointer' issue. I would appreciate if someone could take a look and help me out. I'm using Netbeans IDE 7.2 on a Mac. I'll just post the whole piece I have so far. Thx. #include <iostream> #include <fstream> #include <string> #include <vector> using namespace std; class Product { public: // PLU Code int getiPluCode() { return iPluCode; } void setiPluCode( int iTempPluCode) { iPluCode = iTempPluCode; } // Description string getsDescription() { return sDescription; } void setsDescription( string sTempDescription) { sDescription = sTempDescription; } // Price double getdPrice() { return dPrice; } void setdPrice( double dTempPrice) { dPrice = dTempPrice; } // Type..weight or unit int getiType() { return iType; } void setiType( int iTempType) { iType = iTempType; } // Inventory quantity double getdInventory() { return dInventory; } void setdInventory( double dTempInventory) { dInventory = dTempInventory; } private: int iPluCode; string sDescription; double dPrice; int iType; double dInventory; }; int main () { Product paInventory[21]; // Create inventory array Product paPurchase[21]; // Create customer purchase array // Constructor to open inventory input file ifstream InputInventory ("inventory.txt", ios::in); //If ifstream could not open the file if (!InputInventory) { cerr << "File could not be opened" << endl; exit (1); }//end if int x = 0; while (!InputInventory.eof () ) { int iTempPluCode; string sTempDescription; double dTempPrice; int iTempType; double dTempInventory; InputInventory >> iTempPluCode >> sTempDescription >> dTempPrice >> iTempType >> dTempInventory; paInventory[x].setiPluCode(iTempPluCode); paInventory[x].setsDescription(sTempDescription); paInventory[x].setdPrice(dTempPrice); paInventory[x].setiType(iTempType); paInventory[x].setdInventory(dTempInventory); x++; } bool bQuit = false; //CREATE MY TOTAL VARIABLE HERE! int iUserItemCount; do { int iUserPLUCode; double dUserAmount; double dAmountAvailable; int iProductIndex = -1; //CREATE MY SUBTOTAL VARIABLE HERE! while(iProductIndex == -1) { cout<<"Please enter the PLU Code of the product."<< endl; cin>>iUserPLUCode; for(int i = 0; i < 21; i++) { if(iUserPLUCode == paInventory[i].getiPluCode()) { dAmountAvailable = paInventory[i].getdInventory(); iProductIndex = i; } } //PLU code entry validation if(iProductIndex == -1) { cout << "You have entered an invalid PLU Code."; } } cout<<"Enter the quantity to buy.\n"<< "There are "<< dAmountAvailable << "available.\n"; cin>> dUserAmount; while(dUserAmount > dAmountAvailable) { cout<<"That's too many, please try again"; cin>>dUserAmount; } paPurchase[iUserItemCount].setiPluCode(iUserPLUCode);// Array of objects function calls paPurchase[iUserItemCount].setdInventory(dUserAmount); paPurchase[iUserItemCount].setdPrice(paInventory[iProductIndex].getdPrice()); paInventory[iProductIndex].setdInventory( paInventory[iProductIndex].getdInventory() - dUserAmount ); iUserItemCount++; cout <<"Are you done purchasing items? Enter 1 for yes and 0 for no.\n"; cin >> bQuit; //NOTE: Put Amount * quantity for subtotal //NOTE: Put code to update subtotal (total += subtotal) // NOTE: Need to create the output txt file! }while(!bQuit); return 0; }

  Read the article

• Link List Implementation Help - Visual C++

  - by Greenhouse Gases

  Hi there I'm trying to implement a link list which stores the city name (though you will see this commented out as I need to resolve the issue of not being able to use string and needing to use a primitive data type instead during the declaration), longitude, latitude and of course a pointer to the next node in the chain. I am new to the Visual C++ environment and my brain is somewhat scrambled after coding for several straight hours today so I wondered if anyone could help resolve the 2 errors I am getting (ignore the #include syntax as I had to change them to avoid the browser interpreting html!): 1U08221.obj : error LNK2028: unresolved token (0A000298) "public: __thiscall Locations::Locations(void)" (??0Locations@@$$FQAE@XZ) referenced in function "int __clrcall main(cli::array^)" (?main@@$$HYMHP$01AP$AAVString@System@@@Z) 1U08221.obj : error LNK2019: unresolved external symbol "public: __thiscall Locations::Locations(void)" (??0Locations@@$$FQAE@XZ) referenced in function "int __clrcall main(cli::array^)" (?main@@$$HYMHP$01AP$AAVString@System@@@Z) The code for my header file is here: include string struct locationNode { //char[10] nodeCityName; double nodeLati; double nodeLongi; locationNode* Next; }; class Locations { private: int size; public: Locations(); // constructor for the class locationNode* Head; int Add(locationNode* Item); }; and here is the code for the file containing the main method: // U08221.cpp : main project file. include "stdafx.h" include "Locations.h" include iostream include string using namespace std; int n = 0; int x; string cityNameInput; bool acceptedInput = false; int Locations::Add(locationNode *NewItem) { locationNode *Sample = new locationNode; Sample = NewItem; Sample-Next = Head; Head = Sample; return size++; } void CorrectCase(string name) // Correct upper and lower case letters of input { x = name.size(); int firstLetVal = name[0], letVal; n = 1; // variable for name index from second letter onwards if((name[0] 90) && (name[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter name[0] = firstLetVal; } while(n <= x - 1) { if((name[n] = 65) && (name[n] <= 90)) { letVal = name[n] + 32; name[n] = letVal; } n++; } cityNameInput = name; } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] = 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] =91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array ^args) { cout << "Enter a city name" << endl; cin cityNameInput; nameValidation(cityNameInput); // check is made up of valid characters CorrectCase(cityNameInput); // corrects name to standard format of capitalised first letter, and lower case subsequent letters cout << cityNameInput; cin cityNameInput; Locations::Locations(); Locations *Parts = new Locations(); locationNode *Part; Part = new locationNode; //Part-nodeCityName = "London"; Part-nodeLati = 87; Part-nodeLongi = 80; Parts-Add(Part); } I am familiar with the concepts but somewhat inexperienced with OOP so am making some silly errors that you can never find when you've stared at something too long. Any help you can offer will be appreciated! Thanks

  Read the article

• C++ arrays select square number and make new vector

  - by John Smith

  I have to see which of the following from a vector is a square number then make another vector with only the square numbers For example: (4,15,6,25,7,81) the second will be (4,25,81) 4,25,81 because 2x2=4 5x5=25 and 9x9=81 I started like this: { int A[100],n,r,i; cout<<"Number of elements="; cin>>n; for(i=1;i<=n;i++) { cout<<"A["<<i<<"]="; cin>>A[i]; } for(i=1;i<=n;i++) { r=sqrt(A[i]); if(r*r==A[i]) } return 0; } but I am not really sure how to continue

  Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >