Is it possible to use boost::bind to effectively concatenate functions?
- by Catskul
Assume that I have a boost::function of with an arbitrary signature called type CallbackType.
Is it possible to use boost::bind to compose a function that takes the same arguments as the CallbackType but calls the two functors in succession?
Hypothetical example using a magic template:
Template<typename CallbackType>
class MyClass
{
public:
CallbackType doBoth;
MyClass( CallbackType callback )
{
doBoth = bind( magic<CallbackType>,
protect( bind(&MyClass::alert, this) ),
protect( callback ) );
}
void alert()
{
cout << "It has been called\n";
}
};
void doIt( int a, int b, int c)
{
cout << "Doing it!" << a << b << c << "\n";
}
int main()
{
typedef boost::function<void (int, int, int)> CallbackType;
MyClass<CallbackType> object( boost::bind(doIt) );
object.doBoth();
return 0;
}
